Two blocks are sliding on a horizontal frictionless surface with velocities shown in the sketch. Block A has mass 0.500 kg and block B has mass 0.750 kg. The two blocks have a perfectly inelastic collision and stick together after the collision.
(a) What is the speed of the combined blocks after the collision?
(b) What angle does the velocity of the combined blocks make with the +x-axis after the collision?
(c) What is the magnitude of the decrease in kinetic energy of the system of two blocks due to the collision?
Answers
(a) The conservation of momentum applies to this inelastic collision. The total momentum of the system before the collision is the sum of the momentum of block A and the momentum of block B:
p_i = m_A * v_A + m_B * v_B
= (0.500 kg)(4.00 m/s) + (0.750 kg)(-2.50 m/s)
= 0.500 kg * 4.00 m/s - 0.750 kg * 2.50 m/s
= 0.500 kg * 4.00 m/s + (-0.750 kg) * (-2.50 m/s) (note: v_B is negative)
= 1.250 kg m/s
The total momentum of the system after the collision is the momentum of the combined blocks:
p_f = (m_A + m_B) * v_f
where v_f is the velocity of the combined blocks after the collision. Since the blocks stick together after the collision, they move with the same velocity. Therefore, we can write:
v_f = p_f / (m_A + m_B)
= 1.250 kg m/s / (0.500 kg + 0.750 kg)
= 1.00 m/s
Therefore, the speed of the combined blocks after the collision is 1.00 m/s.
(b) The angle that the velocity of the combined blocks makes with the +x-axis after the collision can be found by using the conservation of momentum in the x and y directions separately. Since there is no external force acting on the system in either the x or y direction, the total momentum in each direction is conserved.
In the x direction, the momentum before the collision is:
p_i,x = m_A * v_A,x + m_B * v_B,x
= (0.500 kg)(4.00 m/s) + (0.750 kg)(-2.50 m/s)
= 0.500 kg * 4.00 m/s - 0.750 kg * 2.50 m/s
= 0.500 kg * 4.00 m/s + (-0.750 kg) * (-2.50 m/s) (note: v_B,x is negative)
= 1.250 kg m/s
After the collision, the x-component of the velocity of the combined blocks is:
v_f,x = p_f,x / (m_A + m_B)
Since there is no external force in the x direction, the x-component of the momentum is conserved, i.e., p_i,x = p_f,x. Therefore, we can write:
p_f,x = m_A * v_f,x + m_B * v_f,x
= (m_A + m_B) * v_f,x
= 1.250 kg m/s
Substituting the values, we get:
v_f,x = 1.250 kg m/s / (0.500 kg + 0.750 kg)
= 1.00 m/s
In the y direction, the momentum before the collision is:
p_i,y = m_A * v_A,y + m_B * v_B,y
= 0 + 0
= 0
After the collision, the y-component of the velocity of the combined blocks is:
v_f,y = p_f,y / (m_A + m_B)
Since there is no external force in the y direction, the y-component of the momentum is conserved, i.e., p_i,y = p_f,y. Therefore, we can write:
p_f,y = m_A * v_f,y + m_B * v_f,y
= (m_A + m_B) * v_f,y
Since the blocks stick together after the collision, their y-velocities must cancel out, i.e., v_f,y = 0. Therefore, we can write:
0 = (m_A + m_B) * v_f,y
Substituting the values, we get:
v_f,y = 0
Therefore, the velocity of the combined blocks after the collision is purely in the x-direction, and makes an angle of 0 degrees (i.e., is parallel to) with the +x-axis.
(c) The kinetic energy of the system before the collision is:
KE_i =[tex](1/2) * m_A * v_A^2 + (1/2) * m_B * v_B^2[/tex]
=[tex](1/2) * (0.500 kg) * (4.00 m/s)^2 + (1/2) * (0.750 kg) * (-2.50 m/s)^2[/tex]
= [tex]2.000 J + 2.344 J[/tex]
= 4.344 J
The kinetic energy of the system after the collision is:
KE_f = (1/2) * (m_A +m_B) * v_f^2
= (1/2) * (0.500 kg + 0.750 kg) * (1.00 m/s)^2
= 0.937 J
Therefore, the decrease in kinetic energy of the system due to the collision is:
ΔKE = KE_i - KE_f = 4.344 J - 0.937 J = 3.407 J
The decrease in kinetic energy is dissipated as heat and sound during the collision.
Related Questions
A 0.311 kg tennis racket moving 37.3 m/s
east makes an elastic collision with a
0.0570 kg ball moving 15.2 m/s west.
Find the velocity of the tennis ball after
the collision.
(Unit = m/s)
Remember: right is +, left is -
Answers
A 0.311 kg tennis racket moving 37.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 15.2 m/s west. The velocity of the tennis ball after the collision is 24.2 m/s.
Given, The mass of the tennis racket, m1 = 0.311 kg. The velocity of the tennis racket, u1 = 37.3 m/s eastThe mass of the ball, m2 = 0.0570 kgThe velocity of the ball, u2 = 15.2 m/s westLet the final velocities of the tennis racket and ball be v1 and v2 respectively.
Momentum in the horizontal direction is
m1u1 + m2u2 = m1v1 + m2v2
The positive sign is taken for the velocities moving to the right and the negative sign is taken for the velocities moving to the left.
The momentum of the tennis racket before collision = Momentum of the tennis racket after collision
Let the final velocities of the tennis racket and ball be v1 and v2 respectively. Momentum in the horizontal direction is
m1u1 + m2u2 = m1v1 + m2v2
On substituting the given values,
m1u1 + m2u2 = m1v1 + m2v2
37.3 x 0.311 - 15.2 x 0.0570 = 0.311v1 + 0.0570
v2v1 = (37.3 x 0.311 - 15.2 x 0.0570 - 0.0570v2) / 0.311 ..........(1)
Conservation of kinetic energy is
(1/2) m1u1² + (1/2) m2u2² = (1/2) m1v1² + (1/2) m2v2²
On substituting the given values,
(1/2) × 0.311 × (37.3)² + (1/2) × 0.0570 × (15.2)² = (1/2) × 0.311 × v1² + (1/2) × 0.0570 × v2²
On solving, v2 = 60.4 m/s
Therefore, from equation (1),
v1 = (37.3 x 0.311 - 15.2 x 0.0570 - 0.0570 x 60.4) / 0.311 = 24.2 m/s east
The velocity of the tennis ball after the collision is 24.2 m/s towards the east.
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What does a resistor in an electrical circuit do?
OA. It allows only a reduced number of electrons to flow through it.
OB. It opposes the flow of electrons.
C. It repels electrons, causing them to return to the battery.
OD. It attracts electrons, causing them to move faster.
NEED THIS LAST QUESTION PLEASE☹️
Answers
Answer:
it limits or regulate the flow of electrical current
Answer:
The correct answer is B. It opposes the flow of electrons
Explanation:
A resistor is an electrical component designed to introduce resistance into a circuit. Resistance is the property that hinders the flow of electric current. When current passes through a resistor, it experiences a reduction in voltage and slows down. This opposition to the flow of electrons is what a resistor does in an electrical circuit.
why is nuclear fusion not used to produce electricity
Answers
Answer:
it is incredibly difficult to sustain a fusion reaction.
Explanation:
The main reason we aren't using nuclear fusion to generate power yet is because it is incredibly difficult to sustain a fusion reaction. The energy requirements are very high, and it is hard to find materials that can withstand such high temperatures.
hi what's magnetic energy give SIMP LE answer please
Answers
Answer:
Magnetic energy is the movement of the charge of the electrons in the different particles It is the movement that generates the current that produces the behavior of the electron like that of a small magnet. The earth also possesses a magnetic field generating magnetic energy on the earth.
Describe how core counselling skills can be used in a counselling relationship and in other helping activities.
Answers
Counselling skills are crucial in both professional and personal relationships because they aid in the development of a supportive environment. It includes the creation of a helping relationship, the promotion of efficient interaction, and the establishment of a secure therapeutic relationship. Core counseling skills help to create a positive atmosphere and are used to maintain a supportive relationship with the patient.
There are several ways that core counseling skills can be used in counseling relationships and other helping activities, which are:Empathy Empathy is the ability to understand and appreciate the feelings and ideas of another person. It is an essential part of counseling since it assists the counselor in comprehending and supporting the client's emotional state. Empathy helps the client to feel listened to and supported, reducing feelings of anxiety and fear. For example, in a medical setting, empathizing with the patient can create a positive atmosphere and make the patient feel more comfortable and at ease.Active Listening Active listening is the capability to pay attention to a person while showing interest and concern. It is an essential aspect of counseling and a method of establishing a relationship with the client. Active listening helps the counselor to understand the client's needs, emotions, and concerns. It is an effective method of gathering information and shows the client that the counselor is concerned about them. For instance, in a school setting, active listening can be used to help students feel heard and understood. It can also be used to provide feedback to parents about their children's needs.Non-judgmental Attitude Non-judgmental attitude means avoiding opinions or judgments on the client's actions or circumstances. It is an essential aspect of counseling because it enables clients to feel safe and valued. It also aids in the development of a relationship of trust between the counselor and the client. Non-judgmental attitude can be used in a variety of helping activities, such as mentoring and peer counseling, to create a supportive environment for clients.In conclusion, core counseling skills, including empathy, active listening, and non-judgmental attitude, can be used in various helping activities, including counseling relationships. The use of these skills can help clients feel supported and understood, allowing them to build a relationship of trust with the counselor or helper.For such more question on counseling
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An electric iron is Mark 120 volts and 500 Watts to units consumed by it in using it for 24 hours will be
Answers
An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I
Using the above formula, we can find the current drawn by the electric iron as follows:I = P/VI = 500/120I = 4.17 ATherefore, the power consumed by the electric iron in 24 hours is:P = VI x tP = 120 x 4.17 x 24P = 120 x 100.08P = 12010.56 watt-hoursTo convert watt-hours to kilowatt-hours, we divide by 1000: Energy consumed = 12010.56 / 1000Energy consumed = 12.01 kWhHence, the units consumed by the electric iron in 24 hours is 12.01 kilowatt-hours.For such more question on Voltage
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A 2.5kg rock is thrown off the top of a 18m tall building with a speed of 14m/s. How fast is it going the instant it hits the ground?
Answers
The question requires us to calculate the velocity of a rock dropped off the top of a building using given data. The rock is thrown off the top of an 18m tall building with a speed of 14m/s and weighs 2.5kg. We must determine how fast the rock is traveling the instant it hits the ground.
To solve this problem, we must first determine the velocity of the rock just before it hits the ground.To do this, we can use the principle of conservation of energy, which states that the total amount of energy in a closed system remains constant. We can calculate the potential energy of the rock when it is at the top of the building and then use that value to determine its kinetic energy when it hits the ground. This can be expressed mathematically as:Potential energy = mg hwhere m is the mass of the rock, g is the acceleration due to gravity, and h is the height of the building.Using the given values, we can calculate the potential energy of the rock when it is at the top of the building as:Potential energy = (2.5kg)(9.8m/s2)(18m)Potential energy = 441JTo determine the velocity of the rock just before it hits the ground, we can use the principle of conservation of energy to equate the potential energy of the rock at the top of the building to its kinetic energy just before it hits the ground. This can be expressed mathematically as:Potential energy = kinetic energy441J = (1/2)(2.5kg)v2where v is the velocity of the rock just before it hits the ground.Simplifying the equation, we get:v2 = (2)(441J) / (2.5kg)v2 = 352v = √(352)v = 18.7m/sTherefore, the rock is going 18.7m/s the instant it hits the ground.For such more question on velocity
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What's elastic energy simple meaning please
Answers
Answer:
Elastic potential energy is energy stored as a result of applying a force to deform an elastic object.
A soft tennis ball is dropped onto a hard floor from a height of 1.60 m and rebounds to a height of 1.28 m. (Assume that the positive direction is upward.)
(a)Calculate its velocity (in m/s) just before it strikes the floor. (answer is -5.6)
(b)Calculate its velocity (in m/s) just after it leaves the floor on its way back up. (answer is 5.01)
(c)Calculate its acceleration (in m/s2) during contact with the floor if that contact lasts 3.50 ms. (answer is 3031)
(d)How much (in m) did the ball compress during its collision with the floor, assuming the floor is absolutely rigid? ( I don't know this one)
Answers
(a) The velocity of the tennis ball just before it strikes the floor is -5.6 m/s.
(b) The velocity of the tennis ball just after it leaves the floor on its way back up is 5.01 m/s.
(c) The acceleration of the tennis ball during contact with the floor, assuming the contact lasts 3.50 ms, is 3031 [tex]m/s^2[/tex].
(d) The amount of compression the ball experienced during its collision with the floor, assuming the floor is absolutely rigid, is unknown.
(a) To calculate the velocity of the tennis ball just before it strikes the floor, we can use the principle of conservation of energy. The potential energy at the initial height is converted into kinetic energy just before it hits the floor.
Using the formula for gravitational potential energy (PE = mgh) and kinetic energy (KE = 0.5[tex]mv^2[/tex]), we can equate the two energies:
mgh = 0.5[tex]mv^2[/tex]
Here, m is the mass of the ball, g is the acceleration due to gravity (approximately 9.8 [tex]m/s^2[/tex]), h is the initial height (1.60 m), and v is the velocity just before it strikes the floor.
Simplifying the equation, we get:
9.8 * 1.60 = 0.5 * [tex]v^2[/tex]
15.68 = 0.5 * [tex]v^2[/tex]
31.36 = [tex]v^2[/tex]
Taking the square root of both sides, we find:
v = ±√31.36
Since the positive direction is upward, the velocity just before it strikes the floor is -5.6 m/s.
(b) To calculate the velocity just after the ball leaves the floor on its way back up, we can use the principle of conservation of energy again. The potential energy at the lowest point (the height of the ball during contact with the floor) is converted into kinetic energy.
Using the same equation as before, but with the final height of 1.28 m, we have:
9.8 * 1.28 = 0.5 * [tex]v^2[/tex]
12.544 = 0.5 * [tex]v^2[/tex]
25.088 = [tex]v^2[/tex]
v = ±√25.088
Since the positive direction is upward, the velocity just after it leaves the floor is 5.01 m/s.
(c) To calculate the acceleration during contact with the floor, we can use the formula for acceleration:
a = (v_f - v_i) / t
Here, v_f is the final velocity (5.01 m/s), v_i is the initial velocity (-5.6 m/s), and t is the duration of contact (3.50 ms = 0.0035 s).
a = (5.01 - (-5.6)) / 0.0035
a = 10.61 / 0.0035
a ≈ 3031 [tex]m/s^2[/tex]
Therefore, the acceleration during contact with the floor is approximately 3031 [tex]m/s^2[/tex].
(d) The amount of compression the ball experiences during its collision with the floor can be calculated using the principles of impulse and momentum.
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Exercise 3 Read the following statement: If I switch from using incandescent light bulbs to LED light bulbs, then my electricity bill will decrease. In this situation, the type of light bulb used is the MENU variable
Answers
If I switch from using incandescent light bulbs to LED light bulbs, then my electricity bill will decrease. In this situation, the type of light bulb used is the Independent variable.
What is the independent variable?The independent variable in a circumstance refers to the element that is not affected by the other variables.
In this case, the switching from incandescent lighting to LED bulbs causes a decrease in the electricity bill. So, the light bulb is the independent variable that is unaffected by the other factors.
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what are crystalline substances in physics
Answers
In physics, crystalline substances refer to materials that possess a well-defined, ordered atomic or molecular structure.
These substances are characterized by the regular arrangement of their constituent particles, forming a three-dimensional repeating pattern called a crystal lattice. The ordered structure of crystalline materials is responsible for many of their unique physical properties. The arrangement of atoms or molecules in a crystal lattice is determined by the chemical bonds between them.
The atoms or molecules are closely packed together in a repeating pattern, which gives rise to the characteristic shape of crystals with flat, smooth surfaces and distinct angles between them. Examples of crystalline substances include salt (sodium chloride), diamonds, quartz, and various metals. Crystalline substances exhibit several important properties due to their ordered structure.
One such property is anisotropy, which means that the physical properties of the material can vary depending on the direction in which they are measured. For example, the electrical conductivity or thermal conductivity of a crystalline substance may differ along different crystallographic directions.
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A bottlenose dolphin (Tursiops truncatus) is about 3.0 m long and has a mass of 230 kg. It can jump 3.4 m above the surface of the water while flipping nose-to-tail at 5.9 rad/s, fast enough to complete 1.5 rotations before landing in the water.
How much energy must the dolphin generate to jump 3.4 m above the surface of the water?
If the dolphin’s moment of inertia about its rotation axis is 240 kg⋅m2, how much energy must the dolphin generate to rotate its body in this way?
Answers
1) The dolphin must generate approximately 7,106 Joules of energy to jump 3.4 m above the water's surface.
2) The dolphin must generate approximately 3,523 Joules of energy to rotate its body in this way.
To calculate the energy required for the dolphin to jump 3.4 m above the water's surface, we can use the concept of gravitational potential energy. The energy required is equal to the change in gravitational potential energy of the dolphin during the jump.
The gravitational potential energy is given by the equation:
PE = m * g * h,
where PE is the potential energy, m is the mass of the dolphin, g is the acceleration due to gravity, and h is the height of the jump.
Substituting the given values, we have:
PE = (230 kg) * (9.8 m/s^2) * (3.4 m) = 7,106 Joules.
Therefore, the dolphin must generate approximately 7,106 Joules of energy to jump 3.4 m above the water's surface.
To calculate the energy required for the rotation, we can use the concept of rotational kinetic energy. The energy required is equal to the change in rotational kinetic energy of the dolphin during the rotation.
The rotational kinetic energy is given by the equation:
KE = (1/2) * I * ω^2,
where KE is the kinetic energy, I is the moment of inertia of the dolphin, and ω is the angular velocity.
Substituting the given values, we have:
KE = (1/2) * (240 kg⋅m^2) * (5.9 rad/s)^2 = 3,523 Joules.
Therefore, the dolphin must generate approximately 3,523 Joules of energy to rotate its body in this way.
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Mantle fluid that is heating up will become ________ and move _________.
A. less dense, upwards
B. denser, upwards
C. less dense, downwards
D. denser, downwards
Answers
Explanation:
What is the change in internal energy if 70J of heat is added to a system and the system does 30J of work on the surroundings
Answers
Answer: Δ 100 J
Explanation:
Since, Q = 70 J (heat added to the system) and W = -30 J (work done by the system on the surroundings), we;
Substitute these values into the equation, we have:
ΔU = 70 J - (-30 J)
ΔU = 70 J + 30 J
ΔU = 100 J
if a 1500 kg car speeds up to 3.0 m/s and the gain is kinetic energy
Answers
Hello!
K.E. = 1/2mv²
m = mass
v = square
K.E.
= 1/2mv²
= 1/2 * 1500 * 3²
= 6750J
A car mass 1200 kg is driven around a corner of radius 45m at 15 ms
Calculate the acceleration of the car
Answers
Answer:
Explanation: Given data:
The mass of the car is, m= 1200kg
The value of the radius of the circular path is, r=45m
The value of the constant speed is, s=15ms
1.The centripetal acceleration of the car is given by the formula,
a=v2/r
Substitute the known values,
a=(15)2/45
=5m/s2
The centripetal acceleration in the motion of the car is 5m/s2
2.The force needed to produce this acceleration is calculated by formula,
F=ma
Substitute the known values,
F=1200KG*5m/s2
=6000N
The force needed to produce the centripetal acceleration is 6000N.
What is a change the temperature for the steel wire?
Answers
A change in temperature can cause a change in the dimensions and mechanical properties of a steel wire. When a steel wire is heated, it expands due to thermal expansion, and when it is cooled, it contracts.
The amount of expansion or contraction of the wire depends on the coefficient of thermal expansion of the steel, which is a material property that describes how much the material expands or contracts per unit temperature change. For steel, the coefficient of thermal expansion is typically around 12 x 10^-6 / °C.
If a steel wire is subjected to a temperature change, its length and diameter may change, which in turn affects its mechanical properties such as its strength, stiffness, and ductility. For example, if a steel wire is heated and expands, its cross-sectional area will increase, which will decrease its stress and increase its strain for a given applied load. On the other hand, if a steel wire is cooled and contracts, its cross-sectional area will decrease, which will increase its stress and decrease its strain for a given applied load.
Therefore, it is important to take into account the effects of temperature when designing and analyzing steel structures and components, and to consider the coefficient of thermal expansion and the resulting changes in dimensions and mechanical properties that may occur due to temperature changes.
Water (at 4oC) flows through a pipe with a flow rate of 3.4 m3/s. Calculate the equivalent mass flow rate to the nearest whole kg/s.
Answers
The equivalent mass flow rate of water is 3400 kg/s (to the nearest whole kg/s) when it flows through a pipe with a flow rate of 3.4 m³/s at 4°C.
To calculate the equivalent mass flow rate of water, we can use the formula:
Mass flow rate = Density * Volume flow rate
First, we need to find the density of water at 4°C. The density of water at this temperature is approximately 1000 kg/m³.
Given that the flow rate of water is 3.4 m³/s, we can now calculate the mass flow rate:
Mass flow rate = 1000 kg/m³ * 3.4 m³/s
Mass flow rate = 3400 kg/s
Therefore, the equivalent mass flow rate of water in the pipe is 3400 kg/s (to the nearest whole kg/s).
Explanation:
The mass flow rate represents the amount of mass passing through a given point in a system per unit of time. In this case, we are calculating the mass flow rate of water flowing through a pipe. By multiplying the density of water (in kg/m³) with the volume flow rate (in m³/s), we can determine the mass flow rate (in kg/s). This value represents the mass of water passing through the pipe every second.
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A 1200 kg car moving +13.7 m/s makes
an elastic collision with a 3200 kg truck,
initially at rest. What is the velocity of the
car after the collision?
(Unit = m/s)
Remember: right is +, left is -
Answers
When a car collides with another object, the total momentum of the system before and after the collision must be conserved. Momentum, on the other hand, is a product of mass and velocity. To find the velocity of a car after a collision, we must first consider the initial momentum of the system before the collision and compare it to the final momentum after the collision.
The total momentum of the system before the collision is calculated as follows:P_initial = m_car x v_carP_initial = 1200 kg x 13.7 m/sP_initial = 16,440 kg*m/s Since the two cars stick together after the collision, their final velocity is the same. Let's suppose the final velocity of the cars after the collision is v_f. Then:P_final = (m_car + m_obstacle) x v_fwhere m_obstacle is the mass of the object the car collided with. Because the car is at rest after the collision, we can assume that the velocity of the object it collided with is zero. Therefore:P_final = m_car x v_fP_final = 1200 kg x v_fThe momentum of the system after the collision must be equal to the momentum of the system before the collision. That means:P_initial = P_final16,440 kg*m/s = 1200 kg x v_fv_f = 13.7 m/s - (16,440 kg*m/s / 1200 kg) v_f = 13.7 m/s - 13.7 m/s v_f = 0 m/sTherefore, the car will come to a stop after the collision.For such more question on velocity
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What unique strengths would you bring to the Grace Scholars Program?
Answers
Grace Scholars Program is a scholarship program that selects the best and brightest students for the program.
The Grace Scholars Program is a prestigious scholarship program that aims to identify and support exceptionally talented and promising students. The program seeks to provide opportunities for these students to excel academically, develop their leadership skills, and make a positive impact in their respective fields.The selection process for the Grace Scholars Program is highly competitive, with a rigorous evaluation of applicants' academic achievements, extracurricular activities, personal qualities, and potential for future success. The program typically looks for students who demonstrate outstanding academic performance, intellectual curiosity, leadership abilities, and a commitment to service and community involvement. By offering this scholarship program, institutions aim to attract and retain top talent, foster a culture of excellence, and contribute to the development of future leaders and innovators who can positively impact society.For such more questions on scholarship
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State three examples where undesirable on a
machine
Answers
In the field of machinery, various problems and challenges may arise during the operation of a machine. Three examples of undesirable conditions on a machine are overheating, excessive vibrations, and noise.
Overheating: When a machine is continuously working, it generates heat due to the resistance caused by the parts involved. However, if the machine becomes too hot, it may lead to severe damage to the machinery or the operators working with the machine. Overheating may occur due to several reasons such as lack of lubrication, excessive friction, or improper functioning of cooling systems.
Excessive vibrations: If a machine vibrates too much, it may cause the machine to loosen and break apart. Moreover, excessive vibrations can cause discomfort to the operator working with the machinery. Excessive vibration may arise due to improper balance, lack of maintenance, or wear and tear of the machine parts.
Noise: Machines produce sounds during their operations, but if the sound is too loud and continuous, it may cause damage to the operator's eardrums or cause distraction to people working around the machine. Noise pollution may occur due to unbalanced machine parts, lack of lubrication, and improper functioning of the machine's internal systems.These undesirable conditions on a machine need to be addressed to avoid severe damage to the machine or harm to operators working with the machinery. Regular maintenance, lubrication, and inspection of the machinery can minimize or eliminate the chances of these undesirable conditions on the machine.
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Candle Wax Melting Point (mp) = 68°c Specific heat Capacity = 291/9°℃ Specific Latent heat of fusion (14) = 220j|g Draw a latent heat Curve for 100grams of Candle wax at 20°C to 68
Answers
The latent heat curve would start at the point of origin on the vertical axis (0J) and at the point corresponding to temperature 20°C on the horizontal axis. The curve will rise linearly, until it reaches 1,409,280 J on the vertical axis and 68°C on the horizontal axis, and will remain constant.
How to reach this result?Find the amount of heat that can heat the candle to 68°C.This will be done with the formula for the amount of heat that is [tex]\[ Q = m \cdot c \cdot \Delta T \][/tex]
The "m" stands for grams of candle wax. The "c" represents the specific heat and the ΔT is the temperature change. Substituting the values in the formula we get:
[tex]Q = 100 \, \text{g} \cdot 291 \, \text{J/g C} \cdot (68^\circ \text{C} - 20^\circ \text{C})\\Q1 = 100 \times 291 \times 48\\Q1 = 1409280 \, \mathrm{J}[/tex]
This calculation shows that the amount of heat required to heat the candle to its melting temperature is equal to 1,409,280 J.
Determine the amount of heat capable of melting the candle wax.We will use the formula:
[tex]$Q = m \cdot L$[/tex]
In this formula, the "m" represents the mass of the candle wax, while the "L" represents the latent heat of melting.
Substituting the formula values we get:
[tex]Q2 = 100 \, \text{g} \times 220 \, \text{J/g}\\Q2 = 22000 J[/tex]
This tells us that the amount of heat needed to melt the candle is equal to 22,000 J.
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Does ISO sensibilty in photography have a unit of measurement?
Ex: like lux, or nit, etc...
Answers
ISO sensitivity in photography does not have a specific unit of measurement.
ISO sensitivity in photography does not have a specific unit of measurement. ISO stands for International Organization for Standardization, and it is a standardized scale used to measure the sensitivity of a camera's image sensor to light. It is commonly referred to as "ISO speed" or "ISO value."
The ISO scale typically ranges from low values, such as ISO 100 or 200, to higher values like ISO 1600 or even higher. The higher the ISO value, the more sensitive the camera's sensor is to light, allowing for capturing images in low-light conditions without the need for longer exposure times.
ISO sensitivity is not expressed in units like lux or nit, which are measurements of illuminance or luminance, respectively. Lux measures the amount of light per unit area, while nit measures the brightness of a light source.
ISO sensitivity is a relative scale that represents the amplification of the sensor's signal. As the ISO value increases, the sensor's sensitivity is increased, but at the cost of introducing more digital noise and reducing image quality.
In summary, ISO sensitivity in photography does not have a specific unit of measurement. It is a standardized scale used to indicate the sensitivity of a camera's image sensor to light, allowing photographers to adjust exposure settings and capture images in various lighting conditions.
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I need the answer to question 15 only, please
Answers
Answer:
The answer is C
Explanation:
My sister took that before on paper and she got a 78%
A 1200 kg car driving downhill goes from an altitude of 70 m to 40 m above sea level and accelerates from 11 m/s to 23 m/s.
a, How much potential energy did the car lose? b,How much kinetic energy did it gain?
c,How much energy is unaccounted for?
d.Where did this energy go?
Answers
a) the car lost 352,800 joules of potential energy. b) the car gained 228,600 joules of kinetic energy. c) there is 124,200 joules of energy that is unaccounted for.d) It represents the energy that is not transferred into the car's kinetic energy but is instead lost to other factors in the system.
How to determine how much potential energy did the car loseTo solve this problem, we can use the principles of potential energy and kinetic energy.
a) The potential energy lost by the car can be calculated using the formula:
Potential energy lost = m * g * Δh
where:
m = mass of the car (1200 kg)
g = acceleration due to gravity (approximately 9.8 m/s^2)
Δh = change in height (70 m - 40 m = 30 m)
Potential energy lost =[tex]1200 kg * 9.8 m/s^2 * 30 m[/tex] = 352,800 J
Therefore, the car lost 352,800 joules of potential energy.
b) The kinetic energy gained by the car can be calculated using the formula:
Kinetic energy gained = [tex](1/2) * m * (v^2 - u^2)[/tex]
where:
m = mass of the car (1200 kg)
v = final velocity (23 m/s)
u = initial velocity (11 m/s)
Kinetic energy gained = (1/2) * 1200 kg * ((23 m/s)^2 - (11 m/s)^2) = 228,600 J
Therefore, the car gained 228,600 joules of kinetic energy.
c) The energy that is unaccounted for can be calculated by subtracting the gained kinetic energy from the lost potential energy:
Energy unaccounted for = Potential energy lost - Kinetic energy gained
Energy unaccounted for = 352,800 J - 228,600 J = 124,200 J
Therefore, there is 124,200 joules of energy that is unaccounted for.
d) This unaccounted energy could be attributed to other forms of energy, such as energy dissipated due to friction and air resistance, or heat generated during the acceleration process. It represents the energy that is not transferred into the car's kinetic energy but is instead lost to other factors in the system.
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At orbital velocity around the Earth, the gamma factor is 1.000000000338. Russian cosmonaut Valery Polyakov spent 438 consecutive days orbiting the Earth on the Mir Space station. If he left a stopwatch running on Earth and took an identical stopwatch running with him on Mir, what would be the difference in elapsed time over the duration of his flight.
Answer Choices,
120 s
3.0 s
1.3 E−2 s
2.5 E−1 s
Answers
Answer:
The time dilation effect can be calculated using the time dilation formula, which is derived from the theory of special relativity. The formula is: Δt' = Δt / √(1 - v²/c²), where Δt is the time interval measured by a stationary observer, Δt' is the time interval measured by an observer in motion, v is the relative velocity between the two observers, and c is the speed of light.
In this case, Valery Polyakov spent 438 consecutive days orbiting the Earth on the Mir Space station at an orbital velocity where the gamma factor is 1.000000000338. The gamma factor is equal to 1 / √(1 - v²/c²), so we can solve for v²/c² = 1 - (1 / gamma)² = 2.28 x 10⁻¹⁸. Plugging this into the time dilation formula, we get that Δt' = Δt / √(1 - 2.28 x 10⁻¹⁸) ≈ Δt (1 + 1.14 x 10⁻¹⁸).
The time interval measured by a stationary observer on Earth is 438 days * 24 hours/day * 60 minutes/hour * 60 seconds/minute = 37,843,200 seconds. Plugging this into the formula above, we get that Δt' ≈ 37,843,200 seconds (1 + 1.14 x 10⁻¹⁸) ≈ 37,843,200.000043 seconds.
Therefore, the difference in elapsed time between the stopwatch on Earth and the stopwatch on Mir over the duration of Valery Polyakov's flight would be approximately 0.000043 seconds or **4.3 x 10⁻⁵ seconds**. This answer is not among the answer choices you provided.
Answer:
1.3 E-2 s
Explanation:
Δt' = 438 days * 1.000000000338
Δt' = 438.00000000044484 days
Therefore, the difference in elapsed time between the stopwatch on Earth and the stopwatch on the Mir Space station over the duration of Valery Polyakov's flight would be approximately 0.00000000044484 days (or about 38.4 microseconds). 0.0384 seconds is closest to "1.3 E−2 s"
You are a traffic engineer planning a new roundabout. You expect cars to be drving through it with a speed of 7m/s. For the purposes of comfort and safety, you want the lateral acceleration to be no larger than 2.9m/s². How big across should the roundabout be? (Hint: how big across)
Answers
Answer: The roundabout should be about 16.7 meters across.
Explanation: To find the diameter of the roundabout, we need to use the formula for lateral acceleration, which relates the velocity, radius and lateral acceleration of an object moving in a circular path. The formula is:
LAT = v^2 / r
where: LAT is the lateral acceleration, v is the velocity of the object or vehicle, and r is the radius of the curve.
In this formula, the lateral acceleration is directly proportional to the square of the velocity and inversely proportional to the radius of the curve.
We are given that the speed of the cars is 7 m/s and the lateral acceleration should be no larger than 2.9 m/s^2. We can plug these values into the formula and solve for r:
2.9 = 7^2 / r r = 7^2 / 2.9 r ≈ 16.7
This means that the radius of the roundabout should be about 16.7 meters. To find the diameter, we simply multiply the radius by 2:
d = 2 * r d = 2 * 16.7 d ≈ 33.4
Therefore, the diameter of the roundabout should be about 33.4 meters, and the roundabout should be about 16.7 meters across.
Hope this helps, and have a great day! =)
400 kg cart with rubber wheel just stopped in a while asphalt road because it ran out of gas attractive attaches a route to the golf cart to tow it in Post Achurr down the road accelerating the golf cart at three Emperor a Square what is the tension in the rope
Answers
To solve this problem, we will use Newton's second law of motion.
Newton's second law states that the force is equal to mass times acceleration.
Hence, the formula is as follows:Force = mass x acceleration
To calculate the force, we need to know the mass of the cart and the acceleration at which it is being towed.
As per the question, the cart's mass is 400 kg, and it is being accelerated at a rate of 3 m/s^2.
Hence, the force required to accelerate the cart can be calculated as follows:
Force = mass x acceleration [tex]Force = 400 kg\times3 m/s^2[/tex]
[tex]Force = 1200 N[/tex]
Therefore, the tension in the rope is 1200 N.
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a stone falls From rest From the Top of a Higher tower. Ignore Air resistance and take g=9.8m/s2. calculate:
a. speed of the stone after 2 seconds
b. how far the stone has travelled after 2 seconds
Answers
a)It takes 0 seconds for the stone to hit the ground.
b)The stone has traveled 19.6 meters after 2 seconds.
When an object is dropped from a height, the motion is described as free fall. It is a special form of motion in which an object is under the sole influence of gravity. The gravitational force acting on an object is always directed towards the center of the Earth, i.e., downwards. Therefore, when an object is dropped from a height, it falls freely towards the ground, and the acceleration of the object is equal to the acceleration due to gravity, which is approximately 9.8 m/s².
In the problem given, a stone is dropped from rest from the top of a higher tower. Therefore, the initial velocity of the stone, u = 0 m/s.
a. Time taken by the stone to reach the ground:
We can use the following equation of motion to calculate the time taken by the stone to reach the ground.
v = u + at
where,
v = final velocity of the object
u = initial velocity of the object
a = acceleration of the object
t = time taken by the object to reach from initial velocity to final velocity
Since the stone is dropped from rest, the initial velocity of the stone, u = 0 m/s.
At the ground level, the final velocity of the stone, v = ?
Again, the acceleration due to gravity, a = 9.8 m/s².
Therefore, we can write the equation as:
v = u + at
v = 0 + 9.8×t
v = 9.8t m/s
When the stone hits the ground, the final velocity of the stone, v = 0 m/s.
Therefore, we can rewrite the equation as:
0 = 9.8t
t = 0 seconds (when the stone is at the top of the tower)
We have found that it takes 0 seconds for the stone to hit the ground.
b. How far the stone has travelled after 2 seconds:
We can use the following equation of motion to calculate how far the stone has travelled after 2 seconds.
s = ut + (1/2)at²
where,
s = displacement of the object
u = initial velocity of the object
a = acceleration of the object
t = time taken by the object to reach from initial velocity to final velocity
Since the stone is dropped from rest, the initial velocity of the stone, u = 0 m/s.
The acceleration due to gravity, a = 9.8 m/s².
Therefore, we can write the equation as:
s = ut + (1/2)at²
s = 0×2 + (1/2)×9.8×(2)²
s = 19.6 m
Therefore, the stone has traveled 19.6 meters after 2 seconds.
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Pls helppp
Bumper car A (281 kg) moving +2.82 m/s
makes an elastic collision with bumper
car B (265 kg) moving -1.72 m/s. What is
the velocity of car A after the collision?
V
(Unit = m/s)
Remember: right is +, left is -
Enter
Answers
Explanation: For some reason, it would not let me click the "ADD YOUR ANWER" button, because it stated that my answer had some sort of "Inappropriate" word or something, so instead I attached two images of the answer that I had written down.
