The increase in tension on the steel wire is 8,484.75 N.
The given parameters;
original length of the wire, l = 8 mradius of the wire, r = 2 mmThe area of the steel wire is calculated as follows;
[tex]A = \pi r^2\\\\A = \pi \times (2\times 10^{-3})^2\\\\A = 1.257 \times 10^{-5} \ m^2[/tex]
The extension of the steel wire is calculated as follows;
[tex]\Delta l = \alpha \times l\times \Delta T\\\\\Delta l = (12\times 10^{-6}) \times (8) \times (10 + 273)\\\\\Delta l = 0.027 \ m[/tex]
The increase in tension on the steel wire is calculated as follows;
[tex]E = \frac{stress}{strain } = \frac{\ F/A}{\Delta l/l} \\\\E = \frac{F\times l}{A \times \Delta l} \\\\F = \frac{E\times A \times \Delta l }{l} \\\\F = \frac{(2\times 10^{11}) \times (1.257\times 10^{-5})\times 0.027}{8} \\\\F = 8,484.75 \ N[/tex]
Thus, the increase in tension on the steel wire is 8,484.75 N.
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Look up the specs on a c6 rocket engine. How many C6 engines would it take to launch Mr. Blazey (90kg)
from the elevation of Boulder to the elevation of longs peak? (3 points) What would the max power be? (3
points) The max acceleration? (3 points) For all 12 points, you'll need to account for the mass of the added
rockets (you can assume their mass declines linearly over their burn and is O after they finish burning).
Answer:
The Estes C6-0 engine is a booster stage engine designed for model rocket flight and has to be used with a standard engine. This engine is for flights in rockets weighing less than 4 ounces, including the engines. Each package includes 3 engines, 4 starters and 4 plugs.
a An object is tarown up with a velocity v = 6.02 +7.0j. Calculate the (1) time taken reach the maximum height (ii) the horizontal range (s = 10m/s2).
Answer:
(i) 0.6s (ii) 8.42m
Explanation:
U² = 6.02² + 7²
U = 9.23
angle of projection
tanø = 6.02/7
ø = 40.7
Time of fligt
t = Usinø/g
t = 9.23 sin 40.7/10
t = 0.6
H range = U²sin2ø/g
H = 9.23²sin 81.4/10
H = 8.42m
The time taken reach the maximum height is 0.6s and the horizontal range is 8.42m.
What is Velocity?Velocity is defined as the directional motion of an object which is indicated by the rate of change of position as observed from a particular frame of reference. It is measured by a particular standard of time. It is a vector quantity as it has both magnitude and direction.
It can be expressed as:
v= d/t
Where. v is the velocity in m/s
d is the displacement measured in meter 'm'
t is the time measured in seconds 's'
For above given information,
v = 6.02 +7.0j, so the initial velocity will be u
u² = 6.02² + 7²
u = 9.23m/s
Angle of projection, tanø = 6.02/7
ø = 40.7
Time taken= t = u sinø/g
t = 9.23 sin 40.7/10
t = 0.6s
Horizontal range = u²sin2ø/g
H = 9.23²sin 81.4/10
H = 8.42m
Thus, the time taken reach the maximum height is 0.6s and the horizontal range is 8.42m.
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A weather forecaster uses a computational model on a Monday to predict the weather on Friday. Why might that forecast change? (1 point)
A. The forecaster may have done the calculations a second time because he made a mistake in the calculation.
B. Someone may have reported the weather incorrectly before the first computation.
C. The forecaster may have had the computer model do the calculations a second time, and he found that the prediction changed.
D. An area of low pressure might move more quickly on Tuesday and Wednesday than expected.
Answer:
D. An area of low pressure might move more quickly on Tuesday and Wednesday than expected.
Explanation:
I took the test and got it wrong :/
What is the acceleration of a box weighing 596 N if a force of 777 N is applied to it?
Answer:
[tex]12.79 m/s^2[/tex]
Explanation:
1. Apply Newton's 2nd law:
[tex]F=ma[/tex]
2. Use the definition of weight to find the mass of the box:
[tex]W=mg=m=\frac{W}{g}[/tex]
3. Solve for acceleration in Newton's 2nd law and substitute for mass:
[tex]a=\frac{F}{\frac{W}{g} }[/tex]
4. Plug in the given values from the question and assume [tex]g=9.81m/s^2[/tex]:
[tex]a=\frac{777N}{\frac{596N}{9.81m/s^2} } } =12.79m/s^2[/tex]
organize the three states of matter from least kinetic energy to greatest kinetic energy
Particle arrangement and movement
⇒ In terms of relative energy, gas particles have the most energy, solid particles have the least energy and liquid particles are somewhere in between. (All compared at the same temperature.)
- BRAINLIEST answerer
A tow truck pulls a car 5.00 km along a horizontal roadway using a cable having a tension of 850 N. (a.) How much work does the cable do on the car if it pulls horizontally? If it pulls at 35.0° above the horizontal? (b.) How much work does the cable do on the tow truck in both cases of part (a)? (c.) How much work does gravity do on the car in part (a)?
I think 1980is the answer because you add???
Identify:
In each case the forces are constant and the displacement is along a straight line, so
[tex]$$W=F s \cos \phi \text {. }$$[/tex]
Set-Up:
In part (a), when the cable pulls horizontally [tex]$\phi=0^{\circ}$[/tex] and when it pulls [tex]$35.0^{\circ}$[/tex] above the horizontal [tex]$\phi=35.0^{\circ}$[/tex]. In part (b), if the cable pulls horizontally[tex]$\phi=180^{\circ}$[/tex]. If the cable pulls on the car [tex]$35.0^{\circ}$[/tex] above the horizontal it pulls on the truck at below the horizontal and [tex]$\phi=145.0^{\circ}$[/tex]. For the gravity force [tex]$\phi=90^{\circ}$[/tex], since the force is vertical and the displacement is horizontal.
Execute:
(a) When the cable is horizontal, [tex]$W=(850 \mathrm{~N})\left(5.00 \times 10^{3} \mathrm{~m}\right) \cos 0^{\circ}=4.25 \times 10^{6} \mathrm{~J}$[/tex].
When the cable is[tex]$35.0^{\circ}$[/tex] above the horizontal,[tex]$W=(850 \mathrm{~N})\left(5.00 \times 10^{3} \mathrm{~m}\right) \cos 35.0^{\circ}=3.48 \times 10^{6} \mathrm{~J}$[/tex].
(b)[tex]$\cos 180^{\circ}=-\cos 0^{\circ}$[/tex] and [tex]$\cos 145.0^{\circ}=-\cos 35.0^{\circ}$[/tex],
So the answers are [tex]$-4.26 \times 10^{6} \mathrm{~J}$[/tex] and [tex]$-3.48 \times 10^{6} \mathrm{~J}$[/tex].
(c) Since [tex]$\cos \phi=\cos 90^{\circ}=0, W=0$[/tex] in both cases.
Evaluate: If the car and truck are taken together as the system, the tension in the cable does no net wnetwork
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50 points please help ASAP! !
What is the average velocity of an object that moves from 6 meter to 2 meter relative to origin in 2 second?
[tex]\\ \rm\rightarrowtail Avg\: velocity=\dfrac{Total\: Displacement }{Total\: time}[/tex]
[tex]\\ \rm\rightarrowtail Avg\: velocity=\dfrac{4}{2}=2m/s[/tex]
what are the greenhouse gasses in the earth that are primarily responsible for the greenhouse effect on Earth
Answer:
Water Vapour, Carbon dioxide, methane,nitrous oxide,ozone.
3. What is Newton's 1st Law?
A For every action there is an equal and opposite reaction
B. Acceleration depends on two variables, the mass of the object and the amount of
force
C. An object at rest will stay at rest, an object in motion will stay in motion, unless an
unbalanced force acts upon it.
O D. The amount of matter in an object
Answer:
A
Explanation:
for every action there is an equal and opposite reaction
PLEASE HELP ME GET THIS RIGHT
Explanation:
I'm not sure, but I would go for the more than A since its orbital speed is at its fastest and the sweep occurs in about the same period of days.
Identify the direction of the net force acting on the object. Explain your reasoning
Answer:
See Below
Explanation:
I am not sure what you exact question is to know what direction it is but here is how you do it.
The direction of the net force is the direction of the largest force.
for example if you were to push a box forward with 100 newton's of force and someone pushed at the same time 50 newton's backwards on the box, the box would move forwards because the was a greater force on the box in a forward direction. hope this helps
i need help with these please
Answer:
Explanation:
I was in Anchorage Alaska during the Summer Solstice. The sun rose around 3am and set around 1 am the next day-- almost 24 hours of sunlight. If the tilt of the Earth was changed to be 10 degrees, how would the length of daylight in Alaska change at the Summer Solstice
Answer:
Daylight hours would be shorter.
Explanation:
If there were no tilt of the axis at all, every place on the planet except the north and south poles would have 12 hours of daylight and 12 hours of night every day of the year.
At a 10° tilt, the arctic circle and antarctic circles would be a little less than half the distance from the poles as they are today.
A phone is dropped from the roof of the school building. The building is 13.2 meters high. How long was the phone in the air before it crashed on the ground?
Answer:
5scs
Explanation:
phones fall fast so i guessed
Harriet is practicing archery. As she draws back an arrow, the arrow has LaTeX: 34.3 J of elastic potnetial energy, and LaTeX: 0.40 J of gravitational potential energy. How much kinetic energy will the arrow have when it is about to hit the ground?
The kinetic energy of the arrow when it is about to hit the ground is 34.7 J.
The given parameters;
elastic potential energy of the arrow, Ux = 34.3 Jgravitational potential energy, P.E = 0.4 JAccording the principle of conservation of energy, the total potential energy of the arrow will be converted to maximum kinetic energy when the arrow is about to hit the ground.
[tex]K.E = P.E + U_x\\\\K.E = 34.3 \ J \ + \ 0.4 \ J\\\\K.E = 34.7 \ J[/tex]
Thus, the kinetic energy of the arrow when it is about to hit the ground is 34.7 J.
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a mass of 7.5kg has a weight of 30n on a certain planet calculate the acceleration due to gravitt on this planet
Answer:
Acceleration due to gravity on a certain planet = 4 m/s²
Explanation:
According to the question,
Weight = 30 N
Mass = 7.5 kg
Let acceleration due to gravity be 'a'
Formula:
Weight = Mass × Acceleration due to gravity
30 = 7.5 × a
a = 30/7.5
a = 4 m/s²
An object with mass 1.2 kg is moving at a constant speed in a circle with radius 2.5 m. If the
object makes exactly 12 revolutions in a 1 minute, what is the acceleration of the object?
Answer:
3.9m/s² is the acceleration
The acceleration of the object is 3.9m/s².
How do you find the acceleration of an object?Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2).
What is an example of an object that has acceleration?When you fall off a bridge. The car turning at the corner is an example of acceleration because the direction is changing. The quicker the turns, the greater the acceleration.
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Which is the best way to avoid plagiarism? O use more than one source from your research O repeat information from your sources O present a topic in your own words O understand your topic before you begin writing
Answer:
O present a topic in your own words
Explanation:
Plagiarism is using someone else's words or work without giving them proper credit. Presenting a topic in your own words means you are not copying anyone.
Answer:
present a topic in your own words
Explanation:
What is the angle θ between vectors A⃗ and B⃗ if A⃗ =4ı^−4ȷ^ and B⃗ =−5ı^+7ȷ^?
The characteristics of the scalar product allows to find the angle between the two vectors is:
The angle θ = 170º
The scalar product is the product between two vectors whose result is a scalar.
A . B = |A| |B| cos θ
Where A and B are the vectors, |A| and |B| are the modules of the vectors and θ at the angle between them.
The vector is given in Cartesian coordinates and the unit vectors in these coordinates are perpendicular.
i.i = j.j = 1
i.j = 0
A . B = (4 i - 4j). * -5 i + 7j)
A . B = - 4 5 - 4 7
A. B = -48
We look for the modulus of each vector.
|A| = [tex]\sqrt{x^2 +y^2 }[/tex]
|A| = [tex]\sqrt{4^2 + 4^2}[/tex]
|A| = 4 √2
|B| = [tex]\sqrt{5^2 +7^2}[/tex]
|B| = 8.60
We substitute.
-48 = 4√2 8.60 cos θ
-48 = 48.66 cos θ
θ = cos⁻¹ [tex]\frac{-48}{48.664}[/tex]
θ = 170º
In conclusion using the dot product we can find the angle between the two vectors is:
the angle θ = 170º
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How much heat must be removed from 1.61 kg of water at 0 ∘C to make ice cubes at 0 ∘C?
Answer:
Explanation:
All
Starting from rest, a racecar moves 112 m in the first 7 s of uniform acceleration. What is the car's acceleration?
Answer:
215mph
Explanation:
multiply 112milws by 2 and multiple that by seven, then divide it by two
define moment of a force about a point and give the si unit of moment?
Answer:
Moment of a force is the product of the force and the perpendicular distance of force from axis of rotation.
The SI unit of force is newton (N).
Explanation:
Hope it helps you again!
Emily sees a ship traveling at a constant speed along a straight section of a river. She walks parallel to the riverbank at a uniform rate faster than the ship. She counts equal steps walking from the back of the ship to the front. Walking in the opposite direction, she counts steps of the same size from the front of the ship to the back. In terms of Emily's equal steps, what is the length of the ship
The length of the ship in terms of Emily's equal steps is 84.
The given parameters;
equal steps forward = 210equal steps backward = 42Defined parameters:
Let the constant velocity of the ship = VLet the velocity of Emily = VsLet the length of the ship = dLet the time of motion, = tThe velocity of Emily when moving forward in the direction of the ship:
[tex]V_s_1 = \frac{210}{t}[/tex]
The velocity of Emily when moving in opposite direction to the ship:
[tex]V_s_2 = \frac{42}{t}[/tex]
The constant velocity of the ship:
[tex]V = \frac{d}{t}[/tex]
Apply relative velocity formula to determine the length of the ship:
For forward (same direction) motion:
[tex](V_s_1 - V)t = d[/tex]
For backward (opposite direction) motion:
[tex](V_s_2 + V)t = d[/tex]
[tex](V_s_1 - V)t = (V_s_2 + V)t\\\\V_s_1 - V = V_s_2 + V\\\\\frac{210}{t} - \frac{d}{t} = \frac{42}{t} + \frac{d}{t} \\\\\frac{210}{t} - \frac{42}{t} = \frac{d}{t} + \frac{d}{t} \\\\\frac{210 - 42}{t} = \frac{d+ d}{t} \\\\\frac{168}{t} = \frac{2d}{t} \\\\2d = 168\\\\d = \frac{168}{2} \\\\d = 84[/tex]
Thus, we can conclude that the length of the ship in terms of Emily's equal steps is 84.
"Your question is not complete, it seems to be missing the following information;"
Emily sees a ship traveling at a constant speed along a straight section of a river. She walks parallel to the riverbank at a uniform rate faster than the ship. She counts 210 equal steps walking from the back of the ship to the front. Walking in the opposite direction, she counts 42 steps of the same size from the front of the ship to the back. In terms of Emily's equal steps, what is the length of the ship
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Given that T= [L] * [m] Y [Lt-2]Z
Find
1) Y
2)X
3)Z
Answer:
2
Explanation:
please mark me as brainlist i need it so sorry
How is aquatic biome classification different from terrestrial biome classification?
Answer: Terrestrial biomes are based on land, while aquatic biomes include both ocean and freshwater biomes.
Explanation:
A solid sphere starts from rest and rolls down a slope that is 6.4 m long. If its speed at the bottom of the slope is 5.3 m/s, what is the angle of the slope
From the relationship between acceleration a and g on an inclined plane, the angle of the slope is 13 degrees
Given that a solid sphere starts from rest and rolls down a slope that is 6.4 m long. The speed at the bottom of the slope is 5.3 m/s, the distance travelled is 6.4 m. That is,
Initial velocity U = 0 ( since it starts from rest)
Final velocity V = 5.3 m/s
distance S = 6.4 m
Let us first calculate its acceleration by using third equation of motion.
[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2aS
[tex]5.3^{2}[/tex] = 0 + 2 x 6.4a
28.09 = 12.8a
a = 28.09 / 12.8
a = 2.2 m / [tex]s^{2}[/tex]
To calculate the angle of the slope, let us use the relationship between acceleration a and g on an inclined plane.
acceleration a = gsin∅
substitute all the relevant parameters
2.2 = 9.8 sin∅
sin∅ = 2.2/9.8
sin∅ = 0.224
∅ = [tex]Sin^{-1}[/tex](0.224)
∅ = 12.97 degrees
∅ = 13 degrees (approximately)
Therefore, the angle of the slope is 13 degrees
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A 67 kg soccer player uses 5100 kJ of energy during a 2.0 h match. What is the
average power produced by the soccer player?
The average power produced by the soccer player is 710 Watts.
Given the data in the question;
Mass of the soccer player; [tex]m = 67kg[/tex]Energy used by the soccer player; [tex]E = 5100KJ = 5100000J[/tex]Time; [tex]t = 2.0h = 7200s[/tex]Power; [tex]P =\ ?[/tex]
Power is simply the amount of energy converted or transferred per unit time. It is expressed as:
[tex]Power = \frac{Energy\ converted }{time}[/tex]
We substitute our given values into the equation
[tex]Power = \frac{5100000J}{7200s}\\\\Power = 708.33J/s \\\\Power = 710J/s \ \ \ \ \ [ 2\ Significant\ Figures]\\\\Power = 710W[/tex]
Therefore, the average power produced by the soccer player is 710 Watts.
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Which is NOT a function of the
cell wall?
A. Protects cell from bursting
B. Provides support for plant cells
C. Protects cell from harsh internal
environments
D. Absorbs sunlight to give energy to the cell
Answer:
The answer is D
Explanation:
The chloroplast absorbs sunlight for energy not the cell wall
A pumpkin is shot upwards at a speed of 15.5 m/s from the ground and lands on a 3.00m
high platform. How long before it hits and smashes?
Answer:
0.2seconds
Explanation:
Speed=distance/time
15.5m/s=3.00m/x seconds
x=3/15.5
x=0.1935
x=0.2sec
hope this helped
SOMEONE HELP! If I don't get this done i will fail, I have been trying for hours.
p.s. both questions have no answer choices.
1. If a baseball has a mass of 0.075kg and is traveling with an acceleration of 25 m/s2. What is the force that the baseball will hit the bat?
````````````````````````````````````````
2. Given the force diagram of the basketball, what can you tell about the basketball motion? (Diagram below)
Thanks in advance!!
Answer:
1. The baseball will hit the bat at a force of 1.875 Newtons (N)
2. The basketball is being pushed to roll to the right of its original position with an applied rightward force. There is a force of friction to the left, a normal force of the floor acting upwards on the ball, and a gravity force of the Earth acting downwards on the ball.
Explanation:
1. To calculate force, you just have to multiply mass (m) and acceleration (a). F = m * a --> F = 0.075kg * 25 m/s^2 = 1.875 N.
2. Use your knowledge of different types of forces and free-body diagrams to come to this conclusion.
