a player catches a ball. consider the action force to be the impact of the ball against the player's glove. the reaction to this force is the friction of the ground against the player's shoes. player's grip on the glove. force the glove exerts on the ball. muscular effort in the player's arms. none of these
The reaction to this force is force the glove exerts on the ball.
When a player catches the ball, what kind of force is this?
Frictional force allows the ball to stay in the hand while muscular force is employed to stop the motion of the ball during catching.
First, second, and third laws of motion of Newton :According to the first law, until a force acts on an item, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction pressures upon one another.
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a hamster runs at a speed of 13 centimeters per second in a wheel of radius 14 centimeters. a) what is the angular velocity of the wheel? (in radians/sec) incorrect radians/sec correctradians/sec no decimals allowed. b) how fast will the wheel spin in revolutions per minute? incorrect rev/min correctrev/min no decimals allowed.
The angular velocity of the wheel is 0.9286 radians/sec and the number of revolutions per minute is 8.84 rpm
The angular velocity of the wheel in radians per second is given by the formula:
ω = v/r where ω is the angular velocity in radians per second, v is the linear velocity in cm/s, and r is the radius of the wheel in cm.
Therefore, the angular velocity of the wheel is:
ω = 13 cm/s / 14 cm = 0.9286 radians/sec
To calculate the revolutions per minute (rpm), we use the formula:
rpm = ω * 60 / (2π)
where 2π is the number of radians in a full revolution.
Therefore, the wheel will spin at a rate of:
rpm = 0.9286 radians/sec * 60 / (2π) = 8.84 rpm
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What kind of motion does a torque tend to impart to an object?
A torque tends to impart rotational motion to an object and is responsible for keeping the object in rotation.
Torque in rotational motion is the same as force in linear motion. It is the main factor that maintains an object's rotation. An object rotates at an acceleration inversely proportional to its moment of inertia when a torque is applied to it. Torque is mathematically determined by:
Γ= Ia
where, I is the moment of inertia and a is the acceleration with which the object rotates. Torque has both magnitude and direction and is, thus, a vector quantity. Torque is expressed in Newton metre or Nm.
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a 2 coulomb charge is moved from a to b in the presence of an electric field created by other charges. the potential energy when the charge is at point b is 30 j higher then the potential energy when the charge was at a. the voltage (created by the other charges) at point a was 10 volts. what is the voltage at point b?
When the charge is at point b, the potential energy is 30 j, and the voltage produced at point b by the other charges is 25 volts.
We can use the formula for potential energy in an electric field to relate the change in potential energy to the difference in voltage between the two points:
ΔU = qΔV
here,
ΔU is change in potential energy,
q is charge, and
ΔV is difference in voltage.
We are given that
q = 2 C, and
That the change in potential energy
= ΔU = 30 J.
Therefore, we can solve for the difference in voltage between points a and b:
ΔV = ΔU / q
ΔV = 30 J / 2
ΔV = 15 V
This means that the voltage at point b is
10 V + 15 V = 25 V,
because the potential energy when the charge is at point b is 30 J higher than at point a.
Therefore, the voltage created by the other charges at point b is 25 volts.
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which of the following statements concerning the motion of a physical pendulum is incorrect? responses the period is changed if the mass of the bob is doubled and the length of the pendulum is halved the period is changed if the mass of the bob is doubled and the length of the pendulum is halved the time interval between conditions of maximum potential energy is one period. the time interval between conditions of maximum potential energy is one period. the kinetic energy is a minimum when the displacement is a maximum. the kinetic energy is a minimum when the displacement is a maximum. the acceleration is a maximum when the displacement is a maximum
The statement that is incorrect is: The time interval between conditions of maximum potential energy is one period.
The time interval between conditions of maximum potential energy is not always one period. The period of a pendulum is the time it takes for the pendulum to complete one full cycle of motion, which is determined by the length of the pendulum and the acceleration due to gravity. The time interval between conditions of maximum potential energy depends on the initial conditions of the pendulum, such as the initial angle and the initial velocity. If the initial angle or the initial velocity is changed, then the time interval between conditions of maximum potential energy will change as well.
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at time t 0, the velocity is (4.00 m/s)i. what are the (a) magni- ilw tude and (b) angle of its velocity when it has been displaced by 12.0 m parallel to the x axis? a moderate wind accelerates a pebble over a horizontal xy plane with a constant acceleration .
(a) magnitude of the final velocity is 11.94 m/s, and the (b) angle of the final velocity with respect to the positive x-axis is 37.1°.
We can tackle this issue utilizing kinematic conditions. Since the speed increase is consistent, we can utilize the accompanying conditions:
v = u + at
s = ut + 1/2 [tex]at^2[/tex]
[tex]v^2 = u^2[/tex] + 2as
where u is the underlying speed, v is the last speed, t is the time, s is the dislodging, and an is the speed increase.
Given: u = 4.00 m/s I, a = 5.00[tex]m/s^2[/tex] I + 7.00 [tex]m/s^2[/tex] j, s = 12.0 m lined up with the x-pivot.
Utilizing the second kinematic condition, we can address for the time taken to venture to every part of the distance:
s = ut + 1/2 [tex]at^2[/tex]
12.0 = 4.00t + 1/2 (5.00)[tex]t^2[/tex]
5.00[tex]t^2[/tex] + 4.00t - 12.0 = 0
Settling for t utilizing the quadratic recipe, we get:
t = 1.09 s (taking the positive root)
Utilizing the first kinematic condition, we can tackle for the last speed in the x-course:
v_x = u_x + a_x t
v_x = 4.00 + 5.00(1.09)
v_x = 9.45 m/s
Utilizing the Pythagorean hypothesis, we can track down the greatness of the last speed:
|v| = sqrt([tex]v_x^2 + v_y^2[/tex])
|v| = sqrt(([tex]9.45)^2[/tex] + ([tex]7.00)^2[/tex])
|v| = 11.94 m/s
Utilizing the reverse digression capability, we can track down the point of the last speed regarding the positive x-hub:
θ = [tex]tan^(- 1)[/tex](v_y/v_x)
θ = [tex]tan^(- 1)[/tex](7.00/9.45)
θ = 37.1°
Thusly, the (a) magnitude of the last speed is 11.94 m/s, and the (b) angle of its velocity as for the positive x-pivot is 37.1°.
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The complete question is:
A moderate wind accelerates a pebble over a horizontal xy plane with a constant acceleration
a=(5.00m/s 2) i^+(7.00m/s 2) j^ .
At time t=0, the velocity is (4.00m/s) i ^.What are the (a) magnitude and (b) angle of its velocity when it has been displaced by 12.0m parallel to the x axis?
a system containing 1 atm of an ideal gas is doubled in temperature and halved in volume. what is the new pressure?
The amount of moles of gas n=RT PV using the Ideal gas equation
P ′ = 2P new pressure
T ′ = 2T new temperature
V ′ =V/2 new volume
Hence, the number of moles of gas n ′ = (2P)/(V/2) / R(2T) (2P)(V/2) = n/2
When all other variables are held constant, pressure is directly proportional to force (F) and inversely proportional to area (A). As a result, when Area A is doubled, the pressure is cut in half. Area A is cut in half. The pressure P has been doubled. At STP (standard temperature, 273.15 K and pressure, 1 atm), the volume of 1.00mol of any gas is measured to be 22.414L. 1 atm equals 760 mm Hg. The Pascal, on the other hand, is the standard international unit for pressure. 1 atm Equals 101325 Pa. The English physicist Robert Boyle conducted a series of pressure tests and arrived at a general law—that the volume of a gas varies inversely with pressure—in 1662. PV stands for constant.
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if both the speed and stopping distance of a driver are doubled, by what factor does the force exerted on the driver change? g
If both the speed and stopping distance of a driver are doubled, the force exerted on the driver will be reduced by a factor of 2 (or 50%).
The force exerted on the driver when stopping a car is given by the formula:
[tex]F = (mv^2) / (2d)[/tex]
Where:
m = mass of the car
v = velocity of the car before braking
d = stopping distance
If both the speed and stopping distance of the car are doubled, then the new velocity and stopping distance will be 2v and 2d, respectively. Therefore, the new force exerted on the driver will be:
[tex]F' = (m(2v)^2) / (2(2d))[/tex]
[tex]F' = (4mv^2) / (4d)[/tex]
[tex]F' = (mv^2) / d[/tex]
Comparing this to the original formula for force, we can see that the new force exerted on the driver is simply half of the original force:
[tex]F' = (mv^2) / d = 1/2 * (mv^2) / (1/2 * d) = 1/2 * F[/tex]
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After which action would the concentration of a solution remain constant?(1 point)
removing solution from the container
adding water to the solution
evaporating water from the container
adding solute to the solution
Answer:
The action that would cause the concentration of a solution to remain constant is removing solution from the container.
What is concentration of a solution?
The concentration of a solution is the measure of the amount of solid particles (solute) that has been dissolved in the given amount of a solvent.
Adding water to a solution will dilute the solution, hence changes the concentration of the solution.
Also, adding solute will change the concentration of the solution.
Thus, the action that would cause the concentration of a solution to remain constant is removing solution from the container.
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two oppositely-charged plates are set up in the lab, where the positive plate is placed north of the other plate. in which direction would the electric field lines between the plates be pointing of a diagram was drawn?
Answer:
Explanation:
an object's moment of inertia is 2.0 kg.m2. its angular velocity increases from 20 rad/s to 60 rad/s in 10 seconds. what is the net torque on the object?
The angular acceleration can be calculated using the formula α = (ωf - ωi) / t, where ωf is the final angular velocity, ωi is the initial angular velocity, and t is the time taken. Substituting the given values, the net torque on the object is found to be 8.0 N.m.
The moment of inertia of an object is a measure of its resistance to rotational motion and depends on its mass and distribution of mass. The angular velocity of an object is the rate at which it rotates around its axis and is measured in radians per second.
In this question, the moment of inertia of the object is given as 2.0 kg.m^2, and its angular velocity increases from 20 rad/s to 60 rad/s in 10 seconds. We need to find the net torque acting on the object during this time.
The net torque on the object can be calculated using the formula τ = Iα, where τ is the net torque, I is the moment of inertia, and α is the angular acceleration. The angular acceleration can be calculated using the formula α = (ωf - ωi) / t, where ωf is the final angular velocity, ωi is the initial angular velocity, and t is the time taken.
Substituting the given values,
we get α = (60 rad/s - 20 rad/s) / 10 s = 4.0 rad/s^2. Therefore, τ = Iα = 2.0 kg.m^2 x 4.0 rad/s^2 = 8.0 N.m. Hence, the net torque acting on the object is 8.0 N.m.
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what is the length l of the pipe? an air-filled pipe is found to have successive harmonics at 480 hz , 800 hz , and 1120 hz . it is unknown whether harmonics below 480 hz and above 1120 hz exist in the pipe. what is the length of the pipe?
Using the formula for the frequency of harmonics in an air-filled pipe, we can write:f_n = nv/(2L), where the pipe's length L, the air's sound speed (v), and harmonic number (n) are all variables.
What can be determined about the length of the pipe?Solving for L, we get:L = nv/(2f_n)For the third harmonic (n=3), we have:L = (3v)/(2f_3) = (3343 m/s)/(21120 Hz) = 0.137 m or 13.7 cm.
Using the given harmonic frequencies, we can determine the length of the pipe by applying the formula: wavelength = speed of sound / frequency.
From this, we can calculate the wavelengths of each harmonic and determine the ratio of their wavelengths. The ratio of the wavelengths will be in the form of 1:3:5 for the 1st, 2nd and 3rd harmonics respectively.
We can then use this ratio to determine the length of the pipe using the formula: length = wavelength x (n/2), where n is the harmonic number.
Therefore, the length of the pipe is approximately 13.7 cm. Using the given harmonic frequencies,
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Calculate the weight of an object of mass 15Kg kept on the earth. If the same object is taken to mars, what change will happen to its mass and weight?(freefall acceleration on mars=3.7 m/s2)
Answer:
Weight on Mars = 55.5 Newtons
Approximately 37.72% of weight on earth
Explanation:
Mass of an object is unchanged throughout the universe
Therefore mass on Mars = mass on Earth = 15kg
Weight = mass x freefall acceleration
Weight on Earth = 15 kg x 9.81 m/s² = 147.15 Newtons (N)
Weight on Mars = 15 x 3.7 m/s² = 55.5 N
Therefore weight on Mars/ weight on earth = 55.5 N/147.15N
≈ 0.3772
= 37.72 % of weight on earth
what is the magnitude of the force caused by air resistance, fr in newtons? (maintain the assumption that the truck's velocity is constant.)
The same as long as the other variables in the equation (Cd, A, and rho) remain unchanged.
What is variables?A variable is a symbolic name that represents a value that can be changed. Variables are used in programming to store values that can be used throughout the program or in specific functions. Variables can be any type of data including numbers, strings, Booleans, and objects.
The magnitude of the force caused by air resistance, fr, in Newtons is determined by the drag equation: fr = 0.5*Cd*A*rho*v^2, where Cd is the drag coefficient, A is the frontal area, rho is the density of the air, and v is the velocity. Since the truck's velocity is assumed to be constant, the magnitude of the force caused by air resistance (fr) will remain the same as long as the other variables in the equation (Cd, A, and rho) remain unchanged.
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on a scale in which the distance from the sun to the earth is about 15 meters, the distance from the earth to the moon is .
On a scale where the distance from Earth to the Sun is about 15 meters, the distance from Earth to the Moon is 38.54 millimeters .
Distance earth-sun= 149.6 x 10^9m
Distance earth-moon= 384.4 x 10^6m
It's the division between the distance earth-sun by the 15 meters:
149.6 x 10^9m / 15m = 9973333333m
Give us the number of meters in the scale equivalent to distance earth-moon.
384.4 x 10^6m / 9973333333m = 0.0385
Converting the answer to millimeters (knowing that 1m=1000mm)
= 38.54mm
Distance is a measure of the physical separation between two objects or locations. It is often described in terms of how far apart two points are from each other. In physics, distance is typically measured in units such as meters, kilometers, or miles.The concept of distance is important in many areas of study, including mathematics, physics, and geography.
Distance can be calculated using various methods, including using instruments such as rulers, tape measures, or GPS systems. It can also be estimated by using landmarks or other points of reference. The precise measurement of distance is crucial in many fields, from construction and engineering to astronomy and space exploration.It is used to determine the spatial relationship between objects or locations, and is often used to calculate travel times and navigation routes.
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Complete Question: -
On a scale where the distance from Earth to the Sun is about 15 meters, the distance from Earth to the Moon is __________.
a 30.0-kg child sits on one end of a long uniform beam with a mass 20.0 kg and a 40.0-kg child sits on the other end. the beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child. how long is the beam? 1.93 m 2.07 m 2.20 m 1.98 m 2.12 m
The length of beam such that the beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child is 2.07m
To calculate this, we can use the equation for moment of inertia:
We know that the M = (m1 × d1) + (m2 × d2)
Where m1 and m2 are the masses of the two children and d1 and d2 are the distances from the fulcrum to either child.
In this case, m1 = 30.0 kg, m2 = 40.0 kg, d1 = 1.10 m and d2 is the variable we are solving for.
So, we can rearrange the equation to solve for d2:
d2 = (M - (m1 × d1)) / m2
d2 = (0 - (30.0 kg × 1.10 m)) / 40.0 kg
d2 = -2.07 m
Therefore, the length of the beam is 2.07 m.
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knowing that the tension in cable ab is 155 lb and that the resultant of the load p and of the forces exerted at a by the two cables must be directed along oa, determine the magnitude of the load p.
Magnitude of the load p, the resultant of the load p and of the forces exerted at a by the two cables must be directed along is 16.22 lb.
In engineering, the word "load" is widely used to refer to the force applied to a surface or mass.
Tab = 155 lb
Tab = Tab λ ab
= 155 x (-48)i + 29j + 24k/61
Tab = (-121.92)i + 73.66j + 60.96 k
Tac = Tac λac
= -48/65Tac i + 25/65Tac j - 36/65Tac k
For resultant to be directed along OA i.e x-axis
Tac = 110.06 lb
R = (-121.92lb i + 73.66lb j + 60.96lb k) + [-48/65Tac i + 25/65Tac j - 36/65Tac k]
To find the magnitude of P we take only J variable
73.66 + 25/65 Tac - P = 0
P = 73.66 + 25/65(110.66)
P = 16.22 lb is the magnitude of the load.
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a merry-go-round makes one complete revolution in 12.71 s. a 34.12 kg child sits on the horizontal floor of the merry-go-round 2.34 m from the center. what minimum coefficient of static friction is necessary to keep the child from slipping? the acceleration of gravity is 9.8 m/s 2 .
To prevent the kid from slipping, static friction needs to be at least 1 coefficient.
Examples of static friction are given below./A force called static friction prevents an object from moving along the path. This friction happens when two materials are slid over one another. Conflict is there all around us. For instance, when we walk, our feet are in contact with the ground.
Newton's second rule of motion can be used to calculate the amount of force needed to prevent the kid from slipping:
ΣF = ma
where ΣF is the sum of the forces acting on the child, m is the mass of the child, and a is the acceleration of the child. Since the child is not slipping, the force of static friction f must equal the force of gravity on the child Fg:
f = Fg
where Fg = mg, and g is the acceleration due to gravity.
The acceleration of the child can be expressed in terms of the angular acceleration of the merry-go-round, α, using the formula:
a = rα
where r is the distance of the child from the center of the merry-go-round.
The angular acceleration can be found from the time it takes for the merry-go-round to make one complete revolution, T, using the formula:
α = 2π / T
Substituting these values into the equations above, we get:
f = Fg
μs N = mg
μs mg = mg
μs = 1
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the nearest star is at a distance of 4.4 light-years. given that light travels at 300,000 km/s in space, how far away is the nearest star in kilometers (km)? (1 year
The nearest star is approximately 40.1 trillion kilometers away from us.
The nearest star is located 4.4 light-years away from us. Since one light-year is defined as the distance that light travels in one year and light travels at a speed of 300,000 km/s.
we can calculate the distance to the nearest star in kilometers by multiplying the speed of light by the number of seconds in a year and then multiplying by 4.4:
Distance to nearest star = 300,000 km/s * 60 seconds/minute * 60 minutes/hour * 24 hours/day * 365 days/year * 4.4 years
= 40,152,000,000,000 kilometers
Therefore, the nearest star is approximately 40.1 trillion kilometers away from us.
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A power line consists of two wires, each carrying a current of 400 A in the same direction. The lines are perpendicular to the earth’s magnetic field and are separated by a distance of 5. 0 m. Which is larger: the force of the earth’s magnetic field on each wire, or the magnetic force between the wires?
The magnetic force between the two wires is larger than the force of the Earth's magnetic field on each wire.
The magnetic force between the two wires is larger than the force of the Earth's magnetic field on each wire. The magnetic force between the two wires can be calculated using the formula
F = μ * I1 * I2 * L / 2 * d
here,
μ is magnetic constant
I1 and I2 are current of each wire,
L is length of each wire,
d is distance between the wires.
Reserving the values,
= F
= [tex]4 * \pi * 10^-^7 * 400 * 400 * 5 / 2 * 5[/tex]
= 0.16 N.
On the other hand, the force of the Earth's magnetic field on each wire can be calculated using the formula:-
F = μ * B * I * L,
here,
B is Earth's magnetic field strength.
Reserving the values,
= F
= [tex]4 * \pi * 10^-^7 * 5 * 10^-^5 * 400 * 5[/tex]
= 0.04 N.
Therefore, the magnetic force between the two wires is larger than the force of the Earth's magnetic field on each wire.
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Transcribed image text: 26) Light enters glass from air. The angle of refraction will be A) greater than the angle of incidence. B) equal to the angle of incidence. C) less than the angle of incidence. Answer: C 27) Water waves pass by a piece of cork floating on the water that bobs up and down on complete cycle each second. The waves are 2 meters long. What is the speed of the wave? A) 0.25 m/s B) 0.50 m/s C) 1.0 m/s D) 4 m/s E) 2 m/s 28) What kinds of waves can show interference? A) Only longitudinal waves show interference. B) Only waves that are out of phase with each other show interference. C) All waves show interference. D) Only transverse waves show interference. 29) If the index of refraction of a material is 2, this means that light travels A) 2 times as fast in air as it does in vacuum. B) 2 times as fast in the material as it does in air. C) 2 times as fast in vacuum as it does in the material. D) 2 times as fast in the material than it does in vacuum. E) 1/2 as fast in air as it does in the material. 30) Light having a speed in vacuum of 3.0 x 108 m/s enters a liquid of refractive index 2.0. In this liquid, its speed will be A) 6.0 × 108 m/s B) 3.0 × 108 m/s C) 1.5 × 108 m/s D) 0.75 x 108 m/s E) 0.67 × 108 m/s
(1) C) less than the angle of incidence. (2) C) 1.0 m/s (3) C) All waves show interference. (4) B) 2 times as fast in the material as it does in air. (5) D) 0.75 x 108 m/s
1. When light travels from a less dense medium (air) to a more dense medium (glass), it bends towards the normal. This causes the angle of refraction to be less than the angle of incidence.
2. The formula for the speed of a wave is v = fλ, where v is the speed, f is the frequency, and λ is the wavelength. The frequency is 1 cycle per second, and wavelength is 2 meters. The speed of the wave is v = 1 Hz x 2 m = 2 m/s.
3. Interference occurs when two or more waves meet and their amplitudes add together. This can occur with any type of wave.
4. The index of refraction of a material is the ratio of the speed of light in a vacuum to the speed of light in that material. If the index of refraction of a material is 2, this means that light travels 2 times as fast in a vacuum as it does in the material.
5. The speed of light in a medium is given by v = c/n, where v is the speed of light in the medium, c is the speed of light in a vacuum, and n is the refractive index of the medium. Substituting the given values, v = (3.0 x 10^8 m/s) / 2.0 = 1.5 x 10^8 m/s.
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--The complete question is, 1) Light enters glass from air. The angle of refraction will be
A) greater than the angle of incidence.
B) equal to the angle of incidence.
C) less than the angle of incidence.
2) Water waves pass by a piece of cork floating on the water that bobs up and down on complete cycle each second. The waves are 2 meters long. What is the speed of the wave?
A) 0.25 m/s
B) 0.50 m/s
C) 1.0 m/s
D) 4 m/s
E) 2 m/s
3) What kinds of waves can show interference?
A) Only longitudinal waves show interference.
B) Only waves that are out of phase with each other show interference.
C) All waves show interference.
D) Only transverse waves show interference.
4) If the index of refraction of a material is 2, this means that light travels
A) 2 times as fast in air as it does in vacuum.
B) 2 times as fast in the material as it does in air.
C) 2 times as fast in vacuum as it does in the material.
D) 2 times as fast in the material than it does in vacuum.
E) 1/2 as fast in air as it does in the material.
5) Light having a speed in vacuum of 3.0 x 108 m/s enters a liquid of refractive index 2.0. In this liquid, its speed will be
A) 6.0 × 108 m/s
B) 3.0 × 108 m/s
C) 1.5 × 108 m/s
D) 0.75 x 108 m/s
E) 0.67 × 108 m/s--
what must be the mass m2 of the hanging block if it is to descend 9.50 m in the first 3.00 s after the system is released from rest? express your answer with the appropriate units.
The mass [tex]m_{2}[/tex] of the hanging block is 20 kg.
A body of coherent matter, typically of undefined form and structure, or maybe even a grouping of incoherent components, components, or things viewed as comprising one body.
Suddenness of movements or operation; promptness; quickness as well as mechanical the measured or counted at which a body's position changes in a specific direction.
For this it is important to assume a tension value, otherwise, it is impossible to determine the value of mass m, in Newton's second law equation.
According to the question,
Initial velocity, [tex]$V_o=0 \mathrm{~m} / \mathrm{s}$[/tex]
Time, t = 3 sec
We know,
[tex]$\Rightarrow y=v_o \times t+0.5 \times a \times t^2$[/tex]
By substituting the values,
0.01 = [tex]0.5 \times a \times(3)^2 \\[/tex]
a = 0.0022 m / [tex]\mathrm{s}^2[/tex]
Hence, T- mg = ma
or,
[tex]$\Rightarrow m & =\frac{T}{g-a} \\[/tex]
[tex]$& =\frac{196}{9.81-0.00222} \\[/tex]
= 20 kg
Therefore the answer is 20 kg.
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the moon is decreasing in light between a full moon and a last quarter moon called___
The moon is decreasing in light between a full moon and a last quarter moon called the waning phase.
What is waning phase?
The waning phase is the third phase of the four phases of the moon. It takes place when the moon is visible in the night sky and its shape appears to be decreasing in size. During the waning phase, the moon is moving away from the Earth and its illuminated side is decreasing. This phase begins when the moon is a full moon and gradually decreases in size until it reaches new moon. During the waning phase, the moon is visible in the night sky during the evening hours and is visible as a thin crescent. This phase is also known as the "waning gibbous phase" or the "last quarter phase". During the waning phase, the moon is gradually getting darker and less illuminated until it reaches the new moon phase.
Therefore, The moon is decreasing in light between a full moon and a last quarter moon called the waning phase.
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which of the following does not accurately describe earth's distance from the sun? which of the following does not accurately describe earth's distance from the sun? earth is closest to the sun in january (perihelion). due to earth's circular orbit, it is always equidistant from the sun throughout the year. the earth-sun distance averages 150 million kilometers (93 million miles). it takes light an average of 8 minutes and 20 seconds to travel from the sun to earth. earth is farthest away from the sun in july (aphelion).
The following are incorrect estimates of Earth's distance to the Sun:
The earth constantly orbits the sun equally throughout the year because of its round orbit.it takes light an average of 8 minutes and 20 seconds to travel from the sun to earth. Explain the revolution of earth around sun?Revolution is the name for the earth's fixed orbital motion around the sun.
The Sun's gravitational force causes the Earth to revolve, creating an elliptical orbit.
An elliptical orbit is just a circle that has been flattened or has an extended route with two distinct foci. The eccentricity of the Earth's orbit, or how far from a circle it deviates from, is roughly 0.01671.According to the stars, the Earth orbits the sun in 365 days, 6 hours, and 9 minutes, rotating at a speed between 29.29 and 30.29 km/s. Every four year, which is known as a leap year, the 6 hours, 9 minutes add up to roughly one extra day, with February 29th being the added day. The eccentric orbit of Earth makes its closest point to a sun, or perihelion, on or around January 4th of every year. Six months later, at 152,100,000 km, is aphelion.Thus, the following are incorrect estimates of Earth's distance to the Sun:
The earth constantly orbits the sun equally throughout the year because of its round orbit.it takes light an average of 8 minutes and 20 seconds to travel from the sun to earth.To know more about the revolution of earth, here
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how much work does juanita do if she uses a force of 40 newtons to pull 2 friends on a wagon for 32 meters?
Juanita does 1280 joules of work to pull her 2 friends on the wagon over a distance of 32 meters with a force of 40 newtons.
To calculate the amount of work Juanita does, we need to use the formula:
Work = Force x Distance x cos(theta)
where:
Force: the amount of force applied (in newtons)
Distance: the distance the object is moved (in meters)
theta: the angle between the direction of the force and the direction of motion (in degrees)
In this case, Juanita applies a force of 40 newtons to pull the wagon with her 2 friends, over a distance of 32 meters.
We don't have information about the angle between the force and the direction of motion, but we can assume that the force is applied in the direction of motion (i.e., theta = 0 degrees).
Using this information, we can calculate the work Juanita does as follows:
Work = Force x Distance x cos(theta)
Work = 40 N x 32 m x cos(0)
Work = 1280 joules
Therefore, Juanita does 1280 joules of work to pull her 2 friends on the wagon over a distance of 32 meters with a force of 40 newtons.
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i] Observe the following picture and answer the given question which evidence of evolution is shown in above picture? what does this evidence indicate? give one more example of evidence of evolution.
The evolution that is shown in the picture that we have here is the evolution of humans from Chimpanzees.
What is evolution?
Evolution is the process by which species of living organisms change over generations through a combination of genetic variation, mutation, natural selection, and genetic drift. The theory of evolution explains how species have changed over time to become the diverse forms that exist today, and provides a scientific explanation for the relatedness of different species.
The evidence in the picture tells us that came to be through mutations and generic drift from the Chimpanzee.
An example of evolution would be: evidence that is gotten from fossils.
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what would the minimum value of the coefficient of static friction need to be for the system not to move when released from rest?
The minimum value of the coefficient of static friction necessary for the system not to move when released from rest would be 2 (10 N / 5 N = 2).
What is static friction?Static friction is the force that resists movement between two surfaces that are in contact with each other. It is the friction that acts to prevent movement between two objects, such as a car and the road, from taking place. This force is always present regardless of the objects’ motion and is perpendicular to the surfaces in contact. It is also known as stiction, sticky friction, limiting friction, or static coefficient of friction.
In order for an object to remain at rest when released from rest, the static friction force must be equal to or greater than the force of gravity acting on the object. Therefore, the minimum value of the coefficient of static friction necessary for the system not to move when released from rest is equal to the ratio of the force of gravity to the normal force between the two surfaces. This ratio is known as the static friction coefficient.
For example, if the force of gravity is 10 N and the normal force between the two surfaces is 5 N, the minimum value of the coefficient of static friction necessary for the system not to move when released from rest would be 2 (10 N / 5 N = 2).
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A child and a sled with a combined mass of 50.0 kg slide down a frictionless hill. If the sled starts from rest and has a speed of 9.0 m/s at the bottom, what is the height of the hill?
Answer:
297.38 meters
Explanation:
The height of the hill can be calculated using the principle of conservation of energy. This principle states that the total energy of a system is conserved, and that the change in potential energy of an object is equal to the work done on it.
The height of the hill can be calculated using the formula:
h = (1/2) m v^2 / g
where m is the mass of the child and sled, v is the final speed of the sled, and g is the acceleration due to gravity (9.8 m/s^2).
Plugging in the values, we get:
h = (1/2) * 50.0 kg * (9.0 m/s)^2 / 9.8 m/s^2
h = (1/2) * 50.0 kg * 81.0 m^2/s^2 / 9.8 m/s^2
h = 40.5 kg * 81.0 m^2/s^2 / 9.8 m/s^2
h = 2911.76 kg m^2/s^2 / 9.8 m/s^2
h = 297.38 m
So the height of the hill is 297.38 meters.
If a box of 11.54 kg is sliding down the ramp at an angle of 31.04 at a constant velocity, what is the force of friction acting on the box?
The frictional force acting on the box is just opposite to the normal force acting on the box by its weight. Here, the frictional force is,
What is friction ?Friction is a kind force that opposes the normal force acting on an object. The frictional force, is a resistive force having a negative sign always. The frictional force increases as the roughness of the surface through which the object is moving.
Here, the mass of the box m = 11.54 kg
angle of sliding = 31.04 °
acceleration due to gravity of earth = 9.8 m/s²
The frictional force that opposes the motion of the box sliding down the surface is just opposite to the normal force on the box by its own weight.
F = - mg cosθ
= - 11.54 kg × 9.8 m/s² × 31.04°
= -105.9 N
Therefore, the frictional force acting on the box is -105.9 N.
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The density equation is
ρ = m/v
The density of water is 1gram per 1milliliter of water. Written as 1g/1ml.
Use the density of water and the density equation to calculate the mass of 334 ml of water.
A 334 grams of water
B 334 grams/ml of water
C .003 grams/ml of water
D .003 grams of water
Answer:
We can use the density equation to find the mass of 334 ml of water.
Explanation:
Given that the density of water is 1 g/ml, we can substitute the values into the density equation:
ρ = m/v
ρ = 1 g/ml
v = 334 ml
So, m = ρ x v
m = 1 g/ml x 334 ml
m = 334 g
Therefore, the mass of 334 ml of water is 334 g, which is answer option A: 334 grams of water.
