The time required by the particles are as follows:
a. t = 1.5 seconds
b. t = 3 seconds
c. t = 0.4 seconds
What is the time required?The time required for the particles to be at several distances apart is calculated using the equation of motion given below:
[tex]S = ut + \frac{1}{2}at^{2}[/tex]
a) Time required to be 30 m apart:
Assuming the distance covered by P is S1 and distance covered by Q is S2.
S1 + S2 = 51 - 30
S1 + S2 = 21
Substituting the values of velocity and acceleration in the equation of motion above:
5t + 1/2t^2 + 6t + 3t^2 = 21
2t^2 + 11t - 21 = 0
Solving for time, t by factorization, t = 1.5 seconds
b) Time required to meet:
Assuming the distance covered by P is S1 and distance covered by Q is S2.
S1 + S2 = 51
Substituting the values of velocity and acceleration in the equation of motion above:
5t + 1/2t^2 + 6t + 3t^2 = 51
2t^2 + 11t - 51 = 0
Solving for time, t by factorization, t = 3 seconds
c) Time required for velocity of P is ¾ of the velocity of Q:
Using the equation of motion: V = u + at
Vp = 3/4 Vq
4Vp= 3Vq
Substituting the values:
4(5 + t) = 3(6 + 3t)
5t = 2
t = 0.4 seconds
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The velocity of the water jet discharging from the orifice can be obtained from v=\12ih, where h = 2 m is the depth of the orifice from the water surface. Determine the time for a particle of water leaving the orifice to reach point B and the horizontal distance x where it hits from surface.
(a) The time for a particle of water leaving the orifice to reach point B is 0.63 s.
(b) The horizontal distance x where it hits from surface is 3.94 m.
Time for the water to reach the surface
The time of the water to reach the surface is calculated as follows;
h = ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
where;
t is time of motionh is height of the orificet = √( (2 x 2)/(9.8) )
t = 0.63 s
Horizontal distanceThe horizontal distance is calculated as follows;
X = vt
where;
v is the velocity of the water = √2ghX = (√2gh)t
X = (√2 x 9.8 x 2) x 0.63
X = 3.94 m
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Why is a valve placed before the rotameter?
a.To measure the flow of liquid entering the extraction bed
b.To regulate the flow of fluid leaving the extraction bed
c.To regulate the flow of liquid entering the extraction bed
d.None of the above.
A valve placed is before the rotameter to regulate the flow of liquid entering the extraction bed. The correct option is c.
What is control valve?Control valves are generally used to maintain a flow as close as possible to the desired value.
Valves positioned before the rotameter for throttling purposes. A control valve will regulates the rate of fluid flow. Control valves control typically flow rate, pressure, and temperature.
Thus, the correct option is c.
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A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled 2.0 × 107 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour?
Answer:
shown below
Explanation:
2 x 10⁷ as a number is 20,000,000
20,000,000 - 10 = 19,999,990
It went 19,999,990 m/h
in km/h:
19,999,990 / 1000 = 19,999.99 km/h
in km/s
19,999,990 / 3,600,000 = ~5.56 km/s
in m/s
19,999,990 / 3600 = ~5555.56 m/s
which one of the following is true about Tesite stress
It is defined as the stress that results in the elongation of the material
Exam Which is a true statement about the energy level of gas? A. Gases have very little energy. B. Gases have more energy than liquids and solids. C. Gases have no energy. D. Gases have less energy than solids. Copyright © 2003-2022 International Academy of Science. All Rights Reserved. Exam Which is a true statement about the energy level of gas ? A. Gases have very little energy . B. Gases have more energy than liquids and solids . C. Gases have no energy . D. Gases have less energy than solids . Copyright © 2003-2022 International Academy of Science . All Rights Reserved .
Statement B is true about the energy level of gas, Gases have more energy than liquids and solids.
What is gas?A gas is a sample of matter that adopts the shape of the container in which it is housed and develops a uniform density inside the container.
Liquid molecules are more energetic than solid molecules. Further heating will cause the molecules to move so quickly that they won't stick together at all. The gas molecules have the highest energy content.
Gases have more energy than liquids and solids.
Hence statement B is true about the energy level of gas.
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An electric field is described by the vector e=yj -xi. what is the electric flux through a rectangular box in the x-z plane that is bounded by x between 0 and 1, and z between 0 and 1? (You need to identify dA to do this problem.)
The flux of [tex]\vec E = -x\,\vec\imath + y\,\vec\jmath[/tex] is given by the surface integral
[tex]\displaystyle \iint_S \vec E \cdot d\vec\sigma[/tex]
where [tex]S[/tex] is the given square region, which we can parameterize by
[tex]\vec s(x, z) = x\,\vec\imath + z\,\vec k[/tex]
with [tex]0\le x\le 1[/tex] and [tex]0\le z\le 1[/tex]. The area element is
[tex]d\vec\sigma = \vec n \, dx\,dz[/tex]
where [tex]\vec n[/tex] is the normal vector to [tex]S[/tex]. Depending on the orientation of [tex]S[/tex], this vector could be
[tex]\vec n = \dfrac{\partial\vec s}{\partial x} \times \dfrac{\partial\vec s}{\partial z} = -\vec\jmath[/tex]
or [tex]-\vec n = \vec \jmath[/tex]; either way, the integral reduces to
[tex]\displaystyle \iint_S \vec E \cdot d\,\vec\sigma = \int_0^1 \int_0^1 (-x\,\vec\imath + z\,\vec k) \cdot (\pm\vec\jmath) \, dx\,dz = \boxed{0}[/tex]
What is the speed of a 16 cm wave with a period of 8 seconds?
A) 48 cm/s
B) 0.5 cm/s
C) 200 cm/s
D) 2 cm/s
The speed of a 16cm wave with a period of 8 seconds is 2cm/s
How to determine the speedUsing the formula;
Speed = distance ÷ time
Distance = 16cm
time = 8 seconds
Substitute into the formula
Speed = 16 ÷ 8
Speed = 2 cm/s
Therefore, the speed of a 16cm wave with a period of 8 seconds is 2cm/s
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A plant is thrown straight
down from a balcony 7.01 m
high at 8.84 m/s. How long
does it take the plant to hit
the ground?
The time taken for the plant to hit the ground from a distance of 7.01m and at a velocity of 8.84m/s is 1.59s.
How to calculate time?The time taken for a motion to occur can be calculated using the following formula:
v² = u² - 2as
Where;
v = final velocityu = initial velocitys = distancea = acceleration8.84² = 0² + 2 × a × 7.01
78.15 = 14.02a
a = 5.57m/s²
V = u + at
8.84 = 0 + 5.57t
t = 1.59s
Therefore, the time taken for the plant to hit the ground from a distance of 7.01m and at a velocity of 8.84m/s is 1.59s.
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A periodic wave has a wavelength of 0,50 m and a speed of 20 m/s, What is the wave frequency?
Answer:
u=speed, w=wavelenght, f=frequency
It's known that u=w*f => f=u/w
u=20m/s ==> f=20/0,5 => f=40 Hz
w=0,50m
Explanation:
Calculate the magnitude of the linear momentum for the following cases.
(a) a proton with mass 1.67 x 10-27 kg, moving with a speed of 5.05 x 106 m/s
(d) the Earth (mass - 5.98 x 1024 kg) moving with an orbital speed equal to 2.98 x 10 m/s.
Answer:
8.4335 x 10^-²¹, 1.78204 x 10²⁶
Explanation:
p = mv
p = (5.05 x 10⁶)(1.67 x 10^-²⁷)
p = 8.4335 x 10^-²¹
p = mv
p = (5.98 x 10²⁴)(2.98 x 10)
p = 1.78204 x 10²⁶
There are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2. What is the minimum speed v which will permit the projectile to reach station Beta?
The minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]
What is gravitational potential energy?If an object is lifted, work is done against gravitational force. The object gains energy.
Given are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2.
The range of the projectile is given by R = v²sin2θ / g
g = gravitational acceleration of Earth
If g = g(p) for planet , range R = v²sin2θ / g(p)..................(1)
The gravitational force of attraction = weight force
Gm² /d² = m g(p)
g(p) = Gm/d².........................(2)
For R = d/3, from equation (1), we have
d/3 = v²sin2θ / g(p)
Plug the expression for g(p) , we get
v = √ [Gm/3dsin2θ ]
For velocity to be minimum, sin2θ =1
So, the minimum velocity will be
v = √ [Gm/3d]
Thus, the minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]
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What is an advantage of using renewable energy resources?
A. They can be converted directly into electric energy.
B. They do not waste energy in heat.
C. They can be replenished in a human lifetime.
D. They do not produce greenhouse gases.
8. A charged ball of mass m = 0.265 kg and unknown charge q is hanging by a light thread from a ceiling. A fixed charge Q = +5.00 μC on an insulated stand is brought close to the unknown charge. As a result, the unknown charge hangs at an angle 0 = 38.0° to the vertical as shown in the diagram below. The distance between the two charges is r = 22.0 cm. (a) What is the sign of the unknown charge? Explain how you know this. (b) What is the magnitude of the unknown charge? 8. A charged ball of mass m = 0.265 kg and unknown charge q is hanging by a light thread from a ceiling . A fixed charge Q = +5.00 μC on an insulated stand is brought close to the unknown charge . As a result , the unknown charge hangs at an angle 0 = 38.0 ° to the vertical as shown in the diagram below . The distance between the two charges is r = 22.0 cm . ( a ) What is the sign of the unknown charge ? Explain how you know this . ( b ) What is the magnitude of the unknown charge ?
(a) The sign of the unknown charge is negative.
(b) The magnitude of the unknown charge is 2.18 μC.
What is charge?The charge is the physical quantity which defines the object's electric field. The charged objects creates the electric field around it and attracts or repels another objects coming into that field.
Given is a charged ball of mass m = 0.265 kg and unknown charge q is hanging by a light thread from a ceiling. A fixed charge Q = +5.00 μC on an insulated stand is brought close to the unknown charge. As a result, the unknown charge hangs at an angle 0 = 38.0° to the vertical as shown in the diagram below. The distance between the two charges is r = 22.0 cm.
Tension in the string has two components, Tsinθ and Tcosθ
(a) The fixed charge Q will attract the movable charge q attached to string. The charge Q is positive. So, the charges must of opposite sign.
Thus, the sign of unknown charge is negative.
(b) From the equilibrium of forces, we get
Electrostatic force Fe = kQq/r²
Fe = Tsinθ .............(1)
and
weight force mg = Tcosθ.............(2)
Dividing both the equations, we get
mg/Fe = tanθ
mg / (kQq/r²) = tanθ
q = mgr²tanθ / kQ
Substitute the values from the question, we have
q = 0.265 x 9.81 x (0.22)² tan38 / (9x10⁹ x 5 x 10⁻⁶)
q = 2.18 x 10⁻⁶ C
or q = 2.18 μC
Thus, the magnitude of charge is 2.18 μC.
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find the direction of this vector.
The direction of this vector is 170° from the positive x-axis.
Vectors are physical quantities with both magnitude and directionTo identify the direction, we usually use angles and take a reference axisThe vector in the diagram is 80° to the left of the positive y-axis, so the direction of the vector is 80° + 90° = 170° anti-clockwise from the positive x-axis.Scalars are physical quantities which have only magnitudeExamples of vector quantities are displacement, velocity, acceleration, force etcExamples of scalar quantities are distance, speed, volume, density, mass, time etcThe direction of the given vector is 170° from the positive x-axis.Learn more about vectors here:
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A rocket is fired with an initial VELOCITY OF 100m/s at an angle of 55° above the horizontal, It explodes On the mountain Side 12s after its Firing What is X - and y-coordinates of the rocket relative to its Firing Point?
Answer
688.32m and 277.44m
Explanation :
⠀
[tex] \large{\maltese{\textsf{\underline{To find :-}}}} [/tex]
The X and Y coordinates of the rocket relative of firing
⠀
⠀
[tex] \large{\maltese{\textsf{\underline{Given :-}}}} \\ \\ \sf velocity (v_i) = 100m{s}^{-1} \\ \sf angle ({\theta}_{1}) = 55.0{\degree} \\ \sf time (t) = 12s [/tex]
⠀
⠀
[tex] \Large{\maltese{\textsf{\underline{\underline{Step by Step Solution:-}}}}} [/tex]
⠀
⠀
The horizontal range of projectile at x.
⠀
[tex] \sf \large{x = v_{xi}} \times t \\ \\ \sf \large{x = v_i \times \cos {\theta}_{i} \times t} [/tex]
⠀
⠀
[tex] \large\textsf{\underline{Now substituting the required values}} [/tex]
⠀
⠀
[tex] \sf x = 300 \times \cos 55{\degree} \times 12 \\ \\ \sf x = 100 \times 0.5756 \times 12 \\ \\ {\underline{\boxed{\bold{ x = 688.32m}}}} [/tex]
⠀
⠀
The vertical position of projectile at y.
⠀
⠀
[tex]\sf \large y = v_{yi} \times t - (\frac{1}{2} \times g \times {t}^{2}) \\ \\ \sf \large y = v_i \times \cos \theta \times t - \frac{1}{2} g {t}^{2} [/tex]
⠀
⠀
[tex]\textsf{ \large {\underline{Now substituting the required values}} } [/tex]
⠀
⠀
[tex] \sf y = 100 \times \cos55{ \degree} \times 12 - \frac{1}{2} \times 9.80 \times {12}^{2} \\ \\ \sf y = 100 \times 0.8192 \times 12 - 0.5 \times 9.8 \times 144 \\ \\ \sf y = 983.04 - 705.6 \\ \\ \underline{ \boxed{ \bold{y = 277.44m}}} [/tex]
⠀
⠀
⠀
Henceforth, the distance at horizon is 688.32m and at vertical is 277.44m.when energy is transferred from one part of a system to another, some of the energy is lost during the transfer and cannot be used as it was intended. Which two sentences describes examples of this?
Sentences A and D describe examples of energy transformation.Heat is produced when a car's tires rub against the pavement and as electricity passes across power wires, they become hotter.
What is the law of conservation of energy?According to the law of conservation of energy, the energy of an isolated system stays unchanged throughout time.it is said to be conserved.
Energy cannot be created nor destroyed and can be transferred from one form to the other form.
The complete question is
"When energy is moved from one component of a system to another, some of the energy is lost and cannot be used as planned.
Which two statements provide examples?
A. Friction between a car's tires and the road produces heat.
B. Sunlight strikes a solar panel, generating electricity.
c. Stereo speakers emit a sound when powered by electrical energy,
D. Wind moves a turbine, generating electricity.
I E. Power lines heat up as electricity flows through them."
Some of the energy wasted during the movement of energy from one section of a system to another is heat is produced by friction between a car's tires and the road and as electricity passes via power lines, they heat up.
Hence, sentences A and D describe examples of energy transformation.
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Proofread the following text and correct the 3 subject-verb disagreements.
Astronomers are telling people to be especially watchful this evening, as a rare event could be making a very special appearance. The release of energised particles from the sun , coupled with particularly helpful overnight conditions , are predicted to make the "Northern Lights" visible much further south than normal.
Interviewed earlier today, Derwent University's Professor Andrew Higgins said, 'Everybody are talking about it. It's a once-in-a-decade opportunity that people really shouldn't miss.'
He added: 'The forecasts given out by the weather office enables us to know when the skies will be clear. Either 11pm or 3am will be best, and I'll be over the moon if we get some good photos.'
(a) From the first sentence, particularly goes with condition.
(b) From the second sentence, everybody goes with is.
(c) From the third sentence, forecasts goes with enable.
What is subject verb agreement?In subject- verb agreement, if a subject is singular, its verb must also be singular and if a subject is plural, its verb must also be plural.
From the first sentence, the correct subject-verb agreement is;
The release of energised particles from the sun , coupled with particularly helpful overnight condition, are predicted to make the "Northern Lights" visible much further south than normal.
From the second sentence, the correct subject-verb agreement is;
'Everybody is talking about it. It's a once-in-a-decade opportunity that people really shouldn't miss.'
From the third sentence, the correct subject-verb agreement is;
'The forecasts given out by the weather office enable us to know when the skies will be clear.
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A comet goes around the sun in an elliptical orbit. At its farthest point, 455 million miles from the sun, it is traveling with a speed of 15,135 mi/h. How fast is it traveling at its closest approach to the sun, at a distance of 116 million miles?
Answer:
A 2kg block is moved a long a level floor by a horizontal force of 20N if the coefficient of sliding friction is 0.4
what is the acceleration of the blove
The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double the specific heat of iron. If the temperature of the Aluminum's mass changes by /\T, what is the change in the Iron's mass temperature?
Answer:
it is double the temperature change of iron
(correct answers only)
A sailfish is swimming after a herring in a straight line at 11.8 m/s and begins to accelerate at 6.39 m/s². How long does it take for the sailfish to reach the herring if it is 55.0 m away?
(unit=s)
The time taken for the sailfish to reach the herring if it is 55.0 m away is 2.7 s.
Time of motion of the star fishThe time taken for the star fish to travel the given distance is calculated as follows;
s = ut + ¹/₂at²
55 = 11.8t + (0.5)(6.39)t²
55 = 11.8t + 3.195t²
3.195t² + 11.8t - 55 = 0
solve the quadratic equation using formula method,
where;
a = 3.195, b = 11.8, c = -55
t = 2.7 s
Thus, the time taken for the sailfish to reach the herring if it is 55.0 m away is 2.7 s.
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what will happen to the pressure in a gas if you compressed it into a volume that was one third the size? why?
Answer:
Pressure will triple (Boyle's Law)
Explanation:
Assuming a constant temperature: (compressing gases usually raises the temp significantly):
P1V1 = P2V2
P1V1 / V2 = P2
Now change V2 to 1/3 V2:
P1V1 / (1/3 V2 ) = P2 / (1/3 )
P1V1/ (1/3 v2 ) = 3 P2 <======= THE PRESSURE WILL TRIPLE
This is Boyle's Law
differentiate e^x - 8x +7
please answer the questions asap
Answer:
eˣ-8.
Explanation:
(eˣ-8x+7)'=eˣ-8.
I was having trouble converting this p-t graph into a velocity-time graph and acceleration-time graph. Can someone convert it and send a picture of it?
We can obtain the velocity from the graph and plot is against time to obtain a velocity time graph.
What is a velocity time graph?The velocity time graph shows the change of velocity with time. Recall that velocity is the change of position with time.
As such, when we have a position time graph as shown, we can obtain the velocity from the graph and plot is against time to obtain a velocity time graph.
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Answer pleaseeeee
Question 2 of 10
Which is directly proportional to your weight on a planet's surface?
OA. The distance from the surface to the center of the planet
B. Only the mass of the planet
OC. Only your mass
OD. Your mass and the mass of the planet
Answer:
from my side the will be b only the mass of the planet thank you
Answer:
D
Explanation:
W=mg
g=GM/r²(G=Gravitational constant, M=mass of earth, r=Radius of earth)
>>W=m(GM/r²)
W is directly proportional to mass of earth and mass of your body
a 2.50 cm tall object is 36.0 cm from a concave mirror with f=12.0 cm. find the image height.
The height of the image is -6 cm.
The reflecting surface of a concave mirror is curled inward and away from the light source. Light is reflected inward to a single focus point via concave mirrors. Concave mirrors, in contrast to convex mirrors, produce a variety of images depending on the object's to the mirror.
Given that, an object placed 36 cm from a concave mirror having the focal length of 12 cm and height of image is 2.50 cm
We have to find height of the Image
Using Mirror Formula:
1/f = 1/v + 1/u
Where,
f = focal length
v = Image distance from the mirror
u = object distance from the mirror (concave)
Substitute the known values in the above formula to find the value of 'v' i.e. from the mirror.
1/(-12) = 1/v + 1/(-36)
1/(-12) = 1/v - (1/36)
1/v = -0.055
v = -18 cm
Therefore, Image distance the from the concave mirror is -18 cm.
Now,
m = -v/u = hi/h
Substitute the values,
-(-18)/(-36) = hi/12
-0.5 = hi/12
-6 = hi
Therefore, the height of the image is -6 cm.
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As you move down a period of the periodic table from top to bottom, what happens to the elements' electronegativity?
A.
It decreases.
B.
It changes in relation to the number of electrons.
C.
It changes in relation to the number of protons.
D.
It increases.
Answer:
A.) It decreases
Explanation:
Generally, as you go from the top to the bottom of the periodic table (down a column), the electronegativity values of the elements decrease.
Also, as you move to the right of the periodic table (across a period), the electronegative values increase. The most electronegative elements are located on the top-right of the periodic table.
What is the effect on a field of tall grass when a wave caused by a cool summer breeze passes through the field?
Select one:
a. The grass leans in the direction the wind is blowing, then returns to its original position.
b. The field of grass exhibits a permanent disturbance in the direction the wind is blowing.
c. To counteract the effect of the breeze, the grass leans into the wind.
d. Some grass leans in the direction the wind is blowing and some leans into the wind.
Whenever a wave is brought on by a cool summer breeze across the field. The grass tilts in the wind's direction before reverting to its original posture. Option A is correct.
What is the wind blowing?Air pressure variations within our atmosphere result in the wind, which is the movement of air.
Areas with a low pressure are approached by air in high pressure. The air flows more quickly when there is a bigger pressure differential. Most rapid winds.
The wind is the movement of air produced by changes in air pressure in our atmosphere.
High-pressure air goes toward low-pressure locations. The bigger the pressure differential, the faster the air moves.
Hence, option A is correct.
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Two charged particles are near each other – the charge magnitudes are +3 uC and +7 uC, respectively. The electrostatic force between these charges is 25 N. A charged particle of -1 uC is added to both of the original two charges. What is the electrostatic force between the two charged particles after the -1 uC charge is added?
Answer:
Approximately [tex]14\; {\rm N}[/tex].
Explanation:
By Coulomb's Law, the magnitude of the electrostatic force between two charges is proportional to the product of the magnitudes of the two charges.
For example, consider charges of magnitude [tex]q_{1}[/tex] and [tex]q_{2}[/tex] that are apart from one another by a distance of [tex]r[/tex] in between. Let [tex]k[/tex] denote Coulomb's constant. By Coulomb's Law, the magnitude of electrostatic force between the two charges would be:
[tex]\displaystyle F = \frac{k\, q_{1}\, q_{2}}{r^{2}}[/tex].
In this question, the product of the magnitude of the two charges was originally [tex]3\; {\rm \mu C} \times 7\; {\rm \mu C} = 21\; {\rm (\mu C)^{2}}[/tex]. After [tex](-1\; {\rm \mu C})[/tex] is added to each charge, product of the magnitude of the two charges would become [tex](3 - 1)\; {\rm \mu C} \times (7 - 1)\; {\rm \mu C} = 12\; {\rm (\mu C)^{2}}[/tex].
Thus, the product of the magnitude of the two charges has been scaled to [tex]12\; {\rm \mu C}[/tex] from [tex]21\; {\rm \mu C}[/tex] . The magnitude of the electrostatic force between the two charges would be scaled from [tex]25\; {\rm N}[/tex] to [tex]25\; {\rm N} \times (12 / 21) \approx 14\; {\rm N}[/tex].
Which graph shows constant acceleration with correctly placed independent and dependent variables?
Answer:
a = (V2 - V1) / t equation for constant acceleration
if t the independent variable is placed on the abcissa or x-axis and V the dependent variable is placed on the ordinate or y-axis then the acceleration would be the slope at the point considered.
an ac voltage of 12.0 v is applied to the primary transformer that has 3 times as many turns in the secondary than in the primary. what is the voltage of the secondary?
The voltage of the secondary will be 36 V.From the given conditions primary transformer has 3 times as many turns in the secondary coil.
What is induced voltage?Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.
In this case, a magnet is pushed in and out of a wire coil attached to a high-resistance voltmeter.
Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.
The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.
Given data;
Primary coil voltage,[tex]\rm V_P = 12 \ v[/tex]
Secondary coil voltage,[tex]\rm V_s = ?[/tex]
No turns in the primary coil,[tex]\rm N_p[/tex]
No turns in the secondary coil,[tex]\rm N_s[/tex]
From the given condition;
[tex]\rm N_s = 3N_p[/tex]
For a transformer,
[tex]\rm \frac{V_p}{V_s}= \frac{N_p}{N_s} \\\\ \rm \frac{12}{V_s}= \frac{N_p.}{3N_p} \\\\ V_s = 36 \ V[/tex]
Hence the voltage of the secondary will be 36 V.
To learn more about the induced voltage refer to the link;
https://brainly.com/question/19482771
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