Step-by-step explanation:
I am not sure what your problem here is.
you understand the inequality signs ?
anyway, to get
6×f(-2) + 3×g(1)
we can calculate every part of the expression separately, and then combine all the results into one final result.
f(-2)
we look at the definition.
into what category is -2 falling ? the one with x<-2, or the one with x>=-2 ?
is -2 < -2 ? no.
is -2 >= -2 ? yes, because -2 = -2. therefore, it is also >= -2.
so, we have to use
1/3 x³
for x = -2 that is
1/3 × (-2)³ = 1/3 × -8 = -8/3
g(1)
again, we look at the definition.
into what category is 1 falling ? the one with x > 2 ? or the one with x <= 1 ?
is 1 > 2 ? no.
is 1 <= 1 ? yes, because 1=1. therefore it is also <= 1.
so we have to use
2×|x - 1| + 3
for x = 1 we get
2×0 + 3 = 3
6×f(-2) = 6 × -8/3 = 2× -8 = -16
3×g(1) = 3× 3 = 9
and so in total we get
6×f(-2) + 3×g(1) = -16 + 9 = -7
Given the function f(x) below, evaluate 3f(-2) + f(1).
if z ≤-3
3z²-2z if -3
-2√2-1
if x > 0
7x-2
f(x) = 3x² - 2x
pls help
The value of the expression 3f(-2) + f(1) is 45
Piecewise functionsPiecewise functions are functions that has two or more equations. They can consists of parabola and straight line.
From the equations, the point where x is -2 is f(x) = 3x^2 - 2x
f(-2) = 3(-2)^2 - 2(-2)
f(-2) = 12 + 4
f(-2) = 16
Similarly the point where x = 1 is -2√x - 1
f(1) = -2√1 - 1
f(1) = -2 - 1
f(1) = -3
Substitute
3f(-2) + f(1) = 3(16) +(-3)
3f(-2) + f(1) = 48 - 3
3f(-2) + f(1) = 45
Hence the value of the expression 3f(-2) + f(1) is 45
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Step 1: 4 x minus x + 2 + 6 = 6 x + 16
Step 2: 3 x + 8 = 6 x + 16
Step 3: 8 minus 16 = 6 x minus 3 x
Step 4: Negative 8 = 3 x
Step 5: Negative StartFraction 8 Over 3 EndFraction = x
Jorge verifies his solution by substituting Negative StartFraction 8 Over 3 EndFraction into the original equation for x. He determines that his solution is incorrect. Which best describes Jorge’s error?
Jorge distributed incorrectly.
Jorge incorrectly combined like terms.
Jorge incorrectly applied the addition and subtraction properties of equality.
Jorge incorrectly applied the multiplication and division properties of equality
The error from Jorge's arithmetic operation on the given algebraic expression is that he distributed it incorrectly.
What is an algebraic expression?An algebraic expression is a mathematical equation that is made up of variables together with arithmetic operations.
From the given expression, we have:
4x - x + 2 + 6 = 6x + 16
Add similar elements together;
3x + 8 = 6x + 16
Using distributive property, subtract 8 from both sides:
3x + 8 - 8 = 6x + 16 - 8
3x = 6x + 8
Simplify
3x-6x = 8
-3x = 8
Divide both sides by -3
-3/-3x = -8/3
x = -8/3
So from Jorge's calculation, because he distributed incorrectly, we can conclude that could be his error.
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1 in = 2.54 cm
how many millimeters are in 10.5 feet?
A.266.7 mm
B. 1,260 mm
C. 320.04 mm
D. 3,200.4 mm
Answer:
[tex]\fbox {D. 3,200.4 mm}[/tex]
Step-by-step explanation:
Given :
[ 1 inch = 2.54 centimeters ]
Unit conversions to keep in mind :
1 feet = 12 inches1 cm = 10 mmSolving
10.5 feet10.5 x 12 inches126 inches126 x 2.54 cm320.04 cm320.04 x 10 mm3200.4 mmThe weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds. Using the empirical rule, what is the probability that a cat will weigh less than 11 pounds?
If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.
What is the z-score?The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x - μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.
Then the probability that a cat will weigh less than 11 pounds will be
The value of z-score will be
z = (11 – 9) / 2
z = 1
Then the probability will be
P(x < 11) = P(z < 1)
P(x < 11) = 0.84134
Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.
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what is the answer for this question
One number is six times another number. Determine the two numbers if the sum of their reciprocals is 7/24
.
Answer:
x=24, y=4
Step-by-step explanation:
x=6y
1/x+1/y=7/24,
1/6y+1/y=7/24
1/6y+6/6y=7/24
(1+6)/6y=7/24
7/6y=7/24, then
6y=24
y=24/6
y=4
x=6y=6*4=24
L
N
(x-4) in. O
(x-3) in.
(x + 2) in.
x in.
K
Which value of x would make NO || KJ?
1
6
08
O 10
Answer:
x = 8
Step-by-step explanation:
[tex]\sf If\:\: \overline{NO} \parallel \overline{KJ}\:\:then\:\: \triangle LNO \sim\triangle LKJ[/tex]
Therefore:
[tex]\implies \sf \overline{LN} : \overline{LO} = \overline{LK} : \overline{LJ}[/tex]
[tex]\implies (x-3):(x-4)=(x-3)+(x+2):(x-4)+x[/tex]
[tex]\implies \dfrac{x-3}{x-4}=\dfrac{2x-1}{2x-4}[/tex]
[tex]\implies (x-3)(2x-4)=(2x-1)(x-4)[/tex]
[tex]\implies 2x^2-10x+12=2x^2-9x+4[/tex]
[tex]\implies -10x+12=-9x+4[/tex]
[tex]\implies 12=x+4[/tex]
[tex]\implies x=8[/tex]
Emily invested $810 in an account paying an interest rate of
Answer:
complete this
Step-by-step explanation:
yeah do it
Angelina's family owns a mini-golf course. When discussing the business with a customer, she explains there is a relationship between the number of visitors and
hole-in-one winners. If x is the number of visitors and y is the number of winners, which conclusion is correct?
A. The ordered pair (-3, 6) is viable.
B. The ordered pair (7, 2) is viable.
C. The ordered pair (15,-7) is viable.
D. The ordered pair (18,3) in non viable
The ordered pair (7,2) is viable and Option B is the correct answer.
What is Relationship ?Relationship between variables defines the way one variable is dependent upon the other variable.
It is given that x is the number of visitors and y is the number of winners,
It has to be seen and chosen that which ordered pair makes sense
The ordered pair is viable if the no. of visitor is positive and more than the number of winners.
Therefore ordered pair (7,2) is viable and Option B is the correct answer.
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Jose rides his bike for 5 minutes to travel 8 blocks he rides for 10 minutes to travel 16 blocks which value will complete the table
Using the unit rate, the missing values that completes the table are:
A = 5; B = 15; C = 40
How to Find Unit Rate?Unit rate (m) = change in y/change in x.
5 minutes for 8 Blocks (5, 8) and 10 minutes for 16 blocks (10, 16)are given.
Unit rate (m) = (16 - 8)/(10 - 5) = 8/5
An equation that will define the function is, y = 8/5x. Use it to complete the table.
Find A (y) when x is 5:
y = 8/5(5) = 8
The value of A is: 5
Find B (x) when y is 24:
24 = 8/5(x)
5(24) = 8x
120 = 8x
120/8 = x
15 = x
The value of B is: 15
Find A (y) when x is 25:
y = 8/5(25) = 40
The value of C is: 40
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What is the solution to -2|x − 1| = -4? A. x = 3 B. x = -1 or x = 3 C. x = 1 or x = 3 D. No solutions exist.
Answer:
B
Step-by-step explanation:
-2|x - 1| = -4
|x - 1| = 2
since we are dealing with a function that brings 2 values to the same result, the reverse function (needed to find the values of x that create the result y) has 2 branches :
(x - 1) = 2
and
(x - 1) = -2
x - 1 = 2
x = 3
x - 1 = -2
x = -1
therefore, B is the right answer.
Estimate the solution to the following system of equations by graphing.
OA (-1,-1)
OB. (1,-1)
oc (1)
D.
3x + 5y = 14
61 - 4y = 9
An equation is formed of two equal expressions. The estimated solution of the two system of equations is at (5/2,4/3). Thus, the correct option is D.
What is an equation?An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
The solution of the system of equation is the point at which the two lines will intersect as shown below. Therefore, the solution will be,
Solution = (5/2, 4/3)
Hence, the estimated solution of the two system of equations is at (5/2,4/3). Thus, the correct option is D.
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Maite's rent increased by 6%. The increase was $97.8. What was the original amount of Maite's rent? Please show me how to solve it as well please
Answer:
1630
Step-by-step explanation:
In words you are looking for 6% of what number is 97.80, turn that into an Algebra equation .06x = 97.80 so x = 97.80/.06 so x = 1630
area of rectangle = l×b find area of rectangle in sq cm
a) l=7cm,b=4cm
Answer:
[tex]28{cm}^{2} [/tex]
Step-by-step explanation:
we know
area of rectangle=l*b=(7*4)sq cm=28sq cm
I need answer as fast as possible please.
Step-by-step explanation:
a=110. x,55
y=180-(x+75)=50
w,75
b,110
x,40
y,30
1. At which point do Line CF and Line GF intersect? They intersect at point?
2. Look at Line AD and Like BE. Do these lines intersect?
(a) yes they will intersect at Point F?
(b) no they will never intersect?
(c) yes they will point at Point G
(d) yes they will intersect at Point F?
3. Look at Line BG and Line AC. Where do they intersect? They intersect at Point?
(Please hurry giving 50 points!)
Answer: i think no?
Step-by-step explanation:
AD and BE are both parallel lines (they are parallel to eachother), so they will never intersect
CF and GF intersect at point F (i think)
Bg and Ac intersect at point B (i think)
i dont want to give a definite answer in the event im wrong bc I just learned this like a few weeks ago-
Find the range of the given function y = 3x + 2 for the domain 4 and -4.
Answer:
Range: (-10 , 14)
Step-by-step explanation:
Given information:
Equation: y = 3x +2Domain: (-4 , 4)Range: (x , y)?
Plug in domain of x = -4 and x = 4 into equation to find range.
f(-4) = 3 * -4 + 2 = -10
f(4) = 12 + 2 = 14
Range: (-10 , 14)
what is the slope of the line that is perpendicular to the line 3y=-5x+21
a -5/3
b -3/5
c- 3/5
d- 5/3
Step-by-step explanation:
the slope is the factor of x in an equation
y = ax + b
we have here
3y = -5x + 21
to get to the general format above we need to divide everything by 3 :
y = -5/3 x + 7
so, we see, the slope is -5/3.
the perpendicular (angle of 90°) slope is the original slope turned upside-down and with flipped sign :
3/5
so, I guess the correct answer option is c.
but it is not clear what you wrote there, as there is a "-" sign somehow in all 4 answers.
Can anyone help me with this
Fnd the value of x.
x = ?
Answer:
X=62 degrees
Step-by-step explanation:
The solution is in the image
Answer:
62°
Step-by-step explanation:
We know that the sum of the interior angles in a triangle is added up to 180°.
Therefore,
68.5° + 49.5° + x = 180°
118° + x° = 180°
x = 180° - 118°
x = 62°
Find the equation of the line in slope-intercept form containing the points (6, -1) and (-3, 2).
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: y= - \cfrac{x}{ 3} + 1 [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
Equation of line (two point form) :
[tex]\qquad \tt \rightarrow \: (y - y_1) = \cfrac{y _1- y_2}{ x_1 - x_2} (x - x_1)[/tex]
[tex]\qquad \tt \rightarrow \: (y - 2) = \cfrac{2 - ( - 1)}{ - 3 - 6} (x - ( - 3))[/tex]
[tex]\qquad \tt \rightarrow \: (y - 2) = \cfrac{2 + 1}{ - 9} (x + 3)[/tex]
[tex]\qquad \tt \rightarrow \: (y - 2) = - \cfrac{3}{ 9} (x + 3)[/tex]
[tex]\qquad \tt \rightarrow \: (y - 2) = - \cfrac{1}{ 3} (x + 3)[/tex]
[tex]\qquad \tt \rightarrow \: y - 2= - \cfrac{x}{ 3} - \cfrac{3}{3} [/tex]
[tex]\qquad \tt \rightarrow \: y = - \cfrac{x}{ 3} - 1 \cfrac{}{} + 2[/tex]
[tex]\qquad \tt \rightarrow \: y = - \cfrac{x}{ 3} + 1[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
y
8 ⠀⠀⠀⠀
6+€ (1,5)
ATE
E (21)
D (4:1)
-8-6-4-2 2 4 6 8
-6-
Find the area of the triangle.
The area of the triangle will be 24912 sq. units. Square units and other similar units are used to measure area.
What is the area?The space filled by a flat form or the surface of an item is known as the area.
The number of unit squares that cover the surface of a closed-form is the figure's area.
For:
(X1, Y1) = (1, 15)
(X2, Y2) = (-2, 1)
d = 14.317821
For:
(X₂, Y₂) = (-2, 1)
(X₃, Y₃) = (4, 5)
d = 7.211103
For applying the pythogorous them we need the right angle triangle obtained by bisect from the mid point.
The value of the base is;
⇒7.2 / 2
⇒3.6
apply the pythogorous theorem for finding the height;
h² = p² + b²
14.31² = p² + 3.6²
p = 13.84
The area of the triangle is;
[tex]\rm A = \frac{1}{2}\times b \times h \\\\ A= \frac{1}{2} \times 3.6 \times 13.84 \\\\ A = 24.912[/tex]
Hence, the area of the triangle will be 24912 sq. units.
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Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Determine each segment length in right triangle . Triangle ABC with right angle marked at vertex B. Side AC, opposite vertex B, is labeled 14. Dashed segment is drawn from vertex B to point D on side AC. Angle BDA is marked right angle. Angles A and C both marked 45 degrees. Segment AD is labeled 7. (dragged tiles) 7(squareroot)3 7(square root) 7. 14. 14(squareroot)3. 14(square root)2
The segment length is 14 (square root)2
Given that Triangle ABC is right angle triangle
The vertex marked is B where side AC is the hypotenuse
The side of AC is at Vertex B is 14
The dash segment from vertex B to point D on side AC
Angle BDA is marked right angle .
Angles A and C both marked 45 degrees.
As shown in diagram
Triangle ABC is drawn according to the statement where B is vertex
The side lengths are 14
Now to find Another side length that is x
So , the equation formed is
x*cos45 = 14
x/√2 = 14
x = 14√2
Hence the length of the segment is 14√2
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Answer:
Step-by-step explanation:
The segment length is 14 (square root)2
Given that Triangle ABC is right angle triangle
The vertex marked is B where side AC is the hypotenuse
The side of AC is at Vertex B is 14
The dash segment from vertex B to point D on side AC
Angle BDA is marked right angle .
Angles A and C both marked 45 degrees.
As shown in diagram
Triangle ABC is drawn according to the statement where B is vertex
The side lengths are 14
Now to find Another side length that is x
So , the equation formed is
x*cos45 = 14
x/√2 = 14
x = 14√2
Hence the length of the segment is 14√2
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Solve for w.
−16w-3 = 5w²
Answer:
w = -1/5
OR
w = -3
Step-by-step explanation:
Given equation:
−16w-3 = 5w²
Solution:
Subtracting 5w^2 from both sides,we get
-16w-3-5w² = 5w² - 5w²-5w²-16w-3=0Factor the LHS of this equation using middle term factor:
(-5w²-1)(w-3)Now,
[tex]( - 5w - 1) = 0 \: \: \: \: \: \: \: \: ...(1)[/tex][tex](w - 3) = 0 \: \: \: \: \: \: \: \: \: \: ... (2)[/tex]Solving for equation 1:
[tex] - 5w = 0 + 1[/tex][tex] - 5w = 1[/tex][tex] \boxed{w = - \cfrac{1}{5} }[/tex]Solving for equation 2:
[tex]w - 3 = 0[/tex][tex]w = 0 - 3[/tex][tex] \boxed{w = - 3}[/tex][tex] - 16w - 3 = 5 {w}^{2} \\ \\ 0 = 5 {w}^{2} + 16w + 3 \\ \\ 5 {w}^{2} + 16w + 3 = 0 \\ \\ 5 {w}^{2} + w + 15w + 3 = 0 \\ \\ (5 {w}^{2} + w) + (15w + 3) = 0 \\ \\ w(5w + 1) + 3(5w + 1) = 0 \\ \\ (w + 3)(5w + 1) = 0. [/tex]
The value of w is -3 and -1/5 .
my father is 4 times old as me. after 5 years my father will be 3 times old how old is my father now
Answer:
Step-by-step explanation:
Which of the following sets of ordered pairs represents a function?
{(-6,-1), (13,8), (1,6), (1,-10)}
{(10,5), (10,-5), (5,10), (5,-10)}
{(3,5), (-17,-5), (3,-5), (-17,5)}
{(10,5), (-10,-5), (5,10), (-5,-10)}
Answer:
Step-by-step explanation:
A function can only have one output for an input. That is, for any value of x, there must be a unique value of y.
{(-6,-1), (13,8), (1,6), (1,-10)} Not a Function: (1,6) and (1,-10)
{(10,5), (10,-5), (5,10), (5,-10)} Not a Function: (10,5) and (10,-5)
{(3,5), (-17,-5), (3,-5), (-17,5)} Not a Function: (3,5) and (3,-5)
{(10,5), (-10,-5), (5,10), (-5,-10)} Function: No duplicate values of y for a value of x.
Find the maxima and minima of the following function:
[tex]\displaystyle f(x) = \frac{x^2 - x - 2}{x^2 - 6x + 9}[/tex]
To find the maxima and minima of the function, we need to calculate the derivative of the function. Note, before the denominator is a perfect square trinomial, so the function can be simplified as
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f(x) = \frac{x^2 - x - 2}{(x - 3)^2}} \end{gathered}$}[/tex]
So the derivative is:
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{(2x - 1)(x - 3)^2 - 2(x - 3)(x^2 - x - 2)}{(x - 3)^4} } \end{gathered}$}[/tex]
Simplifying the numerator, we get:
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{(x - 3)(-5x + 7)}{(x - 3)^4} = \frac{-5x + 7}{(x - 3)^3} } \end{gathered}$}[/tex]
The function will have a maximum or minimum when f'(x) = 0, that is,
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{-5x + 7}{(x - 3)^3} = 0 } \end{gathered}$}[/tex]
which is true if -5x + 7 = 0. Then x = 7/5.
To determine whether x = 7/5 is a maximum, we can use the second derivative test or the first derivative test. In this case, it is easier to use the first derivative test to avoid calculating the second derivative. For this, we evaluate f'(x) at a point to the left of x = 7/5 and at a point to the right of it (as long as it is not greater than 3). Since 1 is to the left of 7/5, we evaluate:
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f(1) = \frac{-5 + 7}{(1 - 3)^3} = \frac{2}{-8} < 0} \end{gathered}$}[/tex]
Likewise, since 2 is to the right of 7/5, then we evaluate:
[tex]\large\displaystyle\text{$\begin{gathered}\sf \displaystyle \bf{\frac{-10 + 7}{(2 - 3)^3} = \frac{-3}{-1} > 0} \end{gathered}$}[/tex]
Note that to the left of 7/5 the derivative is negative (the function decreases) and to the right of 7/5 the derivative is positive (the function increases).
The value of f(x) at 7/5 is:
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f\left(\tfrac{7}{5}\right) = \frac{\tfrac{49}{25} - \tfrac{7}{5} - 2}{\tfrac{49}{25} - 6 \cdot \tfrac{7}{5} + 9} = -\frac{9}{16} } \end{gathered}$}[/tex]
This means that [tex]\bf{\left( \frac{7}{5}, -\frac{9}{16} \right)}[/tex] is a minimum (and the only extreme value of f(x)).
[tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]
Answer:
[tex]\text{Minimum at }\left(\dfrac{7}{5},-\dfrac{9}{16}\right)[/tex]
Step-by-step explanation:
The local maximum and minimum points of a function are stationary points (turning points). Stationary points occur when the gradient of the function is zero. Differentiation is an algebraic process that finds the gradient of a curve.
To find the stationary points of a function:
Differentiate f(x)Set f'(x) = 0Solve f'(x) = 0 to find the x-valuesPut the x-values back into the original equation to find the y-values.[tex]\boxed{\begin{minipage}{5.5 cm}\underline{Quotient Rule for Differentiation}\\\\If $y=\dfrac{u}{v}$ then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{v \dfrac{\text{d}u}{\text{d}x}-u\dfrac{\text{d}v}{\text{d}x}}{v^2}$\\\end{minipage}}[/tex]
[tex]\text{Given function}: \quad \text{f}(x)=\dfrac{x^2-x-2}{x^2-6x+9}[/tex]
Differentiate the function using the Quotient Rule:
[tex]\text{Let }u=x^2-x-2 \implies \dfrac{\text{d}u}{\text{d}x}=2x-1[/tex]
[tex]\text{Let }v=x^2-6x+9 \implies \dfrac{\text{d}v}{\text{d}x}=2x-6[/tex]
[tex]\begin{aligned}\implies \dfrac{\text{d}y}{\text{d}x} & =\dfrac{(x^2-6x+9)(2x-1)-(x^2-x-2)(2x-6)}{(x^2-6x+9)^2}\\\\& =\dfrac{(2x^3-13x^2+24x-9)-(2x^3-8x^2+2x+12)}{(x^2-6x+9)^2}\\\\\implies \text{f}\:'(x)& =\dfrac{-5x^2+22x-21}{(x^2-6x+9)^2}\\\\\end{aligned}[/tex]
Set the differentiated function to zero and solve for x:
[tex]\begin{aligned}\implies \text{f}\:'(x)& =0\\\\\implies \dfrac{-5x^2+22x-21}{(x^2-6x+9)^2} & = 0\\\\-5x^2+22x-21 & = 0\\\\-(5x-7)(x-3) & = 0\\\\\implies 5x-7 & = 0 \implies x=\dfrac{7}{5}\\\\\implies x-3 & = 0 \implies x=3\end{aligned}[/tex]
Put the x-values back into the original equation to find the y-values:
[tex]\implies \text{f}\left(\frac{7}{5}\right)=\dfrac{\left(\frac{7}{5}\right)^2-\left(\frac{7}{5}\right)-2}{\left(\frac{7}{5}\right)^2-6\left(\frac{7}{5}\right)+9}=-\dfrac{9}{16}[/tex]
[tex]\implies \text{f}(3)=\dfrac{\left(3\right)^2-\left(3\right)-2}{\left(3\right)^2-6\left(3\right)+9}=\dfrac{4}{0} \implies \text{unde}\text{fined}[/tex]
Therefore, there is a stationary point at:
[tex]\left(\dfrac{7}{5},-\dfrac{9}{16}\right)\:\text{only}[/tex]
To determine if it's a minimum or a maximum, find the second derivative of the function then input the x-value of the stationary point.
If f''(x) > 0 then its a minimum.If f''(x) < 0 then its a maximum.Differentiate f'(x) using the Quotient Rule:
Simplify f'(x) before differentiating:
[tex]\begin{aligned}\text{f}\:'(x) & =\dfrac{-5x^2+22x-21}{(x^2-6x+9)^2}\\\\& = \dfrac{-(5x-7)(x-3)}{\left((x-3)^2\right)^2}\\\\& = \dfrac{-(5x-7)(x-3)}{(x-3)^4}\\\\& = -\dfrac{(5x-7)}{(x-3)^3}\\\\\end{aligned}[/tex]
[tex]\text{Let }u=-(5x-7) \implies \dfrac{\text{d}u}{\text{d}x}=-5[/tex]
[tex]\text{Let }v=(x-3)^3 \implies \dfrac{\text{d}v}{\text{d}x}=3(x-3)^2[/tex]
[tex]\begin{aligned}\implies \dfrac{\text{d}^2y}{\text{d}x^2} & =\dfrac{-5(x-3)^3+3(5x-7)(x-3)^2}{(x-3)^6}\\\\& =\dfrac{-5(x-3)+3(5x-7)}{(x-3)^4}\\\\\implies \text{f}\:''(x)& =\dfrac{10x-6}{(x-3)^4}\end{aligned}[/tex]
Therefore:
[tex]\text{f}\:''\left(\dfrac{7}{5}\right)=\dfrac{625}{512} > 0 \implies \text{minimum}[/tex]
which of the following must be true?
Answer:
C
Step-by-step explanation:
Answer C is correct. The absolute value of 10 is 10 and that of -10 is 10. Same result.
edg vector operations, any help appreciated!
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
Vector d can be represented as :
[tex]\qquad \tt \rightarrow \: - 2 \hat i - 2 \hat j[/tex]
Vector c can be represented as :
[tex]\qquad \tt \rightarrow \: 4 \hat i + 4\hat j[/tex]
we have to create vector d from vector c
So, let's assume a vector x, such that sum of vector x and vector c equals to vector d
[tex]\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) = - 2 \hat i - 2 \hat j[/tex]
[tex]\qquad \tt \rightarrow \: x = - ( 4 \hat i + 4 \hat j) - 2 \hat i - 2 \hat j[/tex]
[tex]\qquad \tt \rightarrow \: x = (- 4 \hat i - 2 \hat i) + ( - 4 \hat j - 2 \hat j)[/tex]
[tex]\qquad \tt \rightarrow \: x = - 6 \hat i -6 \hat j[/tex]
Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Choose all of the following angles that cannot
be an interior angle in a regular polygon.
40° 45° 108° 132° 179°
Answer:
40 45 because the minimum internal angle is 60
Question 3 of 10
Which choice represents the simplified exponential expression?
(12-4)8
OA. 12-32
B. 12-12
O C. 12
OD. 124
The correct value that equates to this expression is 12‐³². Letter A
.
To solve this expression, just: eliminate the parentheses and multiply the exponents among themselves;[tex] \boxed{ \large \sf (a {}^{n} ) {}^{m} \rightarrow a {}^{n \times m} } \\ \\ [/tex]
Resolution[tex]{ = \large \sf (12{}^{-4} ) {}^{8} } [/tex]
[tex]{ = \large \sf 12{}^{-4 \times 8} } [/tex]
[tex] \pink{ \boxed{ = \large \sf 12{}^{-32} } } \\ [/tex]
Therefore, the answer will be 12‐³²