Answer:
Atoms of the same element are exactly alike in all respects and are different from atoms of other elements.
Explanation:
One of the postulates of the Dalton's atomic theory is that 'Atoms of the same element are exactly alike in all respects and are different from atoms of other elements.'
Hence, if carbon dioxide from two sources are obtained and analysed, the mass percentage of carbon in both samples should be exactly the same since they both contain atoms of carbon. The atoms of carbon in the both samples are exactly the same in all respects in accordance with the Dalton's atomic theory, hence the observation.
Solve for x, where M is molar and s is seconds. x=(5.3×103M−2s−1)(0.26M)3
Answer:
guys can u solve my ques plz
Diamonds are measured in carats, where 1 carat = 0.200 g. The density of diamond is 3.51 g/cm^3. What is the volume of a 5.50 carat diamond?
Answer:
5.0 carat x (0.200g / 1 carat) x (1 cm³ / 3.51g) = 0.28 cm³... with 2 sig figs..
Explanation:
USE DIMENSIONAL ANALYSIS. That is the point of this problem. That is why Dr. Zumdahl wrote this problem and put it in his textbook (chpt 1 Problem #57 if you're using the 7th edition, chpt1 problem #63 if you're using his 8th edition).
What is the IUPAC name of the following compound?
CH3-CH-C---C-CH2-CH-CH3
CH3-CH2 CH2-CH3
(a) 2,6-diethyl-3-nonyne
(b) 2,5-diethyl-3-nonyne
(c) 3,7-dimethyl-5-nonyne
(d) 3,7-dimethyl-4-nonyne
(e) 2,6-diethyl-3-heptyne
Answer:
(d) 3,7-dimethyl-4-nonyne.
Explanation:
Hello,
In this case, considering the attached picture on which you can see that the main chain has nine carbon atoms, one tripe bond at the fourth carbon and two methyl radicals at the third and seventh carbons respectively, by following the IUPAC rules, the name would be: (d) 3,7-dimethyl-4-nonyne since the chain must start at the side closest to the first triple bond due to its priority and subsequently considering the present radicals.
Best regards.
The table below shows some information about four different elements.
Element
Classification
Density (g/cm³)
barium (Ba)
metal
3.6
beryllium (Be)
metal
1.8
chromium Cr)
metal
7.2
phosphorus P)
nonmetal
1.8
A cube of an unknown element has a shiny, silvery color. The side of the cube measures 2.0 cm and the cube has a mass of 14.56 g.
Based on the information in the table, which element makes up the cube?
Answer:beryllium
Explanation:
How do an independent variable and a dependent variable differ in a scientific investigation?
Answer:
stop cheating and be smart
Explanation:
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Use the density formula to solve the following problems. A sample of a substance has a volume of 60.5 mL and a density of 1.20 g/mL. What is the mass of the sample?Use the density formula to solve the following problems.
Answer:
72.6 g
Explanation:
Step 1: Given data
Volume of the substance (V): 60.5 mLDensity of the substance (ρ): 1.20 g/mLMass of the substance (m): ?Step 2: Calculate the mass of the substance
The density of a substance is equañ to its mass divided by its volume. The density formula is:
ρ = m/V
m = ρ × V
m = 1.20 g/mL × 60.5 mL
m = 72.6 g
what element does this Bohr show ?
Identify the molecules or ions below as Lewis acids, Lewis bases, or neither. If there is more than one possible site in the molecule/ion, focus on the central or the charged atom. a) _________ b) _________ c) _________ Submit AnswerRetry Entire Group2 more group attempts remaining Show HintPreviousNext
Answer:
This question is incomplete because of the absence of the molecules been referred to in the question. However, the molecules been referred to in the question is in the attachment below
Explanation:
First of all, we have to define lewis acid and lewis base.
A lewis acid is a substance that has the capacity to accept a pair of electrons. For example, H⁺. While a lewis base is a substance that is capable of donating a pair of electrons (to a lewis acid). For example, OH⁻.
Going by the definitions above, we can deduce the type of substance the molecules in the question (attachment) are
a. BF₃ (boron trifluoride) is a lewis acid because the central atom (as suggested to be focused on in the question) which is boron, has the capacity to accept a pair of electrons.
b. The central atom (carbon) in the compound (2-methyl propane) also has the capacity to accept a pair of electrons since it is positively charged (is electron deficient). Hence, it is a lewis acid.
c. The functional group in this compound (trimethyl borate) is the ether. Ethers are generally lewis bases because the oxygen atom in an ether can donate a pair of electrons from it's lone pair. However, the presence of boron which is central to the compound shows it is also a lewis acid, although weak (majorly due to the presence of the ethers).
You should only change one variable at a time in an experiment.
True or False
Answer:True
Explanation:
Answer:
True
Explanation:
In a galvanic cell:______.a. reduction occurs at the (name of electrode) _____________b. the anode is the (sign) electrode anions flow in solution toward the (name of electrode)__________ ___________ electrons flow from the (name of electrode) to (name of electrode) ________ _______
Answer:
In a galvanic cell:
a. reduction occurs at the cathode.
b. the anode is the (-) electrode. Anions flow in solution toward the anode. Electrons flow from the anode to the cathode.
Explanation:
The experimental apparatus for generating electricity through the use of a spontaneous reaction is called a galvanic cell or voltaic cell.
By definition, the anode in a galvanic cell is the electrode at which oxidation occurs and the cathode is the electrode at which reduction occurs.
To complete the electrical circuit, the solutions must be connected by a conducting medium through which the cations and anions can move from one electrode compartment to the other. This requirement is satisfied by a salt bridge, which, in its simplest form, is an inverted U tube containing an inert electrolyte solution, such as KCl or NH₄NO₃, whose ions will not react with other ions in solution or with the electrodes.
During the course of the overall redox reaction, electrons flow externally from the anode through the wire to the cathode. In the solution, the cations move toward the cathode, while the anions move toward the anode.
An electric current flows from the anode to the cathode because there is a difference in electrical potential energy between the electrodes.
A common example of a galvanic cell is the Daniell cell, with Zn and Cu electrodes and ZnSO₄ and CuSO₄ solutions.
Determine the number of water molecules in 115g of chromium(III) oxalate trihydrate.
Answer:
[tex]4.92x10^{23}molecules H_2O[/tex]
Explanation:
Hello,
In this case, since the chromium(III) oxalate trihydrate is Cr₂(C₂O₄)₃ ·3H₂O whose molar mass is 422 g/mol and one mole of chromium(III) oxalate trihydrate contains three moles of water, by also considering that one mole of substance contains the Avogadro´s number in particles, the number of water molecules turns out:
[tex]=115gCr_2(C_2O_4)_3\ 3H_2O*\frac{1molCr_2(C_2O_4)_3\ 3H_2O}{422gCr_2(C_2O_4)_3\ 3H_2O}*\frac{3molH_2O}{1molCr_2(C_2O_4)_3\ 3H_2O} *\frac{6.022x10^{23}molecules H_2O}{1molH_2O} \\\\=4.92x10^{23}molecules H_2O[/tex]
Best regards.
If the mass of a helicopter is 4500 kg and the net force on it is 18000 n, what is the helicopters acceleration
Answer:
The answer is
4 m/s²Explanation:
The force of an object can be found by using the formula
F = m × awhere
m is the mass
a is the acceleration
F is the force
Since we are finding the acceleration
[tex]a = \frac{F}{m} [/tex]
From the question
F = 18000 N
m = 4500 kg
Substitute the values into the above formula and solve
That's
[tex]a = \frac{18000}{4500} \\ = \frac{180}{45} [/tex]
We have the final answer as
4 m/s²Hope this helps you
11. A 100% silver ring would be an example of a
a) Pure substance
b) Mixture
c) Really nice gift
d) Compound
Answer:
a pure substance or a compound
Answer:
a pure substance
Explanation:
Any substance made from a single material is pure. Silver is an element just like all the others listed on the periodic table, so a block of silver is pure.
Calcium reacts with water to produce hydrogen and slightly soluble calcium
hydroxide, Ca(OH)2.
Ca(s) + 2 H20(1) --> Ca(OH)2(aq/s) + H2(g).
What will be the volume of hydrogen produced at 27°C and 7.00 x 102 torr when 25
g of calcium and 25 g of water react?
Answer:
[tex]V=16.65L[/tex]
Explanation:
Hello,
In this case, considering that both 25 g of calcium and water react, the first step is to identify the limiting reactant by considering the yielded moles of hydrogen for the same amount of reactant as follows:
[tex]n_{H_2}^{from\ Ca}=25gCa*\frac{1molCa}{40.1gCa}*\frac{1molH_2}{1molCa} =0.623molH_2\\\\n_{H_2}^{from\ H_2O}=25gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molH_2}{2molH_2O}=0.694molH_2[/tex]
Thus, since calcium yields a smaller amount of hydrogen, it is the limiting reactant so 0.623 moles of hydrogen are yielded. In such a way, by using the ideal gas equation one finds the volume as follows:
[tex]V=\frac{nRT}{P}=\frac{0.623mol*0.082\frac{atm*L}{mol*K}*300K}{700torr*\frac{1atm}{760 torr} } \\ \\V=16.65L[/tex]
Best regards.
i need help simplifying 4+7(x+3)
Answer:
7x+25
Explanation:
John used an empty beaker with the mass of 53.126 g. In a separate jar, he had a mixture of salt and sand. He transferred two scoops of salt and sand mixture to the beaker. The overall mass was 65.449 g. As you know salt is soluble in water, he added enough water in the beaker with salt and sand mixture to completely dissolve the salt. He filtered the mixture and dried what was left in the filter. The mass of that residue was 8.200 g. Based on the experiment calculate the mass of salt, sand and the mixture (salt sand).
Answer:
[tex]m_{mixture}=12.323g[/tex]
[tex]m_{sand}=8.200 g[/tex]
[tex]m_{salt}=4.123g[/tex]
Explanation:
Hello,
In this case, since the mass of the empty beaker is 53.126 g and with the mixture is 65.449 g, we can compute the mass of the whole mixture (water, sand and salt) via subtraction:
[tex]m_{mixture}=65.449g-53.126g=12.323g[/tex]
In such a way, since the residue obtained via filtration was sand only as it is not soluble in water, we infer that the mass of sand is 8.200 g:
[tex]m_{sand}=8.200 g[/tex]
Finally, since the mixture is composed by salt and sand, the mass of salt is:
[tex]m_{salt}=m_{mixture}-m_{sand}=12.323g-8.200g\\\\m_{salt}=4.123g[/tex]
Best regards.
How many nanometers are in 6.50 times 10^2 terameters?
Answer:
6.50×10² terameters is equal to 6.5 × 10²³ nm.
Explanation:
We need to find how many nanometers are in 6.50×10² terameters.
6.50×10² terameters = 650 terameters
It means we have to find how many nanometers in 650 terameters. We must know that conversion from one unit to another.
We know that,
1 terameter = 10¹² metres
and 1 metre = 10⁹ nm
So,
650 terameters = 650 × 10¹² metres
or
650 × 10¹² metres = 650 × 10¹² × 10⁹ terameters
Hence, 6.50×10² terameters is equal to 6.5 × 10²³ nm.
True or False. For solidification, a substance must absorb heat
Answer:
true
Explanation:
I think it is true but im uncertain
What are some examples of matter?
Answer:
An apple.
A person.
A table.
Air.
Water.
A computer.
Paper.
Iron.
Hope this helps you
Answer:
your boddy is made of mater and a clock too it is still a mater of time.
Explanation:
How many unpaid electrons are in 1s2 2s2 2p6 3s2 3p6
Answer:
No unpaired electrons
Explanation:
This is because it is diamagnetic. Hope that helps:)
Answer:
As we can see, the first shell has its 2 electrons
the second shell has its 8 electrons
we know that the third shell also needs 8 electrons and we can see that the third shell also has 8 electrons.
Therefore, all the shells of this atom are filled and this atom is stable
So we can say that there are no unpaired electrons
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Bromine gas in a container is heated over a flame. What happens to the average kinetic energy of the bromine
particles?
Olt decreases rapidly.
It increases quickly.
O It remains the same.
O It decreases slowly.
Answer:
The answer is b
Explanation:
I got my answer off of quizlet
Answer:
B) It increases quickly.
Explanation:
Edg 2020
A few years ago, a newspaper article reported that the Utah Industrial Depot west of Salt Lake
City had made the short list as a possible storage site for 4,408 metric tons of mercury metal.
This material is owned by the Defense National Stockpile Center. Mercury is mined primarily in Algeria, China, Kyrgyzstan, and Ukraine. At least part of this stockpiled material is from
payments to the US made by Spain as part of a WWII war debt. How many atoms of mercury
does this amount represent? (1 metric ton is 1000 kg, and 1 kg is 1000 g)
Answer:
There are [tex]1.323\times 10^{31} atoms[/tex] of mercury in 4,408 metric tons.
Explanation:
Mass of mercury metal = 4,408 metric ton
1 metric ton = 1000 kg
4,408 metric ton = 4,408 × 1000 kg = 4,408,000 kg
1 kg = 1000 g
4,408,000 kg = 4,408,000 × 1000 g = 4,408,000,000 g
[tex] 4,408,000,000 g=4.408\times 10^9 g[/tex]
Mass of mercury = [tex]4.408\times 10^9 g[/tex]
Atomic mass of mercury = 200.59 g/mol
Moles of mercury = n
[tex]n=\frac{4.408\times 10^9 g}{200.59 g/mol}[/tex]
[tex]1 mole=N_A=6.022\times 10^{23}[/tex] atoms/molecules/ ions
Number of atoms of mercury in n moles = N
[tex]N=n\times N_A[/tex]
[tex]N=\frac{4.408\times 10^9 g}{200.59 g/mol}\times 6.022\times 10^{23}\\=1.323\times 10^{31} atoms[/tex]
Hence, there are [tex]1.323\times 10^{31} atoms[/tex] of mercury in 4,408 metric tons.
What made the discovery of cells possible? (1 point)
O the observation of cells by Hooke and Pasteur
o the invention of the microscope
o the use of magnifying glasses
o the study of viruses and bacteria
Answer:
the invention of the microscope
Explanation:
because cells are very tiny and cant be seen to the humans naked eye
Arrange these elements according to first ionization energy.
highest to lowest ionization energy
Li
N
Be
C
B
F
O
Ne
Answer:
please find the attached file.
Explanation:
In the attachment file, we define the order of the ionization of the energy.
As its components are seen, their energy of ionization rises and falls further. Nitrogen and oxygen were detected as an anomaly. Nitrogen has more IE than oxygen because Nitrogen has the [tex]2p^3[/tex] configuration to Is half-filled It's got bigger IE than B. As, be making the 2s2 configuration fully disc.
Arrangement of elements according to first ionization energy from
highest to lowest ionization energy are Ne>F>O>N>C>B>Be.
Neon, a noble gas with a fully filled electron shell, has the highest ionisation energy of the substances on this list, making it the most stable and least likely to lose an electron. Fluorine has the second-highest ionisation energy, after helium. Due to its strong electron attraction, it is a highly electronegative element, making it more challenging to remove an electron from its outer shell. The ionisation energy of oxygen is third highest. Additionally, it has a high electronegativity and expels an electron with a lot of energy.
The fourth-highest ionisation energy is that of nitrogen, abbreviated as N. In terms of electronegativity, it is comparable to oxygen and requires a lot of energy to remove one electron. Carbon has the fifth-highest ionisation energy, after hydrogen and helium. An enormous amount of energy is needed to take an electron out of its outer shell. The second-lowest ionisation energy on this list belongs to borax, abbreviated as B. Compared to the other elements, boron is simpler to remove an electron from. Beryllium, symbol Be, has the lowest ionisation energy of all the elements on this list. From among these elements, an electron can be taken out the simplest.
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Some enzymes have one or more sulfhydryl (thiol) groups that are important to enzymatic activity but that can react upon standing in solution to form inactive disulfide bonds.
Thiol reagents, such as 1,4-dithiothreitol (DTT), are often added to the solutions of such proteins to protect them from this reaction and to reverse it when it occurs. (The reverse reaction works best at slightly alkaline pH.) Draw the product formed when DTT reacts with a protein disulfide bond to liberate the free thiol groups. Which of the following occurs in this reaction? A. The protein disulfide is oxidized.
B. The protein disulfide is reduced.
C. DTT is reduced.
D. DTT is oxidized.
Answer:
A. Protein disulfide is oxidized.
Explanation:
When thiol reagents are introduced with some protein solutions they react with molecules of disulfide and oxidize the protein. There occurs inter-conversion of thiol molecules into free disulfide molecules. The DTT reduces the disulfide molecules bonds of proteins and it starts to peptide.
Calculate the mass of a piece of metal if its volume is 2.3cm^3 and density is .486g/cm^3
Answer:
1.1178 g
Explanation:
The product of volume and density is mass:
(2.3 cm^3)(0.486 g/cm^3) = 1.1178 g
_____
It would be a very unusual piece of metal that would float higher in water than most kinds of wood. The given "metal" at (0.486) has less than 3/4 the density of birch (at 0.67), which is a pretty light wood.
Draw the products formed when 2−propanol [(CH3)2CHOH], the main ingredient of rubbing alcohol, is treated with H2SO4.
Answer:
Explanation:
Elimination reaction occurs when 2−propanol [(CH3)2CHOH] is treated with H2SO4, this is because the H2SO4 is a dehydrating agent. With concentrated tetraoxosulphate (VI) acid at 180°C, 2 - propanol reacts to form a conjugate acid and a conjugate base.
The reaction formation and the products can be seen in the attached image below.
What isotope has 18 protons and 22 neutrons?
Answer:
Argon.
Explanation:
Argon is the element having 18 protons and 22 neutrons present in its nucleus. so its atomic number is 18 and mass number is 40 if we added both number of protons and neurons. Argon belongs to noble family due to completion of outermost shell and non reactive nature. It is the third most abundant gas about 0.934% present on the earth after nitrogen and oxygen.
Which of the following additions to alkenes occur(s) specifically in an syn fashion?
A) dihydroxylation using Os04, H202
B) addition of H2
C) hydroboration
D) addition of HCI
E) A, B, and C
Answer:
E) A, B, and C
Explanation:
Syn addition refers to the addition of two substituents on the same face or side of a double bond. This differed from anti addition which a occurs across opposite face of the double bond.
Hydrogenation, hydroboration and dihydroxylation all involve syn addition to the double bond, hence the answer chosen above.
Dihydroxylation using Os04, H202, Addition of H2 and Hydroboration to
alkenes occur in a syn fashion.
Syn addition refers to the addition of two substituents( compounds) on the
same side thereby increasing the number of substituents and a decrease in
the bond order.
Hydrogenation, hydroboration and dihydroxylation all undergo syn addition which is the addition of the substituent to the same side which is why it is the right choice.
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Q1. Briefly explain why the Zeff experienced by a valence electron in Cl is larger than in Mg. Q2. Briefly explain why the Zeff difference described in Q1 explains why the radius of Cl is smaller than the radius of Mg. Q3. Briefly explain, in terms of the principal quantum number (n), why the radius of Ba is larger than the radius of Mg.
Answer:
See explanation
Explanation:
Q1:
Chlorine has 17 protons while magnesium has only 12 protons. Recall that the Zeff depends on the size of the nuclear charge. The greater the size of the nuclear charge, the larger the Zeff experienced by a valence electron.
Q2:
The larger the Zeff, the smaller the atomic radius. Since the valence electrons of Cl experience a greater Zeff than those of Mg due to greater size of the nuclear charge, the atomic radius of chlorine will be smaller than that of Mg.
Q3:
The radius of an atom increases as the value of the principal quantum number (n) increases down the group due to addition of more shells. The greater the number of shells added, the greater the principal quantum number (n) and the greater the atomic radius, hence the answer.
