Two thin concentric spherical shells of radii r1 and r2 (r1 < r2) contain uniform surface charge densities V1 and V2, respectively. Determine the electric field for (a) 0 < r < r1 , (b) r1 < r < r2 and (c) r > r2. (d) Under what conditions

Answers

Answer 1

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

We know that the Electric field inside the thin hollow shell is zero, if there is no charge inside it.

So,

a)  0 < r < r1 :

We know that the Electric field inside the thin hollow shell is zero, if there is no charge inside it.

Hence, E = 0 for r < r1

b)  r1 < r < r2:

Electric field =?

Let, us consider the Gaussian Surface,

E x 4 [tex]\pi[/tex] [tex]r^{2}[/tex]  = [tex]\frac{Q1}{E_{0} }[/tex]

So,

Rearranging the above equation to get Electric field, we will get:

E = [tex]\frac{Q1}{E_{0} . 4 \pi. r^{2} }[/tex]

Multiply and divide by [tex]r1^{2}[/tex]

E = [tex]\frac{Q1}{E_{0} . 4 \pi. r^{2} }[/tex] x [tex]\frac{r1^{2} }{r1^{2} }[/tex]

Rearranging the above equation, we will get Electric Field for r1 < r < r2:

E= (σ1 x [tex]r1^{2}[/tex]) /([tex]E_{0}[/tex] x [tex]r^{2}[/tex])

c) r > r2 :

Electric Field = ?

E x 4 [tex]\pi[/tex] [tex]r^{2}[/tex]  = [tex]\frac{Q1 + Q2}{E_{0} }[/tex]

Rearranging the above equation for E:

E = [tex]\frac{Q1+Q2}{E_{0} . 4 \pi. r^{2} }[/tex]

E = [tex]\frac{Q1}{E_{0} . 4 \pi. r^{2} }[/tex] + [tex]\frac{Q2}{E_{0} . 4 \pi. r^{2} }[/tex]

As we know from above, that:

[tex]\frac{Q1}{E_{0} . 4 \pi. r^{2} }[/tex] =  (σ1 x [tex]r1^{2}[/tex]) /([tex]E_{0}[/tex] x [tex]r^{2}[/tex])

Then, Similarly,

[tex]\frac{Q2}{E_{0} . 4 \pi. r^{2} }[/tex] = (σ2 x [tex]r2^{2}[/tex]) /([tex]E_{0}[/tex] x [tex]r^{2}[/tex])

So,

E = [tex]\frac{Q1}{E_{0} . 4 \pi. r^{2} }[/tex] + [tex]\frac{Q2}{E_{0} . 4 \pi. r^{2} }[/tex]

Replacing the above equations to get E:

E = (σ1 x [tex]r1^{2}[/tex]) /([tex]E_{0}[/tex] x [tex]r^{2}[/tex]) + (σ2 x [tex]r2^{2}[/tex]) /([tex]E_{0}[/tex] x [tex]r^{2}[/tex])

Now, for

d) Under what conditions,  E = 0, for r > r2?

For r > r2, E =0 if

σ1 x [tex]r1^{2}[/tex] = - σ2 x [tex]r2^{2}[/tex]


Related Questions

6. What is the complete spectrum of all forms of light?
a. galaxy
b. electromagnetic spectrum
C. energy
d. system

Answers

Answer:

b. the electromagnetic spectrum

Explanation:

the electromagnetic spectrum contains all the forms of light, including gamma rays, x-rays, ultraviolet radiation, visible light, infrared, radio waves, microwaves, etc

what does newton's first law describes​

Answers

Earlier, we stated Newton's first law as “A body at rest remains at rest or, if in motion, remains in motion at constant velocity unless acted on by a net external force.” It can also be stated as “Every body remains in its state of uniform motion in a straight line unless it is compelled to change that state by forces
For example-A stationary object with no outside force will not move. With no outside forces, a moving object will not stop. An astronaut who has their screwdriver knocked into space will see the screwdriver continue on at the same speed and direction forever.

the bouncing back of sound when it hits ahard surface is called

Answers

Answer:

Reflection of sound

Explanation:

Sound waves bounce back from hard surface's.

1.
Which of the following best explains the
relationship between molecules and atoms?
A
Atoms are molecules that have a charge.
B
Atoms have smaller parts, called
molecules.
С
Molecules are made up of two or more
atoms.
D
Molecules are atoms that have no mass.

Answers

Answer:

С . Molecules are made up of two or more  atoms.

Explanation:

The relationship between molecules and atoms is that molecules are made up of two or more atoms.

Molecules are made up of atoms.

A molecule is the smallest particle of a substance element or compound capable of independent existence.

A molecule could be monoatomic, diatomic or polyatomic.

Monoatomic molecules are made up of one atom

Diatomic are made up of two different atoms

Polyatomic substances are made up of more than two kinds of atoms.

What is the electrical consumption in KVA of a motor powered by a 3-phase, 60 Hz, 460 VAC supply that continuously draws 17 A

Answers

Answer:

15.34 kVA

Explanation:

A motor is a device that converts electrical energy into mechanical energy. It takes in electrical energy at the input and produce torque (motion) at the output.

The power consumption for a three phase motor is the product of voltage and current and √3. The √3 is because it is a three phase supply.

Hence Power (P) =√3 × voltage (V) × current (I)

P = √3 × V × I

Given that voltage (V) = 460 V, current (I) = 17 A. Hence:

P = √3 × V × I = √3 × 460 × 17 = 13544.64 VA

But 1000 VA = 1 kVA. Hence:

[tex]P=13544.64\ VA*\frac{1\ kVA}{1000\ VA}=13.54\ kVA[/tex]

Do this for alot of points

Answers

1. A complete fitness and exercise program should incorporate three basic components: Endurance (Aerobic), Flexibility, and Strength. Each of these components has specific guidelines, which govern their effectiveness

1. A complete fitness and exercise program should incorporate three basic components: Endurance (Aerobic), Flexibility, and Strength. Each of these components has specific guidelines, which govern their effectiveness


-- Jax

A small car with a mass of 800kg moving with a velocity of 27.8 m/s. The car stops at a yellow light in 3.9 seconds. What force did it take for the car to stop?

Answers

Answer:

F = 5702.56 N

Explanation:

Given that,

Mass of a small car, m = 800 kg

Initial speed of the car, u = 27.8 m/s

Final speed, v = 0

Time, t = 3.9 s

We need to find the force did it take for the car to stop.

The force acting on an object is given by :

[tex]F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{800\times (0-27.8)}{3.9}\\\\F=-5702.56\ N[/tex]

So, the magnitude of force acting on the car to stop is 5702.56 N.

Light with a wavelength of 560.0 nm is incident on a pair of slits with a separation of 0.380 mm. (a) Find the angles corresponding to the locations of the first three orders of bright fringes away from the central bright fringe

Answers

Answer:

Angles corresponding to the locations of the first three orders of bright fringes away from the central bright fringe are;

∅₁ = 0.8439°

∅₂ = 0.1688°

∅₃ = 0.2533°

Explanation:

Given that;

wavelength λ = 560 nm = 560 × 10⁻⁹

Separation between slits d = 0.380 mm = 0.00038

n = first three orders = 1st order, 2nd order and 3rd oder.

we know that for constructive interference;

λn = dsin∅

sin∅ = λn/d

∅ = sin⁻¹ ( λn/d )

where λ is wavelength, ∅ is the angle, d is the distance between slits, n is the order of constructive interference.

now;

-First order;  n = 1

∅₁ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(1) /0.00038 )

∅₁ = sin⁻¹( 0.001473) = 0.8439°

-2nd order;  n = 2

∅₂ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(2) /0.00038 ) =

∅₂ = sin⁻¹( 0.002947) = 0.1688°

-3rd order;  n = 3

∅₃ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(3) /0.00038 ) =

∅₃ = sin⁻¹( 0.004421) = 0.2533°

Therefore, angles corresponding to the locations of the first three orders of bright fringes away from the central bright fringe are;

∅₁ = 0.8439°

∅₂ = 0.1688°

∅₃ = 0.2533°

A teacher asks students to make a model of a transform plate boundary the students use blocks to represent tectonic plates and Slide the blocks past each other in the directions of the arrows as shown which event can the students best demonstrate with their models

Answers

Answer:

Hello your question is incomplete hence I will give you a general answer as regards to tectonic plates sliding past each other in a sideways direction

answer : The Transform boundary is been demonstrated by the students when sliding tectonic plates past each other in sideways directions

Explanation:

The event that can be demonstrated by the students using blocks to represent tectonic plates and sliding the clocks past each other in sideways direction is Transform Boundary of the tectonic plates

3. Superman is flying on the sky, suddenly approaches an airplane. It is known that this airplane has 1,000,000 kg*m/s of momentum. Superman decides to push the airplane with a force of 1,200,000 N for .09 seconds. What is the impulse that superman gives to the plane? What is the new momentum of the airplane?

Answers

Answer:

Superman's delivered impulse : 108,000 kg m/s

New momentum of the airplane: 1,108,000 kg m/s

Explanation:

Recall that impulse can be estimated by multiplying the applied force times the duration of time the force was applied. Therefore, the impulse added by Superman was:

1,200,000 * 0.09 = 108,000 kg m/s

and then, the new momentum of the plane is the addition:

1000000 + 108000 = 1,108,000 kg m/s

A student drops an object from rest above a force plate that records information about the force exerted on the object as a function of time during the time interval in which the object is in contact with the force plate. Which of the following measurements should the student take, in addition to the measurements from the force plate, to determine the change in momentum of the object from immediately before the collision to immediately after the collision?

a. The mass of the object.
b. The final speed of the object MOH 5000
c. The distance fallen by the object
d. The student has enough information to make the determination

Answers

Answer:

D

Explanation:

The student has enough information to make the determination

Measurements should the student take, in addition to the measurements from the force plate, to determine the change in momentum of the object from immediately before the collision to immediately after the collision the student has enough information to make the determination. Thus, option D is correct.

What happens during the experiment?

A student drops an object from rest above a force plate that records information about the force exerted on the object as a function of time during the time interval in which the object is in contact with the force plate.

Momentum has the measure of motion of the object. Momentum is given by the product of mass and the velocity of the object. The law of conservation of momentum states that the momentum before the collision is equal to the momentum after the collision. It also states that the total momentum of a system or a body remains constant.

Therefore, Measurements should the student take, in addition to the measurements from the force plate, to determine the change in momentum of the object from immediately before the collision to immediately after the collision the student has enough information to make the determination. Thus, option D is correct.

Learn more about Measurements on:

https://brainly.com/question/2107310

#SPJ5

How many significant figures are in 20,000?

Answers

Answer:

4

Explanation:

1. Calculate the heat capacity of a piece of wood if 1500.0 g of the wood absorbs 6.750.000 joules of heat,
and its temperature changes from 32°C to 57°C.

Answers

Answer:

1.8 J/gºC

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 1500 g

Heat (Q) absorbed = 67500 J

Initial temperature (T₁) = 32 °C

Final temperature (T₂) = 57 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature of the wood. This can be obtained as follow:

Initial temperature (T₁) = 32 °C

Final temperature (T₂) = 57 °C

Change in temperature (ΔT) =.?

ΔT = T₂ – T₁

ΔT = 57 – 32

ΔT = 25 °C

Finally, we shall determine the heat capacity of the wood. This can be obtained as follow:

Mass (M) = 1500 g

Heat (Q) absorbed = 67500 J

Change in temperature (ΔT) = 25 °C

Specific heat capacity (C) =?

Q = MCΔT

67500 = 1500 × C × 25

67500 = 37500 × C

Divide both side by 37500

C = 67500 / 37500

C = 1.8 J/gºC

Thus, the heat capacity of the wood is 1.8 J/gºC

A 15.0 kg bowling ball rolling at 3 m/s is stopped by a constant force of 11.2 newtons. Calculate the time the force must act on the bowling ball to stop it.

Answers

Answer:

4.01 seconds

Explanation:

Given that:

Mass of ball = 15kg

Initial velocity, u = 3m/s

Final velocity, v = 0

Force, F= 11.2 N

Change in velocity, dv = 3 - 0 = 3

Time force must act on the ball before stopping it:

Using the relation :

F = ma

a = (v - u) / t

Ft = m(v - u)

11.2 * t = 15 * 3

11.2t = 45

11.2t = 45

t = -+¯ 45 / 11.2

t = 4.01

t = 4 seconds.

What is the relationship among the potential drops across each resistor when the resistors are in series

Answers

Answer:

V = V₁ + V₂ + V₃ + ... + Vₙ

Explanation:

When the resistors are connected end to end such that there is only one path for the current to follow, it is called a series arrangement of resistors. In the series arrangement of the resistors, the current across each resistor is the same as the current applied across the circuit.

The potential difference across each resistor is different in the series arrangement of the resistors. But the sum of potential differences across each of the resistors in the series arrangement of resistors is equal to the total potential difference applied by the battery or source. Therefore, if n number of resistors are connected in a series arrangement with a source of potential V, the:

V = V₁ + V₂ + V₃ + ... + Vₙ

What distance does a plate with an average speed of 1.95 cm/year move in 1000 years? help pls

Answers

Answer:

1950cm

Explanation:

You should multiply 1.95 cm by 1000. This will result in the answer.

Please help if giving 20 points and brainliest

You have designed a prototype of a new, lighter material. What should be the
next step in your process?
O A. Figure out what problems people want to solve.
B. Update your initial design for the new type of material.
O c. Test to see whether your material is strong and works well.
D. Brainstorm new ways to design materials.

Answers

Answer:

O

Explanation:

Because your product will not work well so people will not buy it  and it could be a defect and explode

Answer:

c

Explanation:

Help!!
A stationary hockey puck has a mass of 0.18 kg. A hockey player uses her stick to apply a 11 N force over a distance of 0.56 m.
How much work does this force do on the puck?

A 20j
B 0.10j
C 2.0j
D 6.2j
E 34j

Answers

Answer:

6.2j

Explanation:

work done=force × displacement

wd=11N×0.56m

wd=6.16N/m~6.2j

a traveling wave is described by equation y(x,t)=0.003(20x+200t) whereby y and x are measured in meters and t in second .what is the period of this wave?

Answers

Answer:

0.0314secs

Explanation:

The standard equation of a wave is expressed as;

y(x,t) = Asin(2πx/λ+2πft)

compare and contrast with the equation  y(x,t)=0.003(20x+200t)

2πft = 200t

2πf = 200

f = 200/2π

f = 100/π

Since period T = 1/f

T = π/100

T = 3.14/100

T = 0.0314secs

hence the period of the wave is 0.0314secs

A force of 60 N is applied to a skier to pull him along a horizontal surface so that his speed remains constant. If the coefficient of friction of the skis on snow is 0.05, then what is the weight of the skier?

Answers

Answer:

[tex]1200\ \text{N}[/tex]

Explanation:

F = Force on the skier = 60 N

[tex]\mu[/tex] = Coefficient of friction = 0.05

w = Weight of skier

Force is given by

[tex]F=\mu w[/tex]

[tex]\Rightarrow w=\dfrac{F}{\mu}[/tex]

[tex]\Rightarrow w=\dfrac{60}{0.05}=\dfrac{6000}{5}[/tex]

[tex]\Rightarrow w=1200\ \text{N}[/tex]

Weight of the skier on which the force is being applied is [tex]1200\ \text{N}[/tex] .

electric heater carries a current of 18.0 A when operating at a voltage of 120 V. What is the resistance of the heater

Answers

Answer:

R = 6.67 ohms

Explanation:

Given that,

The current carried in the heater, I = 18 A

Voltage, V = 120 V

We need to find the resistance of the heater. Let the resistance be R.

We can use Ohm's law to find R.

V = IR

[tex]R=\dfrac{V}{I}\\\\R=\dfrac{120}{18}\\\\R=6.67\ \Omega[/tex]

So, the resistance of the heater is 6.67 ohms.

Consider a space shuttle which has a mass of about 1.0 x 105 kg and circles the Earth at an altitude of about 200.0 km. Calculate the force of gravity that the space shuttle experiences

Answers

Answer:

1.6675×10^-16N

Explanation:

The force of gravity that the space shuttle experiences is expressed as;

g = GM/r²

G is the gravitational constant

M is the mass = 1.0 x 10^5 kg

r is the altitude = 200km = 200,000m

Substitute into the formula

g = 6.67×10^-11 × 1.0×10^5/(2×10^5)²

g = 6.67×10^-6/4×10^10

g = 1.6675×10^{-6-10}

g = 1.6675×10^-16N

Hence the force of gravity experienced by the shuttle is 1.6675×10^-16N

4.Jessica Diggins a US world champion cross country skier is participating in the winter Olympic games. Over a 200m stretch in her race she increases her speed with a constant acceleration from 5.1 m/s to 6.2 m/s over a period of 25 seconds. What is her acceleration

Answers

Answer:

[tex]a=0.044\ m/s^2[/tex]

Explanation:

Given that,

Initial speed, u = 5.1 m/s

Final speed, v = 6.2 m/s

Time, t = 25 s

We need to find acceleration. We know that,

acceleration = rate of change of velocity

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{6.2-5.1}{25}\\\\a=0.044\ m/s^2[/tex]

So, her acceleration is [tex]0.044\ m/s^2[/tex].

Find the power of a force F~ = (8 N)ˆı + (−4 N) ˆ if the velocity ~v = (−7 m/s)ˆı + (1 m/s) ˆ. Answer in units of W

Answers

Answer:

[tex]P=-60W[/tex]

Explanation:

From the question we are told that

Force of power [tex]F=8Ni+-4Nj[/tex]

Velocity of power [tex]V=-7m/si+1m/sj[/tex]

Generally the equation for power is mathematically represented as

[tex]Power=Force *Velocity[/tex]

[tex]P=F *V[/tex]

Generally the dot product of F and V is mathematically given as

[tex]P=[/tex] [tex]\begin{vmatrix}8 & -4\end{vmatrix} .[/tex][tex]\begin{vmatrix}-7 & 1\end{vmatrix}[/tex]  [tex]=-56-4[/tex]

[tex]P=-60W[/tex]

An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 34.5 m/s . It then flies a further distance of 46100 m , and afterwards, its velocity is 40.7 m/s . Find the airplane's acceleration.

Answers

Answer:

the acceleration of the airplane is 5.06 x 10⁻³ m/s²

Explanation:

Given;

initial velocity of the airplane. u = 34.5 m/s

distance traveled by the airplane, s = 46,100 m

final velocity of the airplane, v = 40.7 m/s

The acceleration of the airplane is calculated from the following kinematic equation;

v² = u² + 2as

[tex]2as= v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{(40.7)^2 -(34.5)^2}{2 \times 46,100} \\\\a = 5.06 \ \times \ 10^{-3} \ m/s^2[/tex]

Therefore, the acceleration of the airplane is 5.06 x 10⁻³ m/s²

What happens to plankton during the spring bloom?Which organisms are consumers? (Select all that apply.) coyote, snail ,green algae, or bacteria

Answers

Answer:

See explanation

Explanation:

Plankton refers to the small and microscopic organisms drifting or floating in the sea or fresh water, consisting chiefly of diatoms, protozoans, small crustaceans, and the eggs and larval stages of larger animals(Oxford dictionary).

The spring bloom is a sudden growth or increase in plankton abundance. It begins around the early spring and continues until late in the spring or sometimes even early in the summer.

One organism that is a consumer of plankton are the snails. One of the commonest snails that eat plankton are the Nerite Snails.

Blue ran 100 m south then 50 m north

Answers

all togather becomes 150 m

or 150 ×100cm = 15000cm

150m is uhh wiehehehshsheje

a 4.0x 10^3 watt motor applies a force of 8.0 x 10^2 newtons to move a boat at constant speed. ow far does the boat move in 16 seconds

Answers

Answer:

80 m

Explanation:

From the question,

Power(P) = Force(F) × Velocity (V)

P = FV..................... Equation 1

V = P/F.................... Equation 2

Given: P = 4.0×10³ W, F = 8.0×10² N.

Substitute into equation 2

V = 4.0×10³/(8.0×10²)

V = 5 m/s.

Applying,

S = Vt............................ Equation 3

Where S = distance move by the boat, t = time.

Given: t = 16 s, V = 5 m/s

Substitute into equation 3

s = 16(5)

s = 80 m.

Hence the distance moved by the boat is 80 m

a railway train 100m long passes over a bridge 400m long at 20ms.1 how long will it take to pass over the bridge ​

Answers

Total length to be covered=400+100=500mts

time =distance/speed

=500/20

=25 sec

PLEASE ANSWER 50 points
A car manufacturer wants to change its car’s design to increase the car’s acceleration. Which changes should the engineers consider making to the design?
O increase the force that the engine provides
O decrease the force that the engine provides
O increase the mass of the car
O decrease the mass of the car
O increase the top velocity the car can travel
O decrease the top velocity the car can travel

Answers

Increase the force the engine provides and decrease the mass of the car
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