typically, in which type of claim is it most important to have a random sample?

Answers

Answer 1

It is most important to have a random sample in inferential statistics, particularly in making statistical inferences about a population based on the sample data.

Random sampling is a critical component of inferential statistics because it helps to ensure that the sample is representative of the population. When a sample is randomly selected, each member of the population has an equal chance of being included in the sample, which reduces the risk of bias in the results. Without a random sample, the results of statistical analyses may not be accurate or generalizable to the population, and the conclusions drawn from the data may be flawed or misleading.

Therefore, random sampling is crucial in making valid statistical inferences about a population.

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Related Questions

100 points and mark brainly please hurrryy

Answers

Ans: 52 cm²

Ok done. Thank to me >:333

On December 17, 2007 baseball writer John Hickey wrote an article for the Seattle P-I External link about increases to ticket prices for Seattle Mariners games during the 2008 season. The article included a data set that listed the average ticket price for each MLB team, the league in which the team plays (AL or NL), the number of wins during the 2007 season and the cost per win (in dollars). The data for the 16 National League teams are shown below. team league price wins cost/win
Order goes
Team/ League/ Price/ Wins/ cost per win
Arizona Diamondbacks /NL /19.68/ 90 /35.40
Atlanta Braves NL 17.07 /84/ 32.89
Chicago Cubs NL 34.30 /85/ 65.33
Cincinnati Reds NL 17.90 /72 /40.32
Colorado Rockies NL 14.72 /90 /26.67
Florida Marlins NL 16.70 /71 /38.13
Houston Astros NL 26.66 /73 /59.11
Los Angeles Dodgers NL 20.09 /82 /34.64
Milwaukee Brewers NL 18.11 /83 /35.37
N.Y. Mets NL 25.28 /88 /46.56
Philadelphia Phillies NL 26.73 /89 /48.69
Pittsburgh Pirates NL 17.08 /68 /40.67
San Diego Padres NL 20.83 /89 /38.15
San Francisco Giants NL 24.53 /71/ 56.00
St. Louis Cardinals NL 29.78 /78 /61.91
Washington Nationals NL 20.88 /73 /46.30
Compute the correlation between average 2007 price and number of 2007 wins for these 16 teams. (Assume the correlation conditions have been satisfied and round your answer to the nearest 0.001.)

Answers

The correlation between average 2007 price and number of 2007 is 0.207

To compute the correlation between the average 2007 price and the number of 2007 wins for the 16 National League baseball teams, we can use the formula for Pearson's correlation coefficient.

First, we need to calculate the following sums:

Sum of prices (ΣX) = 19.68 + 17.07 + 34.30 + 17.90 + 14.72 + 16.70 + 26.66 + 20.09 + 18.11 + 25.28 + 26.73 + 17.08 + 20.83 + 24.53 + 29.78 + 20.88 = 387.47

Sum of wins (ΣY) = 90 + 84 + 85 + 72 + 90 + 71 + 73 + 82 + 83 + 88 + 89 + 68 + 89 + 71 + 78 + 73 = 1296

Sum of products of prices and wins (ΣXY) = (19.68 * 90) + (17.07 * 84) + (34.30 * 85) + (17.90 * 72) + (14.72 * 90) + (16.70 * 71) + (26.66 * 73) + (20.09 * 82) + (18.11 * 83) + (25.28 * 88) + (26.73 * 89) + (17.08 * 68) + (20.83 * 89) + (24.53 * 71) + (29.78 * 78) + (20.88 * 73) = 24839.87

Sum of squared prices (ΣX^2) = (19.68)^2 + (17.07)^2 + (34.30)^2 + (17.90)^2 + (14.72)^2 + (16.70)^2 + (26.66)^2 + (20.09)^2 + (18.11)^2 + (25.28)^2 + (26.73)^2 + (17.08)^2 + (20.83)^2 + (24.53)^2 + (29.78)^2 + (20.88)^2 = 19151.7899

Sum of squared wins (ΣY^2) = (90)^2 + (84)^2 + (85)^2 + (72)^2 + (90)^2 + (71)^2 + (73)^2 + (82)^2 + (83)^2 + (88)^2 + (89)^2 + (68)^2 + (89)^2 + (71)^2 + (78)^2 + (73)^2 = 94518

Using these sums, we can calculate the correlation coefficient (r):

r = (n * ΣXY - ΣX * ΣY) / sqrt((n * ΣX^2 - (ΣX)^2) * (n * ΣY^2 - (ΣY)^2))

where n is the number of data points, which in this case is 16.

Substituting the values:

r = (16 * 24839.87 - 387.47 * 1296) / sqrt((16 * 19151.7899 - (387.47)^2) * (16 * 94518 - (1296)^2))

Calculating this expression gives us:

r ≈ 0.207

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in the past, the mean running time for a certain type of flashlight battery has been 8 hours. the manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has changed as a result. what are the appropriate null and alternate hypotheses?

Answers

To test these hypotheses, appropriate statistical methods such as a t-test or z-test can be employed, depending on the sample size and whether the population standard deviation is known

In this scenario, the appropriate null and alternative hypotheses can be formulated based on the objective of the hypothesis test. Let's consider the mean running time of the flashlight battery as the parameter of interest.

Null Hypothesis (H0): The mean running time of the flashlight battery is equal to 8 hours.

Alternative Hypothesis (Ha): The mean running time of the flashlight battery has changed, either increased or decreased, as a result of the production method change.

Symbolically, the hypotheses can be represented as:

H0: μ = 8 (mean running time is equal to 8 hours)

Ha: μ ≠ 8 (mean running time is not equal to 8 hours)

Here, μ represents the population mean running time of the flashlight battery. The null hypothesis assumes that the mean running time remains unchanged at 8 hours, while the alternative hypothesis allows for any deviation from this value.

. These tests would help analyze the sample data and provide evidence to either accept or reject the null hypothesis in favor of the alternative hypothesis.

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in the past, the mean running time for a certain type of flashlight battery has been 8 hours. the manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has changed as a result. what are the appropriate null and alternate hypotheses?

brennan's breakfast goodies recently sold 20 muffins, of which 4 were pumpkin spice muffins. what is the experimental probability that the next muffin sold will be a pumpkin spice muffin? write your answer as a fraction or whole number. p(pumpkin spice muffin)

Answers

Answer:

The experimental probability of the next muffin sold being a pumpkin spice muffin is 1/5.

Step-by-step explanation:

The experimental probability of the next muffin sold being a pumpkin spice muffin can be calculated as the ratio of the number of pumpkin spice muffins sold to the total number of muffins sold. In this case, 4 out of 20 muffins were pumpkin spice. So the experimental probability can be expressed as 4/20 or simplified to 1/5.

Solve the application problem.

The Sweetest Jelly Company sells jellies in 3/4
pound jars. How many jars can be filled from 12 pounds of jelly?

Answers

Answer:

12 ÷ 3/4 = 12 × 4/3 = 48/3 = 16

Step-by-step explanation:

We know that each jar contains 3/4 of a pound of jelly. To find out how many jars we can fill with 12 pounds of jelly, we need to divide 12 by 3/4.

To divide by a fraction, we can flip the fraction and multiply.

So:

12 ÷ 3/4 = 12 × 4/3 = 48/3 = 16

Therefore, we can fill 16 jars with 12 pounds of jelly.

Answer:

1/16

Step-by-step explanation:

= 3/4 divided by 12

= 3/4*1/12

= 1/16

** The integer 15 would BEST represent which situations? 4 A points taken away for bad behavior B points given for good behavior C D students adding classes to schedule price increases E price cuts 2023, All Rights Reserved Temms | Privacy PHONE 1-877-377-0537 FAX 1-877-816-0808 Blog​

Answers

The integer 15 would best represent points given for good behavior.

We have,

In situation B,

The integer 15 represents a positive quantity or value that is given or awarded to individuals for exhibiting good behavior.

It can be interpreted as a form of positive reinforcement or recognition for demonstrating desirable conduct.

For example, in a reward system implemented in a classroom or organization, students may earn points for following rules, completing tasks, or displaying positive behaviors.

Each point signifies progress or achievement, and when students accumulate a certain number of points, they may be eligible for rewards or incentives.

The integer 15, in this context, serves as a numerical representation of the rewards or points associated with good behavior.

It indicates a positive outcome and reinforces the desired conduct by providing tangible recognition or benefits.

Thus,

The integer 15 would best represent points given for good behavior.

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Mrs Li baked a pie. She ate 1/3of the pie. Mr li ate 2/9 more pie than Mrs Li. What fraction of the pie did they have left

Answers

If Mrs. Li ate 1/3 of the pie, that means there are 2/3 of the pie left. Mr. Li then ate 2/9 more than Mrs. Li. To find out how much he ate, we first need to add 2/9 to 1/3.

We can find a common denominator by multiplying the denominators of 1/3 and 2/9, which is 9. Thus, 1/3 can be rewritten as 3/9, and 2/9 can be left as is. Adding them together gives us 5/9. Therefore, Mr. Li ate 5/9 of the pie. To find out how much pie is left, we can subtract 5/9 from the 2/3 that was left after Mrs. Li ate her portion. This gives us 1/9 of the pie left, which is the answer to the question.

Mrs. Li had 2/3 of the pie left after eating 1/3.

Mr. Li ate 2/9 more pie than Mrs. Li, so he ate:

(2/9) * (1/3) = 2/27 of the pie.

Together, Mrs. and Mr. Li ate:

1/3 + 2/27 = 9/27 + 2/27 = 11/27 of the pie.

Therefore, they had 1 - 11/27 = 16/27 of the pie left.

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Will mark brainliest and give points

A small sample shows that on average 29% of kids in a class spend 4 hours or more
on thier cell phone with a margin of error of +/- 2.5%. The school has 3650 students
in total.
What is the minimum amount of students that spend more than 4 hours on their
phone . What is the maximum amount of students that spend more than 4
hours on thier phone
ROUND TO AND APPROPRIATE POSITION

Answers

Sample proportion = 29% = 0.29
Margin of error = +/- 2.5% = 0.025
Total number of students = 3650

To find the minimum number of students that spend more than 4 hours on their phone, we can use the lower bound of the confidence interval:

Lower bound = sample proportion - margin of error
Lower bound = 0.29 - 0.025
Lower bound = 0.265

Minimum number of students = 0.265 x 3650
Minimum number of students = 968.25
Minimum number of students that spend more than 4 hours on their phone = 968 (rounded down to the nearest whole number)

To find the maximum number of students that spend more than 4 hours on their phone, we can use the upper bound of the confidence interval:

Upper bound = sample proportion + margin of error
Upper bound = 0.29 + 0.025
Upper bound = 0.315

Maximum number of students = 0.315 x 3650
Maximum number of students = 1149.75
Maximum number of students that spend more than 4 hours on their phone = 1150 (rounded up to the nearest whole number)

Therefore, the minimum number of students that spend more than 4 hours on their phone is 968, and the maximum number of students that spend more than 4 hours on their phone is 1150.
B i just took the test

A cylinder has a radius of 4 meters. Its volume is 803. 84 cubic meters. What is the height of the cylinder

Answers

The height of the cylinder is 20 meters.

To find the height of the cylinder, we can use the formula for the volume of a cylinder, which is given by V = πr^2h, where V represents the volume, r represents the radius, and h represents the height.

In this case, we are given the radius as 4 meters and the volume as 803.84 cubic meters. We can substitute these values into the formula to solve for the height.

803.84 = π * 4^2 * h

Simplifying further, we have:

803.84 = 16πh

To isolate h, we can divide both sides of the equation by 16π:

h = 803.84 / (16π)

Using the approximation of π as 3.14, we can calculate:

h ≈ 803.84 / (16 * 3.14)

h ≈ 50.99

Therefore, the height of the cylinder is approximately 50.99 meters.

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let r be the shaded region in the first quadrant enclosed by the graphs of y=e^-x^2
how do you find the area of the region R?

Answers

To find the area of the shaded region R enclosed by the graphs of y = e^(-x^2) in the first quadrant, you can use integration.

The integral represents the area under a curve between two x-values. In this case, we want the area in the first quadrant, so we need to integrate the function from x = 0 to some positive x-value.

The integral to find the area of R is given by:

A = ∫[0 to a] e^(-x^2) dx

Unfortunately, there is no elementary function to find the antiderivative of e^(-x^2) in terms of elementary functions. Therefore, the integral cannot be evaluated using simple algebraic methods.

However, the integral can be approximated using numerical methods or specialized techniques such as Gaussian quadrature or Monte Carlo methods. These methods can provide an approximation of the area of the shaded region R.

Alternatively, you can use software or graphing calculators that have built-in functions to find definite integrals to numerically approximate the area under the curve.

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Find the perimeter of quadrilateral ABCD.
A(-2,1), B(3,1), C(3,-3), D(-2,-3)

Answers

The Perimeter of quadrilateral ABCD is calculated as: AB + BC + CD + AD = 5 + 4 + 5 + 4 = 18 units.

How to Find the Perimeter of a Quadrilateral?

The perimeter of the quadrilateral ABCD is calculated as the sum of all its side, which is:

Perimeter = AB + BC + CD + AD

Given the following:

A(-2,1),

B(3,1)

C(3,-3)

D(-2,-3)

Find the length of each sides as shown below:

AB = |-2- 3| = |-5| = 5 units.

BC = |1 - (-3)| = 4 units

CD = |3 - (-2)} = 5 units

AD = |1 - (-3)| = 4 units

Perimeter of quadrilateral ABCD = 5 + 4 + 5 + 4

= 18 units.

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the midrange of a distribution is defined as the average of the maximum and the minimumof that distribution. is this statistic robust to outliers and extreme skew? explain your reasoning

Answers

The midrange of a distribution, defined as the average of the maximum and minimum values, is not robust to outliers and extreme skew. It is influenced by extreme values, resulting in an inflated or deflated measure of central tendency. Therefore, it is not a reliable statistic in the presence of outliers and extreme skew.

The midrange is calculated by taking the average of the maximum and minimum values in a distribution. While it provides a simple measure of central tendency, it is sensitive to outliers and extreme skew.

Outliers are extreme values that fall far outside the typical range of the data. When outliers are present, they can significantly affect the maximum and minimum values, leading to an inflated or deflated midrange. For example, if there is a single extremely large or small value, the midrange will be pulled towards that extreme, giving a distorted representation of the central tendency.

Similarly, extreme skewness, where the distribution is heavily skewed towards one tail, can also impact the midrange. In such cases, the minimum or maximum value may be heavily influenced by the skewed portion of the distribution, leading to an inaccurate estimate of the central tendency.

In contrast, robust measures of central tendency, such as the median or trimmed mean, are less affected by outliers and extreme skew. They are designed to be more resistant to extreme values and provide a more reliable estimate of the typical value in a distribution.

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There are three different types of sandwiches on a shelf.
There are
4 egg sandwiches,
5 cheese sandwiches
and 2 ham sandwiches.
Erin takes at random 2 of these sandwiches.
Work out the probability that she takes 2 different types of sandwiches.
(5 marks)

Answers

The probability of taking 2 different types of sandwiches is 0.691

Calculating the probability of taking 2 different types of sandwiches.

From the question, we have the following parameters that can be used in our computation:

4 egg sandwiches,5 cheese sandwiches2 ham sandwiches.

The total number of sandwiches is

4 + 5 + 2 = 11

So, the probability of taking the same types of sandwiches is

P(Same) = (4/11 * 3/10) + (5/11 * 4/10) + (2/11 * 1/10)

This means that the probability of taking 2 different types of sandwiches is

P(Different) = 1 - [(4/11 * 3/10) + (5/11 * 4/10) + (2/11 * 1/10)]

Evaluate

P(Different) = 0.691

Hence, the probability is 0.691

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find the area of this shape

Answers

The area of the shape in the figure, obtained by finding the areas of the component figures is; 31

What is a composite figure?

A composite figure is a figure that is comprised of two or more simpler figures.

The areas of the squares can be found by summing the areas of the each unit squares where available as follows;

The number of squares in the rows 3 to 9 = 25 squares

The area for the squares in the  rows 3 to 9 = 25 square centimeters

The area of the parallelogram = Base length × Height

The base length  =  3 cm

The height of the parallelogram  = 2 cm

Area of the parallelogram = 3 cm × 2 cm = 6 cm²

The area of the figure = 25 + 6 = 31

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HELP ME ASAP Solve the application problem.


A student's tuition was $1500. If a scholarship paid for 4/5

of the tuition, how much was the scholarship?

Answers

If student's tuition was $1500, if a scholarship paid for 4/5

of the tuition then $1200 is the scholarship

Given that a student's tuition was $1500

If a scholarship paid for 4/5 of the tuition

We need to find the how much was the scholarship

To find this we have to multiply 4/5 with $1500

4/5×1500

$1200

Hence, if student's tuition was $1500, if a scholarship paid for 4/5

of the tuition then $1200 is the scholarship

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in the item procurement importance matrix, what item is described as low risk, low value?

Answers

In the item procurement importance matrix, the item described as low risk, low value is referred to as a non-critical item.

The item procurement importance matrix is a tool used in procurement management to categorize items based on their importance and risk. It helps in determining the appropriate procurement strategies and allocation of resources. The matrix typically categorizes items into four quadrants based on their value and risk levels: critical, strategic, non-critical, and bottleneck.

A non-critical item is characterized by low risk and low value. These items are generally of lesser importance in terms of their impact on the overall procurement process. They may include non-essential or low-cost items that are easily replaceable or have minimal consequences if they experience delays or disruptions in the supply chain.

Therefore, in the item procurement importance matrix, the item described as low risk, low value is categorized as a non-critical item.

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a projectile is shot straight up from the earth's surface at a speed of 1.30×104 km/hr. How high does it go?

Answers

Therefore, the projectile goes approximately 6.9 × 10^6 meters or 6,900 kilometers high.

Let's first convert the initial speed from km/hr to m/s to be consistent with the unit of acceleration due to gravity.

1.30×10^4 km/hr = (1.30×10^4 × 1000 m/km) / (3600 s/hr) = 3611.11 m/s

We can use the kinematic equation: Δy = v0t + 1/2at^2 to determine the maximum height reached by the projectile. At the highest point, the velocity is zero, so we can use the fact that v = v0 + at = 0 to find the time it takes to reach the maximum height.

v0 = 3611.11 m/s (initial velocity)

a = -9.81 m/s^2 (acceleration due to gravity)

t = -v0/a = -3611.11/(-9.81) = 367.97 s (time to reach maximum height)

Now we can use the time to find the maximum height reached:

Δy = v0t + 1/2at^2 = 3611.11 × 367.97 + 1/2 × (-9.81) × (367.97)^2 ≈ 6.9 × 10^6 meters

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WILL GIVE BRAINLIST TO BEST ANSWER

Find the value of x that makes lines u and v parallel

Answers

If those two given angles combined = 180, then u and v are parallel.

(91 + x) + 95 = 180

186 + x = 180

x = 180-186

x = -6

When x = -6, lines u and v are parallel.

Help me on all problems pls

Answers

The vertex of the function f(x)=(x-3)²-2 is (3, -2).

13) The given function is f(x)=x²+1.

Rewrite in vertex form and use this form to find the vertex (h, k).

(0, 1)

14) The given function is f(x)=(x-3)²-2.

Rewrite in vertex form and use this form to find the vertex (h, k).

(3, -2)

15) The given functions are f(x)=x² and f(x)= -1/2 x²

To find the transformation, compare the function to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.

Horizontal Shift: None

Vertical Shift: None

Reflection about the x-axis: Reflected

Reflection about the y-axis: None

Vertical Compression or Stretch: Compressed

16) The given functions are f(x)=x² and f(x)= x²-1

To find the transformation, compare the function to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.

Horizontal Shift: None

Vertical Shift: Down 1 Units

Reflection about the x-axis: None

Reflection about the y-axis: None

Vertical Compression or Stretch: None

Therefore, the vertex of the function f(x)=(x-3)²-2 is (3, -2).

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tina randomly selects two distinct numbers from the setand sergio randomly selects a number from the setwhat is the probability that sergio's number is larger than the sum of the two numbers chosen by tina?

Answers

Therefore, the probability that Sergio's number is larger than the sum of the two numbers chosen by Tina is 11/15, or about 0.733.

We can approach this problem by finding the probability of Sergio's number being less than or equal to the sum of Tina's numbers, and then subtracting this probability from 1.

The total number of ways for Tina to select two distinct numbers from the set is 6 choose 2, which is 15. Each pair of numbers has an equal chance of being selected, so we can assume that each pair has probability 1/15 of being selected.

Now, for each pair of numbers Tina selects, there is a range of numbers that Sergio can select such that his number is greater than the sum of Tina's numbers. Specifically, Sergio's number must be greater than the smaller of Tina's numbers and less than or equal to the largest number in the set.The length of this shaded region is 6 - 2 = 4. Therefore, the probability of Sergio's number being greater than the sum of Tina's numbers for a given pair of numbers is 4/6 = 2/3.

The probability of Tina selecting any particular pair of numbers is 1/15, so the probability of Sergio's number being greater than the sum of Tina's numbers for that pair is (2/3)(1/15) = 2/45.

To find the total probability, we sum up the probabilities for all pairs of numbers:

(2/45) + (2/45) + (2/45) + (2/45) + (2/45) + (2/45) = 12/45 = 4/15

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35. Graph the system of inequalities
on the set of axes below:
y<_-3/4x+5
3x-2y>4
6, 3) a solution to the system of inequalities? Explain your answer

Answers

A graph of the system of inequalities is shown on the set of axes below

No, (6, 3) is not a solution to the system of inequalities.

How to graphically solve this system of inequalities?

In order to graphically determine the solution for this system of linear inequalities on a coordinate plane, we would make use of an online graphing calculator to plot the given system of linear inequalities while taking note of the point of intersection;

y ≤ -3x/4 + 5            ......equation 1.

3x - 2y > 4       ......equation 2.

Based on the graph shown (see attachment), we can logically deduce that the solution for this system of linear equations is the point of intersection of each lines on the graph that represents them, which is represented by this ordered pair (3, 2).

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suppose that 8% of the patients tested in a clinic are infected with hiv. furthermore, suppose that when a blood test for hiv is given, 98% of the patients infected with hiv test positive and that 3% of the patients not infected with hiv test positive. what is the probability that a) a patient testing positive for hiv with this test is infected with it? b) a patient testing positive for hiv with this test is not infected with it? c) a patient testing negative for hiv with this test is infected with it? d) a patient testing negative for hiv with this test is not infected with it?

Answers

a) The probability that a patient testing positive for HIV with this test is infected with it is approximately 73.96%

b) With this test, there is a 26.04% chance that a patient who tests positive for HIV is not actually infected.

c) The probability that a patient testing negative for HIV with this test is infected with it is approximately 0.18%.

d) The probability that a patient testing negative for HIV with this test is not infected with it is approximately 99.82%.

What is probability?

Gonna determine how likely something is gonna occur, use probability. Many things are hard to predict with 100% certainty. We can only anticipate the possibility of an event occurring using it, or how likely it is.

Let's denote the events as follows:

A = Patient is infected with HIV

B = Patient tests positive for HIV

Given information:

P(A) = 0.08 (probability of a patient being infected with HIV)

P(B|A) = 0.98 (probability of testing positive given the patient is infected with HIV)

P(B|A') = 0.03 (probability of testing positive given the patient is not infected with HIV)

We need to find:

a) P(A|B) = Probability that a patient testing positive for HIV is infected with it.

b) P(A'|B) = Probability that a patient testing positive for HIV is not infected with it.

c) P(A|B') = Probability that a patient testing negative for HIV is infected with it.

d) P(A'|B') = Probability that a patient testing negative for HIV is not infected with it.

We can use Bayes' theorem to find these probabilities:

a) P(A|B)=P(B|A)*P(A)/P(B)

b) P(A'|B)=P(B|A')*P(A')/P(B)

c) P(A|B') = P(B'|A) * P(A) / P(B')

d) P(A'|B') = P(B'|A') * P(A') / P(B')

To find P(B), we can use the law of total probability:

P(B)=P(B|A)*P(A)+P(B|A')*P(A')

First, let's calculate P(B):

P(B)=P(B|A)*P(A)+P(B|A')*P(A')

     = 0.98 * 0.08 + 0.03 * (1 - 0.08)

     = 0.0784 + 0.0276

     = 0.106

Now, we can calculate the probabilities:

a) P(A|B)=P(B|A)*P(A)/P(B)

          = 0.98 * 0.08 / 0.106

          = 0.0784 / 0.106

          ≈ 0.7396 (or 73.96%)

b) P(A'|B)=P(B|A')*P(A')/P(B)

           = 0.03 * (1 - 0.08) / 0.106

           = 0.0276 / 0.106

           ≈ 0.2604 (or 26.04%)

c) P(A|B') = P(B'|A) * P(A) / P(B')

          = (1 - P(B|A)) * P(A) / (1 - P(B))

          = (1 - 0.98) * 0.08 / (1 - 0.106)

          = 0.02 * 0.08 / 0.894

          ≈ 0.0018 (or 0.18%)

d) P(A'|B') = P(B'|A') * P(A') / P(B')

           = (1 - P(B|A')) * (1 - P(A)) / (1 - P(B))

           = (1 - 0.03) * (1 - 0.08) / (1 - 0.106)

           = 0.97 * 0.92 / 0.894

           ≈ 0.9982 (or 99.82%)

Therefore:

a) The probability that a patient testing positive for HIV with this test is infected with it is approximately 73.96%

b) The probability that a patient testing positive for HIV with this test is not infected with it is approximately 26.04%.

c) The probability that a patient testing negative for HIV with this test is infected with it is approximately 0.18%.

d) The probability that a patient testing negative for HIV with this test is not infected with it is approximately 99.82%.

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suppose that diameters of a new species of apple have a bell-shaped distribution with a mean of 7.2cm and a standard deviation of 0.38cm . using the empirical rule, what percentage of the apples have diameters that are no more than 6.44cm ? please do not round your answer.

Answers

Using the empirical rule, we know that approximately 95% of the data falls within two standard deviations of the mean.

We can use the empirical rule, also known as the 68-95-99.7 rule. According to this rule, approximately 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.
In this case, we want to know what percentage of apples have diameters that are no more than 6.44cm. To find out, we need to determine how many standard deviations this value is from the mean.
First, we calculate the z-score (number of standard deviations from the mean) using the formula z = (x - μ) / σ, where x is the diameter we're interested in, μ is the mean, and σ is the standard deviation.
z = (6.44 - 7.2) / 0.38 = -2
This means that 6.44cm is 2 standard deviations below the mean.
Using the empirical rule, we know that approximately 95% of the data falls within two standard deviations of the mean. Therefore, we can conclude that approximately 95% of the apples have diameters that are greater than 6.44cm, and the remaining 5% have diameters that are no more than 6.44cm.
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If a hummingbird is filmed at 140 frames in one second, there are 140 photos of the hummingbird. If you played the film at 10 frames per second, how long would the film play?

Answers

Answer:

If the hummingbird is filmed at 140 frames in one second, and the film is played at 10 frames per second, then the film would play for 14 seconds.

Step-by-step explanation:

Using dimensional analysis:

140 frames / (10 frames /sec)  =  14 seconds

Charlie's teacher claims that he does not study and just guesses on exams. on an exam with 201 true-false questions, Charlie answered 53.7% of the questions correctly. Calculations using these results show that if he were really just guessing, there would be roughly one chance and seven that he would do this well. Is there a statistically significant evidence against the teachers claim that Charlie is just guessing? Why or why not?

Answers

Answer:

Step-by-step explanation:

True-False questions consists of 2 possible answer, which are 50% each, so basically is Charlie was just guessing 201 questions, which means his possibility of getting everything correct is [tex]\frac{1}{2^2^0^1}[/tex], which is really small, his chance of getting 53,7% correct is [tex]\frac{1}{2^2^0^1 * 0.537}[/tex] which is roughly arround [tex]\frac{1}{2^2^0^0}[/tex]

Please help, I dont understanddd

Answers

Tyler's age when he was inaugurated is given as follows:

50.3 years old.

How to use the normal distribution?

The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is obtained by the equation presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score represents how many standard deviations the measure X is above or below the mean of the distribution of the data-set, depending if the obtained z-score is positive(above the mean) or negative(below the mean).The z-score table is used to obtain the p-value of the z-score, and it represents the percentile of the measure X in the distribution.

The mean and the standard deviation for this problem are given as follows:

[tex]\mu = 54.6, \sigma = 6.3[/tex]

The z-score associated with the 25th percentile is given as follows:

Z = -0.675.

Hence Tyler's age is obtained as follows:

-0.675 = (X - 54.6)/6.3

X - 54.6 = -0.675 x 6.3

X = 50.3.

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One-half of a number diminished by 2 is 4. Find the number.

Answers

Step-by-step explanation:

Depends on how you read it :

x = the number

1/2 x -2 = 4

x = 12             <==== I suspect this is the answer wanted

               

or  

1/2 ( x-2)  = 4

x = 10  

Jane must verify the height of a cell tower for a report, given the measurements of some of the tower's parts. She is able to determine the angles and lengths herself; she obtains other specifications from researching the tower design. One side of the bottom of the cell tower is shown. All measurements and specifications are given below.

Answers

Answer:

23

Step-by-step explanation:

4. Two numbers are shown on the number line?
A. ㅠ
9/3
Which value is NOT located between these two
numbers on the number line?
B. 9

C. 픔
D.
이름 이

Answers

ㅠ is not located between these two numbers on the number line.

The values 3 and √9/3 are located at 3 and √3 on the number line, respectively.

The value π is not located between these two numbers on the number line.

π is approximately 3.14, which is between 3 and 4 on the number line, but it is not between 3 and√3.

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Which of the following is (are) assumption(s) underlying the use of the F test?
A. the raw score populations are normally distributed
B. the variances of the raw score populations are the same
C. the mean of the populations differ
D. the raw score populations are normally distributed and the variances of the raw score populations are the same

Answers

The F test is a statistical test used to compare variances between two or more groups of data. It is often used in ANOVA (analysis of variance) to determine whether the means of three or more groups are significantly different. D. the raw score populations are normally distributed and the variances of the raw score populations are the same

Assumptions underlying the use of the F test include the normal distribution of raw score populations and the equality of variance between groups. The first assumption, that raw score populations are normally distributed, is important because the F test assumes that the population variances are normally distributed. If the distribution of the raw score population is not normal, the F test may not be appropriate.

The second assumption, that the variances of the raw score populations are equal, is also important. The F test assumes that the variance of the populations is equal, and if this assumption is violated, it may lead to inaccurate results. Therefore, the correct answer to the question is D, as both assumptions are required for the F test to be used accurately. If either assumption is not met, it may be necessary to use a different statistical test to analyze the data.

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