typically, over 60% of the mass of a piece of bubble gum is made up of sugar. sugar is dissolved in the mouth and swallowed during chewing. if gum is chewed precisely until it loses its flavor, most if not all of the sugar content of the gum should be gone. how would this affect the mass of the gum? how will the mass of gum be affected by chewing time? how does the chewing time necessary to lose significant mass compare between different brands/types of gum? how large a role does saliva play in the processing of gum in the mouth?
Answers
Answer:
Hello your question is incomplete attached below is the complete question
A) How the mass will be affected by chewing time
The chewing time is an independent variable while the mass of the gum is a dependent variable and would change with increase in chewing time as seen in the regular gum the average mass increase above the average sugar mass before chewing
B) how the chewing time necessary to lose significant mass
The chewing time is neccessary to lose significant mass as seen in the sugar free chewing gum because the more time the gum is chewed the lesser the mass due to the absence/lose of sugar
C) The role saliva play in the processing of gum in the mouth
The saliva mixes up with the sugar contained in the chewing gum to increase its mass as seen when you compare the mean mass value of sugar contained in the regular chewing gum with the mean mass value of the gum after chewing for some time i.e 3.58 < 5.03 , 4.09
Explanation:
we will make two assumptions in order to resolve the given problem
next we have to calculate the mean(average) mass of the Chewing gums for each time interval
Regular gum :
initial mean mass = 5.96
mean mass after 1 minute = 5.03
mean mass after 2 minutes = 4.09
next we calculate the mean mass of sugar in the regular gum using this relationship :summation of( initial masses * 60/100 )/ 4 = 3.58 comparing it the the mass of the chewing gum at different time intervals i.e 1 minute and 2 minutes
sugar free gum :
initial mean mass = 2.98
mean mass after 1 minute = 2.59
mean mass after 2 minutes = 2.32
A) How the mass will be affected by chewing time
The chewing time is an independent variable while the mass of the gum is a dependent variable and would change with increase in chewing time as seen in the regular gum the average mass increase above the average sugar mass before chewing
B) how the chewing time necessary to lose significant mass
The chewing time is neccessary to lose significant mass as seen in the sugar free chewing gum because the more time the gum is chewed the lesser the mass due to the absence/lose of sugar
C) The role saliva play in the processing of gum in the mouth
The saliva mixes up with the sugar contained in the chewing gum to increase its mass as seen when you compare the mean mass value of sugar contained in the regular chewing gum with the mean mass value of the gum after chewing for some time i.e 3.58 < 5.03 , 4.09
Related Questions
Amino acid Is a compound that contains at least
Answers
They contain Carbon, Nitrogen, Hydrogen, Oxygen, and Sulfur
CALCULATE: you need to type/show your work. There is no credit if the work is not show/typed Titanium has five common isotopes: 46Ti (8.00%), mass= 45.953 amu 47 Ti (7.80%), mass= 46.952 amu 48Ti (73.40%), mass= 47.947 amu 49Ti (5.50%), mass= 48.948 amu 50Ti (5.30%), mass = 49.945 amu Calculate the average atomic mass of titanium.
Answers
Answer:
47.871 amu
Explanation:
Average atomic mass of an atom is obtained from the sum of the mass of the isotopes multiplicated by its natural abundance.
That means atomic mass of Ti is:
Ti = 45.953*8.00% + 46.952*7.80% + 47.947*73.40% + 48.948*5.50% + 49.945*5.30%
Average atomic mass of Ti:
47.871 amuHow many electrons are found in an atom of Oyxgen?
10 points
16
O 24
8
Answers
Answer:
8 electrons.
Explanation:
On a periodic table, one can see that Oxygen has 8 protons.
The number of protons in a neutral atom will always equal the number of electrons.
Weak noncovalent interactions:__________ a. do not include ionic interactions b. always involve water. c. can have a large cumulative effect d. combine to form covalent interactions
Answers
Answer:
c. can have a large cumulative effect
Explanation:
Noncovalent interactions between molecules are weaker than covalent interactions. Noncovalent interactions between molecules are of various types which include van der Waals forces, hydrogen bonding, and electrostatic interactions or ionic bonding.
van der Waals forces are weak interactions found in all molecules. They include dipole-dipole interactions - formed due to the differences in the electronegativity of atoms - and the London dispersion forces.
Hydrogen Bonds results when electrons are shared between hydrogen and a strongly electronegative atoms like fluorine, nitrogen, oxygen. The hydrogen acquires a partial positive charge while the electronegative atom acquires a partial negative. This results in attraction between hydrogen and neighboring electronegative molecules.
Ionic bonds result due to the attraction between groups with opposite electrical charges, for example in common salt between sodium and chloride ions.
Even though these noncovalent interactions are weak, cumulatively, they exert strong effect. For example, the high boiling point of water and the crystal structure of ice are due to hydrogen bonding.
what would happen if the leopard attacked any one zebra or wildebeest.
Answers
Answer:
Lepord would win.
Explanation:
The Wildbeast is just another goat/sheep so its like a lepord fighting one of them so the Lepord would win.
How much grams are in 4.78 cup
Answers
Answer:
1130.89
Explanation:
Answer:
963.648
Explanat:::::::)))))))
How does physical properties differ from chemical properties? 1.Chemical properties are observed using your senses. 2.Chemical properties can only be observed using your taste sense. 3.Physical properties can be observed and chemical properties cannot. 4.Physical properties cannot be observed and chemical properties can.
Answers
Answer:
3. Physical properties can be observed and chemical properties can't
According to this food web, which of the following would be considered primary consumer?
A. Grasshoppers
B. Plants
C. Wolves
D. Mushrooms
Answers
Answer:
d mushrooms
Explanation:
The arrows on a food web point to where the energy source goes. Although mushrooms are considered decomposers, all the energy ends up at the mushroom and that is what makes a primary consumer the primary consumer no matter what.
ANSWER:
The answer is GRASSHOPPER
EXPLANATION:
Organisms feed on one another to obtain energy needed for metabolic activities. Food web is one of the ways by which the relationship between these organisms that feed on one another is displayed.
Energy flow starts from a PRODUCER, which is the plant in this food web. An organism (usually an herbivore) that feeds on the producer is referred to as PRIMARY CONSUMER. All consumers are incapable of synthesizing their own food, hence, they depend on other organisms. However, primary consumers directly depend on producers.
In the food web attached to this question as an image, the PRIMARY CONSUMER is the GRASSHOPPER because it directly feeds on the PRODUCER (plant).
Find more explanation here: https://brainly.com/question/11173626
g The tolerance of a Class A 50 mL transfer pipet is ±0.05 mL. A student uses an uncalibrated Class A transfer pipet to deliver a total of 150 mL of solution. What is the uncertainty in the delivered 150 mL? Note: tolerance is different from the uncertainty, so it does not follow the propagation formula of errors
Answers
Answer:
Uncertainty of tolerance transfer pipet = ± 0.15
Volume of liquid between = 149.85, 150.15
Given:
Size of transfer pipet = 50 ml
Tolerance transfer pipet = ± 0.05 ml
Total transfer = 150 ml
Find:
Uncertainty of tolerance transfer pipet
Computation:
Uncertainty of tolerance transfer pipet = [150 / 50](± 0.05)
Uncertainty of tolerance transfer pipet = [3](± 0.05)
Uncertainty of tolerance transfer pipet = ± 0.15
Volume of liquid between = (150-0.15), (150+0.15)
Volume of liquid between = 149.85, 150.15
If our aim is to make 100% pure alum, how could large chunks be bad?
Answers
Answer:
It prevent the solution from making 100% pure alum.
Explanation:
Large chunks could be bad if we make 100% pure alum because the large chunks prevent the production of 100% pure alum so for making 100% pure alum, large chunks will be removed from the solution or process. Alum is a chemical compound having salt of sulfate attached with aluminum in hydrated form i. e. presence of water. It is widely used in vaccines and for the purification of drinking water.
Which one of the following compounds produces a basic solution when dissolved in water? a. Na_2O b. CO_2 c. O_2 d. SO_2 e. OF_2
Answers
Answer:
a. Na_2O.
Explanation:
Hello,
In this case, the formation of a basic solution accounts for the formation of a base or hydroxide which contains hydroxide ions. Such hydroxides are formed via the combination reaction between water and a basic oxide which is formed by a metal and oxygen, that is way a. Na_2O forms the basic solution as it forms sodium hydroxide via:
[tex]Na_2O+H_2O\rightarrow 2NaOH[/tex]
Best regards.
A space air is at a temperature of 75 oF, and the relative humidity (RH) is 45%. Using calculations, find: (a) the partial pressures of the dry air and water vapor, (b) the humidity ratio of the moist air, and (c) the specific volume of the moist air. Assume standard sea-level pressure.
Answers
Answer:
A) Partial Pressure of dry air = 13.32 KPa
Partial Pressure of water vapour = 1.332 KPa
B) Humidity ratio; X = 0.0691
C) V_p = 0.8384 m³/Kg
Explanation:
A) We are given;
Temperature = 75°F
Relative Humidity = 45%
Now,to calculate the partial pressure, we will use the relationship;
Relative Humidity = (Partial Pressure/Vapour Pressure) × 100%
Making partial pressure the subject;
Partial Pressure = Relative Humidity × Vapour Pressure/100%
From the first table attached, at temperature of 75°F, the vapor pressure is 29.6 × 10^(-3) bar = 29.6 KPa
Thus;
Partial Pressure of dry air = (45 × 29.6)/100
Partial Pressure of dry air = 13.32 KPa
From online values, vapour pressure of water vapour at 75°F = 2.96 KPa
Thus;
Partial Pressure of water vapour = (45 × 2.96)/100 = 1.332 KPa
B) humidity ratio of moist air is given as;
X = 0.62198 pw / (pa - pw)
where;
pw = partial pressure of the water vapor in moist air
pa = atmospheric pressure of the moist air
Thus;
X = (0.62198 × 1.332)/(13.32 - 1.332)
X = 0.0691
C) Formula for moist air specific volume is;
V_p = (1 + (xRw/Ra) × RaT/p
Where;
V_p is specific volume
T is temperature = 75°F = 297.039 K
p is barometric pressure which in this case is standard sea level pressure = 101.325 KPa
pw is partial pressure of the water vapor in moist air = 1.332 KPa
Rw is individual gas constant for water = 0.4614 KJ/Kg.K
Ra is individual gas constant for air = 0.2869 KJ/Kg.K
V_p = (1 + (0.0691 * 0.4614/0.2869)) × 0.286.9 * 297.039/101.325
V_p = 0.8384 m³/Kg
Answer and I will give you brainiliest
Answers
Answer:
C. Solids
Particles are closely packed in solids and have less kinetic energy.
01:27:5
ES:
The table shows five items that a person may consider including in a safety contract.
Item number
1
2
Item
Label all containers.
Tie long hair back.
Bring a cell phone to the lab in case of emergency.
Bring a small laptop computer to the lab to use MSDS online.
Wear safety goggles at all times.
3
14
15
Which three of the five items would be best to include in a safety contract?
O 1, 2, and 3
1, 2, and 5
2, 3, and 4
3, 4, and 5
Answers
Answer: 1,2 and 5
Explanation:
Answer: B) 1,2, and 5
Explanation: got it right on edge
Methanol, a potential replacement for gasoline as an automotive fuel, can be made from H2 and CO by the reaction
CO(g) + 2H2(g) CH3OH(g)
At 500.0 K, this reaction has Kp = 6.25 x 10-3. Calculate ?
Answers
Answer:
[tex]\Delta G=-48.2kJ/mol[/tex]
Explanation:
Hello,
In this case, considering that the relationship between Kp and K is:
[tex]K=\frac{Kp}{RT^{\Delta \nu}}[/tex]
Whereas the change in the number of moles (stoichiometric coefficients) is:
[tex]\Delta \nu=1-2-1=-2[/tex]
The equilibrium constant is:
[tex]K=\frac{6.25x10^{-3}}{(8.314\frac{J}{mol\times K}*500.0K)^{-2}}\\\\K=1.08x10^{5}[/tex]
In such a way, the Gibbs free energy of reaction is:
[tex]\Delta G=-RTln(K)=-8.314\frac{J}{mol\times K}*500.0K*ln(1.08x10^5)\\\\\Delta G=-48.2kJ/mol[/tex]
Regards.
The ionization energy of carbon (C) is:________.
I. smaller than that of fluorine (F)
II. larger than that of fluorine (F)
because: ________.
III. Carbon has less electrons and less electron-electron repulsion making it easier to remove an electron from carbon.
IV. The effective nuclear charge of carbon is smaller, so the valence electrons feel a weaker pull from the nucleus.
V. In carbon, the electron being removed is closer to the nucleus.
VI. In carbon, the electron being removed is farther from the nucleus.
Answers
Explanation:
Ionization energy refers to the minimum amount of energy required to remove the valence electron of an isolated neutral gaseous atom or molecule. Generally, ionization energy increases from left to right across the periodic table.
This means that the ionization energy of Carbon would be smaller than that of Fluorine. The reason for this is due to the smaller effective nuclear charge.
The effective nuclear charge and the atomic size are two factors that ionization energy depends on.
The correct option is;
IV. The effective nuclear charge of carbon is smaller, so the valence electrons feel a weaker pull from the nucleus.
Which chemical symbol describes an element?
o H2O
o 02
o CH4
o H2 SO4
Answers
Answer:
H20
Explanation:
. It is a symbol of water where H = Hydrogen, O = Oxygen and2 Elements in hydrogen and 1 element in oxygen;therefore its known as H2O.
H2O is chemical symbol describes an element.
What is chemical symbol?The chemical symbol is a representation of the name of the chemical element which is discovered and expressed in the periodic table, a type of matter that is classified by the atomic number.
The periodic table the chemical elements are present according to their atomic number, electron configuration, and chemical properties.
It help everyone from different language background and used in identification of the element according to the universal chemical symbol, some symbols are H for hydrogen, Cu for copper.
Chemical symbols also applied in case of certain elements which make up the matter like water is made up of two molecules of hydrogen and 1 of oxygen, which is represented with the chemical symbol of H2O.
The chemical element is made up of atoms which have the same number of protons called the atomic number, simplest form of a substance and contains one class of atoms.
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can anyone please help with this!!
Answers
Answer:
2341, last option is the correct choice.
Explanation:
Boiling points of the given compounds are given as:
[tex]CH_4=-161.5\:C^{\circ}\\\\C_4H_{10}=-1\:C^{\circ}\\\\CH_2Cl_2=39.6\:C^{\circ}\\\\H_2O=100\:C^{\circ}[/tex]
Best Regards!
Which of the following is necessarily characterized by a covalent linkage?a. Base-pairing interactionb. Disulfide bondc. Hydrogen bondd. Induced fite. Van der Waals interaction
Answers
Answer:
b. Disulfide bond
Explanation:
Covalent linkage or bonding is a type of bond in which electrons are shared between atoms in a compound or molecule. Each atom contributes to the shared electron.
This is the case of disulfide bonding i.e. S-S, in which two thiol groups (-SH) share electrons with one another. The process of oxidation between two cysteine (amino acid) molecules forms this bond. Hence, Disulfide bond is characterized by a covalent linkage.
2A + 3B--> A2B3 If 3mL of 0.04M A, 4mL of 0.02M B and 3mL of H2O was into a reaction test tube, what are the concentrations of A and B in the test tube.
Answers
Answer:
[tex][A]=0.012M[/tex]
[tex][B]=0.008M[/tex]
Explanation:
Hello,
In this case, given the concentration and volume of each reactant, we first compute their moles in the solution:
[tex]n_A=0.003L*0.04mol/L=1.2x10^{-4}mol\\\\n_B=0.004L*0.02mol/L=8x10^{-5}mol[/tex]
Thus, since the total volume is computed given the volume of each reactant as well as the extra water, we have:
[tex]V=0.003L+0.004L+0.003L=0.010L[/tex]
Thus, the concentrations of A and B are:
[tex][A]=\frac{1.2x10^{-4}mol}{0.010L}=0.012M[/tex]
[tex][B]=\frac{8x10^{-5}mol}{0.010L}=0.008M[/tex]
Best regards.
What are the final hydrogen ion concentration and pH of a solution obtained by mixing 400mL of 0.2M NaOH with 150mL of 0.1M H3PO4?
Answers
Answer : The final hydrogen ion concentration is [tex]1.58\times 10^{-13}M[/tex]
Explanation :
The chemical reaction equation will be:
[tex]H_3PO_4+3NaOH\rightarrow Na_3PO_4+3H_2O[/tex]
In this reaction, 1 mole of [tex]H_3PO_4[/tex] reacts with 3 mole NaOH.
So, the number of moles of [tex]H_3PO_4[/tex] present in 150 ml of 0.1 M solution is calculated as follows.
Number of moles = Concentration × Volume
Number of moles = 0.1 M ×0.150 L = 0.015 mol
As it reacts with 3 moles of NaOH.
Number of moles of NaOH = 3 × 0.015 mol = 0.045 mol
So, moles of NaOH in 400 mL of 0.2 M NaOH is as follows.
Number of moles = 0.2 M × 0.4 L = 0.080 mol
Number of moles remained after the reaction = (0.080 - 0.045) mol = 0.035 mol NaOH in 550 ml (400 ml + 150 ml)
As molarity is the number of moles present in liter of solution. Hence, molarity of NaOH is as follows.
[tex]\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution}}[/tex]
[tex]\text{Molarity}=\frac{0.035mol}{0.550L}=0.0636M[/tex]
Now we have to determine the hydroxide ion concentration.
As, [tex][OH^-][/tex] = 0.0636 M
[tex]pOH=-\log [OH^-][/tex]
[tex]pOH=-\log 0.0636[/tex]
[tex]pOH=1.20[/tex]
Now we have to determine the pH.
As, pH + pOH = 14
pH = 14 - pOH
pH = 14 - 1.20
pH = 12.8
Now we have to determine the hydrogen ion concentration.
[tex]pH=-\log [H^+][/tex]
[tex]12.8=-\log [H^+][/tex]
[tex][H^+]=1.58\times 10^{-13}M[/tex]
Therefore, the final hydrogen ion concentration is [tex]1.58\times 10^{-13}M[/tex]
2. Problem: Is colored or black and white text more easily remembered? Hypothesis: If the text is colored, then the text is more easily remembered. Dependent variable: Independent variable: Control: Constants: ___________________________________________________________________ 3. Problem: Does temperature affect the speed of ants? Hypothesis: Independent variable: Dependent variable: Control: Constants: ----------------------------------------------------------------------------------------------------------------------------- 4. Problem: Does pH of the soil affect the growth of strawberries? Hypothesis: Independent variable: Dependent variable: Control: Constants: ___________________________________________________________________ 5. Problem: Does caffeine raise a person’s blood pressure? Hypothesis: Independent variable: Dependent variable: Control: Constants: ___________________________________________________________________ 6. Problem: Is heart rate affected by music? Hypothesis: Independent variable: Dependent variable: Control: Constants: ___________________________________________________________________ 7. Problem: Does bleach kill bacteria? Hypothesis: Independent variable: Dependent variable: Control:
Answers
Answer:
This question contains a lot of subsections. Please find the variables to each question below
Explanation:
Hypothesis is a testable explanation to a scientific question. It aims at proffering a testable solution to an observed problem. It usually goes in an IF, THEN format.
Dependent variable is the variable being measured in an experiment, while the independent variable is the variable that is manipulated or changed by the experimenter.
The control group is the group that does not receive the experimental treatment while constant is the variable that is kept unchanged for all groups in the experiment.
Based on this explanation, find the answers to the hypothesis, independent variable, dependent variable, constant, and control groups to each question.
2. Dependent variable: How easy it is to remember
Independent variable: Color of the text
Control: Group given Black and White text to read
Constants: Same text
3. Hypothesis: If the temperature is increased, THEN the speed of ants increases or move faster
Independent variable: TEMPERATURE
Dependent variable: SPEED OF ANTS
Control: Ants placed in room temperature
Constants: SAME KIND OF ANTS
4. Hypothesis: IF the pH of the soil is acidic or alkaline, THEN the growth of strawberries will be inhibited
Independent variable: pH of soil
Dependent variable: Growth of strawberries
Control: Strawberries grown in a Neutral pH soil
Constants: Same type of plants (strawberries)
5. Hypothesis: IF caffeine is taken, then the blood pressure will be increased or raised.
Independent variable: CAFFEINE
Dependent variable: BLOOD PRESSURE
Control: Group given no caffeine
Constants: Same amount of caffeine
6. Hypothesis: IF music is played, THEN the heart rate increases
Independent variable: MUSIC
Dependent variable: HEART RATE
Control: Groups placed where no music is played
Constants: Same type of music, same time music runs for etc.
7. Hypothesis: IF bleach is present/used, THEN bacteria will die
Independent variable: Bleach
Dependent variable: Death of bacteria
Control: Bacteria given no bleach
Constants: Same species of bacteria, Same type of bleach
This type of pollution will decay naturally
Answers
Find and fix each mistake in the following equilibrium constant expressions.
Part A
2H2S(g)?2H2(g)+S2(g)
Keq=[H2][S2][H2S]
a. Keq=[H2S]^2/[H2]2[S2]
b. Keq=[H2S]/[H2][S2]
c. Keq=[H2]^2[S2]/[H2S]^2
Part B
CO(g)+Cl2(g)?COCl2(g)
Keq=[CO][Cl2][COCl2]
a. Keq=[CO][Cl2]^2/[COCl2]^2
b. Keq=[COCl2]/[CO][Cl2]
c. Keq=[COCl2]^2/[CO][Cl2]^2
Answers
Answer:
A. c. Keq=[H2]^2[S2]/[H2S]^2
B. b. Keq=[COCl2]/[CO][Cl2]
Explanation:
Hello,
In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:
A. For the reaction:
[tex]2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)[/tex]
The equilibrium expression is:
[tex]Keq=\frac{[H_2]^2[S_2]}{[H_2S]^2}[/tex]
Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.
B. For the reaction:
[tex]CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)[/tex]
The equilibrium expression is:
[tex]Keq=\frac{[COCl_2]}{[CO][Cl_2]}[/tex]
Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].
Regards.
You have a 16 g sample of ethanol with a density of 0.7893 g/mL. What volume of ethanol do you have?
Answers
Answer:
Density is mass/volume d=m/v so volume = m/d or mass divided by density.
That would be 23 / 0.7893 = 29.1397 or 29.14 mL. Grams cancels out
Explanation:
The volume of ethanol is 20.27 g/ml.
What is volume?The area occupied by a three-dimensional object is its volume. It can be determined using density and mass. Liters are used to measure it. The overall weight of a thing is its mass. M designates it.
The mass per unit volume is known as density. The capital letter D and the symbol rho stand for density. You can figure it out by dividing the mass by the volume.
rho = m / V
rho = density
m = mass
V = volume
Given the mass of the sample of ethanol weighs 16 g
The density of 0.7893 g/mL
Putting the values in the equation
Volume = 16 / 0.7893 = 20.27
Thus, the volume of ethanol is 20.27 g/ml.
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how are pure carbon, oxygen and hydrogen different from the compound ethanol which contains all three of those elements?
Answers
Learn more:
brainly.com/question/19235553
Answer:
Explanation:
https://brainly.com/question/19235553
Lesson Question: How can you determine the specific heat of a
metal using a calorimeter?
To do this computation for each of the four metals, you needed
several measurements.
v of the metal and the water
- First, you measured the
inside the calorimeter.
the metal and added it to water in the
. Then, you
calorimeter.
12.459
- After heat transferred from the metal to the water, you measured
the
of both materials.
DONE
Intro
No
Answers
Heated
Temperature change
Hopes this help
Answer:
the person above me is correct
Explanation:
1) How many moles of atoms are in 3.00 g of 13C?2) Based on your answer in Part B, how many electrons are in this amount of 13C?3) Based on your answer in Part B, how many neutrons are in this amount of 13C?
Answers
Answer:
1) 1.39 * 10²³ atoms
2) 8.43 * 10²³ electrons
3) 9.73 * 10²³ neutrons
Explanation:
1) 13 g of C-13 contains 6.02 *10²³ atoms
3.00 g of C-13 will contain 6.02 * 10²³ * (3/13) = 1.39 * 10²³ atoms
2) Each atom of C-13 contains 6 electrons
Therefore 3.00 g of C-13 will contain 6 * 1.39 * 10²³ electrons = 8.43 * 10²³ electrons
3) Each atom of C-13 contains 7 neutrons
Therefore, 3.00 g of C-13 will contain 7 * 1.39 * 10²³ neutrons = 9.73 * 10²³ neutrons
why do oxygen and hydrogen can be kept underwater
Answers
PLEASE HELP WILL MARK BRANLIEST!!!!! Perform the following conversions. Show your set ups. a. 683 nanometer (nm) to angstrom (Å) b. 520 mi/h to m/sec c. 0.714 g/cm3 to lb/ft3 d. -164°C to °F
Answers
Explanation:
a. 1 nm = 10Å
683nm=683×10Å
=6830 Å
b. 1 mi/h=0.44704
520 mi/h=520×0.44704
=232.4608
c. 1 g/cm3=62.427961 lb/ft3
0.714 g/cm3=0.714×62.427961 lb/ft3
=44.573564
d. 1°C =9/5 +32 =33.8°F
-164°C = -164×9/5+32 = -263.2°F
Marks as brainest one.
