Ultrasound waves at intensities above 104 W/m2 can do serious damage to living tissues. a) If 104 W/m2 corresponds to 160 dB, what is the sound intensity level, in decibels, of ultrasound with intensity 105 W/m2, used to pulverize tissue during surgery? β =

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Answer 1

Ultrasound waves at intensities above 104 W/m² can do serious damage to living tissues,  104 W/m² corresponds to 160 dB, 170 dB is the sound intensity level, in decibels, of ultrasound with intensity 105 W/m²,

What is ultrasound waves?

An ultrasonic scan employs high-frequency sound waves to generate a picture of a person's interior body components. Ultrasound is frequently used by medical professionals to examine a growing foetus (unborn child), a person's abdominal and pelvic organs, muscles, tendons, heart, and blood vessels.

Given that,

Ultrasound waves at intensities above 10⁴ W/m² corresponds to 160 dB.

ultrasound with intensity 10⁵ W/m².

Sound intensity levels in dB is defined as:

β = 10 log [tex](\frac{I}{I_0})[/tex]

where [tex]I_0[/tex] is the reference intensity levels.

so, β₁ - β₂ = 10 log [tex](\frac{I_1}{I_0})[/tex] - 10 log [tex](\frac{I_2}{I_0})[/tex]

or, β₁ - β₂ = 10 log [tex](\frac{I_1}{I_2})[/tex]

or, β₁  = β₂ + 10 log [tex](\frac{I_1}{I_2})[/tex]

so, for β₂ = 160 dB, I₂ = 10⁴ W/m² , I₁ = 10⁵ W/m²

or, β₁  = β₂ + 10 log [tex](\frac{10^4}{10^5})[/tex]

or,  β₁  = 160 + 10 log [tex](\frac{10^4}{10^5})[/tex]

or, β₁  = 170 dB.

Thus, the sound intensity level is: 170 dB.

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Related Questions

A person eats an 304.39 J snack before working out. If a person uses all of their
eaten energy to lift a 8.86 kg weight. How high can they lift the weight?

Answers

The height at which the weight of mass 8.86 kg was lifted is 3.5 m.

What is height?

Height is the vertical distance between two points.

To calculate how high the weight is lifted, we use the formula below.

Formula:

H = E/mg........ Equation 1

Where:

H = Height m = Mass of the of the weightg = Acceleration due to gravityE = Energy of the person

From the question,

Given:

m = 8.86 kgE = 304.39 Jg = 9.8 m/s²

Substitute these values into equation 1

H = (304.39)/(8.86×9.8)H = 3.5 m

Hence, the height the weight can be lifted is 3.5 m.

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section 9.4) a plane flies on a bearing of 315 degrees at a speed of 400 mph when it encounters a wind blowing in the direction of n10e at a speed of 30 mph. find the true direction and speed of the plane with the wind.

Answers

In both cases, y and x components are solved and added. The resulting speed hypotenuse is then computed and its direction calculated.

Airplane:

Ф = 270 - 265 = 5°

Hypotenuse, h = 400 mph

y component = 400 Sin Ф = 400 Sin 5 = 36.61 mph

x component = 400 Cos Ф = 400 Cos 5 = 418.40 mph

Wind

Ф = 315 -210 = 60°

Hypotenuse, h = 30 mph

y component = 30 Sin 60 = 25.98 mph

x component = 30 Cos 60 = 15 mph

Total y = 36.61+25.98 = 62.59 mph

Total x = 418.40+15 = 433.40 mph

Resulting speed of airplane = Sqrt (y^2+x^2) = Sqrt (62.59^2+433.40^2) = 437.9 mph

Direction = 270 -[tan^-1 (y/x)] = 270 -[tan^-1(62.59/433.40)] = 261.78°

Therefore, the resulting speed is 437.9 mph in the direction of 261.78°

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A motorcycle accelerates from rest at 6.0 m/s2. How much farther will it travel during the second 3.0 s of its motion than during the first 3.0 s.

Answers

Solving the acceleration is S=ut +1/2at^2, S=27

How do you calculate distance using final speed and acceleration?Solving for Final Velocity from Distance and Acceleration

v 2 = v 0 2 + 2 a ( x − x 0 ) ( constant a ).

Sn = u + a (n – ½). Hence, the formula for distance travelled in nth second is given by, Sn = u + a (n – ½).

distance = speed × time.

Where an is acceleration, v is the change in velocity, and t is the time it took for that change to occur, we can write a = v / t. Meters per second per second, or m/s2, is the unit used to measure acceleration.Using the equation S=ut +1/2at^2

Where

S is displacement

u is initial velocity =0 (as the body is at rest)

a is acceleration

t is time taken

So,

S=1/2at^2

S=1/2 ×6×3 ×3

S=3×3 ×3

S=27

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what is the kinetic energy of an object with a mass of 10 kilograms traveling at a speed of 10 meters per second? assume no other forces act upon the object * 1 point captionless image a) 100 joules b) 500 joules c) 1000 joules d) 50,000 joules

Answers

The kinetic energy of the object with a mass of 10 kilograms traveling at a speed of 10 meters per seconds is 500 Joules.

Newton’s laws are encapsulated in what may be the second most famous equation in physics: F = ma, which states that a force F applied to a mass m results in an acceleration a.

Since the mass is accelerating, its velocity v is not constant, but since the acceleration is constant, and acceleration is the rate of change of velocity, the rate at which v is changing is constant and is equal to the acceleration a.

Since the work done by the force is just the energy imparted to the mass, we will use the letters K.E to stand for this work. Then we get,

K.E = ½ × m × v²

Where;

K.E = kinetic energy

m = mass

v = speed

K.E = ½ × 10 × 10²

K.E = 5 × 100 =  500 J

Hence, the correct option is b.

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for the circuit diagram below: a. find the voltage vout and the current ix. b. find the current iy. c. how much power is delivered by the 6 v source? d. find the power dissipated in the 8 kw resistor.

Answers

A. In the ideal Amp, V⁺ = V⁻

B. [tex]V_{out} = -2v[/tex]

C. [tex]P_{8K} = 4.5 m watts[/tex]

Solution:

[tex]V_{out} = 3-5 = -2v = V_{out} = -2v\\\\I_{y} = \frac{V_{out} }{500} = \frac{-2}{500} = I_{y} = -4ma[/tex]

Power delivered by 6v = P6v = (6)(1) (6)(m) -6mworth = = 6 V Vgk = (8k) (a) = (8k) (0,75 mA)

Power dissipated in the 8k = P₁₁ = (6v) (ia) = (6) (0.75 m) = 4.5 mwatts.

A schematic is a graphical representation of an electrical circuit. Schematics uses simple images of components, and schematics use standardized symbolic representations to show circuit components and connections. A schematic is a simplified representation of the components of an electrical circuit using either pictures of individual parts or standard symbols.

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gravity on the surface of the moon is only 1 6 as strong as gravity on the earth. what is the weight of a 31 kg object on the earth? the acceleration of gravity is 10 m/s2 . answer in units of n.

Answers

The weight of a 31 kg object on the earth is 304.017 newtons.

Briefly:-

Weight equals (mass of the thing) x (acceleration of gravity in that place).

— The acceleration of gravity on Earth is approximately 9.807 m/s2.

31 kilograms of mass has a weight of (31 kg) x (9.807 m/s2) = 304.017 newtons.

— On the Moon, the gravitational acceleration is approximately 1.623 m/s2.

The identical mass of 31 kg has a weight of (31 kg) x (1.623 m/s2) = 5.313 newtons.

Why is lunar gravity only one-sixth that of Earth's?

The Moon is significantly lighter in mass than the Earth. The Moon is not just smaller than the Earth, but it is also only around 60% as dense. As a result, a person weighs less on the Moon than they do on Earth due to the significantly lower gravitational attraction there.

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difference between electric force and gravitational forces is that electrical forces include * 1 point a)separation distance b)repulsive interaction c)the inverse square law e)infinite range

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Electric forces include all of the above, while gravitational forces do not.

Electric forces involve the interaction of electrically charged particles, and the strength of the force depends on the distance between the charges and the strength of the charges. The force decreases inversely with the square of the distance between the charges. The range of electric forces is theoretically infinite, meaning that the force can extend across any distance.

In contrast, gravitational forces involve the interaction of two masses and the strength of the force depends on the mass of the two objects and the distance between them. The force also decreases inversely with the square of the distance between the two masses, but the range of gravitational forces is limited to the universe.

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The electric potential along the x-axis is V=100e−2xV, where x is in meters.

What is Ex at x=1.0m?

Ex?

What is Ex at x=2.0m?

Ex?

Answers

The electric field at x = 1.0 m is 12.18.

The electric field at x = 2.0 m is 0.135.

The electric potential at a point is a scalar quantity that is used to describe the electric potential energy per unit charge at that point. In the equation you provided, V is the electric potential at a point along the x-axis and x is the position along the x-axis. To find the electric field, which is denoted by Ex, you can use the equation Ex = -dV/dx, where dV is the change in electric potential and dx is the change in position along the x-axis.

To find the electric field at x = 1.0 m, you can plug in these values into the equation to get Ex = -dV/dx = -(-100e^(-2x))/dx = 50e^(-2x) = 50e^(-2*1.0) = 50e^(-2) = 12.18.

To find the electric field at x = 2.0 m, you can plug in these values into the equation to get Ex = -dV/dx = -(-100e^(-2x))/dx = 50e^(-2x) = 50e^(-2*2.0) = 50e^(-4) = 0.135.

In both cases, the electric field is positive, indicating that the electric field is directed away from the origin.

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construct a graph corresponding to the stone's vertical velocity, vy(t).

Answers

Graph corresponding to the stone's vertical velocity, vy(t) is slant line from 1st quadrant to 4th quadrant.

Assume, For time direction 0 to 2 seconds

V  = Vo - gt

At T = 2 sec; V = 0

so, 0 = Vo - 20

Vo = 20 m/s

From T = 2 sec to T = 6sec

V = 0 - gt = -10 t

hence

Velocity vs time graph is in figure.

An object's speed and direction on a vertical plane are referred to as vertical velocity. Vertical velocity can be used to describe a variety of objects, including coins dropped into wells by children and balls flung into the air. Gravity, which constantly acts on an item to change its velocity, is a crucial factor in vertical velocity. As the ball ascends, its speed will progressively slow until it eventually comes to a stop, modifies its course, and returns to earth. Anywhere along the ball's course, its velocity can be expressed as a number. The number's sign (positive or negative) indicates the ball's direction, and its value indicates the ball's speed.

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16. Ice has lower density than water because ice: A) molecules vibrate at lower rates than water molecules: B) molecules are more compact in the solid state. sinks_ is made of open-structured, hexagonal crystals: closed sealed can of air placed ona hot stove. The contained air undergoes an Consider increase in: A) volume_ B) mass_ density . pressure and temperature. 18_ Diffraction is a result of: A) refraction: B) reflection. dispersion: interference_ thin film on water are demonstration of: Colors seen when gasoline forms interference_ B) refraction _ C) dispersion. D) reflection_ 19_ 20. Flectromagnetic waves can travel: through a vacuum. through medium through either & medium o a vacuum: D) through a current:

Answers

When water freezes, the water molecules create a crystalline structure that is held together by hydrogen bonding.

define density ?

The density of a material indicates the density of that material in a specified region. The density of a substance is defined as its mass per unit volume. Density is a measurement of how closely stuff is packed together. It is a distinct physical attribute of a certain thing. Archimedes, a Greek scientist, developed the density principle. If you know the formula and understand the units, calculating density is simple. The sign indicates density, which may also be represented by the letter D.  

Water molecules develop a crystalline structure when it freezes, which is sustained by hydrogen bonding. The density of solid water, or ice, is lower than that of liquid water. Because the orientation of hydrogen bonding leads molecules to push further apart, ice has a lower density than water.

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in a double slit experiment light of wavelength 585.0 nm is used, the separation of the slits is 0.100 mm and the viewing screen is 21.0 cm from the slits. on this screen, what is the separation between the fifth maximum and seventh minimum from the central maximum?

Answers

The separation between fifth maximum and seventh minimum from central maximum is calculated to be 2.457mm.

What is the double-slit experiment?

The double-slit experiment shows that light and matter can exhibit the properties of classically defined waves and particles. This experiment was first performed by Thomas Young in 1802 to demonstrate the wave behavior of visible light

This experiment belongs to general class of double-path experiments, in which a wave is split into two separate waves. Changes in the path length of both the waves leads to a phase shift that creates interference patterns.

Separation between 5th and 7th minima is,

= 2 * (wavelength)x(Distance of the screen) / (slit separation)

=(2x 585x10^-9 x21x10^-2 )/ 0.1x10^-3

Hence, Separation between 5th and 7th minima is =2.457mm.

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a ruby laser emits an intense pulse of light that last a mear 10 nm. the light has a wavelength of 690nm, and each pulse has an energy of 500 mj: a) how many photons are emitted with each pulse? b) what is the rate of photon emission, in photons per second, during the 10ns that the laser is on?

Answers

Making a few assumptions like uniformity and flatness of the universe we have :

A. [tex](\frac{a}{a} )^{2} = \frac{8\pi gs+\pi }{3}[/tex]

B. [tex]\frac{a}{a} = - \frac{4\pi G}{3} (S+3P)+\frac{\pi }{3}[/tex]

where is 'a' is a scale factor which tells us how expanded the Universe is. And it's the first derivative gives the rate of expansion and its second derivative gives the acceleration of the universe.

So if G increases, due to the mass of neutrons. Then the acceleration would have a negative value which would mean slowing down.

All the above however does not consider dark energy, which would modify the equations. We still have to understand the nature of dark matter to be able to predict how much in the long run would gravity affect acceleration.

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a. you launch a 0.5 kg object vertically by putting it on top of a spring which has been compressed by 12 cm and which has a spring constant of 24 kn/m . the object starts with zero initial speed and is not attached to the spring. when the spring expands and fires the object straight up, how high vertically does the object go, relative to its starting point?.

Answers

Answer:

A 0.5 kg object is launched vertically when its put on top of a spring that has been compressed by 12 cm. The spring constant is 24 kN/m.

Explanation:

which two measurements are needed in order to calculate the speed of an object in motion?

Answers

The distance travelled and the time it takes to travel that distance must be measured in order to determine an object's speed in motion.

What is motion?

Movement is the act or process of moving or changing one's location or position. ability to move with the force of a living body. gait is the term for the way a person walks. Motion can be divided into three categories depending on its type, as follows: linear movement Rotational Motion Motion in oscillations.

What are the effects of motion?

Things move in response to forces. They have the power to initiate motion, as well as to slow down, stop, or alter the path of an already moving item. We can say that forces produce changes in velocity because they alter an object's speed or direction. Keep in mind that acceleration is a modification of velocity.

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the glowing filament in a lamp is radiating energy at a rate of 60 w. at the filament’s temperature of 1500∘c, the emissivity is 0.23. what is the surface area of the flament

Answers

The surface area of the flament is -4 m square feet.

What is surface?

Surface means an outside part of an body or object.

We are asked to find the surface area. So we have to use the equation that relates power and surface area. So power is :

H= Ae σ T⁴

Where, H= power (60 watts)

A=area

σ=universal constant (5.67×10⁻⁸ w/m²)

T=Temperature(1773k)

So our surface area is just our area. A. So A. Is equal to power divided by the emissivity times of the  Stefan bolts, mons, constant to the  times the temperature to the fourth of  power.

So now we can the  substitute our values

(60/600.23)×5.67×10⁻⁸×1773⁴=4.65×10⁻⁴m²

Area of the filament is 4.65×10⁻⁴m²

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A converging lens is used to project the image of an arrow onto a screen as shown. The image is A) Real and upright B) Real and inverted C) Virtual and upright D) Virtual and inverted E) Impossible to determine

Answers

The correct option is B); Real and inverted , Since, the image is formed on the other side of lens it will be real and inverted.

When an item is positioned in front of the focal point of a converging lens, a virtual picture is created. The picture is enlarged and upright in this posture, making it simpler to observe.

When the rays come together, a true image is created. A virtual picture is always created above the primary axis, therefore it is always upright, as opposed to a real image, which is always formed below the principal axis and is always inverted.

A actual and inverted picture of an item positioned on the primary axis can only be formed by a convex lens.

While virtual pictures are created by diverging beams, real images are created by intersecting rays. While virtual pictures cannot be shown on a screen, real images may. Concave and convex lenses placed in opposition create real pictures.

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a student pushes a 51.5 kilogram bookshelf across a smooth floor with a net force of 67 n. what is the approximate acceleration of the bookshelf?

Answers

The approximate acceleration of the bookshelf is 1.3 m/s².

Using this formula

Acceleration = Net force ÷ Mass of bookshelf

Where:

Mass of bookshelf = 51.5 kilogram

Net force = 67 Newton

Let plug in the formula

Acceleration = 67 ÷ 51.5

Acceleration = 1.30 m/s²

Inconclusion the approximate acceleration of the bookshelf is:- 1.3 m/s².

What is acceleration?

An item is said to be accelerated if there is a change in its velocity. The change in the velocity of an item could be an increment or decrement in speed or a change in the direction of motion. A few examples of acceleration are the falling of an orange, the earth orbiting around the sun, or when a car is stopped at the traffic lights. Through these examples, we can deem that when there is a change in the direction of a moving item or an increment or decrement in speed, acceleration occurs.

The approximate acceleration of the bookshelf is 1.3 m/s².

Using this formula

Acceleration = Net force ÷ Mass of bookshelf

Where:

Mass of bookshelf = 51.5 kilogram

Net force = 67 Newton

Let plug in the formula

Acceleration = 67 ÷ 51.5

Acceleration = 1.30 m/s²

Inconclusion the approximate acceleration of the bookshelf is:- 1.3 m/s².

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(F=ma) How much force is required to move a 10 kilogram object 10 meters per second squared?

Question 2 options:

A. 10 - 10 = 0

B. 100 Newtons

C. 100

D. 20 Newtons

Answers

Answer:B. 100 Newtons

Explanation:

F=ma, this mean that the force is equal to the mass (10 kg) multiplied by the acceleration (10 [tex]m/s^{2}[/tex]). Plug mass and acceleration to solve: [tex]F=10*10[/tex] ∴ [tex]F=100[/tex].

The required force  to move a 10 kilogram object 10 meters per second squared be 100 Newton. So, Option(B) is correct.

What is force?

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

Given parameters:

Mass of the object = 10 kilogram.

Acceleration of the object: a = 10 meter per second squared.

So, from Newton's 2 nd law of motion, we get:

required force = mass × acceleration

= 10 × 10 Newton

= 100 Newton.

Hence, required force  to move a 10 kilogram object 10 meters per second squared be 100 Newton.

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the block is allowed to travel around the hoop for a time t1. at that moment the speed of the block is v1. the experiment is repeated but the initial speed of the block in the second trial is greater than v0. will the speed of the block after a time t1 be greater than, less than, or equal to v1?

Answers

The speed of the block after a time t1 be greater than, less than, or equal to v1 is higher.

Initial velocity is the velocity at time interval t = 0 and it's miles represented by way of u. it's far the speed at which the motion begins. they're four initial pace formulation: (1) If time, acceleration and very last pace are supplied, the initial velocity is articulated as. u = v – at.

Calculation:-

V 1 = R/ (R/v + ut)

Since the denominator is smaller. So the Velocity becomes higher.

Speed is described as. The rate of exchange of function of an item in any course. pace is measured because the ratio of distance to the time wherein the distance was included. speed is a scalar amount as it has simplest course and no magnitude.

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A current flows through a circular coil of wire. How will the strength of the magnetic field change in the center of the coil if three turns of a radius three times smaller are made from this coil?

Answers

Answer:

bhai what is yhis? i dont understand

in a double-slit experiment it is found that blue light of wavelength 446 nm gives a second-order maximum at a certain location on the screen. what wavelength of visible light would have a minimum at the same location?

Answers

Wavelength of 594.6 nm of visible light would have a minimum at the same location.

For constructive interference

d sinQ=ml=2x436nm=892nm

For destructive interference of the other light, we have

d sinQ=(m’+1/2)l

where,  d = distance between slits

            Q = angle formed

            m = order of bright fringe

            m' = order of dark fringe

            I = wavelength

When the two angle are equal, then

892nm=(m’+1/2)l

l=1784 nm for m’=0

l=613 nm for m’=1

l=368 nm for m’=2

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Indicate which of the following physics symbols denote units in which denote variables or quantities

Answers

There are a few different physics symbols that denote units, variables, or quantities:

Units: In physics, units are used to measure physical quantities. Some common units in physics include meters (m) for distance, kilograms (kg) for mass, and seconds (s) for time.Variables: Variables are quantities in physics that can take on different values. Some common variables in physics include position (x), velocity (v), and acceleration (a).Quantities: Quantities are physical quantities that can be measured. Some common quantities in physics include force (F), energy (E), and power (P).

So, to summarize, units are used to measure physical quantities, variables are quantities that can take on different values, and quantities are physical quantities that can be measured.

a reflecting telescope is built with a 10-cm-diameter mirror having a 1.00 m focal length. it is used with a 5× eyepiece. you may want to review (pages 1005 - 1007) .

Answers

A reflecting telescope is built with a 10-cm-diameter mirror having a 1.00 m focal length. it is used with a 5× eyepiece. F/10.

What is Magnification?

Magnification of the[tex]$M_{\text {tellicops }}=\frac{\text { Focallength of the objective }}{\text { focal length of the eyepiece }}$[/tex]

Focal length of the objective [tex]$=1.0 \mathrm{~m}=100 \mathrm{~cm}$[/tex]

For a magnifier, magnification [tex]$M=\frac{10}{\text { Focal length }}$[/tex]

Where the focal length must be in inches

Magnification of eyepiece [tex]$M=5 X$[/tex]

Focal length of the eyepiece[tex]$=\frac{10}{5}=2$ inches $=5.08 \mathrm{~cm}$[/tex]

There for magnification of the telescope

[tex]$$\begin{aligned}& M_{\text {telescope }}=\frac{100}{5.08} \\& M_{\text {telesccpe }}=19.68 \approx 20 \mathrm{X}\end{aligned}$$[/tex]

f number of the telescope[tex]$\mathrm{N}=\frac{f}{D}$[/tex]

f is the focal length of the objective[tex]$=1 \mathrm{~m}=100 \mathrm{~cm}$[/tex]

[tex]$\mathrm{D}$[/tex] is the diameter of the objective[tex]$=10 \mathrm{~cm}$[/tex]

[tex]N=\frac{100}{10}=f / 10$$[/tex]

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two charged particles 1.0 m apart exert an attractive electric force on each other with magnitude 104 n. the magnitudes of the charge on each particle are equal. the separation is then doubled to 2.0 m. what is the magnitude of the force at this distance?

Answers

The magnitude of the force at this distance of 2.0 m is 25.6 N.

The force between two charges q1 and q2 separated by a distance r is given by Coulomb's law:

F = k (q1 q2)/r^2

where k is the electrostatic constant (9 x 10^9 Nm^2/C^2).

In this problem, the distance is 1.0 m and the magnitude of the force is 104 N, so we can solve for the charge on each particle:

104 N = (9 x 10^9 Nm^2/C^2) (q1 q2) / 1.0 m^2

q1 q2 = 104 N / (9 x 10^9 Nm^2/C^2)

q1 q2 = 1.2 x 10^-7 C^2

Since the magnitudes of the charges are equal, q1 = q2 = q, so we can solve for q:

q^2 = 1.2 x 10^-7 C^2

q = 3.4 x 10^-4 C

Now that we know the charge on each particle, we can calculate the force when the separation is doubled to 2.0 m:

F = (9 x 10^9 Nm^2/C^2) (q1 q2) / (2.0 m)^2

F = (9 x 10^9 Nm^2/C^2) (3.4 x 10^-4 C)^2 / (2.0 m)^2

F = 25.6 N

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helicopter blades withstand tremendous stresses. in addition to supporting the weight of a helicopter, they are spun at rapid rates and experience large centripetal accelerations, especially at the tip. calculate the centripetal acceleration at the tip of a 4.00 m long helicopter blade that rotates at 270 rev/min.

Answers

4,860m/s² centripetal acceleration at the tip of a 4.00 m long helicopter blade that rotates at 270 rev/min.

What is Centripetal acceleration?

The rate at which tangential velocity changes is known as centripetal acceleration. Centripetal force is defined as the total force that accelerates an item in a circular motion. The centripetal force points in the direction of the centre, perpendicular to the body's motion.

What is rotation?

An object moves in a circular motion around a central axis when it is rotating or spinning. A two-dimensional spinning object can rotate in either a clockwise or counterclockwise direction and has a single potential central axis. There are countless central axis and rotational directions that can be used to describe a three-dimensional object.

Calculation:

Centripetal acceleration =  ac = w². r

= (270)² × 4 = 4,860m/s²

Hence, 4,860m/s² centripetal acceleration.

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a magnetic field is caused by a _______ electric charge.

Answers

Answer: MOVING

Explanation:

A magnetic field is caused by a MOVING electric charge.

Charge can be positive or negative.

describe the differences between heat transfer through conduction, radiation, and convection.

Answers

Heat transfer in conduction is slow, heat transfer in convection is faster than conduction and heat transfer in radiation is the fastest.

The heat transfer takes place due to the difference in temperature. Heat transfer occurs between objects by direct contact in conduction. In this, heat transfer occurs through a heated solid object. Heat transfer takes within the fluid in convection. In this process heat transfer takes place due to difference in densities. Heat transfer occurs through electromagnetic waves and without involving particles in radiation. Heat transfer in conduction is slow, heat transfer in convection is faster than conduction and heat transfer in radiation is the fastest.

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If a rock is thrown
with an initial velocity of 5.4 m/s in the y-
direction and 8.2 m/s in the x-direction.
At what angle was the rock thrown?

Answers

The angle at which the rock was thrown is 33.37°.

What is angle?

An angle is formed when two rays are joined together at a common point.

To calculate the angle at which the rock was thrown, we use the formula below.

Formula:

∅ = tan⁻¹(Vy/Vx)................ Equation 1

Where:

∅ = Angle at which the rock was thrownVy = Velocity of the rock in y- directionVx = Velocity of the rock in x-direction

From the question,

Given:

Vy = 5.4 m/sVx = 8.2 m/s

Substitute these values into equation 1

∅ = tan⁻¹(5.4/8.2)∅ = tan⁻¹(0.6585)∅ = 33.37°

Hence, the angle is 33.37°.

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An 18 kg curling rock is pushed with a constant force of 13.0 N. The
curling rock has an initial speed of 1.5 m/s. Assuming there is no friction
determine the speed of the rock after it has travelled 2.1 m.

Answers

The speed of the rock after it has travelled 2.1m is 2.3 approx.

What is speed?

Speed is simply defined as the rate of change of position of an object in any direction.

Here mass is m = 18 kg

Initial velocity is 1.5 m/s

So initial kinectic energy,1/2 mv ^ 2= 1/2 (18) 1.5(1.5) = 20.25 J

Then the workdone is ,W= F.s= 13(2.1) = 27.30

Using work energy theorem

Final KE- intial KE = workdone

==> Final KE = workdone + intial KE

Or Final KE = 27.30+20.25= 47.55 J

Then 1/2 M v^ 2 = 47.55 J

Or Final velocity V= 2.3 approx.

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on the moon your mass would be less but your weight would be the same true or false

Answers

Answer:

false

Explanation:

your mass would be the same but you would weigh less

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