The binomial distribution approximates a normal distribution under the following circumstance: a. When npq > 10,
where n is the sample size, p is the probability of success, and q is the probability of failure. When npq > 10, the binomial distribution is approximately normal with a mean of np and a standard deviation of sqrt(npq).
Binomial distribution is a probability distribution that describes the probability of a certain number of successes in a fixed number of independent trials, each with the same probability of success. The trials can be either "success" or "failure" events, and the probability of success is denoted by p. The binomial distribution is described by two parameters: n, the number of trials, and p, the probability of success in each trial.
The probability mass function of the binomial distribution is given by the formula:
P(X = k) = (n choose k) * p^k * (1-p)^(n-k)
where X is the random variable denoting the number of successes, k is the number of successes, n is the number of trials, p is the probability of success in each trial, and (n choose k) is the binomial coefficient, which represents the number of ways to choose k successes from n trials.
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without considering the sizes of the wedges, how do the three pie charts differ in which functions they include?
The three pie charts differ in the functions they include based on the distribution of the wedges.
Even without considering the sizes of the wedges, we can see that the first pie chart includes three functions while the second includes four and the third includes five.
In the first pie chart, the wedges are distributed evenly, representing three different functions. On the other hand, in the second pie chart, the wedges are not evenly distributed, with one wedge taking up more space than the others. This indicates that one function is more prominent in the second pie chart. Finally, in the third pie chart, the wedges are distributed in a way that shows one function taking up almost half of the chart.
Therefore, even without considering the sizes of the wedges, we can tell that the three pie charts differ in which functions they include based on the distribution of the wedges.
The first pie chart represents an even distribution of functions, the second pie chart has one function being more prominent, and the third pie chart has one function being the most significant.
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the sum of the reciprocals of four positive integers is 1.9. what is the sum of the four positive integers?
the sum of the four positive integers is 20. to define what reciprocals are. Reciprocals are simply the inverse of a number, meaning that if you have a number x, the reciprocal of x is 1/x.
Now, let's use this knowledge to solve the problem. We know that the sum of the reciprocals of four positive integers is 1.9, which can be expressed as:
1/a + 1/b + 1/c + 1/d = 1.9
Where a, b, c, and d are the four positive integers we're looking for.
To solve for the sum of these integers, we need to manipulate this equation to isolate the sum.
First, we can multiply both sides by abcd to get rid of the denominators:
bcd + acd + abd + abc = 1.9abcd
Next, we can group the terms with the sum of the four integers together:
(a+b+c+d)(bcd) = 1.9abcd
Now we can solve for (a+b+c+d):
a+b+c+d = 1.9abcd/bcd
Simplifying this expression, we get:
a+b+c+d = 1.9/1 + 1/10
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a measure of the average value of a random variable is called a(n) group of answer choices variance. standard deviation. expected value. coefficient of variation.
The measure of the average value of a random variable is called the expected value. So, the correct answer is B).
The expected value is a measure of central tendency that represents the average value of a random variable over an infinite number of trials. It is calculated by multiplying each possible outcome by its probability of occurring, and then summing up the products.
The expected value is a useful tool in probability theory and statistics, as it provides a way to predict the long-term behavior of a random variable. For example, in a game of chance, the expected value represents the average amount of money that a player can expect to win or lose over a large number of plays.
It is also used in decision-making under uncertainty to compare different alternatives based on their expected outcomes. So, the correct option is B).
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What is the result of the math formula: =2*10+4^2
Answer:
36
Step-by-step explanation:
2(10)+4^2
20+4^2
20+16
36
Answer: The result of the math formula =2*10+4^2 is 28.
To calculate this formula, you first need to perform the exponentiation operation of 4^2, which is 16. Then, you multiply 2 by 10, which gives you 20. Finally, you add 20 to 16, which gives you the final answer of 28.
Given the function
What is the domain of the function?
The domain of the function f(x) = 5x+3 is (-∞, +∞), which means that any real number can be substituted for x in the function.
The domain of a function is the set of all possible values of the independent variable, x, for which the function is defined. In this case, f(x) = 5x+3 is a linear function with a coefficient of 5 and an intercept of 3. Since there are no restrictions or limitations on the value of x that can be input into the function, the domain of f(x) is all real numbers or (-∞, +∞).
This means that any real number can be substituted for x in the function, and a corresponding value of f(x) will be produced. For example, if x = 0, then f(x) = 5(0) + 3 = 3. If x = -2, then f(x) = 5(-2) + 3 = -7.
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Complete question is:
Given the function f(x) = 5x+3
What is the domain of the function?
consider this histogram showing the number of students in grade five who have one or more pets what is the difference in the number of students with the most and least numbers of pets?
To find the difference in the number of students with the most and least numbers of pets, we need to look at the histogram and identify the highest and lowest bars.
The histogram shows the number of students in grade five who have one or more pets, so we can assume that each bar represents a different number of pets.
Let's say the histogram shows bars for 0, 1, 2, 3, 4, and 5 pets. If the highest bar represents 12 students with 2 pets and the lowest bar represents 2 students with 0 pets, then the difference would be 10 students (12-2).
So, the answer to the question depends on the specific histogram provided. However, we can use the information in the histogram to determine the difference in the number of students with the most and least numbers of pets.
To determine the difference in the number of students with the most and least numbers of pets, please follow these steps:
1. Examine the histogram, which shows the number of students in grade five who have one or more pets.
2. Identify the column representing the most number of pets (highest bar).
3. Identify the column representing the least number of pets (lowest bar).
4. Note the number of students associated with each column (the height of the bars).
5. Calculate the difference by subtracting the number of students with the least number of pets from the number of students with the most number of pets.
Your answer: The difference in the number of students with the most and least numbers of pets in the histogram is calculated by following the steps above.
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use the standard deviation to identify any outliers in the given data set. {31, 29, 45, 32, 28, 50, 16, 40}
Answer:1). Variance: 82.73
standard deviation: 9:10
2).variance: 39.84
standard deviation: 6.31
3). variance: 98.48
standard deviation: 9.92
4). none
5)62
Step-by-step explanation:
P.S i am emo
Answer:
none
Step-by-step explanation:
there are no outliers
A result is called statistically significant when ever
A result is called statistically significant whenever it is unlikely to have occurred by chance alone, meaning that there is strong evidence to support the presence of a true effect or relationship.
This is often determined by a p-value less than a predetermined threshold, commonly set at 0.05, which indicates a less than 5% probability that the result is due to chance.
A result is called statistically significant whenever it is unlikely to have occurred by chance alone. This is typically determined by conducting a hypothesis test and calculating a p-value, which represents the probability of obtaining the observed result or a more extreme result if the null hypothesis (i.e. no difference between groups or no relationship between variables) is true.
If the p-value is below a predetermined significance level (often set at 0.05), then the result is considered statistically significant, meaning there is evidence to reject the null hypothesis and support the alternative hypothesis (i.e. there is a difference between groups or a relationship between variables).
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Help pls and thank you
The exact value of y is [tex]\sqrt{3}[/tex]
The correct answer is an option (c)
Let us assume that in the attached diagram of right triangle the angle A measures 45 degrees.
Here, the hypotenuse measures [tex]\sqrt{6}[/tex]
We know that in right triangle, the sine of angle θ is nothing but the ratio of opposite side of angle θ to the hypotenuse.
Consider the sine of angle A
sin(A) = opposite side of angle A / hypotenuse
sin(45°) = y / ( [tex]\sqrt{6}[/tex])
We know that from the standard trigonometric table the value of sin(45°) is [tex]\frac{1}{\sqrt{2} }[/tex]
Substitute this value in above equation we get,
[tex]\frac{1}{\sqrt{2} }[/tex] = y / ( [tex]\sqrt{6}[/tex])
We solve this equation to find the value of y.
y = [tex]\sqrt{6}[/tex] × [tex]\frac{1}{\sqrt{2} }[/tex]
y = [tex]\frac{\sqrt{3}\sqrt{2} }{\sqrt{2} }[/tex]
y = [tex]\sqrt{3}[/tex]
Therefore, the correct answer is an option (c)
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In any one-minute interval, the number of requests for a popular Web page is a Poisson random variable with expected value 180 requests.a A Web server has a capacity of C requests per minute. If the number of requests in a one-minute interval is greater than C, the server is overloaded. Use the central limit theorem to estimate the smallest value of C for which the probability of overload is less than 0.055. Note that your answer must be an integer. Also, since this is a discrete random variable, don't forget to use "continuity correction". C= b Now assume that the server's capacity in any one-second interval is âC/60â, where âxâ is the largest integer â¤x. (This is called the floor function.) For the value of C derived in part (a), what is the probability of overload in a one-second interval? This time, don't approximate via the CLT, but compute the probability exactly.
Poisson distribution of number of requests for a popular Web page,
a) Web server has a capacity of C requests per minute is equals to the 206.
b) The probability of overload in a one-second interval is approximately equal to 1.
Let x denotes the number of requests for a popular web page. Now, X = number of requests per minute ~ Poisson (180)
Now, by central limit theorem the distribution of x can be approximated by Normal diet with mean = 180 and variance 180 and we denote the approximated variable by Y, that is [tex]Y \: \tilde \: \: N(180, 180)[/tex].
If number of requests in a one minute interval is greater than C, then probability of overload is less than 0.055, that is P[ X > C] < 0.055
P[ X > C] ~ P[ Y > C + 0.5] ( by continuity )
so, P[ Y > C + 0.5] < 0.055
[tex]P[ \frac{ Y - 180}{ \sqrt{180}} > \frac{C + 0.5 - 180}{ \sqrt{180} }] < 0.055[/tex]
According to normal distribution, [tex] P[ \frac{ Y - 180}{180} ] = Z ≃N(1,0)[/tex]
Therefore, [tex]P[ Z > \frac{C + 0.5 - 180}{ \sqrt{180} }] < 0.055[/tex]
=> [tex][\frac{C + 0.5 - 180}{ \sqrt{180} }] < Z_{0.055}[/tex]
= 0.478069 ~ 0.4781.
=> [tex]C - 199.5 < 0.4781 × \sqrt{ 180} [/tex]
=> C = 199.5 + 0.4781 × 13.4164
=> C = 205.91 ~ 206.
b) Now, we have to determine the probability of overload in a one-second interval, using the value of C obtained in part(a), so, C = 206 so, [ C/60] = 3
Probability of overload, P = P( X> 3)
= 1 - P( X≤ 3)
[tex]= 1 - \sum_{x = 0}^{3} e^{-180} \frac{ 180^x}{x!} [/tex]
= 1
Hence, required probability is 1.
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Use the given statement to represent a claim. Write its complement and state which is Upper H0 and which is Ha. mu less than or equals μ≤595
To determine the P-value, we can use a standard normal distribution table or a calculator. Since the alternative hypothesis is one-tailed and we are interested in the area to the right of the test statistic, we will look for the area in the upper tail of the standard normal distribution.
Using a calculator, we can find the P-value by calculating the probability of observing a test statistic of 1.32 or greater under the standard normal distribution. This can be done using the normalcdf function in a graphing calculator or an online calculator. Using the normalcdf function in a graphing calculator with a lower limit of 1.32 and upper limit of 9999, we get:
P = normalcdf(1.32, 9999) = 0.093
Therefore, the P-value is 0.093.
Since the P-value is greater than the significance level of 0.02, we fail to reject the null hypothesis. There is not enough evidence to conclude that the population mean is greater than 1180 at the 0.02 significance level
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PLEASE HELP!!!! This question is worth 16 points and I’m stuck will give 100 points
Answer:
EF ≈ 35.4 yards
Step-by-step explanation:
to find EF use the sine ratio in the right triangle, that is
sin40° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{EF}{DF}[/tex] = [tex]\frac{EF}{55}[/tex] ( multiply both sides by 55 )
55 × sin40° = EF , then
EF ≈ 35.4 yards ( to the nearest tenth )
two trains running on the same track travel at the rates of 40 and 45 mph, respectively. if the slower train starts an hour earlier, how long will it take the faster train to catch up to the slower train?
It will take the faster train 8 hours to catch up to the slower train.
What is displacement?When a body shifts from one position to another, displacement is the smallest (straight line) distance between the starting position and the ending position of the body, which is symbolized by an arrow pointing from the starting position to the ending position. Displacement is a vector quantity that describes "how far out of place an object is"; it represents the overall change in the position of the object.
In one hour, the slower train travels 40 miles, so after t hours (where t is the time it takes for the faster train to catch up), the slower train will have traveled:
d = 40(t + 1)
The faster train travels at a rate of 45 mph, so in t hours it will have traveled:
d = 45t
We can set these two equations equal to each other, since they both represent the same distance:
40(t + 1) = 45t
Expanding the left side gives:
40t + 40 = 45t
Subtracting 40t from both sides gives:
40 = 5t
Dividing both sides by 5 gives:
t = 8
So it will take the faster train 8 hours to catch up to the slower train.
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How do you find the solutions to a system of equations involving quadratic functions
Solution of a system of equations involving quadratic functions, required to calculate the values of the variables that satisfy both equations simultaneously.
Write down the equations in standard form.
A quadratic equation can be written in the form ax² + bx + c = 0, where a, b, and c are constants.
Similarly, a system of quadratic equations can be written in the form.
a₁x² + b₁x + c₁= 0
a₂x² + b₂ x + c₂ = 0
Rearrange one of the equations so that one of the variables is expressed in terms of the other.
Then substitute this expression into the other equation to obtain a single quadratic equation in one variable.
Solve the resulting quadratic equation using any of the available methods.
Such as factoring, completing the square, or using the quadratic formula.
Once you have found the values of the variables.
Substitute them back into one of the original equations to find the corresponding values of the other variables.
Check the solutions by plugging them into both equations and verifying that they satisfy both equations.
If the two equations do not have any real solutions, then the system has no real solutions.
If the two equations have infinitely many solutions, then the system is dependent.
And one of the equations is a multiple of the other.
Here, the solution set is given by the equation of the dependent line.
If the two equations have a unique solution, then the system is independent.
And the solution set is given by the coordinates of the intersection point of the two graphs.
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the perimeter of a rectangular street sign is 28 inches. the area is 40 square inches. what are the dimensions of the sign?
The dimensions of the street sign are 10 inches by 4 inches.
What is the perimeter?
The perimeter is a mathematical term that refers to the total distance around the outside of a two-dimensional shape. It is the length of the boundary or the sum of the lengths of all the sides of a closed figure.
Let's assume that the length of the rectangular street sign is L, and the width is W.
We know that the perimeter of the sign is 28 inches, which can be expressed as:
2L + 2W = 28
Simplifying this equation, we get:
L + W = 14 (dividing both sides by 2)
We also know that the area of the sign is 40 square inches, which can be expressed as:
L * W = 40
Now we have two equations with two unknowns (L and W). We can use substitution or elimination to solve for the dimensions.
Using substitution, we can rearrange the first equation to solve for one variable in terms of the other:
L = 14 - W
Then we can substitute this expression for L in the second equation:
(14 - W) * W = 40
Expanding and rearranging terms, we get:
W² - 14W + 40 = 0
This is a quadratic equation that we can solve using the quadratic formula:
W = (-(-14) ± √((-14)² - 4(1)(40))) / 2(1)
W = (14 ± √(36)) / 2
W = 7 ± 3
We can reject the negative value of W since it doesn't make sense for a length or width. Therefore, we have:
W = 10 or W = 4
If W = 10, then L = 14 - W = 4, which gives us a perimeter of 28 inches, but an area of only 40 square inches, so this solution doesn't work.
If W = 4, then L = 14 - W = 10, which gives us a perimeter of 28 inches and an area of 40 square inches, so this is the correct solution.
Therefore, the dimensions of the street sign are 10 inches by 4 inches.
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Circumference of a circle
Circumference of a circle with equation [tex](x+2)^{2}+(y-3)^{2}[/tex] = 9 is 6pi.
To find the circumference of a circle with equation [tex](x+2)^{2}+(y-3)^{2}[/tex] = 9, we first need to identify its radius, which is the square root of the constant term 9. The radius is therefore 3 units.
The formula for the circumference of a circle is C = 2πr, where C is the circumference, r is the radius, and π is a mathematical constant approximately equal to 3.14159.
Using this formula, we can calculate the circumference of the given circle as:
C = 2πr = 2π(3) = 6π
Therefore, the circumference of the circle with equation [tex](x+2)^{2}+(y-3)^{2}[/tex] = 9 is 6π units.
It's important to note that the circumference of a circle is the distance around the edge of the circle. It is an important parameter for many applications in geometry, physics, and engineering, among others. Being able to calculate the circumference of a circle given its equation is a fundamental skill in mathematics and is essential for solving many problems in different fields.
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Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature varies between 33 and 57 degrees during the day and the average daily temperature first occurs at 10 AM. How many hours after midnight, to two decimal places, does the temperature first reach 42 degrees?
Tthe temperature first reaches 42 degrees 7.67 hours after midnight, or approximately at 7:40 AM.
The temperature variation over a day can be represented as a sinusoidal function in the form of y = A sin(Bx - C) + D, where A is the amplitude, B is the frequency, C is the phase shift, and D is the vertical shift.
In this case, the midline of the temperature function is (33 + 57)/2 = 45 degrees. Therefore, D = 45.
The amplitude of the function is (57 - 33)/2 = 12 degrees. Therefore, A = 12.
Since the average temperature first occurs at 10 AM, which is 10 hours after midnight, the phase shift can be determined as C = (10/24) * 2π.
To find the frequency B of the function, we need to use the fact that the temperature function repeats every 24 hours. Therefore, B = 2π/24 = π/12.
Putting all the values in the equation y = 12 sin(π/12(x - 5/3)) + 45, we need to solve for x when y = 42.
42 = 12 sin(π/12(x - 5/3)) + 45
-3 = 12 sin(π/12(x - 5/3))
-1/4 = sin(π/12(x - 5/3))
π/2 = π/12(x - 5/3)
x - 5/3 = 6
x = 23/3
Therefore, the temperature first reaches 42 degrees 7.67 hours after midnight, or approximately at 7:40 AM.
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What is 9.4 x 103 in standard form?
The given number which is in scientific notation that is 9.4 x 10³ is equivalent to 9400 in standard form.
9.4 x 10³ is a number in scientific notation, which is a way of writing numbers that makes them easier to read and work with, especially when dealing with very large or very small numbers.
To convert this number to standard form, we need to move the decimal point three places to the right, since 10³ is equivalent to 1,000 (10 to the power of 3). This gives us:
9.4 x 10³ = 9,400
Therefore, the standard form of 9.4 x 10³ is simply 9,400.
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PLEASE HELP ME I AM GROUNDED AND NEED THIS FINISHED NOWWW
Answer:
x = 8
Step-by-step explanation:
-4x + 10 = -2x - 6
-4x + 2x = -6 - 10 (Calculate)
-2x = -16 (Divide both sides by -2)
x = 8
Have a nice day! :D
Answer:
x=8
Step-by-step explanation:
-4x+10=-2x-6 original equation
-4x+16=-2x add 6 both sides
16=2x add 4 both sides
x=8 divide 2 both sides
A rectangle has a perimeter of 68 ft. The length and width are scaled by a factor of 3.5.
What is the perimeter of the resulting rectangle?
Enter your answer in the box.
ft
Answer:
2l + 2w = 68, so l + w = 34
3.5(l + w) = 3.5(34) = 119, so the perimeter of the new rectangle is 2(119) = 238.
Step-by-step explanation:
at similsrity the perimer ratio and the side ratio are the same so equale to K.
P1/P2 = k .... but u don't explain which one is P1 of P2
so i can work u by both and u will check
and take the correct 1.
1. If P1=68ft
68ft/P2 = 3.5P2 ×3.5 = 68ft P2= 68ft/3.5 P2 = 19.42 ft2. If P2=68ft
P1/68ft = 3.5P1 = 3.5 × 68ftP1 = 238ftso if ur give is p1 take the 1st one and if ur given is p2 take the 2nd one.
Monique collects data from a random sample of seventh graders in her school and finds that 12 out of 20 seventh graders barticipate in after-school activities. Write and solve a proportion to estimate the number of seventh graders n who barticipate in after-school activities if 165 seventh graders attend Monique's
The proportion is 12/20 = n/165 and we can estimate that 99 seventh graders out of the 165 attending Monique's school participate in after-school activities.
To estimate the number of seventh graders who participate in after-school activities, we can set up a proportion using the given data. Let n be the number of seventh graders who participate in after-school activities out of the total number of seventh graders attending Monique's school, which is 165.
The proportion can be written as:
12/20 = n/165
To solve for n, we can cross-multiply and simplify:
12 × 165 = 20n
1980 = 20n
n = 1980/20
n = 99
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g if f is uniformly continuous on a~ r, and fl(x)l > k > 0 for all x e a, show that 1/f is uniformly continuous on a.
It is shown that for any ε > 0, there exists a δ > 0 such that |x - y| < δ implies |1/f(x) - 1/f(y)| < ε/(2kM) for all x, y in a. This proves that 1/f is uniformly continuous on a.
What is uniformly continuous?
Uniform continuity is a property of a function in which for any given value ε > 0, there exists a corresponding value δ > 0 such that for all pairs of points in the function's domain whose distance is less than δ, the difference in the function's values at those points is less than ε. In other words, a function is uniformly continuous if its rate of change does not vary significantly over its entire domain, and small changes in its input result in correspondingly small changes in its output.
To show that 1/f is uniformly continuous on a, we need to prove that for any ε > 0, there exists a δ > 0 such that |x - y| < δ implies |1/f(x) - 1/f(y)| < ε for all x, y in a.
Given that f is uniformly continuous on a, we know that for any ε > 0, there exists a δ > 0 such that |x - y| < δ implies |f(x) - f(y)| < ε/k for all x, y in a.
We also know that |f(x)| > k for all x in a.
Using these facts, we can begin by manipulating the expression |1/f(x) - 1/f(y)|:
|1/f(x) - 1/f(y)| = |(f(y) - f(x))/(f(x)f(y))|
Since |f(y) - f(x)| < ε/k, we can substitute this into the above expression:
|1/f(x) - 1/f(y)| < |(ε/k)/(f(x)f(y))|
Now, we need to find a way to relate f(x)f(y) to |x - y|.
Since f is uniformly continuous, we know that for any ε > 0, there exists a δ > 0 such that |x - y| < δ implies |f(x) - f(y)| < ε/k for all x, y in a.
This implies that |f(x)f(y)| < k(f(x) + f(y)) < 2kM, where M is the supremum of |f(x)| over a.
Thus, we have:
|1/f(x) - 1/f(y)| < ε/(2kM)
Therefore, we have shown that for any ε > 0, there exists a δ > 0 such that |x - y| < δ implies |1/f(x) - 1/f(y)| < ε/(2kM) for all x, y in a. This proves that 1/f is uniformly continuous on a.
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Wesley has a grid of six cells. He wants to colour two of the cells black so that the two black cells share a vertex but not a side. In how many ways can he achieve this?
Wesley can color two cells in 5 ways so that the two black cells share a vertex but not a side.
Total number of cell in the grid is 6
Vertex is a point on a polygon where the sides or edges of the object meet.
1st case Wesley can color 1 & 4
2nd case Wesley can color 2 & 3
3rd case Wesley can color 2 & 5
4rt case Wesley can color 3 & 6
5th case Wesley can color 5 & 6
Total 5 cases form in which two cell are colored whose side don't touch each other only vertexes are shared by the cell
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a card is drawn from a standard deck of 52 cards. find the probability that a king or a club is selected
The probability of selecting a King of Clubs from a standard deck of 52 cards is 1/52, or 0.019.
This is so because there is just one King of Clubs—the lone card with that particular suit and rank—in the regular deck.
No of the card's suit or rank, there is always a 1/52 chance that it will be drawn from a normal deck.
This is due to the fact that every card has an equal chance of being chosen, and as a normal deck contains 52 cards, the likelihood of any card being chosen is 1/52.
In summary, the likelihood of drawing a King of Clubs from a conventional 52-card deck is 1/52, or 0.019.
Complete Question:
A card is drawn from a standard deck of 52 cards. What is the probability of selecting a King of Clubs?
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Weights of females have approximately a normal distribution with mean 135 lbs. and standard deviation 20 lbs. Allison weighs 145 lbs. What is the z-score for her weight?
After using the formula: z = (x - μ) / σ , the z-score for Allison's weight is 0.5.So, the z-score for Allison's weight is 0.5.
To find the z-score for Allison's weight, we use the formula:
z = (x - μ) / σ
where x is Allison's weight (145 lbs), μ is the mean weight of females (135 lbs), and σ is the standard deviation (20 lbs).
Substituting the values, we get:
z = (145 - 135) / 20
z = 0.5
Therefore, the z-score for Allison's weight is 0.5.
To calculate the z-score for Allison's weight, we can use the following formula:
z-score = (Allison's weight - mean weight) / standard deviation
Plugging in the given values:
z-score = (145 lbs - 135 lbs) / 20 lbs = 10 lbs / 20 lbs = 0.5
So, the z-score for Allison's weight is 0.5.
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fragmentation refers to the division of a relation into subsets of tuples. question 47 options: a) vertical b) horizontal c) mixed d) data
Horizontal fragmentation involves dividing a relation into subsets of tuples (rows) based on a specific condition. Together, these subsets form the complete relation, and mixed fragmentation combines both vertical and horizontal fragmentation techniques.
Each fragment contains a portion of the rows from the original relation, and together they form the complete relation.
The correct answer to the question is either a) vertical or b) horizontal, depending on the specific type of fragmentation being referred to. Vertical fragmentation divides a relation into subsets of tuples based on specific attributes or columns, while horizontal fragmentation divides a relation into subsets of tuples based on specific rows or criteria.
Mixed fragmentation is a combination of both vertical and horizontal fragmentation, and data fragmentation refers to the division of data into subsets for distribution or storage purposes.
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kindergarten class has four left-handed children and nine right-handed children. Two children are selected without replacement for a shoe-tying lesson. Let X = the number who are left-handed.
(a) The simple events in the sample space are {RR, RL, LR, LL}. For instance, one simple event is RL, indicating that the first child is right-handed and the second one is left-handed. Find the probability for each of the simple events in the sample space. (Hint: A tree diagram may help you solve this.)
p rr
p rl
p lr
p ll
(b) Find the probability distribution function for X.
So the probability distribution function for X is:
- P(X = 0) = 0.46
- P(X = 1) = 0.46
- P(X = 2) = 0.08
What is probability?Probability is a measure of how likely an event is to occur. Many events are impossible to predict with absolute certainty.
(a) Using the tree diagram:
- P(RR) = (9/13) * (8/12) = 0.46
- P(RL) = (9/13) * (4/12) = 0.23
- P(LR) = (4/13) * (9/12) = 0.23
- P(LL) = (4/13) * (3/12) = 0.08
So the probabilities for the simple events are:
- P(RR) = 0.46
- P(RL) = 0.23
- P(LR) = 0.23
- P(LL) = 0.08
(b) The possible values for X are 0, 1, or 2.
- P(X = 0) = P(RR) = 0.46
- P(X = 1) = P(RL) + P(LR) = 0.23 + 0.23 = 0.46
- P(X = 2) = P(LL) = 0.08
So the probability distribution function for X is:
- P(X = 0) = 0.46
- P(X = 1) = 0.46
- P(X = 2) = 0.08
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How many 5 number license plates can be made using the digits 0,1,2,3,4,5,if repeatitions are allowed?
There are 7776 possible 5-number license plate combinations utilizing the numbers 0, 1, 2, 3, 4, and 5, with repetitions allowed.
The number of 5-number license plates that can be made using the digits 0, 1, 2, 3, 4, and 5, with repetitions allowed, can be found by using the multiplication principle. Since there are 6 digits to choose from for each of the 5 positions, the total number of possible license plates is:
6 x 6 x 6 x 6 x 6 = 6⁵
= 7776
Therefore, there are 7776 possible 5-number license plate combinations utilizing the numbers 0, 1, 2, 3, 4, and 5, with repetitions allowed.
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You would like to determine if there is a higher incidence of smoking among women than among men in a neighborhood. Let women and men be represented by populations 1 and 2, respectively. The relevant hypotheses are constructed as ____________.
The relevant hypotheses for this question would be:Null hypothesis (H0): The incidence of smoking among women is not significantly higher than among men in the neighborhood (μ1 ≤ μ2).
Null hypothesis (H₀): The incidence of smoking among women (population 1) is equal to the incidence of smoking among men (population 2), or p₁ = p₂.
Alternative hypothesis (H₁): The incidence of smoking among women (population 1) is greater than the incidence of smoking among men (population 2), or p₁ > p₂.
You would like to determine if there is a higher incidence of smoking among women than among men in a neighborhood. Let women and men be represented by populations 1 and 2, respectively. The relevant hypotheses are constructed as relevant hypothesis .
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what is the smallest positive integer n such that there are exactly four nonisomorphic abelian groups of order n?
The fourth and final abelian group is the direct product of cyclic groups of order 6 and 6, denoted by Z6 x Z6. These four groups have different structures, even though they have the same order. Thus, we need to carefully factorize n to determine how many nonisomorphic abelian groups of that order exist.
The smallest positive integer n that has exactly four nonisomorphic abelian groups of that order is 36. To understand why, it's important to note that there are different ways to factorize integers into their prime divisors. For example, 36 can be factored into 2^2 * 3^2. Using this factorization, we can construct four different nonisomorphic abelian groups of order 36. The first is the cyclic group of order 36, denoted by Z36. The second is the direct product of two cyclic groups of order 18, denoted by Z18 x Z18. The third is the direct product of cyclic groups of order 12 and 3, denoted by Z12 x Z3 x Z3.
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