Answer:
Since, 113 is on the confidence interval obtained (97.502, 114.098), so, we can suggest that is plausible that the true average IQ score for all seventh-grade female students at this school is 113.
Step-by-step explanation:
The question isn't complete, the missing part asked us to obtain a 99.5% confidence interval for the true average IQ score
Finding the confidence interval using the sample data provided, we can answer the question of plausibility.
Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.
Mathematically,
Confidence Interval = (Sample mean) ± (Margin of error)
Sample Mean = 105.8
Margin of Error is the width of the confidence interval about the mean.
It is given mathematically as,
Margin of Error = (Critical value) × (standard Error of the mean)
Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.
To find the critical value from the t-tables, we first find the degree of freedom and the significance level.
Degree of freedom = df = n - 1 = 31 - 1 = 30
Significance level for 99.5% confidence interval
(100% - 99.5%)/2 = 0.25% = 0.0025
t (0.0025, 30) = 3.03 (from the t-tables)
Standard error of the mean = σₓ = (σ/√n)
σ = standard deviation of the sample = 15
n = sample size = 30
σₓ = (15/√30) = 2.739
99.5% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]
CI = 105.8 ± (3.03 × 2.739)
CI = 105.8 ± 8.298
99.5% CI = (97.502, 111.387)
99.5% Confidence interval = (97.502, 114.098)
Since, 113 is on the confidence interval obtained, so, we can suggest that is plausible that the true average IQ score for all seventh-grade female students at this school is 113.
Hope this Helps!!!
A physical fitness association is including the mile run in its secondary-school fitness test. The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds. Find the probability that a randomly selected boy in secondary school can run the mile in less than 368 seconds.
Answer:
The probability that a randomly selected boy in secondary school can run the mile in less than 368 seconds is P(X<368)=0.011.
Step-by-step explanation:
We have a normal distribution with mean 460 and standard deviation 40 to describe the time for the mile run in its secondary-school fitness test.
We have to calculate the probabiltiy that a randomly selected boy in secondary school can run the mile in less than 368 seconds.
To calculate this, we have to calculate the z-score for X=368:
[tex]z=\dfrac{X-\mu}{\sigma}=\dfrac{368-460}{40}=\dfrac{-92}{40}=-2.3[/tex]
Then, we can calculate the probability:
[tex]P(X<368)=P(z<-2.3)=0.011[/tex]
Based on your understanding of the ideas of external consistency and fruitfulness, which of the following statements best describes the relevance of these ideas to the acceptance of hypotheses?a. A fruitful hypothesis is considered stronger because fruitful hypotheses are always externally consistent with previously held theories. b. A fruitful hypothesis is considered stronger because fruitful hypotheses promote scientific progress by revealing new avenues of research and analysis.c. An adequate theory is always a fruitful theory. d. All internally coherent theories are fruitful.
Answer:
b
Step-by-step explanation:
externally consistent ideas are the ideas that are consistent with other well-confirmed hypothesis.
Fruitfulness of a hypothesis can be measured from the fact it it suggests something other than what it was originally suppose to explain.
Let two cards be dealt successively, without replacement, from a standard 52-card deck. Find the probability of the event. The first card is a queen and the second is a seven
Answer: 4 / 663
Step-by-step explanation:
There are 4 queens in a deck of 52 cards.
Probability = 4/52 = 1/13
There are 4 sevens
Probability = 4/51
Total probability = 1/13 x 4/51 = 4 / 663
The probability of drawing a queen first and a seven-second is 3/613.
What is probability?Probability is defined as the possibility of an event being equal to the ratio of the number of favorable outcomes and the total number of outcomes.
There are 4 queens in a standard deck, and once one queen is drawn, there are 51 cards left, including 3 sevens.
So, the probability of drawing a queen first is 4/52 or 1/13, and the probability of drawing a seven-second is 3/51.
By the multiplication rule of probability, multiply the probabilities of each event occurring:
P(Queen and Seven) = P(Queen) × P(Seven after Queen)
P(Queen and Seven) = (1/13) × (3/51)
P(Queen and Seven) = 3/613
Thus, the probability of drawing a queen first and a seven-second is 3/613.
Learn more about the probability here:
brainly.com/question/11234923
#SPJ2
To convert a measurement, Pete must move the decimal point to the left 4 places. This is a shortcut for an operation. Which operation is he using? Which power of 10 is involved? iLL GIVE 50 POINTS PLEASE IM TIMED IM PANICKING
Answer: The moving of decimal to the left is a shortcut to the operation of multiplying number by decimal numbers
Step-by-step explanation:
the power of 10 that is involved in converting the measurements of pete is -4, so he needs to multiply the measurement by 10^-4 to convert it.
Answer:
Sample Response: Because he moved the decimal 4 places to the left, Pete is dividing by 10 to the 4th power, or 10,000. Pete moved the decimal place 4 places to the left. Pete is dividing by 10 to the 4th power, or 10,000.
Step-by-step explanation:
it was on edg
hope it helps :b
A motorboat can maintain a constant speed of 28 miles
per hour relative to the water. The boat makes a trip
upstream to a certain point in 35 minutes; the return trip
takes 21 minutes. What is the speed of the current?
Answer:
7mph
Step-by-step explanation:
Given
Time Taken to go upstream Tup = 35 min
Time Taken to go downstream Tdown=21 min.
Let the absolute speed (i.e speed relative to the stationary riverbed) be :
Vup : going upstream
Vdown: going downstream.
We know that the distance traveled upstream = distance traveled downstream, hence we can equate both distances, i.e. :
Distance Traveled Upstream = Distance Traveled Downstream
Vup · Tup = Vdown · Tdown (substituting the values for time above)
35Vup = 21Vdown
Vup = (21/35) Vdown ------------(eq 1)
We are also given that the motorboat can travel at V = 28 mph relative to the water.
Since going upstream, we are going AGAINST the current, relative to the riverbed, we expect to be travelling slower. In fact, the absolute difference between the speed relative to the water (i.e V = 28 mph) and the speed relative to the seabed (i.e Vup), is equal to the speed of the current.
The same can be said for going downstream WITH the current, that the absolute difference between V = 28mph and Vdown is also equal to the speed of the current.
Hence we can equate the two:
28 - Vup = Vdown - 28
Vup + Vdown = 2(28)
Vup + Vdown = 56 ---------------------(eq 2)
If we solve the system of equations (eq 1) and (eq2), we will get
Vup = 21 mph and Vdown = 35 mph
(sanity check tells us that this makes sense because we expect to be going slower upstream because we are going against the current)
Hence current speed
= 28-Vup
= 28 - 21
= 7 mph. (answer)
Sanity Check:
Current speed can also be written:
= Vdown-28
= 35 - 28
= 7 mph (same as what we found above, so this checks out)
The speed of the current motorboat = 7 mph
What is an expression?
Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Speed of boat in still water = 28 mph
Let the speed of stream = w
Here, The upstream time is 35 min = 35/60 h = 7/12 h
downstream time is 21 min = 21/60 h = 7/20 hours
Since, The distance (d = vt) traveled either way is the same, but at different speeds and times.
Hence, Set upstream and downstream distances (vt) equal and solve for w as;
⇒ (28 - w)(7/12) = (28 + w)(7/20)
⇒ 20 (28 - w) = 12 (28 + w)
⇒ 5(28 - w) = 3(28 + w)
⇒ 140 - 5w = 84 + 3w
⇒ 140 - 84 = 5w + 3w
⇒ 56 = 8w
⇒ w = 7
Thus, The speed of the current = 7 mph
Learn more about the mathematical expression visit:
brainly.com/question/1859113
#SPJ2
NEED HELP ASP Find the common difference of the arithmetic sequence -8, -15, -22, ...
Answer:
-7
Step-by-step explanation:
To find the differences in a sequence, subtract the term before:
-15 -(-8) = -7
-22 -(-15) = -7
These differences are the same, so constitute the "common" difference.
The common difference of the sequence is -7.
g It is known that 20% of products on a production line are defective. Products are inspected until first defective is encountered. a) What is the probability that the experimenter must inspect six products
Question:
It is known that 20% of products on a production line are defective. Products are inspected until first defective is encountered. a) What is the probability that the experimenter must inspect six products to find a defective product?
Answer:
P(x = 6) = 0.0655
P(x = 6) = 6.55%
Step-by-step explanation:
It is given that 20% of products on a production line are defective.
p = 0.20
Then
q = 1 - p = 1 - 0.20 = 0.80
Which means that 80% of products on the production line are not defective.
We want to find out the probability that the experimenter must inspect six products to find a defective product.
Let x is the number of inspections to get a defective product.
P(x = 6) = ?
If out of 6 inspections 1 is defective then it means 5 are not defective
so the probability is
P(x = 6) = p¹ × q⁵
P(x = 6) = 0.20¹ × 0.80⁵
P(x = 6) = 0.20 × 0.32768
P(x = 6) = 0.0655
P(x = 6) = 6.55%
Therefore, there is 6.55% chance that the experimenter finds a defetive product in 6 inspections.
Removing which point from the coordinate plane would make the graph a function of x? On a coordinate plane, points are at (negative 2, negative 3), (negative 2, 1), (negative 4, 3), (0, 4), (1, 1), and (2, 3). (–4, 3) (–2, 1) (0, 4) (1, 1)
Answer:
(-2, 1)
Step-by-step explanation:
For a relation consisting of (x, y) pairs to be a function, all of the x-values must be unique. In the given relation, points (-2, -3) and (-2, 1) have the same x-value. Removing either point will make the relation a function.
Of these, the only one listed among answer choices is (-2, 1).
Answer:
-2 , 1
Step-by-step explanation:
good luck love
What should be done to both sides of the equation in order to solve w - 9 1/2 = 15?
Answer:
Solve for
w
by simplifying both sides of the equation, then isolating the variable.
Exact Form:
w
=
49
2
Decimal Form:
w
=
24.5
Mixed Number Form:
w
=
24
Answer:
24
Step-by-step explanation:
6x – 2y = 10 2x + 3y = 51 Solving the first equation above for y gives: y = x – 5
Answer:
x =6y =13Step-by-step explanation:
This is the method I am familiar with.
I Hope It helps :)
[tex]METHOD- 1 : Elimination\\6x - 2y=10------(1)\\2x+3y =51------(2)\\Multiply -eq-(1)- by -the-coefficient-of-x-in-equation (2)\\Multiply-eq-(2) -by -the-coefficient-of-x-in-equation (1)\\6x - 2y=10------(1) *2\\2x+3y =51------(2)*6\\\\12x-4y=20 ------(3)\\12x+18y=306 ------(4)\\Subtract -eq- (4)- from- eq -(3)\\-22y =-286\\\frac{-22y}{-22} =\frac{-286}{-22} \\y =13\\[/tex]
[tex]Substitute- 13- for y -in-equation -(1)-or-(2)\\6x - 2y=10------(1)\\6x -2(13)=10\\6x -26=10\\6x =10+26\\6x =36\\\frac{6x}{6} =\frac{36}{6} \\x =6[/tex]
Answer:
Correct answers is
Step-by-step explanation:
1. 3
2. B
3. 6
4. (6,13)
The function h(t) = -4.92f^2 + 17.69f + 575 is used to model the height of an object being tossed from a tall building, where h(t) is the height in meters and t is the time in seconds. What are the domain and range?
Answer:
rounded to 3 decimal places ...
domain: [0, 12.757]range: [0, 590.901]Step-by-step explanation:
The function can be put into vertex form:
h(t) = -4.92(t -(1769/984))^2 +575 +4.92(1769/984)^2
h(t) ≈ -4.92(t -1.79776)^2 +590.90122
The value of h(t) is zero for ...
t = √(590.90122/4.92) +1.79776 ≈ 12.75686
For practical purposes, the domain of the function is those values of t between the time the object is tossed and the time it hits the ground. That is, the domain is ...
0 ≤ t ≤ 12.75686
The range is the set of useful vertical heights, so extends from 0 to the maximum height, given by the vertex.
The range is 0 ≤ h(t) ≤ 590.90122.
_____
Alternate interpretation of the question
The function h(t) is defined for all values of t, so that could be considered the domain.
The function h(t) only gives values less than its vertex value, so the range could be considered to extend from negative infinity to that maximum.
Which graph show the line y-4=3(x+1)
Answer:
x or slope: 3
y-intercept: 7
x y
0 7
1 10
Explanation:
COMPUTE:
A) 40−5÷ 1/5 =
B) (4.8−1.8÷6)÷5=
Answer:
A) 15
B) 0.9
Step-by-step explanation:
Use the correct order of operations.
A) 40 − 5 ÷ 1/5 =
= 40 − 5 * 5
= 40 - 25
= 15
B) (4.8 − 1.8 ÷ 6) ÷ 5 =
= (4.8 − 0.3) ÷ 5
= 4.5 ÷ 5
= 0.9
The radius of a circular disk is given as 21 cm with a maximum error in measurement of 0.2 cm.
A) Use differentials to estimate the maximum error in the calculated area of the disk.
B) What is the relative error?
C) What is the percentage error?
Answer:
a) [tex]\Delta A \approx 26.389\,cm^{2}[/tex], b) [tex]r_{A} \approx 0.019[/tex], c) [tex]\delta = 1.9\,\%[/tex]
Step-by-step explanation:
a) The area of the circular disk is modelled after this expression:
[tex]A = \pi \cdot r^{2}[/tex]
The total differential is given by the following formula:
[tex]\Delta A = 2\pi r \cdot \Delta r[/tex]
The maximum absolute error in the calculated area of the disk is:
[tex]\Delta A = 2\pi \cdot (21\,cm)\cdot (0.2\,cm)[/tex]
[tex]\Delta A \approx 26.389\,cm^{2}[/tex]
b) The relative error is given by:
[tex]r_{A} = \frac{\Delta A}{A}[/tex]
[tex]r_{A} = \frac{26.389\,cm^{2}}{\pi \cdot (21\,cm)^{2}}[/tex]
[tex]r_{A} \approx 0.019[/tex]
c) The percentage error is:
[tex]\delta = r_{A}\times 100\,\%[/tex]
[tex]\delta = 0.019 \times 100\,\%[/tex]
[tex]\delta = 1.9\,\%[/tex]
Score: 4 of 8 pts
TA
23.1.59
A ball is thrown upward and outward from a height of 5 feet. The height of the ball, f(x), in feet, can be mo
f(x) = -0.2x² +2.1x+5
where x is the ball's horizontal distance, in feet from where it was thrown. Use this model to solve parts (
a. What is the maximum height of the ball and how far from where it was thrown does this occur?
The maximum height is feet, which occurs feet from the point of release
(Round to the nearest tenth as needed.)
Answer:
10.5 ft high
5.3 ft horizontally
Step-by-step explanation:
The equation can be written in vertex form to answer these questions.
f(x) = -0.2(x² -10.5x) +5
f(x) = -0.2(x² -10.5x +5.25²) +5 +0.2(5.25²)
f(x) = -0.2(x -5.25)² +10.5125
The vertex of the travel path is (5.25, 10.5125).
The maximum height is 10.5 feet, which occurs 5.3 feet (horizontally) from the point of release.
Suppose 44% of a large sample of a population favor a tax increase. If there
are 95,000 people in the population about how many people in the population
favor a tax increase?
A. 13,300
B. 22,800
C. 41,800
D. 32,300
Answer:
C. 41,800
Step-by-step explanation:
Multiply 0.44 by 95,000.
0.44 x 95,000 = 41,800
simplify 3^5•3^4
a.) 3•20
b. 3^9
c.) 6^9
d.) 3^20
Answer:
But if we are doing 3^x we need to add both of them
This is a rule you should remember if you have both same base to x power when you are multiplying
5+4 = 9
answer is 3^9 or 19683
Can someone solve this?
Answer:
32°CDAStep-by-step explanation:
1. The angle facing the given arcs is half their sum, so is (180 +116)/2 = 148°. Angle 1 is the supplement of this, ...
angle 1 = 180° -148° = 32°
__
2. Short arc WY is the supplement of 70°, Long arc WVY is the difference of that and 360°:
arc WVY = 360° -(180° -70°) = 180°+70°
arc WVY = 250° . . . . . matches choice C
__
3. Call the point of intersection of the secants X. The rule for secants is ...
(XA)(XC) = (XB)(XD)
So, the length XC is ...
XC = (XB)(XD)/(XA) = 2.4
and ...
AC = XA +XC = 3.2 +2.4 = 5.6 . . . . . matches choice D
__
4. As in problem 3, the product of lengths from the point of secant intersection to the points of circle intersection is the same for both secants.
(NQ)(NR) = (NP)(NS)
Substituting segment sums where necessary, we have ...
NQ(NQ +QR) = NP(NP +PS)
Solving for PS, we have ...
PS = NQ(NQ +QR)/NP - NP . . . . . matches choice A
US Department of Transportation As part of a study on transportation safety, the US Department of Transportation collected data on the number of fatal accidents per 1000 licenses and the percentage of licensed drivers under the age of 21 in a sample of 42 cities. Data collected over a one-year period are shown in the table.Use regression to investigate the relationship between the number of fatal accidents and the percentage of drivers under the age of 21.Discuss your findings.What conclusions and recommendations can you derive from your analysis?Percent Under 21 Fatal Accidents per 100013 2.96212 0.7088 0.88512 1.65211 2.09117 2.62718 3.838 0.36813 1.1428 0.6459 1.02816 2.80112 1.4059 1.43310 0.0399 0.33811 1.84912 2.24614 2.85514 2.35211 1.29417 4.18 2.1916 3.62315 2.6239 0.8358 0.8214 2.898 1.26715 3.22410 1.01410 0.49314 1.44318 3.61410 1.92614 1.64316 2.94312 1.91315 2.81413 2.6349 0.92617 3.256
Answer:
we can conclude that for every single unit of : x, y would be increased by 0.2871. and intersection of x and y will be through =1.5974it can be concluded that they are strongly positively correlated. There is strong and positive correlation between them. i.e the number of fatal accidents and the drivers under the age of 21Step-by-step explanation:
WITH THE GIVEN DATA
A ) using regression to investigate the relationship between the number of fatal accidents and the percentage of drivers under the age pf 21
to fit into a regression line we must have ∝ and β
where β = [tex]\frac{S_{xy} }{S_{xx} }[/tex] = 0.2871
and ∝ = y - βx = - 1.5974
regression line = ∝ + β * x
insert values into regression line equation
regression line = -1.5974 + 0.2871 * x
we can conclude that for every single unit of : x, y would be increased by 0.2871. and intersection of x and y will be through =1.5974
B ) conclusion and recommendations can you derive from your analysis
it can be concluded that they are strongly positively correlated. There is strong and positive correlation between them. i.e the number of fatal accidents and the drivers under the age of 21
using the correlation coefficient ( r ) = [tex]\frac{S_{xy} }{\sqrt{S_{xx}*S_{xy} } }[/tex] = 0.8394
Answer:
0.8394
Step-by-step explanation:
.
subtract 2 16/21 - (-8 5/21). reduce if possible
Answer:
11
Step-by-step explanation:
A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles). The fitted regression is Time = −7.126 + .0214 Distance, based on a sample of 20 shipments. The estimated standard error of the slope is 0.0053. Find the critical value for a right-tailed test to see if the slope is positive, using α = .05.
Answer:
Thus; the slope is positive
Step-by-step explanation:
Given that :
the sample size = 20
for the slope; the degree of freedom df = n - 2
= 20 -2
= 18
Using ∝ = 0.05
From t -table , one tailed, at df =18)
[tex]t_{\alpha , df}}= t_{0.05, df = 18} = 1.734[/tex]
Thus the t- critical for the right tailed test is 1.734. This simply refers to the fact that the critical region is test statistics.
Incorporating the Excel Formula [ T.INV (1 - 0.05).18) = 1.734063607
≅ 1.734
calculate the middle between -4 and 5
Answer:
eight (8)
Step-by-step explanation:
-3,-2,-1,0,1,2,3,4
ADDITIONAL 100 POINTS PLS HELP ASAP follow up question ( first question on log )
Answer:
Hello!
I believe this is what you are looking for:
x=3
33=27
32=9
S=Surface area
V=Volume
L=Length
R=Radius
I hope this helped. If not, please let me know. I will try my best again. :)
Step-by-step explanation:
J.D. Power and Associates conducts vehicle quality surveys to provide automobile manufacturers with consumer satisfaction information about their products (Vehicle Quality Survey, January 2010 ). Using a sample of vehicle owners from recent vehicle purchase records, the survey asks the owners a variety of questions about their new vehicles, such as those shown below. For each question, state whether the data collected are categorical or quantitative and indicate the measurement scale being used.
a. What price did you pay for the vehicle?
b. How did you pay for the vehicle? (Cash, Lease, or Finance)
c. How likely would you be to recommend this vehicle to a friend? (Definitely Not, Probably Not, Probably Will, and Definitely Will)
d. What is the current mileage?
e. What is your overall rating of your new vehicle? A 110 -point scale, ranging from I for
unacceptable to 10 for truly exceptional, was used.
Answer:
Categorical data includes
b. How did you pay for the vehicle? (Cash, Lease, or Finance)
c. How likely would you be to recommend this vehicle to a friend? (Definitely Not, Probably Not, Probably Will, and Definitely Will)
e. What is your overall rating of your new vehicle? A 1 to 10 point scale, ranging from I for unacceptable to 10 for truly exceptional, was used.
Quantitative data includes
a. What price did you pay for the vehicle?
d. What is the current mileage?
Step-by-step explanation:
Categorical data refers to the kind of data in which the variables are grouped based on a particular quality, ticking a particular box or satisfying some specific requirements.
It uses one or more qualitative property/properties to assign variables into a limited, usually fixed groups or categories. Note that the qualitative property might be a grouped data of numerical values. As long as there are easily separable and recognizable groups, it is categorical data.
This is also called qualitative data.
Quantitative data is a data that is strictly about numerical values. A dataset that consists of numerical values of the members of the dataset. Deals almost exclusively with numbers, usually ungrouped.
So, examining the given datasets one at a time
a. What price did you pay for the vehicle?
The answer to this question is a numerical value and for various customers, it builds up a dataset of strictly numerical values. Hence, this resulting data is a quantitative data.
b. How did you pay for the vehicle? (Cash, Lease, or Finance)
The answers to this question can only take 3 forms; Cash, Lease or Finance, indicating that all the variables in the dataset can only take on limited, fixed number of groups/categories. Hence, this dataset is a categorical data.
c. How likely would you be to recommend this vehicle to a friend? (Definitely Not, Probably Not, Probably Will, and Definitely Will)
The answers to this question too can take on 4 limited, fixed categories or groups, Hence, it's easy to see that this dataset is also categorical data.
d. What is the current mileage?
The answer to this question is a numerical value. Various answers from numerous persons would lead to a data of numbers. Hence, this is a quantitative data.
e. What is your overall rating of your new vehicle? A 1 to 10 point scale, ranging from I for unacceptable to 10 for truly exceptional, was used.
Limited, fixed categories or groups (10 groups) are also available for this data, hence, it is easily a categorical data.
Hope this Helps!!!
What is X:Compute
|x|=−4
Answer:
The answer is No Solution
Answer:
No solution
Step-by-step explanation:
There is no solution to this question.
Since the x is an absolute number, the answer cannot be -4. It would have to equal 4
So if that x was a -4 it would equal 4 since it is in absolute value brackets
A type of friction that occurs when air pushes against a moving object causing it to negatively accelerate
Answer:
Air resistance
Step-by-step explanation:
Air resistance is a type of friction that occurs when air pushes against a moving object causing it to negatively accelerate
Answer:
Air resistance
Step-by-step explanation:
Air resistance is a type of friction that occurs when air pushes against a moving object causing it to negatively accelerate.
A small child has 6 more quarters than nickels. If the total amount of the coins is $3.00, find the number of nickels and quarters the child has.
Answer:
nickels- 5, quarters- 11
Step-by-step explanation:
nickel= 5 p, quarter= 25 p
5x+25(x+6)= 300
30x+150=300
30x=150
x=150/30
x=5 nickels
x+6= 11 quarters
A recent national survey found that parents read an average (mean) of 10 books per month to their children under five years old. The population standard deviation is 5. The distribution of books read per month follows the normal distribution. A random sample of 25 households revealed that the mean number of books read last month was 12. At the .01 significance level, can we conclude that parents read more than the average number of books to their children
Answer:
Step-by-step explanation:
Null hypothesis: u = 10
Alternative hypothesis: u =/ 10
Using the formula: t = (x - u) / (s /√n)
Where x = 12, u = 10, s = 5 and n = 25
t= (12-10) / (5/√25)
t = (2)/(5/5)
t = 2/1= 2
t = 2.0
At a 0.01 level of significance with a degree of freedom of 24, the p-value is 0.0569, which is greater than 0.01 we will fail to reject the null and conclude that parents do not read more than the average number of books to their children
You are given the following data, where X1 (final percentage in history class) and X2 (number of absences) are used to predict Y (standardized history test score in third grade):
Y X1 X2
465 92 2
415 95 2
345 70 3
410 72 3
370 75 4
400 82 0
390 80 1
480 98 0
420 80 2
485 99 0
485 92 6
375 92 6
310 61 5
Determine the following multiple regression values.
Report intercept and slopes for regression equation accurate to 3 decimal places
Intercept: a =
Partial slope X1: b1 =
Partial slope X2: b2 =
Report sum of squares accurate to 3 decimal places:
SSreg = SS
Total =
Test the significance of the overall regression model (report F-ratio accurate to 3 decimal places and P-value accurate to 4 decimal places):
F-ratio =
P-value =
Report the variance of the residuals accurate to 3 decimal places.
Report the results for the hypothesis test for the significance of the partial slope for number of absences
Answer:
Step-by-step explanation:
Hello!
Given the variables
Y: standardized history test score in third grade.
X₁: final percentage in history class.
X₂: number of absences per student.
Determine the following multiple regression values.
I've estimated the multiple regression equation using statistics software:
^Y= a + b₁X₁ + b₂X₂
a= 118.68
b₁= 3.61
b₂= -3.61
^Y= 118.68 + 3.61X₁ - 3.61X₂
ANOVA Regression model:
Sum of Square:
SS regression: 25653.86
SS Total: 36819.23
F-ratio: 11.49
p-value: 0.0026
Se²= MMError= 1116.54
Hypothesis for the number of absences:
H₀: β₂=0
H₁: β₂≠0
Assuming α:0.05
p-value: 0.4645
The p-value is greater than the significance level, the decision is to not reject the null hypothesis. Then at 5% significance level, there is no evidence to reject the null hypothesis. You can conclude that there is no modification of the test score every time the number of absences increases one unit.
I hope this helps!
The probability of teenager owning a game system is .72 and the probability of teenager owning a cell phone is .93.
the probability of a teenager owning both gaming system and cell phone is .68
what is the probability of a teenager owning a gaming system or a cell phone? round to the nearest thousandth
Answer: 0.97
Step-by-step explanation:
Formula : For events A and B
P(A or B) = P(A) + P(B) - P(A and B)
Given : The probability of teenager owning a game system is .72.
i.e. P(game system) =0.72
The probability of teenager owning a cell phone is .93.
i.e. P(cell phone) = 0.93
The probability of a teenager owning both gaming system and cell phone is .68
i.e. P( game system and cell phone) = 0.68
Now , the probability of a teenager owning a gaming system or a cell phone is given by :_
P(game system or cell phone) = P(game system) +P(cell phone)- P( game system and cell phone)
= 0.72+0.93-0.68
= 0.97
Hence, the probability of a teenager owning a gaming system or a cell phone is 0.97.
