Chemistry High School

Using the balanced chemical equation:
4NH3 + 302 --> 2N2 + 6H20
Determine the amount of grams of N2 is produced If 4.03 moles of NH3 react?

Answers

Answer 1
Your answer and workings are all mentioned in the picture below.
Using The Balanced Chemical Equation:4NH3 + 302 --> 2N2 + 6H20Determine The Amount Of Grams Of N2
Answer 2

Taking into account the reaction stoichiometry, 56.42 grams of N₂ are formed when 4 moles of NH₃ react.

Reaction stoichiometry

In first place, the balanced reaction is:

4 NH₃ + 3 O₂  → 2 N₂+ 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

NH₃: 4 molesO₂: 3 molesN₂: 2 molesH₂O: 6 moles

The molar mass of the compounds is:

NH₃: 17 g/moleO₂: 32 g/moleN₂: 28 g/moleH₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

NH₃: 4 moles ×17 g/mole= 68 gramsO₂: 3 moles ×32 g/mole= 96 gramsN₂: 2 moles ×28 g/mole= 56 gramsH₂O: 6 moles ×18 g/mole= 108 grams

Mass of N₂ formed

The following rule of three can be applied: if by reaction stoichiometry 4 moles of NH₃ form 56 grams of N₂, 4.03 moles of NH₃ form how much mass of N₂?

[tex]mass of N_{2} =\frac{4.03 moles NH_{3} x56 grams of N_{2} }{4 moles NH_{3}}[/tex]

mass of N₂= 56.42 grams

Then, 56.42 grams of N₂ are formed when 4 moles of NH₃ react.

Learn more about the reaction stoichiometry:

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Answers

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