ver-P = W
(Remember these are metric units!)
Work-W = Fd
I. Solve and show your work
a. If a man carries a 44 pound box of books up a flight of stairs and he has a mass of 100
kg himself. How much work is done if the distance up is 10 meters?
*(remember he must lift himself and the box up the stairs)
b. How much power is necessary to do this in only I minute?

Answer:

Therefore, the speed of sound in air, with a frequency of 1120 Hz and a wavelength of 30 cm, is approximately 336 meters per second.

Explanation:

To find the speed of sound in air, we can use the formula:

speed = frequency × wavelength

Given:

Frequency (f) = 1120 Hz

Wavelength (λ) = 30 cm

First, we need to convert the wavelength to meters since the speed of sound is commonly expressed in meters per second.

1 meter = 100 centimeters

Wavelength in meters (λ) = 30 cm ÷ 100 = 0.3 meters

Now we can substitute the values into the formula:

speed = frequency × wavelength

= 1120 Hz × 0.3 meters

Calculating the value:

speed = 336 meters per second

Diving seabirds need to account for the bending of light because water has a higher refractive index than air.

When light passes through the air-water interface, it slows down and changes direction, causing the image of an object to appear distorted. This phenomenon is known as refraction. For diving seabirds, the refraction of light can make it challenging to accurately locate their prey when diving, which is essential for their survival.

To account for the bending of light, diving seabirds have evolved specialized eyes that allow them to adjust their focus and perceive images differently than humans. These adaptations enable the birds to see through the distorted image caused by refraction and accurately locate their prey while diving. One adaptation that diving seabirds have is a flattened cornea, which allows them to maintain a sharp focus while diving.

Overall, the ability of diving seabirds to account for the bending of light is essential for their survival, as it enables them to accurately locate and catch their prey while diving in the often murky and challenging conditions of the ocean.

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Answer:

D

Explanation:

Using the formula for average acceleration, which is:

average acceleration = (final velocity - initial velocity) / time

Where the initial velocity is 0 m/s and the final velocity is 60 m/s, and the time is 3 seconds, we get:

average acceleration = (60 m/s - 0 m/s) / 3 s = 20 m/s²

Therefore, the answer is (d) 20 m/s².

When a small rubber ball bounces off a larger, heavier basketball, the basketball will move slightly in the opposite direction, but it will move much slower than the rubber ball due to its larger mass.

According to Newton's third law of motion, every action has an equal and opposite reaction. In the case of the small rubber ball bouncing off the basketball, the rubber ball exerts a force on the basketball, and the basketball exerts an equal and opposite force back on the rubber ball.

As a result, the small rubber ball bounces back in the opposite direction, while the basketball experiences a force in the opposite direction.

The motion of the basketball after the small ball bounces back depends on the mass and velocity of the two objects. Since the basketball is much larger and heavier than the rubber ball, it will not move much, if at all.

In fact, if the rubber ball is light enough and bounces back with enough force, it may cause the basketball to move slightly in the opposite direction. However, the basketball will move much slower than the rubber ball due to its larger mass and slower acceleration.

In terms of direction, the basketball will move in the opposite direction of the rubber ball, as dictated by the conservation of momentum. Since the total momentum of the system before and after the collision must be conserved, the basketball will move in the opposite direction of the rubber ball to balance out the momentum.

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A linear object is placed parallel to a mirror. The object rotates 40° clockwise, in a perpendicular line on the mirror. The object's image would appear rotated counterclockwise by 40° compared to its initial position.

When a linear object is placed parallel to a mirror and rotates 40° clockwise in a perpendicular line on the mirror, the image of the object undergoes a change. The image formed in a mirror follows the law of reflection, which states that the angle of incidence is equal to the angle of reflection.

Initially, when the object is parallel to the mirror, its image is also parallel and located at the same distance behind the mirror as the object is in front of it. However, as the object rotates clockwise, the incident angle between the object and the mirror changes, resulting in a different reflected angle.

As the object rotates, the image rotates by the same angle but in the opposite direction. In this case, the image would rotate 40° counterclockwise. Therefore, the image of the linear object would appear rotated counterclockwise by 40° compared to its initial position.

It is important to note that the size of the image and the distance between the object and its image remain unchanged, as long as the object maintains the same distance from the mirror throughout the rotation. Only the orientation or rotation of the image changes.

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A transverse wave moves perpendicular to the particle vibration, while a compressional wave moves parallel to the particle vibration. Light waves are an example of a transverse wave, and sound waves are an example of a compressional wave.

A transverse wave is a type of wave in which the particles of the medium vibrate perpendicular to the direction of the wave's propagation. This means that as the wave moves forward, the particles move up and down or side to side. An example of a transverse wave is a light wave. When light travels through space, the electric and magnetic fields oscillate perpendicular to the direction of the wave.
A compressional wave is a type of wave in which the particles of the medium vibrate parallel to the direction of the wave's propagation. This means that as the wave moves forward, the particles move back and forth, creating compressions and rarefactions in the medium. An example of a compressional wave is a sound wave. When sound travels through air, the molecules of air vibrate back and forth, creating areas of high pressure (compressions) and low pressure (rarefactions).
In summary, a transverse wave moves perpendicular to the particle vibration, while a compressional wave moves parallel to the particle vibration. Light waves are an example of a transverse wave, and sound waves are an example of a compressional wave.

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Answer:

P = 39200.76

Explanation:

formula is:

P = pgh

P = pressure

p = density of fluid

g = acceleration due to gravity ( 9.81 m/s2  for earth)

h = height above the point we are looking for

P = pgh

P = 999x9.81x4

P = 39200.76

Answer:

We can use the kinematic equations to solve this problem.

Let a be the acceleration and d be the distance traveled at maximum speed.

First, we can use the equation:

d = vt + (1/2)at^2

where v is the maximum speed, t is the time traveled at maximum speed, and a is the acceleration.

We know that the bus takes 21 seconds to travel 270 meters, so the time traveled at maximum speed is:

21 - 2a = t

We also know that the acceleration is twice as great as the deceleration, so we can write:

a = 2d

Then, we can substitute these expressions into the first equation:

d = (20)(21 - 2a) + (1/2)(2d)(21 - 2a)^2

Simplifying and solving for d, we get:

d = 210 - 5.25a + 0.25a^2

To find the acceleration, we can use the fact that the maximum speed is reached at the midpoint of the trip, so the distance traveled at maximum speed is half the total distance:

d = 1/2(270)

Solving for d, we get:

d = 135

Substituting this value into the equation for d, we get:

135 = 210 - 5.25a + 0.25a^2

Simplifying and solving for a, we get:

a = 8 m/s^2

Finally, we can use the equation:

d = vt

to find the distance traveled at maximum speed:

d = (20)(21 - 2a)

Substituting the value of a, we get:

d ≈ 188.4 m

Therefore, the acceleration of the bus is 8 m/s^2 and the distance traveled at maximum speed is approximately 188.4 meters.

The wavelength of the note produced by the cello is 0.65 m.

The frequency of the note played by cello, f = 346.2 Hz

Speed of the sound in air, v = 225 m/s

Speed of a wave is calculated by taking the product of its frequency and wavelength.

The expression for the speed of the sound wave is given by,

v = fλ

where λ is the wavelength of the note produced.

Therefore, the wavelength of the note produced by the cello,

λ = v/f

Applying the values of v and f,

λ = 225/346.2

λ = 0.65 m

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The question is incomplete. Could you please provide more details or clarify your question? I will explain molecular mass.

A substance's molecular mass, measured in grams per mole (g/mol), is referred to as its molar mass. It is utilized in many chemical computations and conversions and is computed by adding the atomic masses of the atoms in a molecule.

The molar mass is the mass of one mole of a substance, expressed in grams per mole (g/mol). It is calculated by summing the atomic masses of all the atoms in a molecule. The atomic masses can be found on the periodic table. Molar mass is important in various applications, such as stoichiometry, where it is used to convert between the mass of a substance and the number of moles.

It is also used to determine the empirical formula and molecular formula of compounds. Molar mass plays a crucial role in chemical reactions and calculations involving the quantities of substances, providing a bridge between the microscopic realm of atoms and molecules and the macroscopic world of everyday measurements.

Therefore, Molar mass refers to the mass of one mole of a substance, expressed in grams per mole (g/mol). It is calculated by summing the atomic masses of the atoms in a molecule and is used in various chemical calculations and conversions.

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The period of the simple harmonic motion of the center of mass of the two spheres is approximately 0.770 seconds.

To find the period of the simple harmonic motion of the center of mass of the two spheres, we need to use the equation for the period of a mass-spring system:

T = 2π√(m/k)

where T is the period, m is the total mass of the system (two spheres), and k is the spring constant.

First, we need to find the total mass of the system:

m = 2m1 = 2(0.852 kg) = 1.704 kg

where m1 is the mass of one sphere.

Next, we need to find the spring constant:

k = 153 N/m

Now, we can calculate the period:

2π√(1.704 kg/153 N/m) ≈ 0.770 s

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If a swimmer swims the 50m length of a swimming pool in 15.91 second and makes the return swim in 18 seconds then the swimmer's average speed for the full swim is 2.948 metres per second.

To find the swimmer's average speed for the full swim, we need to calculate the total distance swum and the total time taken.
The swimmer swam the 50m length of the pool twice, once in 15.91 seconds and once in 18 seconds. So the total distance swum is 50m + 50m = 100m.
The total time taken is the sum of the time taken for each length: 15.91 seconds + 18 seconds = 33.91 seconds.
To find the swimmer's average speed, we divide the total distance by the total time:
Average speed = total distance ÷ total time
= 100m ÷ 33.91 seconds
= 2.948 metres per second
Therefore, the swimmer's average speed for the full swim is 2.948 metres per second. This is a relatively fast speed, but it's important to note that the swimmer's speed may vary depending on their stroke technique, physical fitness, and other factors. Nonetheless, it's an impressive achievement for the swimmer to complete the full 100m in under 34 seconds.

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Materials with high specific heat include materials such as concrete, masonry, adobe, and some types of stone. These materials can be used in walls, floors, or roofs to provide thermal mass and improve indoor comfort, energy efficiency, and sustainability.