Viết các số 1,2,..,100 theo một thứ tự nào đó, được dãy a1, a2,..,a100. CMR: Tổng S= |a1 - 1| + |a2 -2| + .. +|a100 -100|. Hãy tổng quát hóa bài toán

Distance Formula: [tex]\sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2}[/tex]

Point 1: (9,0)

Point 2: (5,-8)

D = sqrt[ (5 - 9)^2 + (-8 - 0)^2 ]

D = sqrt[ (-4)^2 + (-8)^2 ]

D = sqrt[ 16 + 64]

D = sqrt(80)

Hope this helps!

0.1449 = 14.49% probability that 6 students or more will score an "A" on the final exam.

---------------

For each student, there are only two possible outcomes. Either they score an A, or they do not. The probability of a student scoring an A is independent of any other student, which means that the binomial probability distribution is used to solve this question.

Additionally, to find the proportion of students who scored an A, the normal distribution is used.

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Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which  is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of a success.

----------------

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

----------------

Proportion of students that scored an A:

Scores have a mean of 79 and a standard deviation of 11.3, which means that [tex]\mu = 79, \sigma = 11.3[/tex]

Scores of 90 or higher are graded an A, which means that the proportion is 1 subtracted by the p-value of Z when X = 90, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{90 - 79}{11.3}[/tex]

[tex]Z = 0.97[/tex]

[tex]Z = 0.97[/tex] has a p-value of 0.8340.

1 - 0.8340 = 0.166

The proportion of students that scored an A is 0.166.

----------------

Probability that 6 students or more will score an "A" on the final exam:

Binomial distribution.

22 students, which means that [tex]n = 22[/tex]

The proportion of students that scored an A is 0.166, which means that [tex]p = 0.166[/tex]

The probability is:

[tex]P(X \geq 6) = 1 - P(X < 6)[/tex]

In which

[tex]P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)[/tex]

Then

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{22,0}.(0.166)^{0}.(0.834)^{22} = 0.0184[/tex]

[tex]P(X = 1) = C_{22,1}.(0.166)^{1}.(0.834)^{21} = 0.0807[/tex]

[tex]P(X = 2) = C_{22,2}.(0.166)^{2}.(0.834)^{20} = 0.1687[/tex]

[tex]P(X = 3) = C_{22,3}.(0.166)^{3}.(0.834)^{19} = 0.2239[/tex]

[tex]P(X = 4) = C_{22,4}.(0.166)^{4}.(0.834)^{18} = 0.2117[/tex]

[tex]P(X = 5) = C_{22,5}.(0.166)^{5}.(0.834)^{17} = 0.1517[/tex]

Then

[tex]P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0184 + 0.0807 + 0.1687 + 0.2239 + 0.2117 + 0.1517 = 0.8551[/tex]

[tex]P(X \geq 6) = 1 - P(X < 6) = 1 - 0.8551 = 0.1449[/tex]

Thus

0.1449 = 14.49% probability that 6 students or more will score an "A" on the final exam.

For a problem that used the normal distribution, you can check https://brainly.com/question/15181104, and for a problem that used the binomial distribution, you can check https://brainly.com/question/15557838

Answer:

184.22

Step-by-step explanation:

Answer:

[tex]n = 8[/tex]

Step-by-step explanation:

Given

[tex]3(^nP_2 + 24) = ^{2n}P_2[/tex]

Required

Find n

To do this, we simply apply permutations formula

[tex]nP_r = \frac{n!}{(n -r)!}[/tex]

So, we have:

[tex]3 * [\frac{n!}{(n -2)!} + 24] = \frac{2n!}{(2n -2)!}[/tex]

Expand

[tex]3 * [\frac{n * (n - 1) * (n - 2)!}{(n -2)!} + 24] = \frac{2n * (2n - 1) * (2n - 2)}{2n - 2}[/tex]

[tex]3 * [n * (n - 1) + 24] = 2n * (2n - 1)[/tex]

[tex]3 * [n^2 - n + 24] = 4n^2 - 2n[/tex]

Open bracket

[tex]3n^2 - 3n + 72 = 4n^2 - 2n[/tex]

Collect like terms

[tex]3n^2 - 4n^2- 3n+2n + 72 = 0[/tex]

[tex]-n^2- n + 72 = 0[/tex]

Expand

[tex]-n^2 -9n + 8n + 72 = 0[/tex]

Factorize

[tex]-n(n +9) - 8(n + 9) = 0[/tex]

Factor out n + 9

[tex](-n -8)(n + 9) = 0[/tex]

Split

[tex](-n -8)= 0 \ or\ (n + 9) = 0[/tex]

Solve for n

[tex]n =8\ or\ n = -9[/tex]

The positive value is [tex]n = 8[/tex]

The correct answer of the question is "0.7062" and "0.835". The further solution is provided below.

Given:

Probability of student smoke,

P = 27.7%

  = 0.277

Number of students (n) = 632

[tex]q = 1-p[/tex]

  [tex]=1-0.277[/tex]

  [tex]=0.723[/tex]

(i)

Here,

Number of students (n) = 60

then,

⇒ [tex]n_P=60\times 0.277[/tex]

         [tex]=16.62[/tex]

⇒ [tex]n_q=60\times 0.723[/tex]

        [tex]=43.38[/tex]

We can see that [tex]n_P > 10[/tex] and [tex]n_q>10[/tex] so the normal approximation condition are met.

Now,

[tex]\mu = n_P= 16.62[/tex]

[tex]\sigma = \sqrt{n_{Pq}}[/tex]

  [tex]= \sqrt{60\times 0.277\times 0.723}[/tex]

  [tex]=3.9664[/tex]

Now,

⇒ [tex]P(X<19) = P(X<18.5)[/tex]

                      [tex]=P(Z_{18.5})[/tex]

The Z-score is:

= [tex]\frac{18.5-16.62}{3.4664}[/tex]

= [tex]0.5423[/tex]

hence,

The probability will be:

⇒ [tex]P(Z_{18.5}) = 0.7062[/tex]

or,

⇒ [tex]P(Z<19) = 0.7062[/tex]

(ii)

Here,

Number of students (n) = 75

[tex]\mu = n_P = 75\times 0.277[/tex]

            [tex]=20.775[/tex]

[tex]\sigma = \sqrt{n_{Pq}}[/tex]

   [tex]=\sqrt{75\times 0.277\times 0.723}[/tex]

   [tex]=3.8756[/tex]

Now,

⇒ [tex]P(X>17) = P(X> 17.5)[/tex]

                      [tex]=1-P(X \leq 17.5)[/tex]

                      [tex]=1-P(Z_{17.5})[/tex]

The Z-score is:

= [tex]\frac{17.5-20.775}{3.8756}[/tex]

= [tex]-0.9740[/tex]

then, [tex]P(Z_{17.5}) = 0.165[/tex]

hence,

The probability will be:

⇒ [tex]P(X>17) = 1-0.165[/tex]

                      [tex]=0.835[/tex]    

Learn more about Probability here:

https://brainly.com/question/9825651

Answer:504

This is the answer

504

Answer:

AC is about 4.29

Step-by-step explanation:

we need to use simple trigonometry for this problem

the tangent of an angle is the ratio between the opposite side and the adjacent side

so the tangent of the angle 35º is BC / AC

tan(35) is about 0.7

this means that BC / AC = 0.7

we know BC is 3

so 3 / AC = 0.7

3 = 0.7(AC)

AC is about 4.29

Answer:

ask in English then I can help

(3x +2)(x -3)

FOIL method

3x^2 -9x + 2x -6

3x^2 -7x -6

Your answer: 3x^2 -7x -6

9514 1404 393

Answer:

  (d)  360°

Step-by-step explanation:

The sum of exterior angles of any convex polygon is 360°.

Answer:

y = 3x - 2

Happy Studying

Answer:

The function to determine the value of your car (in dollars) in terms of the number of years t since 2012 is:

[tex]f(t) = 10000(0.9407)^t[/tex]

Step-by-step explanation:

Value of the car:

Constant rate of change, so the value of the car in t years after 2012 is given by:

[tex]f(t) = f(0)(1-r)^t[/tex]

In which f(0) is the initial value and r is the decay rate, as a decimal.

In 2012 your car was worth $10,000.

This means that [tex]f(0) = 10000[/tex], thus:

[tex]f(t) = 10000(1-r)^t[/tex]

2014 your car was worth $8,850.

2014 - 2012 = 2, so:

[tex]f(2) = 8850[/tex]

We use this to find 1 - r.

[tex]f(t) = 10000(1-r)^t[/tex]

[tex]8850 = 10000(1-r)^2[/tex]

[tex](1-r)^2 = \frac{8850}{10000}[/tex]

[tex](1-r)^2 = 0.885[/tex]

[tex]\sqrt{(1-r)^2} = \sqrt{0.885}[/tex]

[tex]1 - r = 0.9407[/tex]

Thus

[tex]f(t) = 10000(1-r)^t[/tex]

[tex]f(t) = 10000(0.9407)^t[/tex]

Answer:

B

Step-by-step explanation:

f(x) = sqrt(x) + 9

f(x) - 9=sqrt(x)

f^(-1)(x)=(x-9)^2 and it's domain is greater than 0

Answer:

605 boys.

Step-by-step explanation:

5:7 means 5 parts consists of boys and 7 parts consist of girls.

Since 7 parts = 847, 1 part = 121 and 5 parts = 605

Hence there are 605 boys.

Hope you have a nice day :)

9514 1404 393

Answer:

  Yes, that distance is the hypotenuse of a right triangle whose sides are known

Step-by-step explanation:

The diagram seems to show the path of the ball as being two segments that are at right angles to each other. Then the direct-line distance to the hole from the tee is the hypotenuse (part A) of the triangle.

Since the leg lengths are known, the Pythagorean theorem can be used (part B) to find the length of the hypotenuse. (The answer to Part B is also the answer to Part C.)

Answer:

Area = 240 cm²

Perimeter = 80 cm

Step-by-step explanation:

✔️ Area of the triangle = ½*base*height

base of the triangle = 24 cm

height = 20 cm

Plug in the known values

Area = ½*24*20

= 12*20

Area = 240 cm²

✔️Perimeter of the triangle = sum of all the three sides that make up the triangle

Perimeter = 22 + 24 + 34

= 80 cm

9514 1404 393

Answer:

  B) -2

Step-by-step explanation:

The midpoint is the average of the end points.

  M = (A +B)/2

  M = (-6 +2)/2 = -4/2 = -2

The coordinate of M is -2.

Let x be the first number in the sequence. Then the first three numbers are

{x, x + 3, x + 6}

The next sentence says that the sequence

{x + 1, x + 9, x + 25}

is geometric, which means there is some fixed number r for which

x + 9 = r (x + 1)

x + 25 = r (x + 9)

Solve for r :

r = (x + 9)/(x + 1) = (x + 25)/(x + 9)

Solve for x :

(x + 9)² = (x + 25) (x + 1)

x ² + 18x + 81 = x ² + 26x + 25

8x = 56

x = 7

Then the three numbers are

{7, 10, 13}

[tex]\\ \sf\longmapsto y=(6x-5)\sqrt{8x-3}[/tex]

[tex]\\ \sf\longmapsto y=6(-4)-5\sqrt{8(-4)-3}[/tex]

[tex]\\ \sf\longmapsto y=-24-5\sqrt{-32-3}[/tex]

[tex]\\ \sf\longmapsto y=-29\sqrt{-35}[/tex]

[tex]\\ \sf\longmapsto y=-29\times 35i[/tex]

[tex]\\ \sf\longmapsto y=-1015i[/tex]

Answer:

Radius on it's own is enough

Step-by-step explanation:

you could get the radius from the other informations, but after all you will calculate the volume with it and not the otheds, so just take radius. a sphere is, in terms of information, the simplest 3D-body to describe, like with a circle in 2D

The dimensions would you need to calculate the volume of a basketball is Radius on its own is enough

We have given that,

radius and height

length, width, and slant height

radius

length, width, and height

We have to determine the dimensions would you need to calculate the volume of a basketball.

Dimensions in mathematics are the measure of the size or distance of an object or region or space in one direction.

you could get the radius from the other information, but after all, you will calculate the volume with it and not the others, so just take the radius.

A sphere is, in terms of information, the simplest 3D body to describe, like a circle in 2D.

To learn more about the dimension visit:

https://brainly.com/question/26740257

#SPJ2

9514 1404 393

Answer:

  90°, 60°, 30°

Step-by-step explanation:

The remaining angles have a ratio of 2:1, so total 3 "ratio units". The first angle is equal to that sum: 3 ratio units, so all of the angles together total 3+2+1 = 6 ratio units. The total of angles is 180°, so each ratio unit is 180°/6 = 30°.

The first angle is 3 ratio units, or 90°.

The second angle is 2 ratio units, or 60°.

The third angle is half that, or 30°.

The three angles are 90°, 60°, 30°.

Answer:

See attachment

Step-by-step explanation:

Given

[tex]\begin{array}{ccccccc}{Marks} & {0-10} & {10-20} & {20-30} & {30-40} & {40-50} & {50-60}\ \\ {Students} & {7} & {15} & {22} & {30} & {16} & {10} \ \end{array}[/tex]

Required

The frequency polygon

We have:

[tex]\begin{array}{ccccccc}{Marks} & {0-10} & {10-20} & {20-30} & {30-40} & {40-50} & {50-60}\ \\ {Students} & {7} & {15} & {22} & {30} & {16} & {10} \ \end{array}[/tex]

First, we calculate the midpoint of each class

[tex]\begin{array}{ccccccc}{Midpoint} & {(0+10)/2} & {(10+20)/2} & {(20+30)/2} & {(30+40)/2} & {(40+50)/2} & {(50+60)/2}\ \\ {Students} & {7} & {15} & {22} & {30} & {16} & {10} \ \end{array}[/tex]

[tex]\begin{array}{ccccccc}{Midpoint} & {5} & {15} & {25} & {35} & {45} & {55}\ \\ {Students} & {7} & {15} & {22} & {30} & {16} & {10} \ \end{array}[/tex]

Lastly, we plot the midpoint against the frequency of students (see attachment)

Answer:

c: 21/205

Step-by-step explanation:

The probability of choosing a yellow marble first is 12/41 bc there are 12 yellow marbles and 41 marbles to choose from.

The probability of choosing a red marble is 14/40 bc there are 14 red marbles and 40 marbles to choose from( since you have removed the marble you first chose so there are 40 marbles left).

Multiplying these two together, 12/41 * 14/40 = 168/1640, simplified it's 21/205.

Answer:

1500000

Step-by-step explanation:

1 metre = 100 cm

15000metre =15000*100

=1500000

The expected value of a normal distribution is the mean of the distribution, while the variance measures the squared deviation of a value from the expected value. The expected value and the variance are: [tex]13.6190 \times 10^{-5}[/tex] and [tex]580.8000 \times 10^{-9}[/tex]

Given that, the diameters are:

[tex]d_1 = 0.02[/tex]

[tex]d_2 = 0.08[/tex]

The radius is:

[tex]r = \frac{d}{2}[/tex]

So, we have:

[tex]r_1 = \frac{0.02}{2} = 0.01[/tex]

[tex]r_2 = \frac{0.08}{2} = 0.04[/tex]

The volume of the sphere is:

[tex]V = \frac{4}{3} \times \pi \times r^3[/tex]

For [tex]r_1 = 0.01[/tex], the volume is:

[tex]V_1 = \frac{4}{3} \times \frac{22}{7} \times 0.01^3 = 0.419047 \times 10^{-5}[/tex]

For [tex]r_2 = 0.04[/tex], the volume is

[tex]V_2 = \frac{4}{3} \times \frac{22}{7} \times 0.04^3 = 26.819047 \times 10^{-5}[/tex]

The mean of a uniform distribution is:

[tex]E(y) = \frac{a + b}{2}[/tex]

In this case, the mean is:

[tex]E(y) = \frac{V_1 + V_2}{2}[/tex]

So, we have:

[tex]E(y) = \frac{0.419047 \times 10^{-5} + 26.819047 \times 10^{-5}}{2}[/tex]

[tex]E(y) = \frac{27.238094\times 10^{-5} }{2}[/tex]

[tex]E(y) = 13.619047 \times 10^{-5}[/tex]

Approximate

[tex]E(y) = 13.6190 \times 10^{-5}[/tex]

The variance of a uniform distribution is:

[tex]V(y) = \frac{(b-a)^2}{12}[/tex]

In this case, the volume is:

[tex]V(y) = \frac{(V_2-V_1)^2}{12}[/tex]

So, we have:

[tex]V(y) = \frac{(26.819047 \times 10^{-5}- 0.419047 \times 10^{-5})^2}{12}[/tex]

[tex]V(y) = \frac{(26.4 \times 10^{-5})^2}{12}[/tex]

[tex]V(y) = \frac{(696.96 \times 10^{-10})}{12}[/tex]

[tex]V(y) = 58.08000 \times 10^{-10}[/tex]

Rewrite as:

[tex]V(y) = 580.8000 \times 10^{-9}[/tex]

Hence, the expected value and the variance of the sphere are:[tex]13.6190 \times 10^{-5}[/tex] and [tex]580.8000 \times 10^{-9}[/tex]

Learn more about expected values and variance at:

https://brainly.com/question/4470015

Answer:D) Under-root 25.Under-root 3

Step-by-step explanation

Under-root 25 = 5

Answer:

Answer D and B.

Step-by-step explanation:

[tex]{ \bf{5 \sqrt{3} }} \\ = { \bf{ \sqrt{ {5}^{2} } \times \sqrt{3} }} \\ = { \bf{ \sqrt{25} . \sqrt{3} }}[/tex]

Answer:

y = -3x/2 - 1/2

Step-by-step explanation:

slope m = -3/2

-5 = (-3/2)×3+b

or, b = -1/2

putting it into y = mx + b

y = -3x/2 - 1/2

Answered by GAUTHMATH

Answer:

Option b: Rectangle

Explanation:

Give branliest pls ;)