The Acceleration of the system is 6.41 m/s².
Given,
α= 15°, m₁ = 7kg
β= 65°, m₂ = 11 kg
Let, a be the acceleration and T is the tensions at the end it's the cord.
Let, the mass m₂ be coming down along the inclined plane along the inclined surface towards downward m₂g sin β and the tension in the upward direction,
Resultant force, m₂a=m₂g sin β -T
11a=((11) ×g sin 65°) -T ...(i)
Now, considering the motion of m₁ which moves downwards, the forces are m₁g sinα, and T both are acting downwards.
Resultant force m₁a = m₁g sin α+T
7a =7g sin 15°+T ...(ii)
Solving both the equations by adding them,
18a=11gsin 65°+7g sin 15°-T+T
18a=11gsin 65°+7g sin 15°=115.45
a=115.45/18=6.41 m/s²
Hence, the Acceleration of the system is 6.41 m/s².
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Against the park ranger's advice, a visitor at a national park throws a stone horizontally off the edge of a 86 m high cliff and it lands a distance of 89 m from the edge of the cliff, narrowly missing a visitor below.
What was the initial horizontal velocity of the rock, in m/s? You can round your answer to the hundredth place and use g ≈ 10 m/s2.
The initial horizontal velocity of the rock, in m/s is 21.241 m/s.
What is projectile?When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.
Time taken by the stone to reach the ground is
t = √2h/g
t = √(2x 86)/9.81
t = 4.19s
The horizontal velocity is
V(x) = Horizontal distance traveled / Time taken t
Put the values, we get
V(x) = 89 m/4.19 s
V(x) = 21.241 m/s
Thus, the horizontal velocity is 21.241 m/s
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how can you tell the difference between an expression of speed and an expression of velocity?
A. velocity has unit expressed as distance/time; speed does not.
B. speed has units expressed as distance/time; velocity does not.
C. speed includes a direction; velocity does not.
D. velocity includes a direction; speed does not.
Find the energy u of the capacitor in terms of c and q by using the definition of capacitance and the formula for the energy in a capacitor
The formula for the energy in a capacitor , u in terms of q and c is q²/2c
What is the energy of a capacitor?The energy of a capacitor u = 1/2qv where
q = charge on capacitor and v = voltage across capacitor.What is the capacitance of a capacitor?Also, the capacitance of a capacitor c = q/v where
q = charge on capacitor and v = voltage across capacitor.So, v = q/c
The formula for energy of the capacitor in terms of q and c
Substituting v into u, we have
u = 1/2qv
= 1/2q(q/c)
= q²/2c
So, the formula for the energy in a capacitor , u in terms of q and c is q²/2c
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What local group of galaxies is the Milky Way part of?
Quasar Cluster
Andromeda Mini-Cluster
Virgo Supercluster
Hubble Open Cluster
The local group of galaxies which the Milky Way belong to is the Virgo Supercluster. C
What are Virgo Supercluster?The Virgo Supercluster as known as the Local Supercluster is a mass concentration of galaxies that contains the Virgo Cluster and Local Group which in turn contains the Milky Way and Andromeda galaxies, as a host as others galaxies.
Therefore, the local group of galaxies which the Milky Way belong to is the Virgo Supercluster.
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when a boy jumps into a pool
Answer:
energy only
Explanation:
Water waves transfer energy via oscillations of the water molecules, but the the water molecules themselves do not move along the wave.
This is why when the boy jumps into the water, his kinetic energy is transferred by the water molecules across the pool, but neither the boy nor the water particles move along with the wave.
In a game of Tug-of-War,
when are the forces
unbalanced?
A. when one side lets go of the rope
B. when the net force is o N
C. when both sides pull with 55 N
Two 2.0-mm diameter beads, c and d, are 12mm mm apart, measured between their centers. bead c has mass 1.0 g and charge 2.5nc nc . bead d has mass 1.7g g and charge -1.0 nc. if the beads are released from rest.
a. what is the speed vc at the instant the beads collide?
b. what is the speed vd at the instant the beads collide?
The speed of Vc at the instant bead collide is 1.38 m/s and the instant speed of Vd at the instant bead collide is 0.106 m/s.
The force of attraction on the beads are due to both gravitational force and electrostatic force
As gravitational force is very weak force as compared to electrostatic force the net force will be due to electrostatic force only.
Net Force = Electrostatic force
Net Force = K q1 q2 / r²
Net Force = (9 × 10⁹) (2.5 × 10⁻⁹) (1 × 10⁻⁹) / (14 × 10⁻³) (as distance between there centre of mass is 14 mm)
Net Force = (9 × 2.5 × 10⁻⁶) / 14
Net Force = 1.6 × 10⁻⁶
For bead c
Force = Mc × Ac = 1.6 × 10⁻⁶
(1 × 10⁻³) × Ac = 1.6 × 10⁻⁶
Ac = 1.6 × 10⁻³
Acceleration of bead C is 1.6 × 10⁻³ m/s²
For bead d
Force = Md × Ad = 1.6 × 10⁻⁶
(1.7 × 10⁻³) × Ad = 1.6 × 10⁻⁶
Ad = 0.94 × 10⁻³
Acceleration of bead D is 0.94 × 10⁻³ m/s²
Let us suppose bead C travels y distance before collision
So bead D should travel 12-y distance before collision
So speed of both the beads before the collision can be find out by using newton third law of motion
For bead C
Vc² - Uc² = 2 Ac s
Vc² = 2 × 1.6 × 10⁻³ × y
Vc² = 3.2 × 10⁻³ × y
Vc = √(3.2 × 10⁻³ × y)
For bead D
Vd² - Ud² = 2 Ad s
Vd² = 2 × 0.94 × 10⁻³ × (12-y)
Vd² = 1.88 × 10⁻³ × (12-y)
Vd = √(1.88 × 10⁻³ × (12-y))
Applying energy conservation
initial = final
0 + 0 = (1/2)McVc² - (1/2)MdVd²
(1/2)McVc² = (1/2)MdVd²
McVc² = MdVd²
1 × 10⁻³ × 3.2 × 10⁻³ × y = 1.7 × 10⁻³ × 1.88 × 10⁻³ × (12-y)
3.2 × y = 3.2 × (12-y)
y = 12-y
2y = 12
y = 6
Putting the value of y in Vc and Vd
Vc = √(3.2 × 10⁻³ × y)
Vc = √(3.2 × 10⁻³ × 6)
Vc = √(19.2 × 10⁻³)
Vc = √0.0192
Vc = 1.38 m/s (approximately)
Vd = √(1.88 × 10⁻³ × (12-y))
Vd = √(1.88 × 10⁻³ × (12-6))
Vd = √(1.88 × 10⁻³ × 6)
Vd = √(11.28 × 10⁻³)
Vd = √0.01128
Vd = 0.106 m/s (approximately)
So the speed of Vc at the instant beads collide will be approximately 1.38 m/s and Vd at the instant speed the beads collide will be approximately 0.106 m/s.
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Question 9 of 34
When you graph displacement versus time (a displacement-time graph), what
variable is on the y-axis?
O A. Speed
OB. Displacement
C. Time
O D. Velocity
SUBMIT
Answer:
Option B) Displacement
You are ask to bring a cylindrical rod of length 45cm and diameter of 4.53cm to a mechanic. what is the weight of the aluminum rod if the density is 3.7*10^3kg/m^3
26.676 × 10³ kg is the weight of the aluminum rod.
To calculate specific weight:Given:
Length of cylindrical rod (h) = 45 cm
Diameter of a cylindrical rod = 4.53 cm
Radius of a cylindrical rod (r) = 2.3 cm
The density = 3.7*10^3kg/m^3
Volume of a cylindrical rod = πr²h
= 3.14× (2.3)² × 45
= 747.89 cm
= 7.4789 m
To find weight ;
ρ = [tex]\frac{Mass}{Volume}[/tex] ; ρ = Density
Mass = ρ × Volume
= 3.7 × 7.48 × 10³
=27.676 × 10³ kg
Therefore, the weight of the aluminum rod is 27.676 × 10³ kg.
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Which of the following differentiates an audiologist from an anthropologist?
An audiologist uses empirical evidence to determine treatment.
An audiologist uses empirical evidence to determine treatment.
An audiologist examines physical characteristics of humans.
An audiologist evaluates communication methods.
An audiologist analyzes observed behaviors.
The statement that differentiates an audiologist from an anthropologist is that an audiologist examines physical characteristics of humans. That is option C.
Who is an audiologist?Audiologist is an individual that specializes in the diagnosis, treatment and management of hearing loss and balance disorders in adults and children.
An anthropologist is also an individual that studied the past and present experiences of individuals.
Therefore, the statement that differentiates an audiologist from an anthropologist is that an audiologist examines physical characteristics of humans.
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The ability to provide for our needs without damaging Earth's resources is called _______.
A. Acid Rain
B. Sustainability
C. Degradation
D. Pollution
Answer = B
Explanation:
Sustainability is the most appropriate as it means meeting our own needs without compromising the ability of future generations to meet their own needs.
Refer to the attached image!!!
The time of motion of the track star is determined as 0.837 s.
Time of motion of the track star
The time of motion of the track star is calculated as follows;
T = (2u sinθ)/g
where;
T is time of motiong is acceleration due to gravityθ is angle of projectionT = (2 x 12 x sin20)/9.8
T = 0.837 s
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Use the image to determine the volume of the rock.
Answer:
12 ml
Explanation:
The initial volume in the cylinder is 20 ml
adding the rock adds volume to the cylinder
the new volume is 32 ml .....the increase in volume is the volume of the rock : 32 - 20 = 12 ml volume of rock
calculate the heat energy required to increase the temperature of 10 kg of water from 25 degrees Celsius to 115 degrees Celsius
Answer:
3 767 400 joules
Explanation:
4.186 J/g-C is the specific heat of water
25 to 115 is 90 degrees C change
10 000 g is 10 kg of water
10 000 * 90 * 4.186 = 3 767 400 Joules
An atom is the most basic particle that represents what type of matter?
OA. Element
OB. Compound
OC. Crystal
OD. Mixture
Answer:
b
Explanation:
a compact car is about 1289 kg and its engine has the ability to generate 183831 W. if all that power is applied from a stand still and no energy is dissipated, how fast will the car be moving after 7 seconds.
The speed of the car moving after 7 seconds will be 31.5 m/sec.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
m is the mass of the car = 1289 Kg.
u is the initial velocity = 0 m/sec
a is the acceleration in m/sec²
v is the velocity after 7 seconds =?
The power developed is;
P =FV
F=ma
P=maV
183831=1289 kg × a × V
a = 142.61 / V
From Newton's second equation of motion;
V=u+at
V=0+at
V=(142.61/V)t
V²=142.61 × 7
V=31.5 m/sec
Hence, the speed of the car moving after 7 seconds will be 31.5 m/sec.
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According to Newton's 2nd law of motion, if you hit a baseball with a bat it will
-hurt your hand from the reaction force
-accelerate according to the applied force
-fly in a straight line unless an outside force changes its course
-fall to the ground because of gravitational pull
Answer:
Newton's second law states that force is directly proportional to the product of mass and acceleration.
so if you hit a baseball with a bat it will accelerate according to the applied force.
Draw a ray diagram for a diverging lens that has a focal length of -10 cm when an object is placed 30 cm from the lens's surface. Calculate the position of the image and list the characteristics of the image.
Explanation:
Hello, nice to meet you.
this answer will help for you
The Volume Of a Body weighing is 1200 kg is 250000 [tex]cm^{3}[/tex] Find ITs density.
Write With Formula
Answer:
[tex]\boxed {Density = 4800 kg/m^{3}}[/tex]
Explanation:
Formula :
[tex]\boxed {Density = \frac{Mass (kg)}{Volume (m^{3})}}[/tex]
Convert volume into standard unit :
⇒ 250000 cm³ × 10⁻⁶
⇒ 0.25 × 10⁶ × 10⁻⁶
⇒ 0.25 m³
Solve for density :
⇒ Density = 1200 kg / 0.25 m³
⇒ Density = 1200 × 4 kg/m³
⇒ Density = 4800 kg/m³
what evidence did astronomers use to prove jets travel in opposite directions?
The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.
Who are the astronomers?Astronomer is a person who study astronomy which is a scientific study that has to do with space, space bodies, comets, planets, stars and so on.
Therefore, The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.
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When does a driver have to stop for a school bus
A driver have to stop for a school bus when the red lights are flashing and there is no barrier between his/her vehicle and the bus.
What are traffic rules?Traffic rules are rules that are expected to follow by the road users for the safety of everyone using the road.
For instance, when the red lights are flashing , it simply means to stop, while the green light means that the vehicle can continue to move, and yellow light means to be at alert to move.
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An electric motor rated 2.5kw is used to lift bales of hay to a store in a dairy farm. A single bale has a mass of 5kg. If the store is 4 meters above the ground, how many bales can the motor raise in 2 minutes.
A boy threw a ball upward and it took 3 sec to reach the highest point. Determine the initial velocity of the ball.
Answer:
V initial = 29.4 m.s²
Explanation:
( Using the laws of motion)
V final = V initial + Acceleration × time
0 = V initial + ( -9.8)(3)
29.4 = V initial
* I took upward as positive that's why I substituted -9.8 *
* for V final we know that at maximum height the ball is not moving thats why is = 0 *
Tabitha knows the redshift value of a particular celestial object. What can she use this information most directly to find out?
the age and distance of the object
the volume and mass of the object
the material composition of the object
the life expectancy of the object
She can use the information of redshift of a celestial body is to find the age and distance of the object.
What is red shift?'Red shift' is a critical idea for astronomers. The frequency of the light is increased, so the light is observed as moving towards the red side of the range.
Tabitha knows the redshift value of a particular celestial object. She uses this information to observe the consequence of the redshift.
Thus, the red shift value is used to determine the age and distance of the object.
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Answer:
A (the age and distance of the object)
Explanation:
How many degrees is the maximum and minimum variation between the true and magnetic poles?
The maximum and minimum variation between the true and magnetic poles is 180 degrees and 0 degrees respectively.
What are the true and magnetic poles?The poles of the earth are the North and South poles.
The North is taken as the reference point.
The true north is a fixed point on the globe and gives the true North and South poles.
The Magnetic north is the direction that a compass needle points to as it aligns with the Earth's magnetic field and gives the magnetic North and South poles.
The maximum maximum and minimum variation between the true and magnetic poles is 180 degrees and 0 degrees respectively.
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What is a characteristic of a catamaran hull? tends to pitch in waves only recommended on calm inland waters planes at low speed a stable ride
A Stable Ride is the main characteristic of a catamaran hull.
What is catamaran hull?
Catamaran Hull is a multi-hulled watercraft, which have two parallel hulls of equal size.
The characteristic of a catamaran hull are as follows:
A catamaran hull has less volume than an equal size monohull.Catamaran hulls are distinguished by lighter displacement and shallower draft when compared to monohulls of the same length. Catamarans can be used in shallow waters as well. This feature makes catamarans quite flexible and versatile.Catamaran has multiple hulls, usually two parallel hulls of equal size. This geometric feature gives the craft an increased stability.Catamarans derives extra stability from its wide beam, in the place of a ballasted keel employed in a regular monohull sailboat.Therefore, Catamarans has a stable ride, according to their characteristic.
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51. A balloon starts rising from the ground, vertically upwards, uniformly at the rate of 1 m s-1. At the end of 4 seconds, a body is released from the balloon. Calculate the time taken by the released body to reach the ground. 51. A balloon starts rising from the ground , vertically upwards , uniformly at the rate of 1 m s - 1 . At the end of 4 seconds , a body is released from the balloon . Calculate the time taken by the released body to reach the ground
Answer:
4s
Explanation:
when a bOdy rises into the air,the time it takes to reach a particular height is the same as the time it will take the body to fall from that height to the ground.
what are the classification of rectifier?
Thank uh ☘️
Explanation: A) half wave rectifier
B) Full wave rectifier :
1) central tapped
2) bridge rectifier
i hope this was helpful to you
In the homecoming game, the field goal kicker attempts to make a 47 yard (43 m) field goal. He kicks with an initial velocity of 20 m/s at an angle of 60° The field goal posts are 3 m high. Does he make the field goal? Explain your answer.
Given the data from the question, the goal kicker did not make the field goal.
To determine if the goal kicker makes the field goal, we shall determine the distance (i.e range) travelled by the ball after it was kicked by the kicker. This can be obtained as follow:
How to determine the range Initial velocity (u) = 20 m/sAngle of projection (θ) = 60 °Acceleration due to gravity (g) = 9.8 m/s²Range (R) = ?R = u²Sine(2θ) / g
R = 20² × Sine (2×60) / 9.8
R = 400 × Sine 120 / 9.8
R = 35.3 m
Since the distance travelled by the ball is 35.3 m and the goal post is situated 47 yard (43 m) away.
Thus, we can conclude that the goal kicker did not make the goal as the ball did not get to the post which is 47 yard (43 m)
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2) A skier stands at rest and begins to ski downhill with an acceleration of 3.0 m/s² {downhill). What is
her displacement after 15.0 seconds?
Answer:
337.5m
Explanation:
Kinematics
Under constant acceleration, the kinematic equation holds:
[tex]s=\frac{1}{2}at^2+v_ot+s_o[/tex], where "s" is the position at time "t", "a" is the constant acceleration, "[tex]v_o[/tex]" is the initial velocity, and [tex]s_o[/tex] is the initial position.
Defining Displacement
Displacement is the difference in positions: [tex]s-s_o[/tex] or [tex]\Delta s[/tex]
[tex]s=\frac{1}{2}at^2+v_ot+s_o[/tex]
[tex]s-s_o=\frac{1}{2}at^2+v_ot[/tex]
[tex]\Delta s=\frac{1}{2}at^2+v_ot[/tex]
Using known information
Given that the initial velocity is zero ("skier stands at rest"), and zero times anything is zero, and zero plus anything remains unchanged, the equation simplifies further to the following:
[tex]\Delta s=\frac{1}{2}at^2+v_ot[/tex]
[tex]\Delta s=\frac{1}{2}at^2+(0)*t[/tex]
[tex]\Delta s=\frac{1}{2}at^2+0[/tex]
[tex]\Delta s=\frac{1}{2}at^2[/tex]
So, to find the displacement after 15 seconds, with a constant acceleration of 3.0 m/s², substitute the known values, and simplify:
[tex]\Delta s=\frac{1}{2}at^2[/tex]
[tex]\Delta s=\frac{1}{2}(3.0[\frac{m}{s^2}])(15.0[s])^2[/tex]
[tex]\Delta s=337.5[m][/tex]
