According to Law of conservation of energy,
"Energy can neither be created , nor be destroyed . I t can only be changed from one form to another."
Hence it clearly states that energy cannot be destroyed and hence energy is transformed from one form to another.
It is due to this very reason that devices are able to transform cell's chemical energy in torches to light energy .
Even the loudspeakers, earphones are able to convert electrical energy into sound energy by consuming electrical energy and converting it to various forms
Thus these devices are possible due to the law of conservation of energy.
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A person is dragging a crate over a shag carpet with a push force of 10N. The shag rug creates a friction force of 5N. The mass of the crate is 5 k
g. Calculate the acceleration of the crate?
(Just enter the numbers, no
The acceleration of the crate after the frictional force is overcame is determined as 1 m/s².
What is acceleration?Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity with time.
The acceleration of the crate is calculated from the net force acting on the crate as shown below;
F(net) = applied force - frictional force
F(net) = 10 N - 5N
F(net) = 5 N
Apply Newton's second law of motion to calculate the acceleration of the crate.
F(net) = ma
where;
m is mass of the cratea is acceleration of the cratea = F(net) / m
a = 5/5
a = 1 m/s²
Thus, the acceleration of the crate after the frictional force is overcame is determined as 1 m/s².
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Marking brainliest for the right awnser
Answer:
It's the last one- Finley > Xander > Max
Explanation:
You just divided the velocity by the time
A 50N force is applied to the free end of a spiral spring of force constant 100N/m. Calculate the work done by the force to stretch the spiral spring.
Explanation:
I solved it in the picture but I'm not a hundred percent sure
1. Do stars going supernova have any impact on
allowing life to exist? Why?
Yes, the stars going supernova will have impact on allowing life to exist in nearby planets.
When a star goes supernova, a large amount of radiation is emitted. So, if a nearby planet inhabiting life has a ozone layer, it will be depleted. This results in increased harmful radiation levels on the ground. There will be mutations in organisms that can survive the radiations. Those that are not strong will die.
A supernova is the explosion of a star. This phenomenon happens when a star's nuclear fuel in its core runs out. As a result the pressure created by the burning in its core becomes completely null. Thus the gravity is only force acting, so the star collapses on itself emitting huge quantities of light and harmful radiation.
Therefore, the stars going supernova will have impact on allowing life to exist in nearby planets.
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An Alaskan rescue plane traveling 45 m/s
drops a package of emergency rations from
a height of 110 m to a stranded party of
explorers.
margolalaraq
The acceleration of gravity is 9.8 m/s².
Where does the package strike the ground
relative to the point directly below where it
was released?
Answer in units of m.
The package strike the ground relative to the point directly below it was released at 213.3m.
Equation:Given values,
Velocity of plane 45 m/s
Acceleration due to gravity 9.8 m/s²
horizontal component of plane velocity is
ux = 45 m/s
Vertical component is zero
In the same way
ay = - 9.8 m/s²
ax = .0 m/s^2
Motion in y direction = -110 m
From equation of motion time of flight is
d = u x t + 1/2 at²
where,
d is distance
u is velocity initial
a is acceleration
t is time
So, putting values
-110 = 0 + 1/2 (-9.8)t²
-110 = -4.9t²
t² = 110 / -4.9
t² = 22.45
t = √22.45
t = 4.74
Motion in x direction,
d = u x t + 1/2 at²
d = ( 45 x 4.74) + 1/2 (0) 4.74²
d = 213.3 + 0
d = 213.3m
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The "Screaming Swing" is a carnival ride that is - not surprisingly - a giant swing. It's actually two swings moving in opposite directions. At the bottom of its arc, a rider in one swing is moving at 34 m/s with respect to the ground in a 46- m -diameter circle. The rider in the other swing is moving in a similar circle at the same speed, but in the exact opposite direction. What is the acceleration, in m/s2 , that riders experience?
The acceleration, in m/s² , that riders experience is 50.3 m/s²
What is the acceleration, in m/s² , that riders experience?Since the riders move in a circle, they undergo circular motion and will have a centripetal acceleration.
So, the centripetal acceleration, is given by a = v²/r where
v = speed of rider andr = radius of circleGiven that a rider in one swing is moving at 34 m/s with respect to the ground in a 46- m -diameter circle. We have that
v = speed of rider = 34 m/s and r = radius of circle = 46/2 = 23 mSo, substituting the values of the variables into the equation for the acceleration, we have
a = v²/r
a = (34 m/s)²/23 m
a = 1156 m²/s²/23 m
a = 50.26 m/s²
a ≅ 50.3 m/s²
So, the acceleration, in m/s² , that riders experience is 50.3 m/s²
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Ken is a 78-year-old gentleman with increasing difficulty breathing over the last three months. He also complains of chest pain when he does small amounts of exercise. His doctor is concerned that this may be caused by coronary artery disease. The doctor performs a physical exam showing normal temperature, heart rate, respiratory rate, and a heart and lung exam. Further cardiac testing shows that he does have blockages of the arteries in his heart. He is then placed on medication to control symptoms and help him improve his long-term situation, which is described as fair.
9. Which of the above are symptoms?
10. Which of the above are signs?
11. What is the diagnosis?
12. Is this an acute or chronic condition?
13. What could be the etiology?
14. What is the prognosis?
The symptoms include chest pain and difficulty to breath; signs are heart/respiratory rate and lung assessment, diagnosis > CAD (treatable disease); chronic condition; etiology > plaque buildup.
What is coronary artery disease?Coronary artery disease (CAD) is a disease caused by the plaque buildup in artery heart walls. This disease is mainly due to a sedentary lifestyle and inadequate nutritional habits such as for example, excessive consumption of saturated fats.
In conclusion, the symptoms of Ken include chest pain and difficulty to breath; signs are heart/respiratory rate and lung assessment, diagnosis > coronary artery disease (treatable disease); chronic condition, etiology > plaque buildup in the walls of the arteries.
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You pull a rope to the left with 300 N and a friend pulls the rope to the right with 425 N. Draw a vector for the two forces acting on the rope
The total forces acting on the rope is 125 N towards the right side.
125 N of total forces are being applied to the rope's right side.
How are two forces operating on the rope represented by a vector?300 N of force as well as additional forces are applied in the proper direction.These forces are 425 N and are bigger than the starting force. The necessary vector diagram is shown here.The two forces' large, calm vector diagram is seen here. We must now determine the product of these two forces for part B.These two forces combine to produce a vector that is equal to the bigger force in the right direction less the smaller force in the left.Due to the smaller forces moving left. Therefore, since positive (425 -300) N is equivalent to 125 N, we have determined that the direction is correct.These two forces add up to 125 newtons moving in the proper direction.We must determine the size of the resultant, which is the magnitude of 125 newtons, for part C.The rightward movement of the outcome entities. The response to part C is this.To construct the resultant vector for party in this manner, we must widen it. The rope is this.Small and pointing in the right direction by 125 N, the outcome vector is small.To know more about vector visit:
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3. What would happen if two black holes were to
collide?
Answer:
What would happen is that once the two collide they will make a bigger black hole.
Explanation:
A flowerpot falls from a window sill 36.5 m
above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? Choose upwards to be
the positive y direction. The acceleration of
gravity is 9.81 m/s
2
Answer in units of m/s.
When a flowerpot falls from a window sill 36.5 m
above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.
From Newton's third equation of motion,
v^2 = u^2 + 2gh
where,
h is the height of the object or body from ground
u is the initial velocity of the body or object
v is the final velocity of the body or object
g is the acceleration due to gravity
Now, as we know that
Flowerpot is at rest. So, u = 0
g = 9.81m/s^2
h = 36.5m
By substituting all the values, we get
v^2 = 2 × 9.81 × 36.5
= 716.13
v = 26.7m/s
Thus, we concluded that when a flowerpot falls from a window sill 36.5 m
above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.
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given that vector c=a+b, indicate the conditions that A and B have to meet in order for c to have the largest and smallest possible magnitudes
A Vector is a quantity which has both magnitude as well as direction.
vectors follow parallelogram law of addition and uses cosine of the angle between the vectors.
The addition of two vectors, i.e. c, is given by the formula
c=[tex]\sqrt{a^2+b^2+2abcos\alpha }[/tex]
where [tex]\alpha[/tex] is the angle between the vectors
now we know that maximum value of cos[tex]\alpha[/tex] can be is 1
and minimum value of cos [tex]\alpha[/tex] can be-1
now the maximum value cos[tex]\alpha[/tex] is 1 at the angle of π/2
and the minimum value of cosα is -1 is at the angle of -π
Therefore, A and B should have 0 degree between them and in the same direction to have the maximum value
there fore they should be in same direction and 0 degree meaning they should be on same line
A and B will have minimum value when the angle is 180 degree which means they should be on same line and be inn opposite direction to each other.
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Which type of circuit has
more than one path for
electrons to flow?
A. Parallel
B. Series
C. Neither
Answer:
A. Parallel connection
Answer:
Parallel circuit to be exact
A car with an initial speed of 22.1 km/h accelerates at a uniform rate of 0.84 m/s2 for 4.4 s. Find the final speed of the car. Answer in units of m/s. Find the displacement of the car after that time. Answer in units of km.
(Desperately need help with Part 2)
Answer:
Final speed of car = 9.834 m/s
Displacement = 0.035 km
Explanation:
Part 1
Final velocity, v of an object moving with an acceleration a m/s² for t seconds and an initial velocity u m/s is given by the formula
v = u + at m/s
[tex]\textrm{Initial velocity } u = 22.1 km/h\\\\\textrm{Convert this to m/s:}\\\\\textrm{1 km/h = 1000m/3600 s}\\\\ 22.1 km/h = 22.1 x 1000/3600 = 6.139 m/s\\\\\boxed{\textrm{Final velocity } v = u + at = 6.138 + 0.84 x 4.4 = 9.834 m/s}[/tex]
Displacement s in m for a constant acceleration of a m/s² for a time t seconds is given by the formula:
[tex]x = ut+\dfrac{1}{2}at^2[/tex]
where u is initial velocity
Plugging in the values we get
[tex]s = 6.139\cdot 4.4 + \dfrac{1}{2}\cdot0.84\cdot (4.4)^2 = 35.143 \;\mathrm {meters}[/tex]
35.143 meters = 35.143/1000 = 0.035 km
Answer:
1) 9.83 m/s (2 d.p.)
2) 0.04 km (2 d.p.)
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Part 1Given:
u = 22.1 km/ha = 0.84 m/s²t = 4.4 sConvert km/h into m/s by dividing by 3.6:
[tex]\implies \sf 22.1\;km/h=\dfrac{22.1}{3.6}\;m/s[/tex]
Substitute the given values into the formula and solve for v:
[tex]\begin{aligned}v&=u+at\\\implies v & = \dfrac{22.1}{3.6}+0.84(4.4)\\v & = 6.1388...+3.696\\v & = 9.834888...\\v & = 9.83 \sf \;m/s\;(2\:d.p.)\end{aligned}[/tex]
Therefore, the final speed of the car was 9.83 m/s (2 d.p.).
Part 2Substitute the given values into the formula and solve for s, remembering to use the initial velocity in m/s:
[tex]\begin{aligned}s & = ut+\dfrac{1}{2}at^2\\\implies s &=\dfrac{22.1}{3.6}(4.4)+\dfrac{1}{2}(0.84)(4.4)^2\\s &=27.0111...+8.1312\\s &=35.1423111...\sf m\end{aligned}[/tex]
Convert meters into kilometers by dividing by 1000:
[tex]\implies \dfrac{35.1423111...}{1000}=0.0351423111...=0.04 \sf \; km\;(2\:d.p.)[/tex]
Therefore, the displacement of the car after 4.4 s was 0.04 km (2 d.p.).
Suppose an electron in some atom absorbs energy and transitions from level 1 up to level 4. Which of the following is a true statement regarding the electron transitions back down to level 1?
a. It must transition from 4 to 3, then 3 to 2, then 2 to 1. All downward transitions are one step at a time.
b. 4 to 2, followed by 2 to 1, is possible. Downward transitions can be any number of levels.
c. It can go from 4 to 1 only. The downward transition must match the upward one.
Suppose you landed on an unknown planet whose mass is 10x that of the Earth and whose radius is 3x that of the Earth. How much would you weigh on this new planet?
Give your answer in what fraction or multiple of your earthly weight.
Mass on the planet would be 10/3 times the mass on Earth weigh on this new planet.
How do you define mass?A quantitative measure of the fundamental characteristic of all matter, inertia. In essence, it's the resistance of a mass of matter to changing its direction or speed in reaction to the force applied to it. The much more weight a body has, the less change an applied force produces.
Briefing:Let the mass of Earth = Me
Let the radius of Earth = Re
Mass of the planet, Mp = 10Me
Radius of the planet, Rp = 3Re
Weight on other planet, W = ?
Weight on planets is determined by the gravitational force
Gravitational force, F = GMm/r²
where, G = gravitational constant
M = Mass of the planet
m = our mass
r = radius of the planet
Gravitational force on Earth:
F = G X Me X ma/ Re².....eq (1) (ma = mass on earth)
Gravitational force on planet :
F = G X 10Me X mₓ/ (3Re)²....eq (2) (mx = mass on other planet)
Dividing both the equations, we get
mx = 10/3ma
Therefore, mass on the planet would be 10/3 times the mass on Earth.
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This huge rocket was as tall as a football field is long. Its mass is 3,038,500 kg. If this rocket accelerated from rest at 5 g’s, How much force was used to lift it off the ground?
The force used to lift the huge rocket off the ground is 148,886,500 N.
Force used to lift the huge rocket off the ground
The force used to lift the huge rocket off the ground is calculated as follows;
F = ma
where;
m is mass of the rocketa is the acceleration of the rocketa = 5g
F = m(5g)
F = ( 3,038,500 kg) x (5 x 9.8 m/s²)
F = 148,886,500 N
Thus, the force used to lift the huge rocket off the ground is 148,886,500 N.
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An 8.50 m long ladder leans against the side of a building. The ladder is initially inclined at an angle of 47.0° to the horizontal. The base of the ladder is then moved 0.82 m closer to the building. At what angle is the ladder now inclined with respect to the horizonta
The angle of the ladder inclined with respect to the horizontal after being moved a distance of 0.82 m closer to the building is 53.84°
cos θ = Adjacent side / Hypotenuse
θ[tex]_{1}[/tex] = 47°
Hypotenuse = Length of ladder = 8.5 m
cos 47° = Adjacent side / 8.5
Adjacent side = Initial distance of base of ladder from the building = 5.8 m
Adjacent side 2 = Final distance of base of ladder from the building
Adjacent side 2 = 5.8 - 0.82 = 4.98 m
cos θ[tex]_{2}[/tex] = Adjacent side 2 / Hypotenuse
cos θ[tex]_{2}[/tex] = 4.98 / 8.5 = 0.59
θ[tex]_{2}[/tex] = [tex]cos^{-1}[/tex] ( 0.59 )
θ[tex]_{2}[/tex] = 53.84°
The formula used above is one of trigonometric ratios. Trigonometric ratios can used only in a right angled triangle where one of the angles in at 90 degrees and the other two angles are less than 90 degrees.
Therefore, the angle of the ladder inclined with respect to the horizontal after being moved is 53.84°
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A bear throws a salmon at 2 m/s horizontally off a 15-meter high cliff in order to feed its baby cub on the ground. Where should the baby cub be located, with respect to the edge of the cliff, in order to catch the salmon?
The location of the baby cub with respect to the cliff would be 6.11 meters.
What is a projectile motion?
It can be defined as the motion of any object or body when thrown from the earth's surface and follows any curved path under the effect of the gravitational force of the earth.
As given in the problem A bear throws a salmon at 2 m/s horizontally off a 15-meter high cliff in order to feed its baby cub on the ground.
Let us first calculate the time to fall down on the ground,
s = ut + 0.5at²
15 = 0 + 0.5×9.81×t²
=3.058 second
The location of the baby cub with respect to the cliff = 2×3.058 second
=6.11 meters
Thus, the location of the baby cub with respect to the cliff would be 6.11 meters.
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The thermal energy that causes the ice to melt is transferred from the lemonade as it cools. The loss of this thermal energy causes the temperature of the 300 g of the lemonade to fall by 19 °C. Calculate the specific heat capacity of the lemonade.
According to the give value of the mass of lemonade and change in the temperature, the specific heat capacity of the lemonade is 3.81 J/kg/k.
The formula for the specific heat capacity (C) = Q/ m × ΔT
Q is energy added and the value, which is 334J
m is the mass of the lemonade, which is 300g = 0.3 kg
Δ T is the change in temperature, which is 19°C =(273+19)= 292 K
So, C = 334/ 0.3 × 292
= 3.81 J/kg/k
So the specific heat capacity of the lemonade is 3.81 J/kg/k.
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Lab: Newton's Second Law
40 points!!!!!!!!
The acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.
Explanation:Newton's Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass (object). Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass. Your leg muscles pushing on the pedals of your bicycle is the force. Newton's second law is a quantitative description of the changes that a force can produce in the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
In 1954 the English runner Roger Bannister broke the four-minute barrier for the mile with a time of 3:59.4 s (3 min and 59.4 s). In 1999 the Moroccan runner Hicham el-Guerrouj set a record of 3:43.13 s for the mile. If these two runners had run in the same race, each running the entire race at the average speed that earned him a place in the record books, el-Guerrouj would have won. By how many meters?
Answer:
Bannister = 3:59.4 sec = 239.4 sec
Guerruoj = 3:43.13 = 223.13 sec
1 mi = 5280 ft
G = 5280 / 223.13 = 23.66 ft/sec
B = 5280 / 239.4 = 22.06 ft/sec
In 223.13 sec B runs 223.13 * 22.06 = 4922 ft
G Wins by 358 ft = 119.3 yds = 109.1 meters
Choose the correct statement about precession of the Earth's axis.
A. Precession of the Earth's axis of rotation is caused by changes in the shape of the Earth's orbit due only to the gravitational pull of the Sun.
B. One complete cycle of the Earth's pole star is not affected by precession.
C. One cycle of the precessional motion of the North Celestial Pole takes about 26,000 years.
D. Precession is the motion of Earth along its orbital path.
The precession is the motion of Earth along its orbital path.
What is earth's axis of rotation?
Earth's rotation or Earth's spin is the rotation of planet Earth around its own axis.
What is precession of the Earth's axis?Precession of the Earth's axis consists of a cyclic wobbling in the orientation of Earth's axis of rotation with a period of 25,772 years.
The precession of the Earth's axis wobble is due to tidal forces caused by the gravitational influences of the Sun and Moon.
Thus, precession is the motion of Earth along its orbital path.
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A driver travels +2170 m in 35.0
S. If the driver's initial velocity is +62.0 m/s, what is her acceleration?
HELP PLEASE
The acceleration of driver with given values is - 1.771 m/s².
Equation :To know acceleration used formula is the rate of change of the velocity of an object with respect to time that is,
a = dv / dt
Where,
dv is the small change in velocity
dt is change in time of an object
Given,
The distance traveled by the driver is +2170 m
The time taken by the driver is 35. 0 s
The initial velocity of driver is + 62.0 m/s
Therefore , to get the acceleration of the driver with the equation of motion
v = u + at
Here v is the final velocity which is taken zero
Then by putting the values in the above equation,
0 = (+62. o m/s) + (a) 35.0s
a = - (+62. o m/s) / ( 35.0s)
a = - 1.771 m/s²
The negative sign of acceleration shows that, the driver is slowing then acceleration is in the opposite as the velocity.
So, the acceleration
a = -1.771 m/s².
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Consider the case of an object moving with
constant acceleration a along a straight line.
If we plot v(t) versus t, we find that v(t) plots
as a straight line with some slope.
What is the physical meaning of that slope?
The straight line in the velocity versus time graph has a physical significance as it depicts constant acceleration of the motion.
What is acceleration?Acceleration is a physical quantity which is defined as the change of velocity per unit time it is a vector quantity and therefore can be both positive and negative.
What is velocity versus time graph?Velocity versus time graph is the depiction of emotion in which the y-axis represents the velocity of the motion and the x-axis represents the time the graph can either be a positive state line or a curve depending on the acceleration of the motion.
According to the question the velocity versus time graph in our case is a straight line.
A straight line in a velocity versus time graph means that motion has a constant acceleration.
The following conclusion can also be reached from the use of differential calculus as we differentiate velocity with respect to time we get a new physical quantity that is known as acceleration.
On differentiating velocity with respect to time we will get a new value that will represent the change in velocity per unit time and since from the definition of acceleration we know that acceleration is change in velocity per unit time therefore we can conclude that the straight line in the velocity time graph depicts constant acceleration.
Therefore, The straight line in the velocity versus time graph has a physical significance as it depicts constant acceleration of the motion.
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.A 2.0-L balloon at room temperature (20.0°C) is placed in a freezer at -18°C. What is the volume of the balloon after it cools in the freezer?
Answer step by.
if a 2.0-L balloon at room temperature (20.0°C) is placed in a freezer at -18°C, then the volume of the balloon would be 1.74 liters.
What is an ideal gas?It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one.
PV = nRT
By assuming the pressure constant the volume would be directly proportional to the temperature changes from 293 kelvin to 255 kelvin,
V₁ /V₂ = T₁/ T₂
1000 litre = 1 m³
1 litre = 1/1000 m³
2 litre = 2/1000 m³
=0.002 m³
0.002 / V₂ = 293 / 255
V₂ = 0.001740 m³
The final volume of the balloon =1.74 liters.
Thus, the volume of the balloon would be 1.74 liters.
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A 20 km long, 8 m wide, two-lane highway is to be paved with a 4 cm thick
layer of asphalt. A fleet of three dump trucks is to be employed, each with
an empty mass of 20 metric tons and a carrying capacity of 20 m3 asphalt
with a density of 0.72 g/cm3 will be used. Determine the following:
a. the total volume of asphalt needed
b. the number of dump truck loads required
c. the gross mass of each truck
(a) The volume of asphalt needed is 6400 m³.
(b) The number of dump truck loads required is 320.
(c) The gross mass of each truck is 34400 kg.
The dimension of the two-lane highway 20 km long, 8 m wide, and 4 cm thick.
The mass of a dump truck is 20 metric tons, and carrying capacity is 20 m³ and the density is 0.72 g/cm³.
The two-lane highway:
length, l = 20 km = 20 × 10³ m
breadth, b = 8 m
Thickness, h = 4 cm = 4 × 10⁻² m
(a) The volume of the asphalt will be:
V = l × b × h
V = 20 × 10³ × 8 × 4 × 10⁻² m³
V = 64 × 10² m³
V = 6400 m³
V = 6400 × 10⁶ cm³
(b) The carrying capacity of 20 m³ asphalt.
Therefore, the number of truckloads required will be:
= 6400 m³ / 20 m³
= 320
(c) Now,
Density, d = 0.72 g/cm³ = 720 kg/m³
The empty mass is 20 metric tons which is equal to 20 ×10³ kg.
Therefore, the gross mass of each truck will be
m = 20 ×10³ kg + 720 kg/m³ × 20 m³
m = 20000 kg + 14400 kg
m = 34400 kg
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launched at ground level with an initial speed of 41 m/s, at an angle of 29° above the horizontal. It strikes a target above the ground 2.3 seconds
What is the vertical distance, in meters, from where the projectile was launched to where it hits the target?
The horizontal distance is 82.455m and vertical distance is 19.734m
Let us first find the x and y components of velocity
The velocity is given to be 41m/s
the angle of projectile is given to be 29 degree
The x component of velocity = Vx =v cosα =41 x 0.8746 =35.85 m/s
The y component of velocity= Vy= v sinα=41 x 0.484 =19.85 m/s
The horizontal displacement x= Vxt = 35.85 x 2.3 =82.455 m
To solve for vertical distance y = Vyt+1.2at^2
y = 19.85 x 2.3 + 1/2 x -9.8 m/s^2 x 2.3
= 19.734m
Hence, the horizontal distance is 82.455m and vertical distance is 19.734m
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What is the kinetic energy of a 29 kg dog that is running at a speed of 8.5 m/s (about 17 mi/h)?
The kinetic energy of of given data is K.E. = 1,047.62 J
Equation:To calculate kinetic energy using the formula,
K.E. = 1/2 m v²
where,
K.E is kinetic energy
m is mass
v is velocity
So, Putting values,
K.E. = 1/2 x 29 x (8.5m/s)²
K.E. = 1,047.62 J
What is kinetic energy in simple words?The energy an object has as a consequence of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the object, which then moves at a new, constant speed.
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What is the magnitude of the resultant of a 61m north and 21m south vector?
Answer:
1281
Explanation:
what is the magnitude of the resultant of a 61m north and 21m south vector
A boy leaves his home at 5:00 pm, drives around the city a distance of 24 miles, and returns home at 5:30 pm. His average velocity is???
We can see that the speed of the car is obtained as 12 miles per hour.
What is speed?The term speed is the ratio of the distance covered to the time taken. We can see that the distance that have been covered by the boy is 24 miles. The total time that have been taken to cover this distance is 30 mins or 0.5 hours.
We now come up with the following;
Distance = 24 miles
time = 0.5 hours
We now want to compute the speed of the boy in miles per hours so we have;
Speed = 24 miles / 0.5 hours = 12 miles per hour
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