Balanced forces are equal in size and opposite in direction, whereas unbalanced forces are not equal in magnitude.
When forces are balanced, there's no alter in motion. In one of your circumstances within the last section, you pushed or pulled on an object from opposite directions but with the same force. To have unbalanced forces implies that the force applied in one direction is greater than the force applied within the opposite direction. When unbalanced forces are acting on an object, there's an alteration in speed and/or direction. By applying an unequal force, you'll be able to alter the motion of an object. Unbalanced forces can make an object at rest begin moving, make a moving object halt, or alter the direction and speed of the object.
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the output of the supply must be electrically isolated from the source and must contain some type of switching converter. the system is to use a feedback control to maintain proper output voltage throughout the full range of input voltages and frequencies.
The supply's output must have some sort of switching converter and must be electrically insulated from the source. Throughout the whole range of input voltages and frequencies, the system is to apply a feedback control to ensure proper output voltage.
Voltage, also referred to as electric tension, electric pressure, or (electric) potential difference, is the difference in electric potential between two places. It is equivalent to the labor required to transfer a test charge between two places in a static electric field. The derived unit for voltage in the metric system is referred to as a volt. One volt equals one joule (of work) for one coulomb, which is how to work per unit charge is defined in SI units (of charge). Power and current were employed in the earlier SI definition for the volt; starting in 1990, the quantum Hall and Josephson effect was applied; and most recently (as of 2019), fundamental physical constants were added to the definitions of all SI units and their derivative units.
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A spring has an unstretched length of 10 cm. It exerts a restoring force F when stretched to a length of 11 cm.
a. For what length of the spring is its restoring force 3F?
b. At what compressed length is the restoring force 2F
a) The length for 3F force is : 13 cm
b) The length for 2F force is : 8 cm
The required length and compressed length of the spring at the given force values are 13 cm and 8 cm respectively.
Explanation:
F = ke
k = spring constant ;
e = extension;
e = (Final length - Initial length)
Initial length, l = 10
Final length = L1 = 11
F = k(11 - 10)
F = k;
Length for a restoring force of 3F ;
3F = k(Final length - Initial length)
k = F
3F = F(L1 - 10)
3F = - 10F + F(L1)
F(L1) = 3F + 10F
F(L1) = 13F
L1 = 13
Hence, required length ls 13 cm
B.)
Let compressed length = c
2F = F(initial length - compressed length)
2F = F(10 - c)
2F = 10F - F(c)
F(c) = 10F - 2F
F(c) = 8F
c = 8F / F
c = 8 cm
Therefore, the required compressed length ls 8 cm
Spring:
A spring is an elastic body that stores mechanical energy. Coil springs are often used in daily life, but there are many different types of springs. Modern quills are usually made of spring steel, but non-metallic items like bows are also quills.
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Classify the characteristics as describing the atmosphere of Saturn, the atmosphere of Jupiter, or the atmosphere of both. Saturn's atmosphere Jupiter's atmosphere Both Answer Bank oval storm system proportionally less bellum differential rotation fewest obvious features invisible light Answer Bank oval storm systems proportionally less helium differential rotation fewest obvious features in visible light composed of mostly hydrogen and helium most colorful in visible light thinner atmosphere Image credit: NASA
Saturn's Atmosphere :-Proportionally less helium, Thinner Atmosphere, Most colorful in visible light, Composed of hydrogen and helium.
Jupiter's Atmosphere :- Oval stroma systems, Differential Rotation, Fewer observers features in light.
Electromagnetic radiation that the human eye can see is referred to as light or visible light. Typically, visible light is characterized as having wavelengths in the 400–700 nanometer (nm) range, which corresponds to frequencies of 750–420 terahertz, lying between the infrared (with longer wavelengths) and the ultraviolet (with shorter wavelengths) (with shorter wavelengths).
In physics, the term visible light" can more widely be used to refer to electromagnetic radiation of any wavelength, whether or not it is visible.
This definition of light includes gamma rays, X-rays, microwaves, and radio waves. The main characteristics of light include intensity, polarization, frequency or wavelength spectrum, and propagation direction. One of nature's basic constants is the speed of light in a vacuum, which is 299 792 458 meters per second (m/s). Visible light travels through space by, like all forms of electromagnetic energy,
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In photography; exposure is the amount of light allowed to strike the film_ Exposure can be adjusted by the number of stops used to take a photograph: The change in the number of stops n needed is related to the change in exposure c by n 10g2 A. How many stops would a photographer use to triple the exposure? B. How many stops would a photographer use to get 5 the exposure?
n = number of stops
c = change in exposure
n = log₂ C ..........(1)
A. Let n be no of stops needed to triple the exposure then n₁ = log(30) = n, log, 3+ log, C ..............(2)
We see using (1) in (2) n₁ = n + log 3 = n+1.5850
Thus we need to increase no. of stops by 1.585 ≈ 1.6.
B. Similarly to get exposure, changing c by c/5
n₁ = log₂ (45) = n₁ = log₂c - log₂5
n₁ = n - log₂5 = n₁ -2.3219
One needs to decrease the no. of stops by 2.3219.
Aperture is one of three camera settings that control the exposure of your image. These settings are collectively known as the exposure triangle and consist of shutter speed aperture and ISO. The aperture controls exposure by increasing or decreasing the relative amount of light entering the camera lens.
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A pressure vessel support bracket is to be designed so that it can withstand a tensile loading cycle of 0-500 MN/m2 once every day for 25 years. Which of the following steels would have the greater tolerance to intrinsic defects in this application: (i) a maraging steel (Ke-82 MNm-, C= 0.15 × 10-11, m-41), or (ii) a medium-strength steel (Kic 50 MN m1, C0.24x 10-", m 3.3)? For the loading situation a geometry factor of 1.12 may be assumed.
Ao for a maraging steel (82 M Nm-, C= 0.15 10-11, m-41) is equal to 58.2*10^-6m, and for a medium-strength steel, it is 40.6*10^-6m (50 MN m1, C0.24x 10-", m 3.3). The second case can be more tolerant.
Ultra-high-strength steel alloys, or maraging steels, are a unique class of low-carbon steel that have comparable ductility while being stronger and tougher than most other steels. A structure's capacity to safely withstand until repair can be made is known as damage tolerance. Based on the presumption that defects can exist in any building and that these problems spread with use, the approach to engineering design that takes damage tolerance into account.
9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - A)
Ao = 58.2*10^-6m
9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - Ao)
comparable to case two
Ao = 40.6*10^-6m
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a car is traveling at 16 m/s . part a how fast would the car need to go to double its kinetic energy? express your answer with the appropriate units.
Answer: 22.63 m/s
Explanation:
Not sure if this is the right answer.
[tex]\frac{1}{2} m(v)^2=2(\frac{1}{2} m(16)^2 )[/tex]
[tex]\frac{1}{2} (v)^2=(16)^2[/tex]
[tex]v = 22.63 \frac{m}{s}[/tex]
if you know the car's potential energy and its kinetic energy, you can determine its mechanical energy through the formula .
The formula to calculate mechanical energy is ME=PE+KE. If you are aware of the kinetic and potential energies of the vehicle.
Simply put, what is kinetic energy?The energy an entity has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.
What makes kinetic energy so crucial?The capacity to perform work is arguably the most significant characteristic of kinetic energy. Force flowing on an object while it is moving is referred to as work. Energy and work are interchangeable because of their tight relationship.
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A block of mass m pulled with constant velocity over a floor by a force T inclined at an angle theta with the floor. The coefficient of friction between the block and the floor in mu. It is a box on floor drawn by a cord half way down fron edge at an angle of about 30 degrees from horizontal. No actual dimensions. The magnitude of the vertical component of the force exerted on the block by the floor is:a. mgb. mg-T cos thetac. mg+T cos thetad. mg-T sin thetae. T sin theta
The floor's force on the block, measured in terms of its vertical component, is expressed as follows: mg- t sin theta
What is the friction coefficient?The resistive friction force (Fr) multiplied by the normal or horizontal force (N) forcing the objects together yields the coefficient of friction (fr), which is a numerical value. It can be represented by the equation fr = Fr/N.
What is a force?A push or pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on each of the things. Newton(N) F=ma stands for the Si system of force.
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Constants A film contains a single thin slit of width a. When monochromatic light passes through this slit, the first two dark fringes on either side of the center on a distant screen are a distance x apart. Part A If you increase the width of the slit, these two dark fringes will move closer together. move farther apart. remain the same distance apart.
These two dark fringes will travel in closer proximity if the slit's width is increased for a Constants A film has just one a-width tiny slit. When this slit is open, monochromatic light enters.
The relationship between the slit width and the distance from the centre maximum to y is (m*(lamda)*D/a, where D is the separation between the slit and the screen and lamda is the wavelength of light, meaning that y is inversely proportional to 1/a. Therefore, monochromatic light is simply light of a single colour. It denotes light that has only one wavelength in scientific terminology. The term "light" refers to the visible and near-visible components of electromagnetic radiation. It is made up of propagating, perpendicularly oscillating sinusoidal waves in the magnetic and electric fields.
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What forces are acting on an airplane as it flies at a constant velocity through the air?; When the plane is flying at a constant height which two forces must be balanced?; Which two forces must be balanced if the airplane is to fly at a constant forward velocity?; Is an airplane cruising in level flight a balanced or unbalanced force?
Thrust, drag, lift, and weight is the forces that act on all aircraft in flight.
Thrust is the forward force produced by the propulsion unit/propeller or rotor.
Drag is the backward force caused by the disturbance of airflow by the wing, rotor, fuselage, and other objects.
When the plane is flying at a constant height, the force of thrust must equal the opposite force of drag, then only the airplane can experience uniform motion in one direction.
All four forces act on an airplane must equate to each other for an airplane to fly straight and level at a constant speed, the lift it creates balances its weight, and the thrust it creates balances its drag.
An unbalanced force changes the equilibrium state of a body. As with an aircraft cruising in level flight, the weight of the aircraft will equally lift and thrust will equal drag. So, the plane experiences a balanced force.
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in today's demonstration, a nonmoving ball placed at the top of the ramp is an example of question 5 options: chemical energy gravitational potential energy elastic potential energy kinetic energy
Gravitational Potential Energy is demonstrated by a stationary ball put at the top of a ramp. The energy that a body has or acquires is known as gravitational potential energy.
because when something is in a gravitational field, it changes position. It is, to put it simply, energy that results from gravitational force or gravity. Taken two pencils is the most typical illustration. If one pencil is set down on a table and the other is raised above it, the pencil raised will have more gravitational potential energy than the pencil set down on the table. The equation U = mgh is used to compute it. The mass, m, is expressed in kilograms.
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a 5.0 cm -thick layer of oil is sandwiched between a 2.0 cm -thick sheet of glass and a 2.4 cm -thick sheet of polystyrene plastic.
The time taken should be 0.399 ns.
What is the refractive index?
The refractive index is the measure of bending of a light ray when passing from one medium to another. It can also be defined as the ratio of the velocity of a light ray in an empty space to the velocity of light in a substance, n = c/v.
We know that
Time taken = Thickness of the layer / speed of the light
Also,
v = speed of sound/refractive index.
Now
T1 = 0.05*1.46/3*10^8 = 2.43*10^-10 s
t2 = 0.01*1.5/3*10^8 = 5*10^-11 s
t3 = 0.02*1.59/3*10^8 = 1.06*10^-10 s
So,
total time is
= 2.43*10^-10 + 5*10^-11 + 1.06*10^-10 = 0.399*10^-9 s
= 0.399 ns
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You want to siphon rainwater and melted snow from the cover of an above-ground swimming pool. The cover is 2.1 m above the ground. You have a plastic hose of 1.5 cm radius with one end in the water on the pool cover and the other end on the ground.
If you want to empty the pool cover in half the time, how much wider should the hose be?
Answer:
Below
Explanation:
You will need a hose with double the cross sectional area
Area = pi r^2
pi * (1.5)^2 = 2.25 pi
now double it to 4.5 pi and solve for r
4.5 pi = pi r^2
4.5 = r^2 r = 2.12 cm radius
2.12 - 1.5 = the hose radius should be increased .621 cm
this would be .621 * 2 = 1.24 cm wider
a 1.90 kg , horizontal, uniform tray is attached to a vertical ideal spring of force constant 200 n/m and a 300 g metal ball is in the tray. the spring is below the tray, so it can oscillate up-and-down. the tray is then pushed down 16.4 cm below its equilibrium point (call this point a) and released from rest.
(a) How high above point A will the tray be when the metal ball leaves the tray?
(b) How much time elapses between releasing the system at point A and the ball leaving the tray?
(c) How fast is the ball moving just as it leaves the tray?
a)When the metal ball leaves the tray, the tray will be 10.78 cm above point A.
b) The total time between the system being released at point A and the ball leaving the tray is 0.086 seconds.
c) The speed of the ball as it exits the tray is 1.175 m/s.
Given,
Mass of tray , m_t=1.90 kg
spring of force constant, k = 200N/m
mass of the ball, m_b = 300 g
Height below the equilibrium point A = 16.4 cm
a)
The tray's height above point A when the metal ball leaves it- The total mass of the tray and ball is 2.2 kg (1.90kg+0.3 kg). The spring force is equal to the product of the spring constant and displacement.Thus,
f=kx
but we know that, f=mg
equating both the equations
[tex]mg=kx\\\\2.2*9.8=200*x\\\\21.56=200x\\\\x=\frac{21.56}{200}\\\\x=0.1078 m=10.78 cm[/tex]
As a result, the tray is pushed down 17.4 cm below its equilibrium point (point A) and released from rest. Thus, the tray's position above point A is h=16.4+10.78=27.18 cm.
b)
The total amount of time that passes between releasing the system at point A and the ball leaving the tray.
The formula for the simple harmonic function of a spring is as follows:
[tex]y=Acos(\sqrt{\frac{k}{m}}-\phi)[/tex]
Here,
y= displacement = 10.78 cm
A=amplitude i.e 16.4 cm
k= spring constant = 200 N/m
m= total mass = 2.2 kg
and [tex]\phi = 0 \degree[/tex]
[tex]10.78=16.4cos(\sqrt{\frac{200}{2.2}}t-0)\\\\\frac{10.78}{16.4}=cos(\sqrt{90.909}t)\\\\0.657=cos(9.534t)\\\\cos^{-1}(0.657)=9.5434t\\\\0.829=9.543 t\\t=\frac{0.829}{9.543}\\\\t=0.086 s[/tex]
c)
The speed at which the ball moves as it exits the tray
The total mechanical energy for simple harmonic motion of a spring can be given as,Here, take the distance measurements in meters
[tex]\frac{1}{2}mv_y^2+\frac{1}{2}ky^2=\frac{1}{2}kA^2\\\\v_y^2=k\frac{A^2-y^2}{m}\\\\v_y^2=200*\frac{0.164^2-0.1078^2}{2.2}\\\\v_y^2=90.909(0.0268-0.0116)\\\\v_y^2=1.38\\\\v_y=1.175 m/s[/tex]
Thus, the speed of ball is 1.175 m/s
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what is the magnitude of the momentum of a 0.140 kg baseball traveling at 45.0 m/s?; impulse: in a collision between two unequal masses, which mass receives a greater magnitude impulse?; a 0.140 kg baseball traveling 35.0 m/s; a 0.140 kg baseball is dropped and reaches a speed of 1.20 m/s; two ice skaters push off against one another; a 100g ball falls from a window that is 12 m; a rubber ball and a lump of clay
Thus, the baseball's momentum is measured as 6.3kg/m/s (6.3 kg/m/s).
What is the size of the average force the ball applies to the bat?
The average force acting during the bat-ball collision is therefore about two tons, with a peak force of nearly four tons, during the 0.7 millisecond contact time. There's a lot of force there.
What is the connection between collision and momentum?
During collisions between objects, momentum is a relevant concept. The total momentum before a collision between two objects equals the total momentum after the impact (in the absence of external forces). The law of conservation of momentum is this. It holds true in every collision.
What is the system's momentum following the collision?
The total momentum of two objects does not change when they collide. The sum of the individual momenta of the objects, both before and after the collision, is the total momentum. The product of an object's mass and velocity, expressed in kilogram meters per second, determines its momentum.
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three identical blocks, X, Y, and Z, hang up from identical strings, as shown in the figure. which of the following free-body diagrams could represent the forces exerted on block Y?
The free-body diagram that could represent the forces exerted on block Y is upward tension force due to block X and downward tension force due to block block Z and its own weight.
option D is the correct answer.
What is free body diagram?A free-body diagram is a sketch of all the forces acting on the given object with all the surrounding objects stripped away and all of the forces acting on the body shown in their respective direction.
For the three identical blocks, X, Y, and Z, hang up from identical strings, as shown in the figure, the following are the direction of the forces acting on the string.
weight of block X -----> acting downwards
weight of block Y ------> acting downwards
weight of block Z ------> acting downwards
According to Newton's third law of motion, acting and reaction are equal and opposite.
As the weight of the blocks are acting downwards, the tension in the rope supporting the weights will be acting upwards.
The total weights of the = downward force of gravity
The tension in the string = upward tension force
The free body diagram is sketched as;
↑ F (Tension Up)
Ф
↓ ↓ F (Gravity) + F (tension down)
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The goal of behavior modification is to
.repair troubled or broken relationships.
.unearth the origin of maladaptive behavior.
.change clients’ maladaptive or undesirable behaviors.
.modify the clients’ personality structure.
The goal of behavior modification is to change clients' maladaptive or undesirable behaviors. Behavior modification is a psychological treatment approach that focuses on changing problematic behaviors by reinforcing desirable behaviors and reducing the reinforcement of undesirable behaviors. It involves identifying the specific behaviors that need to be modified, setting goals for behavior change, and using techniques such as positive reinforcement, punishment, and extinction to modify the behaviors. The goal of behavior modification is not to repair troubled or broken relationships, unearth the origin of maladaptive behavior, or modify the clients' personality structure. These may be addressed as part of the treatment process, but they are not the primary focus of behavior modification.
a barrel will rupture when the gauge pressure within it reaches 350 kpa. it is attached to the lower end of a vertical pipe, with the pipe and barrel filled with oil \rho
The pipe will be 40.1 meter if the barrel is not to rupture.
What is fluid pressure?The pressure exerted by a fluid at equilibrium at any point due to the force of gravity is known as fluid pressure.
Given that: fluid pressure is: p = 350 kPa = 350 * 1000 Pa = 350000 Pa.
Density of fluid is: ρ = 890 kg/m^3.
Let the height of the pipe is h.
Hence, from the formula of P = hρg we get: the height of the pipe is:
h = P/ρg
= 350000/(890×9.8) m
= 40.1 meter.
So, the pipe is 40.1 m long.
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heat is transferred at a rate of 2 kw from a hot reservoir at 775 k to a cold reservoir at 300 k. calculate the rate at which the entropy of the two reservoirs changes. (round the final answer to six decimal places.) the rate at which the entropy of the two reservoirs changes is kw/k. is the second law satisfied? (click to select)
the rate at which the entropy of the two reservoirs changes is 0.004081 KW/K
Yes, the second law is satisfied.
claculation :
ΔS = Q/T (entropy formula)
ΔS1 = 2/300 = 0.006667 KW/K
ΔS2 = 2/715 = 0.002580
Δs = 0.006667 - 0.002580
Δs = 0.004081 KW/K
Yes, the second law is satisfied.
Entropy is a scientific concept and a measurable physical property most commonly associated with states of disorder, randomness, or uncertainty. The term and concept are used in a variety of fields, from classical thermodynamics, where it was first recognized, to microscopic descriptions of nature in statistical physics, to principles of information theory. It finds a wide range of applications in information systems, including information transmission in chemistry and physics, the relationship between biological systems and life, cosmology, economics, sociology, weather science, climate change, and communications.
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a particle of mass slides without friction on the inside of a cone in a circular orbit of radius at height above the base of the cone. the cone is rotating about the vertical axis with angular velocity . the velocity of the particle as observed in the rotating reference frame is given by . here both and are magnitudes (positive quantities). the axis of the cone is vertical and gravity points downward. the apex half-angle of the cone is
the apex half-angle of the cone is [tex]\frac{V^{2} }{g}[/tex]
Calculation :
Ncosθ = mg ---1
Nsinθ =[tex]\frac{mv^{2} }{r}[/tex]
divide eqn 1 and 2
tanθ = V²/rg ---3
now tan θ = h/r ---4
fro eqn 3 and 4
h= [tex]\frac{V^{2} }{g}[/tex]
A cone is a three-dimensional geometric shape that tapers from a flat base (often not necessarily circular) to a point called the vertex or apex.
A cone is formed by a series of line segments, half-lines, or lines that connect a point (vertex) common to all points on the base in a plane that does not contain vertices. Depending on the author, the basis may be restricted to a circle, a one-dimensional square in the plane, a closed his one-dimensional figure, or any of the above plus all enclosed points. A cone is a solid object if the base contains the enclosed points. Otherwise, it is a 2D object in 3D space. For solids, the boundaries formed by these lines or partial lines are called faces. If the sides are unlimited, it is a conical surface.
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❧ What are the images formed by a plane mirror?
The following are some properties of images formed by a plane mirror are; virtual, upright, left-right reversed, the same distance from the mirror as the object's distance, and the same size as the object.
What is a plane mirror?When a ray of light hits a surface, then it can undergo one of the following reflection, refraction, or absorption. So mirrors are polished surfaces coated with mercury such that they reflect most of the light hitting them.
Characteristics of the image formed by a plane mirrorThe image is virtual.The image is laterally inverted.The image is erect.The size of the image is the same as the size of the object.The distance between the image obtained from the mirror is the same as the distance between the object from the mirror.Learn more about plane mirrors:https://brainly.com/question/1126858
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match the feature on mars with the best terrestrial analogy. be sure to think broadly. the analogy can be geological, chemical, or conceptual.
The two planets are similar in size, inclination, structure, composition, and the presence of water on their surfaces. They also have many key differences.
While Earth has 23h 56m and 4 s period of rotation, Mars's period of rotation is about 24 hours and 40 minutes. Mars is inclined on its axis, similar to Earth., It is inclined at 25.19° to its orbital plane.
They are both terrestrial planets. This means that both have a dense metallic core and also an overlying mantle and crust, which is composed of less dense materials (like silicate rock).
Mars also has a surface covered by a mountain range. Ice water exists beneath much of the Martian surface. Radar data and soil samples have confirmed the presence of shallow subsurface water at the middle latitudes as well.
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the term mechanical weathering refers to changes in a rock that are physical; there is little or no chemical change. True or False ?
The term which is called as mechanical weathering always refers to the changes in a rock which are physical and there is no or very little chemical change. So, it's True.
Mechanical weathering (additionally known as bodily weathering) breaks rock into smaller portions. These smaller portions are similar to the larger rock, simply smaller. That means the rock has modified bodily with out converting its composition. Mechanical weathering is likewise called bodily weathering. In this kind of weathering, a huge rock is disintegrated into smaller portions of rocks.
When rocks crumble or split with out experiencing any alternate of their chemical composition, it's far called mechanical weathering. The assertion approximately mechanical weathering that isn't genuine is includes a chief alternate withinside the mineral composition of the weathered material. Mechanical weathering breaks rocks down into smaller fragments, and will increase the floor location of the over all material. By growing the floor location, chemical strategies may also act extra without problems upon the rock floor.
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Two ball bearings from different manufacturers are being considered for a certain application Bearing A has a catalog rating of 2.0 kN based on a catalog rating system of 3000 hours at 500 rev/min. Bearing B has a catalog rating of 7.0 kN based on a catalog that rates at 10^{6 cycles. For a given application, determine which bearing can carry the larger load.
CB =7 KN , Since CA > Cg bearing A can carry the larger load.
In order to compare the bearings, both bearings need to be rated in
terms of same catalog rating.
Calculation :
Calculate basic load rating for bearing A for one million
revolutions.
CA = FA[tex](\frac{LA}{LR} )^{1/a}[/tex]
= [tex]2(\frac{3000*500*60}{10^{6} } )^{1/3}[/tex]
= 8.96kN
Bearing B already is rated at one million revolutions, CB =7 KN
Since CA > Cg bearing A can carry the larger load.
Bearings are mechanical elements that limit relative motion to a desired degree and reduce friction between moving parts. The bearing design can, for example, provide free linear motion of the moving part or free rotation about a fixed axis. Alternatively, movement can be prevented by controlling the normal force vector acting on the moving part. Most bearings facilitate the necessary movement by minimizing friction. Bearings are broadly classified according to the type of motion, permissible motion, and the direction of load (force) applied to parts.
Slewing bearings support rotating components such as shafts and axles in mechanical systems, transferring axial and radial loads from the load source to the supporting structure. Plain bearings, the simplest type of bearing, consist of a shaft that rotates in a bore.
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the loop is in a magnetic field 0.40 t whose direction is perpendicular to the plane of the loop. at t=0, the loop has area A=0.285 m2
The emf induced in the loop at t = 0 is
Part a)
[tex]$$\text { EMF }=14 \times 10^{-3} \mathrm{~V}$$[/tex]
The emf induced in the loop at t = 1.00 s
Part b)
[tex]$$E M F=15.67 \times 10^{-3} \mathrm{~V}$$[/tex]
What is emf induced ?
As we know that magnetic flux through the loop is given as [tex]$\phi=B . A$[/tex]
now we have
[tex]$$\phi=B \pi r^2$$[/tex]
now rate of change in flux is given as
[tex]\frac{d \phi}{d t}=B(2 \pi r) \frac{d r}{d t}$$[/tex]
now we know that
[tex]$$\begin{aligned}& A=\pi r^2 \\& 0.285=\pi r^2 \\& r=0.30 m\end{aligned}$$[/tex]
Now plug in all data
[tex]$$\begin{aligned}& E M F=(0.20) \times 2 \pi \times(0.30) \times(0.037) \\& E M F=14 \times 10^{-3} V\end{aligned}$$[/tex]
Now the radius of the loop after [tex]$t=1 \mathrm{~s}$[/tex]
[tex]$$\begin{aligned}& r_1=r_0+\frac{d r}{d t} \\& r_1=0.30+0.037 \\& r_1=0.337 m\end{aligned}$$[/tex]
Now plug in data in above equation
[tex]$$\begin{aligned}& E M F=(0.20) \times 2 \pi \times(0.337) \times(0.037) \\& E M F=15.67 \times 10^{-3} V\end{aligned}$$[/tex]
Complete question:The loop is in a magnetic field 0.40 T whose direction is perpendicular to the plane of the loop. At t = 0, the loop has area A = 0.285 square m.Suppose the radius of the elastic loop increases at a constant rate, dr/dt = 3.70 cm/s .
A) Determine the emf induced in the loop at t = 0.
B)Determine the emf induced in the loop at t = 1.00 s .
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The coefficient of static friction between the incline and the 200-1b crate in (Figure 1) is pe = 0.3. Part A Determine the force P that must be applied to the rope to begin moving the crate up the incline. Express your answer in pounds to three significant figures. Figure < 1 of 1> IVO AEO J1 vec ? P = lb Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
The force applied due to friction is 32.2 N.
Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.
Coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.
To solve for the minimum force, let us assume it to be F (N)
So
F=mg sin A
But
=>>>> coefficient of static friction x (F + mg cos A
=>3 x 9.8 x sin35 = 0.3 x (F + 3 x 9.8 x cos35)
So making F subject of formula
F + 24.0 = 56.2
F = 32.2N
Therefore, the force applied due to friction is 32.2 N.
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if a person pulls on the rope with a constant force what is the acceleration of the system? answer in units of m/s2.
The tension in a given rope may be thought of as T = (m g) + (m a), where "g" denotes the gravitational acceleration of any items the rope is supporting and "a" denotes any additional accelerations placed on those same objects.
How do you find the tension of a rope with acceleration?Because of the forces tugging on the rope from both ends, a particular strand of thread or rope will be under strain. Remember that force is defined as mass times acceleration. Any change in mass or acceleration of the objects the rope is supporting will result in a change in the tension in the rope, assuming the rope is stretched firmly. A system's components are nevertheless subject to gravity's continual acceleration even when it is at rest. The tension in a given rope may be thought of as T = (m g) + (m a), where "g" denotes the gravitational acceleration of any items the rope is supporting and "a" denotes any additional accelerations placed on those same objects. The assumption that our rope, cable, etc. is thin, massless, and incapable of being stretched or broken is made for the majority of physics problems.Consider a system where a weight is suspended from a wooden beam using only one rope as an example (see picture). The system is completely at rest because neither the weight nor the rope are moving. Due to this, we are aware that in order for the weight to be maintained in equilibrium, the tension force and the weight's gravitational force must be equal. Or, tension (Ft) Equals force of gravity (Fg) = m g.In that case, the tension force would be 10 kg x 9.8 m/s2 = 98 Newtons, assuming the weight is 10 kg.To Learn more About acceleration refer To:
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A cannon is mounted on a tower above a wide, level field. The barrel of the cannon is 29.3 m above the ground below. A cannonball is fired horizontally with an initial speed of 900m/s. Assuming air resistance can be neglected, approximately how long will the cannonball be in flight before it hits the ground?
Projectile motion is a special case of kinematics, whereby an object freely moves only under the influence of gravity. To analyze an object undergoing projectile motion, one can use the kinematics equations:
x=vot+1/2at^2
v^2f=v^2o+2ax
a=vf−vo/t
where x is the displacement, v is the velocity, t is the time, and a is the acceleration. It is important to note that these equations are vector equations, and thus one must analyze the x and y components of the motion separately.
The time of flight is 2.44 seconds.
We know that third equation of motion is [tex]S = ut + \frac{1}{2} at^{2}[/tex] where,
S = distance = 29.3 m
u = initial speed
t = time
a = acceleration = 9.8 [tex]m/s^{2}[/tex]
In this case, the ball is fired horizontally, so vertical initial velocity is 0.
i.e. u = 0
Putting these values in above equation, we get
29.3 = 0 + [tex]\frac{1}{2} (9.8)t^{2}[/tex]
⇒ t = 2.44 seconds
So the time of flight is 2.44 seconds.
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write the magnetic flux through a single turn of the coil as a function of time. remember to use si units.
Weber (Wb) and tesla meter squared (Tm2), which is called after German scientist Wilhelm Weber, is the SI unit for magnetic flux.
How can you determine the magnetic flux passing through a coil?Using Faraday's law, it is possible to determine the size of the induced emf.The long coil's magnetic field has the formula B = 0(N/l)I.NBA = 0(N2/l)IA is the flow through the coil.
What's the formula again for rate at which magnetic flux changes over time?Emf=Nt is the equation for the induced emf brought on by an change in magnetic flux.Faraday's law of duction is the name given to this connection.Volts are used as usual as the emf measurement units.
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A rocket fired horizontally at 50m/s breaks into 2 equal masses. One mass, m1, deflects 30ᴼ above the horizontal while the other mass, m2, deflects 60ᴼ below the horizontal. Find the velocities for m1 and m2 at that moment.
Answer:When a rocket is fired horizontally at 50 m/s and breaks into two equal masses, m1 and m2, the velocities of the two masses at the moment of separation can be determined using the principles of conservation of momentum and conservation of kinetic energy.
According to the principle of conservation of momentum, the total momentum of an isolated system remains constant, unless an external force is applied. This means that the total momentum of the two masses before and after the separation must be the same. Since the two masses are equal and the initial velocity of the rocket is 50 m/s, the total initial momentum of the system is 50 m/s x 2 masses = 100 m/s.
After the separation, the momentum of m1 is equal to the initial momentum of the system, since the direction of motion has not changed. This means that the velocity of m1 is 50 m/s.
The momentum of m2, however, has changed due to the deflection of 60ᴼ below the horizontal. The direction of motion of m2 is now perpendicular to the initial direction of the rocket, and the magnitude of the momentum is equal to the initial momentum of the system. Using the law of cosines, we can determine the magnitude of the velocity of m2 as follows:
v2 = (100 m/s) / (cos 60ᴼ)
v2 = 50 m/s
Therefore, the velocities of m1 and m2 at the moment of separation are 50 m/s and 50 m/s, respectively.
Explanation:
