What are the coordinates of R', the image of R(-4, 3) after a reflection in the line
y = x

Answer:

7,853.982

Step-by-step explanation:

Edg 2022

Answer:

[tex]\boxed {a, b, c, d}[/tex]

Step-by-step explanation:

Rhombuses, parallelograms, rectangles, and squares cannot be classified as trapezoids as they have 2 pairs of parallel sides each. But quadrilaterals can be classified as trapezoids if they have a pair of parallel sides and a pair of non-parallel sides.

a) rhombuses

b) parallelograms

c) rectangles

d) squares

Answer:

9

Step-by-step explanation:

The numerical length of GH is 20.

Given, FH=4x+8, FG=x and GH=5x.

We need to determine the numerical length of GH.

In geometry, a line segment is a part of a line that is bounded by two distinct end points and contains every point on the line that is between its endpoints.

Given Point G is on the line segment FH, then FG + GH = FH.

Now, substitute the given values into the formula as shown:

x + 5x = 4x + 8

6x = 4x + 8

6x - 4x = 8

2x = 8

x=4

To get the length of GH substitute x=4 for 5x

That is, GH = 5(4)= 20

Hence, the numerical length of GH is 20.

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The ERP system is originally configured to handle the transactional component rather than supporting the reporting component.

The ERP System is a form of software used by businesses to handle day-to-day business operations in a company such as finance, marketing, project management, regulatory risk management, as well as, supply chain management.

The primary goal of an ERP system is to improve organizational efficiency by controlling and improving how corporate resources are used. Therefore, the ERP system is originally configured to handle the transactional component rather than supporting the reporting component.

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Answer:

3.2

The value of C when B is 5 is 3.2

Step-by-step explanation:

Answer:

(x+y)

Step-by-step explanation:

[tex] {x}^{2} - {y}^{2} = (x + y)(x - y)[/tex]

Thus, the HCF is (x+y).

Answer:

(x + y)

Step-by-step explanation:

Factorizing both terms :

The HCF of the terms is (x + y).

Answer:

A = 50x^2+3

B = 75

C = 55

Step-by-step explanation:

[tex]f(x)=2x^2+3\\g(x)=5x[/tex]

A. f(g(x))

[tex]2(5x)^2+3\\2(25x^2)+3\\=50x^2+3[/tex]

B. g(g(3))

[tex]5(5(3))\\5(15)\\=75[/tex]

C. g(f(-2))

[tex]g(2(-2)^2+3)\\g(8+3)\\g(11)\\5(11)\\=55[/tex]

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = -3 [/tex]

[tex]\qquad \tt \rightarrow \: f(2) = 1[/tex]

[tex]\qquad \tt \rightarrow \: f(4) = 1 [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

F(x) represents the value of y on curve for given value of x

[tex] \textsf{\large First -} [/tex]

[tex]\qquad \tt \rightarrow \: f(0) =( 0) {}^{2} - 3[/tex]

[ since 0 < 2 ]

[tex]\qquad \tt \rightarrow \: f(0) = 0 {}^{} - 3[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = - 3[/tex]

[tex] \textsf{\large Second} [/tex]

[tex]\qquad \tt \rightarrow \: f(2) = (2) {}^{2} - 3[/tex]

[ since 2 = 2 ]

[tex]\qquad \tt \rightarrow \: f(2) = 4{}^{} - 3[/tex]

[tex]\qquad \tt \rightarrow \: f(2) = 1[/tex]

[tex] \textsf{\large Third -} [/tex]

[tex]\qquad \tt \rightarrow \: f(4) = - 4 + 5[/tex]

[ since 4 > 2 ]

[tex]\qquad \tt \rightarrow \: f(4) = 1[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

Aubree can use 4.6 gigabytes of data while staying within her budget.

If the answer choices only use whole numbers, use 4 gigabytes, because it is the number of full gigabytes she can use.

Step-by-step explanation:

x= gigabyte

58.50 + 3x = 72.30

3x = 72.30-58.50

3x= 13.8

x= 4.6

The complete question is

"What is the component form of the vector represented by 2a when a =⟨−2,3⟩?"

The Component form of the vector represented by 2a is (-4,6)

The component form of a vector is represented by (x, y) that has gone x units left to the origin and y units up from the origin.

Given, a=(-2,3)

By using scalar multiplication,

2a = (2(-2), 2(3))

2a = (-4,6).

Therefore the component form of 2a=(-4,6)

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The two-point A and B will be -1+2i and -2+2i respectively.

A complex number is one that has both a real and an imaginary component, both of which are preceded by the letter I which stands for the square root of -1.

The complex number is given as;

x+iy

Where x is the real part and iy is the imaginary part.

The two points added to obtained -3 + 4i are;

A = -1+2i

B= -2+2i

The sum of the two points is;

⇒A+B;

⇒-1+2i + -2+2 i

⇒-3 + 4 i

Hence the two-point A and B will be -1+2i and -2+2i respectively.

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Answer:

it is in java and it is also can be done in BlueJ

Step-by-step explanation:

please mark me brainlist

The inequalities that define the given conditions are,[tex]4x+3y \leq25[/tex].Option A is correct.

Inequality is a sort of equation in which the equal sign is missing. As we will see, inequality is defined as a statement regarding the relative magnitude of two claims.

Given data;

Soda costs =  $3 per case

Paper plates  = $4 per stac

The maximum amount of money you can spend  is $25

x = the number of cases of soda

y = the number of stacks of paper plates.

The inequalities that define the given conditions are;

[tex]4x+3y \leq25[/tex]

Hence, option A is correct.

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Answer:

(1) 10

(2) 10π

(3) 25π

Step-by-step explanation:

We are given the radius of the circle which is halfway through a circle. The radius of this circle is 5.

We are required to find the diameter, perimeter, and area using the given data we have been provided with.

Let's start:

#1: Diameter

To find diameter [tex]d[/tex] use formula:

                                               [tex]d=2*r[/tex]

After substituting  [tex]r=5[/tex] we have:

                                             [tex]d=2*5\\d=10[/tex]

After calculating, we have found that the diameter of the circle is 10.

#2: Perimeter

The perimeter can also be known as the circumference of a circle as they both measure the outline.

To find circumference [tex]C[/tex] use formula:

                                                  [tex]C=2*r*\pi[/tex]

After substituting [tex]r=5[/tex] we have:

                                          [tex]C=2*5*\pi[/tex]

                                           [tex]C=10\pi[/tex]

Convert [tex]10\pi[/tex] to a decimal and round it to the nearest tenth and we have:
⇒ 31.4159265359

⇒ 31.4

After calculating, we have found that the perimeter (or circumference of the circle is 10π or 31.4 (Rounded to the nearest tenth in decimal form).

#3: Area

To find area [tex]A[/tex] use the formula:

                                            [tex]A=r^2*\pi[/tex]

After substituting  [tex]r=5[/tex] we have:

                                           [tex]A=5^2*\pi \\A=25*\pi \\A=25\pi[/tex]

Convert [tex]25\pi[/tex] to a decimal and round it to the nearest tenth and we have:

⇒ 78.5398163397

⇒ 78.6

After calculating we have found that the area of the circle is either 25π or 78.6 (rounded to the nearest tenth).

After finding all the required information, we have now completed the answer.

Answer:

15 ($20 dollar bills) and 19 ($10 dollar bills) ! Pretty sure this is correct, if wrong let me know and i'll make a question for you to give your points back, i dont know if i can do that but i can try!! Have a good day.

Answer:

The answer is figure A, B, C, D.

Step-by-step explanation:

Because, polygon means a shape with more then 1 side, and in your pic all of the figures have more than one side, so that's the answer.

Answer:

-69

Step-by-step explanation:

inches:-69

-5 9/12 (-5 3/4 clearer) feet

Explanation in detail:

Write the equation down and distribute it.

3x - 1 = 2(x + 34)

3x - 1 = 2x + 68

Remove the variable on one side first (it makes solving the equation less complicated.)

3x - 1 = 2x + 68

-3x -3x

-1 = -x + 68

On all sides, subtract 68.

-1 = -x + 68

-68 -68

-69 = x

I'm guessing the answer in feet and inches is...

inches:-69

-5 9/12 (-5 3/4 simplified) feet

Triangles FGH and ABC are congruent because of the: AAS congruence theorem.

The AAS congruence theorem states that when two angles and one non-included side in one triangle are congruent to corresponding two angles and one non-included side in another triangle, then both triangles are congruent.

In the proof given, it is established that both triangles have two corresponding congruent angles, and also, BC ≅ GH which are non-included sides.

Therefore, both triangles are congruent because of the AAS congruence theorem.

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The activity series is an arrangement of species in order of reactivity.

The activity series is an arrangement of species in order of reactivity. The position of a specie in the series determines the possibility of certain reactions.

The following are the fates of these reactions;

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LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

[tex]\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)[/tex]

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

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Step-by-step explanation:

the problem description is seemingly contradicting itself.

"without replacement" means that you don't put the picked item back into the bag or "pool" of items.

and that means that after Rebecka picked a puppy, Aaron CANNOT pick the same one at all.

but then it says that they both may select the same one. which means it is WITH replacement.

so, what is it now ?

I have to give you both answers, and you will have to clarify with your original question or directly with your teacher what is the true condition.

in any case, a probability is always

desired cases / total possible cases.

WITH replacement (they can both pick the same puppy) :

there are 10 puppies, from which 3 are poodles.

so, total possible cases = 10, desired cases = 3

the probability to pick a poodle at the 1st pick = 3/10.

the picked puppy goes back.

the probability to pick a poodle at the 2nd pick = 3/10.

the probability that both picks are poodles is

3/10 × 3/10 = 9/100 = 0.09

WITHOUT replacement :

the first picked puppy is not returned to the group of 10 puppies, so, it can't be picked again, and the number of available puppies gets less as each puppy is removed. this changes the probabilities.

at the beginning we have 10 puppies, from which 3 are poodles.

the probability to pick a poodle at the 1st pick = 3/10.

the picked puppy does NOT go back.

now we have 9 puppies for Aaron to pick from. and for our desired cases for the second pick we have to combine it with the outcome, that the first pick was a poodle.

that means we have only 2 poodles left in the group of 9 puppies.

the probability to pick a poodle at the 2nd pick = 2/9.

the probability that both picks are poodles is therefore

3/10 × 2/9 = 6/90 = 1/15 = 0.066666666...

This is a geometric progression

So

The general formUla is

[tex]\\ \rm\Rrightarrow a(n)=ar^{n-1}[/tex]

[tex]\\ \rm\Rrightarrow a(n)=\dfrac{1}{4}\left(\dfrac{1}{4}\right)^{n-1}[/tex]

Answer:

[tex]\displaystyle \lim_{n \to \infty} \dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]

Step-by-step explanation:

Series: the sum of the elements of a sequence.

Therefore, as the numbers have been defined as a series and we need to find [tex]S_n[/tex]:

[tex]\dfrac{1}{4}+\dfrac{1}{16}+\dfrac{1}{64}+\dfrac{1}{256}+...[/tex]

First determine if the sequence is arithmetic or geometric.

If it is an arithmetic sequence, there will be a common difference between consecutive terms.

if it is a geometric sequence, there will be a common ratio between consecutive terms.

From inspection of the terms, we can see that there is a common ratio of 1/4, as each term is the previous term multiplied by 1/4, so it is a geometric series.

Sum of the first n terms of a geometric series:

[tex]S_n=\dfrac{a(1-r^n)}{1-r}[/tex]

Given:

[tex]a=\dfrac{1}{4}[/tex]

[tex]r=\dfrac{1}{4}[/tex]

Substitute the values of a and r into the formula:

[tex]\implies S_n=\dfrac{\frac{1}{4}\left(1-\left(\frac{1}{4}\right)^n\right)}{1-\frac{1}{4}}[/tex]

[tex]\implies S_n=\dfrac{\frac{1}{4}\left(1-\left(\frac{1}{4}\right)^n\right)}{\frac{3}{4}}[/tex]

[tex]\implies S_n=\dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]

Therefore:

[tex]\displaystyle \lim_{n \to \infty} \dfrac{1}{3}\left(1-\left(\dfrac{1}{4}\right)^n\right)[/tex]

Answer:

330.6

Step-by-step explanation:

You have to enter 290 for x.

T(290) = 290 + 0.14(290)

T(290) = 290 + 40.6

T(290) = 330.6

horizontal transformation 1 unit left.

vertical translation 2 units down.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

Given:

f(x) = [tex]4^{x}[/tex]

g(x) = [tex]4^{x+1} -2[/tex]

As, we can see that g(x) is shifted left side by 1 unit

So, horizontal transformation 1 unit left.

Now, as 2 is subtracted

So, vertical translation 2 units down.

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Answer:

[tex]\boxed{\bf B. \: c = 4 \sqrt{3} }[/tex]

Step-by-step explanation:

Since a = 6, then, b = 3.47 ( opposite of 30°).

By applying the pythagoras theorem..

Answer:

4√3 or B

Step-by-step explanation:

(A) n=w by the corresponding angles theorem.

(B) This is the correct answer. n=s by the vertical angles theorem and s and x are supplementary by the same-side interior angles theorem. Thus, n and x are supplementary and not always equal.

(C) n=z by the alternate exterior angles theorem.

(D) s=w, so (s+w)/2 = (s+s)/2 = s. Since n=s by the vertical angles theorem, n=s.

(E) n and w are equal by the corresponding angles theorem, and w and y are supplementary as they form a linear pair. Thus, n+y=180, and it follows n=180-y.

Answer:

c

Step-by-step explanation:

Answer:

Step-by-step explanation:

Total number of customers

⇒ 15 + 5 + 10 + 14 + 8 + 12 + 6 = 70

Percentage of customers who came on Friday

[tex]\begin{aligned}\implies \sf Percentage & = \sf \dfrac{Friday\:customers}{Total\:number\:of\:customers} \times 100\\\\& = \sf \dfrac{8}{70} \times 100\\\\& = \sf 11.43\%\:\:(nearest\:hundredth)\end{aligned}[/tex]

Percentage of customers who came on Saturday

[tex]\begin{aligned}\implies \sf Percentage & = \sf \dfrac{Saturday\:customers}{Total\:number\:of\:customers} \times 100\\\\& = \sf \dfrac{12}{70} \times 100\\\\& = \sf 17.14\%\:\:(nearest\:hundredth)\end{aligned}[/tex]

Percentage of customers who came on Friday and Saturday

[tex]\begin{aligned}\implies \sf Percentage & = \sf \dfrac{Fri\:and\:Sat\:customers}{Total\:number\:of\:customers} \times 100\\\\& = \sf \dfrac{8+12}{70} \times 100\\\\& = \sf 28.57\%\:\:(nearest\:hundredth)\end{aligned}[/tex]

28.57 is the answer, and its rounded to the nearest hundredth