Answer: Ionic compound are made by strong electrostatic interactions in the middle of ion , which will result in higher melting points and electrical conductivity when being compared to covalent compounds . covalent counds have bonds where the electrons are shared allying atoms .
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Calcium reacts with water to produce hydrogen and slightly soluble calcium
hydroxide, Ca(OH)2.
Ca(s) + 2 H20(1) --> Ca(OH)2(aq/s) + H2(g).
What will be the volume of hydrogen produced at 27°C and 7.00 x 102 torr when 25
g of calcium and 25 g of water react?
Answer:
[tex]V=16.65L[/tex]
Explanation:
Hello,
In this case, considering that both 25 g of calcium and water react, the first step is to identify the limiting reactant by considering the yielded moles of hydrogen for the same amount of reactant as follows:
[tex]n_{H_2}^{from\ Ca}=25gCa*\frac{1molCa}{40.1gCa}*\frac{1molH_2}{1molCa} =0.623molH_2\\\\n_{H_2}^{from\ H_2O}=25gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molH_2}{2molH_2O}=0.694molH_2[/tex]
Thus, since calcium yields a smaller amount of hydrogen, it is the limiting reactant so 0.623 moles of hydrogen are yielded. In such a way, by using the ideal gas equation one finds the volume as follows:
[tex]V=\frac{nRT}{P}=\frac{0.623mol*0.082\frac{atm*L}{mol*K}*300K}{700torr*\frac{1atm}{760 torr} } \\ \\V=16.65L[/tex]
Best regards.
Draw the products formed when 2−propanol [(CH3)2CHOH], the main ingredient of rubbing alcohol, is treated with H2SO4.
Answer:
Explanation:
Elimination reaction occurs when 2−propanol [(CH3)2CHOH] is treated with H2SO4, this is because the H2SO4 is a dehydrating agent. With concentrated tetraoxosulphate (VI) acid at 180°C, 2 - propanol reacts to form a conjugate acid and a conjugate base.
The reaction formation and the products can be seen in the attached image below.
QUESTION 17
If the theoretical yield of the following reaction is 3.43g of MgO and the actual yield is 2.48g of Mgo, what is the percent yield?
O 1.38%
O 72.3%
O 0.723%
138%
Answer:
72.3%
Explanation:
The following data were obtained from the question:
Theoretical yield of MgO = 3.43 g
Actual yield of MgO = 2.48g
Percentage yield of MgO =.?
Percentage yield of a reaction can simply be obtained by dividing the actual yield by the theoretical yield multiplied by 100. This is illustrated below:
Percentage yield = Actual yield /Theoretical yield × 100
Thus, we can obtain the percentage yield of MgO as follow:
Theoretical yield of MgO = 3.43 g
Actual yield of MgO = 2.48g
Percentage yield of MgO =.? Percentage yield = Actual yield /Theoretical yield × 100
Percentage yield = 2.48/3.43 × 100
Percentage yield = 72.3%
Therefore, the percentage yield of MgO is 72.3%.
The table below shows some information about four different elements.
Element
Classification
Density (g/cm³)
barium (Ba)
metal
3.6
beryllium (Be)
metal
1.8
chromium Cr)
metal
7.2
phosphorus P)
nonmetal
1.8
A cube of an unknown element has a shiny, silvery color. The side of the cube measures 2.0 cm and the cube has a mass of 14.56 g.
Based on the information in the table, which element makes up the cube?
Answer:beryllium
Explanation:
what element does this Bohr show ?
i need help simplifying 4+7(x+3)
Answer:
7x+25
Explanation:
Describe the size and scale of an atom. Explain the relative of the nucleus in relation to the size of an entire atom.
Size of an atom:
Diameter is 10^-10Size of a nucleus:
Diameter 10^-15As you can see, the nucleus is significantly smaller than the atom which is quite superb if you ask me. An atom is the smallest particle that can create a chemical composition.
Best of Luck!
Which element has a gas notation of [Kr]5s2 4d7
I need help answering these Significant Figures - precise measurements questions
1) 0.00030 = ______ 2) 3.3 x 108 = ______ 3) 1000 = ______
4) 3.50 x 107 = ______ 5) 2.100 x 10-1 = ______ 6) 1101 = ______
7) 0.043 = ______ 8) 0.09730 = ______ 9) 2010 = ______
10) 3060 = ______ 11) 43.8 = ______ 12) 0.00810 = ______
13) 5.0 x 10-4 = ______ 14) 8.570 x 10-8 = ______ 15) 7.500 x 103 = ______
Add/ Subtract Sig Fig: Solve and Round accordingly.
1) 2.6391 + 34.3124 + 1.22 = _______ 8) 94.1 + 5.7 = _______
2) 3.9 + 9.7113 + 38.9223 = _______ 9) 81.29 - 75.7 = _______
3) 9.9 + 77.1135 + 2.226 = _______ 10) 61.741 + 6.632 = _______
4) 7.8 + 17.2 = _______ 11) 6.1 + 28.2 + 94.229 = _______
5) 6.219 - 2.9 = _______ 12) 8.1732 - 1.933 = _______
6) 9.8 + 27.771 = _______ 13) 81.87 + 3.37 + 4.8421 = _______
7) 4.48 + 7.2155 + 13.9 = _______ 14) 17.56 - 6.4929 = _______
Multiply/Divide Sig Fig: Solve and round accordingly
1) 0.005 x 81.327 x 1000 = __________ 9) 0.0027 x 1.554 x 3090 = __________
2) 5 x 268 = __________ 10) 38.245 x 0.0069 = __________
3) 565 x 0.0054 x 4040 = __________ 11) 89.0 x 19.13 x 8400 = __________
4) 100 ÷ 2.0 = __________ 12) 208 ÷ 7.6 = __________
5) 4 x 23 = __________ 13) 34 x 800 = __________
6) 5006 ÷ 5.979 = __________ 14) 204 ÷ 92.731 = __________
7) 80 ÷ 8.1 = __________ 15) 300 ÷ 98.434 = __________
8) 0.4 x 0.003 x 2400 = __________ 16) 0.031 x 0.007 x 100 =
Answer:
[tex]3.0 x {10}^{4} [/tex]
10. A small gold nugget has volume of 0.87 cm3. What is its mass if the density of gold is 19.3 g/cm3?
Answer:
16.791 grams
Explanation:
The density formula is:
[tex]d=\frac{m}{v}[/tex]
Rearrange the formula for m, the mass. Multiply both sides of the equation by v.
[tex]d*v=\frac{m}{v}*v[/tex]
[tex]d*v=m[/tex]
The mass of the gold nugget can be found by multiplying the density and volume. The density is 19.3 grams per cubic centimeter and the volume is 0.87 cubic centimeters.
[tex]d= 19.3 g/cm^3\\v-0.87 cm^3[/tex]
Substitute the values into the formula.
[tex]m=d*v[/tex]
[tex]m= 19.3 g/cm^3*0.87 cm^3[/tex]
Multiply. Note that the cubic centimeters, or cm³ will cancel each other out.
[tex]m=19.3 g*0.87[/tex]
[tex]m=16.791 g[/tex]
The mass of the gold nugget is 16.791 grams.
Select the correct answer.
A bicycle traveled 150 meters west from point A to point B. Then it took the same route and came back to point A. It took a total of 2 minutes for
the bicycle to return to point A. What is the average speed and average velocity of the bicycle?
ОА.
The average speed is 2.5 meters/second, and the average velocity is
2.5 meters/second east.
OB
The average speed is O meters/second, and the average velocity is
2.5 meters/second east.
Ос.
The average speed and average velocity are both O meters/second.
OD. The average speed is 2.5 meters/second, and the average velocity is
O meters/second.
Arrange these elements according to first ionization energy.
highest to lowest ionization energy
Li
N
Be
C
B
F
O
Ne
Answer:
please find the attached file.
Explanation:
In the attachment file, we define the order of the ionization of the energy.
As its components are seen, their energy of ionization rises and falls further. Nitrogen and oxygen were detected as an anomaly. Nitrogen has more IE than oxygen because Nitrogen has the [tex]2p^3[/tex] configuration to Is half-filled It's got bigger IE than B. As, be making the 2s2 configuration fully disc.
Arrangement of elements according to first ionization energy from
highest to lowest ionization energy are Ne>F>O>N>C>B>Be.
Neon, a noble gas with a fully filled electron shell, has the highest ionisation energy of the substances on this list, making it the most stable and least likely to lose an electron. Fluorine has the second-highest ionisation energy, after helium. Due to its strong electron attraction, it is a highly electronegative element, making it more challenging to remove an electron from its outer shell. The ionisation energy of oxygen is third highest. Additionally, it has a high electronegativity and expels an electron with a lot of energy.
The fourth-highest ionisation energy is that of nitrogen, abbreviated as N. In terms of electronegativity, it is comparable to oxygen and requires a lot of energy to remove one electron. Carbon has the fifth-highest ionisation energy, after hydrogen and helium. An enormous amount of energy is needed to take an electron out of its outer shell. The second-lowest ionisation energy on this list belongs to borax, abbreviated as B. Compared to the other elements, boron is simpler to remove an electron from. Beryllium, symbol Be, has the lowest ionisation energy of all the elements on this list. From among these elements, an electron can be taken out the simplest.
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Ice Select one: a. is a crystal of water molecules packed in an open structure stabilized by hydrogen bonds. b. is less dense than liquid water. c. contains 17% more hydrogen bonds then water. d. all of the statements above are true. e. none of the statements above are true.
Answer:
All of the statements above are true.
Explanation:
Ice is solid water. Ice consists of an array of water molecules arranged into a crystal lattice. Ice has spaces between the water molecules so it is less dense than liquid water. Ice is about 9% less dense than liquid water. This accounts for the fact that it floats on water.
Ice contains more hydrogen bonds per water molecule when compared to liquid water.
Cylinders of compressed gas are typically filled to a pressure of 200 bar. For oxygen, what would be the molar volume at this pressure and 25 °C based on (i) the perfect gas equation, (ii) the van der Waals equation? For oxygen, a = 1.364 dm6 atm mol−2, b = 3.19 × 10−2 dm3 mol−1.
Answer:
a
[tex]V = 0.124 \ Liters[/tex]
b
[tex]V = 0.112 \ Liters[/tex]
Explanation:
From the question we are told that
The pressure of compressed gas is [tex]P = 200 \ bar = \frac{200}{1.013}= 197.4 \ atm[/tex]
The temperature is [tex]T = 25^oC = 25 + 273 = 298 \ K [/tex]
Generally the perfect gas equation is mathematically represented as
[tex]PV = nRT[/tex]
substituting 0.08206 L-atm/mol-K for R and 1 mole for n
We have that
[tex]V = \frac{1 * 0.08206 * 298 }{ 197.4}[/tex]
[tex]V = 0.124 \ Liters[/tex]
Generally the van der Waals equation is mathematically represented as
[tex]nRT = [P + \frac{n^2 * a }{V^2 } ][V - nb][/tex]
=>[tex]1 * 0.08206 *298 = [197.4 + \frac{1^2 * 1.364}{V^2 } ][V - 1 * 3.19 * 10^{-2}][/tex]
=> [tex]V = 0.112 \ Liters[/tex]
Question 3. Which of these best describes the field of engineering? *
Please help
what are limitations of an egg without the shell but has a very thin layer holding it all together
Answer:
As a hen ages, the eggs that she lays get gradually larger. However, the calcium content deposited in the shell remains the same despite the size of the egg. So the eggshells become thinner as the hen ages.
Explanation:
Use the density formula to solve the following problems. A sample of a substance has a volume of 60.5 mL and a density of 1.20 g/mL. What is the mass of the sample?Use the density formula to solve the following problems.
Answer:
72.6 g
Explanation:
Step 1: Given data
Volume of the substance (V): 60.5 mLDensity of the substance (ρ): 1.20 g/mLMass of the substance (m): ?Step 2: Calculate the mass of the substance
The density of a substance is equañ to its mass divided by its volume. The density formula is:
ρ = m/V
m = ρ × V
m = 1.20 g/mL × 60.5 mL
m = 72.6 g
Suppose that a substance in a beaker is heated over a burner in a science lab. Which observation would most likely indicate that a chemical change has occurred in the substance?
If the substance is a liquid or solid, an increase in temperature would indicate a chemical change.
If the substance is a liquid, a change of some of the liquid to gaseous form would indicate a chemical change.
If the substance is a solid, a change of some of the solid to liquid form would indicate a chemical change.
If the substance is a liquid or solid, production of an odor would indicate a chemical change.
Answer:
its D
Explanation:
Answer:
D
Explanation:
Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A 100-mL graduated cylinder with an inside diameter of 3.16 cm contains 34.6 g of heptane and 34.0 g of water. What is the combined height of the two liquid layers in the cylinder? The volume of a cylinder is π r2h, where r is the radius and h is the height.
Answer:
[tex]h=100.8cm[/tex]
Explanation:
Hello,
In this case, considering the density and mass of both water and heptane we first compute the volume of each one:
[tex]V_{water}=\frac{m_{water}}{\rho _{water}}=\frac{34g}{1.00g/mL}=34mL\\ \\V_{heptane}=\frac{m_{heptane}}{\rho _{heptane}}=\frac{34.6g}{0.684g/mL}=50.6mL\\[/tex]
Now, the total volume is:
[tex]V=50.6mL+34mL=84.6mL[/tex]
Which is equal to:
[tex]V=84.6cm^3[/tex]
Then, by knowing that the volume of a cylinder is πr²h or π(D/2)²h, we solve for the height as follows:
[tex]h=\frac{V}{\pi (D/2)^2} \\\\h=\frac{84.6cm^3}{\pi (3.16cm/2)^2} \\\\h=100.8cm[/tex]
Best regards.
A high protein diet contains 70.0g of carbohydrates, 5.0g of Fat, and 150g of protein. How much energy, in kilocalories, and kilojoules, does each diet provide? Round answers off to tens place
Answer:
925kcal, 3870.2kJ.
Explanation:
The calorie densities of these energy sources are:
Carbohydrates: 4kcal/g
Fat: 9kcal/g
Protein: 4kcal/g
70.0g of carbohydrates are:70.0g * (4kcal/g) = 280kcal
5.0g fat * (9kcal/g) = 45kcal
150g protein * (4kcal/g) = 600kcal
The energy in kilocalories is 600+280+45 = 925kcal
As 1kcal is 4.184kJ. 925kcal are:
925kcal * (4.184kJ/1kcal) = 3870.2kJ
Explain why mass cannot be used as a property to identify a sample of matter.
Mass is an extensive property hence it cannot be used as a property to identify a sample of matter.
The properties of matter can generally be classed into two categories;
Intensive propertiesExtensive propertiesIntensive properties of matter are those properties of matter that do not depend of the amount of matter present. In other words, they are characteristic of a particular kind of matter. Examples of such properties include, density, boiling point, etc.
Extensive properties depend on the amount of matter present. They include; mass, weight, etc.
Intensive properties serve as a sort of fingerprint that identifies a substance.
Extensive properties such as mass only measure the amount of matter in a sample and can not be used to identify a sample of matter.
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what is the name of the element that has electrons arranged
2,8,2
Answer:
The metal element → Magnesium (Mg)
Answer:
magnesium
Explanation:
magnesium has electrons arranged 2,8,2
The electrode that contains the item to be electroplated
a) anode
b)cathode
The electrode that contains the item to be electroplated is a cathode. The correct option is B.
What are electrodes?
Electrodes are a source of conductance of electron and behaves as a conducting material for the current too it is of two types mostly the cathode and the anode.
The anode is responsible for oxidation mostly called oxidation half cell and releases the electron while the cathode is responsible for the gain of electrons and deposition of the material as electroplated and called reduction half cell.
Therefore cathode is an electrode that contains the item to be electroplated. Option B is correct.
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How many unpaid electrons are in 1s2 2s2 2p6 3s2 3p6
Answer:
No unpaired electrons
Explanation:
This is because it is diamagnetic. Hope that helps:)
Answer:
As we can see, the first shell has its 2 electrons
the second shell has its 8 electrons
we know that the third shell also needs 8 electrons and we can see that the third shell also has 8 electrons.
Therefore, all the shells of this atom are filled and this atom is stable
So we can say that there are no unpaired electrons
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Which one of the following combinations cannot function as a buffer solution?
A) HCN and KCN
B) NH3 and (NH4)2SO4
C) HNO3 and NaNO3
D) HF and NAF
E) HNO2 and NaNO2
Answer:
it is B
; )
Which one of the following combinations cannot function as a buffer solution?
A) HCN and KCN
B) NH3 and (NH4)2SO4
C) HNO3 and NaNO3
D) HF and NAF
E) HNO2 and NaNO2
1. A homogeneous mixture of 2 or more metals is called an
a. alloy
C. covalent bond
b. anion
d. chemical bond
What are the conjugate acid-base pairs in the reaction of H2SeO4 with H2O?H2SeO4+H2O→products
Answer:
Conjugate acid- H2SeO4
Conjugate base- H2O
Explanation:
The full equation of the reaction is; H2SeO4(aq) + H2O(aq)-->H3O^+( aq) + HSeO4^-(aq).
The conjugate acid is the specie that donates a proton to the conjugate base, hence H2SeO4 is the conjugate acid while H2O is the conjugate base because it accepts a proton from H2SeO4, hence the answer above.
A 3.31-g sample of lead nitrate, Pb(NO3)2, molar mass = 331 g/mol, is heated in an evacuated cylinder with a volume of 2.53 L. The salt decomposes when heated, according to the equation:
2Pb(NO3)2(s)-->2PbO(s) + 4NO2(g) + O2(g)
Assuming complete decomposition, what is the pressure in the cylinder after decomposition and cooling to a temperature of 300. K? Assume the PbO(s) takes up negligible volume.
Answer:
0.486atm is the pressure of the cylinder
Explanation:
1 mole of Pb(NO₃)₂ descomposes in 4 moles of NO2 and 1 mole of O2. That is 1 mole descomposes in 5 moles of gas.
To find the pressure of the cylinder, we need to find moles of gas produced, and using general gas law we can determine the pressure of the gas:
Moles Pb(NO₃)₂ and moles of gas:
3.31g * (1mol / 331g) = 0.01 moles of Pb(NO₃)₂.
That means moles of gas produced is 0.05 moles.
Pressure of the gas:
Using PV = nRT
P = nRT/V
Where P is pressure (Incognite)
V is volume (2.53L)
R is gas constant (0.082atmL/molK)
T is absolute temperature (300K)
And n are moles of gas (0.05 moles)
P = 0.05mol*0.082atmL/molK*300K / 2.53L
P = 0.486atm is the pressure of the cylinder
What isotope has 18 protons and 22 neutrons?
Answer:
Argon.
Explanation:
Argon is the element having 18 protons and 22 neutrons present in its nucleus. so its atomic number is 18 and mass number is 40 if we added both number of protons and neurons. Argon belongs to noble family due to completion of outermost shell and non reactive nature. It is the third most abundant gas about 0.934% present on the earth after nitrogen and oxygen.
1/2-life of pyruvic acid in the presence of aminotransferase enzyme (which converts it to alanine) was found to be 221 s. how long will it take for the concentration of pyruvic acid to fall to 1/64 of its initial value in this first order reaction?
Answer:
After 1326s, the concentration of pyruvic acid fall to 1/64 of its initial concentration.
Explanation:
The first order kinetics reaction is:
ln [A] = ln [A]₀ - kt
Where [A] is concentration after t time, [A]₀ is intial concentration and k is reaction constant.
To convert half-life to k you must use:
t(1/2) = ln 2 / K
221s = ln 2 / K
K = ln 2 / 221s
K = 3.1364x10⁻³s⁻¹If [A] = 1/64, [A]₀ = 1:
ln [A] = ln [A]₀ - kt
ln (1/64) = ln 1 - 3.1364x10⁻³t
4.1588 = 3.1364x10⁻³s⁻¹t
1326s = t
After 1326s, the concentration of pyruvic acid fall to 1/64 of its initial concentration.
The time takes for the concentration of pyruvic acid to fall to 1/64 of its initial value in this first order reaction 1326s.
How we calculate time?Time will be calculated by using the first order kinetics equation as:
ln [A] = ln [A]₀ - kt, where
[A] = final concentration = 1/64
[A]₀ = initial concentration = 1
t = required time
k is the rate constant and will be calculated by using the half life duration 221s as:
t(1/2) = ln2 / k
221s = ln2 / k
k = ln2 / 221s = 3.1364x10⁻³ per sec
Now putting all these values on the above equation, we get
ln (1/64) = ln 1 - 3.1364x10⁻³t
4.1588 = 3.1364x10⁻³s⁻¹t
1326s = t
Hence, required time is 1326s.
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