What are the last two digits of 7^1867? ​

Yes, I guess so.

Hope this helps!

Answer:

yea actually what if she turned?- but yea its 0 so D

Step-by-step explanation:

Answer:

hopefully this helps :] 16th line down I think

Answer:

carbon (C), hydrogen (H), nitrogen (N), and oxygen (O)—make up 96.5% of an organism's weight.

Step-by-step explanation:

hope this helps.

The value of x, y and z from the system of equation are -1, -8 and 5 respectively.

Data;

To solve this problem, we have to solve the system of equation using substitution method.

From equation (iii)

[tex]2z = 10\\z = 5[/tex]

let us substitute the value of z into equation (ii)

[tex]-3y + 7z = 59\\z = 5\\-3y + 7(5) = 59\\-3y + 35 = 59\\-3y = 59 - 35\\-3y = 24\\y = -8[/tex]

Let's substitute the value of x and y into equation (i)

[tex]-2x + 6y + 3z = -31\\y = -8, z = 5\\-2x + 6(-8) + 3(5) = -31\\-2x - 48 + 15 = -31\\-2x - 33 = -31\\-2x = -31 + 33\\-2x = 2\\x = -1[/tex]

From the calculation above, the value of x, y and z are -1, -8 and 5 respectively.

Learn more on system of equations here;

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[tex]x^2+y^2=r^2~\hfill x=rcos(\theta )~\hfill y=rsin(\theta ) \\\\[-0.35em] ~\dotfill\\\\ r=3sin(A)\implies \stackrel{\textit{multiplying both sides by "r"}}{r^2~~ = ~~3~rsin(A)}\implies x^2+y^2=3y[/tex]

r = 3sinA is written in rectangular form as[tex]x^2+y^2 = 3y.[/tex]

Any complex number z = a + ib can be written in polar form as:

[tex]z = r(\cos(\theta) + i\sin(\theta))[/tex]

Complex numbers are those numbers that contain the imaginary and the real part.

Raising this to nth power (n being an integer), we get:

[tex]z ^n = r^n (\cos(n\theta) + i\sin(n\theta))[/tex]

We need to find r = 3sinA is written in rectangular form as[tex]x^2+y^2[/tex].

We know that

x = r cosA

y = r sin A

We have been given ;

r = 3sinA

Multiply by r on both sides;

[tex]r^2 = 3r sin A\\\\r^2 = 3 y[/tex]

therefore,

[tex]x^2+y^2 = 3y[/tex]

Hence, r = 3sinA is written in rectangular form as [tex]x^2+y^2 = 3y[/tex].

Learn more about cube root of complex numbers here:

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The age of Nina and sam are 15years and 10 years respectively now

They consists of equations and unknown variables

Let their current age be x and y

If five years ago, Nina was twice as old as Sam then;

x - 5 = 2(y-5)

If in five years she will be 1.5 times as old as Sam, then;

x = 1.5y

Substitute

1.5y - 5 = 2y -10

-0.5y  = -5

y =5/0.5

y = 10

Since x = 1.5y

x = 15years

Hence the age of Nina and sam are 15years and 10 years respectively now

Learn more on equation here: https://brainly.com/question/2972832

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Answer:

Step-by-step explanation:

2x + 3y = -7

7x + 9y = -14

-3(2x+3y= -7) = -6x - 9y = 21

-6x - 9y = 21

7x + 9y = -14

add columns (y values cancel)

1x + 0y = 7

x = 7

plug 7 into the x value in either equation to find y

2(7) + 3y = -7

14 + 3y = -7

3y = -21

y = -7

(x,y) = (7,-7)

Answer:

-8

Step-by-step explanation:

This is the same as 4 x -2.

The parenthesis just means to multiply the number to the left by whatver is in the paranthesis when it is touching like that.

Answer:

a) m problems, d days to complete.

m/d

b) m/15d

c)-if 15 was connected; 15d

if 15 WAS NOT connected, m problems

Pi, or π, is a number that is used to represent the ratio between a circle's circumference and its diameter.

Step-by-step explanation:

Answer: dude idek how to do this

Step-by-step explanation:

not lying still dont know

The expression is rewritten as the greatest common factor multiplied by the sum of two numbers is: 6*(8 + 11)

First, we need to find the greatest common factor between 48 and 66.

To find it, we can write both of these as a product of its prime factors, we get:

48 = 2*24 = 2*2*12 = 2*2*2*6 = 2*2*2*2*3

66 = 2*33 = 2*3*11

The greatest common factor that we can make is 2*3 = 6

Then we rewrite the numbers as:

48 = 6*8

66 = 6*11

Now we can rewrite our expression:

48 + 66 = 6*(8 + 11)

So the correct option is C

If you want to learn more about common factors, you can read:

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Answer:

Right angle

Step-by-step explanation:

It is because ANGLE QMS from the given figure denote 90 ° and right angle means 90°.

Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

Recall that the projection of a vector [tex]u[/tex] onto [tex]v[/tex] is [tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v[/tex].

Identify the vectors:

[tex]u=\langle-10,-7\rangle[/tex]

[tex]v=\langle-8,4\rangle[/tex]

Compute the dot product:

[tex]u\cdot v=(-10*-8)+(-7*4)=80+(-28)=52[/tex]

Find the square of the magnitude of vector v:

[tex]||v||^2=\sqrt{(-8)^2+(4)^2}^2=64+16=80[/tex]

Find the projection of vector u onto v:

[tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v\\\\proj_vu=\biggr(\frac{52}{80}\biggr)\langle-8,4\rangle\\\\proj_vu=\biggr\langle\frac{-416}{80} ,\frac{208}{80}\biggr\rangle\\\\proj_vu=\biggr\langle\frac{-26}{5} ,\frac{13}{5}\biggr\rangle\\\\proj_vu=\langle-5.2,2.6\rangle[/tex]

Thus, B is the correct answer

Problem 2

Treat the football and wind as vectors:

Football: [tex]u=\langle42\cos172^\circ,42\sin172^\circ\rangle[/tex]

Wind: [tex]v=\langle13\cos345^\circ,13\sin345^\circ\rangle[/tex]

Add the vectors: [tex]u+v=\langle42\cos172^\circ+13\cos345^\circ,42\sin172^\circ+13\sin345^\circ\rangle\approx\langle-29.034,2.481\rangle[/tex]

Find the magnitude of the resultant vector:

[tex]||u+v||=\sqrt{(-29.034)^2+(2.481)^2}\approx29.14[/tex]

Find the direction of the resultant vector:

[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{2.841}{-29.034}\biggr)\approx -5^\circ[/tex]

Because our resultant vector is in Quadrant II, the true direction angle is 6° clockwise from the negative axis. This means that our true direction angle is [tex]180^\circ-5^\circ=175^\circ[/tex]

Thus, C is the correct answer

Problem 3

We identify the initial point to be [tex]R(-2,12)[/tex] and the terminal point to be [tex]S(-7,6)[/tex]. The vector in component form can be found by subtracting the initial point from the terminal point:

[tex]v=\langle-7-(-2),6-12\rangle=\langle-7+2,-6\rangle=\langle-5,-6\rangle[/tex]

Next, we find the magnitude of the vector:

[tex]||v||=\sqrt{(-5)^2+(-6)^2}=\sqrt{25+36}=\sqrt{61}\approx7.81[/tex]

And finally, we find the direction of the vector:

[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{6}{5}\biggr)\approx50.194^\circ[/tex]

Keep in mind that since our vector is in Quadrant III, our direction angle also needs to be in Quadrant III, so the true direction angle is [tex]180^\circ+50.194^\circ=230.194^\circ[/tex].

Thus, A is the correct answer

Problem 4

Add the vectors:

[tex]v_1+v_2=\langle-60,3\rangle+\langle4,14\rangle=\langle-60+4,3+14\rangle=\langle-56,17\rangle[/tex]

Determine the magnitude of the vector:

[tex]||v_1+v_2||=\sqrt{(-56)^2+(17)^2}=\sqrt{3136+289}=\sqrt{3425}\approx58.524[/tex]

Find the direction of the vector:

[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{17}{-56} \biggr)\approx-17^\circ[/tex]

Because our vector is in Quadrant II, then the direction angle we found is a reference angle, telling us the true direction angle is 17° clockwise from the negative x-axis, so the true direction angle is [tex]180^\circ-17^\circ=163^\circ[/tex]

Thus, A is the correct answer

Problem 5

A vector in trigonometric form is represented as [tex]w=||w||(\cos\theta i+\sin\theta i)[/tex] where [tex]||w||[/tex] is the magnitude of vector [tex]w[/tex] and [tex]\theta[/tex] is the direction of vector [tex]w[/tex].

Magnitude: [tex]||w||=\sqrt{(-16)^2+(-63)^2}=\sqrt{256+3969}=\sqrt{4225}=65[/tex]

Direction: [tex]\displaystyle \theta=tan^{-1}\biggr(\frac{-63}{-16}\biggr)\approx75.75^\circ[/tex]

As our vector is in Quadrant III, our true direction angle will be 75.75° counterclockwise from the negative x-axis, so our true direction angle will be [tex]180^\circ+75.75^\circ=255.75^\circ[/tex].

This means that our vector in trigonometric form is [tex]w=65(\cos255.75^\circ i+\sin255.75^\circ j)[/tex]

Thus, C is the correct answer

Problem 6

Write the vectors in trigonometric form:

[tex]u=\langle40\cos30^\circ,40\sin30^\circ\rangle\\v=\langle50\cos140^\circ,50\sin140^\circ\rangle[/tex]

Add the vectors:

[tex]u+v=\langle40\cos30^\circ+50\cos140^\circ,40\sin30^\circ+50\sin140^\circ\rangle\approx\langle-3.661,52.139\rangle[/tex]

Find the magnitude of the resultant vector:

[tex]||u+v||=\sqrt{3.661^2+52.139^2}\approx52.268[/tex]

Find the direction of the resultant vector:

[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{52.139}{-3.661} \biggr)\approx-86^\circ[/tex]

Because our resultant vector is in Quadrant II, then our true direction angle will be 86° clockwise from the negative x-axis. So, our true direction angle is [tex]180^\circ-86^\circ=94^\circ[/tex].

Thus, B is the correct answer

Answer:

13 pints

Step-by-step explanation:

6 1/2 (6.50) quarts is equal to 13 pints

Answer:

13pt

to go from quarts to pints multiply the value by 2

Answer:

A. evaluate progress

Step-by-step explanation:

common sense

Answer:

D

Step-by-step explanation:

its the closest to the answer i got so that must be it

Did the math for you.

[tex]|5 - 3x| + 2 = 19\\|5 - 3x| = 17\\(|5 - 3x|) = 17^2\\25 -15x -15x + 9x^2 = 289\\25 - 30x + 9x^2 -289 = 0\\9x^2 - 30x - 264 = 0\\3(x + 4)(3x - 22)[/tex]

Answer:

x= -2

x= -3

x= 5

Step-by-step explanation:

=================================================

Explanation:

Refer to the figure below.

Focus on triangle ABF. Angle AFB = 40 is marked in red. Angle BAF = 90 is marked in blue. The missing angle is 180-90-40 = 50 which is angle ABF.

Inscribed angle ABF = 50 doubles to arc AC since this inscribed angle subtends the arc in question. I'm using the inscribed angle theorem.

arc AC = 2*(angle ABF) = 2*50 = 100 degrees

Note: We don't need the fact that angle AGD = 86

Answer:

The probability scale for this question is not 100% sure to buy shoes so the scale is given to be even chance(1/2).

Step-by-step explanation:

Answer:

  30°

Step-by-step explanation:

The angle sum theorem tells you the sum of angles in any triangle is 180°. A right triangle has one angle that is 90°, so the sum of the remaining two acute angles is 180° -90° = 90°. That is, the acute angles in a right triangle are complementary.

__

The other acute angle is ...

  90° -60° = 30°

Step-by-step explanation:

x > 5, both terms are positive

x < - 5, both terms are negative

This is not clear

If x>5

Hence..

If x<-5 terms are negative

If x=-5

Answer:

A. both the interest and fees on a loan.

Step-by-step explanation:

An annual percentage rate (APR) includes both the interest and fees on a loan.

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Answer:

A

Step-by-step explanation:

Close to 0 means there isn't a certain number, and there also isn't a certain answer for what the probability. While all of the others are alreaady stated, this is the only one that is not.

Answer:

what is the question?

do you have to find how much she is investing?

Linear equations are usually organized in slope-intercept form, which looks like this:

[tex]y=mx+b[/tex]

To find the equation of a line in slope-intercept form:

We're given:

First, plug the given slope into the slope-intercept form equation:

[tex]y=mx+b\\\\y=\dfrac{1}{2}x+b[/tex]

Now, determine the y-intercept.

[tex]y=\dfrac{1}{2}x+b[/tex]

⇒ Plug in the given point (4,1) and solve for b:

[tex]1=\dfrac{1}{2}(4)+b\\1=2+b\\b=-1[/tex]

⇒ Therefore, the y-intercept is -1. Plug this back into our original equation:

[tex]y=\dfrac{1}{2}x-1[/tex]

[tex]y=\dfrac{1}{2}x-1[/tex]

Answer:

[tex]m=\frac{6}{7}[/tex]

Step-by-step explanation:

[tex]m=\frac{10-4}{9-2}=\frac{6}{7}[/tex]

Answer:  [tex]\frac{6}{7}[/tex]

Explanation:

In the numerator we have [tex]y_2 - y_1 = 10-4 = 6[/tex] to represent the change in y, aka the rise. This is the vertical change. It's how much we go up.

The denominator has [tex]x_2 - x_1 = 9-2 = 7[/tex] to represent the run. It is the horizontal change, or how much we go to the right.

We go up 6 and to the right 7 to have a slope of [tex]m = \frac{\text{rise}}{\tex{run}} = \frac{6}{7}[/tex]

Here's how you can show the steps

[tex]m = \frac{y_2-y_1}{x_2-x_1}\\\\m = \frac{10-4}{9-2}\\\\m = \frac{6}{7}\\\\[/tex]

Note: To write [tex]\frac{6}{7}[/tex] on the keyboard, you can type 6/7