What are the new vertices of quadrilateral KLMN if the quadrilateral is translated two units to the right and four units upward?


A)

K′ = (–2,0), L′ = (1,0), M′ = (1,–3), N′ = (–2,–3)

B)

K′ = (–2,2), L′ = (1,2), M′ = (1,–1), N′ = (–2,–1)

C)

K′ = (–0,0), L′ = (3,0), M′ = (3,–1), N′ = (0,–1)

D)

K′ = (–2,–2), L′ = (1,–2), M′ = (1,–5), N′ = (–2,–5)

Answer:

2nd quadrant

Step-by-step explanation

if an angle is between 90 and 180 degrees, it is in the second quardrant. since 0<x<90, 90+x will be more than 90 but less than 180, hence it lies in the second quadrant

Answer:

1,000,000

Step-by-step explanation:

length increased by 1000

width increased by 1000

1000 * 1000 = 1,000,000

Answer:

hlo buddy

can u msg me.......,.

Answer:

[tex] \Large \mathbb{SOLUTION:} [/tex]

[tex] \begin{array}{l} \text{Let }r\text{ be the rate of the boat in still water and} \\ c\text{ be the rate of the current.} \\ \\ \text{So } \\ \begin{aligned} \quad&\bullet\:\text{Rate Upstream}= r - c \\ &\bullet\:\text{Rate Downstream}= r - c\end{aligned} \\ \\ \text{We know that }\text{Rate} = \dfrac{\text{Distance}}{\text{Time}}. \end{array} [/tex]

[tex] \begin{array}{l} \bold{Equations:} \\ \\ \begin{aligned} &\quad\quad \quad r - c = \dfrac{104}{4} = 26\quad (1) \\ \\ & \quad \quad \quad r + c = \dfrac{200}{4} = 50\quad (2)\\ \\ & \text{Adding (1) and (2), we get} \\ \\ &\quad\quad 2r = 76 \implies \boxed{r = 38\ \text{kph}} \\ \\ &\text{Using (2), it follows that} \\ \\ & \quad \quad c = 50 - r \implies \boxed{c = 12\ \text{kph}} \end{aligned} \end{array} [/tex]

Answer:

14 and 21 and 28

Step-by-step explanation:

2:3:4.

The shortest side is 14

14/2 = 7

Multiply each side by 7

2*7:3*7:4*7

14 : 21 : 28

Answer:C

Step-by-step explanation:

Answer:

c.

Step-by-step explanation:

I don't know what methods are available to you, so I'll just use one that I'm comfortable with: generating functions. It's a bit tedious, but it works! If you don't know it, there's no harm in learning about it.

Let U(x) be the generating function for the sequence u(n), i.e.

[tex]\displaystyle U(x) = \sum_{n=0}^\infty u(n)x^n[/tex]

In the recurrence equation, we multiply both sides by xⁿ (where |x| < 1, which will come into play later), then take the sums on both sides from n = 0 to ∞, thus recasting the equation as

[tex]\displaystyle \sum_{n=0}^\infty u(n+2) x^n = 8 \sum_{n=0}^\infty u(n+1) x^n - 16 \sum_{n=0}^\infty u(n) x^n[/tex]

Next, we rewrite each sum in terms of U(x). For instance,

[tex]\displaystyle \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \sum_{n=0}^\infty u(n+2) x^{n+2} \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \bigg(u(2)x^2 + u(3)x^3 + u(4)x^4 + \cdots \bigg) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \sum_{n=2}^\infty u(n) x^n \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \left(\sum_{n=0}^\infty u(n) x^n - u(1)x - u(0)\right) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2}(U(x) - 16x - 1) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2}U(x) - \frac{16}x - \frac1{x^2}[/tex]

After rewriting each sum in a similar way, we end up with a linear equation in U(x),

[tex]\displaystyle \frac1{x^2}U(x) - \frac{16}x - \frac1{x^2} = \frac8x U(x) - \frac8x - 16 U(x)[/tex]

Solve for U(x) :

[tex]\displaystyle \left(\frac1{x^2}-\frac8x+16\right) U(x) = \frac1{x^2} + \frac8x \\\\ \left(1-8x+16x^2\right) U(x) = 1 + 8x \\\\ (1-4x)^2 U(x) = 1 + 8x \\\\ U(x) = \dfrac{1+8x}{(1-4x)^2}[/tex]

The next step is to get the power series expansion of U(x) so that we can easily identity u(n) as the coefficient of the n-th term in the expansion.

Recall that for |x| < 1, we have

[tex]\displaystyle \frac1{1-x} = \sum_{n=0}^\infty x^n[/tex]

By differentiating both sides, we get

[tex]\displaystyle \frac1{(1-x)^2} = \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1} = \sum_{n=0}^\infty (n+1)x^n[/tex]

It follows that

[tex]\displaystyle \frac1{(1-4x)^2} = \sum_{n=0}^\infty (n+1)(4x)^n[/tex]

and so

[tex]\displaystyle \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty (n+1)(4x)^n + 8x\sum_{n=0}^\infty (n+1)(4x)^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=0}^\infty 4^{n+1}(n+1)x^{n+1} \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=1}^\infty 4^nnx^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=0}^\infty 4^nnx^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(3n+1)x^n[/tex]

which means

[tex]u(n) = \boxed{4^n(3n+1)}[/tex]

Answer:

3c^2

Step-by-step explanation:

Answer: Choice C. [tex]\frac{1}{x^{2}y^{5} }[/tex]and Choice E. [tex]x^{-2} y^{-5}[/tex]

Step-by-step explanation:

Algebraic exponents.

(y^-8)(y^3)(x^0)(x^-2)

(y^-8)(y^3)(x^-2)

(y^-5)(x^-2)

(1) / (y^5)(x^2)

Options 3 and 5 are correct

Hope this helps!

Answer:

k=4

Step-by-step explanation:

remove x:

10x.(-3) + ky.(-3)=-8.(-3)         (1)

-15x.2 - 6y.2 = 12.2               (2)

(1) - (2)  => -3ky+12y = 0

<=> (12-3k)y = 0

so that y has infinitely many solutions then

12-3k = 0 => k=4

Answer:

∠3z = 108 degrees

∠2z = 72 degrees

Step-by-step explanation:

First, we need to create an equation.

3z + 2z = 180

5z = 180

Divide both sides by 5:

z = 36

Now, substitute z for five for both angles.

3 x 36 = 108 degrees

2 x 36 = 72 degrees

Hope this helps!

If there is something wrong, please let me know.

Answer:

4=x y=325

Step-by-step explanation:

60x + 20 = 65x

group the variables

20=5x

because you subtracted 60x from both

4=x

because you divided 5 from both

now substitute 5 for x

65×5 is 325

y=325

Answer:

"D"

Step-by-step explanation:

just add the two functions

5x^2 - 8x^2 = -3x^2 etc

Answer:I have the same problem

Step-by-step explanation

Answer:

A) 3

Pippa kept 3 stickers for herself

Answer to question 2:

The misconception of if a student selects D) 27 is that instead of dividing to find out how many stickers Pippa kept for herself, the student subtracted. They subtracted instead of dividing.

Step-by-step explanation:

It said that Pippa gave each of her friends an EQUAL number of stickers and AS MANY STICKERS AS POSSIBLE. This tells us that to find our answer we need to divide and what ever the remainder is, is how many stickers Pippa kept for herself.

(You will kind of need to do long division for this)

35 ÷ 8 = 4

8 x 4 = 32

35 - 32 = 3

Pippa will give each of her friends 4 stickers and will keep 3 for herself.

Step-by-step explanation for question 2:

35 stickers - 8 friends = 27

D) 27 is the wrong answer to question 1/part 1

I hope this helped! c:

Answer:

The answer is 5 units.

Step-by-step explanation:

Based on the information, the triangles share two sides but have one different side. one included angle is bigger than the other.

This means that the triangle with side 2x-4 must be smaller than the triangle with the side 10.

Let first, find it minimum amount. A triangle side must be greater than zero so

[tex]2x - 4 > 0[/tex]

[tex]2x > 4[/tex]

[tex]x > 2[/tex]

The triangle side must be smaller than 10.

[tex]2x - 4 < 10[/tex]

[tex]2x < 14[/tex]

[tex]x < 7[/tex]

So x must be greater than 2 but must be smaller than 7.

Answer:

x =7/ 3

Step-by-step explanation:

5x+  22=  2x+  29

⇔5x - 2x= 29 - 22

⇔3x = 7

⇔x = 7/3

everything seems to be correctly filled.

if you wanted confidence by confirmation: here, take some

It is an exponentially decaying function.

An exponential function is where the independent variable is in the exponent. Generally the the independent variable is in the power of a constant term e.

Exponential functions are of two types one is exponentially growing function and exponentially decaying function.

when the we have a positive exponent the function is exponentially growing and when we have a negative exponent the function is exponentially decaying.

In the given question f(x) = 8e⁻ˣ

when, x = 0 f(x) = 8

f(x) = 8e⁻ˣ

f(0) = 8e⁰

f(0) = 8

Learn more about Exponential functions here :

https://brainly.com/question/15352175

#SPJ5

Answer:

[tex] - 3(x + 4) {}^{2} - 4[/tex]

Step-by-step explanation:

Vertex form is

[tex]a(x - h) {}^{2} + k = f(x)[/tex]

We know that h and k are both -4. Let x be -2 and y be -16.

[tex]a( - 2 + 4) {}^{2} - 4 = - 16[/tex]

[tex]a(2) {}^{2} - 4 = - 16[/tex]

[tex]4a - 4 = - 16[/tex]

[tex]4a = - 12[/tex]

[tex]a = - 3[/tex]

So the equation in vertex form is

[tex] - 3(x + 4) {}^{2} - 4[/tex]

Answer:

all of the above

Step-by-step explanation:

the ratio between the flour, the baking soda, and the salt would = 1:1:2 (disregarding tsp or cup measurements, since all the units stay the same in the choices)

so really, all the answers are correct

hope this helps!

Answer:

B. 1/2 teaspoon of salt per 1 teaspoon of baking soda.

Step-by-step explanation:

The ratio of cups of flour to tsp. of baking soda to tsp. of salt shown above is:

1/2 : 1/2 : 1/4

An equivalent rate to the ratio of tsp. of salt to tsp. of baking soda is 1/2 : 1 because:

Ratio of tsp. of salt to tsp. of baking soda is:

1/4 : 1/2

If we were to find an equivalent rate to this, it would be 1/2 teaspoon of salt per 1 teaspoon of baking soda for:

Multiply 2 to both terms in the ratio 1/4 : 1/2:

1/4 x 2 = 1/2 (simplified)

1/2 x 2 = 1 (simplified)

The new ratio is 1/2 : 1, which also represents the rate 1/2 teaspoon of salt per 1 teaspoon of baking soda.

Hope this helps!

Please comment back if this was correct.

The statement that odd degree polynomials have a u-shaped graph and even degree polynomials have an s-shaped graph is FALSE.

Odd degree polynomials have branches that go in opposing directions which means that they will form an s-shaped graph.

Even degree polynomials on the other hand, have graphs that go in the same direction which is why they form u-shaped graphs.

In conclusion, the above statement is false.

Find out more on polynomials at https://brainly.com/question/9696642.

Answer:

[tex]9\sqrt{3}[/tex]

Step-by-step explanation:

This is a 30-60-90 triangle.

It's good to remember this. The side length opposite to the 60 degree angle is always the base multiplied by [tex]\sqrt{3}[/tex]

Answer:

9√3.

Step-by-step explanation:

tan 60 = √3

So w/9 =√3

w = 9√3

Answer:

B

Step-by-step explanation:

9514 1404 393

Answer:

  B.  (21, 6)

Step-by-step explanation:

The preimage coordinates are multiplied by the dilation factor to obtain the image coordinates. If P is the preimage point and the dilation factor is 1/3, you have ...

  (1/3)P = (7, 2)

  P = 3(7, 2) = (3·7, 3·2)

  P = (21, 6)

The preimage point is (21, 6).

Complete Question

Complete Question is attached below

Answer:

[tex]M=160[/tex]

Step-by-step explanation:

From the question we are told that:

Standard models contribute $20

Deluxe  models contribute $30

Availability Average :

Stamping machine S= 30 minutes per hour

Motor installation Production M=60 minutes

Wiring is W=90 minutes per hour

Generally the formulation of the linear program is given as

[tex]Maximium (M)=20x + 30 y[/tex]

Where

For Stamping machine

[tex]S= 3x + 6y \leq 30.....Equ 1[/tex]

For Motor installation Production

[tex]10x + 10y \leq 60....Equ 2[/tex]

For Wiring

[tex]10x + 15y \leq 90....Equ3[/tex]

Therefore

Solving Equ...(1,2,3) simultaneously we have

[tex]x=2\\\\y=4[/tex]

Therefore

[tex]Maximium\ (M)=20x + 30 y[/tex]

[tex]M=20(2)+30(4)[/tex]

[tex]M=160[/tex]

Answer:

l = 15 feet

Step-by-step explanation:

l = 2w + 3

First you solve for the width(w)

(2w+15) (w-6) = 0

This means

2w+15=0 OR. w-6=0

First let’s solve 2w+15=0

2w = -15

w = -7.5

Width can’t be negative so that can’t be the answer. So we look at the second equation w-6=0

w= 6

Since we found the width now we can find the length by using the formula l = 2w + 3

= 2(6) + 3

= 12 + 3

= 15 feet

You can check this by using the given area which is 90.

A = lw = 15*6 = 90

(a) You can parameterize C by the vector function

r(t) = (x(t), y(t) ) = P (1 - t ) + Q t = (2 - 2t, 7t )

where 0 ≤ t ≤ 1.

(b) From the above parameterization, we have

r'(t) = (-2, 7)   ==>   ||r'(t)|| = √((-2)² + 7²) = √53

Then

ds = √53 dt

and the line integral is

[tex]\displaystyle\int_C(9x(t)+5y(t))\,\mathrm ds = \boxed{\sqrt{53}\int_0^1(17t+18)\,\mathrm dt}[/tex]

(c) The remaining integral is pretty simple,

[tex]\displaystyle\sqrt{53}\int_0^1(17t+18)\,\mathrm dt = \sqrt{53}\left(\frac{17}2t^2+18t\right)\bigg|_{t=0}^{t=1} = \boxed{\frac{53^{3/2}}2}[/tex]