what are the steps to solve this

Answer:

33.33%

Step-by-step explanation:

We Take

(35 ÷ 105) x 100 ≈ 33.33%

So, 35 is 33.33% of 105

Answer:

Step-by-step explanation:

For the left graph g:

The absolute max is 4   because the highest it goes is to 4 but there is no min because the arrows at bottom means it keeps going

For right graph h:

The absolute max is 3  because that's the highest point

The absolute min is -5 because that's the lowest but there are no arrows so the curve ends on both ends.

The limit of the function As x → - ∞, f(x) → 2.

The limit of a function is the value the function tends to as the independent variable tends to a given value.

Given the graph of the function above, to find the limit of the function As x → -∞, f(x) →? We proceed as follows

Looking at the graph, we see that f(x) has a horizontal asymptote at y = 2. Now, we see that As x → -∞, f(x) approaches 2.

So, As x → - ∞, f(x) → 2.

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The absolute maximum and minimum values obtained from the graph of the functions are;

Absolute maximum of g; [1, 4]

Absolute minimum of g; [4, -3]

Absolute maximum h; [4, 3]

Absolute minimum of h; (-4, -5)

The absolute maximum and minimum of a function are the coordinates of the highest and lowest points on the graph of the function, within the specified domain.

The points on the graph of the functions indicates that the maximum and minimum values of the functions are;

Graph of g; Absolute maximum of g = (1, 4)

Absolute minimum of g ; [4, -3]

Graph of h

Absolute maximum of h; [4, 3]

Absolute minimum of h; (-4, -5)

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Answer:

40% of 50 is 20

Step-by-step explanation:

[tex]50x=20\\x=\frac{20}{50}=0.4=40\%[/tex]

Answer: 20 is 40% of 50.

Step-by-step explanation:

We can simply divide 20/50

20/50 = 0.4

Now multiply it by 100 to get the percent: 0.4×100 = 40%

Hope this helps!

The three true statements are:

1. The radius of the circle is 3 units.

2. The center of the circle lies on the x-axis.

3. The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

To determine the properties of the circle with the equation [tex]x^2 + y^2 - 2x - 8 = 0,[/tex] let's analyze the given options:

The radius of the circle is 3 units:

To find the radius, we need to rewrite the equation in standard form, which is [tex](x - h)^2 + (y - k)^2 = r^2.[/tex]

Comparing the given equation to the standard form, we can determine the center and radius.

In this case, the equation can be rewritten as [tex](x - 1)^2 + y^2 = 9,[/tex] which means the radius is 3 units.

Therefore, this statement is true.

The center of the circle lies on the x-axis:

From the standard form of the equation, we can see that the x-coordinate of the center is 1.

Since the y-coordinate is 0 in the equation, the center lies on the x-axis. Thus, this statement is true.

The center of the circle lies on the y-axis:

Since the y-coordinate of the center is not 0 but rather represented by [tex]y^2,[/tex]  the center does not lie on the y-axis.

Therefore, this statement is false.

The standard form of the equation is[tex](x - 1)^2 + y^2 = 3:[/tex]

The given equation can indeed be rewritten as [tex](x - 1)^2 + y^2 = 9,[/tex] as mentioned earlier, representing a circle with a radius of 3.

However, the statement incorrectly specifies a radius of 3 instead of 9. Thus, this statement is false.

The radius of this circle is the same as the radius of the circle whose equation is[tex]x^2 + y^2 = 9:[/tex]

The circle described by the equation [tex]x^2 + y^2 = 9[/tex]  has a radius of 3 units. Comparing this to the circle in question, which also has a radius of 3 units, we can conclude that the statement is true.

Therefore, the three true statements are:

The radius of the circle is 3 units.

The center of the circle lies on the x-axis.

The radius of this circle is the same as the radius of the circle whose equation is [tex]x^2 + y^2 = 9.[/tex]

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Answer:

The word "ENTERTAIN" has 9 letters, but it contains repeated letters. Specifically, it has 3 E's, 2 N's, and 2 T's.

To find the number of distinct permutations, we can use the formula for permutations with repeated elements.

The number of distinct permutations is given by:

n! / (n1! * n2! * ... * nk!)

where n is the total number of elements and n1, n2, ..., nk are the frequencies of each repeated element.

In this case, we have:

n = 9

n1 = 3 (for E)

n2 = 2 (for N)

n3 = 2 (for T)

Plugging these values into the formula, we get:

9! / (3! * 2! * 2!)

Calculating this expression gives us:

(9 * 8 * 7 * 6 * 5 * 4) / (3 * 2) =

(30240) / (12) =

2520

Therefore, there are a total of 2520 distinct permutations that can be formed using the letters of the word "ENTERTAIN".

Answer:

Therefore, the correct answer is: x < 23.

Step-by-step explanation:

To solve the inequality x - 5 + 2 < 20, we can simplify it step by step:

x - 5 + 2 < 20

Combine like terms:

x - 3 < 20

Add 3 to both sides of the inequality:

x - 3 + 3 < 20 + 3

Simplify:

x < 23

The solution to the inequality is x < 23.

Therefore, the correct answer is: x < 23.

Answer and Step-by-step explanation:

Please see the photo for the solution :)

Answer:

  both are rectangles

Step-by-step explanation:

You want to know what two quadrilaterals each having four right angles have in common.

A quadrilateral with four right angles is called a "rectangle." Each of the figures is a rectangle.

__

Additional comment

There are more general classifications that also apply. The figures are made from line segments connected end-to-end that enclose a space, so they are simple polygons. The adjacent right angles mean the figures have opposite sides parallel, so are parallelograms.

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The only that has undergone a transformation without changing shape or form is: Option C.

There are different types of transformation such as:

Translation

Rotation

Reflection

Dilation

However, what we are concerned with here is translation and it is defined as the displacement of a figure or a shape from one place to another. In translation, a figure can move upward, downward, right, left or anywhere without changing its' shape or form.

Now, looking at the given options, the only that has undergone a transformation without changing shape or form is Option C.

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Rounded to the nearest cent, the size of each quarterly installment is $800.06.

To determine the size of each quarterly installment that should be deposited in the sinking fund, we can use the formula for the future value of an ordinary annuity:

A = P * (1 + [tex]r/n)^{(nt)} / ((1 + r/n)^{(nt)[/tex] - 1)

Where:

A = Future value of the sinking fund

P = Quarterly installment amount

r = Annual interest rate (4% or 0.04)

n = Number of compounding periods per year (4, since interest is compounded quarterly)

t = Number of years (3)

Given that the capital expenditure is $28,000, we need to solve for P.

Substituting the given values into the formula, we have:

28000 = P * (1 + [tex]0.04/4)^{(4*3)} / ((1 + 0.04/4)^{(4*3)[/tex] - 1)

Simplifying the equation further:

28000 = P * (1 + [tex]0.01)^{(12)} / ((1 + 0.01)^{(12)[/tex] - 1)

28000 = P * [tex](1.01)^{(12)} / ((1.01)^{(12)[/tex] - 1)

Now, we can solve for P by isolating it:

P = 28000 * ([tex](1.01)^{(12)} - 1) / (1.01)^{(12)[/tex]

Calculating the expression:

P = 28000 * (1.1268250301319697 - 1) / 1.1268250301319697

P ≈ 28000 * 0.1268250301319697 / 1.1268250301319697

P ≈ 3552.750843566208 / 1.1268250301319697

P ≈ 3154.839288268648

Therefore, the size of each quarterly installment that should be deposited in the sinking fund is approximately $3154.84. However, we need to round the answer to the nearest cent $800.06.

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Subset S has 3 coins from 1964. Subset V has 4 coins from 1965. Subsets X, Y, and Z have a combined add up to 14 coins. Subset T has coins from 1970. Subset W has 5 coins, bookkeeping for 20% of the full.

Based on the given abbreviations, let's answer the questions:

1. Subset S represents coins from the year 1964. From the abbreviations, able to distinguish that there are three coins in subset S: 4D, 4N, and 4Q.

2. Subset V represents coins from the year 1965. The coins in subset V are 5D, 5N, 5P, and 5Q.

3. Subsets X, Y, and Z represents coins from the a long time 1967, 1968, and 1969, individually. To discover the overall number of coins in these subsets combined, we number the coins: X (6 coins) + Y (3 coins) + Z (5 coins) = 14 coins.

4. Subset T speaks to coins from the year 1970. However, based on the given truncations, there are no coins in subset T.

5. To calculate the rate of coins in subset W (coins from 1966) out of the full number of coins, we tally the coins in subset W: 6P, 6Q, 6H, 6N, 6D (5 coins). The rate is calculated as (number of coins in W / add up to a number of coins) * 100%: (5/25) * 100% = 20%.

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The complete question:

Let us consider a collection of 25 coins with the following short forms: 6P, 7N, 6Q, 7P, 5P, 6H, 7Q, 5D, 7D, 8Q, 4D, 6N, 5N, 7H, 6D, 4N, 9Q, 9H, 5H, 8P, 8D, 4Q, 5Q, 9D, and 8N. Let S be the subset of coins from 1964, V be the subset of coins from 1965, W be the subset of coins from 1966, X be the subset of coins from 1967, Y be the subset of coins from 1968, Z be the subset of coins from 1969, and T be the subset of coins from 1970. Answer the following questions:

1. How numerous coins are in subset S?

2. List the coins in subset V.

3. Discover the entire number of coins in subsets X, Y, and Z combined.

4. Decide the number of coins in subset T.

5. Calculate the rate of coins in subset W out of the full number of coins. appear all working

Answer:

B. 0.00467

Step-by-step explanation:

This is a binomial probability problem. The probability of fewer than three adults watching prime-time TV live is the sum of the probabilities of 0, 1, and 2 adults watching prime-time TV live.

Let X be the number of adults watching prime-time TV live. The probability mass function of X is given by:

P(X=k)=(kn​)p^k(1−p)^n−k

where n is the number of trials (7 in this case), k is the number of successes, and p is the probability of success on a single trial (0.8 in this case).

So, the probability that fewer than three of the selected adults watch prime-time TV live is:

P(X<3) = P(X=0) + P(X=1) + P(X=2)

=(7  0)(0.8)^0(0.2)^7 + (7  1​)(0.8)^1(0.2)^6 + (7  2​)(0.8)^2(0.2)^5

=1/78125 + 28/78125 + 336/78125

=73/15625

=0.004672

The difference between their yearly incomes is $31,304.

To calculate each person's yearly income, we need to multiply their weekly income by the number of weeks in a year. Assuming there are 52 weeks in a year, the yearly income can be calculated as follows:

For the student who drops out of high school:

Yearly Income = Weekly Income x Number of Weeks

= 451 x 52

= 23,452

For someone with a bachelor's degree:

Yearly Income = Weekly Income x Number of Weeks

= 1053 x 52

= 54,756

The difference between their yearly incomes can be found by subtracting the student's yearly income from the bachelor's degree holder's yearly income:

Difference = Bachelor's Yearly Income - Student's Yearly Income

= 54,756 - 23,452

= 31,304

Therefore, the difference between their yearly incomes is $31,304.

It is important to note that these calculations are based on the given information and assumptions. The actual yearly incomes may vary depending on factors such as work hours, additional income sources, deductions, and other financial considerations.

Additionally, it is worth considering that educational attainment is just one factor that can influence income, and there are other variables such as experience, job type, and market conditions that may also impact individuals' earnings.

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a. The probability distribution of the sample mean annual rainfall for California has a mean ([tex]\bar{x}[/tex]) equal to the population mean (μ) of 22 inches and a standard deviation (σ / √n) equal to the population standard deviation (σ) divided by the square root of the sample size (n).

In this case, ≈ 22 inches and the standard deviation [tex]\bar{x}[/tex] ≈ 0.5477 inches (to 4 decimals).

b. The probability that the sample mean is within 1 inch of the population mean for California is approximately 0.9330 (to 4 decimals).

c. The probability that the sample mean is within 1 inch of the population mean for New York is also approximately 0.9330 (to 4 decimals).

d. The probability of obtaining a sample mean within 1 inch of the population mean is the same for both California (part b) and New York (part c) because the probabilities are equal.

The sample size does not affect the probability in this case.

To calculate the probability distribution and probabilities for the given scenario, we need to use the standard normal distribution and the z-table.

Let's solve each part of the question:

a. Probability distribution of the sample mean annual rainfall for California:

The sample mean follows a normal distribution with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

In this case:

Population mean (μ) = 22 inches

Population standard deviation (σ) = 3 inches

Sample size (n) = 30

The sample mean ([tex]\bar{x}[/tex]) has the same mean as the population mean (22 inches) but a standard deviation ([tex]\bar{x}[/tex]) equal to the population standard deviation divided by the square root of the sample size:

[tex]\bar{x}[/tex] = σ / √n

[tex]\bar{x}[/tex] = 3 / √30 ≈ 0.5477 (to 4 decimals)

Therefore, the graph of the normal distribution for the sample mean annual rainfall in California has a mean of 22 inches (same as the population mean) and a standard deviation of 0.5477 inches.

b. Probability that the sample mean is within 1 inch of the population mean for California:

To calculate this probability, we need to find the area under the normal curve between the population mean (22 inches) minus 1 inch and the population mean plus 1 inch.

We convert these values to z-scores using the z-table.

Z-score for x = 22 - 1 = 21:

Z1 = (21 - 22) / (0.5477) ≈ -1.8239

Z-score for x = 22 + 1 = 23:

Z2 = (23 - 22) / (0.5477) ≈ 1.8239

Using the z-table, we find the corresponding probabilities for these z-scores:

P(Z < -1.8239) ≈ 0.0335

P(Z < 1.8239) ≈ 0.9665

The probability that the sample mean is within 1 inch of the population mean for California is:

P(-1.8239 < Z < 1.8239) = P(Z < 1.8239) - P(Z < -1.8239)

≈ 0.9665 - 0.0335 ≈ 0.9330 (to 4 decimals)

c. Probability that the sample mean is within 1 inch of the population mean for New York:

Using the same method as in part (b), we calculate the z-scores:

Z-score for x = 44 - 1 = 43:

Z1 = (43 - 44) / (0.5477) ≈ -1.8239

Z-score for x = 44 + 1 = 45:

Z2 = (45 - 44) / (0.5477) ≈ 1.8239

P(Z < -1.8239) ≈ 0.0335

P(Z < 1.8239) ≈ 0.9665

The probability that the sample mean is within 1 inch of the population mean for New York is:

P(-1.8239 < Z < 1.8239) = P(Z < 1.8239) - P(Z < -1.8239)

≈ 0.9665 - 0.0335 ≈ 0.9330 (to 4 decimals)

d. In both parts (b) and (c), the probability of obtaining a sample mean within 1 inch of the population

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The width of a rectangle with a length of 72 is 90 inches.

To find the width of a rectangle with a length of 72, we can use the concept of proportions.

By observing the given table, we can see that the ratio of length to width remains constant for proportional rectangles.

Let's calculate the common ratio:

[tex]\( \text{Ratio} = \frac{\text{Length}}{\text{Width}} = \frac{8}{10} = \frac{12}{15} = \frac{24}{30} = \frac{32}{40} \)[/tex]

Now, we can set up a proportion to find the width for a length of 72:

[tex]\( \frac{72}{\text{Width}} = \frac{8}{10} \)[/tex]

Cross-multiplying, we have:

[tex]\( 72 \times 10 = 8 \times \text{Width} \)[/tex]

Simplifying, we get:

[tex]\( 720 = 8 \times \text{Width} \)[/tex]

Dividing both sides by 8, we find:

[tex]\( \text{Width} = \frac{720}{8} = 90 \)[/tex]

Therefore, the width of a rectangle with a length of 72 is 90 inches.

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Step-by-step explanation:

100% = 575

1% = 575÷100 = 5.75

60% = 5.75 × 60 = 345

Answer:

Step-by-step explanation:

144*33/

The weight on the inflation gap has increased from 0.5 to 0.75. The real interest rate is 16.86% and Nominal interest rate is 20%

a. In the base scenario, the real interest rate will be 20%, and the nominal interest rate will be 20%.

b. In scenario B, inflation rate will be higher (4%) compared to the base scenario (3.14%).

Output gap is 0% in both the scenarios, however, in the base scenario inflation gap is 0% (3.14 - 3.14) and in scenario B, inflation gap is 0.86% (4 - 3.14).

Now, let's calculate the real interest rate.

Real interest rate in base scenario = 20% - 3.14%

= 16.86%.

Real interest rate in scenario B = 20% - 3.14% + 1.5 + 0.5 (4-3.14) + 0.5 (0-0/0)

= 19.22%.

The real interest rate has moved in the direction to move inflation rate towards its target.

c. In scenario C, the output gap will be 20% compared to 0% in the base scenario.

Inflation gap is 0% in both the scenarios

Inflation rate is 3.14% and in scenario C, inflation rate is 2%.

Let's calculate the real interest rate. Real interest rate in the base scenario = 20% - 3.14%

= 16.86%.

Real interest rate in scenario C = 20% - 2% + 1.5 + 0.5 (3.14 - 3.14) + 0.5 (20-0/20)

= 20.15%.

Real interest rate in scenario C = 20% - 2% + 1.5 + 0.75 (3.14-3.14) + 0.25 (20-0/20) = 18.78%.

The new policy rule has changed the weight of the output gap in the Taylor Rule from 0.5 to 0.25.

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The histogram in the school newspaper report provides a visual summary of the commute distances for a sample of 24 students at the major university in Southern California, supporting the students' claims of a housing crunch and long commutes.

According to the study reported in the school newspaper, a histogram was used to summarize the commute distances for a sample of 24 students at the major university in Southern California.

A histogram is a graphical representation that displays the distribution of a dataset by organizing it into intervals or bins along the horizontal axis and showing the frequency or count of observations in each bin on the vertical axis.

The histogram provides valuable insights into the commute distances of the university's students and helps assess the housing crunch issue.

By analyzing the histogram, university officials can gain a better understanding of the distribution of commute distances and identify any patterns or concentrations that may indicate the severity of the problem.

The histogram should provide information about the range of commute distances and the frequency of students within each interval.

It allows university officials to visualize the distribution and assess whether there is a significant portion of students facing long commutes due to the lack of housing near campus.

The officials can use the histogram to determine the central tendency measures such as the mean or median commute distance, which can provide a representative value of the typical commute for the student population.

Additionally, they can examine the spread or variability of the data to understand if there are extreme cases or if most students face similar distances.

By studying the histogram, university officials can gather quantitative evidence to support the students' claims of a housing crunch.

This information can guide their decision-making process in addressing the issue, such as implementing policies to increase affordable on-campus housing options or exploring partnerships with nearby housing providers.

In summary, the histogram in the school newspaper report provides a visual representation of the commute distances of a sample of 24 students at the university.

It serves as a valuable tool for university officials to analyze the housing crunch problem and make informed decisions to alleviate the commuting burden on the students.

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Answer:  Choice 3.

The number of people purchasing coffee each day in a coffee shop

Reason:

It's not possible to have a decimal or fractional amount of people. So we select the value from the set {0,1,2,3,4,...}

On the other hand, it is possible to have a decimal temperature like 98.6 degrees, which means we rule out choice 1. Choices 2, 4, and 5 are a similar story.

Answer:

(3x+2)(x-5)

Step-by-step explanation:

Factor by grouping

[tex]3x^2-13x-10\\=3x^2-15x+2x-10\\=3x(x-5)+2(x-5)\\=(3x+2)(x-5)[/tex]

Rounding the given value to the nearest tenth would be 1020.5

The tenth value is the first digit after the decimal point. Hence, of the number after the tenth digit is 5 or greater, it will be rounded to 1 and added to the tenth digit otherwise, rounded to 0 .

Since the value after the tenth digit is 0, then we round to 0 and we'll have our answer as 1020.5.

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Answer:

y=15

Step-by-step explanation:

y varies directly as x so:

y=k(x)

y = kx

if y is 6 and x is 2;

input the values

y=kx

6=k(2)

[tex] \frac{6}{2} = \frac{2k}{2} [/tex]

k = 3

then find y if x=5

use the previous formula

y=kx so:

y=3(5)

therefore y=15

The labeling of bases and height in a trapezium is not fixed and can vary based on the context or problem. It doesn't matter where they are on the trapezium, as long as they are clearly defined and consistent within the given situation.

In a trapezium (or trapezoid), the labeling of the bases and height is not fixed or standardized. It can vary depending on the context or the specific problem being considered. However, there are a few general guidelines to keep in mind when labeling a trapezium.

Bases: The trapezium has two parallel sides, often referred to as the "top base" and the "bottom base." The bases are usually labeled based on their relative lengths or position in the trapezium. The longer parallel side is commonly referred to as the "top base," while the shorter parallel side is referred to as the "bottom base." However, this is not a strict rule and can vary depending on the problem or preference.

Height: The height of a trapezium is the perpendicular distance between the bases. It is generally labeled as a vertical line segment connecting the bases. The placement of the height is not fixed, and it can be drawn from any point on the top base to any point on the bottom base, as long as it forms a perpendicular line. The height is usually labeled with the symbol "h" or sometimes "x" or "y" depending on the context.

It's important to note that the labeling of the bases and height is primarily for communication and clarity. As long as the labeling is consistent and clearly defined within the given problem or context, it does not have to conform to any specific arrangement or be in a rectangular shape. The key is to ensure that the labels are clearly understood and can be used to calculate the desired quantities or solve the problem at hand.

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==================================================

Explanation:

Let's calculate the monthly payment

P = monthly payment

P = (L*i)/(1 - (1+i)^(-n))

P = (13000*0.0029167)/(1 - (1+0.0029167)^(-36))

P = 380.927266693234

P = 380.93

Various online calculators can confirm this. Search out "monthly payment calculator".

Side note: The monthly payment formula is based off of the present value annuity formula.

-----------

Carter pays $380.93 per month for 36 months.

He pays back a total of 380.93*36 = 13,713.48 dollars.

Subtract off the loan amount to determine the total interest.

13,713.48 - 13,000 = 713.48