What device is used to create static electricity

The volume of an element in n[tex]m^{3}[/tex] is 3×[tex]10^{27}[/tex] n[tex]m^{3}[/tex].

How are cubic nanometers converted from cubic meters?

When converting cubic meters to cubic nanometers, one must use the following conversion factor:

1 [tex]m^{3}[/tex] = 1×[tex]10^{27}[/tex] n[tex]m^{3}[/tex]

Given that the volume of an element is 3 [tex]m^{3}[/tex]

By using above conversion formula we can now convert as

⇒ 1 [tex]m^{3}[/tex] = 1×[tex]10^{27}[/tex] n[tex]m^{3}[/tex]

⇒ 3 [tex]m^{3}[/tex] = V

    V = (3×1×[tex]10^{27}[/tex]) [tex]m^{3}[/tex] n[tex]m^{3}[/tex] / 1 [tex]m^{3}[/tex]

     By canceling [tex]m^{3}[/tex] we get,

      V = 3×[tex]10^{27}[/tex] n[tex]m^{3}[/tex]

So the volume of an element after conversion is  3×[tex]10^{27}[/tex]n[tex]m^{3}[/tex].

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My walking speed is 1.75 m.

Speed can be defined as the ratio of distance to time.

To calculate the walking speed, we use the formula below.

Formula:

Where:

From the question,

Substiotute these values into equation 1

Hence, my walking speed is 1.75 m.

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When the voltage applied at the drain terminal is small, the mosfet channel behaves like a Current controlled voltage source.

An active load is created when the drain and gate of a MOSFET are coupled together, creating a two-terminal device known as a "diode-connected transistor." An active load is created when the drain and gate of a MOSFET are coupled together, creating a two-terminal device known as a "diode-connected transistor." The drain-source (or source-drain) connection of the MOSFET can be made open or connected by adjusting the charge distribution between the gate and body. Both NMOS and PMOS transistors function as switches in this way, but the specifics of the operation vary between the two types.

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A voltage sensor was used to probe and find the surfaces of electric potential.

One of the most widely utilized electrical quantities is electrical potential, which is essential for both storing and releasing electrical energy.

By dividing the potential energy by the total charge, the electric potential of any charge is calculated.

To measure the electrical potential difference between two locations in an electric circuit, a voltmeter is employed.

The electric potential difference between two places is determined using a voltmeter.

The electrical component whose potential difference is being measured is connected in parallel to voltmeters, which have high resistance.

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The molarity is 0.018M and the percentage is 8.46%.

Net ionic reaction is

[tex]$\mathrm{Cr} 2 \mathrm{O}^{2-}+6 \mathrm{Fe}^{2+}+14 \mathrm{H}^{+} \rightarrow 6 \mathrm{Fe}^{3+}+2 \mathrm{Cr}^{3+}+7 \mathrm{H} 2 \mathrm{O}$[/tex]

[tex]$1 \mathrm{~mol}$[/tex] of [tex]$\mathrm{Cr} 2 \mathrm{O} 7(-2)$[/tex] reacts with [tex]$6 \mathrm{~mol}$[/tex]of [tex]$\mathrm{Fe}(2+)$[/tex] to form [tex]$6 \mathrm{~mol}$[/tex]of [tex]$\mathrm{Fe}(3+)$[/tex] and [tex]$2 \mathrm{~mol}$[/tex] of [tex]$\mathrm{Cr}(3+)$[/tex]

Find molarity of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex]

Molarity = moles of[tex]$\mathrm{K} 2 \mathrm{Cr} 207 /$[/tex] Volume of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7(\mathrm{~L}$[/tex] )

Moles of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex] = grams of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 /$[/tex] molar mass of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex]

[tex]$=1.2275 \mathrm{~g} / 294.19 \mathrm{~mol}=0.0042 \mathrm{~g} / \mathrm{mol}$[/tex]

Molarity of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7=$[/tex] moles of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex]/ Volume of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex](L)

[tex]$=0.0042 \mathrm{~g} / \mathrm{mol} / 0.250 \mathrm{~L}=0.017 \mathrm{M}$[/tex]

Find molarity of [tex]$\mathrm{Fe}$[/tex] (II)

Molarity of [tex]$\mathrm{Fe}(\mathrm{II})=6 \times$[/tex]molarity of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 \times$[/tex]volume of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 /$[/tex]volume of [tex]$\mathrm{Fe}$[/tex] (II)

[tex]$=6 \times 0.017 \mathrm{M} \times 0.03598 \mathrm{~L} / 0.200 \mathrm{~L}$[/tex]

[tex]$=0.018 \mathrm{M}$[/tex]

Find moles of [tex]$\mathrm{Fe}(\mathrm{II})$[/tex]

Moles of [tex]\mathrm{Fe}($ II) =[/tex]molarity of [tex]$\mathrm{Fe}$[/tex] (II) [tex]$\times$[/tex] volume of [tex]$\mathrm{Fe}$[/tex] (II)

[tex]=0.018 \mathrm{M} \times 0.200 \mathrm{~L}=0.004 \mathrm{~mol}[/tex]

Find mass of Fe(II)

Mass of [tex]\mathrm{Fe}( II )=[/tex] moles of [tex]\mathrm{Fe}( II[/tex]) [tex]\times[/tex] molar mass of [tex]$\mathrm{Fe}(\mathrm{II})$[/tex]

[tex]$=0.004 \mathrm{~mol} \times 55.85 \mathrm{~g} / \mathrm{mol}$[/tex]

[tex]$=0.205 \mathrm{~g}$[/tex]

Find [tex]$\% \mathrm{Fe}(\mathrm{II})$[/tex] in unknown sample

[tex]$$\begin{aligned}\% \mathrm{Fe} &=(\text { mass of } \mathrm{Fe} / \text { weight of unknown sample }) \times 100 \\&=(0.205 \mathrm{~g} / 2.4234 \mathrm{~g}) \times 100 \\&=8.46 \%\end{aligned}$$[/tex]

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The impedance of the headphones can be chosen to be 32 ohms impedance.

           Z = V/I

The perceived resistance to the flow of an alternating current in an electrical circuit, which is comparable to the real electrical resistance to a direct current and which equals the ratio of effective electromotive force to effective current.

The magnitude of the impedance Z of a circuit is equal to the maximum value of the potential difference, and  voltage, V (volts) across the circuit, divided by the maximum value of a current I (amperes) through the circuit, or simply Z = V/I. The unit of impedance, such  that of resistance, is the ohm.

Case 1 :

I²R = 2P

p = 50nW

R = 8 ohm

so, on solving,

V = 0.89442 V

Case 2 :

I²R = 2P

p = 50nW

R = 32 ohm

so, on solving,

V = 1.788 V

Case 3 :

I²R = 2P

p = 50nW

R = 1000 ohm

so, on solving,

V = 10 V

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Answer: Polish creates a thin layer of wax on the surface of the leather which protects the leather from getting wet and undergoing wear and tear. It also has a lubricating effect on the leather keeping it supple and preventing the leather from drying out and cracking

The symbol of the element Carbon is C, its proton number is 6, its atomic mass is 12, its neutron number is 6 and finally carbon belong to period 2 of the periodic table.

This is defined as a substance cannot be further broken down by any chemical reaction and examples include oxygen, nitrogen etc.

Carbon is an element and has an atomic number of 6 with a mass number of 12 and is present in period 2 in the periodic table.

For all atoms with no charge, the atomic number is equal to the number of proton. The number of proton is also equal to the number of electron which is why they all have the same value of 6.

Neutron = atomic mass - atomic number

         = 12 - 6 = 6

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Considering the combined law equation the temperature increases by a factor of 1.5.

Gay-Lussac's Law

According to Gay-Law, Lussac's the gas molecules move more quickly as the temperature rises as long as the volume of the container holding the gas remains constant. The pressure then rises as a result of an increase in the number of shocks striking the walls. In other words, the relationship between a gas's pressure and temperature is direct.

In conclusion, when the volume remains constant, the pressure of the gas increases as the temperature rises. Additionally, gas pressure falls as temperature drops.

Gay-law Lussac's has the following mathematical formulation p/T =k so 3 P / T= 1/2 = 3/2 =1.5 =T

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Answer:

Is this psychology or something?

Publishers have the duty of supplying a platform for the exchange of medical data, whilst at the identical time, it's miles the duty of the authors, analysis magazine editors, and peer reviewers to ensure that the posted manuscripts are accurate.

It is through publication that the research, inclusive of their scientific and sensible contributions, is disseminated to others on a particular subject. This makes medical researchers and practitioners with comparable pastimes aware of the latest expertise in their field and it facilitates advanced know-how and its utility. at the same time as many editors and peer reviewers expect that studies posted in their journals have to be probably reproducible, there are no set methods to empirically check whether a finding may be independently reproduced.

A chief supply of irreproducibility additionally testing consists of widespread systematic blunders, that can arise while scientists are engaged in the experiments or all through statistical analyses Goodman et al 2016. Systematic errors can occur for a ramification of reasons, such as loss of medical talent two people acting in the same experiment may not have the same level of revel in or variability in issue populations or reagents Capes‐Davis & Neve, 2016. similarly, whilst a researcher has an insufficient statistical understanding or there are honest flaws inside the experimental layout and statistical output, the mistakes generated might inappropriately have an effect on the translation of the results Baker, 2016 Steen Casadevall, Fang 2013.

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The pressure is  2.43456 atm.

An atom or molecule has electrons all over it. Additionally, electrons are always traveling. Uneven electron distributions are possible at any time. The result is the creation of a transient dipole. Another transient dipole may develop in an atom next to this one as a result of this dipole. It causes a cascade of transient dipoles, which causes the atoms or molecules to attract one another. It's referred as Vander wall force.

We have van der waals equation and values given

use R = 0.0821 l atm/mol/k

[tex][P+an^2/V^2][v-nb] = nRT[/tex]

[tex][P+an^2/V^2] = nRT/[V-nb][/tex]

[tex][P+an^2/V^2]  = 1\times0.0821 l atm/mol/k\times298 K/[10 L ^{- 1}\times 0.04278 Lmol^{-1}][/tex]

[tex][P+an^2/V^2] = 24.4658/9.95722 = 2.45709[/tex]

[tex][P +2.253\times 1^2/(10)^2] = 2.45709[/tex]

P+ 0.02253 = 2.45709

P = 2.45709-0.02253 = 2.43456 atm

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Since the angle of incidence is 45° using the law of reflection we can conclude the reflective ray will also make an angle equal to the angle of incidence i.e. 45° with the normal.

1)The angle between the incident ray and the normal is equal to the angle between the reflected ray and the normal.

2)The incident ray, the normal and the reflected ray are all in the same plane.

3) Incident ray and refracted ray are on different sides of the normal.

Given:

Light rays strike at an angle of 45° to the plane.

Using the law of reflection we can easily draw the reflective wave.

Important terms:

Angle of incidence - it is the angle at which the light way strikes the plane mirror.

Angle of reflection- it is the angle at which the light way is reflected back by the plane mirror.

Now since the angle of incidence is 45° using the law of reflection we can conclude the reflective ray will also make 45° with the normal.

Hence the angle of incidence is 45° and also the angle of reflection is equal to the angle of incidence i.e.45°.

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The temperature of 21.6 g of a metal rises by 6.04 o c when the metal receives 60.0 j of heat , the identity of the metal is 0.46J/gC.

The amount of heat energy needed to raise a substance's temperature by one degree Celsius per unit mass of that substance is known as its specific heat.

The amount of energy required to raise or lower a substance's temperature by 1 unit of 1 kg of material is its specific heat capacity.

Specific heat and specific heat capacity are measured in SI units of J/Kg.

Mass of the metal = m =2.16g

the temperature of metal =ΔT=6.04C

Energy of metal = Q= 60.0J

c∝Q/ΔT

c=q/mΔT

c=60.0J/(21.6g)(6.04)

c=60.0J/130.464g.C

c=0.459896J/g.C

Hence the specific heat capacity is 0.46J/gC.

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A) Transform faults have a direction that is perpendicular to plate motion.

Consider the double line in the transform fault diagram to be the boundary of two diverging plates and consider which direction the diverging plates would be travelling.

Fewer transform faults rip across the lithosphere of the continent. The San Andreas Fault Zone in western North America is the most well-known illustration of this.

Occasionally referred to as a strike-slip boundary, a transform fault or transform boundary is a fault along a plate boundary where the motion.

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If a bag of flour contains 5.00 lbs of flour. you have 3.20 tons of flour. there are 2000 lbs per ton, then there would be 1280 bags of flour that can be made.

Finding the product of two or more numbers in mathematics is done by multiplying the numbers. It is one of the fundamental operations in mathematics that we perform on a daily basis.

As given in the problem, if a bag of flour contains 5.00 lbs of flour. you have 3.20 tons of flour. there are 2000lbs per ton,

The number of bags = 3.20*2000/5.00

                                   =1280 bags

Thus, there would be 1280 bags of flour.

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Answer:

25 m/s

Explanation:

1.25*20=25

The car acceleration at the rate of 1.25 m/s² in the time period of 20 seconds, then the change in velocity will be equal to 25 m/s.

Acceleration is the speed of change in both speed and distance of velocity over time. Anything is said to be propelled when it goes quickly or slowly in a straight line. So because direction is always moving, motion on a circle accelerate even while the speed is increased. Both effects add to, the accelerated for all other types of motion.

It is a vector field because accelerating has both a direction and magnitude. Another vector quantity is velocity. The velocity vector change during a certain period of time, divided by that period of time, is the definition of acceleration.

The given data according to the question is,

Acceleration, a = 1.25 m/s² and,

Time, t = 20 s

Velocity, v = 1.25 × 20

v = 25 m/s.

Therefore, the change in velocity will be equal to 25 m/s.

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The properties of Sodium are as follows:

Elements are defined as any substance which cannot be split into simpler units aby a ordinary chemical process.

Elements are classified into metal, non-metals and metalloids.

Sodium one of the known 118 elements.

In the period table, sodium has the following properties:

In conclusion, sodium is an element in the periodic table.

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45320 kN can be represented as 45.32×10³ kilo Newtons,568 mm can be represented as 0.568 meters and 0.00563 mg can be represented as 5.63×10³ micrograms.

A unit of measurement is a recognized and accepted standard for calculating other amounts of the same kind. It has already been decided by law or convention.

As stated in the issue, Use the proper prefix to represent each of the following as a number between 0.1 and 1000:

In this way, 45.32103-kilo Newtons, 0.568 meters, and 0.00563 mg may all be represented as 5.63103 micrograms, 45.32103-kilo Newtons, and 45.32103-kilo Newtons, respectively.

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Mass % of ethanol :  8.885

molality of ethanol : 2.12m

Given:

Wine = 11 % ethanol by volume

density of ethanal = 0.789 g/cm3

density of water = 1 g/cm3

let 100 cm3 wine  → 11.0 [tex]cm^3[/tex] ethanol, 89.0 [tex]cm^3[/tex] water.

Mass of ethanol = d x V = 0 789 g/cm3 x 11 cm3 = 8.679 cm3

Mass of water = d x Y = 1.000 g/cm3 x 89 cm3) = 89.00 cm3

Total mass of 100 cm3 wine = 8.679+89 = 97.679 cm3

Mass for % of ethanol = 8: 674 X100 = 8.8857 %

Molar mass of ethanol = 46 g/mole

Moles of ethanol = 8.679/46  = 0.1887 mole

Molality of ethanol = 0.1887/0.089 = 2.12 m

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The velocity of the body is 15.96 m/s.

We know that equations of kinematics could be used to obtain the velocity with which the pitcher would hit the ground. In this case we have the following;

Height of the ball = 13 m

Acceleration due to gravity = 9.8 m/s

Using;

v^2 = u^2 + 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height

u = 0 m/s since it was dropped from a height

v^2 = 2gh

v = √2 * 9.8 * 13

v = 15.96 m/s

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The gas temperature change if the volume is halved and the pressure is tripled by factor 6.

An ideal gas is theoretical gas composed of many randomly moving point particles that are not subject to interparticle interactions. The ideal gas concept is useful because it obeys ideal gas law, a simplified equation of state, and is amenable to analysis under statistical mechanics.

Considering combined law equation:

Temperature increases by factor of 6.

Gay-Lussac's Law

Gay-Lussac's Law indicates that, as long as volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then number of shocks against the walls increases, that is, the pressure increases. That is, gas pressure is directly proportional to its temperature.

In summary, when there is constant volume, as the temperature increases, the gas pressure increases. And when temperature decreases, gas pressure decreases.

Gay-Lussac's law can be expressed as mathematically as follows:

where:

P= pressure

T= temperature

k= Constant

Boyle's Law

Pressure and volume are related by Boyle's law, which says that volume occupied by a given mass of gas at constant temperature is inversely proportional to pressure.

Boyle's law is expressed mathematically as follows:

P× V=k

where:

P= pressure

V= volume

k= Constant

Charles's Law

Finally, Charles's Law consists of the relationship that exists between the volume and the temperature of certain amount of ideal gas, which is maintained at a constant pressure.

This law says that for given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, volume is directly proportional to the temperature of the gas.

In summary, Charles' law is a law that says that when amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

where:

V= volume

T= temperature

k= Constant

Combined law equation

Combined law equation is combination of three gas laws called Boyle's, Charlie's and Gay-Lussac's law:

Studying the two different states, an initial state 1 and an final state 2, the following will be true:

In this case, you know that:

Volume is double: V2= 2×V1

Pressure is tripled: P2= 3×P1

So, replacing in combined law equation:

Solving:

T2= 6×T1

Finally, temperature increases by a factor of 6.

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To travel a distance of 400 m the car will take a time of: 8.944 s

The formulas and procedures we will use to solve this exercise are:

Where:

Information about the problem:

Applying the final velocity formula  we have:

vf = √ (vi² + 2 * a * x)

vf = √ ((0 m/s)² + 2 * 10.0 m/s² * 400 m)

vf = √ (0 m²/s² + 8000 m²/s²)

vf = √(8000 m²/s²)

vf = 89.44 m/s

Applying the time formula we have:

t = (2 * x)/ (vi + vf)

t = (2 * 400 m)/ (0 m/s + 89.44 m/s)

t = 800 m / 89.44 m/s

t = 8.944 s

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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By using inductive reactance, the current is 0.93 A.

We need to know about inductive reactance to solve this problem. The inductive reactance is the internal resistance in the inductor caused by changing current. It can be described as

XL = ω . L

where XL is inductive reactance, ω is angular speed and L is inductance.

The angular speed can be determined by

ω = 2π . f

where f is frequency.

From the question above, we know that

f = 100 Hz

L = 16 mH = 16 x 10¯³ H

V = 9.4 V

By substituting the given parameters, we get

XL = ω . L

XL = 2π . f . L

XL = 2π . 100 . 16 x 10¯³

XL = 10.06 Ω

Find the peak current

V = I . XL

9.4 = I . 10.06

I = 0.93 A

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The correct answer is The object must be at equilibrium position. So, the displacement is obtained zero.

Given,

The simple harmonic motion has a time period of T = 2s

The amplitude of oscillation is A = 0.5 m

The displacement of the object from the equilibrium position at time t= 1.5 s should be determined.

At time t = 0 , the displacement of the object is maximum. For objects in SHM, the maximum displacement is equal to its amplitude.

The general equation of a particle in simple harmonic motion can be written as x = A sin(ωt + Φ) where A is the amplitude ω = 2π/T is the angular frequency and Φ is its initial phase which can be determined considering time t= 0 as follows,

x = A sin(ωt + Φ)

A = A sin ( ω × 0 + Φ )

sin Φ = 1

Φ = π/2

Therefore, the equation of the object in SHM becomes,

x = A sin(ωt + π/2)

x = A cos ωt ______(1)

Substituting, t = 1.5s the displacement can be obtained as,

x = 0.5 cos (2π/T × 1.5)

x = 0.5 cos (2π/2 × 1.5)

x = 0.5 (1.5 π)

x = 0

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Produces no change in the energy because total energy is independent of the mass.

Mechanical  energy = [tex]\frac{1}{2} \times K V^2[/tex]

K = Spring constant

A = Amplitude of oscillation

Mechanical energy is the sum of kinetic energy and potential energy in an object that's utilized to do a specific work. In other words, it describes the energy of an object since of its movement or position, or both. mechanical energy, sum of the kinetic energy.

Mechanical energy is the energy of either an object in movement or the energy that's put away in objects by their position.

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The MOV instruction for double word variable three is

mov ax, word ptr three

mov bx, word ptr three+2

mov three, bx

mov word ptr three+2, ax

; initialize DWORD three

three DWORD 12345678h

; move the lower word (5678h) to ax

MOV ax, WORD PTR three

; move the upper word (1234h) to bx

MOV bx, WORD PTR[three + 2]

; move bx to lower word of three

MOV WORD PTR three, bx

; move ax to upper word of three

MOV WORD PTR[three + 2], ax

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