Answers
Explanation:
760 mmHg (millimeters of mercury) is a measure of atmospheric pressure. It represents the height of a column of mercury at which the static pressure at the bottom is equal to the atmospheric pressure.
1 atm = 760 mmHg = 101,325 Pa = 14.7 psi
Related Questions
The energy stored in a wood log is transformed when the log is burned. Which of the following explanations best describes how the
chemical energy stored in the log compares to the heat and light energy produced by burning?
O A The chemical energy is equal to the amount of heat, light, and other applicable energies.
O B The chemical energy is less than the amount of heat, light, and other applicable energies.
OCThe chemical energy is more than the amount of heat, light, and other applicable energies.
D. The chemical energy stays the same; additional energy is produced as heat, light, and other applicable energies.
Answers
Answer:
D. The chemical energy stays the same; additional energy is produced as heat, light, and other applicable energies.
Hope this helps!
The chemical energy stays the same; additional energy is produced as heat, light, and other applicable energies. Thus option D is correct.
What is chemical energy ?Energy is the ability to do work It can be movement of a body to do some physical activity.
If the energy is stored in the form of chemical bonds of a complex molecule then the energy is called as chemical energy.
The energy released in the chemical reaction and produced as as a by-product, that process is known as an exothermic reaction.
For instance, chemical energy sored in biomass, batteries, natural gas, petroleum, and coal.
Dry wood also the storage of chemical energy, as it burns the chemical energy is released and converted into light energy and thermal energy
The food we eat is also an example of chemical energy storage as it is liberated during digestion process.
Thus option D is correct.
Learn more about energy, here:
https://brainly.com/question/1397271
#SPJ2
The resultant velocity with respect to the ground of a fighter
plane flying at 100 km/hr air speed will be
encounters a 45 km/hr tailwind.
Answers
Answer:145 km/hr
Explanation: v1+v2 100+45 =145 km/hr
You are riding in a car that is moving at 50 m/s north.
You pull a gun out while driving and fire a bullet north at 100 m/s. If the ground is the frame of refernce, then the bullet is traveling at
m/s relative to the ground
Answers
Answer:
the bullet is traveling at 150 m/s relative to the ground
Explanation:
The two velocities are pointing in the same direction (both pointing North) therefore, they should add.
Then, from the ground frame of reference the bullet is travelling at: 50 m/s + 100 m/s = 150 m/s
The
reflex causes a
newborn to turn toward the source of any
touching that occurs around his mouth.
Answers
Answer:
rooting reflex
Explanation:
prettysure
A lounging leopard decides to come down out of her tree and hunt for her lunch in the savanna. The graph above represents the motion of the leopard as a function of time.
What is the distance traveled by the leopard during the entire 11 seconds? Please include a number and uni
Answers
An air filter can remove dust particles from air but will reach capacity (saturation) at 50.0 mg. Of air containing 225 µg dust particles per m3 air is passed through the filter at 400 ft3 /min and air leaving the filter has 15.0 µg dust/m3 air, how much time, in days, is required for the filter to reach saturation
Answers
Answer:
Time to Reach Saturation = 0.0146 day
Explanation:
In order to solve this problem, we first need to calculate the dust filtered by the filter per cubic meter of air:
Filtered Dust per m³ = Dust Particles Entering per m³ - Dust Particles Leaving per m³
Filtered Dust per m³ = 225 μg/m³ - 15 μg/m³
Filtered Dust per m³ = 210 μg/m³ = 210 x 10⁻³ mg/m³
Now, we find volume flow rate of air through filter:
Volume Flow Rate of Air = (400 ft³/min)(0.3048 m/1 ft)³
Volume Flow Rate of Air = 11.33 m³/min
Now, we calculate rate of dust filtered:
Rate of Dust Filtered = (Filtered Dust per m³)(Volume Flow Rate of Dust)
Rate of Dust Filtered = (210 x 10⁻³ mg/m³)(11.33 m³/min)
Rate of Dust Filtered = 2.38 mg/min
Now, for the time required to reach saturation:
Time to Reach Saturation = (Saturation Capacity)/(Rate of Dust Filtered)
Time to Reach Saturation = (50 mg)/(2.38 mg/min)
Time to Reach Saturation = (21.02 min)(1 day/24 h)(1 h/60 min)
Time to Reach Saturation = 0.0146 day
You attach a meter stick to an oak tree, such that the top of the meter stick is 1.471.47 meters above the ground. Later, an acorn falls from somewhere higher up in the tree. If the acorn takes 0.2810.281 seconds to pass the length of the meter stick, how high h0h0 above the ground was the acorn before it fell, assuming that the acorn did not run into any branches or leaves on the way down?
Answers
Answer:
The value is [tex]h_a = 1.712 \ m [/tex]
Explanation:
From the question we are told that
The height of the top meter stick above the ground is [tex]h_1 = 1.47 \ m[/tex]
The time taken for the acorn to pass the length of the stick is [tex]t = 0.281 \ s[/tex]
Generally the height of the acorn at the point it is the same height with the metered stick is mathematically represented as
[tex]h = h_m = u_a * t + \frac{1}{g} t^2[/tex]
Here [tex]h_m[/tex] is height of the meter stick and the value is 1 m (This because we are told in the question that the stick is 1 meter in length ( a meter stick))
So
[tex]1 = u_a * 0.281 + \frac{1}{9.8} (0.281)^2[/tex]
=> [tex]u_a = -2.2 \ m/s[/tex]
Generally the velocity of the acorn just before passing the top of the meter stick is mathematically represented by a kinematic equation as
[tex]u^2_a = u^2 + 2gs[/tex]
here u is zero since the acorn started from rest
So
[tex] (-2.2) = 0 + 2 * 9.8 * s[/tex]
[tex]s = 0.242 \ m[/tex]
Generally the height of the acorn is
[tex]h_a = h_1 + s[/tex]
[tex]h_a = 0.242 + 1.47[/tex]\
[tex]h_a = 1.712 \ m [/tex]
g A very early, simple satellite consisted of an inflated spherical aluminum balloon 38 m in diameter and of mass 22 kg. Suppose a meteor having a mass of 21 kg passes within 8.0 m of the surface of the satellite. What is the magnitude of the gravitational force on the meteor from the satellite at the closest approach?
Answers
Answer:
6.37*10^-13 N
Explanation:
Given that
We r = 38/2 = 14 m
m1 = 22kg
m2 = 21 kg
so we can say that distance between center of the satellite and meteor,
d = r + h
= 14 + 8
= 22m
So the gravitational force on the meteor, is
F = G x m1 x m2/d²
= 6.67*10^-11 x 21 *22/22²
= 6.37*10^-13 N
What example represents a healthy alternative to curb nicotine cravings?
O candy bars
O potato chips
O sugar-free gum
o chewing tobacco
Answers
Answer:
C.sugar-free gum
Explanation:
What was the velocity of a dog that ran 50 meters in 15 seconds?
Answers
Answer:
5m/s
Explanation:
there are 3,600 seconds per hour so 5•3600 18,000 hours and 18 km/h
Answer:
velocity = 3.33 m/sec
Explanation:
velocity = distance / time
where
distance = 50 meters i
time = 15 seconds
plugin values into the formula
velocity = 50 m
15 sec
velocity = 3.33 m/sec
A person is wandering in woods and records his movements as a sequence of displacements: d1 is 351 m, 35.0° north of east; d2 is 252m, 55.0° west of north; d3 is 178 m, 35.0° south of west; and d4 is 253 m, 15.0° north of west. Find his displacement going back to his starting point straight.
Answers
Answer:
18.64
Explanation:
A proton (mass=1.67x10^-27 kg, charge= 1.60x10^-19 C) moves from point A to point under the influence of an electrostatic force only. At point A the proton moves with a speed of 50 m/s. At point B the speed of the proton is 80 km/s. Determine the potential difference VB-VA in volts.
Answers
Answer:
[tex]VB - VA = - 33.4[/tex]
Explanation:
Generally the workdone in moving the proton is mathematically represented as
[tex]W = KE_f - KE_i[/tex]
Where [tex]KE_i \ and \ KE_f \ are\ the\ initial \ and \ final \ kinetic \ energy [/tex]
So
[tex]KE_i = \frac{1}{2} m v_a^2[/tex]
Here [tex]v_a[/tex] is the velocity at A with value 50 m/s
So
[tex]KE_i = \frac{1}{2} (1.67*10^{-27}) * 50^2 [/tex]
[tex]KE_i = 2.09 *10^{-24} \ J [/tex]
Also
[tex]KE_f = \frac{1}{2} m v_b^2[/tex]
Here [tex]v_a[/tex] is the velocity at A with value [tex]80 km/s = 80000 m/s [/tex]
=> [tex]KE_f = \frac{1}{2} (1.67*10^{-27}) * 80000^2 [/tex]
=> [tex]KE_f = 5.34 *10^{-18} \ J[/tex]
So
[tex]W = 5.34 *10^{-18} - 2.09 *10^{-24}[/tex]
[tex]W = 5.34 *10^{-18} m/s[/tex]
Now this workdone is also mathematically represented as
[tex]W = q * V[/tex]
So
[tex] q * V = 5.34 *10^{-18} [/tex]
Here [tex]q = 1.60*10^{-19} C[/tex]
So
[tex] V = \frac{5.34 *10^{-18} }{1.60*10^{-19}}[/tex]
[tex] V = 33.4 \ V [/tex]
Generally proton movement is in the direction of the electric field it means that [tex] VA>VB [/tex]
So
[tex]VB - VA = - 33.4[/tex]
The classic Millikan oil drop experiment was the first to obtain an accurate measurement of the charge on an electron. In it, oil drops were suspended against the gravitational force by a vertical electric field. Consider an oil drop with a weight of 2.9 x 10-14N, if the drop has a single excess electron, find the magnitude (in N/C) of the electric field needed to balance its weight. Your should round your answer to an integer, indicate only the number, do not include the unit.
Answers
Answer:
[tex]E=1.81\times 10^5\ N/C[/tex]
Explanation:
In Millikan oil drop experiment, oil drops were suspended against the gravitational force by a vertical electric field such that its weight is balanced by the electron force i.e.
W = qE,
W is weight, W = mg
q is charge,
E is electric field
⇒ [tex]2.9\times 10^{-14}\ N=qE[/tex]
or
[tex]E=\dfrac{2.9\times 10^{-14}\ N}{1.6\times 10^{-19}\ C}\\\\E=181250\ N/C\\\\\text{or}\\\\E=1.81\times 10^5\ N/C[/tex]
So, the magnitude of the electric field is [tex]1.81\times 10^5\ N/C[/tex].
Which of these is an example of acceleration? A a bicyclist turning around a corner B a car traveling south with its cruise control set C a bus traveling north at 25m/s D a helicopter waiting to take off
Answers
The answer is A.
Acceleration means when you go faster in speed. Since the bicyclist is turning, he has to slow down but when he finishes turning, he is going to pedal harder and gain more speed. This is called Acceleration.
Best of Luck!
Answer:
a
Explanation:
Unlike velocity, speed is scalar, which means it is described by
Answers
Answer:
Magnitude
Explanation:
Scalar quantitys have no direction only a size aka magnitude
In a house, a circuit often includes multiple electrical outlets which are parallelconnected to a single voltage source. Each of these circuits also contains a 15-A circuit breaker. Design a parallel-connected circuit which shows three electrical outlets connected to a voltage source with a circuit breaker. What is the advantage of having outlets parallel-connected, and why is a circuit breaker connected in series with the voltage source
Answers
Answer:
In parallel circuits, if one element has a problem, it can be eliminated and the rest of the elements continue to work.
Explanation:
There are two ways to connect electrical circuits, in series and in parallel.
Series circuits have the problem that when one element is damaged, the entire circuit is interrupted and runs out of power.
In parallel circuits, if one element has a problem, it can be eliminated and the rest of the elements continue to work.
In Breaker it is connected in series so that when some maintenance is needed, all the energy can be interrupted simultaneously and if some equipment tries to consume a lot of energy, the circuit prevents this action by interrupting the energy of the entire circuit
If we want to find the size of the force necessary to just barely overcome static friction (in which case fs=μsNfs=μsN), we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as:
Answers
Complete Question
Two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. The block in ( The diagram is shown on the first uploaded image ) has a mass m= 10kg and is being pulled by a force F on a table with coefficient of static friction μs=0.3. Four forces act on it:
The applied force F (directed θ=30∘ above the horizontal).
The force of gravity Fg=mg (directly down, where g=9.8m/s2).
The normal force N (directly up).
The force of static friction fs (directly left, opposing any potential motion).
If we want to find the size of the force necessary to just barely overcome static friction (in which case fs=μsN), we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as:
Fcosθ−μsN=0
Fsinθ+N−mg=0
In order to find the magnitude of force F, we have to solve a system of two equations with both F and the normal force N unknown. Use the methods we have learned to find an expression for F in terms of m, g, θ, and μs (no N)
Note the diagram is shown on the first uploaded image
Answer:
The expression for F is [tex]F = \frac{\mu_s * m* g}{[\mu_s * sin (\theta )] * cos (\theta)}[/tex]
Explanation:
Generally from the diagram we see that
[tex]Fcos\theta -f_s = 0[/tex]
From the question we are told that
[tex]f_s = \mu_s * N[/tex]
So
[tex]Fcos\theta - \mu_s * N = 0[/tex]
=> [tex] N = \frac{Fcos(\theta)}{\mu_s}[/tex]
Also from the diagram
[tex]Fsin(\theta )+N - F_g = 0[/tex]
Here [tex]F_g = m * g[/tex]
So
=> [tex]Fsin(\theta )+ \frac{Fcos(\theta)}{\mu_s} - m* g = 0 [/tex]
=> [tex]F = \frac{\mu_s * m* g}{[\mu_s * sin (\theta )] * cos (\theta)}[/tex]
Two masses m1m1 and m2m2 exert a gravitational force of 12 N onto each other when they are 6 m apart. What will the gravitational force be if the masses are moved closer to be 3 m apart?
Answers
Answer:
48N
Explanation:
because as the distance is halfed. the force on the two objects are quadrupled.
Point charges of 16.7 nC and 47.3 nC are placed 0.500 m apart. What is the electric field halfway between them? Indicate direction by a positive or a negative value. Keep in mind that a positive vector is one directed to the right and a negative vector is one directed to the left. Your answer should be a positive or a negative number with two decimal places, do not include the unit. Hint: 1 nC = 10-9 C
Answers
Answer:
-4320
Explanation:
Using the formula for electric field between two points
E = kq/r²
The electric field at a midpoint, say x, is
E(x) = [(k * 16.7*10^-9)/0.5²] - [(k * 47.3*10^-9)/0.25²]
E(x) = [k * (16.7*10^-9 - 47.3*10^-9)/0.25²]
E(x) = [(k * -30.6*10^-9)/0.0625]
E(x) = [(9*10^-9 * -30.6*10^-9)/0.0625]
E(x) = -270/0.0625
E(x) = -4320
Therefore, we can conclude that the electric field, halfway in between them is -4320
1. A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its
speed is 4 m/s. But 3 seconds later, at the bottom of the slope, its speed is 22 m/s. What is its
average acceleration?
Answers
Answer:
6 m/s²
Explanation:
Average acceleration = change in velocity / change in time
a = Δv / Δt
a = (22 m/s − 4 m/s) / 3 s
a = 6 m/s²
Answer:tryna get points don't mind me
Explanation:
In a study of the effect of lighting on work productivity, the workers were told
that the lights would be changed on Monday, and researchers would measure
their response. The fact that the workers produced more than ever might not
be due to the lighting, but to the:
A. placebo effect
B. Hawthorne effect.
C. hypothesis theory,
D. informed consent theory.
Answers
Answer:
B. Hawthorne effect.
Explanation:
APEX
Answer:
b
Explanation:
Apex as always :)
What does Rockstrom mean by the need to "bend the curves"?
Answers
Answer: Rockstrom meant that it's going to be a challenging decade and that people will need to work hard and also bend the curve by thinking around the curve.
Explanation:
Some years ago, Johan Rockström, who was the executive director of Stockholm Environment Institute, and a professor at Stockholm University, was the head of an international team that was assembled in defining planetary boundaries.
The that was gathered to speak regarding issues that pertained to the Earth ane how it can be protected from being infiltrated ad protecting it from failing. During the conversation, Rockstrom said that it's going to be a challenging decade and that people will need to work hard and also bend the curve by thinking around the curve.
A cylindrical tank of methanol has a mass of 60 kg and a volume of 75 L. Determine the methanol’s weight, den-sity, and specific gravity. Take the gravitational acceleration to be 9.81 m/s2. Also, estimate how much force is needed to accelerate this tank linearly at 0.25 m/s2.
Answers
Answer:
Weight = 588.6 N
Density = 800 kg/m³
Specific Gravity = 0.8
Force = 147.15
Explanation:
W = mg
W = 60 * 9.81
W = 588.6 N
Volume from L to m³ would be
75 L = 75 * 1/1000
75 L = 0.075 m³
Recall, density = mass/volume, so then, density of methanol is.
Density = 60/0.075
Density = 800 kg/m³
Specific gravity, SG is equal to
SG = density of methanol/density of water
SG = 800/1000
SG = 0.8
the force needed to accelerate the tank, F = ma
F = 588.6 * 0.25
F = 147.15 N
Therefore, the needed variables are
Weight = 588.6 N
Density = 800 kg/m³
Specific Gravity = 0.8
Force = 147.15
How is pressure related to the area
Answers
The more the pressure, the lesser the area, and vice-versa.
Two forces P and Q act on an object of mass 9.00 kg with Q being the larger of the two forces. When both forces are directed to the left, the magnitude of the acceleration of the object is 1.20 m/s2. However, when the force P is directed to the left and the force Q is directed to the right, the object has an acceleration of 0.600 m/s2 to the right. Find the magnitudes of the two forces P and Q in newtons.
Answers
Answer:
P = 2.7 N
Q = 8.1 N
Explanation:
Q > P
Both the forces are acting towards the left
Net force = Q + P
Applying newton's 2nd law
net force = mass x acceleration
Q + P = 9 x 1.2 = 10.8 ----------------- ( 1 )
In the second case Q is acting towards the left and P acts towards the right
so they act in opposite direction
Hence net force = Q - P
Applying newton's 2nd law
net force = mass x acceleration
Q - P = 9 x .6 = 5.4 -------------------- ( 2 )
Adding ( 1 ) and ( 2 )
2 Q = 16.2
Q = 8.1 N
From ( 1 )
8.1 + P = 10.8 N .
P = 2.7 N
A wind turbine with a rotor diameter of 40 m produces 90 kW of electrical power when the wind speed is 8 m/s. The density of air impinging on the turbine is 1.2 kg/m3. What fraction of the kinetic energy of the wind impinging on the turbine is converted to electrical energy
Answers
Answer:
0.233
Explanation:
Given that
Diameter of rotor, d = 40 m
Power of rotor, P = 90 kW
Speed of the wind, v = 8 m/s
Density of air, p = 1.2 kg/m³
It is a known fact that
KE = ½mv², where mass flow rate, m
m = p.A.v, where Area, A
A = πd²/4
A = (3.142 * 40²)/4
A = 3.142 * 1600/4
A = 3.142 * 400
A = 1256.8 m², substitute for A in the mass flow rate equation
m = p.A.v
m = 1.2 * 1256.8 * 8
m = 12065.28, substitute for m in the KE equation
KE = ½mv²
KE = ½ * 12065.28 * 8²
KE = 12065.28 * 32
KE = 386088.96 W or
KE = 386.1 kW
Fraction of kinetic energy converted to electric energy is
Fraction = Electric Power / Total KE
Fraction = 90 / 386.1
Fraction = 0.233
The gravitational pull of the sun on Earth keeps Earth orbiting around the sun. Which statement is correct about the force that Earth exerts on the sun?
Answers
Explanation:
The gravitational force exerted by the sun on the earth keeps the earth moving or orbiting around the sun in its orbit. This force is same with force with which the earth pulls the sun or exerts on the sun.
But the sun does not orbit around the earth because of this force since the sun is more massive then earth but the earth is less massive and it is accelerated by this massive force of the sun and moves around the sun in its orbit.
Answer:
Earth pulls the sun towards itself with a force equal to the ratio of the mass of the sun to the mass of Earth
Which of the following is a physical property? 1.flammability 2.acidity 3.color 4.rusting
Answers
Answer:
Color is a physical property, the rest are chemical properties.
A runner is jogging in a straight line at a
steady vr= 5.9 km/hr. When the runner is
L= 6.6 km from the finish line, a bird begins
flying straight from the runner to the finish
line at vb= 29.5 km/hr (5 times as fast as
the runner). When the bird reaches the finish
line, it turns around and flies directly back to
the runner.
What cumulative distance does the bird
travel? Even though the bird is a dodo, assume that it occupies only one point in space
(a "zero" length bird), travels in a straight
line, and that it can turn without loss of
speed.
Answer in units of km.
Answers
Answer:
11.88 km
Explanation:
Given that the bird begins flying straight from the runner to the finish
line at vb= 29.5 km/hr (5 times as fast as the runner). When the bird reaches the finish line, it turns around and flies directly back to the runner.
Then the first distance covered by the bird is 6.6 km.
Since the speed of the bird is five times the speed of the man, the man must have covered the distance one - fifth of the 6.6 km. That is,
1/5 × 6.6 = 1.32
Take 1.32 away from 6.6 you will get
6.6 - 1.32 = 5.28
The cumulative distance the bird
travel will be:
Cumulative distance = 6.6 + 5.28 = 11.88km
Therefore, the cumulative distance the bird travelled is 11.88 km
is weight included in free body diagram
Answers
Answer:
Yes
Explanation:
I took physics last year that that was a requirement.
