Which of the following isn't an example of numerical data?
A.Height
B.Weight
C.Gender
D.Temperature
Answer:
Gender
Explanation:
Diamonds are measured in carats, where 1 carat = 0.200 g. The density of diamond is 3.51 g/cm^3. What is the volume of a 5.50 carat diamond?
Answer:
5.0 carat x (0.200g / 1 carat) x (1 cm³ / 3.51g) = 0.28 cm³... with 2 sig figs..
Explanation:
USE DIMENSIONAL ANALYSIS. That is the point of this problem. That is why Dr. Zumdahl wrote this problem and put it in his textbook (chpt 1 Problem #57 if you're using the 7th edition, chpt1 problem #63 if you're using his 8th edition).
An object has a mass of 33g and a volume of 11ml. What is it's density?
Answer:
3g/ml
Explanation:
Density = [tex]\frac{33g}{11ml}[/tex]
33 divided by 11 = 3
Which type of rock is a foliated metamorphic rock?
A. granite
B. marble
C. quartzite
D. slate
Answer:
D. Slate
Explanation:
Because when it come to think of it then you see that slate is arranged with many parallel layers just like a foliated metamorphic rock.
P.S I took the test and got a 100
Slate is a type of foliated metamorphic rock formed when rocks are subjected to heat,high pressure,etc.
What are metamorphic rocks?Metamorphic rocks are defined as a type of rock which is substantially changed from igneous or sedimentary rocks.They are formed when rocks are subjected to high heat, pressure,hot minerals and even combination of these factors.
Metamorphic rocks are formed by the process of metamorphism which does not melt the rocks rather they are transformed into denser and compact rocks.
New minerals are created by the rearrangement of of minerals or by the reaction of fluids withe the rocks.Metamorphic rocks are often smeared and folded.
Common metamorphic rocks are marble,gneiss,quartzite ,etc.There are two types of metamorphic rocks :foliated and non-foliated metamorphic rocks.
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What made the discovery of cells possible? (1 point)
O the observation of cells by Hooke and Pasteur
o the invention of the microscope
o the use of magnifying glasses
o the study of viruses and bacteria
Answer:
the invention of the microscope
Explanation:
because cells are very tiny and cant be seen to the humans naked eye
What is a good example of homeostasis?
Your body aging overtime
ice melting into water on a warm day (my guess)
weather patterns changing based on the season
a corspe presserved at absolute zero temperature
Answer:
it is:
a corpse preserved at absolute zero temperature
Explanation: hope it helped
A good example of homeostasis is a corpse preserved at absolute zero temperature. The correct option is D.
What is homeostasis?Homeostasis is the ability of the body to adapt according to the environment. The process of homeostasis is important for the survival of life. This term was given by Walter Cannon in 1933.
Homeostasis is of different types. They are thermoregulation, blood glucose regulation, calcium homeostasis, potassium homeostasis, osmoregulation, etc.
The human body keeps the temperature of the body remains stable every the environmental temperature is increasing or decreases. Because an optimum temperature is necessary for performing various functions.
Thus, the correct option is D. a corpse preserved at absolute zero temperature.
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John used an empty beaker with the mass of 53.126 g. In a separate jar, he had a mixture of salt and sand. He transferred two scoops of salt and sand mixture to the beaker. The overall mass was 65.449 g. As you know salt is soluble in water, he added enough water in the beaker with salt and sand mixture to completely dissolve the salt. He filtered the mixture and dried what was left in the filter. The mass of that residue was 8.200 g. Based on the experiment calculate the mass of salt, sand and the mixture (salt sand).
Answer:
[tex]m_{mixture}=12.323g[/tex]
[tex]m_{sand}=8.200 g[/tex]
[tex]m_{salt}=4.123g[/tex]
Explanation:
Hello,
In this case, since the mass of the empty beaker is 53.126 g and with the mixture is 65.449 g, we can compute the mass of the whole mixture (water, sand and salt) via subtraction:
[tex]m_{mixture}=65.449g-53.126g=12.323g[/tex]
In such a way, since the residue obtained via filtration was sand only as it is not soluble in water, we infer that the mass of sand is 8.200 g:
[tex]m_{sand}=8.200 g[/tex]
Finally, since the mixture is composed by salt and sand, the mass of salt is:
[tex]m_{salt}=m_{mixture}-m_{sand}=12.323g-8.200g\\\\m_{salt}=4.123g[/tex]
Best regards.
Solve for x, where M is molar and s is seconds. x=(5.3×103M−2s−1)(0.26M)3
Answer:
guys can u solve my ques plz
typically, over 60% of the mass of a piece of bubble gum is made up of sugar. sugar is dissolved in the mouth and swallowed during chewing. if gum is chewed precisely until it loses its flavor, most if not all of the sugar content of the gum should be gone. how would this affect the mass of the gum? how will the mass of gum be affected by chewing time? how does the chewing time necessary to lose significant mass compare between different brands/types of gum? how large a role does saliva play in the processing of gum in the mouth?
Answer:
Hello your question is incomplete attached below is the complete question
A) How the mass will be affected by chewing time
The chewing time is an independent variable while the mass of the gum is a dependent variable and would change with increase in chewing time as seen in the regular gum the average mass increase above the average sugar mass before chewing
B) how the chewing time necessary to lose significant mass
The chewing time is neccessary to lose significant mass as seen in the sugar free chewing gum because the more time the gum is chewed the lesser the mass due to the absence/lose of sugar
C) The role saliva play in the processing of gum in the mouth
The saliva mixes up with the sugar contained in the chewing gum to increase its mass as seen when you compare the mean mass value of sugar contained in the regular chewing gum with the mean mass value of the gum after chewing for some time i.e 3.58 < 5.03 , 4.09
Explanation:
we will make two assumptions in order to resolve the given problem
next we have to calculate the mean(average) mass of the Chewing gums for each time interval
Regular gum :
initial mean mass = 5.96
mean mass after 1 minute = 5.03
mean mass after 2 minutes = 4.09
next we calculate the mean mass of sugar in the regular gum using this relationship :summation of( initial masses * 60/100 )/ 4 = 3.58 comparing it the the mass of the chewing gum at different time intervals i.e 1 minute and 2 minutes
sugar free gum :
initial mean mass = 2.98
mean mass after 1 minute = 2.59
mean mass after 2 minutes = 2.32
A) How the mass will be affected by chewing time
The chewing time is an independent variable while the mass of the gum is a dependent variable and would change with increase in chewing time as seen in the regular gum the average mass increase above the average sugar mass before chewing
B) how the chewing time necessary to lose significant mass
The chewing time is neccessary to lose significant mass as seen in the sugar free chewing gum because the more time the gum is chewed the lesser the mass due to the absence/lose of sugar
C) The role saliva play in the processing of gum in the mouth
The saliva mixes up with the sugar contained in the chewing gum to increase its mass as seen when you compare the mean mass value of sugar contained in the regular chewing gum with the mean mass value of the gum after chewing for some time i.e 3.58 < 5.03 , 4.09
Which of the following is true concerning ψ²? A) ψ² describes the probability of finding an electron in space. B) ψ² describes the exact path of electron motion in an orbital. C) ψ² describes the electronic structure of the atom according to the Bohr model. D) ψ² describes the exact volume of an atom. E) ψ² describes the size of an atom.
Answer:
A) ψ² describes the probability of finding an electron in space.
Explanation:
The Austrian physicist Erwin Schrödinger formulated an equation that describes the behavior and energies of submicroscopic particles in general.
The Schrödinger equation incorporates both particle behavior, in terms of mass m, and wave behavior, in terms of a wave function ψ, which depends on the location in space of the system (such as an electron in an atom).
The probability of finding the electron in a certain region in space is proportional to the square of the wave function, ψ². According to wave theory, the intensity of light is proportional to the square of the amplitude of the wave, or ψ². The most likely place to find a photon is where the intensity is greatest, that is, where the value of ψ² is greatest. A similar argument associates ψ² with the likelihood of finding an electron in regions surrounding the nucleus.
Identify the molecules or ions below as Lewis acids, Lewis bases, or neither. If there is more than one possible site in the molecule/ion, focus on the central or the charged atom. a) _________ b) _________ c) _________ Submit AnswerRetry Entire Group2 more group attempts remaining Show HintPreviousNext
Answer:
This question is incomplete because of the absence of the molecules been referred to in the question. However, the molecules been referred to in the question is in the attachment below
Explanation:
First of all, we have to define lewis acid and lewis base.
A lewis acid is a substance that has the capacity to accept a pair of electrons. For example, H⁺. While a lewis base is a substance that is capable of donating a pair of electrons (to a lewis acid). For example, OH⁻.
Going by the definitions above, we can deduce the type of substance the molecules in the question (attachment) are
a. BF₃ (boron trifluoride) is a lewis acid because the central atom (as suggested to be focused on in the question) which is boron, has the capacity to accept a pair of electrons.
b. The central atom (carbon) in the compound (2-methyl propane) also has the capacity to accept a pair of electrons since it is positively charged (is electron deficient). Hence, it is a lewis acid.
c. The functional group in this compound (trimethyl borate) is the ether. Ethers are generally lewis bases because the oxygen atom in an ether can donate a pair of electrons from it's lone pair. However, the presence of boron which is central to the compound shows it is also a lewis acid, although weak (majorly due to the presence of the ethers).
What are some examples of matter?
Answer:
An apple.
A person.
A table.
Air.
Water.
A computer.
Paper.
Iron.
Hope this helps you
Answer:
your boddy is made of mater and a clock too it is still a mater of time.
Explanation:
Why do you think Democritus and dalton are grouped together
Democritus and Dalton are grouped together because they had similar opinion about the existence of atom.
Who is Democritus?Democritus is an ancient Greek philosopher who is remembered for his formulation of an atomic theory.
Who is Dalton?Dalton is an english chemist who is known for introducing the theory of atom to chemistry.
What is an atom?An atom is the smallest unit of matter.
According to Democritus's theory of atom, all matter is made up of tiny particles called atoms and according to Dalton all matter is made up of tiny indivisible particles called matter.
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Please help
1. The atomic number tells us how many ____________ an element has.
protons
neutrons
electrons
atomic number tells us how many neutrons an element has
An example of International System of Measurement (SI) unit is:
A) pound <<
B) mile
C) liter
D) ounce
Answer:
the answer is A pound, I'm guessing
Which of the following additions to alkenes occur(s) specifically in an syn fashion?
A) dihydroxylation using Os04, H202
B) addition of H2
C) hydroboration
D) addition of HCI
E) A, B, and C
Answer:
E) A, B, and C
Explanation:
Syn addition refers to the addition of two substituents on the same face or side of a double bond. This differed from anti addition which a occurs across opposite face of the double bond.
Hydrogenation, hydroboration and dihydroxylation all involve syn addition to the double bond, hence the answer chosen above.
Dihydroxylation using Os04, H202, Addition of H2 and Hydroboration to
alkenes occur in a syn fashion.
Syn addition refers to the addition of two substituents( compounds) on the
same side thereby increasing the number of substituents and a decrease in
the bond order.
Hydrogenation, hydroboration and dihydroxylation all undergo syn addition which is the addition of the substituent to the same side which is why it is the right choice.
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How many nanometers are in 6.50 times 10^2 terameters?
Answer:
6.50×10² terameters is equal to 6.5 × 10²³ nm.
Explanation:
We need to find how many nanometers are in 6.50×10² terameters.
6.50×10² terameters = 650 terameters
It means we have to find how many nanometers in 650 terameters. We must know that conversion from one unit to another.
We know that,
1 terameter = 10¹² metres
and 1 metre = 10⁹ nm
So,
650 terameters = 650 × 10¹² metres
or
650 × 10¹² metres = 650 × 10¹² × 10⁹ terameters
Hence, 6.50×10² terameters is equal to 6.5 × 10²³ nm.
You should only change one variable at a time in an experiment.
True or False
Answer:True
Explanation:
Answer:
True
Explanation:
At liftoff, a space shuttle uses a solid mixture of ammonium perchlorate and aluminum powder to obtain great thrust from the volume change of solid to gas. In the presence of a catalyst, the mixture forms solid aluminum oxide and aluminum chloride and gaseous water and nitrogen monoxide.A. Write a balanced equation for the reaction, assign oxidation states for all atoms, and identify the reducing and oxidizing agents.B. How much aluminum oxide can you make when you react 150.0 g of ammonium perchlorate with 50.0 g of powdered aluminum
Answer:
A) 3NH₄ClO₄ + 3Al ---> Al₂O₃ + AlCl₃ + 6H₂O + 3NO
B) 150 g of ammonium perchlorate will produce 43.4 g of aluminum oxide
Explanation:
A)Balanced equation of reaction:
3NH₄ClO₄ + 3Al ---> Al₂O₃ + AlCl₃ + 6H₂O + 3NO
Oxidation states:
Nitrogen, N: from -3 to +2
Hydrogen, H: from +1 to +1
Chlorine, Cl: From +7 to -1
Oxygen, O: from -2 t0 -2
Aluminum, Al: from 0 to +3.
Oxidizing agent is ammonium perchlorate while the reducing agent is the aluminum powder.
B) molar mass of aluminum oxide = 102 g/mol; molar mass of ammonium perchlorate =117.5 g/mol
From the equation of reaction 3 moles of ammonium perchlorate reacts with 3 moles of aluminum to produce 1 mole of aluminum oxide;
that is 3 * 117.5 g of ammonium perchlorate reacts with 3 * 27 g of aluminum to produce 102 g/mol of aluminum oxide
150 g of ammonium perchlorate will react with (150 * 3*27) / (3 * 117.5) of aluminum = 34.47 g of Al
Ammonium perchlorate is the limiting reactant.
150 g of ammonium perchlorate will produce (150 * 102)/(3*117.5) g of aluminum oxide = 43.4 g of aluminum oxide
The branch of science that deals with chemicals and bonds are called chemistry. Chemistry deals with the physical and chemical behavior of the element.
The correct answer to the question is [tex]3NH_4ClO_4 + 3Al ---> Al_2O_3 + AlCl_3 + 6H_2O + 3NO[/tex]
B) 150 g of ammonium perchlorate will produce 43.4 g of aluminum oxide
What is the balanced reaction?A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge are the same for both the reactants and the products. In other words, the mass and the charge are balanced on both sides of the reaction.Oxidation states:Nitrogen, N: from -3 to +2Hydrogen, H: from +1 to +1Chlorine, Cl: From +7 to -1Oxygen, O: from -2 t0 -2Aluminum, Al: from 0 to +3.The oxidizing agent is ammonium perchlorate while the reducing agent is the aluminum powder.
B) molar mass of aluminum oxide = 102 g/mol; molar mass of ammonium perchlorate =117.5 g/mol. From the equation of reaction 3 moles of ammonium perchlorate reacts with 3 moles of aluminum to produce 1 mole of aluminum oxide;
That is[tex]3 * 117.5[/tex] g of ammonium perchlorate reacts with [tex]3 * 27[/tex]g of aluminum to produce 102 g/mol of aluminum oxide. 150 g of ammonium perchlorate will react with [tex]\frac{(150 * 3*27) }{ (3 * 117.5)}[/tex] of aluminum = 34.47 g of Al
Ammonium perchlorate is the limiting reactant.
150 g of ammonium perchlorate will produce (150 * 102)/(3*117.5) g of aluminum oxide
= 43.4 g of aluminum oxide.
Hence, the correct answer is 4.34g.
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True or False. For solidification, a substance must absorb heat
Answer:
true
Explanation:
I think it is true but im uncertain
Determine the number of water molecules in 115g of chromium(III) oxalate trihydrate.
Answer:
[tex]4.92x10^{23}molecules H_2O[/tex]
Explanation:
Hello,
In this case, since the chromium(III) oxalate trihydrate is Cr₂(C₂O₄)₃ ·3H₂O whose molar mass is 422 g/mol and one mole of chromium(III) oxalate trihydrate contains three moles of water, by also considering that one mole of substance contains the Avogadro´s number in particles, the number of water molecules turns out:
[tex]=115gCr_2(C_2O_4)_3\ 3H_2O*\frac{1molCr_2(C_2O_4)_3\ 3H_2O}{422gCr_2(C_2O_4)_3\ 3H_2O}*\frac{3molH_2O}{1molCr_2(C_2O_4)_3\ 3H_2O} *\frac{6.022x10^{23}molecules H_2O}{1molH_2O} \\\\=4.92x10^{23}molecules H_2O[/tex]
Best regards.
explain why metals above zinc in activity series of metals are extracted from the ores by the electrolysis?
Answer:
Metals above zinc in the reactivity series are too reactive to be extracted by heat- ing with carbon or carbon monoxide gas. In this extraction process the metal ions are reduced and the carbon is oxidised. Both iron and copper can be extracted from the ore by heating with carbon.
Explanation:
ok?
What is the IUPAC name of the following compound?
CH3-CH-C---C-CH2-CH-CH3
CH3-CH2 CH2-CH3
(a) 2,6-diethyl-3-nonyne
(b) 2,5-diethyl-3-nonyne
(c) 3,7-dimethyl-5-nonyne
(d) 3,7-dimethyl-4-nonyne
(e) 2,6-diethyl-3-heptyne
Answer:
(d) 3,7-dimethyl-4-nonyne.
Explanation:
Hello,
In this case, considering the attached picture on which you can see that the main chain has nine carbon atoms, one tripe bond at the fourth carbon and two methyl radicals at the third and seventh carbons respectively, by following the IUPAC rules, the name would be: (d) 3,7-dimethyl-4-nonyne since the chain must start at the side closest to the first triple bond due to its priority and subsequently considering the present radicals.
Best regards.
h. Identity of unknown metal
Answer:
you can identify an unknown substance by measuring its density and comparing your results to a list of known densities. Density=mass/volume. Assume that you have to identify an unknown metal. You can determine the mass of the metal on a scale.
If the mass of a helicopter is 4500 kg and the net force on it is 18000 n, what is the helicopters acceleration
Answer:
The answer is
4 m/s²Explanation:
The force of an object can be found by using the formula
F = m × awhere
m is the mass
a is the acceleration
F is the force
Since we are finding the acceleration
[tex]a = \frac{F}{m} [/tex]
From the question
F = 18000 N
m = 4500 kg
Substitute the values into the above formula and solve
That's
[tex]a = \frac{18000}{4500} \\ = \frac{180}{45} [/tex]
We have the final answer as
4 m/s²Hope this helps you
Some enzymes have one or more sulfhydryl (thiol) groups that are important to enzymatic activity but that can react upon standing in solution to form inactive disulfide bonds.
Thiol reagents, such as 1,4-dithiothreitol (DTT), are often added to the solutions of such proteins to protect them from this reaction and to reverse it when it occurs. (The reverse reaction works best at slightly alkaline pH.) Draw the product formed when DTT reacts with a protein disulfide bond to liberate the free thiol groups. Which of the following occurs in this reaction? A. The protein disulfide is oxidized.
B. The protein disulfide is reduced.
C. DTT is reduced.
D. DTT is oxidized.
Answer:
A. Protein disulfide is oxidized.
Explanation:
When thiol reagents are introduced with some protein solutions they react with molecules of disulfide and oxidize the protein. There occurs inter-conversion of thiol molecules into free disulfide molecules. The DTT reduces the disulfide molecules bonds of proteins and it starts to peptide.
A few years ago, a newspaper article reported that the Utah Industrial Depot west of Salt Lake
City had made the short list as a possible storage site for 4,408 metric tons of mercury metal.
This material is owned by the Defense National Stockpile Center. Mercury is mined primarily in Algeria, China, Kyrgyzstan, and Ukraine. At least part of this stockpiled material is from
payments to the US made by Spain as part of a WWII war debt. How many atoms of mercury
does this amount represent? (1 metric ton is 1000 kg, and 1 kg is 1000 g)
Answer:
There are [tex]1.323\times 10^{31} atoms[/tex] of mercury in 4,408 metric tons.
Explanation:
Mass of mercury metal = 4,408 metric ton
1 metric ton = 1000 kg
4,408 metric ton = 4,408 × 1000 kg = 4,408,000 kg
1 kg = 1000 g
4,408,000 kg = 4,408,000 × 1000 g = 4,408,000,000 g
[tex] 4,408,000,000 g=4.408\times 10^9 g[/tex]
Mass of mercury = [tex]4.408\times 10^9 g[/tex]
Atomic mass of mercury = 200.59 g/mol
Moles of mercury = n
[tex]n=\frac{4.408\times 10^9 g}{200.59 g/mol}[/tex]
[tex]1 mole=N_A=6.022\times 10^{23}[/tex] atoms/molecules/ ions
Number of atoms of mercury in n moles = N
[tex]N=n\times N_A[/tex]
[tex]N=\frac{4.408\times 10^9 g}{200.59 g/mol}\times 6.022\times 10^{23}\\=1.323\times 10^{31} atoms[/tex]
Hence, there are [tex]1.323\times 10^{31} atoms[/tex] of mercury in 4,408 metric tons.
14) Describe the Cloud Model.
A student measures the mass of a substance as 1.7132 kg and it’s volume as 0.65 L. What is the density of the substance in g/mL? Round your answer to the correct number of significant figures.
Answer:
[tex]\rho =2.6g/mL[/tex]
Explanation:
Hello,
In this case, considering that the density is defined as:
[tex]\rho =\frac{m}{V}[/tex]
Thus, since 1 kg equals 1000 g and 1 L equal 1000 mL, the required density in g/mL turns out:
[tex]\rho =\frac{1.7132kg}{0.65L}*\frac{1000g}{1kg}*\frac{1L}{1000mL} \\\\\rho=2.6g/mL[/tex]
Take into account that since 0.65 L has two significant figures, the result is also shown with two significant figures.
Regards.
What is the steps of the photosynthetic equation?
Answer: The photosynthesis equation is as follows: 6CO2 + 6H20 + (energy) → C6H12O6 + 6O2 Carbon dioxide + water + energy from light produces glucose and oxygen.
Explanation: Photosynthesis is comprised of two stages, the light-dependent reaction and the light-independent reactions, so that for the light suports energy.
Hope this helps:)
