A 2 kg mass starts from rest and slides down an inclined plane 4 m long in 1 second. What net force is acting on the mass along the incline *.
The net force acting on the mass along the incline is equal to 16 Newton.
Given the following data:
Mass = 2 kgDistance = 4 metersTime = 1 secondsTo determine the net force acting on the mass along the incline:
First of all, we would find the acceleration of the mass by using the second equation of motion:
[tex]S = ut+ \frac{1}{2} at^2\\\\4 = 0(1) + \frac{1}{2} a(1)^2\\\\4=\frac{a}{2}\\\\a=2\times 4[/tex]
Acceleration, a = 8 [tex]m/s^2[/tex]
For the net force, we would apply Newton's Second Law of Motion:
[tex]F_{net} = mass \times acceleration\\\\F_{net} =2 \times 8[/tex]
Net force = 16 Newton.
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What is the relationship between momentum and kinetic energy.
Answer:
constant object, momentum increases directly with speed
Explanation:
whereas kinetic energy increases the square of the velocity due to energy momentum
Lina applies a constant force of 30 N as she pushes a dresser 3 m. How much work did Lina do on the dresser?
Answer:
The answer will be 90
Explanation:
30N×3m= 90
A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.
The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
The given parameters;
initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃PiThe initial and final momentum of the ball is calculated as;
[tex]P_i = m_ivi[/tex]
[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]
The initial and final kinetic energy of the ball is calculated as;
[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]
The change in the kinetic energy is calculated as;
[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]
Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
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what is faster?
A. train
B. bus
C. airplane
D. boat
Answer:
airplane
Explanation:
Answer:
a plane would go by far the fastest
Explanation:
it would be airplane ,train, boat, bus
which wave has a higher frequency and why?
Explanation:
the figure in the left side has higher frequency.
because it has more nos. of wave in 1sec.
A potted plant falls from the window of an apartment building. It falls for 2.0 s and then hits the ground. What is the speed of the plant just before it hits the
ground? Assume only gravity is acting on it.
A) 20m/s
B)9.8m/s
C)2.0m/s
D)4.9m/s
Answer:
D) 4.9 m/s
Explanation:
Speed of Object in Free Fall
s = Rate of Acceleration, Due to Gravity × Length of Time
s = 9.8 × 2.0
s = m/s (Round Up to The Nearest Whole Number)
--
m/s = 9.8 ÷ 2.0 = 4.9 m/s
Dark matter is inferred to exist because Select one: a. we can observe its gravitational influence on visible matter. b. it explains how the expansion of the universe is accelerating. c. we see lots of dark patches in the sky. Clear my choice
Answer:
(a) the gravitational influence on visible matter can not be explained by matter that can be seen.
What can we say about energy on
the low end of the
electromagnetic spectrum?
A. They have longer wavelengths and less dangers.
B. They have lower frequencies and more energy.
C. They have shorter wavelengths and less dangers.
D. They have higher frequencies and more energy.
Answer:
A. Longer wavelengths and less dangers
Explanation:
Radio waves are at the lowest end of the EM spectrum, they have the longest wavelength of any other EM waves, the lowest energy and, accordingly, the lowest frequency;
Their low energy and frequency means they pose little risk of harm or danger as they don't get absorbed by human being.
¿Cuál es la densidad de un metal si una muestra tiene una masa de 63.5 g cuando se mide en el aire y una masa aparente de 55.4 g cuando está sumergida en agua?. Considere la densidad del agua como 1000 kg/m3.
La densidad del metal como se requiere en la pregunta es 7.8 * 10 ^ 3 Kg / m ^ 3.
Sabemos que ese empuje hacia arriba = peso en aire - peso en líquido
Peso en el aire = 63,5 * 10 ^ -3 Kg * 10 m / s ^ 2 = 0,635 N
Peso en líquido = 55,4 * 10 ^ -3 Kg * 10m / s ^ 2 = 0,554 N
Empuje hacia arriba = 0,635 N - 0,554 N = 0,081 N
Pero ;
Empuje hacia arriba = Volumen * densidad del fluido * aceleración debido a la gratitud
volumen = empuje hacia arriba / densidad del fluido * aceleración debido a la gratitud
volumen = 0.081 N / 1000 * 10
Volumen = 8.1 * 10 ^ -6 m ^ 3
Densidad = masa / volumen
Densidad = 63,5 * 10 ^ -3 Kg / 8,1 * 10 ^ -6 m ^ 3
= 7,8 * 10 ^ 3 kg / m ^ 3
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What hazardous wastes are common in ordinary households? What can you do to reduce the impact you make on the environment from the use of hazardous wastes?
Answer:
The most common products include aerosols, anti-freeze, asbestos, fertilizers, motor oil, paint supplies, photo chemicals, poisons, and solvents, cleaning supplies.
Explanation:
Use homemade cleaners
You can find local retailers to take rechargeable batteries from laptop computers, cordless power tools, cellular and cordless phones, and camcorders at the Rechargeable Battery Recycling Corporation’s website
A transformer is being built to triple the voltage produced. Which data are collected to investigate whether the transformer can achieve the goal? (1 point)
A) the ratio of the number of turns in the primary and secondary coils
B) only the number of turns in the secondary coil and the magnetic field of the core
C) only the number of turns in the primary coil and the magnetic field of the core
D) the ratio of the number of turns in the primary and secondary coils and the magnetic field of the core
Answer:
the ratio of the number of turns in the primary and secondary coils.
Explanation:
hope i'm not too late!!
What is a lol diagram.
Answer:
LOL Diagrams
a way to represent how the energy is stored in the chosen system during various snapshots and to represent any changes in total energy for the system. Each “L” represents how the energy is stored during a particular snapshot (instant). The “O” shows the objects inside and outside the system.
3. A mouse crawls 9 meters left in a tube, pauses and then crawls back 5 meters before
stopping. The entire trip took a total of 7 seconds.
a. What is the average speed of the mouse over these 7 seconds?
b. What is the average velocity of the mouse over these 7 seconds?
c. What was the instantaneous velocity of the mouse when it turned around?
Answer:
A
Explanation:
If it is loooking for a proper question, it wants to know how fast the mouse was going
Answer: The answer for this is A.
Explanation: I know this cause i'm smart and totally didn't copy the other guy just to get points
answer question 7 please
How to use bernoulli's equation.
Answer:
Answer is below ….
Explanation:
The Bernoulli equation is a crucial statement that connects a fluid's pressure, height, and velocity at a single point in its flow. In an idealised system, the connection between these fluid conditions along a streamline always equals the same constant along that streamline.
Water from a reservoir runs through enormous tubes called penstocks before reaching a turbine at the end of a hydroelectric dam. The gravitational potential energy drops as the water flows down the pipe according to Bernoulli's equation, yet in many configurations, the water departs at the same speed.
Bernoulli's equation is a more broad and mathematical version of Bernoulli's principle that includes variations in gravitational potential energy. We'll derive this equation in the following part, but first, let's look at Bernoulli's equation to get a sense of what it says and how one may use it.
________________________________________________________
(hope this helps can I pls have brainlist (crown)☺️)
why do we believe 90 percent of the mass of the milky way is in the form of dark matter?
Answer:
The orbital speeds of stars far from the galactic center are surprisingly high, suggesting that these stars are feeling gravitational effects from unseen matter in the halo.
light of wavelength 520 nm falls on a slit that is 3.20 um wide. Estimate how far the first bright-sh difrrection fringe is
Answer:
because of the gravity of the earth
3. Would prudent to do an observatory M 82 for this class?
Answer: Yes,
If you need any other thing let me know, I'll still be on
Explanation:
Two electrons are separated by one cm. What is the ratio of the electric force to the gravitational force between them? (me = 9. 11 ´ 10-31 kg, ke = 8. 99 ´ 109 N×m2 /C2 , G = 6. 67 ´ 10-11 N×m2 /kg2 , and e = 1. 6 ´ 10-19 C) a. 2. 3 ´ 102 b. 1. 3 ´ 1020 c. 3. 1 ´ 1022 d. 4. 2 ´ 1042.
The ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].
The given parameters;
Mass of the electron, [tex]m_e[/tex]= 9.11 x 10⁻¹¹ kgCoulomb's constant, k = 8.99 x 10⁹ Nm²/C²Gravitational constant, G = 6.67 x 10⁻¹¹ Nm²/kg²Charge of electron, q = 1.6 x 10⁻¹⁹ CDistance between the two electrons, r = 1 cmThe electrostatic force between the two electrons is calculated as follows;
[tex]F_c = \frac{kq^2}{r^2} \\\\[/tex]
The gravitational force between the two electrons is calculated as follows;
[tex]F_g = \frac{Gm_e^2}{r^2}[/tex]
The ratio of the electric force to the gravitational force between the two electrons is calculated as follows;
[tex]\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{1}{\frac{Gm^2}{r^2} } \\\\\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{r^2}{Gm^2} \\\\\frac{F_c}{F_g} = \frac{kq^2}{Gm^2}\\\\[/tex]
[tex]\frac{F_c}{F_g} = \frac{(8.99 \times 10^9) \times (1.6 \times 10^{-19}))^2}{(6.67 \times 10^{-11} ) \times (9.11 \times 10^{-31})^2} \\\\\frac{F_c}{F_g} = 4.2 \times 10^{42}[/tex]
Thus, the ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].
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Find the displacement in the time interval 3 seconds to 4 seconds
A. 1m
B.3m
C.7m
D.9m
Answer:
B. 3m
Explanation:
Took the quiz.
Hope this helps!!
How much work is needed to stop a 1,110 kg car that is moving straight down the
highway at 59.0 km/h?
Answer:
382.74 kJ.
Explanation:
The work that must be done to stop an 1100 kg car travelling at 59 km/h is - 382.74 kJ.
The work needed to stop an 1100 kilograms car moving with a velocity of 59.0 km/hr would be 147.72 kilojoules.
What is work done?
The total amount of energy transferred when a force is applied to move an object through some distance
The work done is the multiplication of applied force with displacement.
Work Done = Force * Displacement
As given in the problem we have to find out how much work is needed to stop a 1,110-kilogram car that is moving straight down the highway at 59.0 kilometers/hour
the mass of the car = 1100 kilograms
the velocity of the car = 59 kilometers/hour
KE = 0.5mv²
=0.5×1100×(59×1000/3600)²
= 147.72 kilojoules
Thus, the work needed to stop an 1100 kilograms car would be 147.72 kilojoules
To learn more about work done from here, refer to the link;
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#SPJ2
The total mass of the carts is 1000 kg. The first
drop is 77.7 m. What is the speed of the coaster
at the bottom of the hill?
Answer:41xm/s
Explanation:
Answer:41xm/s
Explanation:
I found this for you hope it helps.
explain properties and importance of light and how it separates into colours
Answer:
White light can be separated into different colors using a special lens called a prism. As visible light passes from air into the glass, the change in medium causes a change in direction and speed. Refraction causing the separation of white light into its various color wavelengths is called dispersion.
hope this helps
What are the variables that affect the force of gravity between objects?
A 30 kg boy stands on rough horizontal ground. The coefficient of
static friction,
us is 0.8. The present static friction between the boy and the ground is
?
Answer:
0n
Explanation:
4) An 873kg dragster, starting from rest, attains a speed of 26.3m/s in 0.590s.
A) What was the acceleration of the dragster?
B) What was the net force needed to accelerate the dragster?
C) Assume that the driver has a mass of 68.0kg. What horizontal force does the seat exert on
him?
Answer:
A.)a=44.57m/s
B.)f=38,909.61
C.)f=666.4
Explanation:
A.) A=v/t 26.3/0.590=44.57
B.) 873kg x 44.57= 38,909.61
C.) 68kg x 9.8=666.4
6. Explain the importance of the law of conservation of mass.
Answer:
According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.
Explanation:
<3
The person is in motion
relative to...
Answer:
muscular force in relative to this
Which of toby's answers is a correct description of what happens when a 1-kg cart traveling at 1 m/s collides inelastically with another 1-kg cart at rest?.
Answer:
hi I don't know sorry sorry forgive me
Explanation:
sorry
