Answer: 4
Step-by-step explanation:
in order to divide one fraction by another, you must multiply by the reciprocal(the reverse of a certain fraction). the reciprocal of 1/6 is 6/1. so:
[tex]\frac{2}{3} / \frac{1}{6}[/tex] = multiply by the reciprocal of 1/6
[tex]\frac{2}{3} * \frac{6}{1}[/tex] = cross out
[tex]\frac{2}{1} * \frac{2}{1}[/tex] = multiply
[tex]\frac{4}{1}[/tex] = simplify
4
Answer:
4
Step-by-step explanation:
(2/3)/(1/6)
Eleminate the denominator by multiplying numerator and denominator with whatever is the reciprocal of the denominator. In this case the denominator is 1/6 so the reciprocal is 6/1 or "just" 6.
So, multiply numerator and denominator by 6. The next three (bold) steps, have been written down for explanatory purposes only, and normally are not nessasary.
(2/3)*6 / (1/6)*6
(2/3)*6 / (6/6)
(2/3)*6 / 1
(2/3)*6
12/3
4
Which of the following points is in the solution set of y
Jeanie wrote the correct first step to divide 8z2 + 4z – 5 by 2z.
Which shows the next step?
A.4z + 2 –
B.4z2 + 2 –
C.4z2 + 2 –
D.4z + 2 –
Answer:
4z + 2 - 5/2z
Step-by-step explanation:
8z^2 + 4z -5
divided by 2z
8z^2 /2z = 4z
4z/2z =2
5/2z = 5/2z
Putting them back together
4z + 2 - 5/2z
Answer:
A 4z + 2 - 5/2z
Step-by-step explanation:
Convert decimal +61 and +27 to binary using the signed 2’s complement representation and enough digits to accommodate the numbers. Then perform the binary equivalent of (27) + (-61), (-27) + (+61), and (-27) + (-61). Convert then answers back to decimal and verify that they are correct.
Answer:
the sum is 01011000₂ = 88
Step-by-step explanation:
For numbers of magnitude less than 128, it is convenient to use an 8-bit representation. I find it works will to convert back and forth through the octal (base-8) representation, as each base-8 digit converts nicely to three (3) base-2 bits.
61 = 8·7 +5 = 075₈ = 00 111 101₂
27 = 8·3 +3 = 033₈ = 00 011 011₂
Then ...
[tex]\begin{array}{cc|ccc}&61&&00111101\\+&27&+&00011011\\ &\overline{88}&&\overline{01011000}\end{array}[/tex]
__
Starting from the right, we can convert the binary back to octal, then to decimal by considering 3 bits at a time:
01 011 000₂ = 130₈ = 1·8² +3·8 +0 = 64 +24 = 88
The binary sum is the same as the decimal sum.
George and Paula are running around a circular track. George starts at the westernmost point of the track, and Paula starts at the easternmost point. The illustration below shows their starting positions and running directions. They start running toward each other at constant speeds. George runs at 9 feet per second. Paula takes 50 seconds to run a lap of the track. George and Paula pass each other after 14 seconds.
After running for 4 minutes, how far east of his starting point is George?
Answer:
George is 43.20 ft East of his starting point.
Step-by-step explanation:
Let Paula's speed be x ft/s
George's speed = 9 ft/s
Note that speed = (distance)/(time)
Distance = (speed) × (time)
George takes 50 s to run a lap of the track at a speed of y ft/s
Meaning that the length of the circular track = y × 50 = 50y ft
George and Paula meet 14 seconds after the start of the run.
Distance covered by George in 14 seconds = 9 × 14 = 126 ft
Distance covered by Paula in 14 seconds = y × 14 = 14y ft
But the sum of the distance covered by both runners in the 14 s before they first meet each other is equal to the length of the circular track
That is,
126 + 14y = 50y
50y - 14y = 126
36y = 126
y = (126/36) = 3.5 ft/s.
Hence, Paula's speed = 3.5 ft/s
Length of the circular track = 50y = 50 × 3.5 = 175 ft
So, in 4 minutes (240 s), with George running at 9 ft/s, he would have ran a total distance of
9 × 240 = 2160 ft.
2160 ft around a circular track of length 175 ft, means that George would have ran a total number of laps (2160/175) = 12.343 laps.
Breaking this into 12 laps and 0.343 of a lap from the starting point. 0.343 of a lap = 0.343 × 175 = 60 ft
So, 60 ft along a circular track subtends an angle θ at the centre of the circle.
Length of an arc = (θ/360°) × 2πr
2πr = total length of the circular track = 175
r = (175/2π) = 27.85 ft
Length of an arc = (θ/360) × 2πr
60 = (θ/360°) × 175
(θ/360°) = (60/175) = 0.343
θ = 0.343 × 360° = 123.45°
The image of this incomplete lap is shown in the attached image,
The distance of George from his starting point along the centre of the circular track = (r + a)
But, a can be obtained using trigonometric relations.
Cos 56.55° = (a/r) = (a/27.85)
a = 27.85 cos 56.55° = 15.35 ft
r + a = 27.85 + 15.35 = 43.20 ft.
Hence, George is 43.20 ft East of his starting point.
Hope this Helps!!!
How do I solve part b and c
Answer:
part a: 52%
part b: 0.4
part c: 0.24
Step-by-step explanation:
For part one, you find the frequency of the number of people that are less that 20. You add the number of tics in each bar and you divide by the total.
so for part a it is (7+6+9+4)/ (7+6+9+4+4+12+8)
for part b you add up the values that are greater than 25(less than 35)
(12+8)/total
part c you find the number of people between 25 and 30
that's 12
over total
12/total
What’s the correct answer for this?
Answer:
D: 17 times
Step-by-step explanation:
Volume of tank = 36×13×24
= 11,232 cubic inches
Now
Bucket = 693 cubic inches
Number of time Valeria will use the bucket = 11232/693
= 16.2
≈ 17
A 15-inch candle is lit and steadily burns until it is burned out. Let b represent the burned length of the candle (in inches) and let r represent the remaining length of the candle (in inches).
a. Write a formula that expresses r in terms of b.When 3.1 inches have burned from the candle, the remaining length of the candle is inches.
b. Graph the relationship between a and b
Answer:
(a)r=15-b
11.9 Inches
(b)See attached
Step-by-step explanation:
Length of the candle =15 inch
Let b represent the burned length of the candle (in inches)
Let r represent the remaining length of the candle (in inches).
Therefore:
(a) r+b=15
r=15-b
When b=3,1 Inches
Remaining Length, r=15-3.1=11.9 Inches
(b)The graph showing te relationship between r and b is shown below.
r is plotted on the y-axis while b is plotted on the x-axis as labelled.
Formula that express r in terms of b is
[tex]r=15-b[/tex]
Remaining length of candle is 11.9 inches
Given :
A 15-inch candle is lit and steadily burns until it is burned out
Let b represent the burned length and let r represent the remaining length
We need to write the formula
remaining length = initial length - burned length
[tex]r=15-b[/tex]
When 3.1 inches have burned from the candle, the remaining length of the candle is inches.
b is 3.1
remaining length [tex]r=15-3.1=11.9[/tex] inches
now we graph the relationship
Graph is attached below.
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Analyze the diagram below and answer the question that follows.
Answer:
B. Complements of congruent angles are congruent.
Step-by-step explanation:
Angles <DCF and <FEG have angles measures that are complementary to to angles E and C.
Z=1.23 z=0.86 WHAT is the area of the shaded region between the two
Answer:
The area of the shaded region between [tex] \\ z = 1.23[/tex] and [tex] \\ z = 0.86[/tex] is [tex] \\ P(0.86 < z < 1.23) = 0.08554[/tex] or 8.554%.
Step-by-step explanation:
To solve this question, we need to find the corresponding probabilities for the standardized values (or z-scores) z = 1.23 and z = 0.86, and then subtract both to obtain the area of the shaded region between these two z-scores.
We need to having into account that a z-score is given by the following formula:
[tex] \\ z = \frac{x - \mu}{\sigma}[/tex]
Where
x is a raw score from the distribution that we want to standardize using [1].[tex] \\ \mu[/tex] is the mean of the normal distribution.[tex] \\ \sigma[/tex] is the standard deviation of the normal distribution.A z-score indicates the distance of x from the mean in standard deviations units, where a positive value "tell us" that x is above [tex] \\ \mu[/tex], and conversely, a negative that x is below [tex] \\ \mu[/tex].
The standard normal distribution is a normal distribution with [tex] \\ \mu = 0[/tex] and [tex] \\ \sigma = 1[/tex], and has probabilities for standardized values obtained using [1]. All these probabilities are tabulated in the standard normal table (available in any Statistical book or on the Internet).
Using the cumulative standard normal table, for [tex] \\ z = 1.23[/tex], the corresponding cumulative probability is:
[tex] \\ P(z<1.23) = 0.89065[/tex]
The steps are as follows:
Consult the cumulative standard table using z = 1.2 as an entry. Z-scores are in the first column of the mentioned table. In the first row of it we have +0.00, +0.01, +0.02 and, finally, +0.03. The probability is the point that result from the intersection of z = 1.2 and +0.03 in the table, which is [tex] \\ P(z<1.23) = 0.89065[/tex].Following the same procedure, the cumulative probability for [tex] \\ z = 0.86[/tex] is:
[tex] \\ P(z<0.86) = 0.80511[/tex]
Subtracting both probabilities (because we need to know the area between these two values) we finally obtain the corresponding area between them (two z-scores):
[tex] \\ P(0.86 < z < 1.23) = 0.89065 - 0.80511[/tex]
[tex] \\ P(0.86 < z < 1.23) = 0.08554[/tex]
Therefore, the area of the shaded region between [tex] \\ z = 1.23[/tex] and [tex] \\ z = 0.86[/tex] is [tex] \\ P(0.86 < z < 1.23) = 0.08554[/tex] or 8.554%.
We can see this resulting area (red shaded area) in the graph below for a standard normal distribution, [tex] \\ N(0, 1)[/tex], and [tex] \\ z = 0.86[/tex] and [tex] \\ z = 1.23[/tex].
the length of a ruler is 170cm,if the ruler broke into four equal parts.what will be the sum of the length of three parts
Answer:
127.5
Step-by-step explanation:
Multiply 170 by 0.75
127.5
Answer:
3 divided by 4 = 0.75 = 3/4
0.75 x 170 = 127.5
or
170/1 x 3/4 = 510/4 = 127 1/2
1/2 = 0.5 = 1 divided by 2
127 + 0.5 = 127.5
127.5 is the answer
Hope this helps
Step-by-step explanation:
Two surveys are conducted to measure the effect of an advertising campaign for a certain brand of detergent.27 In the first survey, interviewers ask house- wives whether they use that brand of detergent. In the second, the interviewers ask to see what detergent is being used. Would you expect the two surveys to reach similar conclusions? Give your reasons.
Answer:
NO
Step-by-step explanation:
The objective of this surveys is to determine if the two surveys will reach a similar conclusion.
From the data given, we have two test surveys here:
The survey is to measure the effect of an advertising campaign for a certain brand of detergent.
Now in the first survey; interviewers ask house- wives whether they use that brand of detergent and in the second survey the interviewers ask to see what detergent is being used.
Let assume that the brand name of the detergent is KLIN ;
From this disparities of statement ; we anticipate that they will reach different conclusion. This is because; from the first survey people will either respond to the fact that they use the brand detergent (KLIN) or do not used the brand detergent. But in the second survey; when being asked to see what detergent that is being used. There are greater chance that they will bring out the detergent that is commonly used which will eventually result to the same detergent .
A car dealership decreased the price of a certain car by 4% . The original price was $43,600 . write the new price in terms of the original price.
Answer: The new price of the car is $41856
Step-by-step explanation:
So we know the the original price as 43,600 which is 100% and is being dropped by 4% so you would have to subtract 4% from a 100% and multiply it by the original price.
100% - 4% = 96%
Now 96% of the original price is the new price.
96% * 43,600= ?
0.96 * 43,600 = 41856
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of grams of fat per pound, with a standard deviation of grams of fat per pound. A random sample of farm-raised trout is selected. The mean fat content for the sample is grams per pound. Find the probability of observing a sample mean of grams of fat per pound or less in a random sample of farm-raised trout.
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
What postulate would justify the following statement?
If D is between A and B, than AD+DB=AB
Answer:
A, D and B must be in a straight line.
Step-by-step explanation:
If D is between A and B, than AD+DB=AB
This would mean A, D and B would be in a straight line.
You are a medical assistant in a pediatrician’s office and one of your responsibilities is evaluating the growth of newborns and infants. Your first patient, a baby girl named Ivy Smith, was 21.5 inches long at 3 months old. At 8 months, you measure her at 24 inches long. For your medical records, all measurements must be given both in inches and in centimeters: 1 inch = 2.54 cm
I need to come up with an equation for this.
Please help. I’ll mark you as brainliest if correct!
Answer:
product = 40
Step-by-step explanation:
The conjugate of (-2 + 6i) is (-2 - 6i)
You just need to change the sign
(-2 + 6i) (-2 - 6i)
Expand:
4 + 12i + -12i - [tex]36i^{2}[/tex]
4 + 12i + -12i + 36
product = 40
A quick quiz consists of a multiple-choice question with 5 possible answers followed by a multiple-choice question with 5 possible answers. If both questions are answered with random guesses, find the probability that both responses are correct. Report the answer as a percent rounded to two decimal place accuracy. You need not enter the "%" symbol. Probability = %
Answer:
Probability = 4%
Step-by-step explanation:
For each answer, there are only two possible outcomes. Either it is correct, or it is not. The probability of an answer being correct is independent of other answers. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
Each question has 5 possible answer:
The person guesses, so [tex]p = \frac{1}{5} = 0.2[/tex]
2 questions:
This means that [tex]n = 2[/tex]
Find the probability that both responses are correct.
This is P(X = 2).
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 2) = C_{2,2}.(0.2)^{2}.(0.8)^{0} = 0.04[/tex]
As a percent:
Probability = 4%
Suppose that the operations manager of a nose mask packaging delivery service is
contemplating the purchase of a new fleet of trucks. When
packages are efficiently stored in the trucks in preparation for delivery, two major constraints
have to be considered. The weight in pounds and volume in cubic feet for each item. Now
suppose that in a sample of 200 packages the average weight is 26.0 pounds with a standard
deviation of 3.9 pounds. In addition suppose that the average volume for each of these
packages is 8.8 cubic feet with standard deviation of 2.2 cubic feet. How can we compare the
variation of the weight and volume?
Answer:
Coefficient of variation (weight) = 15%
Coefficient of variation (volume) = 25%
Step-by-step explanation:
Let's begin by listing out the given information:
Population = 200, Average weight = 26 lb,
standard deviation (weight) = 3.9 lb,
Average volume = 8.8 ft³,
standard deviation (volume) = 2.2 ft³
Based on the data given, the manager will have to make a deduction by comparing the relative scatter of both variables due to the different units of measuring weight (pounds) and volume (cubic feet).
To compare the variation of the weight and volume, we use the coefficient of variation given by the formula:
Coefficient of Variation = (Standard deviation ÷ Mean) * 100%
⇒ [tex]C_{v}[/tex] = (σ ÷ μ) * 100%
For weight
σ = 3.9 lb, μ = 26 lb
[tex]C_{v}[/tex] (weight) = (3.9 ÷ 26.0) * 100% = 15%
[tex]C_{v}[/tex] (weight) = 15%
For volume
σ = 2.2 ft³, μ = 8.8 ft³
[tex]C_{v}[/tex] (volume) = (2.2 ÷ 8.8) * 100% = 25%
[tex]C_{v}[/tex] (volume) = 25%
∴ the relative variation of the volume of the package is greater than that of the weight of the package
A powerful computer is purchased for $2000, but loses 20% of its value each year. How much will it be worth 4 years from now?
a. Growth or Decay?
b. What is your multiplier?
c. Is $2000 your zero term or first term? term
d. Write the equation. (do not use spaces in your response; example: f(x)=10.2(1.22)^x )
e. Solve
Answer:
(A)Decay
(b)0.8
(c)First Term
(d)[tex]f(t)=2000(0.8)^t[/tex]
(e)$819.20
Step-by-step explanation:
The exponential function for modelling growth or decay is given as:
[tex]A(t)=A_o(1\pm r)^t[/tex],
Where:
Plus indicates growth and minus indicates decay.
[tex]A_o$ is the Initial Value\\r is the growth/decay rate\\t is the time period[/tex]
For a powerful computer that was purchased for $2000, but loses 20% of its value each year.
(a)Since it loses value, it is a decay.
(b)Multiplier
Its value decays by 20%.
Therefore, our multiplier(1-r) =(1-20&)=1-0.2
Multiplier =0.8
(c)$2000 is our First term (or Initial Value [tex]A_o[/tex])
(d)The function for this problem is therefore:
[tex]f(t)=f_o(1- r)^t\\f(t)=2000(1- 0.2)^t\\\\f(t)=2000(0.8)^t[/tex]
(e)Since we require the worth of the computer after 4 years,
t=4 years
[tex]f(4)=2000(0.8)^4\\f(4)=\$819.20[/tex]
Lines DE and AB intersect at point C.
What is the value of x?
SER
12
A.
(2x + 2) E
25
0 0 0 0
38
C
(5x + 3)
52
D
31
Answer:
B=25
Step-by-step explanation:
what is the solution for this equation [3y+7]=13
Answer:2
Step-by-step explanation:
3y+ 7= 13
3y= 13 - 7
3y= 6
Y = 6/3
Y= 2
What is 1.036 that add up to 4
Answer:
2.964
Step-by-step explanation:
Solve x2 - 4x - 7 = 0 by completing the square. What are the solutions?
Answer:
[tex]x=2+\sqrt{11},\:x=2-\sqrt{11}[/tex]
Step-by-step explanation:
[tex]x^2-4x-7=0\\\mathrm{Solve\:with\:the\:quadratic\:formula}\\Quadratic\:Equation\:Formula\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\mathrm{For\:}\quad a=1,\:b=-4,\:c=-7:\quad x_{1,\:2}=\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}\\x=\frac{-\left(-4\right)+\sqrt{\left(-4\right)^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}:\quad 2+\sqrt{11}[/tex]
[tex]x=\frac{-\left(-4\right)-\sqrt{\left(-4\right)^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}:\quad 2-\sqrt{11}\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\x=2+\sqrt{11},\:x=2-\sqrt{11}[/tex]
The line y = kx + 4, where k is a constant, is
graphed in the xy-plane. If the line contains the
point (c,d), where c ≠ 0 and d ≠ 0, what is the slope
of the line in terms of c and d ?
Answer:
(d - 4) / c
Step-by-step explanation:
The slope of the line in terms of c and d is (d - 4) / c.
Here, we have,
To find the slope of the line in terms of the coordinates of the point (c, d), we can use the slope-intercept form of a line, y = mx + b, where m represents the slope.
In the given equation, y = kx + 4, we can see that the coefficient of x is k, which represents the slope of the line.
Since the line contains the point (c, d), we can substitute these values into the equation:
d = kc + 4
To isolate the slope term, we rearrange the equation:
d - 4 = kc
Now, divide both sides by c:
(d - 4) / c = k
Therefore, the slope of the line in terms of c and d is (d - 4) / c.
To learn more on slope click:
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Which product represents the fraction of the circle that is shaded?
A
B
C
D
Answer:
B
Step-by-step explanation:
Please help. I’ll mark you as brainliest if correct!!!!
Answer:
a= 0
b= [tex]-\frac{\sqrt{42} }{12}[/tex]
Step-by-step explanation:
We can rewrite the expression to be:
[tex]\frac{i\sqrt{7} }{i^{2}\sqrt{24} }[/tex]
We then can cancel out the i and we get
[tex]\frac{\sqrt{7} }{\sqrt{24} i}[/tex]
Can be rewritten as
[tex]\frac{\sqrt{7} }{2\sqrt{6} i}[/tex]
We then rationalize and get
[tex]-\frac{\sqrt{42} }{12} i[/tex]
Can someone please help me with this question please
Answer:
Read below.
Step-by-step explanation:
Questions are underlined
Answers are bolded
Which of the following statements is true?
If two polygons are similar then the corresponding sides are proportional and the corresponding angles are proportional.
If two polygons are similar, then the corresponding sides are proportional and the corresponding angles are congruent.
If two polygons are similar, then the corresponding sides are congruent and the corresponding angles are proportional.
None of the choices are correct.
Which of the following sides are corresponding if ΔABC is similar to ΔMNL?
AC and ML, BC and NL, AB and MN is the correct answer but the answer choices are:
AB and MN, BC and NL, AC and ML
AC and MN, BC and NL, AB and ML
AB and ML, BC and NL, AC and MN
None of the choices are correct.
An individual who has automobile insurance from acertain company is randomly selected. Let Y be thenumber of moving violations for which the individualwas cited during the last 3 years. The pmf of Y is y p(y) 0 0.6 1 0.25 2 0.10 3 0.05 Suppose an individual with Y violations incurs a surcharge of $ 100 Y squared. Calculate the expected amount of the surcharge.
Answer:
[tex] E(100 Y^2) =100 E(Y^2)[/tex]
And we have that :
[tex] E(Y^2) =\sum_{i=1}^n X^2_i P(X_i)[/tex]
And replacing we got:
[tex] E(Y^2) =0^2 *0.6 + 1^2 *0.25 +2^2*0.10 +3^2 *0.05 = 1.1[/tex]
And finally we have:
[tex] E(100 Y^2) =100 *1.1 = 110[/tex]
Step-by-step explanation:
For this case we have the following probability masss function given:
Y 0 1 2 3
p(Y) 0.6 0.25 0.10 0.05
And we can define the surcharge with this expression [tex] 100Y^2[/tex]
We want to find the expected value for the last expression and we can do it on this way:
[tex] E(100 Y^2) =100 E(Y^2)[/tex]
And we have that :
[tex] E(Y^2) =\sum_{i=1}^n X^2_i P(X_i)[/tex]
And replacing we got:
[tex] E(Y^2) =0^2 *0.6 + 1^2 *0.25 +2^2*0.10 +3^2 *0.05 = 1.1[/tex]
And finally we have:
[tex] E(100 Y^2) =100 *1.1 = 110[/tex]
Suppose a county’s population can be approximated with the function () = 34(1.00804) where is the number of years since 2000, and is measured in millions of citizens.
Answer:
Population = 34.27336
Step-by-step explanation:
Given:
Population function (t) = 34(1.00804)^t
Number of year = 2000
Find:
Number of citizen in year 2000
Computation:
We know that, base year is 2000
So, t = 1
Population function (t) = 34(1.00804)^t
Population function (1) = 34(1.00804)^1
Population = 34(1.00804)
Population = 34.27336
Therefore, Population is 34.273636 million
Which ordered pair is the solution of the system of equations? 3x+2y=4, -2+2y=24, I need help Im very confused on how to solve this...
Answer:
x = -7.33 OR x = [tex]\frac{-22}{3}[/tex]
y = 13
Step-by-step explanation:
→You can use the substitution method. First, make y by itself in (-2 + 2y = 24):
-2 + 2y = 24
2y = 26
y = 13
→Then, plug in 13 for y into the other equation:
3x + 2y = 4
3x + 2(13) = 4
3x + 26 = 4
3x = -22
x = -7.33 OR x = [tex]\frac{-22}{3}[/tex]