What is a main difference between a mixture and a pure substance?
O A mixture is only a liquid, but a pure substance can be in any state.
A mixture looks the same throughout, but a pure substance does not.
A mixture can vary in composition, but a pure substance has a set composition.
A mixture can be made up of a single compound, but a pure substance cannot.
оо

Answers

Answer 1

Answer:

C- A mixture can vary in composition, but a pure substance has a set composition

Explanation:

Answer 2

The main difference between a mixture and a pure substance is: A mixture can vary in composition, but a pure substance has a set composition ( option c )

Mixture

A mixture is a substance which contains two or more constituents which can easily be separated by a physical means. It consists of two or more different substances, not chemically joined together.

Substance

A pure substance consists only of one element or one compound.

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Related Questions

The voltage across a 8.5-F capacitor is 2te–3t V. Find the current and the power.

Answers

Answer:

Explanation:

Given the capacitance of a capacitor = 8.5F

Voltage across the capacitor = 2te^-3tV

The current across a capacitor is expresses as shown;

I = Cdv/dt

Given V = 2te^-3tV

dv/dt = 2t(-3e^-3t) + 2(e^-3t)

dv/dt = -6te^-3t + 2e^-3t

Factor out the common term

dv/dt = -2e^-3t{3t-1}

If C = 8.5F

I = 8.5 × -2e^-3t{3t-1}

I = -17.0e^-3t{3t-1} A

Power is the product of current and voltage.

P = IV

Given I = -17.0e^-3t{3t-1} A

V = 2te^-3t V

Power = -17.0e^-3t{3t-1} × 2te^-3t

Power = (17e^-3t - 51te^-3t) × 2te^-3t

Power = 34te^{-3t-3t} - 102t²e^{-3t-3t}

Power = 34te^-6t - 102t²e^-6t

Power = 34te^-6t{1-3t} Watts

a golf ball is launched straight up with an initial velocity of 15.68m/s. Calculate the balls displacement and velocity every 0.4 sec into the ball's flight. How long will it take the ball in the air?​

Answers

Explanation:

Given:

v₀ = 15.68 m/s

a = -9.8 m/s²

t = 0.4n s, n = 0, 1, 2, etc.

Find: Δy and v

To find displacement, use the equation:

Δy = v₀ t + ½ at²

To find velocity, use the equation:

v = at + v₀

[tex]\left\begin{array}{ccc}t&y&v\\0&0&15.68\\0.4&5.49&11.76\\0.8&9.41&7.84\\1.2&11.76&3.92\\1.6&12.54&0\\2.0&11.76&-3.92\\2.4&9.41&-7.84\\2.8&5.49&-11.76\\3.2&0&-15.68\end{array}\right[/tex]

The ball lands after 3.2 seconds.

Answer:

calculated velocities:

(t,v(t))

(0.4,11.756)

(0.8,7.832)

(1.2,3.908)

(1.6,-0.016)

calculated displacements:

[tex](t,\Delta x)[/tex]

(0.4, 5.487)

(0.8,9.4048)

(1.2, 11.7528)

(1.6, 12.5312)

the ball spends 3.2 seconds in the air

Explanation:

Assuming the ball is launched on earth with standard gravity and that the effects of drag is neglected.

assume that 'up' is positive direciton since that is direction of travel

'down' is negative direction

formula for velocity is [tex]v(t)=v_0+at[/tex]

where [tex]v(t)[/tex] is the velocity at time [tex]t[/tex]

[tex]v_0[/tex] is the initial velocity at time [tex]t=0[/tex]

[tex]a[/tex] is the acceleration in the direction of the velocity

velocity is in m/s and accelration is in m/s^2 and t is in seconds

for displacement: [tex]\Delta x=v_0 t+\frac{1}{2}at^2[/tex]

Known stuffs:

in our case, we know we are on earth so, [tex]a=-9.81[/tex]m/s^2. the negative sign indicates that the direction is oposite the velocity since the ball travels up but gravity pulls down

the initial velocity is given as [tex]v_0=15.68[/tex]m/s

therefore, our equation for velocity is

[tex]v(x)=15.68-9.81t[/tex]

now we just need to plot it every 0.4 seconds

this is easy subsituteion. here's the first:

[tex]v(0.4)=15.68-9.81(0.4)=11.756[/tex]m/s

if we keep plotting this, we get the following table

(t,v(t))

(0.4,11.756)

(0.8,7.832)

(1.2,3.908)

(1.6,-0.016) the velocity is negative meaning that the ball is now going 'down' and therefor the ball has just passed the peak of it's upward travel

so since it took about 1.6 seconds to get here, it will spend about twice this time in the air or about 3.2 seconds

to get an exact answer, solve for the time when velocity is 0, ie when the ball has reached its peak and stopped moving

set [tex]v(t)=0[/tex] and solve for t

[tex]0=15.68-9.81t\rightarrow 15.68=9.81t\rightarrow t=1.598s[/tex]

so it takes 1.598 seconds to get to peak, therefore it spends twice this time in the air or 3.197 seconds in the air. it's close enough to 3.2 seconds

the ball spends 3.2 seconds in the air

displacement:

[tex]\Delta x=v_0t+\frac{1}{2}at^2[/tex]

[tex]\Delta x=15.68t+\frac{1}{2}(-9.81)t^2[/tex]

some values are

[tex](t,\Delta x)[/tex]

(0.4, 5.487)

(0.8,9.4048)

(1.2, 11.7528)

(1.6, 12.5312)

using keplers 3rd law, determine the distance between the earth and the sun

Answers

Answer:

93.615 million or more

Explanation:

The Sun is about 93 million miles from Earth to calculate the distance to a star, astronomers observe it from different places along Earth's orbit around the Sun.

the Earth is about 147.5 million kilometers from the sun. Fun fact: every planet can fit in the distance between the Earth and Moon

For the system of Problem3.18, determine the amount of energy transfer by heat, in kJ per kg of refrigerant.[Problem3.18A closed, rigid tank contains a two‐phase liquid–vapor mixture of Refrigerant 22 initially at−20°Cwith a quality of 50.36%. Energy transfer by heat into the tank occurs until the refrigerant is at a final pressure of 6 bar. Determine the final temperature, in°C. If the final state is in the superheated vapor region, at what temperature, in°C, does the tank contain only saturated vapor?]

Answers

Answer:

35.625° C

Explanation:

See attachment

a) Final temperature is 35.625° C

b) 0°

Julie, a third-grade student, believes that the moon disappears on certain days every month. Explain why the following information is or is not scientific evidence which can be used to evaluate Julie’s hypothesis.

Answers

Julie believes the moon disappear on certain days every month because when there is a new moon, she can’t see the moon. As an teenager, we learn that we cannot see the moon because the side of the moon we see on earth is not getting any light from the sun at night. This would be your scientific explanation. Julie’s is not scientific, but just an observation that she made.

Hope this helps :)

A train is travelling east along a straight run of track at 54.0 km/hr. Inside, two siblings 1.90 m apart are playing catch directly across the aisle. The kid wearing a Catherine Wheel T-shirt throws the ball horizontally north. The ball crosses the train and is caught 1.05 s later by her little brother. (Ignore any effects of gravity or friction.)
a) Find the magnitude of the ball's velocity from the little brother's point of view.
b) What is the magnitude of the velocity of the ball as seen by someone standing still outside the train?
c) What is the angle between the direction of the ball and the direction of the train as measured by someone standing still outside the train?

Answers

Answer:

A.) 1.81 m/s

B.) 16.07 m/s

C.) 6.88 degree.

Explanation:

Given that Inside, two siblings 1.90 m apart are playing catch directly across the aisle. The kid wearing a Catherine Wheel T-shirt throws the ball horizontally north. The ball crosses the train and is caught 1.05 s later by her little brother.

The velocity of the ball will be

Velocity = displacement/ time

Where displacement = 1.90 m

Time = 1.05 s

Velocity = 1.9 / 1.05

Velocity = 1.8095

Velocity = 1.81 m/s

A.) From the little brother point of view, the magnitude of ball's velocity will be 1.81 m/s

B.) The magnitude of the velocity of the ball as seen by someone standing still outside the train will be achieved by first converting km/h to m/s

(54 × 1000) / 3600 = 15 m/s

Then, use pythagorean theorem to find the velocity

V = sqrt ( 15^2 + 1.81^2)

V = sqrt ( 225 + 3.2761)

V = sqrt ( 258.2761)

V = 16.07 m/s

C.) The angle will be

Tan Ø = 1.81 / 15

Tan Ø = 0.1206666

Ø = tan^-1(0. 1206666)

Ø = 6.88 degree.

An airplane traveled 2,400 meters in 3 seconds. How fast was the plane going?

Answers

Answer:

800 miles per hour

Explanation:

There are two ways that an object can get in motion. What are they?

Answers

Answer:

pull or push

Explanation:

According to Newton's first law of motion "An object will continue to stay or remain at rest or continue to be in constant motion "unless acted upon by an external force"

F= ma

Basically a force is a pull or a push

so in other words the two ways by which an object can get in motion is by

1. A pull force

2. A push force

9. Which unit goes with time
kg
K
s
mm

Answers

the unit “s” goes with time it stands for seconds
The unit “s” goes with Time.

An object is thrown upward at an angle θ above the ground, eventually returning to earth. (a) Is there any place along the trajectory where the velocity and acceleration are perpendicular? If so, where? at the initial position of motion at the highest point in the trajectory at the final position of motion velocity and acceleration are never perpendicular

Answers

Answer:

Yes, at the highest point in the trajectory velocity and acceleration are perpendicular.

Explanation:

Let [tex]x-[/tex]axis be the ground and [tex]y-[/tex]axis is the height above the ground. Let the initial velocity of the object is [tex]u[/tex] having angle [tex]\theta[/tex] with respect to ground and the acceleration due to gravity , [tex]g[/tex], is acting in vertically downward direction as shown in figure.

As gravitational force is acting in vertical direction, so, it will not change the horizontal velocity of the object. So, at any instant throughout the projectile motion the [tex]x-[/tex]component of the initial velocity will remailns constant, i.e. [tex]u_x=u \cos \theta[/tex].

While, due gravitational force, [tex]y-[/tex]component of the initial velocity will change. Initially, [tex]u_y=u \sin \theta[/tex] is in vertically upward direction and gravitational force is actiongn vertically downward direction, so, at first [tex]u_y[/tex] will decrease untill it reaches the highest point of the trajectory as shown. At the highest point the vertical component of the velocity [tex]u_y=0[/tex], so, there is only horizontal component of the velocity. i.e [tex]u_x= u \cos\theta[/tex] .

Now, the resultant velocity of the object at the highest point is [tex]u \cos \theta[/tex] which is in the horizontal direction while the acceleration , [tex]g[/tex] , (due to gravily) is actiog in vertically downward direction.

Hence, at the highest point in the trajectory velocity and acceleration are perpendicular.

During this moment, the two remain perpendicular even though the acceleration seems to be vertical well as the velocity seems to be horizontal.

Somewhere at the greatest point of the trajectory, vector quantities become perpendicular. Considering gravity constantly pushes downward, a projectile's acceleration would always be downward.Furthermore, because the vertical velocity of something like a projectile approaches zero at the height of its trajectory, the first and only portion of the velocity which thus might not be zero seems to be the horizontal factor.

Thus the response above is appropriate.

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_____ electrons are the most important electrons to an atom .

Answers

Answer:

stable is the answer

Explanation:

stable electrons

position (m)
80!
В
с
60
40
20
A
- 20
-40
10
20
30
40
50
time (sec)

Answers

Answer:

hola bb como estas dime bb en que te ayudo

Explanation:

You are given a vector in the XY plane that has a magnitude of 89.0 units and a y component of -70.0 units.

Answers

Hi I need help with my work can you help me please

A cement block accidentally falls from rest from the ledge of a 51.1-m-high building. When the block is 13.4 m above the ground, a man, 1.70 m tall, looks up and notices that the block is directly above him. How much time, at most, does the man have to get out of the way?

Answers

Answer:

The man has, at most, 0.4 secs to get out of the way

Explanation:

First, we will determine, the time the block takes to reach height 13.4 m above the ground.

Also, we will determine the time it will take to reach the man, if he does not notice it.

Then, the difference in the two times will be the time the man has to get out of the way.

From the formula

[tex]h =ut - \frac{1}{2}gt^{2}[/tex]

Where [tex]h[/tex] is height

[tex]u[/tex] is the initial velocity

[tex]t[/tex] is time

and [tex]g[/tex] is acceleration due to gravity ( Take [tex]g =[/tex] 9.8 m/s²)

Let the time the block takes to reach height 13.4 m be [tex]t_{1}[/tex]

The cement block falls from a 51.1 m high building, then by the time it reaches a height 13.4 m above the ground, the displacement is

13.4 m - 51.1 m = - 37.7 m  

The is the height the block has fallen from by the time it gets to a height 13.4 m above the ground

Then,  

[tex]h =ut - \frac{1}{2}gt^{2}[/tex]

[tex]-37.7 = (0)(t_{1}) - \frac{1}{2}(9.8)t_{1}^{2}[/tex]

(NOTE: [tex]u[/tex] = 0 m/s because the cement block falls from rest)

[tex]37.7 = 4.9t_{1}^{2}[/tex]

[tex]t_{1}^{2}= \frac{37.7}{4.9}[/tex]

[tex]t_{1}= \sqrt{7.69} \\[/tex]

[tex]t_{1}= 2.77 secs[/tex]

Hence, It takes the block 2.77 secs to reach height 13.4 m

Also,

Let the time it will take to reach the man be [tex]t_{2}[/tex]

The man is 1.70 m tall, hence, to reach the man, the cement block would have reached a height ( 1.70 m - 51.1 m) = - 49.4 m

Then,

[tex]h =ut - \frac{1}{2}gt^{2}[/tex]

[tex]-49.4 = (0)(t_{2}) - \frac{1}{2}(9.8)t_{2}^{2}[/tex]

[tex]49.4 = 4.9t_{2}^{2}[/tex]

[tex]t_{2}^{2} = \frac{49.4}{4.9}[/tex]

[tex]t_{2}= \sqrt{10.08}[/tex]

[tex]t_{2}= 3.17 secs[/tex]

Hence, it will take 3.17 secs to reach the man

Now, for the time the man has to get out of the way, that is

[tex]t_{2} - t_{1}[/tex] = 3.17 secs - 2.77 secs

= 0.4 secs

Hence, the man has, at most, 0.4 secs to get out of the way

Physics 1102 Experiment 5 Pre Lab Name_________________________________ Instructor name _________________________ You must show and explain all work in a neat and organized way to receive credit. Please show each step for calculations. YOU MUST TURN IN THIS SHEET. 1. (a) What does electrically neutral mean

Answers

Answer:

Explanation:

An atom is said to be electrically neutral, if the said atom contains equal or the same numbers of protons and electrons.

Worthy of note is that most bodies are normally close to being electrically neutral. This is because of the number of electrons on the body being equal to the number of protons on the same body. Charging a body means one would have to transfer electric charge to the body, or from the body. As a result, the number of electrons in the body will no longer be equal to the number of protons on the body.

A box of mass 20kg is pulled up an inclined plane by a force of 285N. Given that the value of the incline angle is 30 degrees and the coefficient of dynamic friction is 0.72, what is the speed with which the box is moving with, assuming it takes 4seconds to reach the top of the incline?

Answers

Given :

Mass of box , m = 250 kg.

Force applied , F = 285 N.

The value of the incline angle is 30°.

the coefficient of dynamic friction is [tex]\mu=0.72[/tex] .

To Find :

The speed with which the box is moving with, assuming it takes 4 seconds to reach the top of the incline.

Solution :

Net force applied in box is :

[tex]F=285 - mgsin\ \theta - \mu mg cos \ \theta\\ \\F=285-mg( sin \ \theta - \mu cos\ \theta)\\\\F=285 - 20\times 10( \dfrac{1}{2}+0.72\times \dfrac{\sqrt{3}}{2})\\\\F=60.29\ N[/tex]

Acceleration , [tex]a=\dfrac{F}{m}=\dfrac{60.29}{20}=3.01\ m/s^2[/tex].

By equation of motion :

[tex]v=u+at\\\\v=0+3.01\times 4\\\\v=12.04\ m/s[/tex]

Therefore, the speed of box is 12.04 m/s.

Hence, this is the required solution.  

Saturn is 890,700,000 miles from the Sun. What is this distance in scientific notation? The ratio of miles to meters is 1 mile equals 1.61 x 103 meters. What is this distance in meters? If the speed of light is 3.0 x 108 meters/second, how long does it take for light from the Sun to reach Saturn? Hint: Use the distance in meters to calculate.

Answers

Answer:

13 hours, 16 minutes, 41 seconds

Explanation:

Distance of Saturn from the Sun

= 890,700,000 miles

[tex] = 8.907\times 10^8 \: miles\\

= 8.907\times 10^8 \times 1.61 \times 10^3 \:meters\\

= 14.34027\times 10^{11}\: m\\

= 1. 434027\times 10^{12}\: m\\\\

\because Time = \frac{Distance}{Speed} \\

\therefore Time = \frac{1.434027\times 10^{12}}{3\times 10^8}\\

\therefore Time = 4.78009 \times 10^{12-8}\\

\therefore Time = 4.78009 \times 10^{4} \:seconds \\

\therefore Time = 47800.9 \:seconds\\

\therefore Time = 47801 \:seconds\\

\therefore Time = 13h\: 16m\: 41s\\[/tex]

Saturn is 890,700,000 miles from the Sun. This distance in the scientific notation would be 1.434×10¹² metes.

If the speed of light is 3.0 x 108 meters/second, then it would take 4780 seconds for light from the Sun to reach Saturn.

What is Velocity?

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The generally considered unit for velocity is a meter per second.

As given in the problem Saturn is 890,700,000 miles from the Sun

1 mile = 1.61 x 10³ meters

890,700,000 miles = 890,700,000×1.61×10³ meters

                                =1.434×10¹² metes

As given  If the speed of light is 3.0 x 10⁸ meters/second

Time = distance /speed

        = 1.434×10¹² metes / 3.0 x 10⁸ meters/second

        = 4780 seconds

Thus, the distance in the scientific notation would be 1.434×10¹² metes and it would take 4780 seconds for light from the Sun to reach Saturn.

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What three forms of energy are represented when a match is lit?

Answers

Answer:

Three forms of energy when a match is being lit are potential, kinetic and thermal.

hope this helps! :)

Explanation:

Answer:

Potential Energy

Kinetic Energy

Thermal Energy

Explanation:

After a group of researchers conducts a new experiment that has never been conducted before, what is the best way for other scientists to make sure that the data is real?

Answers

Answer:

I think it would be interviewing the researchers I'm unsure though

Answer:

Probably C) Conducting the experiment again

Explanation:

Option A is wrong because there is a chance that the group of researchers made a mistake or got the wrong data. So when interviewing the researchers, there is a chance of them giving the wrong data, especially since the experiment has never been conducted before.

Option B is wrong because the experiment the researchers where doing was new and has never been conducted before. Therefore there is no older research done on that topic.

Option C is correct because when conducted the experiment again, they can compare their results with the group of researchers. Checking if the data is correct.

Option D is wrong because the group of researchers might have made a mistake when writing down the procedure, leading to false data.

Which principle(s) of the cell
theory shows that all organisms
are somehow similar?

Answers

Explanation:

The unified cell theory states that: all living things are composed of one or more cells; the cell is the basic unit of life; and new cells arise from existing cells.

hope it helps

plz mark as brainliest

a ball rolling down a hill was displaced 21.9 m while using uniformly accelerating from rest, If the final velocity was 7.14 m/s, what was the rate of acceleration?

Answers

Answer:

a = 1.16 m/s²

Explanation:

In order to find the rate of acceleration of the ball, we will use third equation of motion, as follows:

2as = Vf² - Vi²

where,

a = rate of acceleration = ?

s = distance covered by the ball = 21.9 m

Vf = Final Velocity of the ball = 7.14 m/s

Vi = Initial Velocity of the ball = 0 m/s (Since, the ball started from rest)

Therefore,

2(a)(21.9 m) = (7.14 m/s)² - (0 m/s)²

a = (50.97 m²/s²)/(43.8 m)

a = 1.16 m/s²

A web page designer creates an animation in which a dot on a computer screen has a position of r⃗ =[ 4.50 cm +( 2.90 cm/s2 )t2]i^+( 4.70 cm/s )tj^ . Part A Find the average velocity of the dot between t=0 and t=2.0s. Give your answer as a pair of components separated by a comma. For example, if you think the x component is 3 and the y component is 4, then you should enter 3,4.

Answers

Answer:

V = (5.8cm/s)i, (4.7cm/s)j

Explanation:

Given :

r⃗ =[ 4.50 cm +( 2.90 cm/s2 )t2]i^+( 4.70 cm/s )tj^

To obtain the average velocity (V)

V = (r2 - r1) / (t2 - t1)

To obtain r1 and r2, substitute t1 = 0 and t2 = 2 respectively in the equation above

r1 = [ 4.50 cm +( 2.90 cm/s2 ) 0]i^+( 4.70 cm/s )0 j

r1 = 4.50 cm + 0 + 0 = (4.50cm)i + 0j

r2 = [ 4.50 cm +( 2.90 cm/s2 )2²]i^+( 4.70 cm/s )2 j

r2 = 4.50cm + (2.90 × 4)i + (4.70 × 2)j

r2 = (16.1cm)i + (9.4cm)j

V = [(16.1 - 4.50)i - (9.4 - 0)j] / 2 - 0

V = 11.6i / 2 ; 9.4j / 2

V = (5.8cm/s)i, (4.7cm/s)j

When air sinks, it:_________
(a) compresses and warms.
(b) reaches its equilibrium level and then begins to sink.
(c) expands and cools.
(d) forms into clouds.

Answers

Answer:

a) compresses and warms.

Explanation:

When air sinks, it falls down and compresses the air close to the surface of the ground, which raises the temperature of the air (since compression results in a rise in temperature). Also, as the air sinks, it prevent the already warm air close to the surface from rising, further increasing its own temperature, warming it up.

What did Rutherford’s model of the atom include that Thomson’s model did not have?
a nucleus
energy levels
electron clouds
smaller particles

Answers

Answer:

Yes the answer is A.)  A Nucleus

Explanation:

I took the test

Rutherford’s model of the atom included a nucleus  that Thomson’s model did not have, therefore the correct option is A

What are atomic models?

There are some models that are used to explain the arrangements of subatomic particles inside the atom based on the atomic theory of atom are known as the atomic models.

There are many types of atomic models proposed in past based on their individual assumptions and the experimentations

There are mainly five most widely accepted atomic models

John Dalton's atomic model which based on the assumption that all the entities of the universe are made up of the fundamental particle that is an atom.

J.J. Thomson's model: Plum Pudding model explains the arrangement of subatomic particles by taking the example of plum pudding in which positive charge is distributed uniformly throughout and the negative charge particles are sprinkled on it in a random fashion.

Rutherford's model explained the existence of a nucleus inside the atom by using the alpha particle bombardment experiment on a thin sheet of gold.

Niels Bohr's model explained the revolving nature of the electrons in the different shells around the nucleus of the atom.

Erwin Schrodinger's model explains the arrangement of the subatomic particles as the electron Cloud Model also known as the Quantum Model.

Rutherford’s model of the atom included a nucleus  that Thomson’s model did not have, therefore the correct option is A

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Which refers to the ratio of output work to input work of a machine expressed as a percent?
total work
wattage
efficiency
power

Answers

Answer:

Efficiency Or C. on e2020

The ratio of output work to input work of a machine expressed as a percent refers to efficiency of the machine.

What is efficiency of machine?

How well a machine converts its input energy into useable output energy, or work, is referred to as its efficiency. It is the portion or percentage of the output divided by the input, and it plays a significant role in a machine's utility.

It denotes the degree of performance that requires the fewest inputs to provide the greatest amount of output in more mathematical or scientific words. It frequently particularly refers to the ability of a particular application of effort to deliver a particular output with the least amount of waste, expense, or superfluous work. Efficiency covers a wide range of inputs and outputs across numerous disciplines and sectors.

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Michael threw a football and it traveled for 8 seconds at a velocity of 3 meters per second. How far did the football travel?

Answers

It traveled 24 meters

Suppose you first walk 12.0 m in a direction 200 west of north and then 20.0 m in a direction 40.00 south of west. How far are you from your starting point, and what is the compass direction of a line connecting your starting point to your final position?

Answers

Complete Question

The  complete question is shown on the first uploaded image

Answer:

the compass direction of the resultant displacement is  [tex]\theta  =4.7^o [/tex] south of west

Explanation:

Generally using cosine we can obtain the resultant R as follows

     [tex]R^2  =  A^2  + B^2 -2ABcos(70)[/tex]

=>   [tex]R  =  \sqrt{12^2  + 20^2  - 2(12 ) *  (20) cos  70}[/tex]

=>    [tex]R  =  19.48 \  m[/tex]

We can obtain the direction of the resultant by first  using sine rule to obtain angle C as follows

       [tex]\frac{A}{sin  C}  =  \frac{R}{sin70 }[/tex]

=>    [tex]C=  sin ^{-1} [\frac{A *  (sin 70)}{R} ][/tex]

=>    [tex]C =  sin ^{-1} [\frac{20 *  (sin 70)}{19.48} ][/tex]

=>  [tex]C =  74.7 ^o[/tex]

Then the direction is obtained as

       [tex]\theta  =  C  -  70[/tex]

=>    [tex]\theta  = 74.7   -  70[/tex]

=>     [tex]\theta  =4.7^o [/tex]

Hence the compass direction of the resultant displacement is  [tex]\theta  =4.7^o [/tex] south of west

What is applied force?

Answers

Answer:

An applied force is a force that is applied to an object by a person or another object. If a person is pushing a desk across the room, then there is an applied force acting upon the object.

Explanation:

What is a population?
Group of answer choices
A. a group of individuals of the same species living in the same area
B. a group of different species living in the same area
C. a group of individuals of the same species living in separated areas a group of different species living in separated areas

Answers

Answer:

A

Explanation:

A sperm whale can accelerate at about 0.0800 m/s 2 0.0800 m/s 2 when swimming on the surface of the ocean. How far will a sperm whale travel if it starts at a speed of 0.700 m/s 0.700 m/s and accelerates to a speed of 2.18 m/s 2.18 m/s ? Assume the whale travels in a straight line.

Answers

Answer:

26.64 m

Explanation:

Given the following :

Acceleration at ocean surface = 0.0800 m/s²

Distance covered if initial speed = 0.700 m/s and accelerates to a speed of 2.18m/s

Using the equation :

v² = u² + 2as

Where ;

v = final velocity ; u = initial velocity ; a = acceleration ; s = distance covered

Therefore,

v² = u² + 2as

2.18² = 0.7² + (2 × 0.08 × s)

4.7524 = 0.49 + 0.16s

4.7524 - 0.49 = 0.16s

4.2624 = 0.16s

s = 4.2624 / 0.16

s = 26.64 m

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