What is a push or pull that one object excerpts on another object?

Given :

Mass, m = 68.05 kg.

To Find :

How much gravitational force would you experience on mars ?

Solution :

Acceleration due to gravity on mars is, g = 3.711 m/s²

( You can find it on internet )

Now, weight can be given as :

W = mg

W = 68.05 kg × 3.711 m/s²

W = 252.533 kg m/s² = 252.533 N

Hence, this is the required solution.

Answer:

117.8 m/s

Explanation:

Given that:

String length, L = 0.28

pipe length, L' = 0.82

Speed of sound in air, v = 345 m/s

n = 3 (3rd harmonic)

Frequency, f of 3rd harmonic ;

f = (v*n) / 2L - - - - (1)

for the pipe: ; 3rd harmonic

f = (v*n) / 2L' - - - (2)

Equating (1) and (2)

(v*n) / 2L = (v*n) / 2L'

2L' * v * n = v* n * 2L

v = vL / L'

v = (345 * 0.28) / 0.82

v = 96.6 / 0.82

v = 117.80487

v = 117.8 m/s

Answer:

5

Explanation:

Answer:

If there is a large difference between the concentration of one fluid and the concentration of the other, then the particles will diffuse faster. In the experiment, the dye particles in the food coloring are very concentrated.

Explanation:

Answer: I think this is the answer, In a collision, there is a force on both objects that causes an acceleration of both objects; the forces are equal in magnitude and opposite in direction. For collisions between equal-mass objects, each object experiences the same acceleration.

Explanation: I had a question similar to this, Hope this helps!

Answer:

44.5s ; 22.64 m/s

Explanation:

The motion of the truck could be separated into 3 different phases :

First :

Time of motion :

Initial Velocity, u = 0 ; final velocity, v = 29 m/s

Acceleration, a = 2 m/s²

Recall: acceleration = change in velocity / time

Time = change in velocity / acceleration

Time = (29 - 0) / 2 = 14.5 second

Distance traveled = ((29 + 0) /2) * 14.5 = 210.25 m

Second :

Time = 25 seconds at constant speed

29 m/s for 25 seconds

v*t = 29 * 25 = 725 m

Third:

5 seconds before coming to rest

((29 + 0) /2) * 5

14.5 * 5 = 72.5 m

A.)

Length of journey = (14.5+ 25 + 5) = 44.5 seconds

B.)

Average velocity = total distance / total time taken

Average velocity = (210.25 + 725 + 72.5) / 44.5

= 1007.75 / 44.5

= 22.646067

= 22.64 m/s

Answer:

d = 10.2 m

Explanation:

When the car travels up the inclined plane, its kinetic energy will be used to do the work in climbing up. So according to the law of conservation of energy, we can write that:

[tex]Kinetic\ Energy\ of\ the \ Car = Work\ Done\ while\ moving\ up\ the\ plane\\\frac{1}{2}mv^{2} = Fd[/tex]

where,

m = mass of car

v = speed of car at the start of plane = (36 km/h)(1000 m/1 km)(1 h/3600 s)

v = 10 m/s

F = force on the car in direction of inclination = W Sin θ

W = weight of car = mg

θ = Angle of inclinition = 30°

d = distance covered up the ramp = ?

Therefore,

[tex]\frac{1}{2}mv^{2} = mgdSin\theta\\\frac{1}{2}v^{2} = gdSin\theta\\\frac{1}{2}(10\ m/s)^{2} = d(9.81\ m/s^{2}) Sin\ 30^{0}[/tex]

d = 10.2 m

Answer:

50.97 m

Explanation:

m = Mass of truck

[tex]\mu_s[/tex] = Coefficient of static friction = 0.4

v = Final velocity = 0

u = Initial velocity = 72 km/h = [tex]\dfrac{72}{3.6}=20\ \text{m/s}[/tex]

s = Displacement

Force applied

[tex]F=ma[/tex]

Frictional force

[tex]f=\mu_s mg[/tex]

Now these forces act opposite to each other so are equal. This is valid for the case when the load does not slide

[tex]ma=\mu_s mg\\\Rightarrow a=\mu_s g\\\Rightarrow a=0.4\times 9.81\\\Rightarrow a=3.924\ \text{m/s}^2[/tex]

Since the obect will be decelerating the acceleration will be [tex]-3.924\ \text{m/s}^2[/tex]

From the kinematic equations we have

[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-20^2}{2\times -3.924}\\\Rightarrow s=50.97\ \text{m}[/tex]

So, the minimum distance at which the car will stop without making the load shift is 50.97 m.

Answer:

v = 5.7554 m/s

Explanation:

First of all we need to know if the angle of the vine is measured in the horizontal or vertical.

To do this easier, let's assume the angle is measured with the horizontal. In this case, the innitial height of the monkey will be:

h₀ = h sinα

h₀ = 5.32 sin43° = 3.6282 m

As the monkey is dropping from the innitial point which is the suspension point, is also dropping from 5.32. Then the actual height of the monkey will be:

Δh = 5.32 - 3.63 = 1.69 m

In order to calculate the speed of the monkey we need to understand that the monkey has a potential energy. This energy, because of the gravity, is converted in kinetic energy, and the value will be the same. Therefore we can say that:

Ep = Ek

From here, we can calculate the speed of the monkey.

Ep = mgΔH

Ek = 1/2 mv²

The potential energy is:

Ep = 16.9 * 9.8 * 1.69 = 279.9

Now with the kinetic energy:

1/2 * (16.9) * v² = 279.9

v² = (279.9) * 2 / 16.9

v² = 33.12

v = √33.12

Hope this helps

some positions are quarterback, offence, defense, linebacker, and wider receiver hoped it helped :)

Answer: Charge 3 is located on the x-axis a distance of 0.67 cm from charge 1 and 1.33 cm from charge 2.

Explanation: Electrostatic Force is the force of repulsion or attraction between two charged particles. It's directly proportional to the charge of the particles and inversely proportional to the distance between them:

[tex]F=k\frac{|q||Q|}{r^{2}}[/tex]

k is an electrostatic constant

For the system of 3 particles, suppose distance from 1 to 3 is x meters, so, distance from 2 to 3 is (0.02-x) meters.

Force will be

[tex]F_{13}=F_{23}[/tex]

[tex]k\frac{q_{1}q_{3}}{r_{13}^{2}} =k\frac{q_{2}q_{3}}{r_{23}^{2}}[/tex]

[tex]\frac{q_{1}}{r_{13}^{2}} =\frac{q_{2}}{r^{2}_{{23}}}[/tex]

Substituting:

[tex]\frac{2.10^{-6}}{x^{2}} =\frac{8.10^{-6}}{(0.02-x)^{2}}[/tex]

[tex]8.10^{-6}x^{2}=2.10^{-6}(0.0004-0.04x+x^{2})[/tex]

[tex]4x^{2}=x^{2}-0.04x+0.0004[/tex]

[tex]3x^{2}+0.04x-0.0004=0[/tex]

Solving quadratic equation using Bhaskara:

[tex]x_{1}=\frac{-0.04+\sqrt{(0.04)^{2}+0.048} }{6}[/tex]

[tex]x_{2}=\frac{-0.04-\sqrt{(0.04)^{2}+0.048} }{6}[/tex]

x₂ will give a negative value and since distance can't be negative, use x₁

[tex]x_{1}=\frac{-0.04+\sqrt{0.0064} }{6}[/tex]

x₁ = 0.0067 m

The position of charge 3 is 0.67 cm from charge 1 and 1.33 cm from charge 2.

Answer:

Mass of player 2 is 55.044kg

Explanation:

Step one:

given data

Weight of player 1= 900 N

mass= weight/acceleration due to gravity

mass of player= 900/9.81

m1= 91.74kg

v1= 8m/s

mass of player 2

m2= ?

v2= 0m/s

Step two:

from the problem description, after impact, they both moved with a common velocity of V= 5m/s, hence the collision is an inelastic collision

the expression for inelastic collision is

m1v1+m2v2=(m1+m2)V

substitute

91.74*8+m2*0=(91.74+m2)5

733.92=458.7+5m2

275.22=5m2

divide both sides by 5

m2=275.22/5

m2=55.044kg

The weight of player two is

=55.044*9.81

=539.98N

Answer:

The  velocity of the waves in the string is 30 m/s.

Explanation:

Given;

frequency of the wave, F = 60.0 Hz

number of loops, n = 5

length of the string, L = 1.25 m

1 loop, L  = λ/2

For 5 loops;

[tex]L = \frac{5\lambda}{2}[/tex]

where;

λ is the wavelength

[tex]L = \frac{5 \lambda}{2} \\\\5 \lambda = 2L\\\\\lambda = \frac{2L}{5} \\\\\lambda = \frac{2 \ \times \ 1.25}{5} \\\\\lambda = 0.5 \ m[/tex]

The velocity of the waves in the string is calculated as;

V = Fλ

V = (60)(0.5)

V = 30 m/s

Therefore, the  velocity of the waves in the string is 30 m/s.

Answer:

10.44 liters of gasoline.

Explanation:

First, we need to convert the units of the car from mi/gal to km/L as follows:

[tex] mileage = 32.0 \frac{mi}{gal}*\frac{1.609 km}{1 mi}*\frac{1 gal}{3.785 L} = 13.60 km/L [/tex]

That means that for every liter of gasoline the car travels 13.60 kilometers.

So, to complete a 142-km trip in Europe the volume of gasoline needed is:

[tex] V = \frac{1 L}{13.60 km}*142 km = 10.44 L [/tex]

Therefore, to complete a 142-km trip in Europe we need to buy 10.44 liters of gasoline.

I hope it helps you!                

Answer:

C increase in potential energy

The work done by the given force should be -45 joules

Since force acts in the negative y direction

So,

F = -15j

here the displacement vector is d = 3i+3j-1k

Now

work done is W = dot product of force and displacement

                        = [-15j ] . [ 3i+3j-1k]

                        =-45 joules

Therefore, The work done by the given force should be -45 joules

Learn more about force here:

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Answer:

21977.56kg⋅m/s

Explanation:

Step one:

Given data

Weight of car= 9800N

The mass of the car is

m= w/g

m= 9800/9.81

m=998.98kg

Velocity of car= 22 m/s

time of impact= 0.5 seconds

Required

The impulse of the force F

Step two:

Ft= mv

Ft= 998.98*22

Ft=21977.56kg⋅m/s

The impulse is 21977.56kg⋅m/s

Answer:

a= 17.69 m/s^2

Explanation:

Step one:

given data

A car accelerates uniformly from rest to 23 m/s

u= 0m/s

v= 23m/s

distance= 30m

Step two:

We know that

acceleration= velocity/time

also,

velocity= distance/time

23= 30/t

t= 30/23

t= 1.30 seconds

hence

acceleration= 23/1.30

accelaration= 17.69 m/s^2

Answer:

T = 3.14 10⁻²  s

Explanation:

The general equation for a traveling transverse wave is

           y = A sin (k x - wt +Ф)

where w is the angular velocity that is related to the period and Ф is the phase of the oscillation

           w = 2π / T          (1)

In this case they indicate that the expression of the wave

         y = 0.003 cos (20 x + 200t)

if we use the relationship of the double angles

          a = kx - wt

          b = Ф

          sin (a + b) = sin a cos b + sin b cos a

for the case Ф = 90 we have

          sin (a + b) = cos b

we substitute

          y = A cos (kx -wt)

with an initial phase of fi = 90º

if we compare the terms of the two expressions

         A = 0.003 m  

         k = 20 m⁻¹

         w = -200  rad/s

the negative sign indicates that the wave goes to the left

if we clear from equation 1

          T = 2π / w

          T = 2π / 200

          T = 3.14 10⁻²  s

Answer:

392 Nm or J

Explanation:

Work is equal to force times distance. The force required is the mass times acceleration - in this case F = 5kg x 9.81 ( gravity) = 49N. So work is 49N x 8m = 392 Nm or Joules.

Answer:

the frequency of the beats is 8.7687 kHz

Explanation:  

Given the data in the question;

The frequency for stationary source and moving observer is;

f' = f( 1 +( v_observer/v_sound))

we know that, speed of sound in dry air =  343 m/s

so we substitute

f' = 41.2 kHz( 1 + (33.0 m/s / 343 m/s) ) = 41.2kHz( 1 + 0.0962) = 41.2kHz(1.0962)

f' = 45.1634 kHz

Now the frequency for stationary observer and moving source with frequency f' will be

f" = f'( 1 / (1 - ( v_observer/v_sound)))

45.1634 kHz( 343 / 343 - 33)

we substitute

f" = 45.1634 kHz( 1 / (1 - (33.0 m/s / 343 m/s)))

f" = 45.1634 kHz( 1 / (1 - 0.0962))

f" = 45.1634 kHz( 1 / 0.9038 )

f" = 45.1634 kHz( 1.1064 )

f" = 49.9687 kHz

Now the beat frequency will be;

f_beat = f' - f

we substitute

f_beat = 49.9687 kHz - 41.2 kHz

f_beat = 8.7687 kHz

Therefore, the frequency of the beats is 8.7687 kHz

Answer: Change occurs when forces in one direction exceed forces in opposing direction

Explanation:

Force field analysis is the basic tool typically used in root cause analysis which enable an individual to take certain action after the identification of the root cause.

According to force-field analysis, there is a change when the forces in one direction exceed the forces in opposing direction.

Answer:

B - the box pushing against the boy

Explanation:

Newton's third law of motion also known as the law of action and reaction  states that for every action there is equal and opposite reaction.

The action force is the force acting in one direction while the reaction force is  the force acting in the opposite direction. for example, when a person wants to jump, the person exerts a downward force on the ground known as action force and also, the ground exerts upward force on the person known as reaction force.

If the action force is the boy pushing the box, what is the reaction force is the box pushing against the boy.

If we compare the energy of visible light to the energy of X-rays, we find that X-rays have a much higher frequency. Usually, electromagnetic radiation with higher frequency (energy) have a higher degree of penetration than those with low frequency.

Answer:

5.67

Explanation:

force is = m x a

which will give us

0.63

x 9

= 5.67

Answer:

37.33m

Explanation:

Using the equation of motion

S = ut + 1/2gt^2

Time t = 2.76secs

g = 9.8m/s^2

S = 0 + 1/2(9.8)(2.76)^2

S = 4.9*7.6176

S = 37.33

Hence the window is 37.33m above the ground

Answer:

Positive charge is attracted to the neutral object.

Explanation:

Recall ; Like charges repel, unlike charges attract. This phrase simply means (positive (+) is attracted to negative (-ve) and vuc versa while both positive, positive and negative, negative charge repel.

For a neutral object. The quantity of positive charge equals the quantity of negative charges. This simply means a neutral object contains charges as well, which are usually scattered or randomly aligned.

Therefore, when a positive charge is brought near a neutral body, the order of alignment of the charges change, with the negative charge all moving towards the direction of the positively charged body and the positive charges in the neutral body aligning in the opposite direction.

The charge will be attracted.

As you may know, opposite charges attract (and equal charges repel).

So, when you put a positive charge near a neutral material, all the negative charges in the material will move towards the surface of the material closer to the positive charge (and the positive charges in the material will move away).

Now the charge in the material is not homogeneous, so the positive charge will see a negatively charged surface near it, and it will be attracted to that surface.

Thus we can conclude that as a positive charge is brought near a neutral, insulating piece of material, the charge will be attracted towards it.

If you want to learn more about electromagnetic forces, you can read:

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Answer:

Collection. or Precipitation.

Explanation:

b or d

The part of the water cycle when ocean water may end up in the river is to be considered as the condensation.

It is the change with regard to the state of matter from the gas phase into the liquid phase. Also, it should be considered as the reverse of vaporization.

So based on this, we can say that The part of the water cycle when ocean water may end up in the river is to be considered as the condensation.

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