Answer:
y=7
Step-by-step explanation:
The slope is (7-7)/(3+7) = 0. So, the line is a horizontal line.
The y value of both points is 7.
A survey asked 50 students if they play an instrument and if they are in band.
1.25 students play an instrument.
2. 20 students are in band.
3. 30 students are not in band.
Which table shows these data correctly entered in a two-way frequency?
C, just look at the "Total" for each single information.
the values in the inner grid combine multiple informations.
The table shows these data correctly entered in a two-way frequency is table C.
What is Two way Frequency?Two-way frequency tables show the potential connections between two sets of categorical data visually. The table's four (or more) inside cells contain the frequency (count) data, which is displayed above and to the left of the table's designated categories.
We have been the information 25 students play an instrument 20 are in a band 30 are not in a band.
So, the two way table is:
Band Not in Band Total
Play instrument 20 5 25
Do not play instrument 0 25 25
Total 20 30 50
So, Table C is Correct.
Learn more about two-way frequency here:
https://brainly.com/question/9033726
#SPJ7
Teresita wanted to buy a dress for $50, but she decided to wait because she didn't have
enough money. A week later, the price had gone up 20%. Now she definitely had to wait to
buy it. A week later, she went back to the store, and the price had gone down 20% from the
last price. Teresita finally bought the dress. What did she pay for it?
Answer:
$48
Explanation:
> 50 x .20 = $10
$50 + $10= $60
-----------------------------
> 60 x .20 = $12
$60 - $12= $48
CAN SOMEBODY ANSWER MY QUESTIONS !!!!
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Answer:
A''(-1, 2)B''(3, 5)C''(4, 3)Step-by-step explanation:
Reflection over the line x=a is the transformation ...
(x, y) ⇒ (2a -x, y)
Then the double reflection over x=a and x=b is the transformation ...
(x, y) ⇒ (2b -(2a -x), y) = (2(b-a) +x, y)
That is, the result is translation by twice the distance between the lines. For a=1 and b=3, the transformation is ...
(x, y) ⇒ (x +4, y) . . . . . . . translation to the right by 4 units.
A(-5, 2) ⇒ A''(-1, 2)
B(-1, 5) ⇒ B''(3, 5)
C(0, 3) ⇒ C''(4, 3)
Which of the following represents the factorization of the trinomial below?
- 4x3 - 4x2 +24 x
O A. -4(x2-2)(x+3)
B. -4(x2 + 2)(x+3)
O C. -4x(x + 2)(x+3)
D. -4x(x - 2)(x+3)
Answer:
D. -4x(x - 2)(x+3)
Step-by-step explanation:
We are given the following trinomial:
[tex]-4x^3 - 4x^2 + 24x[/tex]
-4x is the common term, so:
[tex]-4x(\frac{-4x^3}{-4x} - \frac{4x^2}{-4x^3} + \frac{24x}{-4x}) = -4x(x^2+x-6)[/tex]
The second degree polynomial can also be factored, finding it's roots.
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]
[tex]\Delta = b^{2} - 4ac[/tex]
x² + x - 6
Quadratic equation with [tex]a = 1, b = 1, c = -6[/tex]
So
[tex]\Delta = 1^{2} - 4(1)(-6) = 25[/tex]
[tex]x_{1} = \frac{-1 + \sqrt{25}}{2} = 2[/tex]
[tex]x_{2} = \frac{-1 - \sqrt{25}}{2} = -3[/tex]
So
[tex]x^2 + x - 6 = (x - 2)(x - (-3)) = (x - 2)(x + 3)[/tex]
The complete factorization is:
[tex]-4x(x^2+x-6) = -4x(x - 2)(x + 3)[/tex]
Thus the correct answer is given by option d.
A ball is thrown upward with an initial velocity (v) of 13 meters per second. Suppose that the initial height (h) above the ground is 7 meters. At what time t will the ball hit the ground? The ball is on the ground when S=0. Use the equation S=−5t2+vt+h.
Answer:
the correct answer is, 4
Move the numbers to the lines to order them from least to greatest.
least
greatest
67.98
68.6
68.11
Please answer ASAP
Answer:
67.98,68.11, 68.6
Which graph shows the quadratic function y = 3x2 + 12x + 10? (5 points)
The following graph is labeled A: A four quadrant graph with a parabola opening up, passing through the points negative 3, 1, negative 2, negative 2, and negative 1, 1 with the vertex at 2, negative 2. The following graph is labeled B: A four quadrant graph with a parabola opening up, passing through the points 1, 4, 2, 1, and 3, 4 with the vertex at 2, 1. The following graph is labeled C: A four quadrant graph with a parabola opening up, passing through the points negative 3, 5, negative 2, 2, and negative 1, 5 with the vertex at negative 2, 2. The following graph is labeled D: A four quadrant graph with a parabola opening up, passing through the points 1, 1, 2, negative 2, and 3, 1 with the vertex at 2, negative 2.
Answer:
The correct graph is A.
Answer:
A i got it right
Step-by-step explanation:
If g(x)=x+1/x-2 and h(x) = 4 – x, what is the value of (9*h)(-3)?
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Answer:
(g·h)(-3) = 2.8
Step-by-step explanation:
Given:
g(x) = (x +1)/(x -2)
h(x) = 4 -x
Find:
(g·h)(x) = g(x) × h(x) for x = -3
Solution:
g(-3) = (-3+1)/(-3-2) = -2/-5 = 2/5
h(-3) = 4 -(-3) = 4 +3 = 7
Then the product is ...
g(-3)·h(-3) = (2/5)(7) = 14/5 = 2.8
(g·h)(-3) = 2.8
question is in picture
Answer: A
Step-by-step explanation:
(tangent is opposite over adjacent)
[tex]tan(40)=\frac{x}{3.8}\\x=3.8*tan(40)[/tex]
I NEED HELP ON C,E,F,G PLEASE ASAP!!!!
Which table represents a linear function
Answer:
3rd option (top right)
Step-by-step explanation:
3rd option represents a linear equation
y = -2x-1
Answered by GAUTHMATH
prove that.
lim Vx (Vx+ 1 - Vx) = 1/2 X>00
Answer:
The idea is to transform the expression by multiplying [tex](\sqrt{x + 1} - \sqrt{x})[/tex] with its conjugate, [tex](\sqrt{x + 1} + \sqrt{x})[/tex].
Step-by-step explanation:
For any real number [tex]a[/tex] and [tex]b[/tex], [tex](a + b)\, (a - b) = a^{2} - b^{2}[/tex].
The factor [tex](\sqrt{x + 1} - \sqrt{x})[/tex] is irrational. However, when multiplied with its square root conjugate [tex](\sqrt{x + 1} + \sqrt{x})[/tex], the product would become rational:
[tex]\begin{aligned} & (\sqrt{x + 1} - \sqrt{x}) \, (\sqrt{x + 1} + \sqrt{x}) \\ &= (\sqrt{x + 1})^{2} -(\sqrt{x})^{2} \\ &= (x + 1) - (x) = 1\end{aligned}[/tex].
The idea is to multiply [tex]\sqrt{x}\, (\sqrt{x + 1} - \sqrt{x})[/tex] by [tex]\displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}}[/tex] so as to make it easier to take the limit.
Since [tex]\displaystyle \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}} = 1[/tex], multiplying the expression by this fraction would not change the value of the original expression.
[tex]\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \lim\limits_{x \to \infty} \left[\sqrt{x} \, (\sqrt{x + 1} - \sqrt{x})\cdot \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}}\right] \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}\, ((x + 1) - x)}{\sqrt{x + 1} + \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}}\end{aligned}[/tex].
The order of [tex]x[/tex] in both the numerator and the denominator are now both [tex](1/2)[/tex]. Hence, dividing both the numerator and the denominator by [tex]x^{(1/2)}[/tex] (same as [tex]\sqrt{x}[/tex]) would ensure that all but the constant terms would approach [tex]0[/tex] under this limit:
[tex]\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x} / \sqrt{x}}{(\sqrt{x + 1} / \sqrt{x}) + (\sqrt{x} / \sqrt{x})} \\ &= \lim\limits_{x \to \infty}\frac{1}{\sqrt{(x / x) + (1 / x)} + 1} \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1}\end{aligned}[/tex].
By continuity:
[tex]\begin{aligned} & \lim\limits_{x \to \infty} \sqrt{x} \, (\sqrt{x + 1} - \sqrt{x}) \\ &= \cdots\\ &= \lim\limits_{x \to \infty} \frac{\sqrt{x}}{\sqrt{x + 1}+ \sqrt{x}} \\ &= \cdots \\ &= \lim\limits_{x \to \infty} \frac{1}{\sqrt{1 + (1/x)} + 1} \\ &= \frac{1}{\sqrt{1 + \lim\limits_{x \to \infty}(1/x)} + 1} \\ &= \frac{1}{1 + 1} \\ &= \frac{1}{2}\end{aligned}[/tex].
Answer:
Hello,
Step-by-step explanation:
[tex]\displaystyle \lim_{x \to \infty} \sqrt{x}*(\sqrt{x+1}-\sqrt{x} ) \\\\\\= \lim_{x \to \infty}\dfrac{ \sqrt{x}*(\sqrt{x+1}-\sqrt{x} )*(\sqrt{x+1}+\sqrt{x} )}{\sqrt{x+1} +\sqrt{x} } \\\\= \lim_{x \to \infty} \dfrac{\sqrt{x} *1}{\sqrt{x+1} +\sqrt{x} } \\\\\\= \lim_{x \to \infty} \dfrac{1} {\sqrt {\dfrac {x+1} {x} }+\sqrt{\dfrac{x}{x} } } \\\\\\=\dfrac{1} {\sqrt {1}+\sqrt{1} } \\\\\\=\dfrac{1} {2} \\[/tex]
A math professor is wondering if students today are better or worse than in the past. He has given the same final to this year's class that he gave ten years ago. Compute mean, median, and mode for both classes and write a paragraph summarizing the differences.
This Year
35 45 65 75 87
80 69 71 53 90
99 95 70 82 73
93 67 61 57 74
72 77 71 81 83
Ten Years Ago
56 77 75 76 59
74 51 89 55 79
67 77 69 91 68
90 65 79 69 79
87 86 98 91 95
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following data:
This year :
35, 45, 53, 57, 61, 65, 67, 69, 70, 71, 71, 72, 73, 74, 75, 77, 80, 81, 82, 83, 87, 90, 93, 95, 99
Mean = ΣX / n = 1825 / 25 = 73
The mode = 71 ( most frequently occurring)
Median = 1/2(n+1)th term = 1/(26) = 13th term
Median = 73
10 years ago :
51, 55, 56, 59, 65, 67, 68, 69, 69, 74, 75, 76, 77, 77, 79, 79, 79, 86, 87, 89, 90, 91, 91, 95, 98
Mean = ΣX / n = 1902 / 25 = 76.08
The mode = 79 ( most frequently occurring)
Median = 1/2(n+1)th term = 1/(26) = 13th term
Median = 77
According to the computed statistics, we can conclude that, today is worse than the past as the average score which is almost similar to the median value is higher 10 years ago and the modal score is better 10 years ago as well.
HELP ASAP PIC IS BELOW!!!
Answer:
55°
Step-by-step explanation:
Vertical angles are similar
Answered by GAUTHMATH
I need help completing this problem ASAP
Answer:
8 sqrt(5)
Step-by-step explanation:
sqrt(45) + sqrt(125)
Rewriting
sqrt(9*5) + sqrt( 25 *5)
we know sqrt(ab) = sqrt(a) sqrt(b)
sqrt(9) sqrt(5) + sqrt(25) sqrt(5)
3 sqrt(5)+5 sqrt(5)
Add like terms
8 sqrt(5)
Answer:
A. [tex] 8\sqrt{5} [/tex]
Step-by-step explanation:
[tex] \sqrt{45} + \sqrt{125} = [/tex]
[tex] = \sqrt{9 \times 5} + \sqrt{25 \times 5} [/tex]
[tex] = 3\sqrt{5} + 5\sqrt{5} [/tex]
[tex] = 8\sqrt{5} [/tex]
write 6x10x10x10x10 with an expont
Answer:
6x10^4
Step-by-step explanation:
Suppose a jar contains 7 red marbles and 28 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same time, find the probability that both are red.
Answer:
3/85
Step-by-step explanation:
that's the answer above
I need help answering this ASAP
Answer:
A the input x=3 goes to two different output values
Step-by-step explanation:
This is not a function
x = 3 goes to two different y values
x = 3 goes to t = 10 and y = 5
Find the measure of the missing angles.
Answer:
Step-by-step explanation:
Find x. Round your answer to the nearest tenth of a degree.
Answer: x=52.6°
Step-by-step explanation:
To find the value of x, we have to use our SOHCAHTOA. We can eliminate sine and cosine because both uses hypotenuse, which is not labelled. Therefore, we use tangent.
[tex]tan(x)=\frac{17}{13}[/tex]
To find x, we want to use inverse tangent.
[tex]x=tan^{-1}(\frac{17}{13} )[/tex] [plug into calculator]
[tex]x=52.6[/tex]
Now, we know that x=52.6°.
Find the product and simplify your answer 6w(5w^2-5w+5)
help. WORTH 15 POINTS!!!
Answer:
x=27
Step-by-step explanation:
The sum of the angles of a triangle are 180 degrees
90 + x+15 + 2x-6 = 180
Combine like terms
3x+99=180
Subtract 99 from each side
3x+99-99=180-99
3x =81
Divide each side by 3
3x/3 = 81/3
x=27
Which function is graphed?
(Help please)
Answer:
the function that is graphed is y=½CSC(x)
14. In a garden 746496 apple trees are arranged in such a way that, there are as inany rows as there are in a row. How many rows are there in the garden
Answer:
864
Step-by-step explanation:
do the square root of the total number
Solve for x.
5x - 3 = 12
A) X = 3
B) X = -3
C) X = -9/5
D) X = 9/5
Answer:
A. x = 3
Step-by-step explanation:
5x - 3 = 12
5x = 12 + 3
5x = 15
x = 15/5
= 3
Anyone know how to do this
Answer:
30 cm
Step-by-step explanation:
Since the length of tangents drawn from a point are equal, the perimeter is 3+3+9+9+3+3=30
Answer:
30 centimeter
Use the distributive property to find the product of the rational number.
5/2 (- 8/5 + 7/5)
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Answer:
-1/2
Step-by-step explanation:
The factor outside parentheses multiplies each term inside.
5/2(-8/5 +7/5)
= (5/2)(-8/5) +(5/2)(7/5)
= -8/2 +7/2 = -1/2
Suppose a young sedentary woman wanted to lose 30 pounds of body fat in a period of 20 weeks. She now weighs 160 pounds and her activity level is such so she needs 15 Calories per pound of body weight to maintain her weight. Calculate the number of Calories she may consume daily in order to lose the 30 pounds by diet only. 1,000 1,250 1,400 1,650 1,900
Answer:
The answer is "1900"
Step-by-step explanation:
It takes 500 fewer calories per day for her to lose 1 lb of weight every week.
[tex]\to (15 \times 160)-500 =(2400)-500 =2400-500=1900[/tex]
given that the following two are geometric series are convergent: 1+x+x^2+x^3+...and 1-x+x^2-x^3+... determine the value(s) of x for which the sum of the two series is equal to 8
Let S and T denote the two finite sums,
S = 1 + x + x ² + x ³ + … + x ᴺ
T = 1 - x + x ² - x ³ + … + (-x) ᴺ
• If both S = 8 and T = 8 as N goes to infinity:
Then
xS = x + x ² + x ³ + x ⁴ + … + x ᴺ⁺¹
-xT = -x + x ² - x ³ + x ⁴ + … + (-x) ᴺ⁺¹
so that
S - xS = 1 - x ᴺ⁺¹ ==> S = (1 - x ᴺ⁺¹)/(1 - x)
and similarly,
T = (1 - (-x) ᴺ⁺¹)/(1 + x)
For both sums, so long as |x| < 1, we have
lim [N → ∞] S = 1/(1 - x)
lim [N → ∞] T = 1/(1 + x)
Then if both sums converge to 8, this happens for
S : 1/(1 - x) = 8 ==> x = 7/8
T : 1/(1 + x) = 8 ==> x = -7/8
• If the sum S + T = 8 as N goes to infinity:
From the previous results, we have
1/(1 - x) + 1/(1 + x) = 8 ==> x = ±√3/2
Please Help with this
Answer:
csc = 6/5= 1.2
cot = √(11)/5= 0.6633
sin = 5÷6= 0.83333
