What is gravitational potential energy?
OA. Energy stored in atoms
B. Energy of motion
C. Energy stored in height differences
D. Energy from light

Answer: I think 82.46

Explanation: The atomic number for strontium, or Sr on the periodic table, is 38. With knowing the atomic number, I multiplied that by the number of moles given.

38 × 2.17 = 82.46

I hope this helps!!

The number of atoms present in 2.17 moles of strontium are  [tex]1.306774 \times 10^{24}[/tex].

An atom is the smallest indivisible unit of a chemical element that retains the chemical properties of that element. It is the basic building block of matter.

To determine the number of atoms in a given number of moles, we can use Avogadro's number, which is approximately [tex]6.022 \times 10 ^{24}[/tex] atoms per mole.

In this case, we have 2.17 moles of strontium. To find the number of atoms, we multiply the number of moles by Avogadro's number:

Number of atoms = [tex]2.17 moles\times6.022\times 10^{23}[/tex][tex]atoms/mole[/tex]

On calculating this expression:

Number of atoms =[tex]1.306774 \times 10^{24}[/tex]

Therefore, there are approximately [tex]1.306774 \times 10^{24}[/tex] atoms in 2.17 moles of strontium.

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2Li + 2H2O____ 2LiaOH + 2H2

Answer:

2 Li + 2 H2O --> 2 LiaOH + 1 H2

Answer:

D.) It has a negative charge and is located in orbitals around the nucleus.

Explanation:

Electrons always have a negative charge. Since electrons can be shared or donated/received, they must be located in the orbitals around the nucleus. Protons, which have a positive charge, and neutrons, which are neutral, are  located in the nucleus.

Answer:

b

Explanation:

because it freezer in temperature

2.73 atm is the pressure in the vessel. Hence, option B is correct.

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= ?

V= 25.1 L

[tex]n= \frac{m}{molar \;mass \;of \;nitrogen} + \frac{m}{molar \;mass \;of \;hydrogen } +\frac{m}{molar \;mass \;of \;argon}[/tex]

[tex]n= \frac{2.80 g}{14} + \frac{0.605 g}{1} +\frac{79.9 g}{40}[/tex]

n= 2.8025

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=25°C + 273= 298 K

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]2.8025 = \frac{P\; X \;25.1 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]

P = 2.73 atm

2.73 atm is the pressure in the vessel. Hence, option B is correct.

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To determine the percentage yield, do the following:

Stoichiometry simply defined the relationships of the various quantities as they react in a chemical reaction

Scientist are mostly inquisitive and as such may want to determine the percentage yield of a reaction even before carrying it out.

To determine the percentage for a given reaction, we must set up the following:

From the above, we can conclude that option A gives the right steps if we must successfully determine the percentage yield of a reaction.

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Answer:

A

Explanation:

Edge 2022

Answer:

4.458 L

Explanation:

Assuming the pressure remains constant  and assuming 24° C and 58° C

V1/T1  = V2/T2       Where T is in Kelvin

V1/T1  *  T2  = V2

4 / ( 273.15 +24)    *    ( 273.15 + 58)    =  4.458 L

The number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Moles of hydrochloric acid = 0.385 mol

Mass of chlorine gas =?

Chemical equation:

4HCl +  O₂ → 2Cl₂  + 2H₂O

Now we will compare the moles of Cl₂ with HCl.

                 HCl           :               Cl₂

                   4             :               2

                0.385       :              2÷4× 0.385 = 0.1925 mol

Oxygen is present in excess that's why the mass of chlorine produced depends upon the available amount of HCl.

Mass of Cl₂ :

Mass of Cl₂ = moles × molar mass

Mass of Cl₂ =0.1925 mol × 71 g/mol

Mass of Cl₂ =  13.6675 g

Hence, the number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2 is 13.6675 g.

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The amount of nitrogen oxide in the air sample is determined as 7.01 ppb.

The amount of Nitrogen oxide (NO2) in the air in parts per billion (ppb) is calculated as follows;

12 micrograms of NO2 = 12 μg = 12 x 10⁻⁶ g

PV = nRT

V = nRT/P

Where;

n = m/M

M = molar mass of NO2 = 46

n =  12 x 10⁻⁶/46

n = 2.73 x 10⁻⁷ mole

V = (2.73 x 10⁻⁷ x 0.082057 x 313)/(1)

V = 7.01 x 10⁻⁶ L

V =  7.01 x 10⁻⁹ m³

= (Volume of NO2)/(volume of air) x 10⁹

= (7.01 x 10⁻⁹)/(1) x  10⁹

= 7.01 ppb

Thus, the amount of nitrogen oxide in the air sample is determined as 7.01 ppb.

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Oven cleaners typically contain a layer of sodium hydroxide, which converts the greases and oils on the oven walls into soap, which can then be cleaned away more easily.

A chamber used for baking, heating, or drying.

Self-cleaning ovens emit dangerous fumes into the air with an unpleasant burning smell. Self-cleaning ovens reach high temperatures and produce fumes from the cooking of food particles. These fumes circulate with the air and can affect the home substances.

Spray-on oven cleaner ovens contain a layer (sodium hydroxide), which converts the greases of the oven walls into soap, which can then be cleaned away more easily.

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They are forms of water in its liquid state at ground level. Thus, the correct option is A.

Precipitation, or water in the atmosphere, forms hail. When water drops freeze together in the chilly higher parts of thunderstorm clouds, hail is the result.

When a water droplet is lifted by an updraft from a thunderstorm over the freezing point of the atmosphere, hail is created. The super-cooled water or water vapor that the frozen water droplet accretes later freezes when it comes into touch with it. A hailstone grows as a result of this process.

When water vapor from the atmosphere condenses into liquid water droplets, they become heavy enough to fall as a result of gravity.

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Answer:A

Explanation:

.

M = n/V

V = n/M

V = (14.5 : 56.1056)/2.8

V = 0.0923 L = 92.3 mL

Answer:

1. Used in many smoke detectors for homes and businesses to measure levels of toxic lead in dried paint sample to ensure uniform thickness in rolling processes like steel and paper production and to help determine where oil wells should be drilled.

2.Used to treat cancerous tumors to measure correct patient dosages of radioactive pharmaceutical to measure and control the liquid flow in oil pipelines to tell researchers whether oil wells are plugged by sand and to ensure the right fill level for packages of food, drugs, and other

products.

3.Used in medical diagnosis

4.Used to treat thyroid disorders. (Graves’s disease).

5.Used in molecular biology and genetics research.

6.Used in nuclear medicine for lung ventilation and blood flow studies.

7.Used in dental fixtures like crowns and dentures to provide a Uranium-234 natural color and brightness.

8.Used in electric blanket thermostats and to gauge the thickness of thin plastics, thin sheet metal, rubber, textile and paper.

Answer:

2 Hg (g) + o2 ---> 2 H2o

equilibrium constant

K = (c) (d) / (a)(b)

K= ( H2o)²/(He) ²(o2)

A sample of rainwater with a pH of 3.5 is sure to contain a large concentration of [tex]H_3O^+[/tex]

A pH value of 7 downward is said to be acidic. Upward of 7 is said to be basic. A pH of 7 on the dot is said to be neutral.

An acid is defined as a substance that produces  [tex]H_3O^+[/tex] as its only positively charged ion in solution.

Thus, rainwater with a pH of 3.5 is acidic and will contain a high concentration of  [tex]H_3O^+[/tex].

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The variable "air pressure inside the football" in this experiment is quantitative and dependent variable. Hence, option D is correct.

The dependent variable is the variable that is being measured or tested in an experiment.

In the experiment, the scientist filled the footballs with fix quantity of pressure which was then kept for 12 hours. After 12 hours the pressure inside the footballs was again measured. Pressure here is a quantitative variable.

Since the air temperature is an independent variable. The pressure being the dependent variable depends upon the temperature of the air.

Independent variable; The variable which does not depends upon any other variable.

Dependent variable; The variable which depends upon the independent variable or varies with the change independent variable.

Qualitative variables are variables which cannot be expressed in form of numbers. They generally convey the characteristic, category, quality or type.

Whereas Quantitative variables are the variables which can be expressed in the form of numbers. These are the variables which exist along the continuous sequence.

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They are converted into a single “o” when "ao" or "oo" are together when naming covalent bonds.

A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms.

Sometimes, while naming the chemical compounds, a problem arises when compounds with “ao” and “oo” are written with -ide name. Conventionally, they are converted into a single “o”.

For example, the “ao” in the dichlorine hept-ao-xide ([tex]Cl_2O_7[/tex]). This “ao” in the [tex]Cl_2O_7[/tex] can be converted into “o”. As the result, the correct name of this compound would be dichlorine hept-o-xide.

Hence, they are converted into a single “o” when "ao" or "oo" are together when naming covalent bonds.

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(CH₂)n=42

(14)n=42

n=3

C₃H₆

Answer:

The two that are true are, "this represents a pure compound in two different states" and "it represents a mixture a solid and a gas".

Explanation:

This two are concluded only from the picture and the use of uniform colors throughout the picture (Showing the same element).

Avogadro's law states that in a mole of any substance, there are [tex]6.022 \times 10^{23}[/tex] atoms. This means that in the given sample, there are

[tex]\frac{6.075 \times 10^{26}}{6.022 \times 10^{23}}=1008.8010627 \text{ mol}[/tex]

So, the atomic mass of sulfur dioxide is

[tex]32.06+2(15.9994=64.0588 \text{ g/mol}[/tex]

Therefore, the mass is:

[tex](64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}[/tex]

Answer:

The time required to decompose the substance is 360 seconds.

Answer:

Natural Selection

The answer is:

A. Natural Selection

The sulfuric acid can be constituted into different concentrations using distilled water as a diluent.

Dilution of acid is defined as the decrease in the concentration of an acid using water.

For sulfuric acid to be diluted, it is slowly added to distilled water using the following guidelines:

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Answer:

[tex]a. \ \ \ \text{The mass of ethylene is 11.375 g}. \\ \\ b. \ \ \ \text{The volume of water produced is 7.875 ml}.[/tex]

Explanation:

a. According to the chemical equation for the combustion of ethylene, 5

   moles of oxygen are required to react with 2 moles of ethylene, hence

           [tex]m_{C_{2}H_{2}} \ = \ 35 \ \text{g} \ \times \ \displaystyle\frac{1 \ \text{mol}}{\left(2 \times 16 \right) \text{g}} \ \times \ \displaystyle\frac{2 \ \text{mol}}{5 \ \text{mol}} \ \times \ \displaystyle\frac{\left(12 \ \times \ 2 \ + \ 1 \ \times \ 2 \right) \ \text{g}}{1 \ \text{mol}} \\ \\ m_{C_{2}H_{2}} \ = \ 11.375 \ \text{g}[/tex]

b. Similarly, 5 moles of oxygen are required as a reactant to produce 2  

    moles of water, thus

             [tex]m_{H_{2}O} \ = \ 35 \ \text{g} \ \times \ \displaystyle\frac{1 \ \text{mol}}{\left(2 \times 16 \right) \text{g}} \ \times \ \displaystyle\frac{2 \ \text{mol}}{5 \ \text{mol}} \ \times \ \displaystyle\frac{\left(1 \ \times \ 2 \ + \ 16 \right) \ \text{g}}{1 \ \text{mol}} \\ \\ m_{H_{2}O} \ = \ 7.875 \ \text{g}[/tex]

      Given that the density of water is [tex]1.0 \ \text{g ml}^{-1}[/tex], therefore

                                               [tex]\rho_{H_{2}O} \ = \ \displaystyle\frac{m_{H_{2}O}}{V_{H_{2}O}} \\ \\ V_{H_{2}O} \ = \ \displaystyle\frac{m_{H_{2}O}}{\rho_{H_{2}O}} \\ \\ V_{H_{2}O} \ = \ \displaystyle\frac{7.875 \ \text{g}}{1.0 \ \text{g ml}^{-1}} \\ \\ V_{H_{2}O} \ = \ 7.875 \ \text{ml}[/tex]

11.375 g ethylene is consumed if 35.0 grams of oxygen is allowed to react and 7.875 ml of water will be produced when the 35.0 grams of oxygen is allowed to react.

A mole is defined as 6.02214076 ×[tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

According to the chemical equation for the combustion of ethylene, 5

moles of oxygen are required to react with 2 moles of ethylene, hence

[tex]m_{_C_2_H_2}[/tex]  [tex]= 35gX \frac{1 mol}{(2 \;X\; 16)g } X \frac{2 mol}{(5\;mol )} X \frac{26g}{1 mol }[/tex]

[tex]m_{_C_2_H_2} = 11.375 g[/tex]

Similarly, 5 moles of oxygen are required as a reactant to produce 2 moles of water, thus

[tex]m_{_H_2_O} = 35gX \frac{1 mol}{(2 \;X\; 16)g } X \frac{2 mol}{(5\;mol )} X \frac{18g}{1 mol }[/tex]

[tex]m_{_H_2_O} = 7.875 g[/tex]

Given that the density of water is [tex]1.0g ml^{-1}[/tex], therefore

[tex]Density = \frac{Mass \;of \;water}{Volume \;of \;water}[/tex]

[tex]Volume \;of \;water = \frac{7.875}{1.0 g ml^{-1}}[/tex]

The volume of water = 7.875 ml

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Answer:

5.06 M LiCl

Explanation:

To find the new molarity of the solution, you need to (1) find the amount of moles LiCl (via the molarity equation using the original molarity and volume) and then (2) calculate the new molarity (via the molarity equation using the new volume and old moles). The final answer should have 3 sig figs to match the given values.

Molarity (M) = moles / volume (L)

Step (1)

381 mL / 1,000 = 0.381 L

Molarity = moles / volume

9.96 M = moles / 0.381 L

(9.96 M) x (0.381 L) = moles

3.79 = moles

Step (2)

750 mL / 1,000 = 0.750 L

Molarity = moles / volume

Molarity = 3.79 moles / 0.750 L

Molarity = 5.06 M