what is kineamatics (60 words)

Claudia is performing an experiment, testing to see if decreasing the temperature in which pea plants are growing makes them flower sooner which means that some values that Claudia will want to hold constant include the following below:

b.the amount of light the plants get.

d.the type and amount of fertilizer used.

e.the amount of water the plants get.

This refers to a procedure which is carried out by scientists in other to support or refute a hypothesis and is usually done in the laboratory. It is also used to ascertain the authenticity of a claim and consists of two types of variables which are constant and control variables.

The constant variables doesn't change and is applied uniformly to all the specimens. In this scenario they include the amount of light, fertilizer and water the plants gets.

Controlled variables are the ones which are changed and its varied application on different specimens are used to measure the effect and in this case an example is the temperature the plants are grown in because the test involves this parameter.

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Answer:

Explanation:

velocity and position

Answer:

A. Velocity and position

Took the test.

The speed of the ball have in falling 3.6 s is 35.5 m/s.

The speed of the ball is calculated using the equation of a body falling under the influence of gravity or velocity of free fall.

The equation of the motion of the body is given as follows:

v = u - gt

where;

u is the initial velocity

g = acceleration due to gravity

t = time

v = final velocity

Assuming u = 0 m/s, g = 9.8 m/s², t = 3.6 s

v = 0 - 9.8 * 3.6

v = 35.5 m/s

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Answer: zero acceleration is zero acceleration, not constant acceleration.

Explanation:

Answer:

2 m/s²

Explanation:

To calculate the acceleration of an object, we use the following formula:

[tex]\boxed{a = \frac{v - u}{t}}[/tex],

where:

• a = acceleration

• v = final speed

• u = initial speed, and

• t = time taken

We are told in the question that the final speed of the helicopter is 40 m/s, its initial speed is 30 m/s, and that the time it took to get from 30 m/s to 40 m/s is 5 seconds.

Therefore, using this information, as well as the formula above, we can evaluate the acceleration of the helicopter:

[tex]a = \frac{40 - 30}{5}[/tex]

  [tex]= \frac{10}{5}[/tex]

  [tex]= \bf 2 \: m/s^2[/tex]

So the acceleration of the helicopter is 2 m/s².

If a tumbleweed tumbles over an empty plain with a speed of 16.3 meters per minute for 2.3 minutes, then it would have traveled 37.49 meters

The total distance covered by any object per unit of time is known as speed.

It depends only on the magnitude of the moving object.

As given in the problem a tumbleweed tumbles over an empty plain with a speed of 16.3 meters per minute for 2.3 minutes.

The distance traveled by the tumbleweed = speed ×time

                                                                       =  16.3 meters/minute×minutes

                                                                       =37.49 meters

Thus, the distance traveled would be 37.49 meters.

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Answer:

8.3 m

Explanation:

The initial position of the bunny is at time  t = 0

x = 8.3  +  2.2 (0)   = 8.3 m

The initial position of a bunny hopping across a yard is 8.3 meters.

It is the location of the object in relation to time, when the object starts moving it is changing its position in relation to time. When the position of an object keeps changing then the displacement of an object can be calculated as the reference point is necessary to calculate the position, and it also shows the direction, therefore, it is a vector quantity. The graph of position and time gives us the velocity of the object.

Given: The position time equation of the object;

x = 8.3 + 2.2 t     (x is the distance / position, t is time in seconds)

so for the initial position, time will be zero (t = 0);

Therefore, at t = 0 the position will be;

x = 8.3 + 2.2 ×0

x = 8.3 meters

Hence, the initial position of the bunny hopping across a yard is 8.3 meters.

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According to Pascal, pressure applied to a fluid is transmitted equally in all directions.

P = F / A

P = Pressure

F = Force

A = Area

Pressure is in Pa ( Pascals ).

Force is in N ( Newtons )

Area is in m² ( Meter² )

Pascal's law states that, pressure applied to an incompressible fluid enclosed in a container is transmitted equally throughout the fluid without any change in magnitude.

Therefore, According to Pascal, pressure applied to a fluid is transmitted equally in all directions.

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Answer:

56.39 hours

Explanation:

I say this because to calculate how long something is traveling you have to divide the distance traveled by the rate or do distance/time

The falcon take 14 seconds to reach the pigeon.

A mathematical expression that expresses the location, speed, or acceleration of a body in relation to a specified frame of reference is called as Equation of motion,

By using equation of motion

s = [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

where, s = total distance travelled by an object = 68.6 m

g = acceleration of gravity = 9.8m/[tex]s^{2}[/tex]

t = time taken to travel the distance = ?

Therefore, t = [tex]\sqrt{2s/g}[/tex]

t = [tex]\sqrt{2*68.6/9.8}[/tex]

t = 14 seconds

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A part of me which I would love to change is over trusting people around me.

It happens that there is always a solution to every problem as long one one is willing to make an ammend. I as as person have been hurt many countless times by friends which I am giving my possible best to withdraw from over trusting someone who will later hurt me.

I have been able to modify this by making sure I am not too emotional on anything, keeping my words to myself and revealing my weaknesses to anyone.

So therefore, behavioral modification is very important to every individual who has a character that needs to be changed.

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The capacitance needed in the LC circuit is 1 μF.

The capacitance needed to make the LC circuit is calculated as follows;

capacitive reactance = inductive reactance

Xc = Xl

1/2πfC = 2πfL

2πfC(2πfL) = 1

4π²f²LC = 1

LC = 1/4π²f²

C = 1/(4π²f²L)

where;

Substitute the given parameter and solve for the capacitance as follows;

C = (1)/(4π² x 100² x 2.5)

C = 1.01 x 10⁻⁶ F

C ≈ 1 μF

Thus, the capacitance needed in the LC circuit is 1 μF.

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A bus is about to leave in exactly 5 seconds. You are 20 meters away. With a speed of 4 m/sec you will be able to catch the bus on time.

By dividing the distance traveled by the time required to complete that distance, speed is calculated. For a specific distance, it provides the travel time / distance.

Speed and distance are tightly related, whereas time and distance have an inverse relationship. Speed times the passing of time equals distance.

Distance divided by speed is how time is calculated; as speed rises, time slows down, and vice versa.

Given

Time = 5 secs

Distance = 20 m

On putting the values in the given formula we get,

Speed = Distance / Time

Speed = 20 m / 5 secs

Speed = 4 m/secs

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The distance of the image formed is -8.85 cm and the height of the image is 6.02 cm.

The position of the image formed is calculated as follows;

-1/f = 1/v + 1/u

where;

1/v = -1/f - 1/u

1/v = -/14.2 - 1/23.5

1/v = -0.112975

v = -1/0.112975

v = -8.85 cm

The height of the image formed  is calculated as follows.

Use magnification equation;

image distance/object distance = image height / object height

v/u = hi/h0

8.85/23.5 = hi/16

hi = (8.85/23.5) x 16

hi = 6.02 cm

Thus, the distance of the image formed is -8.85 cm and the height of the image is 6.02 cm.

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The question has two parts

beginning with part 1:

R1 and R2 are in series

R3 and R4 are in series with each other

R5 and R6 are in series with each other

R3 and R4 are parallel to R5 and R6

it is given that R1=R2=R3=R4 =2 Ohm

R5=R7=1 Ohm

R6 = 3ohm

We know that resistance is the sum of resistances in series and reciprocal sum of resistances in parallel

R1+R2=2+2=4 ohm

R3+R4 = 2+2 = 4ohm

R5+R6 =1+3=4Ohm

R3 and R4  and R5 and r6  are in parallel = 4 x 4/4+4 = 16/8 = 2 ohm

Resultant resistance = 4 + 2 +1 =7 phms

In part 2 of the question,

R1=R7=2 ohm

R2=R3=R6 =1 ohm

R4=R5=3 ohm

R2,R3 are in series, R5 and R6 are in series

R2,R3 AND R4 and R5 ,R6 in parallel

R2+R3 = 1+1 =2 ohm

R5 +R6 = 3+1 =4 ohm

R2,R3 AND R4 and R5 ,R6 in parallel= 1/(1/2+1/4+1/3 )=v 1/(6+3+4)/12

                                                            =12/13

Resultant resistance = 2+2+12/13 =4.93 ohm

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Answer:

The equation for velocity is: Velocity = distance / time. Velocity is a measure of the speed at which an object moves in a specific direction. The equation for velocity states that the velocity of an object is equal to the distance it travels divided by the time it takes to travel that distance. This equation can be used to calculate the velocity of an object if the distance it travels and the time it takes to travel that distance are known.

Explanation:

The moment of the force about point A found using the moments formula, [tex]|M| = |F| \cdot \: d \perp[/tex] is 67.695 ft–lb.

The moment of a force is the turning effect of the force about a point.

The moment of the force is given by the formula;

[tex]|M| = |F| \cdot \: d \perp[/tex]

Where;

d = The perpendicular distance from the point to the line of action of the force.

The length of the sides of ∆ABC are;

AB = √(20.5²+4.38²) ≈ 20.9626907

BC = √(17.2²+7.62²) ≈ 18.812347

AC = √((7.62+4.38)²+(20.5-17.2)²) ≈ 12.4454811

The semi–perimeter of triangle ABC = (20.9626907 + 18.812347 + 12.4454811)/2 ≈ 26.1102594

The area, A, of triangle ∆ABC found using Heron's formula is therefore;

A = √((26.1102594×(26.1102594-20.9626907)×(26.1102594-18.812347)×(26.1102594-12.4454811)) ≈ 115.773

The perpendicular distance, d, from point A to BC is therefore;

d = A/(BC)

Which gives;

d = 115.773/18.812347 ≈ 6.15409696

The magnitude of the moment about point A is therefore;

M = 132 lb × 0.51284138 ft. ≈ 67.695 ft.–lb

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Answer:

5/2m/s^2

Explanation:

Acceleration is change in velocity divided by change in time. You might have seen it written like this:

ΔV/Δt

in this case, your change in velocity is -10m/s and your change in time is 4s thus your acceleration is -5/2m/s^2

It is measured in the airless tube because  there is no air to offer resistance to the fall of the object.

The acceleration due to gravity refers to the acceleration that is imparted to a body because of its movement in the earth's gravitational field. Irrespective of mass, all objects move with the same acceleration in the earth gravitational field.

If air is present, air resistance makes it appear as if different masses are accelerated to different amounts. Thus, the acceleration due to gravity is measured in an airless tube the where there is no air to offer resistance to the fall of the object.

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Answer:

Nickel is the correct answer here.

Answer:

Ex; If the robot traveled 20 cm around the octagon then the circle circumference = 20 cm

Use the equation circumference = 2 π radius to calculate radius(C = 2πr)

          If circumference = 20cm;  radius = circumference / ( 2 π) = 20/6.28= 3.18 cm. Use your scale to express your answer in meters, km, etc

now set the protractor distance measure as 3.18 cm, place the protractor's metal spike at the octagon center and draw the circle.

Explanation:

The force exerted during a work of 200 J done to move a toy car 40 m is 5 N

W = F * d

W = Work done

F = Force

d = Distance

W = 200 J

d = 40 m

F = W / d

F = 200 / 40

F = 5 N

The force exerted to move an object is work done. It is denoted as W. Its unit is Joules.

Therefore, the force exerted is 5 N

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At 10⁻¹⁰ s during the evolution of the universe, quarks formed, which are elementary particles that make up protons and neutrons.

Generally, an atom comprises three (3) distinct subatomic particles and these include the following

Protons can be defined as the positively charged subatomic particles that are found in the nucleus of a chemical element and they have a magnitude of +1. Also, the number of protons in the nucleus of a chemical element always the same as its atomic number.

Quarks can be defined as the elementary particles that make up both protons and neutrons, and they are the basic component of matter. Also, quarks have a charge that's approximately equal to 1.07 × 10⁻¹⁹ Coulomb.

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Complete Question:

At 10⁻¹⁰ s during the evolution of the universe, ________ formed, which are elementary particles that make up protons and neutrons.

A vector is a physical quantity that has both magnitude and direction

A two dimensional vector represented by r = xi + yj has the magnitude r = √(x² + y²) where

Also, a three dimensional vector represented by r = xi + yj + zk has the magnitude r = √(x² + y² + z²) where

Given a vector r = 3i + 4j, we find its magnitude thus r = √(x² + y²) where

So, r = √(x² + y²)

r = √(3² + 4²)

r = √(9 + 16)

r = √25

r = 25 units

Also, given a vector r = 3i + 4j + 5k, we find its magnitude thus r = √(x² + y² + z²) where

So, r = √(x² + y² + z²)

r = √(3² + 4² + 5²)

r = √(9 + 16 + 25)

r = √(25 + 25)

r = √50

r = 5√2 units

So,

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The length of the total cells in the human body when all the cells are stretched out is 7.5 x 10⁸ m.

Cells are the basic building blocks of all living things, including humans. The human body is composed of trillions of cells with  average cell diameter of 1 x 10⁻⁵ m.

The length of the total cells in the human body when all the cells are stretched out is calculated as follows;

total length of the cells = average diameter of a cell x number of cells

total length of the cells = 1 x 10⁻⁵ m x 7.5 x 10¹³

total length of the cells = 7.5 x 10⁸ m

Thus, the length of the total cells in the human body when all the cells are stretched out is 7.5 x 10⁸ m.

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The height of the cliff is 88 m.

The initial velocity of the rock, when it is dropped is V(i) = 0 m/s.

The sum of the time taken by the rock to reach the surface of the ocean from the sea cliff and the time taken by the sound of the splash of the rock to the ears of the person who threw the rock is t = 2.7 s.

The speed of sound in air is V(s) = 340 m/s.

The acceleration due to gravity is g = 10 m/s².

The displacement made by the rock during this period will be as follows if we use the kinematic equation for translational motion under gravity and assume that the time it takes the rock to reach the ocean's surface is t₁ :

d = 0 − h = V(i) × t₁ + (1/2) × (− g ) × ( t₁ )²

Since the positions of the rock are taken from the surface of the ocean.

Substituting the values in the equation.

t₁ = √ [ 2h/g ]

( t₁ )² = 2h / g

Since sound moves through the medium at a constant speed, the following is how long it will take for the sound to reach the rock-thrower:

t₂ = h / V(s)

h = V(s) × t₂

Therefore,

( t₁ )² = ( 2 × V(s) × t₂) / g

Now, since t = t₁ + t₂ , therefore, t₂ = t − t₁ .

( t₁ )² = ( 2 × V(s) × ( t - t₁ ) ) / g

( t₁ )² = 2 × ( 340 ) ×( 4.5 − t₁ ) / 10

( t₁ )² = 306 − 68 t₁

Now,

( t₁ )² - 306 + 68t₁ = 0

By using the quadratic formula,

t₁ = { − 68 ± √ [( 68 )² − 4 × ( 1 ) × ( − 306 )] } / 2 × ( 1 )

t₁ = − 68 ± 76.47 / 2

( t₁ = − 68 + 76.47 / 2 = 4.24 s) and;

( t₁ = − 68 − 76.47 / 2 = − 72.24 s )

Since time can't be negative,

t₁ = 4.24 s.

Therefore,

t₂ = t − t₁

t₂ = 4.5 s − 4.24 s

t₂ = 0.26 s

Now,

h = V(s) × t₂

h = ( 340 m / s ) × ( 0.26 s )

h ≈ 88 m

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Answer:

m/s^2

Explanation:

m/s^2 is a unit of acceleration.

The magnitude of the electric field at the given radial distances from the center of the charge distribution is, For the first case electric field=E₁= 1211.37N/C, For the second case electric field =E₂=762.82 N/C, For the third case electric field= E₃= 3276.7 N/C, For the fourth case electric field=E₄=555.04N/C

Electric field is defined in a way that a field is present in a frame. There is two electric source is present that associated with each other and make the field electrified and source of electric. It can be shown in electric per unit area.

The conducting shell carries a total charge of=Q=−11.9 nC=11.9*10⁻⁹C

A sphere of radius=R =0.280m

A uniform charge density of a sphere=ρ₁= 151 nC/m³= 151×10⁻⁹C/m³

A uniform charge density of a spheric shell,

ρ₂=Q/(4/3)π[(4.00R)³−(3.50R)³]

Or,ρ₂=3Q/4πR³[(4.00)³−(3.50)³]

Or,ρ₂=3*11.9*10⁻⁹/4π(0.280)³[(4.00)³−(3.50)³]

Or,ρ₂=6.15*10⁻⁹ C/m³

We know the law of electric field,

E=(1/4πϵ₀)*(q/r²)

(a) r₁=0.76R

The electric field, in this case, can be given as:

E₁=(1/4πϵ₀)*(q₁/r₁²)

Or, E₁=(1/4πϵ₀)*(ρ₁*{(4/3)πr₁³}/r₁²)

Or, E₁=(1/4πϵ₀)*(ρ₁*(4/3)πr₁)

Or, E₁=9*10⁹*( 151×10⁻⁹*(4/3)π*0.76*0.280)

Or, E₁= 1211.37N/C

According to the calculation, The electric field for this case is, E₁= 1211.37N/C

(b) r₂=3.65R

The electric field, in this case, can be given as:

E₂=(1/4πϵ₀)*(q₂/r₂²)

Here, q₂=Q+(4/3)π[(4.00)³−(3.50)³]

Or, q₂=11.9*10⁻⁹+(4/3)π[(4.00)³−(3.50)³]

Or, q₂=88.488*10⁻⁹C

Now, E₂=(1/4πϵ₀)*(q₂/r₂²)

Or, E₂=(1/4πϵ₀)*(88.488*10⁻⁹/(3.65*0.280)²)

Or, E₂=762.82 N/C

According to the calculation, The electric field for this case is, E₂=762.82 N/C

(c) r₃=2.30R

The electric field, in this case, can be given as:

E₃=(1/4πϵ₀)*(q₃/r₃²)

In this case, electric charge enclosed by the Gaussian surface is given by: q₃=151×10⁻⁹C/m³

Now, E₃=(1/4πϵ₀)*(q₃/r₃²)

Or, E₃=(1/4πϵ₀)*(151×10⁻⁹/(2.30*0.280)²)

Or, E₃= 3276.7 N/C

According to the calculation, The electric field for this case is,  E₃= 3276.7 N/C

(d) r₄=4.50R

Here, q₄=Q+(4/3)π[(4.00)³−(3.50)³]

Or, q₄=11.9*10⁻⁹+(4/3)π[(4.00)³−(3.50)³]

Or, q₄=88.488*10⁻⁹C

Now, E₄=(1/4πϵ₀)*(q₄/r₄²)

Or, E₄=(1/4πϵ₀)*(88.488*10⁻⁹/(4.50*0.280)²)

Or, E₄=555.04N/C

According to the calculation, The electric field for this case is, E₄=555.04N/C

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Answer:  Coats make people warmer.

Explanation: Coats help keep us warm due to the fillings inside the materials.