What is the area of a triangle with the Base of √10 and a height of √13

Answers

Answer 1

Answer:

5.70

Step-by-step explanation:

[tex] a = \frac{1}{2} bh \\ \frac{ \sqrt{10} \sqrt{13} }{2} \\ \frac{ \sqrt{130} }{2} [/tex]

[tex]a = \frac{11.401}{2} \\ = 5.70[/tex]

Answer 2

Answer:

5.70

Step-by-step explanation:

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Related Questions

Find f′ in terms of g′

f(x)=x2g(x)

Select one:

f′(x)=2xf′(x)+2xg′(x)


f′(x)=2xg′(x)


f′(x)=2x+g′(x)


f′(x)=x2g(x)+2x2g′(x)


f′(x)=2xg(x)+x2g′(x)

Answers

f(x)g(x) if you find the derivative of two products, you get f(x)g’(x)+f’(x)g(x). Let’s say x^2 = f(x).

(x^2)(g’(x))+2x(g(x)) so it would be your last option, 2x(g(x))+x^2(g’(x))

Write an absolute value equation to satisfy the given solution set shown on a number line.

Answers

Answer:

|x + 6|  = 2

Step-by-step explanation:

For a general absolute value equation:

| f(x) |  = b

We can rewrite it as:

f(x) = b

f(x) = -b

with b > 0.

Because in the number line we have only two points graphed, this means that our absolute value equation has two solutions.

And we can conclude that one solution comes from the equation:

f(x) = b

And the other solution comes from the equation:

f(x) = -b

And thus, f(x) is a linear equation, that we can simply write as:

x - c

Then our equations can be rewritten as:

x - c = b

x -c = -b

Now let's look at the graph, we can see that the two solutions are:

x = -8

and

x = -4

Let's input each one of these in one of our above equations (the order does not matter).

-4 - c = b

-8 - c = -b

The larger value of x, (x = -4) needs to be in the equation with the positive value of b.

From the first equation we can get:

b = -4 - c

now we can replace the variable "b" in the second equation by "-4 - c" to get:

-8 - c = -(-4 - c)

-8 - c = 4 + c

-8 - 4 = c + c

-12 = 2c

-12/2  =c

-6 = c

Now that we know the value of c, we can input it in the equation:

b = -4 - c

to find the value of b

b = -4 - (-6) = -4 + 6 = 2

b = 2

Then the absolute value equation is:

|x - (-6) | = 2

|x + 6|  = 2

Twenty students randomly assigned to an experimental group receive an instructional program; 30 in a control group do not. After 6 months, both groups are tested on their knowledge. The experimental group has a mean of 38 on the test (with an estimated population standard deviation of 3); the control group has a mean of 35 (with an estimated population standard deviation of 5). Using the .05 level, evaluate the researcher's hypothesis that the instructional program affects students' knowledge. What is the correct cutoff score(s)

Answers

Answer:

The solution according to the problem given is provided below in the explanation segment.

Step-by-step explanation:

According to the question,

[tex]H_o: \mu_1=\mu_2[/tex]

[tex]H_a: \mu_1 \neq \mu_2[/tex]

Level of significance,

[tex]\alpha = .05[/tex]

The test statistics will be:

⇒ [tex]Z = \frac{(\bar x_1 - \bar x_2)}{\sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} } }[/tex]

       [tex]=\frac{(38-35)}{\sqrt{\frac{(3)^2}{30} +\frac{(5)^2}{30} } }[/tex]

       [tex]=2.82[/tex]

The p-value will be:

= [tex]0.0024[/tex]

What is (4n + 3n2 + 2) - (n - 6n
+1) simplified?
A -3n2 + 3n-2 C 9n2 + 3 + 2
B 3n2 + 3n + 2 D 9n2 + 3n + 1
C 9n2 + 3n + 2
D 9n2 + 3n + 1

Answers

Step-by-step explanation:

4n + 3n2 + 2 + n + 6n – 1 Expand with – 1

3n2 + 4n + n + 6n + 2 – 1 Grouped liked terms

3n2 + 11n – 1

Find the inequality represented by the graph

I'm using khan academy btw

Answers

Answer:

Step-by-step explanation:

slope of line through (0,0) and (4,3) =(3-0)/(4-0)=3/4

eq. of line is y-0=3/4(x-0)

y=3/4 x

put x=4

y=2

2=3/4×4

2=3

which is true if 2<3

2<3

so y<3/4 x

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at the beginning and end of the course to determine the effectiveness of the course. The following measurements are the net change in 6 students' scores on the exam after completing the course: 6,16,19,12,15,14.
Using these data, construct a 90% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal. Find the critical value that should be used in constructing the confidence interval.

Answers

Answer:

The critical value is [tex]T_c = 2.5706[/tex].

The 90% confidence interval for the average net change in a student's score after completing the course is (9.04, 18.30).

Step-by-step explanation:

Before building the confidence interval, we need to find the sample mean and the sample standard deviation:

Sample mean:

[tex]\overline{x} = \frac{6+16+19+12+15+14}{6} = 13.67[/tex]

Sample standard deviation:

[tex]s = \sqrt{\frac{(6-13.67)^2+(16-13.67)^2+(19-13.67)^2+(12-13.67)^2+(15-13.67)^2+(14-13.67)^2}{5}} = 4.4121[/tex]

Confidence interval:

We have the standard deviation for the sample, so the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 2.5706, that is, the critical value is [tex]T_c = 2.5706[/tex]

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.5706\frac{4.4121}{\sqrt{6}} = 4.63[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 13.67 - 4.63 = 9.04.

The upper end of the interval is the sample mean added to M. So it is 13.67 + 4.63 = 18.30.

The 90% confidence interval for the average net change in a student's score after completing the course is (9.04, 18.30).

A rectangle is 19 inches long and 6 inches wide find it’s area

Answers

Step-by-step explanation:

how to find the area

multiply the length times the width

19 × 6 = 114 inches squared

The area of the rectangle is 114 square inches if the length and breadth of the rectangle are 19 inches and 6 inches.

A rectangle is one of the elementary geometric figures. It is a quadrilateral with a pair of equal and parallel sides. All angles of a rectangle are right angles.

The length of the rectangle is given as 19 inches.

The breadth of the rectangle is given as 6 inches.

The area of the given rectangle is given as:

Area = length × breadth

Area = 19 × 6

Area = 114 square inches

Thus, the area of the given rectangle is 114 square inches.

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11. The unit digit in the expression (31 + 132 + 143 + 414 + 515 +156 + 61) i (A) 4 (B) 3 (C) 2 . (D) 1​

Answers

Answer:

Step-by-step explanation:

[tex]we \ add \ \ only \ \ units \ we \ do \ not \ need \ the \ rest \\\\ \bf (3\underline 1 + 13\underline2 + 14\underline3 + 41\underline4 + 51\underline5 +15\underline6 + 6\underline1)= \\\\ 1+2+3+4+5+6+1=2\underline 2 \\\\ Answer: C) \ 2[/tex]

if x-y =2 and xy=15, find the value of x cube - y cube.​

Answers

Answer:

5³ = 125 : -3³ = -27

Step-by-step explanation:

let x= 5 and y= 3x - y = 25 - 3 = 2xy = 155 × 3 = 15x³ = ? : -y³ = ?5³ = 125 : -3³ = -27

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

5x + 2y + 19 = 0 3x + 4y + 17 = 0​

Answers

Answer:

x = -3; y = 2

Step-by-step explanation:

5x + 2y + 19 = 0

3x + 4y + 17 = 0​

-10x - 4y - 38 = 0

3x + 4y + 17 = 0

-7x - 21 = 0

x = -3

5(-3) + 2y = -19

2y = -4

y = -2

Answer: x = -3; y = 2

What are the values of a, b, and c in the quadratic equation 0 = one-halfx2 – 3x – 2?

a = one-half, b = 3, c = 2
a = one-half, b = –3, c = –2
a = one-half, b = 3, c = –2
a = one-half, b = –3, c = 2

Answers

Answer:

b

Step-by-step explanation:

ax^2+bx+c=0

1/2x^2-3x-2=0

Answer:

B

Step-by-step explanation:

If a ∥ b and b ⊥ y, then _____

Answers

Answer:

a ⊥ y

Step-by-step explanation:

since b is parallel to a & perpendicular to y , line y will eventually cut across line a at a 90 degree angle as well

Answer:

a ⊥ y

Step-by-step explanation:

Look at the image given below.

A 10​-sided die is rolled. Find the probability of rolling an even number. The set of equally likely outcomes is shown below. ​{1, 2, 3, 4, 5, 6, 7, 8, 9, 10​}

The probability of rolling an even number on a 10​-sided die is:

Answers

Answer:

1/2

Step-by-step explanation:

There are ten sides on this die. As stated in your question, there are five even numbers and five odd numbers. If we take the amount of even numbers over the total, you get 5/10, which simplifies to 1/2.

The probability of rolling an even number on a 10 - sided die is 1/2 or 0.5

What is Probability?

The probability that an event will occur is measured by the ratio of favorable examples to the total number of situations possible

The value of probability lies between 0 and 1

Given data ,

Let the data set be S = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 ​}

So , the number of elements in the data set = 10 elements

Now , in order to get an even number when dolling the dice ,

The set of possible outcomes P = { 2 , 4 , 6 , 8 , 10 }

The number of elements in the data set P of outcomes = 5 elements

So , the probability of getting an even number from the data set when rolling a 10 sided dice is P ( x ) =
number of elements in the data set P of outcomes / number of elements in the data set

The probability of getting an even number from the data set when rolling a 10 sided dice is P ( x ) = 5 / 10

The probability P ( x ) = 1/2

                                   = 0.5

Hence , The probability of rolling an even number on a 10 - sided die is 1/2 or 0.5

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Aku has less than 3 times as many mangoes as Alaba and half as many mangoes as Amina if alaba has x mangoes the interns of x then how many mangoes do aku alaba and Amina have in combined

Answers

Answer:

I have no clue my bad bro.

Can you please help me

Answers

9514 1404 393

Answer:

  1/63

Step-by-step explanation:

There are various ways the question "how much larger" can be answered. Here, we choose to answer it by telling the difference between the two fractions:

  4/9 -3/7 = (4·7 -9·3)/(9·7) = 1/63

The larger fraction is 1/63 unit larger than the smaller fraction.

A note card company has found that the marginal cost per card of producing x note cards is given by the function below, where C'(x) is the
marginal cost, in cents, per card. Find the total cost of producing 900 cards, disregarding any fixed costs.
C'(x) = -0.05x + 77, for x S 1000
The total cost is
cents

Answers

Answer:

49,050cents

Step-by-step explanation:

Given the expression for calculating the marginal cost per card of producing x note cards expressed as

C'(x) = -0.05x + 77

On intergrating the marginal cost, we will get the total cost

C(x) =  -0.05x²/2 + 77x

Substitute x = 900 into the resulting expression

C(900) =  -0.05(900)²/2 + 77(900)

C(900) = -20,250+69,300

C(900) = 49,050

Hence the total costs in cents is 49,050cents

6. Find the missing side. Round to the nearest tenth ​

Answers

Answer:

x = 7.6

Step-by-step explanation:

We know the opposite side and the adj side and this is a right triangle

tan theta = opp / adj

tan 66 = 17/x

x tan 66 = 17

x = 17 /tan 66

x=7.56888

To the nearest tenth

x = 7.6

tanØ=Perpendicular/Base

tan66=17/xx=17/tan66x=7.57x=7.6

Point D is 8 units away from the origin along the x-axis, and is 6 units away along the y-axis. Which of the following could be the coordinates of Point D

Answers

Answer:

The distance between two points (x₁, y₁) and (x₂, y₂) is given by:

[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

Now we know that point D, which we can write as (x, y), is at a distance of 8 units from the origin.

Where the origin is written as (0, 0)

We also know that point D is 6 units away along the y-axis.

Then point D could be:

(x, 6)

or

(x, -6)

Now, let's find the x-value for each case, we need to solve:

[tex]8 = \sqrt{(x - 0)^2 + (\pm6 - 0)^2}[/tex]

notice that because we have an even power, we will get the same value of x, regardless of which y value we choose.

[tex]8 = \sqrt{x^2 + 36} \\\\8^2 = x^2 + 36\\64 - 36 = x^2\\28 = x^2\\\pm\sqrt{28} = x\\\pm 5.29 = x[/tex]

So we have two possible values of x.

x = 5.29

and

x = -5.29

Then the points that are at a distance of 8 units from the origin, and that are 6 units away along the y-axis are:

(5.29, 6)

(5.29, -6)

(-5.29, 6)

(-5.29, -6)

Find the slope and the y-intercept of the line with the given equation.

f(x) = 7 -4/5x
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

A. The slope is
(Type an integer or a simplified fraction.)
B. The slope is undefined.
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

A. The y-intercept is
(Simplify your answer. Type an ordered pair, using integers or fractions.)
B. There is no y-intercept.

Answers

Answer:

The slope is -4/5

The y intercept is (0,7)

Step-by-step explanation:

f(x) = 7 -4/5x

Rewriting

y = -4/5x +7

This is in slope intercept form

y = mx+b where m is the slope and x is the y intercept

The slope is -4/5

The y intercept is (0,7)

A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than 60,000 miles. The manufacturer tests 250 tires and finds the mean life for these tires to be 64,500 miles.What is the alternative hypothesis being tested in this example

Answers

Answer:

The alternative hypothesis being tested in this example is that the tire life is of more than 60,000 miles, that is:

[tex]H_1: \mu > 60,000[/tex]

Step-by-step explanation:

A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than 60,000 miles.

At the null hypothesis, we test if the tire life is of at most 60,000 miles, that is:

[tex]H_0: \mu \leq 60,000[/tex]

At the alternative hypothesis, we test if the tire life is of more than 60,000 miles, that is:

[tex]H_1: \mu > 60,000[/tex]

How can you minimize the risk from your investments?

A.
by investing in a stock with the highest volatility
B.
by investing in a stock with maximum returns
C.
by investing in a variety of investment options

Answers

by common sense I can tell is C.) by investigating in a variety of investment options!

while doing business I rather have multiple options than one! but that is personal you may have your own thought!

Answer:

C. by investigating in a variety of investment options

Explanation:

diversification reduces investment risk

(it is obviously not a as volatility is high degree of variation which is negative)

The pie chart shows the favorite type of book of the more than 50,000 high school students. About what percent of favorite type of book is drama? About what percent is mystery?


Complete the statements based on the information.


About

% of high school students chose dramas as their favorite type of book.


About

% of high school student chose mysteries as their favorite type of book.

Ans:
50%

25%

Answers

Answer:

About 50% of high school student chose dramas as their favorite type of book.

About 25% of high school student chose mysteries as their favorite type of book.

Thus, 50% of high school students chose dramas as their favorite type of book and 25% of high school students chose mysteries as their favorite type of book.

What is the percentage?

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

It is given that:

The pie chart shows the favorite type of book of more than 50,000 high school students.

As we know,

A circular statistical visual with slices illustrating a normal probability plot is named a pie chart. Each slice's arc length in a pie chart matches to the quantity it displays.

Thus, 50% of high school students chose dramas as their favorite type of book and 25% of high school students chose mysteries as their favorite type of book.

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Find the missing length indicated

Answers

Answer:

x = 15

Step-by-step explanation:

x = √{(25-16)×25}

x = √(9×25)

x = √225

x = 15

Answered by GAUTHMATH

In 20P4 how many choices are
there for vice-president from a
state of four officers?
Note: The vice president is the second officer
to be elected.
Acellus

Answers

Answer:  B) 19

Explanation:

There are 20 choices for president, and 20-1 = 19 choices for vice president. You count down by 1 each time you fill a seat. So that means you'll have 19-1 = 18 choices for the third seat, and 18-1 = 17 choices for the fourth seat.

Hello people can you please help me on this

Answers

Step-by-step explanation:

Step 1:  Complete the first equation

0.1 is a tenth, therefore if we have 15.3 then we have 153 tenths.

Step 2:  Complete the second equation

15.3 / 3 = 5.1  

0.1 is a tenth, therefore if we have 5.1 then we have 51 tenths.  

Step 3:  Complete the third equation

15.3 / 3 = 5.1

The difference of two numbers is 8. If the sum of the smaller number and the square of the larger number is 148, what is the smaller number?

Answers

Answer:

C

Step-by-step explanation:

x^ 3 +x^ 2 +4x/x^ 2 +x-2
into partial
fractions​

Answers

Answer:

x + (4/ x-2) + (2/ x-1)

Step-by-step explanation:

x + (6x/ x^2 + 2x - x -2)

x + (6x/ (x + 2) X (x - 1))

(6x/ (x + 2) X (x - 1))

(A/ x+2) + (B/ x-1)

(6x/ (x + 2) X (x - 1)) = (A/ x+2) + (B/ x-1)

6x = Ax + Bx - A + 2B

6x = (A+B)x + (-A+2b)

{0 = -A+2B

{6 = A+B

(A,B) = (4, 2)

(4/ x+2) + (2/ x-1)

x + (4/ x-2) + (2/ x-1)

A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let Y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation. y p(x, y) 0 1 2 x 0 0.10 0.03 0.02 1 0.06 0.20 0.07 2 0.05 0.14 0.33 (a) What is P(X

Answers

Answer:

[tex]P(x = 1) = 0.33[/tex]

[tex]P(y = 2) = 0.42[/tex]

Step-by-step explanation:

Given

                    y

x [tex]\begin{array}{cccc}P(x,y) & {0} & {1} & {2} & {0} & {0.10} & {0.03} & {0.02} & {1} & {0.06} & {0.20} & {0.07} & {2} & {0.05} & {0.14} & {0.33}\ \end{array}[/tex]

Solving (a)

[tex]P(x = 1)[/tex]

To do this, we simply add all data where x = 1

So, we have:

[tex]P(x = 1) = P(x=1|y=0) + P(x=1|y=1) + P(x=1|y=2)[/tex]

[tex]P(x = 1) = 0.06 + 0.20 + 0.07[/tex]

[tex]P(x = 1) = 0.33[/tex]

Solving (b)

[tex]P(y = 2)[/tex]

To do this, we simply add all data where y = 2

So, we have:

[tex]P(y = 2) = P(x=0|y=2) + P(x=1|y=2) + P(x=2|y=2)[/tex]

[tex]P(y = 2) = 0.02 + 0.07 + 0.33[/tex]

[tex]P(y = 2) = 0.42[/tex]

Expand and simplify the following expressions. a. (2 − 3)( − 6)

Answers

Answer:

your answer should be six I hope this help

Answer:

the should be 6

Step-by-step explanation:

(2-3)(-6)

-12+18

=6

What is the remainder for the synthetic division problem below?
2/ 3 1 2 -7
A. 25
B. 17
C. -29
D. -39

Answers

Answer:

B.17

Step-by-step explanation:

B.17

B.17

B.17

B.17

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