Answer:
0.67 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]d = \frac{m}{v} \\ [/tex]
m is the mass
v is the volume
From the question
m = 20 g
v = 30 mL
We have
[tex]d = \frac{20}{30} = \frac{2}{3} \\ = 0.66666...[/tex]
We have the final answer as
0.67 g/mLHope this helps you
Describe the water cycle. Be sure to include the following terms in your response: evaporation, condensation, and precipitation.your respone:
Evaporation, or turning liquid to a gas, is first. Then it goes into the atmosphere and codensates, or turns back to a liquid, these water droplets form into clouds and come down as precipitation, rain, sleet, snow etc. Then the water cycle starts again
Compare the amount of kinetic energy of particles in each state of matter- solid, liquid, gas
Answer:
gas moves around the most so it would have the most kinetic energy and solids would have the least as they only vibrate a tiny bit(not visible to the naked eye)
What is the smallest value of the force F such that the 8.0 kg block will not slide down the wall? The coefficient of static friction between the block and the wall is 0.4.
Select one:
a. 10N
b. 100N
c. 200N
d. 98N
The smallest value of the force that will make the block not to slide down is 10 N.
We'll begin by calculating the normal reaction. This can be obtained as follow:
Mass (m) = 8 KgAcceleration due to gravity (g) = 10 m/s²Normal reaction (N) =?N = mg
N = 8 × 10
N = 80 N
Finally, we shall determine the frictional force.
Coefficient of friction (μ) = 0.4Normal reaction (N) = 80 NFrictional Force (F) =?F = μN
F = 0.4 × 80
F = 32 N
Since the frictional force is 32 N, therefore, a force lesser than the frictional force will make the block not to slide down.
From the options given above, only option A has a force that is lesser than the frictional force.
Therefore, the correct answer to the question is Option A. 10 N
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A sound frequency 100Hz and wavelength 3.34m is travelling through air, calculate the Velocity of sound in air.
Answer:
334m/s
Explanation:
If you take the data you gave and insert it into the equation f=v/λ the frequency would come out to be 3.34m
334 m/s is the Velocity of sound in air.
What is the velocity of a wave?Wave velocity in common usage refers to speed, although, properly, velocity implies both speed and direction.
The velocity of a wave is equal to the product of its wavelength and frequency (number of vibrations per second) and is independent of its intensity.
Mathematically , v=fλ
According to the question,
Sound frequency (f) = 100Hz
Wavelength (λ)= 3.34m
Computing the values in the formula,
v=fλ
v = 100Hz x 3.34m
v= 334m/s
Therefore,
Velocity of sound in air is 334 m/s.
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What would be the difference in your welght if you were four times farther from the center of Earth than you are now?
you would die.
the core of the earth is as hot as the sun surface so you would be dead
pls help me, its just fill in the blank
1. Frequency
2. Reflected
3. Absorbed
4. Black
Which of these best describes the relationship between the incident ray, the reflected ray, and the normal for a curved mirror?(1 point)
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is different than the angle that the reflected ray makes with the normal. Different points on a curved mirror have a different normal.
The angle that the incident ray makes with the normal is the same as the angle that the reflected ray makes with the normal. All points on a curved mirror have the same normal.
For a curved mirror, all points have the same normal and the angle of incidence is also equal to the angle of reflection.
According to the laws of reflection, the incident ray, reflected ray and normal all lie on the same plane. For a curved mirror, the normal remains the same at all points along the curved mirror.
Again, the angle made between the incident ray and the normal is the same as the angle made between the reflected ray and the normal. Therefore, the angle of reflection is equal to the angle of incidence.
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give answer or fight me
Answer:
translucent
Explanation:
Hope this helps! Pls give brainliest! Also, please sub to Kgirl633 on yt.
Two solid cubes have the same Mass but their edges are in the ratio of 4:1. What isthe ratio of their densities?
Let m be the mass of both cubes. If the smaller cube has side length x, then its volume is x ³. The side lengths of the larger cube have length 4x, so the larger cube's volume is (4x)³ = 64x ³, or 64 times as large as the smaller cube.
The first cube has a density of m/x ³, while the larger one has a density of m/(64x ³) = 1/64 m/x ³, so the ratio of densities is (1/64):1, or 1:64 (larger cube to smaller cube).
A sled is launched off a cliff 39 m high and lands 74 m away from the base of the cliff. How fast was the sled launched?
The sled was launched with a velocity of 26.24 m/s
We'll begin by calculating the the time taken for the sled to land
Height (h) = 39 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?[tex]t = \sqrt{ \frac{2h}{g}} \\ \\t = \sqrt{ \frac{2 \times 39}{9.8}} \\ \\ t = 2.82 \: s \\ \\ [/tex]
Finally, we shall determine the velocity.Time (t) = 2.82 s
Horizontal distance (s) = 74 m
Horizontal velocity (u) =?[tex]u = \frac{s}{t} \\ \\ u= \frac{74}{2.82} \\ \\ u = 26.24 \: m/s \\ \\ [/tex]
Therefore, the sled was launched with a velocity of 26.24 m/s
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An object of length 3.00 cm is inside a plastic block with index of refraction 1.40. If the object is viewed from directly above, what is the length of its image?
Given,
length of object, [tex]h_o = 3 cm[/tex]
We know, for flat refracting surface,
Image distance = object distance
So,
magnification is = [tex]-1[/tex]
length of the image,
[tex]h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm[/tex]
Here, negative sign means inverted image.
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how far away is a train if you see the steam from is nozzle 4.5 seconds
before you hear its sound?(take speed of sound as 331 m/sec)
Answer:
Distance = 1489.5 meters
Explanation:
Given the following data;
Time = 4.5 secondsSpeed of sound = 331 m/sTo find how far away is the train;
Mathematically, the distance of an object is calculated using the formula;
Distance = speed * time
Distance = 331 * 4.5
Distance = 1489.5 meters
Preston goes on a camel safari. There, he travels 5 km north, then 3 km east.
7777Answer:
Explanation:
What is kinematics . Give two examples
Answer:
kinematics explains the terms like acceleration, velocity, and position of the objects while in motion.
Some important parameters in kinematics are displacement, velocity, and time.
Explanation:
your welcome,can you give me the brainliest? plssss
thank me if it was correct for you too.
Answer:
Definition of Kinematics :- Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them. ... An example model of bodies in a system is the gears in a vehicle's transmission.Example of kinematics :- The examples for kinematics are given below: -i) Moving train and bus. ii) Motion of a mass on inclined plane. iii) Running water in the river. iv) Falling water from a mountain peak.Explanation:
Hope this helps you dear ✌️Carry on learning !!An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?
Answer:
[tex]88.3ms {}^{ - 2} [/tex]
or 88.3m/s^2
Explanation:
Using suvat where we list everything that we are given
s=49m
u=0m/s
v=93m/s
a=?
t=we are not given this value, so we don't use
using a formula that doesn't involve time:
[tex]v {}^{2} = u {}^{2} + 2as[/tex]
rearranging to find acceleration by subtracting u^2 on both sides
[tex]v {}^{2} - u {}^{2} = 2as[/tex]
then dividing 2s on both sides
[tex] \frac{v {}^{2} - u {}^{2} }{2s} = a[/tex]
[tex] \frac{(93) {}^{2} - (0) {}^{2} }{2 \times(49) } = 88.3ms {}^{ - 2} [/tex]
so the acceleration is 88.3ms^-2 (1dp)
A person uses a screwdriver to turn a screw and insert it into a piece of wood. The person applies a force of 20 newtons to the screwdriver and turns the handle of the screwdriver a total distance of 0.5 meter. How would these numbers be different if the person inserted a nail with a hammer instead of the screw with the screwdriver?
A. The force applied would be greater, but the distance would be shorter.
B. The force applied would be less, but the distance would be greater.
C. The force applied would be the same, but the distance would be shorter.
D. The force applied would be the same, but the distance would be greater.
If the person inserted a nail with a hammer instead of the screw with the screwdriver, the force applied would be greater, but the distance would be shorter. The correct option is A.
What is force?The action of push or pull in order to make a body change its state of motion or rest is called Force.
As the force is pressure per unit area. Force is inversely proportional to the area over which force is to applied.
The hammer would take more force to insert the nail. The screw has its helix which is to be inserted and application of force is small.
Thus, the force applied would be greater, but the distance would be shorter. The correct option is A.
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t if the person inserted a nail with a hammer instead of the screw with the screwdriver?
There are four charges, each with a magnitude of 4.25 C. Two are positive and two are negative. The charges are fixed to the corners of a 0.440-m square, one to a corner, in such a way that the net force on any charge is directed toward the center of the square. Find the magnitude of the net electrostatic force experienced by any charge.
Answer:
F = 7.68 10¹¹ N, θ = 45º
Explanation:
In this exercise we ask for the net electric force. Let's start by writing the configuration of the charges, the charges of the same sign must be on the diagonal of the cube so that the net force is directed towards the interior of the cube, see in the attached numbering and sign of the charges
The net force is
F_ {net} = F₂₁ + F₂₃ + F₂₄
bold letters indicate vectors. The easiest method to solve this exercise is by using the components of each force.
let's use trigonometry
cos 45 = F₂₄ₓ / F₂₄
sin 45 = F_{24y) / F₂₄
F₂₄ₓ = F₂₄ cos 45
F_{24y} = F₂₄ sin 45
let's do the sum on each axis
X axis
Fₓ = -F₂₁ + F₂₄ₓ
Fₓ = -F₂₁₁ + F₂₄ cos 45
Y axis
F_y = - F₂₃ + F_{24y}
F_y = -F₂₃ + F₂₄ sin 45
They indicate that the magnitude of all charges is the same, therefore
F₂₁ = F₂₃
Let's use Coulomb's law
F₂₁ = k q₁ q₂ / r₁₂²
the distance between the two charges is
r = a
F₂₁ = k q² / a²
we calculate F₂₄
F₂₄ = k q₂ q₄ / r₂₄²
the distance is
r² = a² + a²
r² = 2 a²
we substitute
F₂₄ = k q² / 2 a²
we substitute in the components of the forces
Fx = [tex]- k \frac{q^2}{a^2} + k \frac{q^2}{2 a^2} \ cos 45[/tex]
Fx = [tex]k \frac{q^2}{a^2}[/tex] ( -1 + ½ cos 45)
F_y = k \frac{q^2}{a^2} ( -1 + ½ sin 45)
We calculate
F₀ = 9 10⁹ 4.25² / 0.440²
F₀ = 8.40 10¹¹ N
Fₓ = 8.40 10¹¹ (½ 0.707 - 1)
Fₓ = -5.43 10¹¹ N
remember cos 45 = sin 45
F_y = - 5.43 10¹¹ N
We can give the resultant force in two ways
a) F = Fₓ î + F_y ^j
F = -5.43 10¹¹ (i + j) N
b) In the form of module and angle.
For the module we use the Pythagorean theorem
F = [tex]\sqrt{F_x^2 + F_y^2}[/tex]
F = 5.43 10¹¹ √2
F = 7.68 10¹¹ N
in angle is
θ = 45º
Make a super villain out of these resources
Answer:the super villain would have the ability to control electricity and could take any Metal object or weapons that anyone points at him because he is magnetic
Explanation:
A 2-kg object is pulled to the left with a force of 30 N and to the right with a force of 9 N. What is the acceleration of the object?
An object that weighs 75 N is pulled horizontally to the right with a force of 50 N. The force of friction on this object is 30 N to the left. What is the acceleration of the object?
The force on the object is 50 N to the right and 30 N to the left.
⇒ The net force on the object is, =50−30=20 N to the right.
The weight of the object is, =75 N.
⇒ The mass of the object is ==759.8 kg.
⇒ The acceleration of the object is ==20759.8=2.613 m/s 2.
The acceleration of the object is 10 [tex]m/s^2[/tex].
What is Acceleration?Acceleration is defined as the rate of change of velocity of an object with respect to time which are vector quantities i.e. both magnitude and direction. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
It can be expressed as:
a= v/t
where, a is the acceleration
v is the velocity
t is the time taken
It can also be expressed as F=ma
where, F= force applied
m= mass of the object
So, for above given information
The force on the object is 9N to the right and 30N to the left. The net force on the object is 21N to the left
The mass of the object is 2kg
So, a= 21N/ 2 kg = 10.5 [tex]m/s^2[/tex]
Thus, the acceleration of the object is 10 [tex]m/s^2[/tex].
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A loaded truck collides with a car causing huge damage to the car. Which of the following is true about the collision? *
A. The force on the truck is greater than the force on the car
B. The force on the car is greater than the force on the truck
C. The force on the truck is the same in magnitude as the force on the car
D. During the collision the truck makes greater displacement than the car
E. During the collision the truck has greater acceleration than the car
The force on the truck is the same in magnitude as the force on the car.
The impulse experienced by an object during collision is directly proportional to the applied force and time of collision of the objects.
J = Ft
where;
J is the impulse experienced by the objectt is the timeThe increase in the force applied to an object causes an increase in the impulse experienced by the object.
Also, according to Newton's third law of motion, the force exerted on the loaded truck and the car are equal in magnitude but opposite in direction.
Thus, we can conclude that, the force on the truck is the same in magnitude as the force on the car.
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Help if u can please
Answer:
d
Explanation:
A pail of water of mass 2000 gm is rotated in a vertical circle of radius 1.00 m. What is the pail’s minimum speed at the top of the circle if no water is to spill out and the tension exerted by the string is 25 N?
The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.
The given parameters:
Mass of the water, m = 2000 g = 2 kgRadius of the circle, r = 1 mTension on the string, T = 25 NThe net force on the pail of water at the top of the vertical circle is calculated as follows;
[tex]T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s[/tex]
Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.
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The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s
We are given;
Mass of the pail of water; m = 2000 g = 2kg
Radius of the circle; r = 1 m
Tension exerted by string; T = 25 N
To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;
W - T = ma
Where;
W is weight = mg
T is tension on the string
Now, in circular motion, we know that;
Acceleration is; a = v²/r
Thus;
mg - T = m(v²/r)
Making v the subject of the formula gives us;
v = √[(r(T + mg)/m)
Plugging in the relevant values gives;
v = √[(1(25 + (2 * 9.8))/2)
v = 4.722 m/s
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GUYS COULD SOMEONE PLEASE HELP ME?
PLEASE ASAP
Write a summary of how the eye works:
Answer:
Eye function renders you the sense of sight. They convert light into electrical signals. Afterwards, the brain deciphers these electrical signals into images. Properly working healthy eyes are able to perform the following functions.
Explanation:
Miguel, a single teacher, earns $1,500 every two weeks (biweekly). He claims two allowances. What is his federal income tax withholding for each biweekly paycheck?
The federal income tax withholding for each biweekly paycheck for the single teacher is $259.9.
The given parameters:
Biweekly amount earned by the single teacher, = $1,500
The federal tax rate for single workers is given as;
amount between $436 and $1,506 = $34.9 plus 15%
The federal income tax withholding for each biweekly paycheck for the single teacher is calculated as follows;
income tax withholding = $34.9 + 0.15($1,500)
income tax withholding = $34.9 + $225
income tax withholding = $259.9
Thus, the federal income tax withholding for each biweekly paycheck for the single teacher is $259.9.
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The table below describes some features of methods used to generate electricity. What is method 3?
Answer:
dam/hydro power
Explanation:
estuary is the place where rivers meet the ocean, there are a lot of currents there (waves...) so it likely means thery use a dam or some sort of way of collecting electricity from the motion of the water there. many birds live in estuaries because of being able to find fish to feed from
Method 3 is "Estuary." describes some features of methods used to generate electricity.
An estuary is a coastal area where freshwater from rivers meets and mixes with saltwater from the ocean. This mixing creates a unique and dynamic environment that can be harnessed for electricity generation using a method called "tidal energy" or "tidal power." Tidal energy is a renewable energy source that captures the kinetic energy generated by the ebb and flow of tides in estuaries.
Ideal Location: Estuaries are ideal locations for tidal energy generation because they experience regular and predictable tidal movements due to the gravitational pull of the moon and sun. The rise and fall of tides create kinetic energy in the moving water.
Method: Tidal energy is harnessed using underwater turbines that are placed in strategic locations within the estuary. As the tidal currents flow in and out, they drive the turbines, which generate mechanical energy. This mechanical energy is then converted into electricity using generators.
Possible Problem: One potential problem associated with tidal energy generation in estuaries is its impact on the local ecosystem. The underwater turbines and infrastructure could potentially disrupt marine life and habitats, affecting fish migration patterns and other aquatic species. It's important to carefully study and manage the environmental impact of tidal energy projects to minimize any negative consequences.
Overall, tidal energy from estuaries offers a renewable and predictable source of electricity, but it requires careful planning and environmental considerations to ensure sustainable and responsible energy production.
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Which are the products in the equation CH3SH + 4O2 → CO2 + SO2 +2H2O? Check all that apply.
Answer:
ch3sh + 4O2 are the products
15millas a km alguien pliss para ahorita porfa lo sigo
Answer:
X = 24.135 kilometres
Explanation:
Given the following data;
Distance = 15 miles
To convert the value in miles to kilometers;
Conversion:
1 mile = 1.609 kilometres
15 miles = X kilometres
Cross-multiplying, we have;
X = 1.609 * 15
X = 24.135 kilometres
i do believe that i need help
AB
ca
The trough of a transverse wave is BEST shown by choice
es - )
8
8
Answer:
bro the way you worded it makes no since
A 40 N block is resting on a rough inclined plane. The static friction between the block and the plane is ____ N.
The static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].
The given parameters:
Weight of the block, W = 40 NThe normal reaction on the rough surface due to weight of the block is calculated as follows;
[tex]F_n = 40 \ N[/tex]
The static friction between the block and the plane is calculated as follows;
[tex]F_s = \mu_s F_n[/tex]
where;
[tex]\mu_s[/tex] is coefficient of static frictionThus, the static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].
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