What is the electrical consumption in KVA of a motor powered by a 3-phase, 60 Hz, 460 VAC supply that continuously draws 17 A

Answers

Answer 1

Answer:

15.34 kVA

Explanation:

A motor is a device that converts electrical energy into mechanical energy. It takes in electrical energy at the input and produce torque (motion) at the output.

The power consumption for a three phase motor is the product of voltage and current and √3. The √3 is because it is a three phase supply.

Hence Power (P) =√3 × voltage (V) × current (I)

P = √3 × V × I

Given that voltage (V) = 460 V, current (I) = 17 A. Hence:

P = √3 × V × I = √3 × 460 × 17 = 13544.64 VA

But 1000 VA = 1 kVA. Hence:

[tex]P=13544.64\ VA*\frac{1\ kVA}{1000\ VA}=13.54\ kVA[/tex]


Related Questions

Which do you suppose exerts more pressure on the ground—an elephant or a lady standing on spike heels? (Which will be more likely to make dents in a linoleum floor?) Can you approximate a rough calculation for each?

Answers

Answer:

A woman with a spike heel

Explanation:

Since we're assuming here, we proceed to assuming that the mass of the elephant is 6000 kg, and the mass of the lady is 60 kg. Then,

a woman with a spike heel will exert more pressure on the ground than an elephant weighing 6000 kg. This is because, the force exerted by the woman is a 588 N and she has a, say 1 cm² spike heel. This puts half her weight on each foot, and if evenly distributed to half on her heel and half on her sole, the pressure being exerted by each heel is 147 N/ 2cm² = 147 N/cm². On the other hand, if a 58,860 N elephant with an 1000 cm² feet is exerting 1/4 its weight on each foo. Then it has 14715 N/1000 cm² = 14.7 N/cm²; which is exactly 10 times lesser pressure than what the woman is exerting. So, the woman with the hell exerts more pressure, than the elephant will.

7. A girl pushes her little brother on his sled with a force of 300. N for 750. m. How much work is this if the force of friction acting on the sled is (a) 200. N. (b) 300. N?​

Answers

Answer:

a) 75000Joules

b) 0Joules

Explanation:

Workdone = Force * Distance

Given

distance= 750m

Force = 300N

a) If the frictional force = 200N

The Total force = 300N - 200N = 100N

Work done = 100 * 750

Workdone = 75,000Joules

Hence the workdone if the force of friction is 200N is 75,000Joules

b) If the frictional force = 300N

The Total force = 300N - 300N = 0N

Work done = 0* 750

Workdone = 0Joules

Hence the workdone if the force of friction is 300N is 0Joules i.e no work will be done on the sled

5. Candance got $0.22 in change when she bought chips at the
store. What percent of a dollar does her change represent?

Answers

Answer:

22%

Explanation:

Given parameters:

The amount of change  = $0.22

Unknown

What percentage of a dollar the change represents  = ?

Solution:

A dollar is made up of 100cents;

        So;

 $0.22 represents 22cents

Percentage of dollar this represents  = [tex]\frac{22}{100}[/tex]  x 100  = 22%

A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocity selector is 3.10 103 N/C, while the magnetic field is 0.360 T. When the electric field is turned off, the charged particle travels on a circular path whose radius is 4.20 cm. Find the charge-to-mass ratio of the particle.

Answers

Answer:

The charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg

Explanation:

From the formulae

F = qvB and F = mv²/r

Where F is Force

q is charge

v is speed

B is magnetic field strength

m is mass

and r is radius

Then,

qvB = mv²/r

qB = mv/r

We can write that

q/m = v/rB ---- (1)

Also

From Electric force formula

F = Eq

Where E is the electric field

and magnetic force formula

F = Bqv

Since, electric force = magnetic force

Then, Eq = Bqv

E = Bv

∴ v = E/B

Substitute v = E/B into equation (1)

q/m = (E/B)/rB

∴ q/m = E/rB²

(NOTE: q/m is the charge to mass ratio)

From the question,

E =  3.10 ×10³ N/C

r = 4.20 cm = 0.0420 m

B = 0.360 T

Hence,

q/m = 3.10 ×10³ / 0.0420 × (0.360)²

q/m = 569517.9306 C/kg

q/m = 5.7 × 10⁵ C/kg

Hence, the charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg.

A very long solid insulating cylinder has radius R = 0.1 m and uniform charge density rho0= 10-3 C/m3. Find the electric field at distance r from the axis inside the cylinder in terms of r/R.​

Answers

Answer:

[tex]E = (0.56 \times 10^8 ) r \ \ N/c[/tex]

Explanation:

Given that:

[tex]\rho_o = (10^{-3} ) \ c/m^3[/tex]

R = (0.1) m

To find  the electric field for r < R by using Gauss Law

[tex]{\oint}E^{\to}* da^{\to} = \dfrac{Q_{enclosed}}{\varepsilon_o} --- (1)[/tex]

For r < R

[tex]Q_{enclosed}=(\rho) ( \pi r^2 ) l[/tex]

[tex]E*(2 \pi rl)= \dfrac{\rho ( \pi r ^2 l)}{\varepsilon_o}[/tex]

[tex]E= \dfrac{\rho ( r)}{2 \varepsilon_o}[/tex]

where;

[tex]\varepsilon_o = 8.85 \times 10^{-12}[/tex]

[tex]E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}[/tex]

[tex]E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}[/tex]

[tex]E = (0.56 \times 10^8 ) r \ \ N/c[/tex]

In October 1997, Andy Green broke the sound barrier on land in a jet-powered car. Green's car had accelerated from rest to 763 mi/h (341 m/s) over a 5.0-mi (8047-m) stretch. Assuming constant acceleration, over what time interval had he reached the top speed

Answers

Answer: the time interval Green had to reached the top speed is 47.2 secs

Explanation:

Given the data in the question;

first we determine Green's acceleration.

from third equation of motion, v² - u² = 2as

a = v² - u² / 2s

we substitute,

a = ( (341 m/s)² - (0)² ) / 2(8047)

a = (116281 - 0) / 16094

a = 7.23 m/s²

Now we determine the time interval need to reach top or maximum speed,

v = u + at

at = v - u

t = (v - u) / a

so we substitute

t = (341 - 0) / 7.23

t = 341 / 7.23

t = 47.2 secs

Therefore, the time interval Green had to reached the top speed is 47.2 secs

a substance has a pH of 9.what type of substance is it

Answers

Answer:

I think its Baking soda, antacids, Sorry if i'm wrong!

Explanation:

Answer:

it base

Explanation:

because i passed the test on that

What is the electric field inside a hollow sphere with total charge Q distributed evenly along the surface of the sphere

Answers

Answer:

0 N/C

Explanation:

Using Gauss' law ∫εE.dA = Q. where E = electric field, dA = differential area and Q = charge enclosed.

Since for r < r₀ where r₀ = radius of the sphere, Q = 0. and ∫εE.dA = ∫εEdAcos180 (since the electric field is directed radially inward opposite to the normal area vector)

∫-εEdA = 0

-εE∫dA = 0

-εEA = 0

E = 0/-εA

E = 0 N/C

What causes the movement of electrical current in the circuit within the device shown in the diagram?


NASA
Movement of protons
Movement of electrons
Heating of silicon
The anti-reflection coating

Answers

Answer:

B. Movement of electrons

Hope this helps!! may I have brainliest? :)

Answer:

Movenment of electrons

Explanation:

Soccer fields vary in size. A large soccer field is 115 m long and 85.0 m wide. Assume that 1 m equals 3.281 ft. What are its dimensions in feet

Answers

Answer:

The dimensions are 377.3 feet by 278.9 feet.

Explanation:

Given that,

Length of a soccer field = 115 m

Width of a soccer field = 85 m

We need to assume that, 1 m equals 3.281 ft

We need to find the dimensions in feet.

As 1 m = 3.281 ft

⇒ 115 m = (115×3.281) feet

= 377.315 feet ≅ 377.3 feet

⇒ 85 m = (85×3.281) feet

= 278.885 feet ≅ 278.9 feet

Hence, the dimensions are 377.3 feet by 278.9 feet.

Does the voltage of a battery affect the strength of an electromagnet?

Answers

I'm trying to make an electromagnet that's strength is constantly getting incremented by small amounts every second. I need to know, which would have a greater effect on the electromagnet's strength, amps or volts? (I know increasing the turns and/or density of the magnet wire will increase the strength, but I am looking for answers other than that particular one.)

What is a Wave In your own words

Answers

A wave is a big pile of water

Calculate the momentum of a 1150 kg car traveling with a velocity of 24.5 m/s.

Answers

Answer:

P = 28175 Ns

Explanation:

Momentum is defined as the quantity of motion contained in a body. Mathematically, momentum is defined as the product of the mass and velocity of an object. So we  will use the following formula to find the momentum of the car:

[tex]P = mv\\[/tex]

where,

P = momentum of the car = ?

m = mass of the car = 1150 kg

v = speed of the car = 24.5 m/s

Therefore,

[tex]P = (1150\ kg)(24.5\ m/s)[/tex]

P = 28175 Ns

Sound waves can be modeled by the equation of the form y=20sin(3t+theta). Determine what type of interference results when sound waves modeled by the equations y=20sin(3t+90) and y=20sin(3t+270) are combined.

Answers

Answer:

go to the link quizzlet it will give you tha answer

Explanation:

An engine has an output energy of 2,400 J in 10 seconds. What is its average power in watts?

Answers

Answer:

P = 240 W

Explanation:

By definition, the average power is the rate of change of Energy (in Joules) regarding time (in seconds), as follows:

       [tex]P = \frac{\Delta E}{\Delta t} (1)[/tex]

Replacing in (1) by the givens of ΔE = 2, 400 J and Δt = 10 sec, we can find the average power in Watts as follows:

       [tex]P = \frac{\Delta E}{\Delta t} =\frac{2,400J}{10s} = 240 W (2)[/tex]

How does work done on an object affect its kinetic energy

Answers

According to the work-energy theorem, the work done on an object by a net force equals the change in kinetic energy of the object. Essentially kinetic energy is the energy used for motion. Interestingly, as work is done on an object, potential energy can be stored in that object. A moving object has kinetic energy because work has been done on it. When work is done energy in one form is transferred to the kinetic energy of the moving object. To stop the object again, the same amount of work would have to be done to bring it back to rest.

If the radius of curvature of the bump is 52 m, find the apparent weight of a 62-kg person in your car as you pass over the top of the bump. Express your answer using two significant figures.

Answers

Answer:

The answer is below

Explanation:

Driving in your car with a constant speed of 12m/s, you encounter a bump in the road that has a circular cross-section, as indicated in the figure . If the radius of curvature of the bump is 52 m, find the apparent weight of a 62-kg person in your car as you pass over the top of the bump.  

Solution:

Centripetal force is the net force acting on a body which makes it move along a curved path. This force is always towards the center of curvature.

As the car passes over the bump, the centripetal acceleration acts downward towards the circle center.

The sum of all vertical forces is equal to zero, hence:

F - mg + ma = 0

where F is the apparent weight of the person, m is the mass of the person, ma = centripetal force = mv²/r

Given that:

m = 62 kg, v = velocity = 12 m/s, r = radius of curvature of bump = 52 m, g = acceleration due to gravity = 10 m/s. Therefore:

F - mg + ma = 0

F - mg + mv²/r = 0

F = mg - mv²/r

F = m(g - v²/r)

Substituting:

F = 62(10 - 12²/54)

F = 456.67 N

The apparent weight of a 62-kg person as the top of the bump is passed = 456.67 N

But the weight of the person = mg = 62* 10 = 620 N

A wooden block is let go from a height of 5.80 m. What is the velocity of the block just before it hits the ground?

Answers

Given :

A wooden block is let go from a height of 5.80 m.

To Find :

The velocity of the block just before it hits the ground.

Solution :

We know, by equation of motion :

[tex]v^2 - u^2 = 2as[/tex]

Here, a = g = 9.8 m/s²( Acceleration due to gravity )

Putting all given values in above equation, we get :

[tex]v^2 - u^2 = 2as\\\\v^2 -0 = 2\times 9.8 \times 5.8 \\\\v = \sqrt{2\times 9.8 \times 5.8 } \ m/s\\\\v = 10.66\ m/s[/tex]

Hence, this is the required solution.

Match each word to its correct meaning.

1. humus
the thin upper layer of Earth's crust that supports plant life
2. inorganic
a vertical section of soil that shows the horizon and parent material
3. organic
the layer of loose rock on the surface of the earth; also called mantle rock
4. parent material
dark colored organic material in soil; it is left over from the decay of living things
5. regolith
a physical property of soil that describes how the soil feels, and the relative components of sand, silt, and clay sized particles
6. soil
a chemical property of soils that describes the measure of hydrogen ions in a soil sample; how acidic or basic a soil sample is
7. soil horizon
a substance that does not contain carbon and hydrogen atoms, such as salts, rocks, and minerals
8. soil ph
a distinct layer of soil that has characteristic properties
9. soil profile
the rock material that was weathered to form the sediments in a given soil
10. soil texture
a substance that contains carbon and hydrogen atoms, such as carbon dioxide, glucose, methane, and nucleic acid

Answers

Answer:

1. Soil.

2. Soil profile.

3. Regolith.

4. Humus.

5. Soil texture.

6. Soil pH.

7. Inorganic.

8. Soil horizon.

9. Parent material.

10. Organic.

Explanation:

1. Soil: the thin upper layer of Earth's crust that supports plant life. There are three (3) main types of soil; sandy, clay and loamy soil.

2. Soil profile: a vertical section of soil that shows the horizon and parent material.

3. Regolith: the layer of loose rock on the surface of the earth; also called mantle rock.

4. Humus: dark colored organic material in soil; it is left over from the decay of living things.

5. Soil texture: a physical property of soil that describes how the soil feels, and the relative components of sand, silt, and clay sized particles.

6. Soil pH: a chemical property of soils that describes the measure of hydrogen ions in a soil sample; how acidic or basic a soil sample is.

7. Inorganic: a substance that does not contain carbon and hydrogen atoms, such as salts, rocks, and minerals.

8. Soil horizon: a distinct layer of soil that has characteristic properties.

9. Parent material: the rock material that was weathered to form the sediments in a given soil.

10. Organic: a substance that contains carbon and hydrogen atoms, such as carbon dioxide, glucose, methane, and nucleic acid.

A hunter points a rifle directly at a coconut that he intends to shoot off a tree. It so happens that the coconut falls from the tree at the exact instant the hunter pulls the trigger. What happens to the bullet?

Answers

Answer:

Explanation:

The bullet will hit the coconut .

Both coconut and bullet will fall under the gravitational pull of the earth . They will experience same acceleration because acceleration does not depend upon mass . So both bullet and coconut will fall by the same distance vertically .

So bullet will exactly hit the coconut .

1) If Shagreen bought the energy star refrigerator for $1800 and saved

$200 every year, how many years would it take for her to save back the

money she spent on the refrigerator?

Answers

Answer:

9

Explanation:

Shagreen bought the energy star generator for $1800

She saves $200/every year

Therefore the number of years it would take for her to save that amount can be calculated as follows

= 1800/200

= 9

Hence it would take 9 years to save up the money

6. Thomas sits on a small rug on a polished wooden floor. The coefficient to kinetic friction between the rug and

the slippery wooden floor is only 0.12. If Thomas weighs 650 N, what horizontal force is needed to pull the rug

and Thomas across the floor at a constant speed?[78N]

1

Answers

Answer:

F=78 N

Explanation:

Taking to Thomas and the rug as a single system, if they slide across the floor at constant speed, this means that their acceleration is just zero.According to Newton's 2nd Law, if the acceleration is zero, this means that the net force applied is zero too.In the horizontal direction, there are two forces acting on Thomas and the rug (as a single system), the applied force, and the kinetic friction force, which must be equal and opposite each other:

      [tex]F_{app} = F_{kfr} (1)[/tex]

By definition, as the friction force is the horizontal component of the contact force, it can be expressed as follows:

      [tex]F_{1kfr} = \mu_{k} * F_{n} (2)[/tex]

     where μk = coefficient of kinetic friction = 0.12

     Fn = normal force

In this case, as the system boy+rug is not accelerating in the vertical direction, and the surface is level, the normal force (which is always perpendicular to the surface), must be equal to the force of gravity.Assuming that the mass of the rug is neglectable, we can write:

      [tex]F_{n} = F_{g} = m*g = 650 N (3)[/tex]

Replacing (3) and μk in (2)

      [tex]F_{1kfr} = \mu_{k} * F_{n} = 0.12 * 650 N = 78 N (4)[/tex]

From (1), we finally get:

       [tex]F_{app} = F_{kfr} = 78 N (5)[/tex]

1. Which of the following will be surrounded by a magnetic field? *
1Two copper wires held close together.
2A pot being heated on an electric stove.
3A wire that is conducting an electrical current.
4An aluminum rod that has been touched by a magnet.

Answers

Answer:

4th answer

Explanation:

what causes dispersion of light?​

Answers

Dispersion occurs due to the different degrees of refraction experienced by different colours of light. Light of different colours may travel with the same speed in a vacuum, but they travel at different speeds in some refracting medium. The speed of violet light is relatively lower than that of red light.

A 70 kg object strikes the ground with 2500 J of KE after falling freely from rest. How far above the ground was the object when it was released?

Answers

Answer:

3.64 m

Explanation:

m = Mass of object = 70 kg

Kinetic energy of the object = 2500 J

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

h = Height from which the object is dropped

Kinetic energy is given by

[tex]\dfrac{1}{2}mv^2=2500\\\Rightarrow v^2=\dfrac{2\times 2500}{70}[/tex]

From conservation of energy we get kinetic energy equal to potential energy.

[tex]\dfrac{1}{2}mv^2=mgh\\\Rightarrow h=\dfrac{1}{2g}v^2\\\Rightarrow h=\dfrac{1}{2\times 9.81}\times \dfrac{2\times 2500}{70}\\\Rightarrow h=3.64\ \text{m}[/tex]

The object was released from a height of 3.64 m.

Determine the values of mm and nn when the following mass of the Earth is written in scientific notation: 5,970,000,000,000,000,000,000,000 kgkg.

Answers

Answer:

"m" and "n" are 5.97 and 24 respectively.

Explanation:

Standard form which is a scientific notation [m × 10^n] can be regarded as way to reduce large figures to small one in a decimal firm and this is usually done for conviniency sake.

✓Let us find "m" , to do this we will shorten the long number so that it will be from 1-9. And this is 5.97, hence

m = 5.97

✓ " n" can be determined by counting the digits from our right hand then stop where the decimal point was put when we were finding our "m". Hence

n= 24

✓ if we input the values to the scientific expresion above, we have

m = 5.97 and n = 24

Hence, the Standard form = 5.97 × 10^24 kg which is the scientific notation.

A quantitative review of the health record for missing reports and signatures that occurs when the patient is in the hospital is referred to as a review

Answers

Answer: This is referred to as a Concurrent review.

Explanation:

A health records of a patient consists of the medical history, diagnosis, treatment and even laboratory test results which provides reasonable information for health providers to make decisions about a patient's care.

A quantitative review of these health records are carried out by trained professionals to have a clear view of everything that has occurred previously to the patient and to know the extent of current injury or illness.

A quantitative review of these records can be:

--> Retrospective or

--> Concurrent.

Retrospective record review is carried out when the patient has left the hospital facility. This is used to supplement the concurrent record review to ensure a complete data set for performance measurement purposes.

Concurrent record review is carried out when a patient is hospitalised or undergoing active treatment. This review helps to obtain missing information or reports about the patient. The advantage of concurrent record review is the ability to easily initiate interventions when problems are identified as the patient is still in the facility.

Definition of dispersal​

Answers

The action of process of distributing things are people over a wide area

Answer:

the action or process of distributing things or people over a wide area.

"the dispersal of people to increasingly distant suburbs"

the splitting up of a group or gathering of people, causing them to leave in different directions.

"the dispersal of the crowd by mounted police"

the splitting up and selling off of a collection of artifacts or books.

"the dispersal of the John Willett Collection"

Explanation:

A 235 kg object and a 1.37×1012 kg are located 2.59×104 m away from each other. What is the force due to gravity between the two objects?

Answers

Answer:

F = 3.2 x 10⁻⁵ N

Explanation:

The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:

[tex]F = \frac{Gm_{1}m_{2}}{r^{2}}[/tex]

where,

F = gravitational force = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

m₁ = mass of object 1 = 235 kg

m₂ = mass of object 2 = 1.37 x 10¹² kg

r = distance between objects = 2.59 x 10⁴ m

Therefore,

[tex]F = \frac{(6.67\ x\ 10^{-11}\ Nm^{2}/kg^{2})(235\ kg)(1.37\ x\ 10^{12}\ kg)}{(2.59\ x\ 10^{4}\ m)^{2}}[/tex]

F = 3.2 x 10⁻⁵ N

Answer:

the force due to gravity between the two objects is 3.2 x 10⁻⁵ N.

Explanation:

Given;

mass of the first object, m₁ = 235 kg

mass of the second object, m₂ = 1.37 x 10¹² kg

distance between the two object, r = 2.59 x 10⁴ m

The gravitational force between the two object is calculated as;

[tex]F= \frac{Gm_1m_2}{r^2}[/tex]

where;

G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

[tex]F= \frac{(6.67\times 10^{-11})(235)(1.37\times 10^{12})}{(2.59\times 10^4)^2} \\\\F = 3.2 \times 10^{-5} \ N[/tex]

Therefore, the force due to gravity between the two objects is 3.2 x 10⁻⁵ N.

The acceleration due to gravity on or near the surface of Earth is 32 ft./s/s. Neglecting friction, from what height must a stone be dropped on Earth to strike the ground with a velocity of 136 ft./s

Answers

Given :

The acceleration due to gravity on or near the surface of Earth is 32 ft/s/s

To Find :

From what height must a stone be dropped on Earth to strike the ground with a velocity of 136 ft/s.

Solution :

Initial velocity of stone, u = 0 ft/s.

Now, by equation of motion :

[tex]2as = v^2 -u^2 \\\\2\times 32 \times s = 136^2 -0^2\\\\s = \dfrac{136^2}{2\times 32}\ ft\\\\s = 289 \ ft[/tex]

Therefore, height from which stone is thrown is 289 ft.

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