What is the frequency of a wave that has a period of 0.002 seconds?

Answer:

You will do twice the work of climbing 1 stair.

Explanation:

To obtain the answer to the question, we shall determine the work done on each case. This is illustrated below:

Case 1 ( climbing 2 stairs):

Mass (m) = m

One stair = 4 m

Height (h) = 2 × 4 = 8 m

Acceleration due to gravity (g) = 10 m/s²

Workdone 1 (Wd₁) =?

Wd₁ = mgh

Wd₁ = m × 10 × 8

Wd₁ = 80 × m

Case 2 (Climbing 1 stair)

Mass (m) = m

Height (h) = 4 m

Acceleration due to gravity (g) = 10 m/s²

Workdone 2 (Wd₂) =?

Wd₂ = mgh

Wd₂ = m × 10 × 4

Wd₂ = 40 × m

Now comparing the Workdone in both case:

Workdone 1 (Wd₁) = 80 × m

Workdone 2 (Wd₂) = 40 × m

Wd₁ / Wd₂ = 80 × m / 40 × m

Wd₁ / Wd₂ = 2

Cross multiply

Wd₁ = 2 × Wd₂

Thus, we can see that the Workdone in climbing 2 stairs is twice the Workdone in climbing 1 stair.

Therefore, you will do twice the work of climbing 1 stair.

Answer:

Yes, the carters are always facing the Earth as the moon orbits.

Explanation:

Answer:

Amoeba, paramecium, euglena are the examples of unicellular organism

Explanation:

Hope you like my answer

Answer:

[tex] \underline{ \boxed{F_m = 3.35 { \times 10}^{ - 2} N}}[/tex]

Explanation:

[tex]since \: in \: this \: case \to \: \underline{ v }\: is \perp \: to \:\underline{ q} \\ then \: the \: magnetic \: force \: (F_m) \: is \: max = qvB \sin(90) \\ F_m = qvB \times (1) = qvB \\ hence \to \\ F_m = qvB \\ where \\ \: q = 0.75 C : v = 235m {s}^{ - 1} : B = 1.9 { \times 10}^{ - 4} T \\ therefore \to \\ F_m = 0.75 \times 235 \times 1.9 { \times 10}^{ - 4} \\ F_m = 176.25 \times 1.9 { \times 10}^{ - 4} \\ F_m = 0.0334875 = 3.35 { \times 10}^{ - 2} N \\ \boxed{F_m = 3.35 { \times 10}^{ - 2} N}[/tex]

Answer:

v = 381 m/s

Explanation:

Linear Speed

The linear speed of the bullet is calculated by the formula:

[tex]\displaystyle v=\frac{x}{t}[/tex]

Where:

x = Distance traveled

t = Time needed to travel x

We are given the distance the bullet travels x=61 cm = 0.61 m. We need to determine the time the bullet took to make the holes between the two disks.

The formula for the angular speed of a rotating object is:

[tex]\displaystyle \omega=\frac{\theta}{t}[/tex]

Where θ is the angular displacement and t is the time. Solving for t:

[tex]\displaystyle t=\frac{\theta}{\omega}[/tex]

The angular displacement is θ=14°. Converting to radians:

[tex]\theta=14*\pi/180=0.2443\ rad[/tex]

The angular speed is w=1436 rev/min. Converting to rad/s:

[tex]\omega = 1436*2\pi/60=150.3776\ rad/s[/tex]

Thus the time is:

[tex]\displaystyle t=\frac{0.2443\ rad}{150.3776\ rad/s}[/tex]

t = 0.0016 s

Thus the speed of the bullet is:

[tex]\displaystyle v=\frac{0.61}{0.0016}[/tex]

v = 381 m/s

Answer:For a perfectly elastic collision, the final velocities of the carts will each be 1/2 the velocity of the initial velocity of the moving cart. For a perfectly inelastic collision, the final velocity of the cart system will be 1/2 the initial velocity of the moving cart.

Explanation:

Answer:

B

Explanation:

The two most abundant elements in a main sequence star are the hydrogen and helium. Thus, the correct option is B.

The main sequence is a continuous and distinctive band of the stars which appears on the plots of stellar color versus the brightness. These color-magnitude plots are known as the Hertzsprung–Russell diagrams, named after their co-developers, Ejnar Hertzsprung and Henry Norris Russell. The stars on this band are known as the main-sequence stars or the dwarf stars. These are the most numerous true stars present in the universe and include the Sun.

Hydrogen is the most abundant element which is possessed by the main sequence star. After hydrogen atom, the most abundant element which is found is helium. This gets accumulated in the star's core through the process of nuclear fusion.

Therefore, the correct option is B.

Learn more about Sequence star here:

https://brainly.com/question/30369795

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Explanation:

In a balanced equation, the total number of atoms of each element on the reactant side is equal total number of atoms on the product side

Answer:

5600N

Explanation:

Given parameters:

Mass of car  = 700kg

Initial velocity  = 10m/s

Final velocity  = 30m/s

Displacement  = 50m

Unknown:

Net force acting on the car  = ?

Solution:

To find the force acting on a body, it is pertinent we know the mass and acceleration.

 Force  = mass x acceleration

Now;

 Let us find the acceleration from the kinematics equations:

 v²  = u²  + 2aS

 v is the final velocity

 u is the initial velocity

 a is the acceleration

 S is the distance

  30²  = 10²  + (2 x a x 50)

 900 = 100 + 100a

      100a  = 800

           a  = 8m/s²

Therefore;

     Force  = 700 x 8  = 5600N

Answer:

41.576 N

Explanation:

Resolving force in the inclined plane in the x and y directions gives us;

F_x = mg sin θ

F_y = mg cos θ

Thus;

F_x = 4.8 × 9.81 × sin 28

F_x = 22.106 N

F_y = 4.8 × 9.81 × cos 28

F_y = 41.576 N

We can use Newton's second law to find the normal force.. Thus;

N - F_y = 0.

Where N is normal force;

N = 41.576 N

Answer:

1kg/ L

Explanation:

Answer:

It is a base

Explanation:

Because

Answer:it’s a base

Explanation: this is because the bases have a very bitter taste but a very slippery feel at the same time leading to a substance with a ph of 8.5 and the red turning to blue so this is a base

Answer:

The normal force experienced by the car is approximately 8223.2 N

Explanation:

The question relates to banking of road where the centripetal force for the circular motion of the vehicle is provided by the horizontal component of the normal reaction

The mass of the vehicle that moves around the curve, m = 900 kg

The incline of the curve, θ = 20°

The speed with which the vehicle moves around the curve, v = 12.5 m/s

The radius of the curve, R = 50 meters

We have;

[tex]N \cdot sin(\theta) = \dfrac{m \cdot v^2}{R}[/tex]

Where;

θ = The angle of inclination of the road = 20°

N = The normal force experienced by the car

m = The mass of the car = 900 kg

v = The velocity with which the car is moving = 12.5 m/s

R = The radius of the curve around which the vehicle moves = 50 m

[tex]\therefore N = \dfrac{m \cdot v^2}{R \cdot sin(\theta)} = \dfrac{900 \times (12.5)^2}{50 \times sin(20^{\circ})} = 8223.1998754586828969046217875927[/tex]

The normal force experienced by the car = N ≈ 8223.2 N.

When a car sounds its horn as it approaches and moves away from an observer, there is a change in pitch known as a Doppler shift. During the approach, the received frequency is higher than the emitted frequency. ]Thus, option B is correct.

You hear a fairly high-pitched sound, like an ambulance coming at you with sirens blazing. This is because the moving ambulance is squishing the sound waves in front of the car together.

A good illustration of the Doppler effect is this. Since the effective wavelength is reduced due to an approaching source moving closer throughout the sound wave's period while the wave's velocity remains constant, the pitch is increased. Similar to this, a sound source that is fading away will have a lower pitch.

Therefore, Sound waves are pushed closer together, increasing wavelength and decreasing frequency.

Learn more about Doppler effect here:

Answer:B

Explanation:

Answer:

[tex]P_J=195N[/tex]

Explanation:

From the question we are told that

[tex]Mass\ of T-joe\ M_J=65\\Velocity\ of T-joe\ V_J=3m/s\\Mass of\ T-Brud\ M_B=50kg\\Velocity\ of T-Brud\ V_B=3m/s\\[/tex]

Generally the equation for momentum is mathematically given by

[tex]P=mv[/tex]

Therefore

T-Joe momentum [tex]P_J[/tex]

[tex]P_J=65*3[/tex]

[tex]P_J=195N[/tex]

Answer:

I had that on 6th grade here u go

His third law states that for every action in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Answer:

all

Explanation:

i was in a question kinda like this and I think it's all

Answer:

irrational

Explanation:

Answer:

In a pulley, the ideal mechanical advantage is equal to the number of rope segments pulling up on the object. The more rope segments that are helping to do the lifting work, the less force that is needed for the job.

There would be more hurricanes because hurricanes from by water.

More rain because you would get more precipitation.

Higher flooding if a storm comes through.

Answer:

90.07794 grams

Explanation:

Answer:

MKS stands for Meter, Kilogram and second. In this system of unit mass is given in Kilogram, length in meter and time in second. ... CGS system stands for Centimeter- Gram- Second system. In CGS system, length is measured in centimeters mass is measured in grams and time is in seconds.

Answer: The property that will best provide evidence that the samples are solid includes:

--> if the substance has a definite shape,

-->if the substance has a definite volume

--> if it's tightly packed.

Explanation:

According to the kinetic theory of matter, every substance consist of very large number of very small particles called molecules. These molecules, which are made up of atoms that are the smallest particles of a substance that can exist in a free state.

Matter can exist in the following states:

--> Solid state

--> liquid state or

--> Gaseous state.

The general property of a substance that is in gaseous state includes:

--> Definite shape: A substance can be grouped as a solid if it's shape is fixed that is, it doesn't depend on the shape of other materials.

--> Definite volume: A substance can be grouped as a solid if it occupies its own shape. This is due to the force of cohesion among its molecules.

--> Tightly packed: A substance can be grouped as solid if the molecular movements of the particles are negligible.

From the samples under observation by Juan and kym, if the sample that possesses the above described qualities, it is a solid rather than liquid or gas.

Answer:

Cp = 397 [J/kg*K]

Explanation:

By means of the energy equation for heat transfer in substances and objects, we can calculate the specific heat. In this way, we have the following equation.

[tex]Q=m*C_{p}*DT[/tex]

where:

Dt = temperature change = 10 [K]

m = mass = 0.5 [kg]

Q = heat = 1985 [J]

Cp = specific heat [J/kg*K]

Now replacing:

[tex]1985=0.5*C_{p}*10\\C_{p}=\frac{1985}{0.5*10}\\C_{p}=397[\frac{J}{kg*K} ][/tex]

Answer:

Explanation:

They require a medium.

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Answer:

- They require a medium

Explanation:

Sound waves are, by definition, waves of vibrating matter. You need a medium like a solid, liquid or gas to transmit sound waves. A vacuum is space without matter, and so sound cannot be transmitted through it. Outer space is, for the most part, a vacuum, so that line from Alien rings pretty true:

"In space, no one can hear you scream."

Answer:

A. At warm tempetures, molecules move around more.

Explanation:

I'm at k12 and I just took the test got it right. Physical Science: Unit 2 Test

Answer:

At warm temperatures, molecules move around more.

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