The fundamental frequency of a 0.672-m-long tube, open at both ends, on a day when the speed of sound is 344 m/s is 256 Hz.
How to calculate the fundamental frequency?The fundamental frequency is the lowest frequency that any given instrument can produce. The instrument's first harmonic is another name for the fundamental frequency.
Given,
Length of the tube = 0.672-m
Speed of sound = 344 m/s
Tube open at both the ends
Solution:
Since the tube is open at both ends,
[tex]f_{n}[/tex] = n ([tex]V_{w/2L}[/tex])
n = 1, 2, 3, 4,...
[tex]f_{1}[/tex] = 1(344/2*0.672)
= 256 Hz
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Calculate the density in units of g/ml of a 4.5-g cube with an edge length of 5.5 cm.
The density of a 4.5 g cube with an edge length of 5.5 cm is 0.027 g/mL
The formulas and the procedures we will use are:
v = s³ρ = m/vWhere:
s= edge lengthv= volumeρ= densitym= massInformation about the problem:
s = 5.5 cmm= 4.5 gρ= ?v= ?Calculating the volume of the cube, we get:
v = s³
v = (5.5 cm)³
v = 166.38 cm³
Converting the volume of the cube from cm3 to mL, we get:
1 cm3 is equivalent to 1 mL, so
166.38 cm³ is equivalent to 166.38 mL
Applying the density formula, we get:
ρ = m/v
ρ = 4.5 g/166.38 mL
ρ = 0.027 g/mL
What is density?It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.
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Triangle has a base that is decreasing at a rate of 11cm/s with the height being held constant. what is the rate of change of the area of the triangle if the height is 7cm?
The rate of change of the area of the triangle if the height is 7cm is 38.5 cm/s
What is Rate of change?
A rate is anything that can be measured over time. Common rates include velocity (which is the rate of distance traveled), power (rate of work being done), etc. All these have one thing in common which is that they are all divided by the amount of time it took to obtain a certain measurement.
Let the base of the triangle be b,
the height of the triangle = h
and the area of the triangle = A
Area of a triangle, A is = bh/2
Rate of change of the area, A is :
dA/dt = d(1/2(bh))/dt = 1/2 (db/dt)h + 1/2(bdh/dt)
At constant height, dh/dt = 0
that is
dA/dt = 1/2(db/dt)h
It is given that :
db/dt = 11 cm/s
h = 7cm
dA/dt = (11x7)/2 = 38.5 cm/s
Therefore, the rate of change of the area of the triangle if the height is 7cm is 38.5 cm/s
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Find the distance traveled in 27 seconds by an object traveling at a constant velocity of 15 feet per second.
The distance d travelled by in object is 68.58 m
What is velocity ?
velocity is defined as rate of change of displacement d of the object with respect to rate of change in time t. In mathematics It is written as :
v = d/t
it should be noted that, velocity is nothing but speed in particular direction. That is velocity is vector quality having both magnitude and direction where as speed is just the magnitude of velocity.
1 feet = 0.3048 m
15 feet = 4.572 m
Now, calculating the distance d travelled by in object :
d = vt
d = 4.572 x 27
d = 68.58 m
Therefore, the distance d travelled by in object is 68.58 m
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If the mirror is immersed in water (refractive index 1.33), what is its focal length?1`
The refractive index of the mirror immersed in the water is 1.33. There is no change in its focal length. The focal length of mirrors will not depend on the external medium in which the mirror is immersed.
What is focal length?Focal length is defined as the distance of the pole of the mirror from the point on the axis of the mirror at which the beams, parallel to the principle axis, show up to merge. In other words, the distance between the pole of the mirror and the centre point is called the focal length
A concave mirror converges all the rays of light falling on this, so it is called converging mirror
A convex mirror diverges all the rays of light falling on this, so it is called diverging mirror
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If you place a 4.00 g effervescent antacid pill into 110 ml (110 g ) of water in a 105 g glass, how much will the glass of water weigh once the antacid pill has dissolved?
The glass of water weigh once the antacid pill has dissolved will be less than the 219 grams due to evolution of carbon dioxide.
Evaluating :Mass of effervescent antacid pill = 4.00 g
Mass of water = 110 g
Mass of glass = 105 g
Total mass of the substances together : 4.00 g + 110 g + 105 g = 219 g
Effervescent antacid pill , moment it will get dissolved in water carbon dioxide gas is evolves and hide from the solutions.
This states that mass of the weight of the glass of water with antacid dissolved in it will be less than 219 grams.
What happens once you put antacid tablets in water?
Effervescent antacid tablets are made up of aspirin, acid and sodium bicarbonate. When bicarbonate of soda dissolves in water, it reacts with hydrogen ions from the acid and forms carbon dioxide. Because CO₂ is a gas, it forms bubbles inside the water that you simply can see as foam on the surface
Is antacid an acid or base?Antacids are weak bases that act by neutralizing gastric acid . Raising the pH of the stomach contents leads to suppression of the action of pepsin that exacerbates ulceration due to acid.
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A jumpy squirrel is trying to cross the street. Its velocity vvv as a function of time ttt is given in the graph below where rightwards is the positive velocity direction.
A set of black coordinate axes are given with the vertical axis labeled "v (m/s)" and the horizontal axes labeled "t (s)". A curve that relates v to t is shown in blue. It begins with a straight line of endpoints (0,0) and (1,5). This first line is connected to a second line with endpoints (1,5) and (3,-5). This second line is then connected to a third line of endpoints (3,-5) and (6,-5).
A set of black coordinate axes are given with the vertical axis labeled "v (m/s)" and the horizontal axes labeled "t (s)". A curve that relates v to t is shown in blue. It begins with a straight line of endpoints (0,0) and (1,5). This first line is connected to a second line with endpoints (1,5) and (3,-5). This second line is then connected to a third line of endpoints (3,-5) and (6,-5).
What is the squirrel's displacement \Delta xΔxdelta, x from t=1\,\text st=1st, equals, 1, start text, s, end text to 2\,\text s2s2, start text, s, the answer is 2.5 I solved it
Answer: 2.5
Explanation: cause it is
5km straight north then 5km straight west
what is the total displacment
The total displacement of the person will be 15 km.
If a person moves 5 km towards north and then 5 km towards west, so what will be the total displacement?
If we move in a straight path means that moves towards 5 km north and then a person moves towards the 5 km west, so the total displacement of the person will be 15 km and the reason behind this is given below;
For example a car moves towards the north 5km and then directly he want to go towards the 5km west, so the total displacement will be 15 km because the car first moves towards the north so he covered 5 km and then the car directly goes towards the west 5 km, so for coming this he will again come to his initial stage and then the car will go towards the west and covers 5 km. So therefore the total displacement will be 15 km.
So we can conclude that the total displacement of the person will be 15 km.
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Calculate the height of a cliff if it takes 2. 35 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8. 00 m/s.
The height of the cliff is 8.26 m.
Time taken by a rock to reach the ground from the cliff is t.
t = 2.35 seconds
The initial velocity at which rock is thrown straight up is u.
u = 8 m/s
The gravity of the earth is g.
g = 9.8 m/s²
The height of the cliff from where is rock is thrown straight up at the initial velocity of 8 m/s is,
[tex]Height= Initial \: velocity × Time - \frac{1}{2} Gravity \: of \: the \: earth ×( Time) ^{2} [/tex]
[tex]h = 8 \times 2.35 - \frac{1}{2} \times 9.8 \times (2.35) ^{2} [/tex]
h = -8.26 m
Therefore, the height of the cliff is 8.26 m.
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For how many seconds would a force of 8.00 n have to act on a 2.00 kg mass in order to change its velocity from 2 m/s to 7 m/s?
By using uniform motion, the time taken is 1.25 seconds.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
F = 8 N
m = 2 kg
vo = 2 m/s
vt = 7 m/s
Find the acceleration by second Newton's Law
F = m.a
8 = 2 . a
a = 4 m/s²
Find the time taken
vt = vo + a . t
7 = 2 + 4t
4t = 5
t = 1.25 seconds
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How does the amount of potential energy change if a hill is taller.
What is the change in the electrical potential energy in a lightning bolt
if 35 C of charge travels to the ground from a cloud 2.0 km above the
ground in the direction of the field? Assume the electric field is uniform
and has a magnitude of 1.0 × 10° N/C.
Explanation:
Given Data,
Amount of charge transferred to the ground by the lightening bolt, q = 35 C
Amount of charge transferred to the ground by the lightening bolt, q = 35 C
Amount of charge transferred to the ground by the lightening bolt, q = 35 C Distance between the cloud and the ground, d
Amount of charge transferred to the ground by the lightening bolt, q = 35 C Distance between the cloud and the ground, d = 2.0 km = 2000 m
Amount of charge transferred to the ground by the lightening bolt, q = 35 C Distance between the cloud and the ground, d = 2.0 km = 2000 m
Amount of charge transferred to the ground by the lightening bolt, q = 35 C Distance between the cloud and the ground, d = 2.0 km = 2000 m Magnitude of electric field, E = 1.0 × 10⁶ N/C
Now, finding PE(∆U) in lightning bolt,
ΔU = -q×E×dΔU = −35
C × 1.0 × 10⁶
N/C × 2000 m
ΔU = −7.0×10¹⁰ J
Momentum describes *
O How much force is needed to change an object's motion
O How much velocity changes in a given amount of time
The tendency of an object to resist a change in motion
O The balanced forces on a falling object with a constant speed
Answer:
How much velocity changes in a given amount of time
A bicyclist accelerates at a constant rate from a standstill to 15 km/hr in 72 sec. a) how fast is the bicyclist traveling after 55 sec? b) how far has the bicyclist traveled after 72 sec?
A cyclist who accelerates steadily from a stop to 15 km/hr in 72 seconds would reach 4.167 meters per second after 55 seconds.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity.
As given in the problem a bicyclist accelerates at a constant rate from a standstill to 15 km/hr in 72 sec.
15 kilometers / hour = 15×1000 /3600
=4.167 meters / seconds
v = u + at
4.167 = 0 +a*72
a =4.167/72
a = 0.05787 meters /second²
Speed after 55 seconds = 0.05787*55
=3.18285 meters/ seconds
Distance after 72 seconds,
s = ut + 0.5at²
=0 + 0.5× 0.05787×72²
=150 meters
Thus, the bicyclist would have traveled 150 meters after 72 seconds.
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What is the symbol, atomic number, # of protons, # of electrons, atomic mass, rounded atomic mass, # of neutrons (show work), and period of: helium
The symbol of the element helium is He, its proton number is 2, its atomic mass is 4, its neutron number is 2 and finally; helium belong to period 1 of the periodic table.
However, helium is a noble gas, meaning it has a stable octet electronic configuration ( having 8 valence electrons)
According to the periodic table, helium belong group 0 of the periodic table which is the 8th group. It belongs to period 1
Chemical elementsA chemical element refers a chemical substance which cannot be split into simpler units by chemical ordinary means.
Elements in the periodic table are generally categorized as metals, nonmetals and metalloids.
In addition, an atom is the smallest part of element which can take part in a chemical reaction.
Some examples of elements are as follows including their symbols
Hydrogen, HHelium, HeLithium, LiBeryllium, BeBoron, BCarbon, CNitrogen, NOxygen, OFluorine, FNeon, NeSodium, Na Magnesium, MgAluminum, AlSilicon, SIPhosphorus, PSulphur, SChlorine, ClArgon, ArPotassium, KCalcium, CaSo therefore, the symbol of the element helium is He, its proton number is 2, its atomic mass is 4, its neutron number is 2 and finally; helium belong to period 1 of the periodic table.
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When the pilot reverses the propeller in a boat moving north, the boat moves with an acceleration directed south. Assume the acceleration of the boat remains constant in magnitude and direction. What happens to the boat?.
When the pilot reverses the propeller in a boat moving north, the boat moves with an acceleration directed south. Assume the acceleration of the boat remains constant in magnitude and direction. The boat will eventually stops and then speeds up in the reverse direction.
As the pilot reverses the propeller in a boat moving north, the boat moves with an acceleration directed south. This is because the propeller is pushing against the water in the opposite direction to the boat's motion. The acceleration of the boat remains constant in magnitude and direction until the boat reaches its maximum speed in the reverse direction. At this point, the boat will eventually stop and then speed up in the reverse direction.
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A cart of mass 20kg is sitting on the floor, you push it and it has an acceleration of 3 m/s2, how much force did you apply to it?
Answer:
60N
Explanation:
Fnet=m.a
Fnet=(20)(3)
Fnet=60N
Acceleration due to gravity on Mars is -3.7 m/s2. If you throw a Martian rock upwards with a velocity of 21.1 m/s, how long will it take to land back in your hand, at the same height from which it was thrown?
Answer:
5.7 seconds
Explanation:
1. We know that :
acceleration = change in velocity / time
2. We have been given the following :
acceleration = - 3.7 m/s^2
initial velocity = 21.1 m/s
final velocity = 0 (at the rock's max greatest height its velocity is 0)
time = ?
3. Subsitute the values + rearrange for t :
-3.7 = 0 - 21.1/t
t = 0-21.1/-3.7
t = -21.1/-3.7
t = 5.7 seconds (1.d.p)
Indicate how many of each type of molecular orbital exist in acetone. for each type of molecular orbital, enter an integer (0, 1, 2, etc.) with no decimal places.
There are 10 bonding orbitals
10 antibonding orbitals
2 nonbonding orbitals
Each of the lone pairs on the oxygen is contained in a nonbonding molecular orbital.
What kinds of molecular orbitals does acetone contain?In acetone, there are ten antibonding orbitals.
What percentage of molecular orbitals have a N value of two?
The two 2s orbitals and all three 2p orbitals are the atomic orbitals with a n value of 2.
Eight molecular orbitals, of which half are bonding and the other half are antibonding, are created when these four orbitals from one atom interact with these four orbitals from another atom.
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A blimp is approximated by a prolate spheroid 90 m long and 30 m in diameter. estimate the weight of gas within the blimp for (a) helium at 1.1 atm and (b) air at 1.0 atm.'
(a) Let's start by calculating the helium's weight. We'll apply the well-known weight equation:
W helium =m helium ⋅g
where m helium is the mass of the helium and g is the gravity.
=>W helium =ρ helium ⋅V⋅g
putting the values we get
ρ helium =0.183 kg/ m^3
Therefore, W helilum =76.2 kN
(b) The weight of the air will also be determined in the same manner:
W air =ρ air ⋅V⋅g
=> ρ air =1.205 kg/ m^3
Therefore after substituting the values we get,
W air = 501.35 kN
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n order to maintain good sleep hygiene, it is best to reserve your bed for sleeping and to engage in all other activities in other parts of your house.
You start from rest and ski down a hill with an acceleration of 2 m/sec2. Find your speed
at the following times:
a. 2 seconds
b. 10 seconds
a. Your speed after 2 seconds is 4 m/s.
b. your speed after 10 seconds is 20 m/s.
a. How to find your speed after 2 secondsTo find the speed after 2 seconds, we use the equation of motion v = u + at where
v = speed after 2 seconds, u = initial speed, a = acceleration and t = timeGiven that You start from rest and ski down a hill with an acceleration of 2 m/sec².
u = 0 m/s (since you start from rest)a = 2 m/s² andt = 2 sSo, substituting the values of the variables into the equation for the speed, v, we have
v = u + at
v = 0 m/s + 2 m/s² × 2 s
v = 0 m/s + 4 m/s
v = 4 m/s
So, your speed after 2 seconds is 4 m/s.
b. How to find your speed after 10 secondsTo find the speed after 10 seconds, we use the equation of motion v = u + at where
v = speed after 10 seconds, u = initial speed, a = acceleration and t = timeGiven that You start from rest and ski down a hill with an acceleration of 2 m/sec².
u = 0 m/s (since you start from rest)a = 2 m/s² andt = 10 sSo, substituting the values of the variables into the equation for the speed, v, we have
v = u + at
v = 0 m/s + 2 m/s² × 10 s
v = 0 m/s + 20 m/s
v = 20 m/s
So, your speed after 10 seconds is 20 m/s.
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The shaded region in the diagram below is a region of uniform electric field that is parallel to the horizontal direction (x-axis). A charge
Q = −4.9 µC
moves through this region as shown by the green arrow.
(b) The work done by the electric field as the charge moves from location A to location B is +2.30 10-3 J. What is the potential difference
VB − VA?
(A) The direction of electric field in given region is to the left.
(B) The potential difference is -0.46×[tex]10^{3}[/tex].
(A) When charge is present in any form, a point in space has an electric field that is connected to it. The value of E, often known as the electric field strength, electric field intensity, expresses the strength and direction of the electric field.
Therefore, the direction of electric field in given region is to the left.
(B) The amount of work required to move a unit charge from one point to another point is equal to the potential difference between two points in an electric circuit.
[tex]V_{B} -V_{A}[/tex] = W / Q
[tex]V_{B} -V_{A}[/tex] = 2.30×[tex]10^{-3}[/tex] / -4.9×[tex]10^{-6}[/tex]
[tex]V_{B} -V_{A}[/tex] = -0.46×[tex]10^{3}[/tex]
Therefore, the potential difference is -0.46×[tex]10^{3}[/tex].
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A bicycle has a constant velocity of 10 m/s. a person starts from rest and runs to catch up to the bicycle in 30 s. what is the acceleration of the person?
The person running from rest that catch up the bicycle in 30 s has an acceleration of: 0.66 m/s²
The formulas and procedures we will use to solve this exercise are:
v = x/ta = 2 * [x - (vi * t)] / t²Where:
v= velocityx = distancet = timevi = initial velocitya = accelerationInformation about the problem:
v(bicycle)= 10 m/sx(bicycle) =? t = 30 svi(person)= 0 m/sa(person)=?Applying the velocity formula and clearing the distance we have:
v = x/t
x = v * t
x(bicycle) = 10 m/s * 30 s
x(bicycle) = 300 m
With the distance the bicycle has traveled in 30 s we can calculate the person's acceleration
Applying the acceleration formula we have:
a = 2 * [x - (vi * t)] / t²
a = 2 * [300 m - (0 m/s * 30 s)] / (30 s)²
a = 2 * [300 m - (0 m)] / 900 s²
a = 600 m - 0 m / 900 s²
a = 600 m / 900 s²
a = 0.66 m/s²
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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What is the km of the enzyme for the substrate a? b) what is the value of v0 when [a] = 43?
The km of the enzyme for the substrate a is determined as 5000mM, and the value of V0 would be calculated as 0.682nM/minute as per the calculations done.
Why are Km values high or low?The relationship between KM and the enzyme’s affinity for its substrate is inverse.
Low enzyme substrate affinity is correlated with high levels of KM (it takes more substrate to get to Vmax). An enzyme with a low KM value has a strong substrate affinity.
What is Vmax, and why is it important?Vmax is the reaction’s maximum rate at the specified enzyme concentration.
The reaction’s speed increases when the concentration of the substrate rises, but after a while, when the enzyme becomes saturated with the substrate, the reaction speed does not continue to rise.
CalculationAs seen after 10000mM concentration of substrate velocity of enzyme becomes constant attain maximum velocity i.e., Vmax
Therefore, we have Km = Vmax/2
= 10000/2 = 5000mM
Then by applying the equation
V = Vmax[S/S+km]
V = 80[43/43+5000]
= 0.682nM/minute
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A force of 200.0 n is exerted on a 1,000 n object. the object moves a distance of 30.0 m. how much work was done on the car?
When a force of 200.0 n is exerted on a 1,000 n object. The object moves a distance of 30.0 m. 24,000J work was done on the car.
Work=Force × Distance is a formula that describes the relationship between work, force, and distance. While distance is expressed in meters, force is expressed in Newtons (N). The result is Joule.
So, total force is 1000-200 = 800N
Work=Force × Distance
Work=800 × 30
Work=24,000J
So, when a force of 200.0 n is exerted on a 1,000 n object. The object moves a distance of 30.0 m. 24,000J work was done on the car.
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What happens to the pressure of an ideal gas inside a container if the temperature increases from 25 oc to 100 oc but the volume and amount of gas remains constant? (0 oc = 273 k).
By ideal gas approximation, the pressure will rise until 1.25 times greater than the initial pressure.
We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation
P . V = n . R . T
where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.
From the question above, we know that
T1 = 25 ⁰C = 298 K
T2 = 100 ⁰C = 373 K
Assume that P1 = P
When the initial and final temperature is the same, we can use the ratio of pressure and temperature as
P1 / T1 = P2 / T2
P / 298 = P2 / 373
P2 = 1.25 P
Hence, the pressure will rise until 1.25 times greater than the initial pressure.
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how do you know if you have a base unit
Answer:
Доброе утро, ответ 5+5="4
Explanation:
The area of each plate of an air filled parallel plate capacitor is 0.8 m2 , and the spacing between the plates is 1.1e-006 m. what is its capacitance?
The capacitance of capacitor is 6.44 μF.
We need to know about the capacitance of the air-filled capacitor to solve this problem. The capacitance of the air-filled capacitor depends on the charge and voltage. It can be written as
C = Q/V
where C is capacitance, Q is charge and V is voltage.
Capacitance also can be calculated by the area and distance between the capacitor plate
C = εo . A / d
where εo is vacuum permittivity (8.85 x 10¯¹² F/m), A is the area of the plate and d is distance.
From the question above, we know that
A = 0.8 m²
d = 1.1 x 10¯⁶ m
By substituting the given parameters, we can calculate the capacitance
C = εo . A / d
C = 8.85 x 10¯¹² . 0.8 / 1.1 x 10¯⁶
C = 6.44 x 10¯⁶ F
C = 6.44 μF
Hence, the capacitance of capacitor is 6.44 μF.
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An atom emitted green color during flame test which is about 550 nm. what is the frequency of this light? .545 x10-15/s 3.5 x 10-8/s 5.5x 10-7/s 5.45x 1014/s
During the flame test, an atom emitting a green color with a wavelength of roughly 550 nm would have a frequency of 5.45 1014 Hertz.
What is wavelength?It may be explained in terms of the separation between any two identical succeeding locations on a wave, such as how the wavelength can be determined by calculating the separation between any two successive crests.
Speed of light = frequency of the green light ×wavelength of the light
3×10⁸ = 550×10⁻⁹ × frequency
frequency = 3×10⁸ / 550×10⁻⁹
= 5.45 ×10¹⁴ Hertz
Thus, the correct answer is option D.
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Psychologists only focus on how people think and feel.
Truth or false
