What is the greatest common factor of 3 and 33?

Answer: Start off and multiply 12x30=360

Step-by-step explanation: He will recieve 360$

Answer:

9

Step-by-step explanation:

For each pizza variety, Daniel can choose 18 different toppings. Therefore, for 23 pizza varieties, Daniel can choose from 23 * 18 = 414 different combinations of varieties and toppings.

For each pizza size, Daniel can choose from 414 different combinations of varieties and toppings. Therefore, for n pizza sizes, Daniel can choose from n * 414 = 3726 combinations

414n = 3726

divide both sides by 414 to isolate the n

n = 9

The function of the polynomial is (b) [tex]f(x) = (x + 2) ^ 2 * (x - 3) * (x + 1)[/tex]

From the graph, we have the following highlights

The above highlights mean that:

So, the function of the polynomial is:

[tex]f(x) =a(x + 2)^2(x + 1)(x - 3)[/tex]

Assume a = 1.

So, we have:

[tex]f(x) =1(x + 2)^2(x + 1)(x - 3)[/tex]

Multiply

[tex]f(x) =(x + 2)^2(x + 1)(x - 3)[/tex]

Hence, the function of the polynomial is (b) [tex]f(x) = (x + 2) ^ 2 * (x - 3) * (x + 1)[/tex]

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Answer:

Hey will you marry me? serious question

Answer:y=16

Step-by-step explanation:

Of 103 people that are considered to use two facilities, only 14 use all three. In this case, we must make a percentage of this information.

This is roughly 14.5%, meaning there is only a 14.5% chance someone will use all three facilities if they are known to use two.

The probability that a randomly selected person uses at least two facilities is 103/135 and the probability that the selected people uses all the three facilities is 14/103.

Probability is the likeliness of an event to happen, it has a range from 0 to 1.

The number of people using the facilities are

73 people use the gym.

73 people use the swimming pool.

67 people use the track.

36 people use the gym and the pool.

35 people use the pool and the track.

32 people use the gym and the track.

14 people use all three facilities.

The total people using two facilities is = (36+32+35 ) = 103

Total number of people is 135

The probability that a randomly selected person uses at least two facilities is 103/135.

The probability that the selected people uses all the three facilities is 14/103.

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Answer:

4:1

Step-by-step explanation:

Answer:

edge of cube = 20 cm

volume of cube = 20x20x20

volume of each small cube = 5x5x5

number of cubes

= (20x20x20)/(5x5x5)

=64

Step-by-step explanation:

I believe that is the answer im sorry in advanced if its not.

Answer:

A.) 4/5

Step-by-step explanation:

Another fraction that's not on there that is correct is 8/10

Hope you could get an idea from here.

Doubt clarification - use comment section

Answer:

3/5

Step-by-step explanation:

From the computation done, the linear equation that represents the information given will be A. y = -2x + 30.

From the information given, we're told that Yuson must complete 30 hours of community service and that she does 2 hours each day.

Therefore, the linear equation that represents the hours Yuson has left after x days will be represented thus:

y = 30 - (2 × x)

y = 30 - 2x

y = -2x + 30

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[tex]\large\mathcal\red{Answer✓}[/tex]

Ans :- E...

I'm gonna go with answer choice B

Answer:

A. x = 4

B. RQ = 6

C. 48 square units

Step-by-step explanation:

A. 3x - 2 = 10

3x = 12

x = 12/3

B. a^2 + b^2 = c^2

8^2 + b^2 = 10^2

64 + b^2 = 100

b = sqrt (100 - 64

b = 6

C. Area of a triangle = (b*h)/2

b = (2)(6) = 12

Area = (12 * 8)/2 = 48 square units

384 +37289 x 638203

then you will get the calculation

Answer:

its option c i believe

Answer:

282.6 cm

Hope it helps:)

Answer: 36.4 seconds

(Unitary method)

5 meters take 2 seconds

1 meter takes 2/5 seconds

91 meter takes 2/5 * 91 --> 36.4 seconds

The time taken by Andre to run 91 meters is 36.5 seconds.

Speed is the rate at which an object's position changes, measured in meters per second. For example, if an object starts at the origin, and then moves three meters in three seconds, its speed is one meter per second. The equation for speed is simple: distance divided by time

Given here: Distance travelled by Andre=5 meters in time t=2seconds

Thus Andre's speed = 5/2

                                  =2.5 m/sec

Thus time taken to run 91 m is = 91/2.5

                                                  =36.5 seconds

Hence, The time taken by Andre to run 91 meters is 36.5 seconds.

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Answer:

Step-by-step explanation:

9h + 24 = 60

Answer:

look it up i need my coins

Step-by-step explanation:

Answer: C

Step-by-step explanation: The range of a function is all the outputs, or in this case all the values on the right side of the function. Therefore, we just look at what numbers are there and we find the range

Answer:

Step-by-step explanation:

A( - 1 , - 3 ) ------> A' ( - 2 , - 1 )

B( 4 , - 3 ) ------> B' ( 8 , - 1 )

C( 4 , 3 ) ------> C' ( 8 , 1 )

D ( - 1 , 3 ) ------> D' ( - 2 , 1 )

Answer:

I dont know your answer

Step-by-step explanation:

Because i dont

The multiplication property of equality states that if [tex]x=y[/tex] is true, then [tex]xz=yz[/tex] must also be true.

The property of equality illustrated by the statement "if x = y, then -2x = -2y" is the: Multiplication Property of Equality.

The properties of equality describe the relation between the two sides of an equation and state that the two sides remain equal even after applying the same arithmetic operation on each side.

The property of equality illustrated by the statement "if x = y, then -2x = -2y" is the Multiplication Property of Equality.

This property states that if you multiply both sides of an equation by the same nonzero number, the equality still holds true.

In this question, both sides of the equation are multiplied by -2, maintaining the equality between the expressions.

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Answer:

Step-by-step explanation:

the answer is 5.76$ , 20% is -1.44$

Answer:

[tex]f(x)\div g(x)=x-10[/tex]

Step-by-step explanation:

[tex]\frac{x^2-19x+90}{x-9}[/tex]

[tex]\frac{(x-10)(x-9)}{x-9}[/tex]

[tex]x-10[/tex]

Answer:

[tex]f(x)\div g(x)=-10[/tex]

Step-by-step explanation:

Solve [tex]f(x)[/tex]

[tex]f(x)=x^2-19x+90[/tex]

[tex]x^2-19x+90[/tex]

[tex]\mathrm{Break\:the\:expression\:into\:groups}[/tex]

[tex]\left(x^2-9x\right)+\left(-10x+90\right)[/tex]

[tex]\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-9x[/tex]

[tex]=x(x-9)[/tex]

[tex]\mathrm{Factor\:out\:-10\;from}\:\:-10x+90[/tex]

[tex]=-10(x-9)[/tex]

[tex]=x\left(x-9\right)-10\left(x-9\right)[/tex]

[tex]\mathrm{Factor\:out\:common\:term\:}x-9[/tex]

[tex]\bold{\left(x-9\right)\left(x-10\right)}[/tex]

Solve [tex]g(x)[/tex]

[tex]g(x)=x-9[/tex]

[tex]\bold{x-9}[/tex]

[tex](x-9\right)\left(x-10)}\div \:x-9[/tex]

Now, solve:

[tex](x-9\right)\left(x-10)}\div \:x-9[/tex]

[tex]=\frac{(x-9)\left(x-10)}{:x-9}[/tex]

[tex]= -10[/tex]

Therefore, [tex]f(x)\div g(x)=-10[/tex]

Answer:

y is the height and x is the length

Step-by-step explanation:

Remember when you're doing y and x axis y is height and x is length it works like coordinates.

Answer:

6 and -4

Step-by-step explanation:

a + b = 2

a - b = 10

Solve:

from the first eq.

a = 2 - b

replacing this value in the second eq.

(2-b) - b = 10

2 - 2b = 10

-2b = 10 - 2

-2b = 8

b = 8/-2

b = -4

from the second eq.

a - b = 10

a - (-4) = 10

a  + 4 = 10

a = 10 - 4

a = 6

Check:

from the first eq.

6 + (-4) = 2

6 - 4 = 2

Answer:

  x = {-2 5/6, +2}

Step-by-step explanation:

To use the quadratic formula, it is helpful to write the equation in standard form.

  (2x +1)(3x +1) = 35

  6x^2 +5x -34 = 0 . . . . . . . subtract 35 and simplify. a=6, b=5, c=-34

The quadratic formula tells you the values of x are ...

  [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-5\pm\sqrt{5^2-4(6)(-34)}}{2(6)}\\\\=\dfrac{-5\pm\sqrt{841}}{12}=\dfrac{-5\pm29}{12}\\\\\boxed{x=\left\{-\dfrac{17}{6},2\right\}}[/tex]

Answer: The equation is not an identity

==========================================================

Explanation:

We'll expand out the right hand side to see if we can simplify it to the left hand side. The stuff on the left will stay the same for each step.

I'll use  c = a+b as a way to help distribute.

[tex]a^4 + b^4 = (a+b)(a^3 - a^2b-ab^2 + b^3)\\\\a^4 + b^4 = c(a^3 - a^2b-ab^2 + b^3)\\\\a^4 + b^4 = a^3c - a^2bc-ab^2c + b^3c\\\\a^4 + b^4 = a^3(c) - a^2b(c)-ab^2(c) + b^3(c)\\\\a^4 + b^4 = a^3(a+b) - a^2b(a+b)-ab^2(a+b) + b^3(a+b)\\\\a^4 + b^4 = a^4+a^3b - a^3b-a^2b^2-a^2b^2-ab^3 + ab^3+b^4\\\\a^4 + b^4 = a^4+(a^3b - a^3b)+(-a^2b^2-a^2b^2)+(-ab^3 + ab^3)+b^4\\\\a^4 + b^4 = a^4-2a^2b^2+b^4\\\\[/tex]

Unfortunately, we can't go any further. We have a^4 and b^4 on the right hand side, but we also have the term -2a^2b^2 that didn't cancel out. Therefore, the original equation is not an identity.

----------------

Here's another way you can see that we don't have an identity.

Let's say we fixed 'a' to be equal to 1.

That means the equation

[tex]a^4 + b^4 = (a+b)(a^3 - a^2b-ab^2 + b^3)[/tex]

would turn into

[tex]1^4 + b^4 = (1+b)(1^3 - 1^2b-1b^2 + b^3)[/tex]

and simplify to

[tex]1 + b^4 = (1+b)(1 - b-b^2 + b^3)[/tex]

Now replace b with x and you'll have the two equations to represent the left and right hand sides

[tex]y = 1+x^4\\y = (1+x)(1-x-x^2+x^3)[/tex]

which you can graph on the same xy axis. You should note that the two equations produce different curves. The curves would need to be identical if we wanted an identity to happen.

Side note: you can pick other values for 'a' instead of just 1.