What is the horizontal acceleration of a ball that is launched horizontally with a velocity of 5. 6 m/s? â€""9. 8 m/s2 0 m/s2 5. 6 m/s2 9. 8 m/s2.

Answers

Answer 1

The horizontal acceleration of a ball that is launched horizontally is equal to: B. 0 [tex]m/s^2[/tex]

Given the following data:

Horizontal velocity = 5.6 m/s

To determine the horizontal acceleration of a ball that is launched horizontally:

Acceleration can be defined as the rate of change of velocity with respect to time. In Physics, the acceleration of an object or body is calculated by subtracting its initial velocity from the final velocity and dividing by the time.

Mathematically, acceleration is given by the formula;

[tex]Acceleration = \frac{V\; -\;U}{t}[/tex]

The projectile motion of an object launched horizontally has a constant velocity and as such its horizontal acceleration would be equal to zero meter per seconds square ([tex]0\;m/s^2[/tex]).

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Related Questions

answer question 7 please

Answers

If the only answers are kinetic and potential, then blank 1: potential, blank 2: kinetic

Find the displacement in the time interval 3 seconds to 4 seconds
A. 1m
B.3m
C.7m
D.9m

Answers

Answer:

B. 3m

Explanation:

Took the quiz.

Hope this helps!!

given. force of 88N and an acceleration of 4 m/s 2 what is the mass?

Answers

Mass, m=22 kg
It is given that Force, F = 88N
Acceleration, a=4 m/s 2

A 2 kg mass starts from rest and slides down an inclined plane 4 m long in 1 second. What net force is acting on the mass along the incline *.

Answers

The net force acting on the mass along the incline is equal to 16 Newton.

Given the following data:

Mass = 2 kgDistance = 4 metersTime = 1 seconds

To determine the net force acting on the mass along the incline:

First of all, we would find the acceleration of the mass by using the second equation of motion:

[tex]S = ut+ \frac{1}{2} at^2\\\\4 = 0(1) + \frac{1}{2} a(1)^2\\\\4=\frac{a}{2}\\\\a=2\times 4[/tex]

Acceleration, a = 8 [tex]m/s^2[/tex]

For the net force, we would apply Newton's Second Law of Motion:

[tex]F_{net} = mass \times acceleration\\\\F_{net} =2 \times 8[/tex]

Net force = 16 Newton.

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The product of pressure and volume of any gas equals a constant, k. What variable(s) must not change in order for the value of k to remain constant

Answers

The variable is temperature

Describe the steps in solving the problem below.
A red cart of mass 4 kg slides to the right on a frictionless track with a velocity of +4 m/s. It collides with the stationary blue cart of mass 1 kg. After the collision, the blue cart has a velocity of +8 m/s. Calculate the velocity of the red cart after the collision. ;)


Answers

The velocity of the red cart after the collision is 2 m/s

From the law of conservation of momentum, initial momentum of system = final momentum of system.

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.

Substituting the values of the variables into the equation, we have,

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄

4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s

16 kgm/s + 0 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s - 8 kgm/s =  (4 kg)v₃

(4 kg)v₃ = 8 kgm/s

Divide both sides by 4 kg, we have

v₃ = 8 kgm/s ÷ 4 kg

v₃ = 2 m/s

The velocity of the red cart after the collision is 2 m/s.

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A 30 kg boy stands on rough horizontal ground. The coefficient of
static friction,
us is 0.8. The present static friction between the boy and the ground is
?

Answers

Answer:

0n

Explanation:

A transformer is being built to triple the voltage produced. Which data are collected to investigate whether the transformer can achieve the goal? (1 point)

A) the ratio of the number of turns in the primary and secondary coils

B) only the number of turns in the secondary coil and the magnetic field of the core

C) only the number of turns in the primary coil and the magnetic field of the core

D) the ratio of the number of turns in the primary and secondary coils and the magnetic field of the core

Answers

Answer:

the ratio of the number of turns in the primary and secondary coils.

Explanation:

hope i'm not too late!!

How to use bernoulli's equation.

Answers

Answer:

Answer is below ….

Explanation:

The Bernoulli equation is a crucial statement that connects a fluid's pressure, height, and velocity at a single point in its flow. In an idealised system, the connection between these fluid conditions along a streamline always equals the same constant along that streamline.

Water from a reservoir runs through enormous tubes called penstocks before reaching a turbine at the end of a hydroelectric dam. The gravitational potential energy drops as the water flows down the pipe according to Bernoulli's equation, yet in many configurations, the water departs at the same speed.

Bernoulli's equation is a more broad and mathematical version of Bernoulli's principle that includes variations in gravitational potential energy. We'll derive this equation in the following part, but first, let's look at Bernoulli's equation to get a sense of what it says and how one may use it.

________________________________________________________

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4) An 873kg dragster, starting from rest, attains a speed of 26.3m/s in 0.590s.
A) What was the acceleration of the dragster?
B) What was the net force needed to accelerate the dragster?
C) Assume that the driver has a mass of 68.0kg. What horizontal force does the seat exert on
him?

Answers

Answer:

A.)a=44.57m/s

B.)f=38,909.61

C.)f=666.4

Explanation:

A.) A=v/t 26.3/0.590=44.57

B.) 873kg x 44.57= 38,909.61

C.) 68kg x 9.8=666.4

A potted plant falls from the window of an apartment building. It falls for 2.0 s and then hits the ground. What is the speed of the plant just before it hits the
ground? Assume only gravity is acting on it.
A) 20m/s
B)9.8m/s
C)2.0m/s
D)4.9m/s

Answers

Answer:

D) 4.9 m/s

Explanation:

Speed of Object in Free Fall

s = Rate of Acceleration, Due to Gravity × Length of Time

s = 9.8 × 2.0

s = m/s (Round Up to The Nearest Whole Number)

--

m/s = 9.8 ÷ 2.0 = 4.9 m/s

Dark matter is inferred to exist because Select one: a. we can observe its gravitational influence on visible matter. b. it explains how the expansion of the universe is accelerating. c. we see lots of dark patches in the sky. Clear my choice

Answers

Answer:

(a)   the gravitational influence on visible matter can not be explained by matter that can be seen.

A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.

Answers

The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].

The given parameters;

initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃Pi

The initial and final momentum of the ball is calculated as;

[tex]P_i = m_ivi[/tex]

[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]

The initial and final kinetic energy of the ball is calculated as;

[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]

The change in the kinetic energy is calculated as;

[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]

Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].

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Lina applies a constant force of 30 N as she pushes a dresser 3 m. How much work did Lina do on the dresser?​

Answers

Answer:

The answer will be 90

Explanation:

30N×3m= 90

What are the variables that affect the force of gravity between objects?

Answers

The answer is to say I don’t have to say it was wrong

¿Cuál es la densidad de un metal si una muestra tiene una masa de 63.5 g cuando se mide en el aire y una masa aparente de 55.4 g cuando está sumergida en agua?. Considere la densidad del agua como 1000 kg/m3.

Answers

La densidad del metal como se requiere en la pregunta es 7.8 * 10 ^ 3 Kg / m ^ 3.

Sabemos que ese empuje hacia arriba = peso en aire - peso en líquido

Peso en el aire = 63,5 * 10 ^ -3 Kg * 10 m / s ^ 2 = 0,635 N

Peso en líquido = 55,4 * 10 ^ -3 Kg * 10m / s ^ 2 = 0,554 N

Empuje hacia arriba = 0,635 N - 0,554 N = 0,081 N

Pero ;

Empuje hacia arriba = Volumen * densidad del fluido * aceleración debido a la gratitud

volumen = empuje hacia arriba / densidad del fluido * aceleración debido a la gratitud

volumen = 0.081 N / 1000 * 10

Volumen = 8.1 * 10 ^ -6 m ^ 3

Densidad = masa / volumen

Densidad = 63,5 * 10 ^ -3 Kg / 8,1 * 10 ^ -6 m ^ 3

= 7,8 * 10 ^ 3 kg / m ^ 3

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Complete the following sentence. Pressure in a liquid depends on the __________ of the liquid.

Answers

Answer:

density

Explanation:

because it is directly proportional

Pressure in a liquid depends on the density of the liquid.

What is density?

Density is defined as the mass per unit volume. It is an important parameter to understand the fluid and its properties. Its unit is kg/m³.

The pressure in the liquid is;

P = ρgh

Where,

h is the height

ρ is the density

g is the acceleration due to gravity

The density of a liquid determines its pressure.

Hence, density is the correct answer.

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What hazardous wastes are common in ordinary households? What can you do to reduce the impact you make on the environment from the use of hazardous wastes?

Answers

Answer:

The most common products include aerosols, anti-freeze, asbestos, fertilizers, motor oil, paint supplies, photo chemicals, poisons, and solvents, cleaning supplies.

Explanation:

Use homemade cleaners

You can find local retailers to take rechargeable batteries from laptop computers, cordless power tools, cellular and cordless phones, and camcorders at the Rechargeable Battery Recycling Corporation’s website

Which of toby's answers is a correct description of what happens when a 1-kg cart traveling at 1 m/s collides inelastically with another 1-kg cart at rest?.

Answers

Answer:

hi I don't know sorry sorry forgive me

Explanation:

sorry

what kind of frog species is this

Answers

Answer: i think its a bullfrog forgive me if im wrong i dont exactly know

Explanation:

Answer:

that is an African bullfrog

3. Would prudent to do an observatory M 82 for this class?​

Answers

Answer: Yes,

If you need any other thing let me know, I'll still be on

Explanation:

explain properties and importance of light and how it separates into colours

Answers

Answer:

White light can be separated into different colors using a special lens called a prism. As visible light passes from air into the glass, the change in medium causes a change in direction and speed. Refraction causing the separation of white light into its various color wavelengths is called dispersion.

hope this helps

How much work is needed to stop a 1,110 kg car that is moving straight down the
highway at 59.0 km/h?

Answers

Answer:

382.74 kJ.

Explanation:

The work that must be done to stop an 1100 kg car travelling at 59  km/h is  - 382.74 kJ.

The work needed to stop an 1100 kilograms car moving with a velocity of  59.0 km/hr would be  147.72 kilojoules.

What is work done?

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

Work Done = Force * Displacement

As given in the problem we have to find out how much work is needed to stop a 1,110-kilogram car that is moving straight down the highway at 59.0 kilometers/hour

the mass of the car = 1100 kilograms

the velocity of the car = 59 kilometers/hour

KE = 0.5mv²

     =0.5×1100×(59×1000/3600)²

     = 147.72 kilojoules

Thus, the work needed to stop an 1100 kilograms car would be  147.72 kilojoules

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3. A mouse crawls 9 meters left in a tube, pauses and then crawls back 5 meters before
stopping. The entire trip took a total of 7 seconds.
a. What is the average speed of the mouse over these 7 seconds?
b. What is the average velocity of the mouse over these 7 seconds?
c. What was the instantaneous velocity of the mouse when it turned around?

Answers

Answer:

A

Explanation:

If it is loooking for a proper question, it wants to know how fast the mouse was going

Answer: The answer for this is A.

Explanation: I know this cause i'm smart and totally didn't copy the other guy just to get points

Which of the following statements about lipids and carbohydrates is true?

Answers

Answer : Lipids and carbohydrates are both made from carbon, hydrogen, and oxygen, but lipids have less oxygen (Option B)

Carbohydrates are biomolecules composed of carbon (C), hydrogen (H), and oxygen (O) in a 1:2:1 ratio, respectively.

Carbohydrates can be divided regarding the number of monomers in the biomolecule into monosaccharides, disaccharides, and polysaccharides.

Explanation:

hope this answer will helps you !

If you double the pressure of a constant amount of gas at a constant temperature, what happens to the volume

Answers

Answer: if you double the pressure, you will halve the volume. If you increase the pressure 10 times, the volume will decrease 10 times.

Explanation:

Two electrons are separated by one cm. What is the ratio of the electric force to the gravitational force between them? (me = 9. 11 ´ 10-31 kg, ke = 8. 99 ´ 109 N×m2 /C2 , G = 6. 67 ´ 10-11 N×m2 /kg2 , and e = 1. 6 ´ 10-19 C) a. 2. 3 ´ 102 b. 1. 3 ´ 1020 c. 3. 1 ´ 1022 d. 4. 2 ´ 1042.

Answers

The ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].

The given parameters;

Mass of the electron, [tex]m_e[/tex]= 9.11 x 10⁻¹¹ kgCoulomb's constant, k = 8.99 x 10⁹ Nm²/C²Gravitational constant, G = 6.67 x 10⁻¹¹ Nm²/kg²Charge of electron, q = 1.6 x 10⁻¹⁹ CDistance between the two electrons, r = 1 cm

The electrostatic force between the two electrons is calculated as follows;

[tex]F_c = \frac{kq^2}{r^2} \\\\[/tex]

The gravitational force between the two electrons is calculated as follows;

[tex]F_g = \frac{Gm_e^2}{r^2}[/tex]

The ratio of the electric force to the gravitational force between the two electrons is calculated as follows;

[tex]\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{1}{\frac{Gm^2}{r^2} } \\\\\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{r^2}{Gm^2} \\\\\frac{F_c}{F_g} = \frac{kq^2}{Gm^2}\\\\[/tex]

[tex]\frac{F_c}{F_g} = \frac{(8.99 \times 10^9) \times (1.6 \times 10^{-19}))^2}{(6.67 \times 10^{-11} ) \times (9.11 \times 10^{-31})^2} \\\\\frac{F_c}{F_g} = 4.2 \times 10^{42}[/tex]

Thus, the ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].

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what is the mass of an object if it’s weight on earth is 1150N

Answers

Answer:

calculate it by using formula w=m×g

The mass of an object if its weight on earth is 1150N is 117.347 kg.

What is Weight?

The weight of an object is defined as the force that acts on the object due to gravity. Sometimes weight is defined as a vector quantity, the force of gravity acting on an object. Others define weight as a scalar quantity, the magnitude of the force of gravity.

It is gravitational force of attraction on an object which is caused by the presence of a massive second object like Earth or Moon. Weight is expressed by multiplying the mass times the acceleration due to gravity.

W=mg

Where, W= weight of the object

m= Mass of the object

g= Acceleration due to gravity i.e. [tex]9.8[/tex] [tex]m/s^2[/tex]

In above information,

W= 1150N

g= [tex]9.8[/tex] [tex]m/s^2[/tex]

Using the formula

m=W/g

m=1150/9.8

m=117.347 kg

Thus, the mass of an object if its weight on earth is 1150N is 117.347 kg.

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the first qstn plsss​

Answers

answer:

the first one  

Explanation:

i think it is this one because 4k is bigger than 2k . also it is asking which one has the lager magnitude so it is the first one

Which wave has the longest wavelength?

Answers

Answer:

A

Explanation:

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