The magnitude of the force on the calcium ion is 1.0 x 10^7 N/C * e = 1.6 x 10^-19 N.
What is magnitude?Magnitude is a measure of the size or strength of a physical quantity, such as size, brightness, or intensity. Magnitude can be measured in terms of intensity, size, brightness, or a combination of those criteria. For example, the magnitude of an earthquake is usually determined by measuring the intensity of the seismic waves that are generated by the earthquake. Magnitude is also used to measure the brightness of stars, with the brightest stars being given the highest magnitude.
The magnitude of the force on a calcium ion with charge +e is equal to the field strength multiplied by the charge of the ion. Thus, the magnitude of the force on the calcium ion is 1.0 x 10^7 N/C * e = 1.6 x 10^-19 N.
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The illumination lights in an operating room use a concave mirror to focus an image of a bright lamp onto the surgical site. One such light has a mirror with a focal length of 15.0 cm. Use ray tracing to find the position of its lamp when the patient is positioned 1.0 m from the mirror (you'll need a careful drawing to get a good answer).
The position of its lamp when the patient is positioned 1.0 m from the mirror is 17cm.
The mirror is the concave radius of curvature of mirror R = 30 cm
Distance between the mirror and the patient = 1.2 m
We need to find out the distance of lamp from the mirror.
Focal length = radius/2
Focal length= 15cm
Using formula:
[tex]1/s+1/s'=1/f[/tex]
On solving:
[tex]1/s=s'-f/fs'[/tex]
[tex]s=fs'/s'-f\\s=15*120/120-15\\s=17cm[/tex]
What is the formula for calculating focal length?
The focal length is half the radius of curvature and is as f=R2 where f is the focal length, and R is the radius of curvature.
How do you apply the thin lens equation?
To predict exactly what a lens will do, we can use the thin lens equation: (1/do) + (1/di) = 1/f. In this equation, do is the object distance or the distance of the object from the center of the lens. Di is the image distance or the distance to the image that the lens produces from the center of the lens.
Therefore, the position of its lamp is 17cm.
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If the net force applied by the truck ramp in the previous question is -300,000 N, how far along the ramp will the truck move as it stops?
The distance moved by the truck along the ramp as it stops is 72.9 m.
What is the distance moved by the truck?The distance moved by the truck before coming to stop is determined from the acceleration and initial velocity of the truck.
The acceleration of the truck is calculated by applying Newton's second law of motion as follows.
F = ma
where;
F is the net force applied by the truck rampm is the mass of the trucka is the acceleration of the trucka = F / m
a = ( -300,000 ) / ( 60,000)
a = -5 m/s²
Now, we will apply the third kinematic equation to calculated the distance moved by the truck before coming to a stop;
v² = u² + 2as
where;
v is the final velocity when the truck stopsu is the initial velocity of the trucks is the distance travelledWhen the truck comes to a stop, the final velocity, v will be zero.
0 = u² + 2as
0 = (27²) + (2)(-5)(s)
= (27²) - 10s
10s = 27²
s = ( 27² ) / 10
s = 72.9 m
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a meter stick is supported at the 50 cm mark. a 0.40 kg mass is hanging at the 20 cm mark and a 0.60 kg hanging at the 80 cm mark. where should a third mass that weighs 0.30 kg be hung to keep the stick balanced?
The new mass must be inserted and hung at a distance of 30 cm, per the calculation.
Is hung or hanged a word?The past tense of the verb hang, which means "to suspend or be suspended," is "to hold." When it implies "to kill someone by tying a rope attached from above and removing the supporting from beneath," the past tense of the verb to hang is "to hang someone."
From the diagram,
W₁(50-30) + W₃(x-50) = W₂(80-50)
were, W₁ = m₁g = 0.4×9.8 = 3.92 N ( Where m₁ = 0.4 kg and g = 9.8
W₂ = m₂g =0.6×9.8 = 5.88 N ( where m₂ = 0.6 kg)
W₃ = m₃g = 0.3×9.8 = 2.94 N ( where m₃ = 0.3 kg)
Therefore,
3.92(30) + 2.94(50-x) = 5.88(30)
117.6 + 147-2.94x = 176.4
2.94x+264.6 = 176.4
-2.94x = 176.4-264.6
2.94x = 88.2
x = -88.2/-2.94
x = 30 cm
Thus the third mass must be hung 30 cm
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the two graphs in (figure 1) are for two different vertical mass/spring systems.Part AWhat is the frequency of system A?Express your answer using two significant figures.Part BWhat is the first time at which the mass of system A has maximum speed while traveling in the upward direction?Express your answer using two significant figures.Part CWhat is the period of system B?Express your answer using two significant figures.Part DWhat is the first time at which the mechanical energy of system B is all potential?Express your answer using two significant figures.Part EIf both systems have the same mass, what is the ratio kA/kB of their spring constants?Express your answer using two significant figures.
The frequency of system A determined based on given graph is 0.25
What is the system's period?The interval between two consecutive cycles is referred to as the period, also known as the periodic time, of a periodic oscillation of a quantity. Time, or T, is defined as the period of oscillation, with T = 2 or T = 2/. The formula f = 1/T = /2 gives the reciprocal of the period, or the frequency f, in oscillations per second.
Based on the graph:
In system A; 3 wavelength in 12 secs
for time for 1 wavelength => 12/3 = 4 sec
Thus, frequency => 1/t = 1/4 => 0.25
What is the wave speed equation?The wavelength and frequency components of the wave speed formula are given by the equation: v = f. where v denotes the wave's speed. The wave's frequency is f.
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I'LL GIVE A BRAINLIST FOR SHOWING WORK
What is the difference in momentum between a 50 kg runner moving at 3 m/s and a 3000 kg truck moving at a speed of 1 m/s?
The momentum of the runner:
momentum = mass x velocity = 50 kg x 3 m/s = 150 kg*m/s
The momentum of the truck:
momentum = mass x velocity = 3000 kg x 1 m/s = 3000 kg*m/s
The difference in momentum between the runner and the truck:
difference in momentum = momentum of truck - momentum of runner = 3000 kgm/s - 150 kgm/s = 2850 kg*m/s
So, the difference in momentum between the 50 kg runner moving at 3 m/s and the 3000 kg truck moving at a speed of 1 m/s is 2850 kg*m/s
A horizontal force acts on a block sliding on a horizontal surface. the force of kinetic friction between the block and the surface is 0.5 n. if the direction of the applied force is reversed, which is true?
If the direction of the applied force is reversed on a block sliding on a horizontal surface, the force of kinetic friction between the block and the surface will also be reversed.
The force of kinetic friction will now act in the opposite direction of the applied force, and its magnitude will remain the same (0.5 N). As a result, the net force acting on the block will be the difference between the applied force and the force of kinetic friction, which will determine the block's acceleration. The block will slow down and eventually stop moving, as the force of kinetic friction will be greater than the applied force in this case.
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Your question is incomplete, but most probably, the complete question is:
A horizontal force acts on a block sliding on a horizontal surface. The force of kinetic friction between the block and the surface is 0.5F. If the direction of the applied force is reversed, which is true?
The magnitude of the net force on the block increases.
The magnitude of the acceleration of the block remains the same.
The kinetic energy of the block increases.
The velocity of the block remains the same.
A rock is thrown and it takes 6 seconds to hit the ground how High did it travel
When a rock is thrown and it takes 6 seconds to hit the ground, it travelled 176.4 meters.
What is acceleration of free fall?
Acceleration of free fall is the acceleration at which a body falls when only the gravitational forces of the earth is acting upon it. It is represented by the letter g, and its value on the earth's surface is 9.8 m/s².
Time taken to hit the ground by the rock: Δt = 6 seconds.
Hence, it travelled a height of = 1/2 × gΔt²
= 1/2 × 9.8 × 6² meter
= 176.4 meters.
Hence, , it travelled 176.4 meters.
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Derive an expression for the torque applied by the adult rider (on the left) in terms of given quantities and variables available in the palette. Assume counterclockwise is positive.
The torque applied by the adult rider can be represented by the following expression: Torque = force x distance from the axis of rotation, in terms of quantities and variables.
In this case, the force applied by the adult rider is the force exerted by the rider on the pedal, and the distance from the axis of rotation is the distance between the pedal and the axis of rotation (the center of the wheel). Let's assume the force exerted by the adult rider on the pedal is represented by the variable F_rider, and the distance between the pedal and the axis of rotation is represented by the variable r. Torque = F_rider x r. It's important to note that the torque is also affected by the angle between the applied force and the radius vector. In this case, we assumed that the rider is applying force in a direction that is perpendicular to the radius vector. Also, the direction of rotation that is positive is assumed to be counter clockwise.
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Which of the following is the best description of the events of anaphase I?Homologous chromosomes randomly separate and migrate to opposite poles.
Homologous chromosomes arbitrarily divide and move to opposing poles throughout Ana-phase I of meiosis, which is the best way to describe what happens.
What do the Earth's poles do?Either of the two sites on Earth in which the rotation axis crosses the surface is referred to as a geographical pole. "Poles" are the parts of magnets with the strongest magnetic fields. Numerous magnet poles will either repel, pull, or attract one another.
Which pole is stronger?A magnet's south and north poles are equally powerful. The capacity of a magnet to generate a magnetic flux and to pull or push other magnetically or superconductors is referred to as its strength. The power of a magnet is not reliant on its magnetic field.
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A pulse of a wave train travels along a stretched string and reaches the fixed end of
the string. It will be reflected back with :
A aphase change of 180° with velocity reversed
B the same phase as the incident pulse with no reversal of velocity
Cc aphase change of 180° with no reversal of velocity
D__ the same phase as the incident pulse but with velocity reversed
A wave train pulse moves along a slinky until it reaches the string's fixed end. It will return with a 180° phase shift and the opposite velocity.
What does velocity mean?The dislocation that an objects or particle experiences with regards to the time is expressed vectorially as velocity. The metres per second (m/s) is the accepted unit of fluid velocity (usually known as speed).
What is the SI unit for velocity?The velocity is the rate at which a given displacement changes. By figuring out the displaced to total time ratio, this could be calculated. The same as for speed, "m/s" is the SI unit for velocity.
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Consider an ideal spring that has an unstretched length l_0. Assume the spring has a constant k. Suppose the spring is attached to an cart of mass m that lies on a frictionless plane that is inclined by an angle theta from the horizontal. Let g denote the gravitational constant The given quantities in this problem are l_0, m, k, theta, and g. a) The spring stretches slightly to a new length l>l_0 to hold the cart in equilibrium. Find the length l in terms of the given quantities. b) Now move the cart up along the ramp so that the spring is compressed a distance x from the unstretched length l_0. Then the cart is released from rest What is the velocity of the cart when the spring has first returned to its unstretched length l_0? c) What is the period of oscillation of the cart?
The length of the spring in equilibrium is l = l0 +(mgsin(theta)/k in terms of the given quantities
a) The length of the spring in equilibrium can be calculated using the spring's force equation, F = -k(l-l0).The force exerted by gravity on the cart is mgsin (theta), which must be equal to the force exerted by the spring in order to achieve equilibrium. Setting these two forces equal to each other and solving for l gives:
l = l0 +(mgsin(theta)/k
b) When the cart is released from rest, it will have potential energy stored in the spring. This potential energy can be converted into kinetic energy as the spring expands. The velocity of the cart when the spring has first returned to its unstretched length can be found using the conservation of energy. The potential energy stored in the spring when the cart is released is (1÷2) kx2, and the kinetic energy at the point when the spring returns to its unstretched length is (1÷2) mv². Setting these two equal to each other and solving for v gives:
sqrt(2kx÷m) = v
c) The period of oscillation of the cart is the time it takes for the cart to complete one full oscillation. T = 2pisqrt(m/k) can be used to calculate it.
2pisqrt(m÷k) = T
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if there is a and - charge near each other and they are moved further apart, work must be done and the result is strong electric potential energy. what would be a good analogy to this process in the case of gravity?
A good analogy to this process in the case of gravity would be carrying a heavy object up a flight of stairs. Work must be done and energy is expended to move the object further away from the ground.
What is the move ?
The move is a change of direction or position, usually from one place to another. It can involve anything from a simple walk to a large and complex relocation. In the context of sports, it means a technique used by a player to gain an advantage over an opponent. In dance, it is a gesture or step that is part of a larger routine. In business, it can mean a strategic shift in direction taken by a company in order to improve its performance or gain a competitive edge. Moves can also be used in the context of decision-making, where one assesses the pros and cons of different options before settling on the best option.
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a hooke's law spring is mounted horizontally over a frictionless surface. the spring is then compressed a distance d and is used to launch a mass m along the frictionless surface. what compression of the spring would result in the mass attaining double the kinetic energy received in the above situation? a hooke's law spring is mounted horizontally over a frictionless surface. the spring is then compressed a distance d and is used to launch a mass m along the frictionless surface. what compression of the spring would result in the mass attaining double the kinetic energy received in the above situation? 2.00 d 1.73 d 1.41 d 4.00 d
The mass would gain twice the kinetic energy it did in the scenario above if the spring were compressed by 14.1 cm.
Do you mean by kinetic energy?A particle or perhaps an item that is currently motion has a type of energy called kinetic energy. An item acquires kinetic energy when work, which involves the transmission of energy, is performed on it by exerting a net force.
A spring's energy reserve is proportional to the square of the compression, x.
PE of compression = 0.5kx^2 where k is a constant to do with how easy it is to compress the spring.
So 0.5d^2 gives a KE of value Q
If you double Q you get 2Q and get 0.5D^2 where D is the new compression
So 0.5d^2/0.5D^2 = Q/2Q
d^2/D^2 = 1/2 which means that D^2 = 2d^2 or D = d(sqrt2)
Therefore, the new compression is roughly 1.414 times that of the old one.
Easiest method for recalling is that KE is proportional to sqrt(d)
To double KE you need to compress the spring sqrt2 times as much as before.
Hope this helps.
PE of spring = stored energy = (1/2)kx^2 = (1.2)mv^2
So kx^2 = mv^2
x^2 = (m/k)v^2
x is proportional to v
If x is doubled, v is doubled, and the KE is quadrupled.
the distance would then be ? 2*d or 1.41d = 1.41(10) = 14.1 cm
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the windpipe of a typical whooping crane is about 5.0 ft. long. what is the lowest resonant frequency of this pipe, assuming it is closed at one end? assume a temperature of 37c.
The lowest resonant frequency of this pipe is approximately 58 Hz.
What is frequency?
Frequency is a measure of how often a particular event occurs or a certain value appears in a set of data. It is usually expressed as a number of occurrences or a percentage of the total. Frequency is a useful concept in statistics and probability theory as it can provide insight into the underlying data and help to draw conclusions about the data.
The speed of the sound is:
[tex]$v =331 \sqrt{1 + \frac{T}{273} }[/tex]
[tex]$v =331 \sqrt{1 + \frac{37}{273} }[/tex]
v = 352.72 m/s
The length of the pipe is:
L = 5.0 ft = 1.524 m
The wavelength is:
λ = 4L
= (4)(1.524)
= 6.096 m
[tex]$f = \frac{v}{\lambda}[/tex]
[tex]$ f =\frac{352.72}{6.096}[/tex]
A stone was thrown horizontally at a speed of 5.0m/s from the top of a cliff 78.4 m high
a. how long does it take the stone to hit the bottom of the cliff
b. how far from the base of the cliff does the stone strike the ground
c. what are the horizontal and vertical components of velocity of the stone as it hits the ground
The time taken to reach ground will be 4 sec, stone hits 20 meters from base of cliff, and final velocity in Y axis is 39.2 m/s.
What is the definition of a velocity simple?The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.
Given:
Speed of stone = 5.0 m/s
Hight = 78.4 m
(a).
The stone is horizontally thrown, the initial vertical velocity will be zero.
[tex]h=u_y(t)+\frac{1}{2} gt^2[/tex]
[tex]78.4=0(t)+\frac{1}{2} (9.8)t^2[/tex]
[tex]78.4=4.9t^2[/tex]
[tex]t^2=16[/tex]
[tex]t=4sec[/tex]
(b).
Now, Range (R) will be,
[tex]R=u_x(t)[/tex]
[tex]R=5*4[/tex]
[tex]R=20 meters[/tex]
(c).
The horizontal component of velocity will still remain 5 m/s because there is no acceleration in X axis.
But in Y axis, we can say,
[tex]u_y=u_x+gt[/tex]
[tex]u_y=0+9.8(4)[/tex]
[tex]u_y=39.2m/s[/tex]
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compare compass needle deflection under the wire with charge flowing into the risis wirth deflection under the wire with charge flowing out of the resistor
A compass needle is used to detect magnetic fields and will be deflected when placed near a wire that carries an electric current.
When charge flows into a resistor, the current flowing through the resistor generates a magnetic field in the clockwise direction as seen from the end of the wire through which the current is flowing. This will cause the compass needle to be deflected in the clockwise direction.
When charge flows out of a resistor, the current flowing through the resistor generates a magnetic field in the counter-clockwise direction as seen from the end of the wire through which the current is flowing. This will cause the compass needle to be deflected in the counter-clockwise direction.
In summary, when charge flows into the resistor, the compass needle will be deflected in the clockwise direction, and when charge flows out of the resistor, the compass needle will be deflected in the counter-clockwise direction.
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How is Faraday's law of electromagnetic induction used? (in things like security alarms etc.)
Answer:
helps us predict how a magnetic field would interact with an electric circuit to produce an electromotive force
Explanation:
a car with a wheel of radius 14 inches is moving with a speed of 55 mph. find the angular speed of the wheel in radians per second.
The response to the question is that a car's wheel rotates at a rate of 1.44 radians per second.
What is angular velocity or speed?The angular velocity (w), a vector quantity in a uniform circular motion, is determined by dividing the displacement (), also a vector quantity, by the change in time (t). Speed is equal to |w|R and is computed by dividing the arc length traversed (S) by the time difference (t).
Is angular speed and angular acceleration equivalent?A scalar measurement of the revolving object is its angular speed. A vector representation of the rotor blade is the angular velocity. Only the degree of an angle's speed is specified. The direction and magnitude are both specified by angular velocity.
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damping is negligible for a 0.150kg object hanging from a light, 6.30n/m spring. a sinusoidal force with an amplitude of 1.70n drives the system. at what frequency will the force make the object vibrate with an amplitude of 0.440m ?\
The frequency of the force at which the object will vibrate with an amplitude of 0.440m is f ≈ 5.2 Hz.
What is frequency?
Frequency is a concept in physics that describes the number of times a repeating event occurs in a given period of time. It is a scalar quantity and is measured in units of hertz (Hz), where 1 Hz is equal to one event per second. The frequency of a wave is the number of oscillations or cycles that occur in a given period of time, and it is the reciprocal of the period (the time it takes for one cycle to occur).
To determine the frequency at which the force will make the object vibrate with an amplitude of 0.440m, we can use the equation for the natural frequency of a damped harmonic oscillator:
f = (1 / (2 * pi)) * sqrt ( k / m)
where f is the frequency of the vibration, k is the spring constant, m is the mass of the object and pi is the mathematical constant pi. Given that the spring constant is 6.30 N/m and the mass of the object is 0.150 kg, we can substitute these values into the equation to find the natural frequency of the system:
f = (1 / (2 * pi)) * sqrt ( 6.30 N/m / 0.150 kg)
f = (1 / (2 * pi)) * sqrt ( 42 N/m/kg)
since damping is negligible, the frequency of the vibration will be the same as the natural frequency of the system.
f = (1 / (2 * pi)) * sqrt ( 42 N/m/kg)
The frequency of the force at which the object will vibrate with an amplitude of 0.440m is f ≈ 5.2 Hz.
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which of the following wavelength regions cannot be studied with telescopes on the ground?
A) radio waves
B) X rays
C) ultraviolet
D) both B and C
E) both A and C
Radio waves and X- rays wavelength regions cannot be studied with telescopes on the ground.
The longest wavelengths of the electromagnetic spectrum, which are present in radio waves, are often found at frequencies of 300 gigahertz and lower. While the wavelength for 30 Hz is 10,000 kilometers, it is 1 mm for 300 GHz.An X-ray or, much less frequently, an X-radiation is a penetrating kind of high-energy electromagnetic radiation. The majority of X-rays have wavelengths in the range of 10 picometers to 10 nanometers, which corresponds to energy of 145 eV to 124 keV and frequency of 30 petahertz to 30 exahertz.
X-ray(s) can be spelled in English as x-ray(s), xray(s), and X ray (s). Although the most common use of X-rays is to check for fractures (broken bones), there are other applications as well.
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particles on an x axis: q 3.20 1019 c at x 3.00 m and q 3.20 1019 c at x 3.00 m. what are the (a) magnitude and (b) direction (relative to the positive direction of the x axis)
The magnitude of the charged particles will be 1.38 x 10-10N/C
A charged particle in physics is a particle that has an electric charge. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. It could also be an elementary particle like as an electron, proton, or another one that is thought to have the same charge (except antimatter).
By symmetry, the vertical components of each field (caused by the two charges) cancel.
When d and y are set to 3 and 4 meters, respectively, the horizontal components (both pointing in the direction of -x) sum up to a magnitude of
Ex.net = 2lqld 4лε (d² +y²)³/2
2(8.99 × 10°N.m²/C²)(3.20 × 10-19℃)(3.00 m) [(3.00 m)2 + (4.00 m)2] 3/2
= 1.38 x 10-10N/C.
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what is the speed vfinal of the electron when it is 10.0 cm from charge 1? Two stationary positive point charges, charge 1 of magnitude 4.00 nC and charge 2 of magnitude 1.80 nC , are separated by a distance of 58.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed vfinal of the electron when it is 10.0 cm from charge 1? Express your answer in meters per second.
According to the question,
The speed of the electron when it is 10.0 cm from charge 1 is 11.33 m/s.
What is the electron?
The electron is a subatomic particle that carries a negative electric charge. It is the lightest of all the particles that make up matter. Electrons are found in all atoms, and they are responsible for chemical bonding between atoms. Electrons are found in a cloud surrounding the nucleus of an atom, and they are always moving. The size of the electron is much smaller than the size of the nucleus. Electrons travel in orbits around the nucleus, and each orbit has a certain amount of energy. Electrons are also involved in many physical and chemical reactions, such as the production of heat, light and electricity. Electrons play an important role in the structure of atoms, and they are essential for life as we know it.
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Horses with the greatest linear speed on a merry-go round are located:
a. near the center
b. near the outside
c. anywhere
Horses with the greatest linear speed on a merry-go round are located near the outside.
The measurement of a moving object's actual distance traveled is called linear speed. Linear speed is the rate of motion of an object along a straight line.
The carousel ( merry-go-round) is a delicate balance of motion and forces, in spite of all its beauty and outward appearance of simplicity. One full circuit is completed by each horse in precisely the same amount of time. In the same length of time, the horses inside the carousel must travel a greater distance than the horses outside. As a result, the horses outside move more quickly along a straight line than those inside the hub. Therefore, a rotating object's linear speed is higher on its outside edge than it is closer to the axis.
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suppose you drop an object out of the window of a building and wait for it to hit the ground. how does the halfway point in distance compare to the halfway point in time? please explain.
It travels below half the distance in 1⁄2 the time required to reach the surface while remaining above the window-to-ground halfway point.
What is the straightforward meaning of time?The amount of time that something happens, undergoes a procedure or stays the same: duration.: a non-spatial continuum where events succeed one another in time from the past through the present to the future
How does science define a time?time is a continuum without spatial dimensions that can be measured or quantified. Time is a philosophically intriguing concept that is also the focus of mathematical research.
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Determine the greatest force P that can be applied to the frame if the largest force resultant acting at A can have a magnitude of 5kN.
To determine the greatest force P that can be applied to the frame, we need to analyze the forces acting on point A. The force P is acting on the frame at an angle of 45 degrees, and we know that the largest force resultant that can act on point A has a magnitude of 5 kN.
We can use vector addition to find the magnitude of the force resultant at point A. We can resolve force P into its x and y components, Px and Py, using trigonometry.
Px = P * cos(45) = P * 1/√2 = P/√2
Py = P * sin(45) = P * 1/√2 = P/√2
The force resultant at point A is the vector sum of Px and Py.
|F_resultant| = √(Px^2 + Py^2) = √((P/√2)^2 + (P/√2)^2) = √(P^2/2 + P^2/2) = √(P^2) = P
Since the force resultant at point A cannot exceed 5 kN, the magnitude of P must also be less than or equal to 5 kN. Therefore, the greatest force P that can be applied to the frame is 5 kN.
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a mass on a spring completes 8 oscillations in 4.0 s. determine the period of its simple harmonic motion.
The time period of its simple harmonic motion is 0.5 second, if the mass on a spring completes 8 oscillations in 4 seconds.
The time period of a wave is defined as the time required to complete one one oscillation or cycle. One oscillation is when a wave particle repeats its position in a path. On the other hand number of oscillation in one second is called frequency.
A motion in which restoring force in a body is directly proportional to the distance of the body from its mean position, is called simple harmonic motion.
As per the question statement, time required to complete 8 oscillation = 4.0 sec
Then, time required to complete 1 oscillation = 4/8 = 0.5 second.
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Two charged metal plates in vacuum arc scparated by 15 Cm as showmn in the figure. The electric field between the plates uniform and has an intensity ol 3.' 103 N/C. An electron with charge and mass 9-1 kg is released from point just inside the negative plate JC00 N/C Calculate the time the electron will take to hit the other plate- Note that you cannot neglect gravity! How (ar dawn from point A (directly horizontally across from point P) will the clectron hit?
The time taken by the electron from one plate to reach the other plate is 1.12 x 10⁻¹⁷ s
Two metal plates separated by the distance = 15 cm
= 0.15 m
The electric field between the plates = 3 x 10³ N/C
The mass of the electron = 9.1 x 10⁻³¹ kg
The charge of the electron = 1.6 x 10⁻¹⁹ C
The time taken by the electron to hit the other plate can be found using the formula,
d = 1/2at² + vt
where d is the distance between the plate
a is the acceleration of the electron
t is the time taken by the electron
v is the velocity of the electron.
Let us find the acceleration of the electron
a = E/m
where E is the electric field of the electron
m is the mass of the electron
a = 3 x 10³ / 9.1 x 10⁻³¹
= 3.27 x 10³³m/s²
Let us substitute the known values in the distance equation, we get
d = 1/2at² + vt
0.15 = 1/2 x 3.27 x 10³³ x t² x 0t [ the initial velocity of the electron is zero]
t² = 2 x 0.15 / 3.27 x 10³³
= 0.3 / 3.27 x 10³³
= 0.0917 x 10⁻³³
= √ (0.0917 x 10⁻³³)
= 1.12 x 10⁻¹⁷ s
Therefore, the time taken by the electron is 1.12 x 10⁻¹⁷ s
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The wind on which planet can blow up to 1,500 miles per hour?
The wind on Neptune can blow up to 1,500 miles per hour.
What is Neptune?Neptune is the eighth and most distant planet from the Sun, and it is also the third most massive planet in the solar system. It is impossible to see it without a telescope due to its great distance from Earth. It looks like a tiny, indistinct blue-green disc through a micro telescope. The symbol serves as a designation.
A son of the Titan Cronus (the Roman god Saturn) and a brother of Zeus, Neptune is named after the Roman sea god, Poseidon, who is also known by his Greek name Poseidon (the Roman god Jupiter). Through the use of a telescope, it was the second planet discovered.
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Question 8
A lightbulb has a power of 60 W and is used for 16 hours. A toaster oven has a power of 1500 W and is used for 45 minutes. (Use correct units in all answers)
a. How much energy is used by the lightbulb? (2 points)
b. How much energy is used by the toaster oven? (2 points)
c. The lightbulb has an efficiency of 2.3%. How much light energy does the lightbulb produce in 16 hours? (2 points)
Explanation:
a) power = energy/time
taking time in seconds: 16 x 60 min x 60 sec =57600 s
now:
60 W = E/57600 s
E = 3456000 J or 3456 KJ
b) time: 45 x 60 s = 2700 s
P = E/t
1500 W = E/2700
E = 4050000 J or 4050 KJ
c) efficiency = (output energy/input energy) x 100
2.3% = (X/3456000) x 100
X = (2.3/100) x 3456000
X = 79488 J
A highway curves to the left with radius of
curvature of 36 m and is banked at 25 ◦
so
that cars can take this curve at higher speeds.
Consider a car of mass 1091 kg whose tires
have a static friction coefficient 0.87 against
the pavement.
How fast can the car take this curve without
skidding to the outside of the curve? The
acceleration of gravity is 9.8 m/s
2
.
Answer in units of m/s.
Velocity at which the car can take the curve without skidding to the outside of the curve is approximately 29.5 m/s.
How do we determine the velocity of the car without skidding outside the curve?To determine the speed at which the car can take the curve without skidding to the outside of the curve, we need to calculate the maximum force of static friction that can act on the car as it goes around the curve.
The maximum force of static friction can be found using the formula:
f_max = friction_coefficient * f_norm
where f_max is the maximum force of static friction, friction_coefficient is the coefficient of static friction between the tires and the pavement (0.87), and f_norm is the normal force acting on the car.
The normal force can be found by calculating the centripetal force acting on the car as it goes around the curve, which can be found using the formula:
f_cent = m * a_cent
where f_cent is the centripetal force, m is the mass of the car (1091 kg), and a_cent is the centripetal acceleration, which can be found using the formula:
a_cent = v² / r
where v is the velocity of the car and r is the radius of the curve (36 m).
Substitute the value of a_cent in the formula for f_cent
f_cent = m * (v² / r)
Also we know that the maximum force of static friction is equal to the normal force acting on the car
f_max = f_norm = m * (v² / r)
Now we know friction_coefficient * f_norm = m * (v² / r)
so we can substitute the value of friction_coefficient and m and r
0.87 * m * g * sin(25) = m * (v² / 36)
v = √(0.87 * 9.8 * 36 * sin(25))
v = 29.5m/s
Therefore, the velocity of the car without skidding outside the curve is 29.5m/s
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