Answer:
468 g _______________________
The mass of 8 moles of sodium chloride is 468 grams. Therefore, option A is correct.
Molar mass, also known as molecular weight, is the mass of one mole of a substance. It is typically expressed in grams per mole (g/mol). Molar mass is calculated by summing the atomic masses of all the atoms in a molecule.
To calculate the mass of a substance, multiply the number of moles by the molar mass of the substance. The molar mass of sodium chloride (NaCl) is approximately 58.44 grams per mole.
The mass of 8 moles of sodium chloride:
Mass = Number of moles × Molar mass
Mass = 8 moles × 58.44 g/mol
Mass = 467.52 grams
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answer this please thank you
Answer:
6am
Explanation:
answer this please thank you
Soldium and sulphur compound form formula
Answer:
Na2S
Explanation:
hope this helps
How much does a cloud weigh in pounds?
Answer:
1.1 million pounds
Explanation:
Answer:
1.1 million pounds
Explanation:
that's a lot of water above us!!
Chemical properties of mercury hg
Answer:
Mercury has a relatively high vapour pressure and the highest volatility of any metal, vapourizing to become a colourless, odourless gas. The metal is a fair conductor of electricity, but a poor conductor of heat. Mercury's atomic number is 8.
A student mixes some soap with water and then blows through a straw into the solution. Bubbles form. Do you think a chemical change has taken place? Explain
Answer:
No it has not.
Explanation:
The actual chemical compound has not changed, the materials have mixed but no reaction has taken place. Blowing the bubbles causes a physical change. Hope this helped!
Mixing soap and water and forming bubbles is a physical change as there is no change in composition.
What is a physical change?
Physical changes are defined as changes which affect only the form of a substance but not it's chemical composition. They are used to separate mixtures in to chemical components but cannot be used to separate compounds to simpler compounds.
Physical changes are always reversible using physical means and involve a change in the physical properties.Examples of physical changes include melting,boiling , change in texture, size,color,volume and density.Magnetism, crystallization, formation of alloys are all reversible and hence physical changes.
They involve only rearrangement of atoms and are often characterized to be changes which are reversible.
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What is the mass in grams of one mole of sulfur? (round to 3 sig figs)
Answer:
This tells you that one mole of sulfur atoms, S , has a mass of 32 g
Which of the following best describes the scientific exploration of the atom?
Escriba un poema usando 4 de las siguientes palabras: lluvia, nieve, lluvia, granizo, tornado, huracanes, frente cálido, frente frío, alta presión, baja presión, termómetro, barómetro, anemómetro, pluviómetro, veleta o higrómetro.
plis ayúdenme porfa
Answer:
i dont speak mexican
Explanation:
How many grams are in 0.787 moles of kcn
Answer:
=> moles = Given mass/molar mass
=> 0.787 = Given mass/(39 + 12 + 14)
=> 0.787 = Given mass/65
=> mass = 0.787 × 65
=> mass = 51.155 g
What element is being oxidized in the following redox reaction?
Cr(OH)4-(aq) + ClO-(aq) → CrO42-(aq) + Cl-(aq)
Answer:
Cr
Explanation:
Cr goes from +3 to +6 and when it increases it means is being oxidized.
The element being oxidized in the redox reaction is Cr. Oxidation state helps to determine the amount of oxidation which an atom undergoes. An increase in oxidation state or number signifies oxidation has taken place.
A decrease in oxidation state depicts reduction has taken place. In this
scenario, the element Cr has a change in oxidation state from +3 to +6 which
signifies oxidation took place in the atoms of the element. This is why Cr will
be the right option.
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________ are neutral particles found in the nucleus of an atom.
The sum of the number of proteins and neutrons in an atoms nucleus is its __________ ___________.
Answer:
Mass Number
Explanation:
In nuclear physics, the sum of the numbers of protons and neutrons present in the nucleus of an atom.
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The mass of a metal ball was 20.350 g. The volume of the water in a 25 mL graduated cylinder was increased from 16.05 to 17.90 mL when the metal ball was placed in the cylinder. What is the density of the metal ball
Answer:
11000 g/L
Explanation:
Since density is mass divided by volume, find the volume of the metal ball by subtracting the initial volume of water in the graduated cylinder from the ending volume. In this case, the volume would be 17.90 mL - 16.05 mL = 1.85 mL = 0.00185 L. Then using the formula for density, calculate 20.350 g / 0.00185 L = 11000 g/L.
Density is an intensive property as it does not depend on the quantity of the substances Whereas mass and volume are extensive property. Therefore, the density of the metal ball is 11000 g/L.
What is density?Density tells about the compactness of the substances, how much dense is the substances in other words. Object that is more denser than water they just sink in the water.
Mathematically,
Density = Mass of the metal ball ÷volume marked on the graduated cylinder
volume=ending volume- initial volume of water in the graduated cylinder
=17.90 mL - 16.05 mL
= 1.85 mL
= 0.00185 L.
substituting all the given values in the above equation, we get
density= 20.350 g / 0.00185 L
= 11000 g/L.
Therefore, the density of the metal ball is 11000 g/L.
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Page No. Date Chemistry traignment Scientific Notation Covert 0.00000046 in to Scientific Notation
Answer:
answer is 4.6×10 with exponent 7
Answer:
[tex]4.6\times10^{-7}[/tex]
Explanation:
Remember that if the decimal point is to the right then the exponent is a negative.
[tex]4.6\times10^{-7}[/tex]
Move the decimal point to the left:
[tex].0.0.0.0.0.0.4.6[/tex]
[tex].0.0.0.0.0.0.4.6=0.00000046[/tex]
Hope this helps
A hydrochloric acid solution is standardized by titrating 0.2329 g of primary standard sodium carbonate to a methyl red end point by boiling the carbonate solution near the end point to remove carbon dioxide. If 42.87 mL acid is required for the titration, what is its molarity
HELP
The molarity of the acid, HCl solution is 0.103 M
We'll begin by calculating the number of mole in 0.2329 g of Na₂CO₃
Mass of Na₂CO₃ = 0.2329 g
Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3) = 106 g/mol
Mole of Na₂CO₃ =?Mole = mass / molar mass
Mole of Na₂CO₃ = 0.2329 / 106
Mole of Na₂CO₃ = 0.0022 mole Next, we shall determine the number of mole of HCl needed to react with 0.0022 mole of Na₂CO₃Na₂CO₃ + 2HCl —> 2NaCl + H₂O + CO₂
From the balanced equation above,
1 mole of Na₂CO₃ reacted with 2 moles of HCl.
Therefore,
0.0022 mole of Na₂CO₃ will react with = 0.0022 × 2 = 0.0044 mole of HCl
Finally, we shall determine the molarity of the HCl.Mole of HCl = 0.0044 mole
Volume = 42.87 mL = 42.87 / 1000 = 0.04287 L
Molarity of HCl =?Molarity = mole / Volume
Molarity of HCl = 0.0044 / 0.04287
Molarity of HCl = 0.103 MThus, the molarity of the acid, HCl solution is 0.103 M
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g Element X is an element in period 4. Identify X given that in the molecule XH3. It exhibits hybridization sp3. WHat is the element
Answer:
XF3 is our compound. X is unknown For the problem I am using the periodic table at this ...
Explanation:Solution for Element X is an element in period 3. Identify X given that in the molecule XH3, it exhibits hybridization sp2 . Indicate the symbol and not ...
Two or more than two atoms with different physical or chemical properties can not combine together to form an element. The element X in period 4 with covalency 3 is Arsenic (As).
What is element?Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same. The periodic table is divided into groups and periods. depending on the number of valence electrons and the number of outermost orbit respectively.
In the given compound XH[tex]_3[/tex], the covalency of X is 3, means the valence electrons in the outermost shell of element X is 3. The only group that have valence electron 3 is group 15 that is nitrogen family. In the fourth period of group 15 we find Arsenic element.
Therefore the element X in period 4 with covalency 3 is Arsenic (As).
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How many moles of potassium iodide, KI, are required to precipitate all of the lead (II) ion from 25.0 mL of a 1.6 M Pb(NO3)2 solution? (First, write a balanced equation for the reaction.)
0.04 moles of iodide is required to precipitate all the lead II ions from 25.0 mL of a 1.6 M Pb(NO3)2 solution.
The reaction equation is;
2KI(aq) + Pb(NO3)2(aq) -------> PbI2(s) + 2KNO3(aq)
The net ionic equation is;
Pb^2+(aq) + 2I^-(aq) ------> PbI2(s)
Number of moles of Pb(NO3)2 = 25/1000 L × 1.6 M = 0.04 moles
Number of moles of Pb^2+ = 0.04 moles /2 = 0.02 moles
Since 2 moles of iodide reacts with 1 mole of Pb^2+
x moles of iodide reacts with 0.02 moles of Pb^2+
x = 2 moles × 0.02 moles/ 1 mole
x = 0.04 moles of iodide
Hence, 0.04 moles of iodide is required to precipitate all the lead II ions from 25.0 mL of a 1.6 M Pb(NO3)2 solution.
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Given the ionic formula below, what is the charge on ion X? Be sure to
include the sign (+ or -). Li2 x
Answer:Charge on X = (+ 2)
Explanation:
Charge on one Cl = -1
So Charge on two Cl = -2
The molecule = Neutral = 0 charge
So, to make total charge = 0 , the X should have +2 charge
XCl2 = +2 -2 = 0
X = +2
Alkaline earth metals(Be , Mg , Ca , Sr) form such type of compounds
Explanation:
Why did you place each biotic factor in the model where you did?
Answer:
Biotic and abiotic are the two essential factors responsible for shaping the ecosystem. The biotic factors refer to all the living beings present in an ecosystem, and the abiotic factors refer to all the non-living components like physical conditions (temperature, pH, humidity, salinity, sunlight, etc.) and chemical agents (different gases and mineral nutrients present in the air, water, soil, etc.) in an ecosystem. Therefore, both the abiotic and biotic resources affect survival and reproduction process.
Furthermore, both these components are reliant on each other. Suppose if one of the factors is removed or altered, its repercussions will be faced by the entire ecosystem. Without a doubt, abiotic factors directly affect the survival of organisms. Read on to explore what role do abiotic and biotic resources play in the ecosystem.
The two primary forces influencing the ecosystem are biotic and abiotic. The terms "biotic factors" and "abiotic factors" describe the various living and non-living elements of an ecosystem, respectively.
What is biotic factor ?A living thing that alters its surroundings is referred to as a biotic factor. Examples of organisms found in a freshwater habitat include algae, fish, amphibians, and aquatic plants. A particular ecosystem is the result of the interaction of biotic and abiotic components.
All living things, including people, fungi, and bacteria as well as animals and plants, are considered to be biotic factors. For each species to reproduce and to meet basic needs like food, the interactions between numerous biotic variables are vital.
Due to the fact that these organisms "create" food using inorganic materials and energy sources, the producers are biotic elements that are crucial to an ecological system. Without them, life might not be able to exist.
Thus, The two primary forces influencing the ecosystem are biotic and abiotic.
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answer this please ......................
Answer:
River esk the third one is righttt
PLS HELP CHEM
What is the temperature, in Celsius, of 20.8 g of carbon dioxide (CO2) in a 575 mL container under 1.5 atm of pressure?
Answer:
Use the formula PV=nRT to get the temperature
which two types of food are homogeneous mixtures
A. mustard
B. mayonnaise
C. tossed salad
D. trail mix
6) 0.5 moles of gas is kept at 2.0 L of volume and 0.75 atm of pressure. What is the temperature of the gas in K?
Answer:
310K
Explanation:
Rearrange PV=nRT to get T=PV/nR
T=(2.0L)(0.75atm)/(0.5mol)(0.08206)
=36.5 or 37
add 273 for K to get
310
Cesium-137 is part of the nuclear waste produced by uranium-235 fission. The half-life of cesium-137 is 30.2 years. How much time is required for the activity of a sample of cesium-137 to fall to 8.32 percent of its original value
Answer:
la primera va con la última
Calculate the number of molecules present in 11 moles of H2O.
Answer:
[tex]11 \times 6.022 \times {10}^{23} \\ = 66.242\times {10}^{23} \: of \: \\ water \: molecules[/tex]
When the following equation is balanced, the coefficients are ________.
NH3 (g) + O2 (g) ---> NO2 (g) + H2O (g)
a. 1,1,1,1
b. 4,7,4,6
c. 2,3,2,3
d. 1,3,1,2
e. 4,3,4,3
Answer:
B
Explanation:
Option B is the correct answer. When you add 7 in front of the O2 in the left side, and then you add 4 and 6 in front of NO2 and H2O respectively, the number of oxygen atoms is the same in both sides.
A local water retention pond was found to have elevated mass concentration of mercury of 14 ng per liter. You would like to collect some mercury for your homemade perpetuum mobile machine. How many moles of mercury can you get you collect and process the entire volume of 1250 m3 of the water in the pond?
The number of moles of mercury can you get you collect and process the entire volume of 1250 m3 of the water in the pond is 8.7 × 10^-5 moles.
First, we must convert the concentration of mercury in the pond to molar concentration using the relation;
Mass concentration = Molar concentration × molar mass
Molar concentration = Mass concentration /molar mass
Molar mass of mercury = 201 g/mol
Molar concentration = 14 × 10^-9 g/201 g/mol = 6.97 × 10^-11 M
Volume of solution = 1250 m3 or 1250000 L
Number of moles = concentration × volume
Number of moles = 6.97 × 10^-11 M × 1250000 L
Number of moles = 8.7 × 10^-5 moles
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How is hot spot and ring of fire similar
Answer:The plates are not fixed but are constantly moving atop a layer of solid and molten rock called the mantle. The Ring of Fire is a string of volcanoes and sites of seismic activity, or earthquakes, around the edges of the Pacific Ocean. ... A hotspot is a place in the middle of a tectonic plate where hot magma rises.
Explanation:
The sun, fire, lightnings and fireflies are all
Answer:
Natural source of light
Explanation:
Please Mark Me Brainlest Me#CarryOnLearningA balloon with an initial volume of 3.1 L at a temperature of 193 K is warmed to 374 K.
What is its volume at the final temperature? (Assume constant temperature.)
Answer:
New volume = 6.0L
Explanation:
Make a list of variables given in the question, and what we want to find:
Initial volume (L) = Vi = 3.1
Initial temperature (K) = Ti = 193
New temperature (K) = Tn = 374
New volume (L) = Vn
We have volumes and temperatures given and we're talking about gas, the equation including both these variables that should come to mind is the ideal gas equation:
PV = nRT
P = pressure (Pa)
n = number of moles
R = gas constant = 8.31
Now, we construct an equation we can solve to get the new volume:
P(Vn) = nR(Tn)
And insert the values we know:
P(Vn) = n(8.31)(374)
P(Vn) = n·3107.94
The equation contains 3 unknown variables;
We should first try to see if we can eliminate the 2 we are not interested in, namely P and n;
What we should recognise is that the pressure and number of moles will not change upon warming the balloon;
Firstly, heating the gas inside the balloon doesn't add anything to the balloon, i.e. doesn't increase the moles of gas, it simply raises the energy of the gas particles already within the balloon, so n will not change;
Secondly, I think there is a mistake in the question, it should read "assume constant pressure" in the brackets, since the temperature does change, which we are told;
Also, we can assume normal atmospheric pressure inside and outside the balloon as would be the case ordinarily;
What we want to do with this information is rearrange the equation we constructed to have these 2 constant or unchanging variables on one side and everything else on the other, so:
[tex]\frac{P}{n} = \frac{3107.94}{V_{n} }[/tex]
Next, we construct an equation for the balloon before warming:
P(Vi) = nR(Ti)
P(3.1) = n(8.31)(193)
P·3.1 = n·1603.83
Once again, rearrange to get P and n on one side of the equation and everything else on the other:
[tex]\frac{P}{n} = \frac{1603.83}{3.1} \\\\ \frac{P}{n} = 517.364516[/tex]
Now, we have two equations for P/n, we can eliminate P/n since both these values remain the same before and after warming the balloon as previously established:
[tex]\frac{3107.94}{V_{n} } = \frac{P}{n} = 517.364516 \\\\ \frac{3107.94}{V_{n} } = 517.364516 \\\\[/tex]
Now, rearrange and solve for Vn:
[tex]\frac{3107.94}{V_{n} } = 517.364516 \\\\ V_{n} = \frac{3107.94}{517.364516} \\\\ V_{n} = 6.00725...[/tex]
Vn = 6.0L
