I assume the curve is flat and not banked. A car making a turn on the curve has 3 forces acting on it:
• its weight, mg, pulling it downward
• the normal force from contact with the road, n, pushing upward
• static friction, f = µn, directed toward the center of the curve (where µ is the coefficient of static friction)
By Newton's second law, the net forces on the car in either the vertical or horizontal directions are
∑ F (vertical) = n - mg = 0
∑ F (horizontal) = f = ma
where a is the car's centripetal acceleration, given by
a = v ²/r
and where v is the maximum speed you want to find and r = 25 m.
From the first equation, we have n = mg, and so f = µmg. Then in the second equation, we have
µmg = mv ²/r ==> v ² = µgr ==> v = √(µgr )
So the maximum speed at which the car can make the turn without sliding off the road is
v = √(0.80 (9.80 m/s²) (25 m)) = 14 m/s
I need a short answer ?
Answer:
Explanation:
7a) t = d/v = 100/45cos14.5 = 2.29533...= 2.30 s
7b) h = ½(9.81)(2.29533/2)² = 6.46056... = 6.45 m
or
h = (45sin14.5)² / (2(9.81)) = 6.47 m
which rounds to the same 6.5 m when limiting to the two significant digits of the initial velocity.
What is Acceleration?
Answer:
Depends on what are you looking at. All of the following are valid definitions, it just depends on which way you are analizing the problem.
From a kinematics point of view:
Acceleration is, by definition, is a vector quantity that measures the rate of change of the rate of change in position (add brackets if it helps visualizing the idea). This leads to the following different definitions - which are more like means of calculating it
the second derivative of position with respect to time [tex]a = \ddot x= \frac{d}{dt}({\frac d{dt}} x)[/tex];the first derivative of velocity with respect to time [tex]a = \dot v = \frac d{dt} v[/tex].From a dinamics point of view
Acceleration is the effect of a force applied to a body, and measures the ratio of the force applied to a body of mass m and the mass itself (which is another formulation of Newton second law):
[tex]a = \frac Fm[/tex]
Acceleration is the rate of change of velocity
To define acceleration, We need to know more about motion.
Motion: This can be defined as the change in position of a body from one point to another. When an object accelerates, it undergoes motion.
Definition
Acceleration can be defined as the rate of change of velocity. The S.I unit of acceleration is meter-per-squared seconds. (m/s²)
The formula of acceleration is
a = (v-u)/t................. Equation 1⇒ Where:
a = accelerationu = initial velocityv = final velocityt = timeHence, Acceleration is the rate of change of velocity
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Question 4 of 10
What is thermodynamics?
A. The movement of matter
B. The flow of fluids
C. The movement of particles
D. The flow of energy, heat, and work
SUBMIT
Answer:
Explanation:
D.
Thermodynamics is the study of how different types of energy is transferred through the chemical systems
Answer: Thermodynamics is the flow of energy, heat, and work.
Explanation: This is seen in the formula for the first law of thermodynamics, U = Q - W, or “The change of the internal energy of a system (U) is equal to the heat absorbed (Q) minus the work done by that system (W).”
Gravity is what
A 0.98 N.
B 5N.
C 10 N.
D 100 N.
E none of the above
Answer:
C that's 10N I think. not sure though
9.The force of gravity between two asteroids is 10,000 newtons (N).
When the distance between the asteroids is halved, what will be the force of gravity between them?
Answer:
F1 = G m1 m2 / R^2 force of attraction
F2 = G m1 m2 / (R/2)^2
F2 / F1 = 4 the force of gravity will be quadrupled
Answer This!!!!!!
I'll give brainliest to whoever gets it right.
Answer:
yes the answer is C. 32.16
A 1200 kg car moves due north with a speed of 15m/s. An identical car moves due east with the same speed of 15m/s what are the direction and the magnitude of the system’s total momentum
a.
The direction of the total momentum is 45°
The momentum of the first car is given by p = mv where m = mass of car = 1200 kg and v = velocity of car = 15 m/sj (since it moves due north).
So, p = mv
= 1200 kg × (15 m/s)j
= (18000 kgm/s)j
Also, the momentum of the identical car, p' = mv' where m = mass of car = 1200 kg and v' = velocity of car = (15 m/s)i (since it moves due east).
So, p' = mv'
= 1200 kg × (15 m/s)i
= (18000 kgm/s)i
So, the total momentum of the system P = p + p'
= (18000 kgm/s)j + (18000 kgm/s)i
= (18000 kgm/s)i + (18000 kgm/s)j
The direction of the total momentum of the system P is gotten from
tanФ = p'/p
= 18000 kgm/s ÷ 18000 kgm/s
= 1
Ф = tan⁻¹(1)
= 45°
The direction of the total momentum is 45°
b.
The magnitude of the total momentum of the system is 25455.84 kgm/s
The magnitude of the total momentum of the system P = √(p'² + p²)
= √[(18000 kgm/s)² + (18000 kgm/s)²]
= (18000 kgm/s)√(1 + 1)
= (18000 kgm/s)√2
= 25455.84 kgm/s
The magnitude of the total momentum of the system is 25455.84 kgm/s
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Fireworks have a very high reaction rate. Describe and explain what could be done to slow down their reaction.
Answer:
Don't light up the firework or put less fire
Explanation:
Using Pharaoh's serpent or "black snake" firework could be done to slow down their reaction.
What are fireworks chemically?Gunpowder is typically made using three reagents: potassium nitrate, carbon, and Sulphur. These kinds of elements are used in a combustion reaction that results in this detonation explosion. You have solid reagents reacting to produce gases in the form of solid potassium carbonate, solid potassium sulphate, nitrogen gas, and carbon dioxide gas.
The numerous metal salts that are added to produce the colours spread out all of that material, which is in a super-heated state. In such extremely intense environment, the metal salts heat up and get "excited," emitting light as a result.
If you want an explosion, you need the chemical reaction to go quickly in order to release a large volume of gas in a brief period of time. You might have a chemical reaction that happens rather slowly, like the Pharaoh's serpent or "black snake" firework.
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Which object would have more momentum?
A 2 kg ball rolling at 4 m/s
A 5 kg ball rolling at 2 m/s
(Hint: Use momentum = mass * velocity)
a
Not enough information to determine which ball has more momentum.
b
They have the same momentum.
c
The 2 kg ball will have more momentum.
d
The 5 kg ball will have more momentum.
Answer:
b is the ans......
Explanation:
"b" (and any subsequent words) was ignored because we limit queries to 32 words.
When a baseball curves to the right (a curveball) , air is flowing faster over the right side than over the left side. at the same speed all around the baseball, but the ball curves as a result of the way the wind is blowing on the field. faster over the left side than over the right side. faster over the top than underneath.
Answer:
faster over the left side than over the right side.
Explanation:
due to ball rotation, the right side is more closely matched to the speed of the air passing by as the ball progresses. This causes the air to stick more closely to the right side of the ball and that air stays with the ball surface as the spin moves it to the back of the ball and therefore leftward. As every action has an equal and opposite reaction the leftward force moving air causes the ball to experience an equal rightward force.
When the baseball curves to the right (a curveball), then the ball moves faster over the left side than over the right side.
What direction does a curveball move?The ball, which is thrown with a spin, is curve in the direction in which the front of the ball turns.
When a baseball curves to the right (a curveball),
For this condition, the pressure of air should be high on the left side than the pressure on right side.Molecules of the air on right side pushed backward by this spinning ball.The left side with high pressure push the ball towards right side where the pressure is low.Due to higher pressure, the ball move faster on the left side than the right side.Hence, when the baseball curves to the right (a curveball), then the ball moves faster over the left side than over the right side.
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Based on the law of conservation of mass, if approximately 20g of water reacts in the following equation,
producing about 15g of oxygen, what mass of hydrogen (H2) was produced in this reaction?
2H20
2H2 + O2
Answer: H2O2
Explanation:
First, calculate the moles of H2O2 reacting. In order to do this, we must evaluate the relative molecular mass ( Mr ) of hydrogen peroxide
Section 1: Basic Energy Relationships
1. Click/tap the Start button and observe the motion. View the bar
charts and the velocity value as the coaster car moves. Complete
the following paragraph by entering total mechanical energy
(ME), kinetic energy (KE), and potential energy (PE). The
labeled locations refer to the graphic at the right.
As the coaster car rolls down the track from A to E, the
________ values decrease and the _______ value
increase and the ________ values remain constant. The
_______ is greatest at point A and smallest at point E.
However, the _______ is smallest at point A and largest
at point E.
Section 2: Hill Design
2. Click/tap on the Bumps tab at the top of the
Interactive. Then drag the grey circles to modify the
track so that it looks like the track design at the right.
Pay attention to the background grid to help with the
design. Note that Dot G is at the same height as Dot E;
make sure that the same is true of your final design.
3. Run the simulation. Does the coaster car travel as high
as point H? ___________ Give an explanation for why
it does or doesn't reach point H.
As the coaster car rolls down the track from A to E, the potential energy values decrease and the kinetic energy value increase and the total mechanical energy values remain constant. The potential energy is greatest at point A and smallest at point E. However, the kinetic energy is smallest at point A and largest at point E.
According the principle of conservation of mechanical energy, as the potential energy decreases, the kinetic energy increases.
[tex]P.E + K.E = M.A[/tex]
At point A, the coater has maximum potential energy.
At point E, the coaster has maximum kinetic energy.
We can fill the blanks as follows;
As the coaster car rolls down the track from A to E, the potential energy values decrease and the kinetic energy value increase and the total mechanical energy values remain constant. The potential energy is greatest at point A and smallest at point E. However, the kinetic energy is smallest at point A and largest at point E.
Based on the principle of conservation of mechanical energy, if the second simulation occurs at the same condition as the first, the height reached by coaster will be same.
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The 0.15kg baseball has a speed of v=30 m/s just before it is struck by the bat. It then travels along the trajectory shown before the outfielder catches it. Determine the magnitude of the average impulsive force imparted to the ball if it is in contact with the bat for 0.75 ms
The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N
The mass of the baseball, m = 0.15 kg
The speed at which it moves, v = 30 m/s
Time at which the baseball was in contact with the bat, t = 0.75 ms
t = 0.75/1000 s
t = 0.00075 s
The impulsive force is given by the formula:
[tex]F=\frac{mv}{t}[/tex]
Substitute m = 0.15 kg, v = 30, and t = 0.00075s into the formula above:
[tex]F=\frac{0.15 \times 30}{0.00075} \\\\F=6000N[/tex]
The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N
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Why does the earth stay in orbit around the sun instead of drifting away from it into space?
A Electric force between the Sun and Earth
B Magnetic force between the Sun and Earth
Gravitational force between the Sun and Earth
Answer:
b it is b part answer i think so
Hey there!
having a question which is from ( JEE Advanced 2014 )
[tex]\huge\color{black}\boxed{\colorbox{pink}{Question♡}}[/tex]
A rocket is moving in a gravity free space with a constant acceleration of 2 −2 along +x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in +x direction with a speed of 0.3 −1 relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 −1 from its right end relative to the rocket. The time in seconds when the two balls hit each other is?
[tex] \\ \\ [/tex]
proper explanation needed~
thankyou~
The time taken for the two balls to hit each other is 8 s.
The given parameters:
Acceleration of the rocket, a = 2 m/s²Length of the chamber, s = 4 mSpeed of the first ball, = V1 = 0.3 m/sSpeed of the second ball, V2 = 0.2 m/sThe time taken for the two balls to hit each other is calculated by applying relative velocity formula as shown below;
[tex](V_1 - (-V_2) )t = s\\\\(V_1 + V_2) t = s\\\\(0.3 + 0.2) t = 4\\\\0.5t = 4\\\\t = \frac{4}{0.5} \\\\t = 8 \ s[/tex]
Thus, the time taken for the two balls to hit each other is 8 s.
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1. In Newton's cannonball experiment, if the velocity is larger than the orbital velocity the Cannon
ball will
1. stay in orbit
2. fall to the earth
3. escape the earth
4. none of the above
Answer:
escape the earth I think
In Newton's cannonball experiment, is the velocity is larger than the orbital velocity the Cannon ball will escape the Earth. Thus, the correct option is 3.
What was Newton's Cannonball experiment?
In this experiment, Newton visualizes a stone that is a cannonball which is being projected on top of a very high mountain. And, if there were no gravitational force or air resistance in that area, the body should follow a straight line path away from the Earth, in the direction in which it was projected.
If the cannonball is launched at a velocity that matches the orbital velocity of the planet, then it will not be able to be drawn in by gravitational force due to the Earth which results into moving away from the cannonball at the same speed at which the cannonball itself is falling.
If the velocity of the cannonball is larger than the orbital velocity than the ball will escape the Earth.
Therefore, the correct option is 3.
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The surface temperature of our sun is about 5800 K, and the peak of its intensity curve is in the middle of the visible spectrum. Mammals have a body temperature of about 310 K. A star that appears reddish could have a surface temperature of:
Explanation:
i expected to use Stefan's law of heat exchange but the value you gave aren't conclusive.
I should say that the temperature of the star should be close to that of the sun because of the similarity in the intensity curves
I need ideas of what kind of simple motor i can build and how i can build it. The simple motor MUST spin without using your own force. What materials would i use and how would i create it. what would i create
Answer:
i don't know but my father i think he can't answer this
Chronic diseases are also know as
Answer:
Chronic Condition or Long-term Illness
Explanation:
They can also be known as Chronic Conditions or Long-Term Illnesses, hope this helps.
Answer:
Chronic condition, also called long-term condition.
Explanation:
Please help
According to the seismograph recording of an earthquake shown above, we can conclude the following about this particular earthquake:
A.) The P-waves arrived at 24 min, the S- waves arrived at 27 min, the P-waves had a larger amplitude than the S- waves, and therefore the P- waves carried more energy than the S-waves.
B.) The P-waves arrived at 24 min, the S-waves arrived at 27 min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
C.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27 min, the P-waves had a larger amplitude than the S-waves, and therefore the P- waves carried less energy than the S-waves.
D.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
Answer:
don't know ....?
Explanation:
Please help
According to the seismograph recording of an earthquake shown above, we can conclude the following about this particular earthquake:
A.) The P-waves arrived at 24 min, the S- waves arrived at 27 min, the P-waves had a larger amplitude than the S- waves, and therefore the P- waves carried more energy than the S-waves.
B.) The P-waves arrived at 24 min, the S-waves arrived at 27 min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
C.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27 min, the P-waves had a larger amplitude than the S-waves, and therefore the P- waves carried less energy than the S-waves.
D.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.
Challenge
Marks: 1
How much energy is transferred by a 500 watt heater that is on for 2
minutes?
Answer:
Explanation:
500 W = 500 J/s
500 J/s(2 min(60 s/min) = 60000 J
Describe a vibration that is not periodic. NO LINKS PLEASE
Answer:
1)The position change of almost any manually operated room light switch.
2) Sunlight striking a point on the ground on a partly cloudy and windy day
Explanation:
The primary evidence that has led astronomers to conclude that the expansion of the universe is accelerating comes from __________.
The Universe is often studied by Scientist. The primary form of evidence that has led astronomers to conclude that the expansion of the universe is accelerating is the Observations of white dwarf supernovae.
There was the discovery of the faintness of high-redshift Type I supernovae by a team of scientist which showed that the expansion of the universe is accelerating.
The key evidence for that made scientist to talk about the expansion of the universe is accelerating comes from viewing and studying of white dwarf supernovae. It has been found that most distant stars all orbit at approximate speed as stars found about 30,000 light-years from their center.
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Four men are pushing on a broken car. One man pushes on the car with 345 N, another with 203 N, another
with 291 N and 101 N. The friction between the car and road pushes in the opposite direction with a force of 940 N.
1.) Make a claim: What is the net force on the car?
2.) Cite evidence: What evidence supports your claim?
3.) Make a claim: Will the car move?
4.) Provide reasoning: Why do you say that?
Answer:
1. 3 N
2. The total force being put on the car by the men is 943 while the friction is going in the opposite direction with a force of 940.
3. Yes
4. The net force is not equal to zero
Explanation:
1. 345 + 203 + 291 + 101 = 943 + -940 = 3
The slope of a line on a distant-time graph is
A. distance
B. time
C. speed
Answer:
c. speed
Explanation:
In a distant-time graph the x value is usually the time and the y value is usually the distance.
If slope is the change in y over the change in x, on a distant time graph the slope would be the change in time over the change in distance
Or time / distance.
Time / distance happens to calculate speed.
Thus, the slope of a line on a distant-time graph is speed.
[tex]\huge\textbf{Hey there!}[/tex]
[tex]\large\textbf{The formula for Slope of a line is: }\mathbf{m = \dfrac{rise}{run}}\large\textbf{ whereas it is}\\\large\textbf{equal to/equivalent to }\mathbf{ \dfrac{y_2 - y_1}{x_2- x_1} \ .}\\\\\large\textbf{Basically, the slope of the line is measured with its }\\\large\textbf{\underline{steepness}. The word steepness simply means a}\\\lage\textbf{very sharp slope.}[/tex]
[tex]\large\textbf{On slope of a line on distant-time graph is basically how }\\\large\textbf{ \boxed{\bf FAST} a particular object is.}[/tex]
[tex]\large\textbf{Now, that we got that information out of the way we}\\\large\textbf{can find out our answer.}[/tex]
[tex]\large\textbf{The formula for distance is: }\mathbf{d= \sqrt{(x_2 - x_1)^2 + (y_2 +y_1)^2}}}[/tex]
[tex]\large\textsf{We cannot say that OPTION A isn't your answer because you}\\\large\textsf{cannot calculate slope of a line on a distant-time graph. You}\\\large\textsf{cannot calculate the speed of the object by using that formula.}\\\large\textsf{So, this eliminates Option A. as your answer.}[/tex]
[tex]\large\textbf{The formula of time is: }\mathbf{time = \dfrac{distance}{speed}}[/tex]
[tex]\large\textsf{Yes, it calculates the distance but it doesn't calculate how fast a(n)}\\\large\textsf{object is going. So this eliminates Option B. as your answer.}[/tex]
[tex]\large\textsf{The formula for speed is: }\mathbf{s = \dfrac{d}{t}}\large\textbf{ whereas s = \underline{speed}, }\\\large\textsf{d = \underline{distance} you have \underline{traveled}, \& t = \underline{time} that has}\\\large\textsf{been \underline{elapsed}.}\\\large\textsf{Option C. could possibly be your answer}[/tex]
[tex]\large\textbf{Option C. seems to be the closes to your result than the}\\\large\textbf{to your answer.}[/tex]
[tex]\large\boxed{\text{Therefore, your answer should be: \boxed{\textbf{Option C. Speed}}}}\huge\checkmark[/tex]
[tex]\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
at room tmeperature none of the metals are
What metal is not at room temperature?
Mercury is a metallic chemical element that is an only metal that is not a solid at room temperature.
A 60.0 kg person jumps onto the floor from a height of 3.0m. Find
the KE of the jumper when she hits the ground.
Answer:
1800 J
Explanation:
GPE= mgh
60*3*10
=1800 J
The columns in the periodic table are called groups. What do the elements in group 18 have in common
A. They are found only in compounds in nature
B. They tend to form ions of a -1 Electric charge
C. They tend to form ions with a +1 electric charge
D. They rarely react with any other elements
Answer: D
Explanation:
they are all odorless, colorless, monatomic gases with very low chemical reactivity.
Brainliest?
The elements in group 18 that they rarely react with any other elements. The correct option is D.
What is periodic table?The periodic table, also known as the periodic table of the elements, is an arrangement of chemical elements in rows and columns.
It is widely used in chemistry, physics, and other sciences, and is widely regarded as a chemistry icon.
The periodic table is worked upon by scientists to quickly refer to information about an element, such as its atomic mass and chemical symbol.
The arrangement of the periodic table also allows scientists to detect trends in element properties such as electronegativity, ionization energy, and atomic radius.
The noble gases are found at the far right of the periodic table and were previously known as "inert gases" due to their filled valence shells, which make them extremely nonreactive. In comparison to other element groups, noble gases were discovered relatively late.
Thus, the correct option is D.
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Magma usually stays below the Earth's
under great pressure.
o mantle
Inner core
outer core
Crust
Answer:
In the inner vote part of the earth
just this last one!!
A car slams on its brakes creating an acceleration of -4.7 m/s^2. It comes to rest after traveling a distance of 235 m. What was its velocity before it began to accelerate?
Answer:
[tex]47 \ \frac{m}{s}[/tex]
Explanation:
s = displacement (m)
u = initial velocity [tex](\frac{m}{s})[/tex]
v = final velocity [tex](\frac{m}{s})[/tex]
a = acceleration [tex](\frac{m}{s^{2} })[/tex]
t = time (s)
s = 235
a = -4.7
v = 0
v² = u² + 2as
(0)² = u² + 2(-4.7)(235)
u² - 2209 = 0
u² = 2209
u = 47
Answer:
[tex]\boxed {\boxed {\sf 47 \ m/s}}[/tex]
Explanation:
We are asked to find the initial velocity of the car before it began to accelerate.
We are given the acceleration, distance, and final velocity, so we will use the following kinematic equation:
[tex]{v_f}^2 = {v_i}^2 + 2ad[/tex]
The car's acceleration is -4.7 meters per second square. It traveled a distance of 235 meters. It came to rest, or a final velocity of 0 meters per second.
a= -4.7 m/s²d= 235 m [tex]v_f[/tex]= 0 m/sSubstitute the values into the formula.
[tex](0 \ m/s)^2 = {v_i}^2 + 2 (-4.7 \ m/s^2)(235 \ m)[/tex]
[tex]0 = {v_i}^2 + 2 (-4.7 \ m/s^2)(235 \ m)[/tex]
Multiply the numbers in parentheses.
[tex]0= {v_i}^2 + (-2209 \ m^2 / s^2)[/tex]
Add -2209 to both sides of the equation.
[tex]0+ 2209 \ m^2 /s^2 = {v_i}^2+ ( -2209 \ m^2 /s^2 )+ 2209 \ m^2 /s^2[/tex]
[tex]2209 \ m^2 /s^2 = {v_i}^2[/tex]
Take the square root of both sides.
[tex]\sqrt {2209 \ m^2 /s^2} = \sqrt {{v_i}^2[/tex]
[tex]\sqrt {2209 \ m^2 /s^2} = v_i[/tex]
[tex]47 \ m/s = v_i[/tex]
The inital velocity of the car was 47 meters per second.
