The molarity of a solution containing 150 mL of a 3.25 M sodium hydroxide ( NaOH ) solution after we add 275 mL more water is 1.14 M
Given that :
molarity of solution M1 = 3.25 M
volume of solution V1 = 150 mL
Molarity of solution M2 = ?
Volume of solution after dilution V2 = 150 mL + 275 mL = 425 mL
using the dilution law , we get :
M1 V1 = M2 V2
M2 = (M1 V1) / V2
M2 = ( 3.25 × 150 ) / 425
M2 = 1.14 M
Thus, The molarity of a solution containing 150 mL of a 3.25 M sodium hydroxide ( NaOH ) solution after we add 275 mL more water is 1.14 M
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