What is the molarity of a solution containing 150 mL of a 3.25 M sodium hydroxide
(Na0H) solution after we add 275 mL more water?

Answers

Answer 1

The molarity of a solution containing 150 mL of a 3.25 M sodium hydroxide ( NaOH ) solution after we add 275 mL more water is 1.14 M

Given that :

molarity of solution M1 = 3.25 M

volume of solution V1 = 150 mL

Molarity of solution M2  = ?

Volume of solution after dilution V2 = 150 mL + 275 mL = 425 mL

using the dilution law , we get :

M1 V1 = M2 V2

M2 = (M1 V1) / V2

M2 = ( 3.25 × 150 ) / 425

M2 = 1.14 M

Thus, The molarity of a solution containing 150 mL of a 3.25 M sodium hydroxide ( NaOH ) solution after we add 275 mL more water is 1.14 M

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