The output voltage of a transformer is 40V.
What is an output voltage?An output voltage is the voltage released by a device, such as a voltage regulator or a generator.
The formula to calculate Output voltage of transformer is:
[tex]\frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }[/tex]
here, [tex]V_{s}[/tex] is the secondary voltage, [tex]V_{p}[/tex] is the primary voltage, [tex]N_{s}[/tex] is the number of secondary windings and [tex]N_{p}[/tex] is the number of primary windings.
According to the question.
[tex]N_{p}[/tex] =1200 , [tex]N_{s}[/tex]=200 , [tex]V_{p}[/tex]=240V ,[tex]V_{s}[/tex]= ?
By using the formula of Output voltage,
[tex]{V_{s} } = \frac{V_{p}N_{s} }{N_{p} }[/tex]
=[tex]\frac{240*200}{1200}[/tex]
[tex]=40V[/tex]
Therefore, 40V is the output voltage of a transformer.
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A stone is dropped from the top of a tower which touches the ground after 2 seconds. Calculate the speed of the stone hitting the ground surface. (g = 9.8 m/s²)
Answer:
19.6 m/s
Explanation:
The velocity is the product of acceleration and time.
__
Here, the acceleration is due to gravity.
v = at
v = (9.8 m/s²)(2 s) = 19.6 m/s
The stone hits the ground with a speed of 19.6 m/s.
A stone is dropped from the top of a tower which touches the ground after 2 seconds.
Calculate the speed of the stone hitting the ground surface. (g = 9.8 m/s²).[tex] \mathbb{SOLUTION:} [/tex][tex]v = u + at[/tex][tex]v = 9.8 m/s² x 2sec[/tex][tex]v = 19.6 \: m/ {s}^{2} [/tex]••••••••••••••••••••••••••••••••••••••••••••Hence, The stone hit the ground with the velocity speed of 19m/s².
- When you're solving velocity, you're determining how fast an object moves from its original position, with respect to a frame of reference, and a function of time.
- That means an object's velocity will be equal to the object's speed and direction of motion.
"Problem has been solve"
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An appliance draws 3 amperes at 120 V (plugged into the wall). If the same appliance is run with a 12 V car battery, how many amperes will it need?
The appliance is run with a 12 V car battery and the value of the electric current will be 0.3A.
What is electric current?The pace at which electrons travel through a conductor is known as electric current. The ampere is the SI unit for electric current.
From ohm's law;
Case 1;
V=IR
120 V = 3 A × R
R = 40 ohm
For the same appliances, the value of the resistance is the same;
Case 2;
V=IR
12 V = I × 40 ohm
I = 0.3 A
Hence the value of the current for case 2 will be 0.3 A.
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If a cup of coffee is at 90°C and a person with a body temperature of 36°C touches it, how will heat flow between
them?
O from the hand to the cup
from the cup to the hand
from the cup to the surrounding air
from the hand to surrounding air
Mark this and return
Save and Exit
ext
Submit
Answer:
if you pick it up the heat will flow to the hand until the Temperature of both evens out
5, the following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2, b=1m/s. Find
A, the average velocity of the particle in the time interval t1=2sec and t2=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
The average velocity is 4i m/sec
The average acceleration is 4i
What is a average velocity ?Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs. T
According to the question,
x=at²i + btj ( t is in second and x is in meter).
Average velocity = [tex]\frac{dx}{dt}[/tex]
[tex]\frac{dx}{dt} = 2at i + b j\\\\\frac{dx}{dt} = 2 * 2 * t i +1 j\\\\\frac{dx}{dt} = 4t i +j[/tex]
[tex]\frac{dx}{dt}[/tex] in the time interval of 2 to 3 sec is
at 2 sec,
[tex]\frac{dx}{dt} = 4 * 2 i +j = 8i +j[/tex]
at 3 sec ,
[tex]\frac{dx}{dt}[/tex] = 4 * 3 i + j = 12i+j
Therefore the average velocity is
[tex]\frac{(12i +j - 8i -j)}{(3-2)} = 4i[/tex]
The velocity at any given time is [tex]\frac{dx}{dt} = 4t i +j[/tex]
The acceleration at any given time is [tex]\frac{dx^2}{dt^2}[/tex]
[tex]\frac{dx^2}{dt^2} = 4 i[/tex]
The average acceleration in the time interval t₁=2sec and t₂=3sec
Average Acceleration = 4i
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Injuries occur from muscle imbalances which result from the body's inability to ....................... these types of stress.
Answer:
Tolerate
Explanation:
A spoon inserted in a half-filled cup of water appears crooked because as light travels into a substance with a lower index of refraction, it... Select one: a. does not bend. b. bends away from the normal. c. bends toward the normal. d. is reflected.
Explanation:
The light is bent away from the normal
Calculate the height of stairs a 60 kg student would have to run in order to burn off 1 Calorie of food energy, which is the equivalent of 4190 Joules.
The height of stairs a 60 kg student would have to run in order to burn off 1 Calorie of food energy will be 7.1 meters.
What is potential energy?The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.
Given data;
Mass of student,m = 60 kg
Energy,E = 4190 J
Height of stairs,h=?
The potential energy is mainly dependent upon the height of the object. The potential energy is found as;
Potential energy = mgh
E=mgh
h=E/mg
h= 4190 J / (60 kg× 9.81 m/s²)
h = 7.1 metre
Hence the height of the stairs will be 7.1 meters.
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A car headed north at 15.0 m/s experiences an acceleration of 2.50 m/s2 for 3.00 s. What is the final velocity of the car?
Answer:
i dond no can you put another question
Which of the following can be contracted from contact with bloodborne pathogens?
HIV can be contracted from contact with bloodborne pathogens.
Other bloodborne diseases are HBV, malaria, syphilis and brucellosis
What are bloodborne pathogens?Bloodborne pathogens can be defined as those microorganisms or pathogenic organisms that cause disease and are present in human blood.
Blood borne pathogens can also be contacted through the following means
Se- xual contactNeedle contactIn conclusion; HIV can be contracted from contact with bloodborne pathogens.
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Joe runs 10 m north, 20 m south, 9m south, and then 15 m north. What is Joe's
displacement?
Answer:
Joes displacement is 54m
Why is it important to remember "association, not
causation" when discussing correlations?
It is important to remember "association", instead of "causation" when discussing correlations because associations can be used to make predictions.
What is the value of associations in science?The associations among variables have a fundamental value in science because they can determine how such variables behave in hypothetical situations.
Moreover, correlation only indicates a type of association between variables and therefore it is less informative.
In conclusion, it is important to remember "association", instead of "causation" when discussing correlations because associations can be used to make predictions.
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A uniform electric field exist between two parallel plate seperated by 1.2 cm. The intensity of the field is 23 KN/C. What is the potential difference between the plates
Explanation:
this is the answer 276 volts
A pendulum bob executing simple harmonic motion has 2cm and 12Hz as amplitude and frequency respectively. Calculate the period of the motion
Answer:
Explanation:
The amplitude is extraneous information for this question.
Period (T) is simply a measure of time (how long it takes to complete a full cycle).
The frequency (f), is the reciprocal (how many cycles it can complete per unit of time).
The frequency reported is 12Hz. Hz is a unit meaning "cycles per second"
Thus 12cycles = 1second.
To find the number of seconds per cycle, simply create the other unit fraction and simplify:
[tex]T=\frac{1second}{12cycles}\\T=0.8\bar{3}\frac{seconds}{cycle}\\[/tex]
[tex]T=0.83seconds[/tex]
A 2.0-V battery is connected in a circuit with an ammeter and an unknown resistor, P. The current is observed to be 0.70 A. What would be the current in the circuit if a 12-V battery replaces the 2.0-V battery?
Answer:
4.2 A
Explanation:
V=IR
V= voltage
I= Current
R= resistance
so you will find the resistance in the circuit so
R= V/I
R=2V/0.70A
R=2.857 ohms ( TO THE NEAREST THOUSANDTH)
then you will find the current of the 12V battery using the resistance in the circuit
I=V/R
I=12/2.857
I=4.2A (TO THE NEAREST TENTH)
A single Oreo cookie provides 53 kcal of energy. An athlete does an exercise that involves repeatedly lifting (without acceleration) a 100-kilogram weight 2-decimeters above the ground with an energy efficiency of 25%. How many repetitions can she do with the energy supplied from a single Oreo cookie? What happens to the number of repetitions that can be done if the efficiency increases?
Answer:
Approximately [tex]325[/tex] (rounded down,) assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].
The number of repetitions would increase if efficiency increases.
Explanation:
Ensure that all quantities involved are in standard units:
Energy from the cookie (should be in joules, [tex]{\rm J}[/tex]):
[tex]\begin{aligned} & 53\; {\rm kCal} \times \frac{1\; {\rm kJ}}{4.184\; {\rm kCal}} \times \frac{1000\; {\rm J}}{1\; {\rm kJ}} \approx 2.551 \times 10^{5}\; {\rm J} \end{aligned}[/tex].
Height of the weight (should be in meters, [tex]{\rm m}[/tex]):
[tex]\begin{aligned} h &= 2\; {\rm dm} \times \frac{1\; {\rm m}}{10\; {\rm dm}} = 0.2\; {\rm m}\end{aligned}[/tex].
Energy required to lift the weight by [tex]\Delta h = 0.2\; {\rm m}[/tex] without acceleration:
[tex]\begin{aligned} W &= m\, g\, \Delta h \\ &= 100\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times 0.2\; {\rm m} \\ &= 196\; {\rm N \cdot m} \\ &= 196\; {\rm J} \end{aligned}[/tex].
At an efficiency of [tex]0.25[/tex], the actual amount of energy required to raise this weight to that height would be:
[tex]\begin{aligned} \text{Energy Input} &= \frac{\text{Useful Work Output}}{\text{Efficiency}} \\ &= \frac{196\; {\rm J}}{0.25} \\ &=784\; {\rm J}\end{aligned}[/tex].
Divide [tex]2.551 \times 10^{5}\; {\rm J}[/tex] by [tex]784\; {\rm J}[/tex] to find the number of times this weight could be lifted up within that energy budget:
[tex]\begin{aligned} \frac{2.551 \times 10^{5}\; {\rm J}}{784\; {\rm J}} &\approx 325 \end{aligned}[/tex].
Increasing the efficiency (the denominator) would reduce the amount of energy input required to achieve the same amount of useful work. Thus, the same energy budget would allow this weight to be lifted up for more times.
In the following word completion task: carrot, peas, corn, b_____, most people would answer “beans” (instead of “beetle” for example) even though there were no instructions on how to do this task. The psychological reason we made the assumption that the blank word was related to the previous words is due to
Answer:
Explanation:
Wow, I said 'beets'..... I must be weird.
The value of acceleration due to gravity (g) on Pluto is about 0.61 meters/second2. How much will an object that weighs 250 newtons on Earth weigh on Pluto? Note that the value of acceleration due to gravity on Earth is 9.8 meters/second2.
The weight of the object on pluto will be 15.56 N
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Given data;
[tex]\rm g_e[/tex] is the acceleration due to gravity on earth.
m is the mass of an object
[tex]\rm g_p[/tex] is the acceleration due to gravity on pluto.
[tex]\rm W_e[/tex] is the weight of the object on earth
[tex]\rm W_ p[/tex] is the weight of an object on pluto
The mass of the object on the earth's surface is found as;
We = m × ge
m = W / ge
m = 250 / 9.81
m = 25.51 kg
The weight of the object on pluto.
Wp = m × gp
Wp = 25.51 kg × 0.61 m/s²
Wp =15.56 N.
Hence the weight of the object on pluto will be 15.56 N
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Answer: B.
15.6 newtons
Explanation: edmentum
a highway curve has a radius of 300 m. at what angle should it be banked for a traffic speed of 100 km/h
The angle at which it should be banked for a traffic speed of 100 km/h is
14.57°.
How do find the angle of Banking of road?Banking of roads is the practice of raising the outer borders of curving roads over the inner edge in order to give vehicles the necessary centripetal force to make a turn safely.Skidding can be prevented by banking.The banking of roadways aids in preventing toppling or overturning.To find the angle of banking following formula can be used,
[tex]tan \alpha = v^{2} /rg[/tex]
Given v = 100km/h or
= 100 x 1000 / 3600
= 27.7 m/s
Hence,
[tex]tan \alpha = (27.7)^{2} / 300 * 9.81[/tex]
[tex]tan\alpha = 0.26[/tex]
[tex]\alpha = tan^{-1} 0.26[/tex]
[tex]\alpha = 14.57[/tex]°
Hence, the angle of banking of the road will be 14.57°
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Where is the body or mass in the water when the buoyant force is equal to the weight of the mass? Does it float up, or down or in the middle?
Answer:
it will float
Explanation:
according to Archimedes' principle, if the buoyant force is equal to the weight of the mass of the object, the object will float
1. If the amplitude of a vibrating mass attached to the free end of an ideal spring is
25 cm, then the mass in one period travels 'a distance:
a) 1m
b) 0
c) 25m
The mass in one period travels 'a distance less than 25 cm which will be 0.
What is amplitude of a pendulum?
The amplitude of a pendulum is the maximum displacement of the pendulum.
If the maximum displacement of the pendulum is 25 cm, the mass in one period travels a distance less that 25 cm.
Thus, then the mass in one period travels 'a distance less than 25 cm which will be 0.
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The high point of the ripple seen in a pond after throwing in a pebble is the...
Select one:
a. crest.
b. trough.
c. wavelength.
d. A & B
The crest is the highest point of a pebble-induced ripple in a body of water. Option a is correct.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength. The highest point of the wave is the crest, while the trough is the lowest.
The high point of the ripple seen in a pond after throwing in a pebble is the crest.
Hence option a is correct.
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You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, it accelerates because the engines are at full throttle and because there is a catapult that propels the jet forward. You begin to wonder how much force is supplied by the catapult. You look on the Web and find that the flight deck of an aircraft carrier is about 90.0 m long, that an F-14 has a mass of 24800 kg, that each of the two engines supplies 27000 lb of thrust, and that the takeoff speed of such a plane is about 158 mi/h. Estimate the average force on the jet due to the catapult.
You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, the average force on the jet is due to the catapult is mathematically given as
What is the average force on the jet is due to the catapult?
Generally, the equation for acceleration is mathematically given as
[tex]a=\frac{vf^2-vi^2}{2s}\\\\\Therefore\\\\a=\frac{69.29^2-0^2}{2(90}\\\\a=26.673m/s^2[/tex]
In conclusion, The force
F=m*a
F=15100*26.673
F=40272.3N
F 402 KN
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An arrow is shot horizontally from the top of a building and it lands 200m from the foot of the building after 10s.Assuming air resistance is negligible,calculate the initial velocity of the arrow and the height of the building?
Need an answer urgently please
The initial velocity of the arrow and the height of the building will be 29.05 m/s² and 781 m respectively.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is;
u is the initial velocity of fall = ? m/sec
h is the distance of fall = 200 m
g is the acceleration of free fall = 9.81 m/sec²
H is the height of the building
t is the time period = 10 second
According to Newton's second equation of motion,
[tex]\rm h= ut+\frac{1}{2} gt^2 \\\\\ h-\frac{1}{2} gt^2 =ut \\\\ 200 - 0.5 \times(9.81) \times 10^2 = 10 u \\\\ u = - 29.05 \ m/sec[/tex]
- ve shows the direction is downward.The magnitude of the initial velocity is found as;
u = 29.05 m/sec
The height of the building
[tex]\rm H= ut+\frac{1}{2} gt^2 \\\\\ H = 29.05 \times 10 + 0.5 \times 9.81 \times 10^2 \\\\ H = 781 \ m[/tex]
Hence the initial velocity of the arrow and the height of the building will be 29.05 m/s² and 781 m respectively.
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Part A
Calculate the spring constant.
• Look at the graph of x vs. t graph. (You may want to double-click on
it to examine it in the Data Tool view.)
. From the graph, determine the period T.
• The first video frame lists the mass.
• Use the equation below to solve for the spring constant k. Show
your work below.
m
T = 2π√√T
Answer:
Using 3 periods to get an accurate reading:
3T = (6.40 S - 0.90 s) = 5.50 S So, T = 1.83 s
m = 0.250 kg
Using algebra:
k= [tex]\frac{4\pi ^{2}m }{T^{2} }[/tex]=[tex]\frac{4\pi ^{2}0.250 }{1.90^{2} }[/tex]=2.95kg/sec
state how the centripetal force is provided in a c held on a playground roundabout
The centripetal force is obtained by its formulas is,[tex]\rm F_C= \frac{mv^2}{r}[/tex]
What is centripetal acceleration?The acceleration needed to move a body in a curved way is understood as centripetal acceleration.
The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.
The formula for the centripetal force is ;
[tex]\rm F_C= \frac{mv^2}{r}[/tex]
Where,
r is the radius
v is the linear speed
m is the mass of an object
Hence, the centripetal force obtained by its formulas as,[tex]\rm F_C= \frac{mv^2}{r}[/tex]
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A diver shines a light up to the surface of a flat glass-bottomed boat at an angle of 37◦ relative to the normal. If the indices of refraction of air, water, and glass are 1.0, 1.33, and 1.4 respectively, at what angle does the light leave the glass (relative to its normal)? Answer in units of ◦ .
Answer:
Approximately [tex]53^{\circ}[/tex], assuming that the upper and lower surfaces of the glass on this boat are parallel.
Explanation:
Assume that the upper and lower surfaces of the glass at the bottom of this ship are parallel. Refer to the diagram attached. The two normals would also be parallel to each other.
The following angles would be alternate interior angles between the two normals:
The angle at which the light enters the glass, andThe angle at which the light leaves the glass.Since the two normals are parallel to each other, these two angles would have the same value. Let [tex]\theta_{\text{glass}}[/tex] denote the value of both of these angles.
Let [tex]\theta_{\text{src}}[/tex] denotes the angle at which a beam of light leaves the original medium (angle of incidence.) Let [tex]\theta_{\text{dst}}[/tex] denote the angle at which this beam of light enters the new medium.
Let [tex]n_\text{src}[/tex] and [tex]n_\text{dst}[/tex] denote the refractive indices of the original and the new medium, respectively. By Snell's Law:
[tex]\begin{aligned}\frac{\sin(\theta_{\text{dst}})}{\sin(\theta_{\text{src}})} = \frac{n_{\text{src}}}{n_{\text{dst}}}\end{aligned}[/tex].
Let [tex]\theta_{\text{water}}[/tex] denote the angle at which the beam of light in this question leaves the water. Let [tex]\theta_{\text{air}}[/tex] denote the angle at which this beam of light enters the air. It is given that [tex]\theta_{\text{water}} = 37^{\circ}[/tex], while [tex]\theta_{\text{air}}[/tex] is the value that needs to be found.
Let [tex]n_{\text{air}}[/tex], [tex]n_{\text{water}}[/tex], and [tex]n_{\text{glass}}[/tex] denote the refractive index of air, water, and glass, respectively. By Snell's Law:
[tex]\begin{aligned}\frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})} = \frac{n_{\text{water}}}{n_{\text{glass}}}\end{aligned}[/tex].
[tex]\begin{aligned}\frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} = \frac{n_{\text{glass}}}{n_{\text{air}}}\end{aligned}[/tex].
Thus:
[tex]\begin{aligned} & \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})}\times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} \\ =\; & \frac{n_{\text{water}}}{n_{\text{glass}}}\times \frac{n_{\text{glass}}}{n_{\text{air}}} \\ =\; & \frac{n_{\text{water}}}{n_{\text{air}}}\end{aligned}[/tex].
Since [tex]\theta_{\text{water}} = 37^{\circ}[/tex]:
[tex]\begin{aligned} & \sin(\theta_{\text{air}})\\ =\; & \sin(\theta_{\text{water}}) \times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \sin(\theta_{\text{water}})\times \frac{n_{\text{water}}}{n_{\text{air}}} \\ =\; & \sin(37^{\circ}) \times \frac{1.33}{1.0} \\ \approx \; & 0.800 \end{aligned}[/tex].
Therefore:
[tex]\begin{aligned}\theta_{\text{air}} &= \arcsin(\sin(\theta_{\text{air}})) \\ & \approx \arcsin(0.800) \\ &\approx 53^{\circ} \end{aligned}[/tex].
In other words, this beam of light would leave the glass at approximately [tex]53^{\cic}[/tex] from the normal.
Please help me!!
1. For objects like insulators (plastics), they can get charged by ___.
2. For metals, where there are more loosely bound electrons, they can get charged without contact by ___.
3. For metals, they can also be charged by direct contact by ___.
Select the correct answer.
What is the average velocity of the particle from rest to 9 seconds?
The average velocity of the particle from rest to 9 seconds would be 2 meters/sec.
How to find the average velocity?This average velocity can be calculated with the following equation:
v = dx / dt
where:
dx = displacement = 18 meters
dt = interval of time = 9 seconds
Substitute;
v = dx / dt
v = 18 / 9
v = 2 meters/sec
Hence, the average velocity of the particle from rest to 9 seconds would be 2 meters/sec.
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What is the magnitude of the force exerted on an electron in an electric field with a strength of 6.5 *10^ 8 N/C? Remember, the charge on an electron is 1.6 * 10 ^ - 19 * C
All work must be shown to earn credit
The field exerts 6.5 x 10⁸ Newton of force on EACH COULOMB of charge in the field.
We're putting 1.6 x 10⁻¹⁹ Coulomb of charge into the field.
The force on it will be
(1.6 x 10⁻¹⁹ Coulomb) x (6.5 x 10⁻⁸ Newton/Coulomb).
That's 1.04 x 10⁻¹⁰ Newton.
What is the magnetic force on a proton that is moving at 5.2 x 107 m/s to the
right through a magnetic field that is 1.4 T and pointing away from you? The
charge on a proton is 1.6 × 10-19 C. Use F = qvx B sin(e)
Hello!
We can use the following equation for magnetic force on a charged particle:
[tex]F_B = qv \times B[/tex]
[tex]F_B[/tex] = Magnetic force (N)
q = Charge of particle (1.6 × 10⁻¹⁹ C)
v = velocity of particle (5.2 × 10⁷ m/s)
B = Magnetic field strength (1.4 T)
This is a cross-product, so the equation can be rewritten to F = qvBsinφ where φ is the angle between the magnetic field and particle velocity vectors.
Since the proton's velocity vector and the magnetic field vector are perpendicular, sin(90) = 1. We can reduce the equation to:
[tex]F_B = qvB[/tex]
Plug in the known values.
[tex]F_B = (1.6*10^{-19})(5.2*10^7)(1.4) = \boxed{1.1648 *10^{-11} N}[/tex]
