What is the potential energy of an object 20 m in the air with a
mass of 600 kg?

Answers

Answer 1

Answer:

Ep = 117600 J

Explanation:

Data:

Mass (m) = 600 kgHeight (h) = 20 mGravity (g) = 9.8 m/s²Potential Energy (Ep) = ?

Use formula:

Ep = m * g * h

Replace:

Ep = 600 kg * 9.8 m/s² * 20 m

Multiply operations, and units:

Ep = 117600 J

What is the potential energy?

The potential energy is 117600 Joules.


Related Questions

What simple machine can best be described as "a simple machine that uses an inclined plane wrapped around a rod"? *

a wedge
a screw
a wheel and axle
a lever

Answers

Screw because the inclined place is the spiral of the screw rotating around the center rod

A 10,000 g body falls from a height of 20 m. Calculate the potential energy when it is at a height of 10 m

Answers

Answer:

Ep = 980 J

Explanation:

First, grams must be converted to kilograms. So, we must divide the value of the mass, by 1000.

[tex]\boxed{\frac{10000}{1000}=\boxed{10kg}}[/tex] ---------- Converted to kg.

==================================================================

Data:

Mass (m) = 10 kgGravity (g) = 9.8 m/s²Height (h) = 10 mPotential Energy (Ep) = ?

Use formula:

Ep = m * g * h

Replace:

Ep = 10 kg * 9.8 m/s² * 10 m

Multiply operations, with units:

Ep = 980 J

What is the potential energy?

The potential energy is 980 Joules.

Orion, also called the Hunter, has three stars that make up Orion's belt.

Which star is at the tip of the arrow? PLEASE HELP I NEED THIS FAST


A. Sirius


B. Betelgeuse


C. Rigel


D. Polaris

Answers

Answer - B. Betelguese.

I really hope this helps!!

Before working this problem, review Conceptual Example 14. A pellet gun is fired straight downward from the edge of a cliff that is 14.7 m above the ground. The pellet strikes the ground with a speed of 27.2 m/s. How far above the cliff edge would the pellet have gone had the gun been fired straight upward

Answers

Answer:

23.04 m

Explanation:

We'll begin by calculating the initial velocity of the pellet. This can be obtained as follow:

Height (h) of cliff = 14.7 m

Final velocity (v) = 27.2 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =?

v² = u² + 2gh

27.2² = u² + (2 × 9.8 × 14.7)

739.84 = u² + 288.12

Collect like terms

u² = 739.84 – 288.12

u² = 451.72

Take the square root of both side

u = √451.72

u = 21.25 m/s

Thus, the initial velocity of the pellet is 21.25 m/s.

Finally, we shall determine the maximum height to which the pellet would have gone assuming the gun was fired straight upward. This can be obtained as follow:

Initial velocity (u) = 21.25 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 m/s (at maximum height)

Maximum height (h) =?

v² = u² – 2gh (since the pellet is going against gravity.

0² = 21.25² – (2 × 9.8 × h)

0 = 451.5625 – 19.6h

Collect like terms

0 – 451.5625 = –19.6h

–451.5625 = –19.6h

Divide both side by –19.6

h = –451.5625 / –19.6

h = 23.04 m

Therefore, the pellet will reach a maximum height of 23.04 m above the cliff.

Which is an advantage of storing data digitally?
A. It is easy to change the data if you have the right computer
programs.
B. It is easy to copy a computer virus to a device along with the data.
C. The quality of copies decrease as more copies are made.
D. Other people can access personal data from unsecured devices.

Answers

Answer:

A

Explanation:

Because I said so

Answer:

A

Explanation:

i took the test and got it right please mark me ❤️

formula for percentage error​

Answers

Answer:

PE = (|accepted value – experimental value| \ accepted value) x 100%

Explanation:

A swimmer pushing off from the wall of a pool exerts a force of 1 newton on the wall. What is the reaction force of the wall on the swimmer?

Answers

Answer: 1 Newton

Explanation:

"Every action has an equal and opposite reaction."

Please mark as Brainliest if it is correct.

Force is an action-reaction principle. It stated that the force always exists in a pair. The reaction force of the wall on the swimmer will be 1N.

What is Newton's third law of motion?

Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.

Both occur in an action-reaction form. Hence for every action, there is an equal and opposite reaction.

[tex]\rm F_{action}=F_{reaction} \\\\ \rm F_{action= 1N[/tex]

[tex]\rm F_{reaction} = 1N[/tex]

Hence the reaction force of the wall on the swimmer will be 1N.

To learn more about Newton's third law refer to the link;

https://brainly.com/question/1077877

Heart Disease is the number one cause of preventable death in the United States
A True
B False

Answers

Falsefalsefalsefalsefalsr

Heart disease is the leading cause of death for both men and women. This is the case in the U.S. and worldwide. More than half of all people who die due to heart disease are men.

TRUE

6. The petrol in a petrol can weighs 2000g. The density of petrol is 0.8g/cm3.
What is the volume of the petrol in the can in a) cm3 b)litres (1000cm3=1 litre)

Pls help :((

Answers

Answer:

a. 2500 cm³.

b. 2.5 litres.

Explanation:

Given the following data:

Density = 0.8g/cm³

Mass = 2000g

To find the volume of the petrol;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

[tex]Density = \frac{mass}{volume}[/tex]

Making volume the subject of formula, we have;

[tex]Volume = \frac{mass}{density}[/tex]

Substituting into the equation, we have:

[tex]Volume = \frac{2000}{0.8}[/tex]

Volume = 2500 cm³

a. The volume of the petrol in the can in cubic centimeters (cm³) is 2000.

b. The volume of the petrol in the can in litres;

1000 cm³ = 1 litre

2500 cm³ = x litres

Cross-multiplying, we have;

1000x = 2500

x = 2500/1000

x = 2.5 litres.

Therefore, the volume of the petrol in the can in litres is 2.5.

Sarah took 204 seconds to bicycle to their grandmother's house, a total of
430 meters. What was their velocity in m/s?

Answers

Answer:

2.1m/s towards your grandmother's house

Explanation:

Given parameters:

Time taken  = 204s

Distance  = 430m

Unknown:

Velocity  = ?

Solution:

The velocity is determined by:

    Velocity  = [tex]\frac{displacement}{time}[/tex]  

   Velocity  = [tex]\frac{430}{204}[/tex]   = 2.1m/s towards your grandmother's house

Each tire on a car has a radius of 0.330 m and is rotating with an angular speed of 15.6 revolutions/s. Find the linear speed v of the car, assuming that the tires are not slipping against the ground.

Answers

Answer:

v = 32.345 m/s

Explanation:

given data

radius r = 0.330 m

angular speed = 15.6 revolutions/s

solution

we will get here linear speed v, that is express as

v = r × w        .....................1

here w = 17.5 × 2 × π    radians

so now put value in eq1

v = 0.330 × 15.6× 2 × π

v = 32.345 m/s

A 3" diameter germanium wafer that is 0.020" thick at 300K has 1.015 x 10^17 As atoms added to it. What is the resistivity of the wafer? Germanium has 4.42 x10^22 atoms/cc, electron and hole mobilities are 3900 and 1900 cm^2/(V*s). What is the resistivity of the Ge in ohm*microns?

Answers

Answer:

0.546 ohm / μm

Explanation:

Given that :

N = 1.015 * 10^17

Electron mobility, u = 3900

Hole mobility, h = 1900

Ng = 4.42 x10^22

q = 1.6*10^-19

Resistivity = 1/qNu

Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)

= 0.01578880889 ohm /cm

Resistivity of germanium :

R = 1 / 2q * sqrt(Ng) * sqrt(u*h)

R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)

R = 1 /0.0001831

R = 5461.4964 ohm /cm

5461.4964 / 10000

0.546 ohm / μm

Answer this and you get 100 points
You better answer it quick though

Answers

Answer what? Apologies, but I don't see anything. (。>︿<)

Explain two reasons why astronomers are continually building larger and larger telescopes. Explain two reasons why astronomers are continually building larger and larger telescopes. Larger telescope mirrors have a larger surface area and can therefore collect more light, which makes faint objects bright enough to detect. Also, larger telescope mirrors produce more scattering of light due to diffraction, which contributes to better angular resolution. Larger telescope mirrors have a larger surface area and can therefore collect more light, which contributes to better angular resolution. Also, larger telescope mirrors produce more scattering of light due to diffraction, which makes faint objects bright enough to detect. Larger telescope mirrors have a larger surface area and can therefore collect more light, which contributes to better angular resolution. Also, larger telescope mirrors produce less scattering of light due to diffraction, which makes faint objects bright enough to detect. Larger telescope mirrors have a larger surface area and can therefore collect more light, which makes faint objects bright enough to detect. Also, larger telescope mirrors produce less scattering of light due to diffraction, which contributes to better angular resolution.

Answers

Answer:

* Larger mirrors collect more light and therefore fainter and more distant objects can have enough intensity to be detected

* arger mirrors decreases the angle of dispersion giving a better resolution of the bodies

Explanation:

Refracting telescopes get bigger every day for two main reasons.

* Larger mirrors collect more light and therefore fainter and more distant objects can have enough intensity to be detected

* the diffraction process for circular apertures is given by

               θ = 1.22 λ / D

where d is the diameter of the mirror, therefore having larger mirrors decreases the angle of dispersion giving a better resolution of the bodies

Suppose a car is traveling at 22.8 m/s, and the driver sees a traffic light turn red. After 0.404 s has elapsed (the reaction time), the driver applies the brakes, and the car decelerates at 9.00 m/s2. What is the stopping distance of the car, as measured from the point where the driver first notices the red light?

Answers

Answer:

38.09 m

Explanation:

We'll begin by calculating the distance travelled by the car during the reaction time. This can be obtained as follow:

Reaction time (tᵣ) = 0.404 s

Initial velocity (u) = 22.8 m/s,

Distance travelled during the reaction time (sᵣ) =?

sᵣ = utᵣ

sᵣ = 22.8 × 0.404

sᵣ = 9.21 m

Next, we shall determine the distance travelled by the car when the brake was applied. This can be obtained as follow:

Initial velocity (u) = 22.8 m/s

Acceleration (a) = –9 m/s² (since the car is decelerating)

Final velocity (v) = 0 m/s

Distance travelled when the brake was applied (s₆) =?

v² = u² + 2as₆

0² = 22.8² + (2 × –9 × s₆)

0 = 519.84 – 18s₆

Collect like terms

0 – 519.84 = –18s₆

–519.84 = –18s₆

Divide both side by –18

s₆ = –519.84 / –18

s₆ = 28.88 m

Finally, we shall determine the stopping distance of the car, as measured from the point where the driver first notices the red light. This can be obtained as follow:

Distance travelled during the reaction time (sᵣ) = 9.21 m

Distance travelled when the brake was applied (s₆) = 28.88 m

Stopping distance =?

Stopping distance = sᵣ + s₆

Stopping distance = 9.21 + 28.88

Stopping distance = 38.09 m

Desperado, a roller coaster built in Nevada, has a mass of 800 kg. It also has a vertical drop of 225 feet down the first hill. The roller coaster is designed so that the speed of the cars at the end of this drop is 80 mi/h. Assume the cars are at rest at the start of the drop. How much work is done by friction on the car as it drops down the hill

Answers

Answer:

the work done by friction on the car is 524,582 J.

Explanation:

Given;

mass of the roller coaster, m = 800 kg

distance moved by the coaster, d = 225 ft = 68.58 m

final velocity of the coaster, v = 80 mi/h = 35.76 m/s

The time taken for the coaster to drop down the hill is calculated as;

[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\ \times \ 68.58}{9.8} } \\\\t = 3.74 \ s[/tex]

The work done by friction on the car is calculated as;

[tex]W =F\ \times \ d = \frac{mv}{t} \times \ d\\\\W = \frac{800 \ \times \ 35.76 }{3.74} \times \ 68.58\\\\W = 524,582 \ J[/tex]

Therefore, the work done by friction on the car is 524,582 J.

A clump of soft clay is thrown horizontally from 9.80 m above the ground with a speed of 20.0 m/s. Assume it sticks in place when it hits the ground At what time will the clay hit the ground

Answers

Answer:

Explanation:

The time to hit the ground will be same as time taken to fall from the height of 9.8 m with initial vertical velocity of zero .

Considering vertical displacement

initial velocity u = 0

displacement s = 9.8 m

acceleration a = g = 9.8 m /s²

time t = ?

s = ut + 1/2 g t²

9.8 = 0 + .5 x 9.8 x t²

t² = 2

t = √2 = 1.4 s

A 97.1 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.63 rad/s . A monkey drops a 8.97 kg bunch of bananas vertically onto the platform. They hit the platform at 45 of its radius from the center, adhere to it there, and continue to rotate with it. Then the monkey, with a mass of 22.1 kg , drops vertically to the edge of the platform, grasps it, and continues to rotate with the platform. Find the angular velocity of the platform with its load. Model the platform as a disk of radius 1.73 m .

Answers

Answer:

the final angular velocity of the platform with its load is 1.0356 rad/s

Explanation:

Given that;

mass of circular platform m = 97.1 kg

Initial angular velocity of platform ω₀ = 1.63 rad/s

mass of banana [tex]m_{b}[/tex] = 8.97 kg

at distance r = 4/5  { radius of platform }

mass of monkey [tex]m_{m}[/tex] = 22.1 kg

at edge = R

R = 1.73 m

now since there is No external Torque

Angular momentum will be conserved, so;

mR²/2 × ω₀ = [ mR²/2 + [tex]m_{b}[/tex] ([tex]\frac{4}{5}[/tex] R)² + [tex]m_{m}[/tex]R² ]w

m/2 × ω₀ = [ m/2 + [tex]m_{b}[/tex] ([tex]\frac{4}{5}[/tex] )² + [tex]m_{m}[/tex] ]w

we substitute

w = 97.1/2 × 1.63 / ( 97.1/2 + 8.97(16/25) + 22.1

w = 48.55 × [ 1.63 / ( 48.55 + 5.7408 + 22.1 )

w = 48.55 × [ 1.63 / ( 76.3908 ) ]

w = 48.55 × 0.02133

w = 1.0356 rad/s

Therefore; the final angular velocity of the platform with its load is 1.0356 rad/s

How does earths magnetic field work

Answers

Answer: On Earth, flowing of liquid metal in the outer core of the planet generates electric currents. The rotation of Earth on its axis causes these electric currents to form a magnetic field which extends around the planet.

Explanation:

Answer:

the rotation of earth on its axis causes electric currents to form a magnetic field which extends around the planet

Which image best illustrates diffraction

Answers

Answer:

There is no image

Explanation:

Answer: Send me image than I will be able to help

Explanation:

What term is used to describe DNA Replication?
Conservative
Un-conservative
Non-conservative
Semi-conservative

Answers

Answer:

Semi-conservative

Explanation:

Each strand of the original DNA molecule serves as a template for the production of its counterpart

Your favorite golfer taps the golf ball with just enough force that it rolls into the ninth hole is an example of what law of motion???

Answers

The law of motion is the second law.


Second law definition: The acceleration of an object is dependent upon the force acting on the object & the mass of the object.

And the golf ball does so when it’s hit by enough force.

Answer:

mass and on the net force acting on it. ... Tap again to see term ... Newton's second law of motion states that an object's acceleration depends on its ... You hit a ping-pong ball & a tennis ball with a tennis rack

Q4. What is the speed of light in a block of glass that
has an Index of refraction of 1.11?

Answers

Refractive index(n)= speed of light in vacuum/ speed of light in medium.
Since refractive index is 1.11, and usually we know that the speed of light is 300,000km/s, simply divide 300,000km/s over 1.11. That is, 270,270.2703 when simply rounding, its 270,270 km/s.

plsss answer this plsss answer this plsss answer this plsss answer this ​

Answers

Answer:

I dont see file

dndndndbnfbfbfbfbfbf

Answer:

ye ek rod h or electric ⚡ field h P point

PLEASE HELP GIVING BRAINLIEST ANSWER
Explain why your PE and KE are usually not both high at the same time (If PE is high then usually KE is low)

Answers

Potential energy is an object’s stored energy when it is not moving. Kinetic energy is an object’s energy in motion. You can’t be both moving and not moving at the same time, so PE and KE cannot be equal.




From the Water in each of the next move

Answers

Any key words? That they put there

A hiker walks 7.7 miles to the east in 3.6 hours, then turns around and walks 2.1 miles to the west in 2.4 hours. What was the magnitude of her average velocity during the trip?

Answers

Answer:

2.18 miles per hour

Explanation:

Given:

A hiker walks 7.7 miles to the east in 3.6 hours.

A hiker walks 2.1 miles to the west in 2.4 hours

To find: magnitude of average velocity during the trip

Solution:

Total distance = 7.7 + 2.1 = 9.8 miles

Total Time = 2.1 + 2.4 = 4.5 hours

Average velocity = Total distance ÷ Total Time =[tex]\frac{9.8}{4.5}=2.18[/tex] miles per hour

What is the mass of a block concrete that gains 52,800 joules of energy when its temperature is increased by 5 degrees Celsius specific heat of concrete 880 J/K degrees Celsius

Answers

Answer:

12 kg

Explanation:

q = 52,800 J

c = 880 J/(kg * K) Pretty sure you missed the kg here

ΔT = 5 °C = 5 K (reminder that this only applies to ΔT and not T)

q = mcΔT ⇒ m = q/(cΔT) = 52,800 J / (880 J/(kg * K) * 5 K) = 12 kg

The mass of a block concrete that gains 52,800 joules of energy when its temperature is increased by 5 degrees Celsius specific heat of concrete 880 J/K degrees Celsius is 12kg

The formula for calculating the quantity of heat energy absorbed by the block is expressed as:

Q = mcΔt

Q is the quantity of heat = 52,800 Joules

m is the mass of the concrete

c is the  specific heat of concrete = 880 J/K

Δt is the change in temperature = 5 degrees

substitute the given values into the formula:

[tex]52800=m(880)(5)\\52800 = 4400m\\m=\frac{52800}{4400}\\m= 12kg[/tex]

Hence the mass of a block of concrete that gains 52,800 joules of energy when its temperature is increased by 5 degrees Celsius specific heat of concrete 880 J/K degrees Celsius is 12kg

Learn more here: https://brainly.com/question/22991121

Problem 6: A bullet in a gun is accelerated from rest from the firing chamber to the end of the barrel at an average rate of 6.3 × 105 m/s2 for 8.2 × 10-4 s.Ball,removedc795646bb4371e1754411a7dadf94458c503446af1b6450bb3269c1f97e8ef53removedremoved58b1e9a401041b69266daacea519e828d050d14013adc67f8c64697e40f2ef89removedtheexpertta - tracking id: 0W86-2A-6A-4E-962A-28979. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account.show answer No Attempt What is the gun’s muzzle velocity (that is, the bullet’s final speed), in meters per second

Answers

Answer:

v = 5.166 10² m / s

Explanation:

We can solve this exercise using the kinematics equations

           v = v₀ + at

as the bullet starts from rest its initial velocity is zero

           v = a t

let's calculate

           v = 6.3 10⁵   8.2 10⁻⁴

           v = 5.166 10² m / s

Pulling a rubber band back and then letting it fly across the room is an example of
A. converting energy to work
B. converting elastic energy to gravitational
C. converting kinetic energy to potential

Answers

Answer:

b

Explanation:

because a elastic band uses elastic energy

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