What is the product?
- 6(x²-1)-8(x+1)
O 6(x-1)²
O 6(x²-1)
O(x + 1)(6x-1)
O(x-1)(6x - 1)

Answer:

200 cans.

Step-by-step explanation:

f(c)=10r + 120

Put t=8 into it

T(c) = 10 x 8 + 120

=200 cans

(Use substitution method)

Answer:

-3 is a zero of the function  False

-1 is a zero of the function  True

1 is a zero of the function   False

2 is a zero of the function  True

4 is a zero of the function   False

Using conditional probability, it is found that there is a 0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which:

In this problem, we have that the probabilities are given as follows:

[tex]P(A) = 0.433, P(A \cap B) = 0.29 \times 0.50 = 0.145[/tex]

Hence the conditional probability is:

[tex]P(B|A) = \frac{0.145}{0.433} = 0.3349[/tex]

0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.

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Answer:

[tex]31[/tex]

Step-by-step explanation:

It's 31 degrees, I hope it is the right answer

Answer:

64 degrees

Step-by-step explanation:

90-32=58

180-58-58=64

Answer:

x = 64°

Step-by-step explanation:

supplementary angles is two angles whose sum is 180° (straight line)

90 + 32 = 122°

To find angle A,

A + 122 = 180

subtract 122 from both sides,

A + 122 - 122 = 180 - 122

A = 58°

This is an isosceles triangle, two angles are equal in measure (A and B). These angles lie opposite to the equal sides.

A triangles angles add up to 180°

58° + 58° + x° = 180°

116° + x = 180°

116 - 116 + x = 180 - 116

x = 64°

The estimated cost of the ending inventory, assuming the gross profit rate is 35% is; $11250

Let us first calculate the gross profit;

Gross Profit = Sales * Profit%

Gross Profit = 395000 * 35%

Gross Profit = $138250

Cost of goods sold = Sales - Gross Profit

Cost of goods sold = 395000 - 138250

Cost of goods sold = $256750

Cost of ending inventory = Cost of goods available for sale - Cost of goods sold

Cost of ending inventory = 268000 - 256750

Cost of ending inventory = $11250

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Answer:

They could make at most 5 teams and its not possible to make everyone on team.

Step-by-step explanation:

If there are 4 players on a team, then we use 23 ÷ 4 = 5.75, 0.75 is not enough for 1, so there are 3 players remaining after making 5 teams.

Answer:

Step-by-step explanation:

sin θ=1/4,tan θ>0

so θ lies in first quadrant.

cos θ=√(1-sin²θ)=√(1-(1/4)²)=√(1-1/16)=√(15/16)=√15/4

[tex]2cos^2 \frac{\theta}{2} =1+cos \theta[/tex]

[tex]2~cos^2\frac{\theta}{2} =1+\frac{\sqrt{15} }{4} =\frac{4+\sqrt{15}}{4} \\cos~\frac{\theta}{2} =\sqrt{\frac{4+\sqrt{15} }{4 \times 2} } \\cos\frac{\theta}{2} =\frac{\sqrt{8+2\sqrt{15}} }{4}[/tex]

Answer:

a. b = 2A/a

b. 30

Step-by-step explanation:

a. to solve for b:

[tex]A = 1/2 ab[/tex]

multiply both sides by 2

[tex]2A = ab[/tex]

divide both sides by a

[tex]2A/a=b[/tex]

so b = 2A/a

b. using the equation b = 2A/a

[tex]b = 2*18/(6/5)\\= 36/(6/5)\\= 30[/tex]

Answer:

I iitiriririrrifjjrjr idiocy jdkthink 179.86

Answer:

1/4 or 0.25

Step-by-step explanation:

The total possibilities of any 7 digit number using 0-9 is :

9×10×10×10×10×10×10=9000000

To work out the total possibilities in this question :

We look at the conditions :

The first digit can only be 5 numbers :

1 , 3 , 5 , 7 , 9

Now we subtract 5 from 9 :

9-5 = 4

Since no repeats for 2 , 3 , 4, 5, 6:

9 , 8 , 7 , 6 , 5,  

5 possibilities for the last digit :

Total possibilities for this code :

4 × 9 × 8 × 7 × 6 × 5 × 5 = 302400

If it begins with 5 that is only 1 possibility for the first digit

1 × 9 × 8 × 7 × 6 × 5 × 5 = 75600

Now we make a fraction :

75600÷302400

Dividing top and bottom by 75600 gives you 1/4 or 0.25

Hope this helped and have a good day

Answer:

Step-by-step explanation:

Comment

The first digit and the last digit are both odd. That tells you that so far what you have is one of 5 digits for the first digit and and one of 4 for the last digit. 4 because you can't repeat the first digit.

5, , , , , ,4

2 digits are gone 8 remain.

5* 8 * 7* 6* 5* 4* 4 = 134400

Part 2

Only one number can go at the beginning, and that is a 5. Everything else remains the same.

1 * 8 * 7 * 6 *5 * 4 * 4 = 26880

P(picking a number beginning with a 5 is  25880 /13440) = 0.2

The value of the probability P(x > 2) is 0.8369

The given parameters are:

n = 5

p =0.7

The probability is calculated as:

[tex]P(x) = ^nC_x *p^x * (1 - p)^x[/tex]

Using the complement rule, we have:

P(x > 2) = 1 - P(0) - P(1) - P(2)

Where:

[tex]P(0) = ^5C_0 *0.7^0 * (1 - 0.7)^5[/tex]

P(0) = 1 *1 * (1 - 0.7)^5 = 0.00243

[tex]P(1) = ^5C_1 *0.7^1 * (1 - 0.7)^4[/tex]

P(1) = 5 *0.7^1 * (1 - 0.7)^4 = 0.02835

[tex]P(2) = ^5C_2 *0.7^2 * (1 - 0.7)^3[/tex]

P(2) = 10 *0.7^2 * (1 - 0.7)^3 = 0.1323

Recall that:

P(x > 2) = 1 - P(0) - P(1) - P(2)

So, we have:

P(x > 2) = 1 - 0.00243 - 0.02835 - 0.1323

Evaluate

P(x > 2) = 0.83692

Approximate

P(x > 2) = 0.8369

Hence, the value of the probability P(x > 2) is 0.8369

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The solution will be x= -10

Simplifying the given expression

[tex]1.8(1.1x - 1.3) - 1.88 = - 24.02[/tex]

Step1: Convert decimal to fraction

[tex]1.8( \frac{11x}{10} - 1.3) - 1.88 = - 24.02[/tex]

[tex]1.8( \frac{11x}{10} - \frac{13}{10} ) - 1.88 = - 24.02[/tex]

[tex]\frac{18}{10} ( \frac{11x}{10} - \frac{13}{10} ) - 1.88 = - 24.02[/tex]

Step2: Make denominator common

[tex]\frac{18}{10} ( \frac{11x - 13}{10}) - 1.88 = - 24.02[/tex]

Step3: Simplifying the fraction

[tex]\frac{9}{5} ( \frac{11x - 13}{10}) - 1.88 = - 24.02[/tex]

Step4: Make denominator common

[tex] \frac{9(11x - 13)}{5 \times 10} - \frac{1.88 \times 50}{50} = - 24.02[/tex]

[tex] \frac{9(11x - 13)}{50} - \frac{94}{50} = - 24.02[/tex]

[tex] \frac{9(11x - 13 - 94)}{50} = - 24.02[/tex]

[tex] \frac{99x - 117 - 94}{50} = - 24.02[/tex]

Step5: Simplifying

[tex] \frac{99x - 211}{50} = - 24.02[/tex]

[tex] 99x - 211 = - 24.02 \times 50[/tex]

[tex] 99x - 211 = - 1201[/tex]

[tex] 99x = - 1201 + 211[/tex]

[tex] 99x = - 990[/tex]

[tex] x = \frac{ - 990}{99} [/tex]

[tex]x = - 10[/tex]

Hence, the solution x=-10

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Answer:

Step-by-step explanation:

Write the number as [tex]abc[/tex] and use the divisibility rules for 10 and 3. From the rule for 10, we know that the last digit of [tex]abc+cba[/tex] is [tex]o[/tex], hence [tex]a+c=10[/tex]. Thus the options are [tex]a=1[/tex] & [tex]c=9[/tex], [tex]a=2[/tex], & [tex]c=8[/tex], etc.

From the rule for 3, namely that the digit sum must be divisible by 3, we find that [tex]2a+2b+2c=20+2b[/tex]  is divisible by [tex]3[/tex]. By hand it's easy to check that [tex]b=2,5,8[/tex] are the only options that work.

So there are 9 choices for [tex]a[/tex] and [tex]c[/tex] and [tex]3[/tex] for [tex]b[/tex] , giving 27 total.

Answer:

[tex]\huge\boxed{\sf x =5 \ \ \ OR \ \ \ x = 1}[/tex]

Step-by-step explanation:

[tex]x^2-6x+5=0[/tex]

[tex]x^2-5x-x+5=0\\\\Take \ common\\\\x(x-5)-1(x-5)=0\\\\Take \ (x-5) \ common\\\\(x-5)(x-1)=0[/tex]

Either,

x - 5 = 0         OR         x - 1 = 0

[tex]\rule[225]{225}{2}[/tex]

The match is shown in the picture for the function of a parabola and the graph of a parabola.

It is defined as the graph of a quadratic function that has something bowl-shaped.

As we know the standard form of the parabola is:

y = a(x - h)² + k

If a > 0 (parabola opens upwards)

If a < 0 (parabola opens downwards)

or

x = a(y - h)² + k

If a > 0 (parabola opens right side)

If a < 0 (parabola opens left side)

Here (h, k) is the vertex of the parabola and a is the leading term.

Thus, the match is shown in the picture for the function of a parabola and the graph of a parabola.

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Answer:

-10 and -2

Step-by-step explanation:

First, divide both sides by 4 to get |x+6| = 4
Then, Take the absolute vaule on both sides
x+6= 4 or -4
So, x could be 2 vaules
Your welcome!

4 | x + 6 | = 16

Divide both sides by 4.

[tex]\bf{\dfrac{4|x+6|}{4}=\dfrac{16}{4} }[/tex]

[tex]\bf{|x+6|=4 }[/tex]

Absolute value is solved.

[tex]\bf{|x+6|=4 }[/tex]

We know either x + 6 = 4 or x + 6 = -4.

x + 6 = 4 (Possibility 1)

x + 6 - 6 = 4 - 6 (Subtract 6 from both sides)

x=−2

x + 6 = -4 (Possibility 2)

x + 6 - 6 = -4 - 6 (Subtract 6 from both sides)

x=-10

Solution:

x=−2 or x=−10

[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

The average rate of change for this function for the interval from x = 2

to x = 4 is 20

The function is given as:

x   y

0  18

2   32

3    50

4   72

The average rate of change at the interval from x = 2 to x = 4 is calculated using:

m = (f(4) - f(2))/(4 - 2)

Using the table values, we have:

m = (72 - 32)/(4 - 2)

Evaluate

m = 20

Hence, the average rate of change is 20

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Answer:

please mark me brainlist

Step-by-step explanation:

i need it

Answer:

3^1 multiplied by 3^2 = 3^(1 + 2) = 3^3

162

Simplify ——————

(2•3^3)

Canceling out 2 as it appears on both sides of the fraction line

3^4 divided by 3^3 = 3^(4 - 3) = 3^1 = 3

Step-by-step explanation:

hope this helps you ♡

Step-by-step explanation:

(4²-x²)³/²

or,(4+X) (4-X)

Substitute [tex]x = 4 \sin(y)[/tex], so that [tex]dx = 4\cos(y)\,dy[/tex]. Part of the integrand reduces to

[tex]16 - x^2 = 16 - (4\sin(y))^2 = 16 - 16 \sin^2(y) = 16 (1 - \sin^2(y)) = 16 \cos^2(y)[/tex]

Note that we want this substitution to be reversible, so we tacitly assume [tex]-\frac\pi2\le y\le \frac\pi2[/tex]. Then [tex]\cos(y)\ge0[/tex], and

[tex](16-x^2)^{3/2} = 16^{3/2} \left(\cos^2(y)\right)^{3/2} = 64 |\cos(y)|^3 = 64 \cos^3(y)[/tex]

(since [tex]\sqrt{x^2} = |x|[/tex] for all real [tex]x[/tex])

So, the integral we want transforms to

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx = 64 \int \cos^3(y) \times 4\cos(y) \, dy = 256 \int \cos^4(y) \, dy[/tex]

Expand the integrand using the identity

[tex]\cos^2(x) = \dfrac{1+\cos(2x)}2[/tex]

to write

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx = 256 \int \left(\frac{1 + \cos(2y)}2\right)^2 \, dy \\\\ = 64 \int (1 + 2 \cos(2y) + \cos^2(2y)) \, dy \\\\ = 64 \int (1 + 2 \cos(2y) + \frac{1 + \cos(4y)}2\right) \, dy \\\\ = 32 \int (3 + 4 \cos(2y) + \cos(4y)) \, dy[/tex]

Now integrate to get

[tex]\displaystyle 32 \int (3 + 4 \cos(2y) + \cos(4y)) \, dy = 32 \left(3y + 2 \sin(2y) + \frac14 \sin(4y)\right) + C \\\\ = 96 y + 64 \sin(2y) + 8 \sin(4y) + C[/tex]

Recall the double angle identity,

[tex]\sin(2y) = 2 \sin(y) \cos(y)[/tex]

[tex]\implies \sin(4y) = 2 \sin(2y) \cos(2y) = 4 \sin(y) \cos(y) (\cos^2(y) - \sin^2(y))[/tex]

By the Pythagorean identity,

[tex]\cos(y) = \sqrt{1 - \sin^2(y)} = \sqrt{1 - \dfrac{x^2}{16}} = \dfrac{\sqrt{16-x^2}}4[/tex]

Finally, put the result back in terms of [tex]x[/tex].

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx \\\\ = 96 \sin^{-1}\left(\frac x4\right) + 128 \frac x4 \frac{\sqrt{16-x^2}}4 + 32 \frac x4 \frac{\sqrt{16-x^2}}4 \left(\frac{16-x^2}{16} - \frac{x^2}{16}\right) + C \\\\ = 96 \sin^{-1}\left(\frac x4\right) + 8 x \sqrt{16 - x^2} + \frac14 x \sqrt{16 - x^2} (8 - x^2) + C \\\\ = \boxed{96 \sin^{-1}\left(\frac x4\right) + \frac14 x \sqrt{16 - x^2} \left(40 - x^2\right) + C}[/tex]

Another way to write the equation is 7x + 54 = 0

Given the equation;

[tex]\frac{7}{8}x + \frac{3}{4} = -6[/tex]

Find the LCM on the left side, which is 8

[tex]\frac{7x + 6}{8} = -6[/tex]

Cross multiply

[tex]7x + 6 = -6[/tex] × [tex]8[/tex]

[tex]7x + 6 = -48[/tex]

Collect like terms

[tex]7x = -48 - 6[/tex]

[tex]7x = -54[/tex]

Take all to one side

[tex]7x + 54 = 0[/tex]

Thus, another way to write the equation is 7x + 54 = 0

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Answer:

The equation of a parallel line is y = x

Step-by-step explanation:

Parallel lines have the same slope

hence the new lines slope is = 1

The equation of the line is written in the slope-intercept form,

y = mx + b

where m represents the slope

          b represents the y-intercept

where the format of a point is (x, y)

Given:

we need to find b, y = 1x + b

we can plug in the point (2, 2)

2 = 1(2) + b

2 = 2 + b

0 = b

Hence, the equation of the line through point

(2, 2) and parallel to y = x+4 is y = x

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The following statements accurately compare the three functions on the graph: option A and C.

In Geometry, the following statements are true about the graph of a function:

By critically observing the graph of a function, we can logically deduce that the following statements accurately compare the three functions on the graph:

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Answer:

please help me find em ah and I will be able to do what I can