what is the quotient of 64/-11

Answer:

28.284

Step-by-step explanation:

Answer:

2(4) + 2(l) >14 (second option is the answer).

Answer:

Step-by-step explanation done

They could complete the job together in 2.4 days

The known parameters are;

The number of days it would take Michelle to complete the landscaping job = 6 days

The number of days it would take Danielle to complete the landscaping job = 4 days

The unknown parameter;

The number of days can the job be completed if they work together

The process of finding the solution;

The rate at which Michelle works = 1/6 of the landscaping work per day

The rate at which Danielle works = 1/4 of the landscaping work per day

Method;

Find their combined work rate, from which the time would take them to complete the job together can be found

Let, C, represent their combined work rate

Therefore, we have;

C = (1/6 + 1/4) = 5/12 of the landscaping (work) job/(per) day

The number of days they could complete the, 1, job = 1 job(work)/(5/12 (work)job/day) = 12/5 days = 2.4 days

∴ The number of days they could complete the job together = 2.4 days.

Learn more about unit rate here;

https://brainly.com/question/19605901

Answer:

Step-by-step explanation:

(1/4 + 1/9 + 1/3)x = 25.

x = 36

Answer:

Let the number be x

(1/4 + 1/9 + 1/3) * x = 25

25/36 * x = 25

25x = 25*36

x = 25*36/25

x = 36

Step-by-step explanation:

Answer:

lemonade is 4:10 to ice or .4:1

Step-by-step explanation:

Assuming lemonade is 2 and tea is 5, you can use a table or multiply both reciprocals by 2 so 2x2 and 2x5 = 4:10. then if you want to see how much is in just once cup of tea divide by ten to each for the product of .4:1

Answer:  For every 2 cups of lemonade, there are 5 cups of iced tea.

if the ratio is 2:5 then for every 2 cups of lemonade there are 5 cups of tea.

it is just another way of saying the ratio

Answer:

x = 1, y = −1

x = 5/2, y = 1/2

Step-by-step explanation:

From the question given above, the following data were obtained:

y = 2x² − 6x + 3 ........ (1)

y = x − 2 ...... (2)

We can obtain the solutions to the equation as follow:

y = 2x² − 6x + 3 ........ (1)

y = x − 2 ...... (2)

Substitute the value of y in equation 2 into equation 1

y = 2x² − 6x + 3

y = x − 2

2x² − 6x + 3 = x − 2

Rearrange

2x² − 6x − x + 3 + 2 = 0

2x² − 7x + 5 = 0

Solve by factorization

Obtain the product of 2x² and 5. The result is 10x².

Find two factors of 10x² such that their sum will result to −7x.

The factors are −2x and −5x.

Replace −7x in the equation above with −2x and −5x as shown below:

2x² − 2x − 5x + 5 = 0

2x(x − 1) − 5(x − 1) = 0

(x − 1)(2x − 5) = 0

x − 1 = 0 or 2x − 5 = 0

x = 1 or 2x = 5

x = 1 or x = 5/2

Substitute the value of x into equation 2 to obtain y

y = x − 2

x = 1

y = 1 − 2

y = −1

x = 5/2

y = x − 2

y = 5/2 − 2

y = (5 − 4)/2

y = 1/2

SUMMARY:

x = 1, y = −1

x = 5/2, y = 1/2

Answer:

Can you Specify the Question?

Answer:

1 A

2c

3B

4f

do not use the last one f(X)=x

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (1, 4) and (x₂, y₂ ) = (2, 5 ) ← 2 ordered pairs from the table

m = [tex]\frac{5-4}{2-1}[/tex] = [tex]\frac{1}{1}[/tex] = 1

The line crosses the y- axis at (0, 3 ) → c = 3

y = x + 3 ← equation of line → A

Answer:

Option a, 13

if you solve it, you get 13 as the answer

³√(5x-1)=4

or, 5x-1=64

or, 5x=65

or, x=13

Sin74 = Cos16

cause 16 + 74 = 90

Whenever the sum of two angles is equal with 90, the Sin of one is equal with the Cos of the other like :

Sin(30) = Cos(60)

and also

Tan(30) = Cot(60)

Answer:

16

Step-by-step explanation:

sin(74) = cos(x)

sin(x)=cos(90-x)

sin (74) = cos(90-74)

sin 74 = cos( 16)

Answer:

The test statistic will be "-2.33". A further explanation is provided below.

Step-by-step explanation:

According to the question,

[tex]H_0: \mu = 2.05[/tex]

[tex]H_0: \mu < 2.05[/tex]

Given:

[tex]\bar x = 1.98[/tex]

[tex]s = 0.3[/tex]

[tex]n = 100[/tex]

The test statistics will be:

⇒ [tex]t_0 = \frac{\bar x - \mu_0}{\frac{s}{\sqrt{n} } }[/tex]

       [tex]=\frac{1.98-2.05}{\frac{0.3}{\sqrt{100} } }[/tex]

       [tex]=-2.33[/tex]

and the P-value will be:

= [tex]0.011< \alpha[/tex]

Answer:

x=8

Step-by-step explanation:

x^2+15^2=17^2, x=sqrt(64)=8

Answer:

I HOPE IT WILL HELP

EXPLANATION IS IN THE PHOTO .

Answer:

[tex]\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppppppppppppppppppppppppp\dddddd \displaystyle \Large \boldsymbol{} t_1=\boxed{5} \\\\d=\boxed{-4} \\\\t_n=\boxed{9-4n}[/tex]

Step-by-step explanation:

[tex]\displaystyle\large \boldsymbol{Rule: t_n=S_{n}-S_{n-1}} \\\\\\S_n=7n-2n^2 \ \ \ \ then \\\\\Longrightarrow S_{n-1}=7(n-1)-2(n-1)^2 =7n-7-2n^2+4n-2 \\\\then \\\\\\S_{n}-S_{n-1}=7n\!\!\!\!\!\!\diagup-2n^2\!\!\!\!\!\!\diagup-7n\!\!\!\!\!\!\diagup+7+2n^2\!\!\!\!\!\!\diagup-4n+2=9-4n \\\\t_n=9-4n => t_1=5\\\\d=t_2-t_{1}=1-5=-4[/tex]

============================================================

Explanation:

Each x represents a data point location.

So, for example, having an x over 60 means 60 is part of the set.

The set of values we're working with is

{59,60,61,63,63,64,66,68,70,71,71,73}

The repeated values are due to the fact we have a stack of two 'x' markers, and they occur at 63 and 71.

To find the IQR (interquartile range), we'll first need to find the median of this set. That's the middle most value.

Count out the number of values to find that there are n = 12 values.

The list splits into two halves that are n/2 = 12/2 = 6 items each

Between slots 6 and 7 is where the median is located.

The value in slot 6 is 64 and the value in slot 7 is 66. Average those two items to get (64+66)/2 = 65

The median is 65

---------------------------------

Next, we'll form two groups L and U such that

L = set of items lower than the median

U = set of items larger than the median

Because n is even, we simply just break the original set into two equal groups (6 items each)

L = {59,60,61,63,63,64}

U = {66,68,70,71,71,73}

The values of Q1 and Q3 represent the medians of L and U in that order.

The median of set L is (61+63)/2 = 62, so Q1 = 62

The median of set U is (70+71)/2 = 70.5, which is Q3

-----------------------------------

To summarize everything so far, we have found

Subtract those items to get the IQR

IQR = Q3 - Q1

IQR = 70.5 - 62

IQR = 8.5 which points us to choice C as the final answer.

Answer:

54

Step-by-step explanation:

The perimeter is the sum of the outside

P = 8+4+5+10+( 4+10) +(8+5)

P = 54

Answer:

Area of triangle =1/2b×h

1/2×10×8.7

=44 square inches

Answer:

44

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh

where b is the base and h is the height

A = 1/2 (10) (8.7)

A= 43.5

Rounding to the nearest whole number

A = 44

Let

We know

[tex]\boxed{\sf n(A\cup B)=n(A)+n(B)-n(A\cap B)}[/tex]

[tex]\\ \sf\longmapsto n(A\cap B)=n(A)+n(B)-n(A\cup B)[/tex]

[tex]\\ \sf\longmapsto n(A\cap B)=60+65-100[/tex]

[tex]\\ \sf\longmapsto n(A\cap B)=125-100[/tex]

[tex]\\ \sf\longmapsto n(A\cap B)=25[/tex]

9514 1404 393

Answer:

  A, C

Step-by-step explanation:

Any table with no repeated x-values is a relation that is a function.

Step-by-step explanation:

let debbie be x years

let felix be 6x years

in 12 years felix will be 2x older than debbie

do the calc

Answer:

[tex](6a-7)5a=30a^2-35a[/tex]

Step-by-step explanation:

Message if you want a detailed explanation.

65.4Step-by-step explanation:KHAN

Important formula:

[tex]N_t = N_0 (1/2)^\frac{t}{t_{1/2}}[/tex]

Here, you are trying to find Nt and you have N0 = 4.5g, t = 23 days, t1/2 = 30 days. Plug the values in and you should get 2.7g left after 23 days.

Step-by-step explanation:

म नजन्मिदै विधवा भएकी हिमाल

खै! किन हो मेरा यी हेर्ने नयनले उनलाइ

अझै पनि दिन र रातमा

सेतै लुगा पहिरिएकी देख्छ

अचम्म लाग्छ मलाइ पहिरिएकी सेतो लुगा माथि

मुनालले पाइला टेके पनि विष्ठा गरे पनि कहिल्यै

मैलो हुदैन सेतो लुगाको वास्तविक रङ

उत्तिकै सेतो देख्छु म

निर्जीव वस्तु भएनी हिमाललाइ

सजीव मनुस्यको जस्तै चोटको कल्पना गरेको छु मैले

किनकी चोटै चोटले ग्रसित भएकी उनी आजभोली

अपाङ्गको सिकार बनिसकेकी छिन

उनलाइ अन्धो भन्छु म किनकी उनी आँखा देख्दैनन

आँखा नदेखे पनि अरु कसैलाइ सुम्सुम्याउन समेत सक्दैनन

तर पनि कस्तुरी, डाफे,मुनाल,घोरल,चितुवा आदि जनावरहरुको

सहारा दिने आश्रय स्थल भएर उभिएकी छिन, के कम छिन र?

जमिन भित्र उनको खुट्टा गाडिएर होला

खुट्टाको दृश्य मैले अझै पनि देख्न पाएको छैन

कस्तो होला है! हिमालको खुट्टा ? सोचिरहन्छु म

सायद खुट्टा नै छैन र पो कहिल्यै पनि हिड्डुल गर्न सक्दैनन कि?

जब कुनै समयमा चुचुरोमा हावा बहन थाल्यो

एकदिन सेतो कपाल धरतीमा हाम फालेर

नदिहरु बढ्न थाले तर उहीँ बहेको हावाले

हिमालको श्रवण गर्ने कानको जाली

नै फुटाइदिएछ त्यही भएर म भन्छु

हिमाललाइ बहिरो पनि हुनुहुन्छ तपाईं

सधै टोलाएर बसेकी देख्छु म

रोजगारी भन्ने कुरा त उहीँ हो हिमाललाइ

बिहानीपख देखि सन्ध्या काल सम्म

प्रकृतिले बसिबसी ऐना टल्काउने

पदभार ग्रहण गराइदिएको छ जब घाम

झुल्किन्छ उनी अस्ताउन्जेल सम्म ऐना टल्काइरहन्छिन्

त्यसैले म भन्छु हिमाललाइ बिधवा भएर के भो त

खान लाउनको लागि रोजगारी मिलेकै छ क्यारे !

Complete question is;

Alejandra correctly wrote the equation y – 3 = (1/5) (x – 10) to represent a line that her teacher sketched. The teacher then changed the line so it had a slope of 2, but still went through the same point. Which equation should Alejandra write to represent the new line?

Answer:

y – 3 = 2(x – 10)

Step-by-step explanation:

Since the original line is;

y – 3 = (1/5) (x – 10)

This means the slope is 1/5 and the x and y coordinates are (10, 3) respectively.

Now, if she changes the slope to 2 and it still passed through the same point, then it means it's x and y points are still (10, 3). Thus, the equation will now be;

y – 3 = 2(x – 10)

Solution :

Maximize, S = xy

subject to 2x + 2y = 996

So,

2x + 2y = 996

2(x + y) = 996

x + y = 498

y = 498 - x

Therefore,

S = x (498 - x)

S = 498x - [tex]x^2[/tex]

S = [tex]-x^2 + 498x[/tex]

[tex]$S = -(x^2-498x + 249^2) + 300^2$[/tex]

[tex]$S= -(x-249)^2 + 249^2$[/tex]

S = x (498 - x)

S = 498x - [tex]x^2[/tex]

[tex]$\frac{dS}{dx}= 498 - 2x$[/tex]

[tex]$\frac{dS}{dx}= 0$[/tex]

498 - 2x = 0

2x = 498

x = 249

∴ y = 498 - x

  y = 498 - 249

     = 249

Answer:

A = 249 x 249 = 62001 square meter.

Side is L = 249 m

Step-by-step explanation:

Total length of the fence is 996 m.

Let the length is L and the width is W.

Perimeter = 2 (L + W)

996 = 2 (L + W)

498 = L + W

L = 498 - W ...... (1)

Let the area is

A = L W

A = (498 - W) W

A = 498 W - W^2

Differentiate with respect to W.

dA/dW = 498 - 2 W

Put it equal to zero.

498 - 2 W = 0

W = 249 m

Now, L = 498 - 249 = 249 m

Differentiate with respect to W again

[tex]\frac{d^2A}{dW^2} = - 2[/tex]

As it is negative so the area is maximum.  

The maximum area is

A = 249 x 249 = 62001 square meter.

Side is L = 249 m

Answer:

let,

x=ky

y=39 when x=7 so,

7=39k

or, k=7/39

now, when x=22

22=7y/39

or, y=39×22/7

or, y=858/7

or, y=122.57 (rounded to the nearest hundredth)