What is the range of the relation in the table below?

The value of the element in row 1, column 1 of matrix x is; y.

According to the task content, it follows that matrix x is defined as; x= [y 4].

In essence, it follows that the matrix x contains one row and 2 columns. Therefore, the element in row 1, column 1 of matrix x is; y.

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Answer: A

Step-by-step explanation:

Answer:

angle s = 22

angle r = 117

angle q = 41

Step-by-step explanation:

so all of the angles equal to 180 degrees in a triangle

so you add all of t he angles like this:

x+5x+7x+2x-3=180

collect all of the like terms,

8x + 4 = 180

subtract 4 from both sides, which leaves you with 8x = 176

divide both sides by 8 leaving x on its own.

x = 22

angle s = 22

angle r = (5x22)+7 which is 117

angles q = (2x22)-3 which is 41

The  total distance it flies, rounded to the nearest mile is: d. 1,692 miles .

First distance= 550 miles (given)

Second distance=483 miles (given)

Now let find the third distance

Let x represent the third distance

Hence:

x/sin79 = 550/sin55

x= 659.1

Now let calculate the total distance

Total distance=550+483+659.1

Total distance= 1692.1

Total distance= 1692 miles (rounded)

Therefore the correct option is d.

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The correct answer is option D which is the model will be

A = 13000( 0.72 ) [tex].^t[/tex].

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Given that:-

The expression will be formed as:-

As we can see that the depreciation of the car per year is 28% so the amount of the car is decreased by 28 percent every year.

Now the remaining value of the car will be 100 - 28 = 78%. So the expression will be given as:-

A = 13000( 0.72 ) [tex].^t[/tex].

Therefore the correct answer is option D which is the model will be

A = 13000( 0.72 ) [tex].^t[/tex].

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Step-by-step explanation:

95 95 branded to the nearest 10 with the number line

deter determine the two constructive multiples of 10 that bracket 95

9 is between 90 and 100

asteroid on the number line 95 is the midpoint between the 90 and 100

therefore 95 rounding to the nearest 10 is equal to 100

[tex] \huge\underline{\underline{\boxed{\color{blueviolet}{ANSWER}}}}[/tex]

★ 15 trucks can carry 26,850 kg weight

★ We've to find the weight carried by one truck

[tex]\huge \pink {\overline{ \quad \quad \quad \quad \quad \quad \quad\quad \quad}}[/tex]

[tex] \sf{Number \: of \: trucks = 15 }[/tex]

[tex] \sf{Weight \: carried \: by \: one \: truck = \frac{26,850Kg}{15} }[/tex]

[tex] \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= 1790Kg[/tex]

Therefore , the weight carried by one truck is 1790 kg

Answer: B. 55°

Step-by-step explanation: A single line is 180°. There are two of those lines that are both marked, meaning that they are equal. If this is true, then that must be the same for the other side. We would just have to find the angle for that.

180°- 125° = 55°

Therefore, the answer is B. 55°.

I hope this helps! Pls give brainliest!! :)

Answer:

x = 3

Step-by-step explanation:

6x + 7 = 9x - 2

-3x = -9

x = 3

Answer:

parallel

a quadrilateral can be a parallelogram only and only if pair of opposite sides are equal and parallel.

Answer:

Step-by-step explanation:

Step-by-step explanation:

tan 30 degre = perpendicular /base

I wrote the rule than you can easily find hope this help you

Using 3 different methods, we can find that YZ = 25m

The complete image of a triangle is attached with the answer below.

The branch of mathematics sets up a relationship between the sides and the angles of the right-angle triangle is termed trigonometry.

For a given triangle rectangle with a known angle θ and a hypotenuse H, we can write the trigonometric relations

sin(θ) = (opposite cathetus)/H

cos(θ) =(adjacent cathetus)/H

tan(θ) =(opposite cathetus)/(adjacent cathetus)

Now, in the given image we can see that:

θ = 30°

H = 50m

XY = adjacent cathetus

YZ = opposite cathetus.

We want to find YZ, so with the known things, we can use the first relation:

Sin 30 = YZ / 50

YZ = 50 x Sin30 = 25 meters

Now let's try another way.

We know that the sum of the internal angles of a triangle is always equal to 180°

In a triangle rectangle, we always have an angle equal to 90°.

Then the missing angle for our triangle can be computed from:

Z + 90° + 30° = 180°

Z = 180° - 90° - 30° = 60°

From this angle, the side YZ is the adjacent cathetus, then we can use the second trigonometric relation:

Cos 60 = YZ / 50

YZ = 50 x Cos 60 = 25 meters

Third way.

Whit the same angle we could find the side XY, the opposite cathetus, with:

Sin 60 = XY / 50

XY = 50Sin 60 = 43.3 meters

Now that we know one of the catheti, we can use the last trigonometric relation

tan 60 = XZ / YZ = 43.3 / YZ

YZ = 43.3 / tan 60 = 25 meters

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A comparison of the actual number of people who violate the speed limit to the total number of drivers is an example of a rate

A rate is known as the quantity measured with respect to another measured quantity. It refers to the comparison of a part to a whole.

It is also the measure of a part with respect to a whole or a proportion.

Therefore, a comparison of the actual number of people who violate the speed limit to the total number of drivers is an example of a rate

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Answer:

C and D.

Step-by-step explanation:

In option C, they are collecting data about the lengths of fish in a pond.

In option D, they are collecting data about people's favorite show.

Hope this helps!

If not, I am sorry.

Answer:

C.  20 ≤ h < 30

Step-by-step explanation:

Median

The value in the middle of the data set when all the data values are placed in order of size.

As this is grouped data, we can only estimate the median.

Add an extra row to the table showing the Cumulative Frequency:

[tex]\begin{array}{|c|c|c|}\cline{1-3} \sf Height & \sf Frequency & \sf Cumulative\:Frequency \\\cline{1-3} \sf 0 \leq h < 10 & 1 & 1 \\\cline{1-3} \sf 10 \leq h < 20 & 9 & 10 \\\cline{1-3} \sf 20 \leq h < 30 & 7 & 17 \\\cline{1-3} \sf 30 \leq h < 40 & 13 & 30 \\\cline{1-3}\end{array}[/tex]

To find which class the median is in, divide the total number of data values by 2:

[tex]\implies \sf \dfrac{n}{2}=\dfrac{30}{2}=15[/tex]

Therefore, there are 15 values less than or equal to the median.

From the table, the 11th to 17th data values are in class 20 ≤ h < 30.  Therefore, the median must be in the 20 ≤ h < 30 class.

Answer:

C (look at explain!)

Step-by-step explanation:

Answer:

x = 3.16

Step-by-step explanation:

x * x = 10

[tex]x^2 = 10[/tex]

square root both sides

[tex]\sqrt{x^2} = \sqrt{10}[/tex]

[tex]x = \sqrt{10}[/tex]

x is appr. 3.16

Answer:

x=  √-10, √ 10

Step-by-step explanation:

Answer + Explanation:

#1 Simplification:

(2x - 3) - (x - 4)

2x - 3 - x + 4

2x - x - 3 + 4

x + 1

#2 Factorization:

16 - 4x²

-4x² + 16

-4(x² - 4)

-4(x² - 2²)

-4(x + 2)(x - 2)

Answer:

[tex]-2\sqrt{3} +2\sqrt{15}[/tex]

Step-by-step explanation:

When we simplify this equation, we have to multiply the numbers outside the parenthesis with the the numbers inside the parenthesis. In this equation, we have to multiply [tex]\sqrt{12}[/tex] by [tex]-1[/tex] , getting the answer of [tex]-\sqrt{12}[/tex], which can be further simplified into [tex]-2\sqrt{3}[/tex]. Next, looking at [tex]\sqrt{12}[/tex] × [tex]\sqrt{5}[/tex], we get [tex]\sqrt{60}[/tex], which can also be simplified further into [tex]2\sqrt{15}[/tex]. Now, adding up these two numbers get [tex]-2\sqrt{3} +2\sqrt{15}[/tex].

Answer:

Mean score for the class B is 66.66

Step-by-step explanation:

Mean : It is the sum (total) of all the values in a set of data, such as numbers or measurements, divided by the number of values on the list.

Mean = sum of all numbers/ total numbers

Given,

mean score of class A = 34.

mean score of both the classes = 55

mean score of class a = sum of marks/total strength of class

                              34   = sum of marks/10

                             340 = sum of marks of class A

similarly,  Mean score of both classes

= ( sum of marks of class A and class B)/(total students in both classes)

= (340 + sum of marks of class B)/ 28  

55 =  (340 + sum of marks of class B)/ 28  

55 × 28 =  (340 + sum of marks of class B)

1540 - 340 = sum of marks of students of class B    

     1200    =  sum of marks of students of class B  

now to find Mean score of class B

sum of marks of students of class B / total students in class B

1200/18 = 66.66 answer  

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The shape of the cross-section resulting from the cut is rhombus.

A rhombus simply means a shape that has opposite sides to be parallel and the sides are equal.

Given:

object is cut by a vertical plane containing A and B and bisecting two of the horizontal edges.

Edges of the object in the diagram are equal in length and that the object is cut by a vertical plane containing A and B.

Hence, the shape of the cross-section resulting from the cut is a rhombus.

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Answer:.20

Step-by-step explanation:

According to what are written in the table the probability for x=-10 is .20

16.39492

Step-by-step explanation:

Answer:

Step-by-step explanation:

12 becuase you have to read the equasion and do the problem

Let's take this problem step by step:

To find the ordered pair of the system:

 ⇒ must set both equations equal to each other

     ⇒ solve for 'x'

Let's solve:

 [tex]x^2-2x+3=-2x+12\\x^2-2x+2x+3-12\\x^2-9=0\\(x+3)(x-3)=0[/tex]

Let's find the x-values:

 [tex](x+3)=0\\x=-3\\\\(x-3)=0\\x+3[/tex]

Let's find f(x)'s value for each 'x':

 [tex]x=-3\\f(-3)=-2(-3)+12=6+12=18\\\\x=3\\f(3)=-2(3)+12=-6+12=6[/tex]

Answer: (3, 6), (-3,18)

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The IQR for male data is 10, the estimated difference between medians is 2, the box plot for males is symmetric and for females, the box plot is left side skewed.

A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.

From the box plot:

Part A:

IQR for males data:

IQR = Q3 - Q1

The estimated value of Q3 is 15 (between 10 and 20)

The estimated value of Q1 is 5 (between 0 and 10)

IQR = 15 -5 = 10

Part B:

= Median(male) - Median(femal)

= 10 - 8

= 2

Part C:

The box plot for males is symmetric and for females, the box plot is left side skewed.

Part D:

There can be holidays for the outliers

Thus, the IQR for male data is 10, estimated difference between medians is 2, the box plot for males is symmetric and for females, the box plot is left side skewed.

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Answer:

Base = 24 cm or 10cm

Step-by-step explanation:

REMEMBER:
An isosceles triangle ABC with base BC = ‘b' & height AD = ‘h' & its equal sides =13 cm & area = 60 cm²

Using the formulas

[tex]A=\frac{bh_b}{2}[/tex]

[tex]h_b=\sqrt{a^2-\frac{b^2}{4} }[/tex]

There are 2 solutions for [tex]b[/tex]

[tex]b=2\sqrt{2} \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2+\sqrt{13^4-4*60^2} } }[/tex] ≈ [tex]10cm[/tex][tex]b=2\sqrt{2} \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2-\sqrt{13^4-4*60^2} } }=24cm[/tex]

Less complex:

Area of a triangle = 1/2 * b * h = 60

=> h = 120/b

In right triangle ABD

13² = h² + b² /4 ( by Pythagoras law)

=>169 = 120²/b² + b²/4

=>676 b² = 57600 + b^4

=> b^4 - 676 b² + 57600 = 0

=> b² = 676 +- √(676² - 4*57600) / 2

=> b²= 676 +- √(226576) /2

=> b² = (676 +- 476 )/2

=> b² = 1152/2 , 200 /2

=> b² = 576 , 100

=> b = 24, 10

So, Base = 24 cm or 10cm

Answer: The domain would be all real numbers.

Step-by-step explanation:

This is not a piecewise function, so it means that the domain, which means all possible x values, is all real numbers, not imaginary.

The reflection is written as:

[tex]g(x) = -3*(1.5)^x[/tex]

And the graph can be seen below.

Here we have the function:

[tex]f(x) = 3*(1.5)^x[/tex]

A reflection across the x-axis is given by:

[tex]g(x) = -f(x).[/tex]

Then, replacing the function f(x) by the actual equation:

[tex]g(x) = -3*(1.5)^x[/tex]

The graph of the function g(x) can be seen below:

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Answer:

5. c = 8pi cm

6. c = 18pi ft

7. c = 8.6pi in

8. c = 11/2pi m

Step-by-step explanation:

The circumference of a circle can be easily found using the formula: c = [tex]\pi[/tex]d, where the diameter is d.

Now you just plug your numbers into the formula!

5. c = pi x d

   c = 8pi cm

6. This one gives you the radius instead of the diameter. All you need to do now is to double the radius to find the diameter.

     9 ft x 2 = 18 ft

   Now, it follows the formula.

   c = pi x d

   c = 18pi ft

7. c = pi x d

   c = 8.6pi in

8. c = pi x d

   c = pi x 2(2 3/4m) - Note that this is a mixed fraction. To be able to multiply it, you need to convert it to an improper fraction.

  c = pi x 2(11/4)

  c = pi x 11/2

  c = 11/2pi m

:)