Answer:
R = 35.8 Ω
Explanation:
Recall Ohm's Law:
V = I * R
then R = V / I
in our case:
R = 179 V / 5 A = 35.8 Ω
What is the average velocity of someone who walks 3 km in a half hour, then 3 km in an hour, then 6 km in an hour and a half?
Answer:
The average velocity is 4 [tex]\frac{km}{hour}[/tex]
Explanation:
Velocity is the magnitude that relates the change in position with time. That is, the speed expresses the relationship between the space traveled by an object and the time used for it.
The average velocity relates the change in position with the time taken to effect said change through the expression:
[tex]velocity=\frac{distance}{time}[/tex]
In this case:
distance= 3 km + 3 km + 6 km= 12 kmtime= half hour + an hour + an hour and a half= 30 minutes + 1 hour + 1 hour 30 minutes= 0.5 hour + 1 hour + 1.5 hour= 3 hoursReplacing:
[tex]velocity=\frac{12 km}{3 hours}[/tex]
Solving:
velocity= 4 [tex]\frac{km}{hour}[/tex]
The average velocity is 4 [tex]\frac{km}{hour}[/tex]
When synthetic materials are made from natural materials, the atoms that make
up the original substances are regrouped into new molecules. *
True
False
a steel sphere and brass ring have diameter 25cm and 24.9cm at 15°C.If the sphere and the ring are heated together.what is the temperature at which the sphere could pass through the ring? alpha steel= 12×10^-6 and alpha brass= 20×10^-6
Answer:
Explanation:
Due to heat energy , metal expands . Formula for linear expansion is as follows .
L = l ( 1 + α Δt )
where L is expanded length , l is original length , α is coefficient of linear expansion and Δt is increase in temperature .
To pass the sphere through the ring , the diameter of both ring and sphere should be same after heating . Let after increase of temperature Δt , their diameter becomes same as L . The linear coefficient of brass and steel are
20 x 10⁻⁶ and 12 x 10⁻⁶ respectively .
For steel sphere ,
L = 25 ( 1 + 12 x 10⁻⁶ Δt )
For brass ring
L = 24.9 ( 1 + 20 x 10⁻⁶ Δt )
25 ( 1 + 12 x 10⁻⁶ Δt ) = 24.9 ( 1 + 20 x 10⁻⁶ Δt )
1.004( 1 + 12 x 10⁻⁶ Δt ) = ( 1 + 20 x 10⁻⁶ Δt )
1.004 + 12.0482 x 10⁻⁶ Δt = 1 + 20 x 10⁻⁶ Δt
.004 = 7.9518 x 10⁻⁶ Δt
Δt = 4000 / 7.9518
= 503⁰C.
final temp = 503 + 15 = 518⁰C .
it is easier to see clothes with pointed needle than a blunt one
Answer:
Explanation:
It is easier to see clothes with pointed needle than a blunt one because pressure exerted is more in a pointed needle as it occupies less space compared to blunt needle, A blunt has more surface area so the pressure exerted will less as compared to a pointed needle.
IF YOU FOUND MY ANSWER USEFUL THEN PLEASE MARK ME BRAINLIEST.
Please help with this question!!!!
The net electric flux through a cubic box with sides that are 22.0 cm long is 4950 N⋅m2/C . What charge is enclosed by the box?
Answer:
43.83 nC
Explanation:
We know Q = ε₀Ψ where Q = charge enclosed by the cubic box, ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m and Ψ = net electric flux through cubic box = 4950 Nm²/C
So, substituting the values of the variables into the equation, we have
Q = ε₀Ψ
= 8.854 × 10⁻¹² F/m × 4950 Nm²/C
= 43827.3 × 10⁻¹² C = 4.38273 × 10⁻⁸ C
= 43.8273 × 10⁻⁹ C
= 43.8273 nC
≅ 43.83 nC
5 A truck travelling at 25 m/s puts on its brakes for 4 s. This produces an acceleration of –2 m/s. What is the truck's
velocity after braking?
Answer: The truck's velocity after braking = 17m/s.
Explanation:
Given: Initial velocity(i) = 25 m/s
Time(t) = 4s
Acceleration(a) = -2 m/s ²
We use the following formula to compute final velocity (v):
[tex]v= i+at\\\\\Rightarrow\ v=25+(-2)(4\ \ \ [\text{Substitute all values}]\\\\\Rightarrow\ v=25-8\\\\\Rightarrow\ v=17\ m/s[/tex]
Hence, the truck's velocity after braking = 17m/s.
Which is an indication that a man might be choking
Answer:
If they put their hands near their neck, if they're not breathing properly, if they aren't coughing.
Explanation:
Answer:
if they are struggling to breathe, attempting to cough (like coughing something up) or asking for help whilst holding their stomach, neck
Neutrons can change the charge of an atom
True
False
Answer:
False. They can’t change the charge but they can change the mass
A race car accelerates from 50 m/s to 75 m/s over a distance of 400 m. What is the race car's acceleration?
Answer:
[tex]a=3.90\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity, u = 50 m/s
Final velocity, v = 75 m/s
DIstance, d = 400 m
We need to find the acceleration of the car. Let the acceleration of the car be a. We can use the third equation of motion to find it as follows :
[tex]v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(75)^2-(50)^2}{2(400)}\\\\=\dfrac{3125}{2(400)}\\\\=3.90\ m/s^2[/tex]
So, the acceleration of the car is [tex]3.90\ m/s^2[/tex].
HELP ME, I WILL RATE 5 STARS AND I WILL HEART ANSWER.
Answer:
im going to guess the 3rd one
Explanation:
How much heat is needed to warm up 10g of water from 10*C to 30*c
Answer: 10
Explanation:
2. List a similarity between magnetic force and gravitational force,
Answer:
Both Electrical and Magnetic Forces take place between two charged objects
Explanation:
Si se deja caer un carrito de una pista de coches sin friccion y su altura inicial es de 1.4 metros, cual es la velocidad maxima que puede alcanzar el carrito?
Answer:
[tex]5.241\ \text{m/s}[/tex]
Explanation:
m = Masa del coche
g = Aceleración debida a la gravedad = [tex]9.81\ \text{m/s}^2[/tex]
h = Altura = [tex]1.4\ \text{m}[/tex]
v = Velocidad del automóvil en la parte inferior de la pista
Aquí asumimos que el automóvil desciende verticalmente. La energía potencial del automóvil se completará convertida en energía cinética en la parte inferior de la pista ya que no hay pérdida de energía.
[tex]mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.4}\\\Rightarrow v=5.241\ \text{m/s}[/tex]
La velocidad máxima que puede alcanzar el coche es [tex]5.241\ \text{m/s}[/tex].
Which shows zero as significant digits? Check all that apply.
0.02
7.560
O 430
0 604
O 70,230
Answer:
Explanation:
0.02
0.604
70,230
becuase if you take away the 0 then it would change the value of the number
Which of the following is an example of acceleration?
A) Standing in position while waiting to begin jumping jacks.
B) A leaf blown from a tree by the wind.
C) Gravity holding a rock still on the ground.
D) Slowing a bike by applying the brakes.
Answer:
B) a leaf blown from a tree by the wind
Answer:
the answer is B A leaf being blown from a tree by the ground
A boy is holding a ball 1 m from the ground with a force of 20 N. He holds it still for 60seconds. How much power in watts is being used in this situation?
Answer:
Power = 0.33 Watts
Explanation:
Given the following data;
Distance = 1m
Force = 20N
First of all, we would solve for the work done by the boy.
Workdone = force * distance
Substituting into the equation, we have;
Workdone = 20*1 = 20J
Now to find power;
Power = workdone/time
Power = 20/60
Power = 0.33 Watts.
Which is a substance that takes the shape and volume of its container?
amorphous solid
liquid
crystalline solid
gas
A baby carriage is rolling down a hill. Take into consideration, the carriage has 90J of kinetic energy and the mass of the carriage is 0.5m. If you can only run at a speed of 10m/s, will you catch the baby carriage? What is the velocity of the carriage?
Answer:
YES. 6√10
Explanation:
apply E=1/2mv^2 and find the velocity of carriage which is 6√10 ms-1
as our velocity is higher than that of cart. we can catch the carriage
If you pay children in kindergarten to make things from modeling clay, and then stop, you may find that they are less willing to do it for nothing than they were before you ever started paying them. This is an example of?
Answer: overjustification
Explanation:
The overjustification effect is a situation that occurs when an incentive like prizes or money or prizes leads to the reduction in an individual's intrinsic motivation that is necessary in performing a task.
In this case, because the children are motivated by money, when the take doesn't involve money anymore, they may not be willing to do it.
If Emily tries to jump over a narrow river at the speed of 6 m/s
at angle 30° to the horizontal, then the total flight time will be
seconds.
Answer: 0.6
Explanation: I'm doing the projectile motion problem solving and I was stuck but I guessed and choose that answer and it said I was correct.
Help plzzz, if a question has more than one answer, pur both letters! Plzz I need 5 letters, this is the third time I’m posting this for help, someone plzzzz help!!
Answer:
1) e
2)c
3)b
4)d
i dont know if these are right, but something along these lines if you understand the pattern
Explanation:
Just like traditional film cameras, the small opening that allows light to pass through the lens of a digital camera is called the
Answer:
dsadadas
Explanation:
dadadda
All celestial objects we tracted to each other by gravity.Asteroids A and B are 5 meters (m) part. Asteroids C and D are also 5 m apart. Asteroids A and B both have a mass of 5 kilograms(kg) and asteroids C and D both have a mass of 7 kg.Between which set of asteroids is the gravitational attraction?
A between asteroids c and d because gravitational attraction is greatest with increased mass
B between asteroids a and b because gravitational attraction is greatest with decreased mass
C between asteroids a and b because gravitational attraction is greatest with increased distance
D between asteroids c and d because gravitational attraction is greatest with increased distance
The two parents shown in (Figure 1) exert upward forces
of Fi = 18 N on the left end of the plank and F2 = 65 N
on the right end.
How much does the child weigh?
Answer:
W = 83 [N] (weight)
Explanation:
We must clarify that the system is in static equilibrium, in such a way that we must perform a sum of forces on the Y-axis equal to zero, in order to determine the downward force corresponding to the weight of the child.
∑Fy = 0
[tex]F_{1}+F_{2}-m*g=0\\18+65=m*g\\m*g = 83 [N][/tex]
And the mass can be determined as follows:
[tex]m*g=83\\m = 83/9.81\\m=8.46[kg][/tex]
The weight of the child is equal to 83 Newton.
Given the following data:
Upward force 1 = 18 NewtonUpward force 2 = 65 NewtonTo determine the weight of the child:
From the diagram, we can deduce that the system is in static equilibrium. Thus, we would resolve the horizontal component of the forces, in order to determine the downward force (weight of child).
Mathematically, the horizontal component of the forces is given by:
[tex]\sum F_y = 0\\\\F_1 +F_2 -mg=0[/tex]
Substituting the given parameters into the formula, we have;
[tex]18+65-mg=0\\\\83=mg[/tex]
Note: Weight = mg
Weight of child = 83 Newton.
Read more: https://brainly.com/question/366299
by how much does the speed of a vehicle moving ina straight line change each second when it is accelerating at 2km/h/s? At 4 km/h/s ? At 10 km /h/s?
Answer:
At 2km/h*s it is changing speed every 2 seconds.
At 4km/h*s it is changing speed every 4 seconds.
At 10km/h*s it is changing speed every 10 seconds.
Two reindeer-in-training pull on a sleigh. Connie pulls with a force of 200 N at an angle of 20 degrees above the (positive) -axis, while Randolph pulls with a force of 800 N at an angle of 50 degrees ° below the positive) -axis. What is their resultant magnitude of the force on the sleigh?
Answer:
[tex]F_r \approx 978.3N[/tex]
[tex]\theta =44 \textdegree[/tex]
Explanation:
From the question we are told that
Connie pulls with a force of [tex]F_c=200 N[/tex]
At an angle [tex]\theta _c=20 \textdegree[/tex]
Randolph pulls with a force of [tex]F_R=800 N[/tex]
At an angle [tex]\theta _R=50 \textdegree[/tex]
Generally the horizontal axis can mathematically be represented as
[tex]f_x=f_ccos\theta _c+F_Rcos\theta _R[/tex]
[tex]f_x=200*cos20+800*cos50[/tex]
[tex]f_x=702.2N[/tex]
Generally the vertical axis can mathematically be represented as
[tex]f_y=f_csin\theta _c+F_Rsin\theta _R[/tex]
[tex]f_y=200*sin20+800*sin50[/tex]
[tex]f_y=681.24N[/tex]
Generally the resultant force [tex]F_r[/tex] is mathematically given by
[tex]F_r=\sqrt{f_x^2+f_y^2}[/tex]
[tex]F_r=\sqrt{702.1686119^2+681.2395832^2}[/tex]
[tex]F_r=978.3230731N[/tex]
[tex]F_r \approx 978.3N[/tex]
Generally the Direction [tex]\theta[/tex] of force is mathematically given by
[tex]\theta =tan^-^1(\frac{f_c}{f_y})[/tex]
[tex]\theta =tan^-^1(\frac{681.23}{702.16})[/tex]
[tex]\theta =44 \textdegree[/tex]
What is the frequency of a wave that has a period of 0.002 seconds?
Answer:
The frequency of a wave whose time period is 0.002 second is 500 Hz
Explanation:
Given,
Time period of wave = 0.002 seconds
We know,
Frequency = 1 / Time period
Substituting the values;
= 1 / 0.002sec
= 1000/2
Frequency = 500Hz
Hence,
The frequency of a wave whose time period is 0.002 second is 500 Hz
PLEASE HURRY!!!!!!!!
Your brother pulls up to a corvette at a stop light and revs his engine. When the light turns green he slams the gas pedal to the floor. He begins at 9km/hr and after 6 seconds is going 82Km/hr. What was his acceleration rate? (Hint: your label with be Km/hr/s)
Answer:
9.1km/hr...................I think I'm not %100
b) We find
all matter.
Lesson exercise
1. A stone has a mass of 200 grams. When it is immersed in a measuring cylinde
of water, the water rises 100 ml. What is the density of the stone?
2. A 48 g metal bar was placed in water. The initial volume of water was 89ml.the
final volume was 86ml. What is the volume and density of the metal bar?
3. A rectangular wooden block measures 10cm x 4cm x 5cm. Given the density of
the block is 8.9g/cm?, determine the mass of the block.
4. When a vessel of mass 50g is filled with water, the total mass is 126g. When the
vessel is filled with liquid L. The total mass is 110g.
a. Determine the relative density of the liquid L.
b. Calculate the total mass of the vessel when filled with equal volume of water
and liquid L.
Answer:
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